[Exercise 03] Caesar Cipher Decoder

Question

You have received an encrypted message from Julius Caesar-- the message is ebiil.  You are asked to decipher the message in order to understand what Caesar trying to say to you.

Hint

Luckily, Caesar has given you a hint, he says: 'I, myself, encoded the message by shifting every word backwards by 3.' 

Solution

Write a program that receives 5 characters 'ebiil'. Then decode those characters into 5 new characters.

Example

#include <stdio.h>

int main(int argc, char *argv[]) {


	char a;
    	char b;
	 	
	scanf("%c%c", &a, &b);
	
	//decode the message how??
	
	printf("%c%c", a,b);
	
	return 0;
}

Input

ebiil

 

 

 

 

 

 

 

 

 

 

Output

hello

** REMEMBER ** 
This is an online-compiler, don't put anything except the codes. If you want to make a comment, please use // or /* */

Answer 1

Hidden content!
**  *** * ***   *

int   **   argc, char **  {
** * *  * *** * *   * * ***  */

  *** **   ****  ** int number;
* ****    * **** char a;
 * * * *    **  *   **      b;
*  **  ** **    * **    ** * **   c;
    ** ***  * * * **** * *    **  d;
  ** ***    * ****   ** *** * e;
    *  ** ** **  ***  **
 *****  * *   **  *   forgert how to shift word  *   *  * ** *  **  * 
 * *****   *  **   ****    **   **      * *  ***   **   **  * ***     * *     ******
    * * ** ** *  
 ** ***  *   *  * ** the message how??
* * * *  *** *  
 * *     *  **   * ***  **** ***   *  *   **  **   **   
* *    * * *  **** 
*    *** **    return 0;
}

Comments

Case 0: Wrong output
Case 1: Wrong output

---

Case 0: Correct output
Case 1: Wrong output

Answer 2

Hidden content!
 **  * ****  *  ** **** *
 
 * *   * **    *  *  * {

** *** 
  =   * * 
 * ** * * 
** = * *    
* =  ** *
 =   *  *  

* = **  
* =  *
   =   
* = ****

*** ** *
*   ***  
**  *  *
 **** 
***  **
 
 ** *** **   ** * *   

Comments

Case 0: Correct output
Case 1: Wrong output

Answer 3

Hidden content!
#include  **   *     *
#include * *  **       ***

/* run this program using the console pauser or add your own getch, *  *    * ****    or input loop */

int main(int argc, char *argv[]) {
    **** **  **     * ** *** *  a;
 *   ******* *    **  * ** ** * b;
* *  *   *  *   * ** *     **  *** c;
* ****   **  ** ** ** **** d;
*         *** * * *** ****   ** e;
*    * *** * ** **  *   ** 
* * * ******* * **  ****** *   ***  *   *** the words you want to    ***  *    
 **    * *  * ****   **   *** 
**  ** **  **** ** *    * = getchar();
* * * *  *     * *  * * * ** = a+3;
*  ** *  ****  *    ***** ***
**  **   *    *  ** ****  = getchar();
 **   * *    * *    = b+3;
   **  ****     * * *  *** ** *
  * *            *  * * ** = getchar();
 **   *** **  *  **   * *   * **** = c+3;
***  **  * ** * * *   *****   **     
      *  * *** * **  ** * * *  * = getchar();
  *  *  *   *** ** ** * * * = d+3;
       *  **  *  ***       *  ***
** * * **    *  **** *  = getchar();
 * * * ******* * * ***   * * = e+3;
  **** ***** * * **    * **   
   **** *  **  *****     *    *    * * * * *  * *  *   *  *  * *
* **  **  ******  *** * *     ***   **   ***  *** &a, &b, &c, &d, **  *   * 
* **  ** **   *** * *** ***
** * * *     *   * *   *   *       the message how??
* ** ***  **     **  *** 
* ****** ** * ******* * *  *   * *** ** *** ** *   a, b, c, d, e);
* *  * *** **** ** ****   
 **   *** *  ******* * * *   *    0;
}

Comments

Your program receives only 2 characters, and it doesn't move characters' positions.

