[Exercise 03] Caesar Cipher Decoder

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You have received an encrypted message from Julius Caesar-- the message is ebiil.  You are asked to decipher the message in order to understand what Caesar trying to say to you.

Hint

Luckily, Caesar has given you a hint, he says: 'I, myself, encoded the message by shifting every word backwards by 3.' 

Solution

Write a program that receives 5 characters 'ebiil'. Then decode those characters into 5 new characters.

Example

#include <stdio.h>

int main(int argc, char *argv[]) {


	char a;
    	char b;
	 	
	scanf("%c%c", &a, &b);
	
	//decode the message how??
	
	printf("%c%c", a,b);
	
	return 0;
}

Input

ebiil

 

 

 

 

 

 

 

 

 

 

Output

hello

** REMEMBER ** 
This is an online-compiler, don't put anything except the codes. If you want to make a comment, please use // or /* */

[Exercise] Coding (C) - asked in Chapter 2: Syntax structure of the C language by (5.9k points)
ID: 26955 - Available when: Unlimited - Due to: Unlimited
edited by | 5.8k views

22 Answers

0 like 0 dislike 
Hidden content!
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**** ****       return 0;
}
100/100 answered by (449 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
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100/100 answered by (153 points)
0 0
Case 0: Correct output
Case 1: Wrong output
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
#include *  * *  *     *** 
#include *    *** * ** * *

/* run this program using the console pauser or add your own getch, ***  * **    ******** or input loop */

int main(int argc, char *argv[]) {
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*  *  *   *   ** * ** * * **
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}
100/100 answered by (281 points)
edited by
0 0
Your program receives only 2 characters, and it doesn't move characters' positions.

Try to make it receive 5 characters, and move their positions forward by 3.
commented by (5.9k points)
0 0
This exercise expects only 'hello'. However, your code has.....

printf("Put the words you want to decode:");

Kindly consider delete this part :)
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
*   ***   *  ***** 
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int ***    ** * char   ** {
/*
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*****    * *

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a = a+3;
b = * 
c = ** *
d = d+3;
e = * 

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*   ** *  * **  *  *
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  *  *  * *     * ** 
  ** ** *     *   *         0;
}
100/100 answered by (273 points)
edited by
0 0
prog.c:28:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:32:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:32:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
0 0
Your program can end at
  
    return 0;
}
------------------------------------------
You don't need to put

INPUT

ebiil

OUTPUT

hello
commented by (5.9k points)
0 0
Case 0: Correct output
Case 1: Wrong output
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
*  * *  *  * *  **  
 **    **  * *   **   * 

/* run this *  *    the ***  * or add your own  * **   * ***** * ** *****  **   or * *    *  */

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}
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50/100 answered by (252 points)
0 0
prog.c: In function 'main':
prog.c:19:2: error: expected declaration or statement at end of input
  return 0;
  ^~~~~~
commented by (4.3k points)
0 0
Great job using an array and a loop. There are two mistakes found in your code. Please check
1.     printf("\n\n%s", code);  <--- in order to make it match the fixed output '\n\n' should be deleted
2.     At the end of your code, there's something missing.
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
*   ** *   *  **     *
 
  * ****    *** ***    *
*
     * * *    *     *  **   **    * *       * *    ** ** * **    **** ** * **  * *  

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*   b + **

**  = c +  

* = d + **
*
*** * *   * 
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*
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*
100/100 answered by (268 points)
0 0
It's correct lol you can't judge me
commented by (268 points)
0 0
Well, that's because your output doesn't match with the fixed answer. Please take a look at this
printf("%c%c%c%c%c\n", a1, b1, c1, d1, e1);

Hint: You should delete something  :)

By the way, great job.
commented by (5.9k points)
0 0
printf("%c%c%c%c%c", a1, b1, c1, d1, e1);

