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You have received an encrypted message from Julius Caesar-- the message is ebiil.  You are asked to decipher the message in order to understand what Caesar trying to say to you.

Hint

Luckily, Caesar has given you a hint, he says: 'I, myself, encoded the message by shifting every word backwards by 3.' 

Solution

Write a program that receives 5 characters 'ebiil'. Then decode those characters into 5 new characters.

Example

#include <stdio.h>

int main(int argc, char *argv[]) {


	char a;
    	char b;
	 	
	scanf("%c%c", &a, &b);
	
	//decode the message how??
	
	printf("%c%c", a,b);
	
	return 0;
}

Input

ebiil

 

 

 

 

 

 

 

 

 

 

Output

hello

** REMEMBER ** 
This is an online-compiler, don't put anything except the codes. If you want to make a comment, please use // or /* */

[練習] Coding (C) - 最新提問 分類:Chapter 2: Syntax structure of the C language | 用戶: (5.9k 分)
ID: 26955 - 從幾時開始: 無限制 - 到幾時結束: 無限制

修改於 用戶: | 5.6k 瀏覽

22 個回答

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內容已隱藏
#include<stdio.h>

int main (int argc,char *argv)
{
    char a;
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* **** * * * * ** * * * ** ******** ** ** * *
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}
100/100 最新回答 用戶: (244 分)
0 0
Case 0: Correct output
Case 1: Wrong output
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內容已隱藏
#include **** ***** * *
int main(int argc, char *argv[]) {


** char a;
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}
100/100 最新回答 用戶: (221 分)
0 0
prog.c: In function 'main':
prog.c:10:2: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
  scanf("%c%c%c%c%c", &a, &b, &c, &d, &e);
  ^~~~~
prog.c:10:2: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:10:2: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:14:2: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
  printf("%c%c%c%c%c", a+3,b+3,c+3,d+3,e+3);
  ^~~~~~
prog.c:14:2: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:14:2: note: include '<stdio.h>' or provide a declaration of 'printf'
0 0
Case 0: Correct output
Case 1: Wrong output
0 喜歡 0 不喜歡
內容已隱藏
int main(int argc, char *argv[]) {


* *   char a;
**** * *** * * * * * * * * b;
* **** * * char c;
* *** * **** * * * *** * * d;
* * * * * ** * * * e;
*** * ** *** **** * * * ******  
    * * ** %c %c %c %c ** ** * **** * ***** * *** * ***** *
** *  
    * * ** ***** * * ** ** *** ** * * ** ** ** **** ** *** *
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*   * *** **** ** *** *
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* **** ** *** * * * *
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* * * **** ** ** ** * * * * *** ** * *
** ** * * * ** *
** * * * * ** 0;
}
50/100 最新回答 用戶: (244 分)
0 0
prog.c: In function 'main':
prog.c:10:2: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
  scanf("%c %c %c %c %c %c", &a, &b,&c, &d,&e);
  ^~~~~
prog.c:10:2: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:10:2: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:10:25: warning: format '%c' expects a matching 'char *' argument [-Wformat=]
  scanf("%c %c %c %c %c %c", &a, &b,&c, &d,&e);
                         ^
prog.c:12:6: warning: assignment makes integer from pointer without a cast [-Wint-conversion]
  if(a="e",b="b",c="i",d="i",e="l")
      ^
prog.c:12:12: warning: assignment makes integer from pointer without a cast [-Wint-conversion]
  if(a="e",b="b",c="i",d="i",e="l")
            ^
prog.c:12:18: warning: assignment makes integer from pointer without a cast [-Wint-conversion]
  if(a="e",b="b",c="i",d="i",e="l")
                  ^
prog.c:12:24: warning: assignment makes integer from pointer without a cast [-Wint-conversion]
  if(a="e",b="b",c="i",d="i",e="l")
                        ^
prog.c:12:30: warning: assignment makes integer from pointer without a cast [-Wint-conversion]
  if(a="e",b="b",c="i",d="i",e="l")
                              ^
prog.c:14:2: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
  printf("hello");
  ^~~~~~
prog.c:14:2: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:14:2: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:18:5: warning: incompatible implicit declaration of built-in function 'printf'
     printf("errol");
     ^~~~~~
prog.c:18:5: note: include '<stdio.h>' or provide a declaration of 'printf'
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內容已隱藏
* * ** * * ***** **