Try to make it receive 5 characters, and move their positions forward by 3.

---

This exercise expects only 'hello'. However, your code has.....

printf("Put the words you want to decode:");

Kindly consider delete this part :)

Answer 4

Hidden content!
 **    *  *  ** * **  *
*  ****  * *    *  ** **

int ***  **** char **     {
/*
*****  *  *** */

   *   **** 

*  *  * *   * *  * ***** ***   * **    **  * * *   * **  *   *  ** **  
a = a+3;
b = *
c =  * *
d = d+3;
e = *** 

 **    the * * ** * *
   * * * ** * *  
* ***      *** *  *  * *     ******* ** 

    *  ****    **   
*   * ***  *****  * *****  ***    0;
}

Comments

prog.c:28:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:32:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:32:1: error: unknown type name 'OUTPUT'

---

Your program can end at
  
    return 0;
}
------------------------------------------
You don't need to put

INPUT

ebiil

OUTPUT

hello

---

Case 0: Correct output
Case 1: Wrong output

Answer 5

Hidden content!
******      ** *****    
*  *    ** *      * *

/* run this  *        *  the ** *  *   or add your own * ***   *   * **      ***** or *** *  */

int *** *  *   char * * **   {
 * ***** ***      int num, ** 
  ****      *    *     *
 * *  **  ** *   
 *        *   *         *  *  *    
 *      **   * for  ** =  *     *     * **
{
*   ** **      ** * *  =  *    * * 
** ** *** **** if ** * *  * *   *
      **  *    * *  = ** * ***** 
  *  ** *  * * * * * **  ** 
}
 *   *    * ** * **   ****       ** * **
** *  * *   * * 0;

Comments

prog.c: In function 'main':
prog.c:19:2: error: expected declaration or statement at end of input
  return 0;
  ^~~~~~

---

Great job using an array and a loop. There are two mistakes found in your code. Please check
1.     printf("\n\n%s", code);  <--- in order to make it match the fixed output '\n\n' should be deleted
2.     At the end of your code, there's something missing.

Answer 6

Hidden content!
** *  *  ** *    * *    *
 
**** * *  *     ***   ***

*  * *  ** ** **        * *     * ** *  ** ** * * *  **  **   * *  * * *  * ** * **

* ** *   * *   *     * *    
 
*   **    *  

 *         *    *
*
* * * *  * * **   * ******  *    *   * * **  * *     **  *   ***  **  

 * = *   **
*
      b + 

*  = c +   

   = d + *
*
** *      
*
* * * * * ** ***     *  * *     *  
*
  *    

 

Comments

It's correct lol you can't judge me

---

Well, that's because your output doesn't match with the fixed answer. Please take a look at this
printf("%c%c%c%c%c\n", a1, b1, c1, d1, e1);

Hint: You should delete something  :)

By the way, great job.

---

printf("%c%c%c%c%c", a1, b1, c1, d1, e1);

How's that?

---

That's correct.

Answer 7

Hidden content!
** *    *** **       
*   ** *  * * **** *  *    

int *** ** argc, char *  *  {
   **    * *  *    char *** 
* ***         *  char *   *
 **    **  *  char  **   
*   **  ***  char  ** *  
 * * *   ** char   * * 
 ***       * 
  * *   **  **     *** *****   input the letter to * * ** **  * **
 * ***  *** * 
 **      * ***     **** *  * * **** * * **     ***     *       * *** ** ***  **  *      **  *   ** *  ****
 * **** *****     *  =   ***  + 3;
 * * *   **  ** *  * ** =  *** * + 3;
  **  *  * *  * *  * =   *   + 3;
   *  *    * * letterc =       + 3;
   ****    ****  * **   = *   + 3;
*  *   * ***     
 *     * ****  * ** ***  ** * * ***  * ** * * **  *  ** * **    * ****  *** *** 
  *** ***      * * 
* *** *** *****  *** return 0;
}

Comments

-----------Re-judge-----------
Case 0: Wrong output

---

Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     hello

Anyway, great job. Full marks.

