[Exercise 03] Caesar Cipher Decoder

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You have received an encrypted message from Julius Caesar-- the message is ebiil.  You are asked to decipher the message in order to understand what Caesar trying to say to you.

Hint

Luckily, Caesar has given you a hint, he says: 'I, myself, encoded the message by shifting every word backwards by 3.' 

Solution

Write a program that receives 5 characters 'ebiil'. Then decode those characters into 5 new characters.

Example

#include <stdio.h>

int main(int argc, char *argv[]) {


	char a;
    	char b;
	 	
	scanf("%c%c", &a, &b);
	
	//decode the message how??
	
	printf("%c%c", a,b);
	
	return 0;
}

Input

ebiil

 

 

 

 

 

 

 

 

 

 

Output

hello

** REMEMBER ** 
This is an online-compiler, don't put anything except the codes. If you want to make a comment, please use // or /* */

[Exercise] Coding (C) - asked in Chapter 2: Syntax structure of the C language by (5.9k points)
ID: 26955 - Available when: Unlimited - Due to: Unlimited
edited by | 5.8k views

22 Answers

0 like 0 dislike 
Hidden content!
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**  *     * *** return 0;
}
100/100 answered by (449 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
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100/100 answered by (153 points)
0 0
Case 0: Correct output
Case 1: Wrong output
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
#include *  ******    *
#include   **   ***   *  ** *

/* run this program using the console pauser or add your own getch,  *    * ****** **  * or input loop */

int main(int argc, char *argv[]) {
*    * ***  *  *** *    **** * a;
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***    *   * *  **** **  *  *  = c+3;
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** * * **  ** *  * * *** *  * = getchar();
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 *  *** ** **   ********* 
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}
100/100 answered by (281 points)
edited by
0 0
Your program receives only 2 characters, and it doesn't move characters' positions.

Try to make it receive 5 characters, and move their positions forward by 3.
commented by (5.9k points)
0 0
This exercise expects only 'hello'. However, your code has.....

printf("Put the words you want to decode:");

Kindly consider delete this part :)
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
  *** *  *  ** ***
*  *  * ***** ** * *

int  ***   *   char * *** {
/*
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*  *    **  * * *    ***   * ** ***  *     * *  *** *         ***  *   
a = a+3;
b =  
c =  **
d = d+3;
e = * 

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  **** *** ***      *
* * ** *  *    ******   *  * 0;
}
100/100 answered by (273 points)
edited by
0 0
prog.c:28:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:32:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:32:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
0 0
Your program can end at
  
    return 0;
}
------------------------------------------
You don't need to put

INPUT

ebiil

OUTPUT

hello
commented by (5.9k points)
0 0
Case 0: Correct output
Case 1: Wrong output
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
*  *  * * *   * **  ******
*   ** * *  ***   *   

/* run this    * *    the **  ** * **   or add your own      **  *  ****     *    **   or  **    */

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}
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50/100 answered by (252 points)
0 0
prog.c: In function 'main':
prog.c:19:2: error: expected declaration or statement at end of input
  return 0;
  ^~~~~~
commented by (4.3k points)
0 0
Great job using an array and a loop. There are two mistakes found in your code. Please check
1.     printf("\n\n%s", code);  <--- in order to make it match the fixed output '\n\n' should be deleted
2.     At the end of your code, there's something missing.
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
    ***  ****    * *
 
*  *   ** **   *   * * 

* * *  * **** **  ** * *    *    * ** *   ***      * * **   * ** ** *   *  * ** *
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*   = d +  *

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*
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*
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100/100 answered by (268 points)
0 0
It's correct lol you can't judge me
commented by (268 points)
0 0
Well, that's because your output doesn't match with the fixed answer. Please take a look at this
printf("%c%c%c%c%c\n", a1, b1, c1, d1, e1);

Hint: You should delete something  :)

By the way, great job.
commented by (5.9k points)
0 0
printf("%c%c%c%c%c", a1, b1, c1, d1, e1);

