[Exercise 03] Caesar Cipher Decoder

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You have received an encrypted message from Julius Caesar-- the message is ebiil.  You are asked to decipher the message in order to understand what Caesar trying to say to you.

Hint

Luckily, Caesar has given you a hint, he says: 'I, myself, encoded the message by shifting every word backwards by 3.' 

Solution

Write a program that receives 5 characters 'ebiil'. Then decode those characters into 5 new characters.

Example

#include <stdio.h>

int main(int argc, char *argv[]) {


	char a;
    	char b;
	 	
	scanf("%c%c", &a, &b);
	
	//decode the message how??
	
	printf("%c%c", a,b);
	
	return 0;
}

Input

ebiil

 

 

 

 

 

 

 

 

 

 

Output

hello

** REMEMBER ** 
This is an online-compiler, don't put anything except the codes. If you want to make a comment, please use // or /* */

[Exercise] Coding (C) - asked in Chapter 2: Syntax structure of the C language by (5.9k points)
ID: 26955 - Available when: Unlimited - Due to: Unlimited
edited by | 6.5k views

22 Answers

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Hidden content!
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****    ****  return 0;
}
100/100 answered by (449 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
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100/100 answered by (153 points)
0 0
Case 0: Correct output
Case 1: Wrong output
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
#include  *  ** *  **
#include **    *  ** * * **

/* run this program using the console pauser or add your own getch,   * ** * **  ***   *** or input loop */

int main(int argc, char *argv[]) {
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** * ****  **  **  ***      = e+3;
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   **  ***** *  *****   *  * 
 ** * * *   * * **        * ** 0;
}
100/100 answered by (281 points)
edited by
0 0
Your program receives only 2 characters, and it doesn't move characters' positions.

Try to make it receive 5 characters, and move their positions forward by 3.
commented by (5.9k points)
0 0
This exercise expects only 'hello'. However, your code has.....

printf("Put the words you want to decode:");

Kindly consider delete this part :)
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
*    *  *    **  *       * 
* ** * **  ** *** *  **

int    ** *   *  char * **  {
/*
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a = a+3;
b = * *
c =   *
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}
100/100 answered by (273 points)
edited by
0 0
prog.c:28:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:32:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:32:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
0 0
Your program can end at
  
    return 0;
}
------------------------------------------
You don't need to put

INPUT

ebiil

OUTPUT

hello
commented by (5.9k points)
0 0
Case 0: Correct output
Case 1: Wrong output
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
 **            **  * 
**** **    *   ****** 

/* run this * *  * the    *  *** or add your own     *** * * ****  * ****    * or  **      */

int  *  *  * char ** ***  {
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}
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    * * *  *       *** 0;
50/100 answered by (252 points)
0 0
prog.c: In function 'main':
prog.c:19:2: error: expected declaration or statement at end of input
  return 0;
  ^~~~~~
commented by (4.3k points)
0 0
Great job using an array and a loop. There are two mistakes found in your code. Please check
1.     printf("\n\n%s", code);  <--- in order to make it match the fixed output '\n\n' should be deleted
2.     At the end of your code, there's something missing.
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
*** *   ***   **  * 
 
 **   *   ******    *  *
*
**     * *   * * ** * ** * *  * ***    * **   **  *    *  *  *** * ***  *   **  **   

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*  =     

*   * b + * 

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*   = d + 
 
      *   

******** ** ** *   *** ****  * *       *   **

     *
100/100 answered by (268 points)
0 0
It's correct lol you can't judge me
commented by (268 points)
0 0
Well, that's because your output doesn't match with the fixed answer. Please take a look at this
printf("%c%c%c%c%c\n", a1, b1, c1, d1, e1);

Hint: You should delete something  :)

By the way, great job.
commented by (5.9k points)
0 0
printf("%c%c%c%c%c", a1, b1, c1, d1, e1);