Answer 8

Hidden content!
***** * * * ***     * *
**  ** ** ** * ** ***

int ***** argc, char *argv[]) {
      ** **** *  *  char  ** **
* **** * * ***** char letteri;
* *** *   * *** char **  *
 ** *   *    **** char   *  * 
* * **     *** char * **
**** *** **       
   *    *  **      * * * *** * input the letter to encode:   * * **      ***
   *   **** *** 
 ***    *  **** **  ** *   ***** ** * **  *** **    ****  *  ***      * * ** * **  *   **  *    *      * 
* **        **  *    *     +3;
    *    *  **   ******  * +3;
 **  **  **   *   ** ***** +3;
** ***      * *  **      +3;
** * * *  *  * **** * * * +3;
  **      *   
**  * * *  *  
*       **      *** * *  *** ***** * ***      * ***   ****     *  **
*   **  * *  * 
***** *  * * * return 0;
}


INPUT
******  **    *  *
*  * **** ** ***
OUTPUT
   **  *    * *  

Comments

Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     hello

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.

---

prog.c:27:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:30:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:30:1: error: unknown type name 'OUTPUT'

Answer 9

Hidden content!
* * *** * *** ** ***  *  
*   *        *** *  * 

int  * *  argc, char *  ***   {
*  * *  * ****** char     
* ****  * char   * 
   *   *   char   *
*  *  *   *   * char   * 
* ***   *** ** char  * 
  *    **  ** 
 **   **  * *   * *** ** **** input the  *  to *    ***** * **   *
 *   ***** 
*** ***  * *   **   **  **** * **** **  ** * * *  *     ** * ** *    *    *   *     * ** *** *    ** *
*** ** * *  * ** 
       * ****  * * letter = letter + 3;
** *   *** **   ** = *   * + 3;
 ** *  * **** * ** *** =      + 3;
 ********      **       =   ** + 3;
 **  * **   * ** **   =  * * + 3;
 *   ***   *  
  *   ** **    * *       *     ** letter is  *  *   * **  * *  * ***   *      **  *   
**  *** *     * 
 * **      ** return 0;
}

INPUT
**  *  ** ** **
*** * *  *
** *
   ** *   * ** *  

Comments

Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     The encrypted letter is hello

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.

---

prog.c:26:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:29:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:29:1: error: unknown type name 'OUTPUT'

Answer 10

Hidden content!
#include  * ** ** ********  

int main(int argc, char *argv[]) {
*  *   **    ***   ***  ****** *  lettera;
  ***  * *  *** *     *****   letterb;
  * **  * *** ** * **** *** letterc;
 * **** **    * *  **       ** *  letterd;
* ** ******* *  ** * *** lettere;
*  * *  ***  ** *   **   * ** 
 **  *    ** *      * * *****    %c %c %c     ****  ** ** * ***       ** * ** * *    *   * *   *     ** **    
*** * * *     * ***   ** *   * * = lettera + 3;
    ****  ** * ** * **** *******  = letterb + 3;
    *    **** * * *** * *  ** *  = letterc + 3;
***   ** **       **  *  ****  **   = letterd + 3;
*  ** ** *  **** *   ** **** * = lettere + 3;
  **  ***  **       *        **** ****  ** *  *   
 * *** *** ****   ***   ****   **********  %c %c %c  *** **  *  *****  letterb,   **  ***     * **
 *** *** * ****   **** *   
 *   **   ***   ***    * *  * 0;
}

  **  *
* *   **
     ** ***   
 *** 
//hello

Comments

Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: e b i i l
     h e l l o

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.

---

prog.c:25:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:28:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:28:1: error: unknown type name 'OUTPUT'

---

prog.c: In function 'main':
prog.c:10:5: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
     scanf("%c %c %c %c %c", &lettera, &letterb, &letterc, &letterd, &lettere);
     ^~~~~
prog.c:10:5: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:10:5: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:17:5: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
     printf("%c %c %c %c %c", lettera, letterb, letterc, letterd, lettere);
     ^~~~~~
prog.c:17:5: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:17:5: note: include '<stdio.h>' or provide a declaration of 'printf'