How's that?
commented by (268 points)
0 0
That's correct.
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
** ** *         *** * *
 ****  *  *    ***  * *

int ***   * argc, char  **  {
* ***   *  * * char * 
**  *        char ** 
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*  *  * * ****  
* * * ******  ***  *  * ** ** *   *  *  ***  ****  *   * * *  **  *   * * * ** **  *   * ***  **   ***
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* **    **  *   *  * =      * + 3;
** *  *   ** letterc = * *  * + 3;
  ** **   * * *    *   *  = *   *  + 3;
*     * *    *   
*     ** *  ***   *   ** ***      *  * **  *          ** *  * * **   * * * 
  *   *  * *  
**  *  *   ***   return 0;
}
100/100 answered
reshown by
0 0
-----------Re-judge-----------
Case 0: Wrong output
commented by (4.3k points)
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     hello

Anyway, great job. Full marks.
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
   ****     * **    **
**** *  ***   ** * **

int *  **  argc, char *argv[]) {
*  * *      * char      
** *   *   *  char letteri;
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* * **     char ** * 
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* * *** ** *  
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* * ****    *   *    *  *** **    **  *    ** *  ***   * * *  * *  ** ****   ** *
 * *** * **  * * 
     * * *  *    return 0;
}


INPUT
 **  ** **  
 ** *    *   *
OUTPUT
*      * * ** **
100/100 answered by (269 points)
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     hello

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
commented by (5.9k points)
0 0
prog.c:27:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:30:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:30:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
*  *    *  ** *      
* ** ** * ** * * *** * ** *

int   *   argc, char ** **  {
**    *  ** * * char    ***
*        * * *** char     *
*  **** * * ** char  * *
*****    * ** char   *****
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* ** * * ***   
  ** *   *  **  * ******     **** input the ** *  to *  * **   ** *** 
**   *** *** *  
  * *    * **** ***   * * ***  ******* **   *     *****    * *   * **  **    *    *** *  ** * *   *  *** *
 *****  *  *  *   
 **  *    ***   letter = letter + 3;
       ** *   *** = *     + 3;
   *    * * * * *   =  **** + 3;
 *     * *    * *   *    =  * * + 3;
   *** * ** **      * =      + 3;
    * **  * **  
 *  ***  *  *   * *** ** **  **  letter is * * ****** *    *    * ** * ** *        * *  **  *
* ** *  * **  * 
    *  * * *  return 0;
}

INPUT
    ***  *  ***** **  *
   ** *** * 
  **
 *****  ** *** **  **
100/100 answered by (290 points)
reshown by
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     The encrypted letter is hello

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
commented by (5.9k points)
0 0
prog.c:26:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:29:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:29:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
#include   *  ** ** *   

int main(int argc, char *argv[]) {
 **** **    *      **  * lettera;
*** * ***   **   ***   ** *  letterb;
**   *  *    *  * ** *** *   **  letterc;
 ** ****  **  **   **    * *** letterd;
***    ****  *  *  *** * * *   lettere;
 ***    ******  *  *  ** * 
* *  *  ** *  * ****   * * **  * ** %c %c %c * *      **  * * *  **  *** * * *  * ***   ***     * * *    * *** ** *   
 *   *  ** * *  ** **  **   = lettera + 3;
   ** *   *  ******   * * *** = letterb + 3;
     *  * * *  **** * **** **** *** = letterc + 3;
*** **  * ** **     *** *  ** *  * = letterd + 3;
*     ** ********  **   * * **   ****   * = lettere + 3;
    ** ** ***    *    ***   ***   * * ***  * * * *  
 * *****  **        ** *    ***  * ** ** * %c %c %c *  *** * *    letterb,     *   *   **   
*  *   *  * * *** ******    
**     *   ** **  ****  *  *** *  0;
}

* * ***
***  *
** *    *   *
** ** **
//hello
100/100 answered by (271 points)
edited by
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: e b i i l
     h e l l o

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
commented by (5.9k points)
0 0
prog.c:25:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:28:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:28:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:10:5: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
     scanf("%c %c %c %c %c", &lettera, &letterb, &letterc, &letterd, &lettere);
     ^~~~~
prog.c:10:5: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:10:5: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:17:5: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
     printf("%c %c %c %c %c", lettera, letterb, letterc, letterd, lettere);
     ^~~~~~
prog.c:17:5: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:17:5: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
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