How's that?
commented by (268 points)
0 0
That's correct.
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
* ***   ****  *
**  **  ** * *   **** ** ** *

int  **** argc, char  * * {
**  * *** ** char *   * 
* ** **   ****  * char ** **
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*   *    *   *  *  *** ** *  input the letter to    *  ****  *
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  * *  *     ** letterc = * * + 3;
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* *  *  * **  ** 
   *   **  * * *   ***  *  *  ** * * * *   *      *  *        *   *  ** ** * * ** 
* * **   *  ** 
 * **      *  *** return 0;
}
100/100 answered
reshown by
0 0
-----------Re-judge-----------
Case 0: Wrong output
commented by (4.3k points)
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     hello

Anyway, great job. Full marks.
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
   **  * ** *  * * 
 * *    * **** * **

int *** *  argc, char *argv[]) {
**** ** *    *    char  ***
* * *** ****   char letteri;
 **** *  *    * char **** * 
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**      ****  * 
*     * * * * ** **  ******      * *  ** ***  * ********    ** *** *   *    **     * **   *   * *** *** * *
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* *  * * ***  * *    * +3;
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***  *    **  
** ** * ***** return 0;
}


INPUT
 ** *** ***    
  **** * **  **
OUTPUT
* ** * ** *   * *    **
100/100 answered by (269 points)
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     hello

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
commented by (5.9k points)
0 0
prog.c:27:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:30:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:30:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
 *    ****  *** *  
 ** **    **** *  ****** *

int ** **  argc, char *  *  *  {
 * *  ***  ****  char  * * 
 **  ****   *  char *   * 
**  ***      * *  char  **  *
***** *  **** char * ** *
 *  *      *  ** * char *******
 ** **   *   **  
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**  *  *  ** 
** ** *    **   * ****  ** *  * *   *  *  * *   ***    *  * **  ****      * * **** *   *  *  **
* ***       * 
     * **  ***     letter = letter + 3;
 *   **  * **** * *** = * ** * + 3;
 * ** *  * ** * ** =  ***  + 3;
 ****  * **     * * = **** + 3;
* *  * ***      * ** =   *  *  + 3;
**    ** * **   
    **  **** ** * * *  *    **    letter is ***** * **     ** **  ****   *  *    * * 
* *    * * **  * 
  *    * ***   * return 0;
}

INPUT
*   * *  ** **** 
     * *  ** 
 *  
**** * *****  ** *
100/100 answered by (290 points)
reshown by
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     The encrypted letter is hello

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
commented by (5.9k points)
0 0
prog.c:26:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:29:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:29:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
#include ***  **  *   **

int main(int argc, char *argv[]) {
  **     * ** *     ** * lettera;
*    ** ***** ** ******   **  letterb;
***   * **  * *** *   *** *    letterc;
**** **  **  ** **    ** * * letterd;
  ****  ****  *   *  *  ****  lettere;
** ***** **     **  *** 
  * **   * * *      ***        ** ** %c %c %c *   *     ** * *   *** **  *      ***  ***  *   **** *** *   *** *** *** 
*  ** ****  *** **** **    = lettera + 3;
  ***** *  * ** **   * ** ***  * = letterb + 3;
    *   * * *** ** * *  * * *   * = letterc + 3;
    * * **** *  *******     **   **  = letterd + 3;
   * * * *    *  *** *   **** ** = lettere + 3;
 * **** * ****    **** * *  **  ***  *********  ** *  * *
****** * **  **** ** *  * **  * **    * %c %c %c * **  *  * ***   letterb,  *** *       * *  
  * * *********  *   **  
* ** **** *** ***** ** **   *** 0;
}

 * **
*   **
 ****   * * * 
*** *
//hello
100/100 answered by (271 points)
edited by
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: e b i i l
     h e l l o

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
commented by (5.9k points)
0 0
prog.c:25:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:28:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:28:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:10:5: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
     scanf("%c %c %c %c %c", &lettera, &letterb, &letterc, &letterd, &lettere);
     ^~~~~
prog.c:10:5: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:10:5: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:17:5: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
     printf("%c %c %c %c %c", lettera, letterb, letterc, letterd, lettere);
     ^~~~~~
prog.c:17:5: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:17:5: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
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