[Exercise 03] Caesar Cipher Decoder

Question

You have received an encrypted message from Julius Caesar-- the message is ebiil.  You are asked to decipher the message in order to understand what Caesar trying to say to you.

Hint

Luckily, Caesar has given you a hint, he says: 'I, myself, encoded the message by shifting every word backwards by 3.' 

Solution

Write a program that receives 5 characters 'ebiil'. Then decode those characters into 5 new characters.

Example

#include <stdio.h>

int main(int argc, char *argv[]) {


	char a;
    	char b;
	 	
	scanf("%c%c", &a, &b);
	
	//decode the message how??
	
	printf("%c%c", a,b);
	
	return 0;
}

Input

ebiil

 

 

 

 

 

 

 

 

 

 

Output

hello

** REMEMBER ** 
This is an online-compiler, don't put anything except the codes. If you want to make a comment, please use // or /* */

Answer 1

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}

Comments

Case 0: Wrong output
Case 1: Wrong output

---

Case 0: Correct output
Case 1: Wrong output

Answer 2

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Comments

Case 0: Correct output
Case 1: Wrong output

Answer 3

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int main(int argc, char *argv[]) {
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*    *  ** * ***      ****** * **   *    
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}

Comments

Your program receives only 2 characters, and it doesn't move characters' positions.

Try to make it receive 5 characters, and move their positions forward by 3.

---

This exercise expects only 'hello'. However, your code has.....

printf("Put the words you want to decode:");

Kindly consider delete this part :)

Answer 4

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* * *    *** **  **
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int **  *  char       {
/*
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**    ***  ***

****  ** * *** *  * **    *** *  * * * *  ***   ** *  **** *
a = a+3;
b =  * 
c = *  
d = d+3;
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* ** *** *** * ** *  **  *   **  ** 

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}

Comments

prog.c:28:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:32:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:32:1: error: unknown type name 'OUTPUT'

---

Your program can end at
  
    return 0;
}
------------------------------------------
You don't need to put

INPUT

ebiil

OUTPUT

hello

---

Case 0: Correct output
Case 1: Wrong output

Answer 5

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/* run this **  **  the *  **   or add your own *  * *   ** **  ***** * ****  or ***      */

int   *  *  **  char       {
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{
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**     *** *    * ** *   
}
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Comments

prog.c: In function 'main':
prog.c:19:2: error: expected declaration or statement at end of input
  return 0;
  ^~~~~~

---

Great job using an array and a loop. There are two mistakes found in your code. Please check
1.     printf("\n\n%s", code);  <--- in order to make it match the fixed output '\n\n' should be deleted
2.     At the end of your code, there's something missing.

Answer 6

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*  = c + 

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Comments

It's correct lol you can't judge me

---

Well, that's because your output doesn't match with the fixed answer. Please take a look at this
printf("%c%c%c%c%c\n", a1, b1, c1, d1, e1);

Hint: You should delete something  :)

By the way, great job.

---

printf("%c%c%c%c%c", a1, b1, c1, d1, e1);

How's that?

---

That's correct.

Answer 7

Hidden content!
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int **  *  argc, char  **** {
  ***   **** char *  *
   *** * * ** *  char ** ****
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   **  **  *  * *    ** =     * + 3;
*            * ** = ** ** + 3;
**    ** *  **   **    = **   + 3;
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**** *  ** * * ** *  =     + 3;
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*** *    **   
* ****  ** * return 0;
}

Comments

-----------Re-judge-----------
Case 0: Wrong output

---

Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     hello

Anyway, great job. Full marks.

Answer 8

Hidden content!
** *    * **  * * ***
*  *  *   ***     ** *   * 

int  ** argc, char *argv[]) {
*      **  **  *    char *  * 
** ****     ** * char letteri;
*  ***   * **    char *  ** 
 *  **   * **** char  **  *
 *     **  ** * char ** ** 
    ** * *  **    
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 **       ** * 
** ** *   ***** *   * ** **  *** *** **  *  * **    * * ** * *   *   * * *     * *  *  * *    **  ** 
** *** **   * ***** *     +3;
*     * ** ** **  * **   * +3;
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*    ***  * *   * *****  +3;
 *  *   *   *** *    ** *  ** +3;
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**** * *   * 
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  * *   **  * return 0;
}


INPUT
* *        *** *  **
 * ***  *** * *
OUTPUT
* **  *   * *  

Comments

Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     hello

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.

---

prog.c:27:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:30:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:30:1: error: unknown type name 'OUTPUT'

Answer 9

Hidden content!
     * *  *** ** * **   
**    *   * * ** **

int     * argc, char  **** {
 *    * **** char ** **
**  **     *    ** char   * 
 ***   *   char ** * 
**    *  * *   * char  **
*   *   *  * *** char   ** 
 *  *     *** 
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 * *  **   *  *   
     ***      ** *    * * **   *   * *   **    ** **      *  ** *  *  *  *       * ***  *  *** **  
    *   *     
** ** **** letter = letter + 3;
 * *  ******   * =  ****  + 3;
   **    *  * *  ** **** = ***  * + 3;
 *     **     * **     ** = * *   + 3;
* *   *  *** ***  ** **  =  ** *   + 3;
  *   ** *   * 
**  *     *  **  ** ** ** * * *  *  * letter is   *     ** *** **  * *      **** * *   *   ** *
  *  *  ****  * * 
  ***  *  **   *  return 0;
}

INPUT
   * ****** 
  ******  **** 
**   *
* *  * *  *  *  *  **

Comments

Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     The encrypted letter is hello

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.

---

prog.c:26:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:29:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:29:1: error: unknown type name 'OUTPUT'

Answer 10

Hidden content!
#include  * *  ************  *

int main(int argc, char *argv[]) {
 **   * *  * ***        **      lettera;
   *  **** * *        * * ***  ** letterb;
*  * * *** *  *   ** ***     letterc;
    * * **  * * ** *** ** letterd;
** **  **    ********** lettere;
 * ***     * **   **
** *  ***   ****** * **  ****  ***    *   %c %c %c  *     ** *    **    * *    *  * *   * *****         * * *  * 
 *   * **  *     *   ** ***** ** = lettera + 3;
 * * ** ***** *    * * *     *** = letterb + 3;
 * **  ******* ** *** *   ***    = letterc + 3;
*******  **   ***  *  *  *  *  **   = letterd + 3;
 ***  **   *    ***         ** = lettere + 3;
  ** ***     *    ***     ***  *  * **** **     
* *    **  * **  * * * *    ** **     * *  %c %c %c **  *  ** * * letterb, * ***     ** * ** **
* ***  * * ***       **  
**  *   * ****** *** *   ***   0;
}

** **
 *** 
* *  **    *
 ***  
//hello

Comments

Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: e b i i l
     h e l l o

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.

---

prog.c:25:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:28:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:28:1: error: unknown type name 'OUTPUT'

---

prog.c: In function 'main':
prog.c:10:5: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
     scanf("%c %c %c %c %c", &lettera, &letterb, &letterc, &letterd, &lettere);
     ^~~~~
prog.c:10:5: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:10:5: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:17:5: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
     printf("%c %c %c %c %c", lettera, letterb, letterc, letterd, lettere);
     ^~~~~~
prog.c:17:5: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:17:5: note: include '<stdio.h>' or provide a declaration of 'printf'