How's that?
commented by (268 points)
0 0
That's correct.
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
 ***   ** *** *  * *
* ***       * ***  *  

int      *  argc, char  * *  {
** *    *  * * * char *****
   *   *  *    char ** ** *
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*  *   * * * *   char * **
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****      **  *** 
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*** *  *  **  *  *** = * * * + 3;
 *  *** **** *      = *   * + 3;
*     *     *   *  =  *  * + 3;
* * **   * *  * letterc = ***  + 3;
* **    **     **  = *** + 3;
    * *  **      
*   *  *  *  *   **  *     *** *      * * *     *  *   **     *   * * *  * * 
 *    *  
*** *   **  *  return 0;
}
100/100 answered
reshown by
0 0
-----------Re-judge-----------
Case 0: Wrong output
commented by (4.3k points)
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     hello

Anyway, great job. Full marks.
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
*** *      **  *    
*  ** ** *    ***   

int  *   argc, char *argv[]) {
**   *  ** char  *  **
**    *   * *  * char letteri;
 ***  * ** *    char   *  
*     *   **** char *   
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 **** * *  * * *  
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* ***     ***** ******   ***   +3;
** **     *   
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 ****  * *  ** * 
*  **    ***  return 0;
}


INPUT
* ***  *     ** ***
*    *  ****  
OUTPUT
*   ***** * ** *
100/100 answered by (269 points)
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     hello

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
commented by (5.9k points)
0 0
prog.c:27:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:30:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:30:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
*** ***  *** *** *  * 
 * * *** **   * *   *** * 

int **  *   argc, char  * *  {
* *** *  * * char * *
         **  char    * *
   * * * *   ** char *  *  
**   * *  * ** char  **** 
 * *      *  * char  *   *
  ** *    
***  **    *     *   ** ** ** ** input the *   to   ** *    *   ***
 *** ** * **   
   *      **     * ***  **  ** * *  * * **   *****          ** **  * *** ****** *  ** *   **  ** *   * ** 
   **  *   ***  
** **   **  ** letter = letter + 3;
  ****    **   ** ****  = ****  + 3;
 * * * *    * * *    =  *   + 3;
* *    *  **         *  = *    + 3;
**      * ***   **     =  * * + 3;
   *** * *    * 
** *** *     **   * * *  *  ** **  ** letter is    *** * *  ** * **   **     *    *****  *    
 ** ** *   *  
* ****    **  * * return 0;
}

INPUT
*** **  ****** **
 * *  *   *  
** ** 
*** ** * ***
100/100 answered by (290 points)
reshown by
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     The encrypted letter is hello

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
commented by (5.9k points)
0 0
prog.c:26:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:29:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:29:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
#include    * **     ***

int main(int argc, char *argv[]) {
** * *** * *    *** * * *  * **  lettera;
 *     **  * * *  *  *** * *  ** letterb;
*****  *    ***** ***   ***  *   * letterc;
  *  * **  *    ** *   *** * letterd;
* *  ** ** ** * **  * ***  lettere;
**  **  *   **   ** * * **     
******* *****   ****  * * * * *    * %c %c %c  ***  *  *   ** ** *  **  ** **** *  *    ** *  **  ** ** *    **  ***    * 
 ** * ** ** **     ***  *  * = lettera + 3;
* *** * *** * ** *** **** **  **  = letterb + 3;
*****   **** * **   *** **** * * *  = letterc + 3;
   * **** **     *  *** ** * *  = letterd + 3;
**   *  * **** * * ** *   **     * = lettere + 3;
    **  *  * ** ** ** ** *  *  *    *** *  * ***** ** 
 * * * *   *      *  **  * ** **   %c %c %c    * ***  * * * letterb,  * *  * * **  ******
 ****  *** ** * *   * *****
*   **    ** * **   *     ***     **  0;
}

  **  
*    
  * *    **
****  
//hello
100/100 answered by (271 points)
edited by
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: e b i i l
     h e l l o

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
commented by (5.9k points)
0 0
prog.c:25:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:28:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:28:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:10:5: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
     scanf("%c %c %c %c %c", &lettera, &letterb, &letterc, &letterd, &lettere);
     ^~~~~
prog.c:10:5: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:10:5: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:17:5: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
     printf("%c %c %c %c %c", lettera, letterb, letterc, letterd, lettere);
     ^~~~~~
prog.c:17:5: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:17:5: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
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