* ** * {

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* * * ** **** * * ** * *
100/100 最新回答 用戶: (183 分)
0 0
Case 0: Correct output
Case 1: Wrong output
0 喜歡 0 不喜歡
內容已隱藏
** * * **** *

* *** * * *** *** {

* * ** *
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** = *****
* = *** * **

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*** *
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* * ** * **** * **** * *
100/100 最新回答
0 0
Case 0: Correct output
Case 1: Wrong output
0 喜歡 0 不喜歡
內容已隱藏
#include ** *
#include ** *** * ** * ** *

int main(int argc, char *argv[]) {
* **** * * * * *** * *** ** letterj;
* *** ** ** ** *** * * letteri;
* * * * ** ** ** * letterm;
** **** * * *** * *** **** lettere;
** * * * * * * * ** * lettern;
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** ** ** * * *** ** ***** input the letter to encode: ");  
*** *** ** **** **
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** * *** ** * * ** *** * * +3;
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* * ** * **** * ** *** *** **** +3;
**** *** * ** *** *** * ** +3;
* ** **** * * ** *
** * * * ** **** * **
** * *** ** * * ** * ** * * * *** ** * ** ** **** lettere, lettern);
*** ** * * * *** * *
* ** ** ******* * *** * *** 0;
}


INPUT
** * * ***
* * *** *
OUTPUT
***** ** * ** *
100/100 最新回答 用戶: (243 分)
0 0
prog.c:27:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:30:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:30:1: error: unknown type name 'OUTPUT'
0 喜歡 0 不喜歡
內容已隱藏
** * *** * * ****

int * argc, char {


** *** * * char a;
*** *** * * * *** **** ** *** * * char b;
** ** * ** * * * ** * ***
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* * * * *
* * * * * ** the ** * how??
** **
* * * * ** * ** * * a,b);
***** * *****
* * ** ** * * * 0;
}
50/100 最新回答
0 0
Case 0: Wrong output
Case 1: Wrong output
0 喜歡 0 不喜歡
內容已隱藏
#include * * ** **

int main(int argc, char *argv[])
{
** ** * letterj;
* ** ** * ** * * * * * *** * letteri;
*** **** ** ******** *** letterm;
***** * * **** * * * ** * ** lettere;
** * * * * * *** ** lettern;
** *** * *** * ** ***
**** * *** * ** ***** * * * ** **** * input the letter to encode: ** * * ***
* ***** *** * * * *** * ***** ***** *** **** ** * *** *** * * * * * * *** * *********
** * * * ** * ** **
** * * ** *** * * * * **** = letterj +3;
* * **** * ****** * *** ** = letteri +3;
* ** *** * *** * * ** * * ** = letterm +3;
* * * ** ***** *** ** * = lettere +3;
* * * ** ** ** *** ** = lettern +3;
** * **** * * *
* * ** * **** * * ** * ** * * *** * ** * *** * lettere, lettern);
* * ** * * ** ***** *

* * ** * * * ** 0;
}
100/100 最新回答 用戶: (220 分)
0 0
Case 0: Wrong output
Case 1: Wrong output
0 喜歡 0 不喜歡
內容已隱藏
** ** * **

* * * * * * * * {

** *
= *** * *
= * *
i = *** ***
* = ***
* = ***
e =
= **
** = *
= **

* **
* **
* ****
* * *
* ** *

****** * * * **** ** *** *
*
100/100 最新回答 用戶: (283 分)
修改於 用戶:
0 0
prog.c:1:16: fatal error: stdio: No such file or directory
 #include<stdio>
                ^
compilation terminated.
0 0
prog.c: In function 'main':
prog.c:6:5: error: 'cin' undeclared (first use in this function)
     cin >> a;
     ^~~
prog.c:6:5: note: each undeclared identifier is reported only once for each function it appears in
prog.c:11:5: error: 'cout' undeclared (first use in this function)
     cout << a << endl << endl;
     ^~~~
prog.c:11:18: error: 'endl' undeclared (first use in this function)
     cout << a << endl << endl;
                  ^~~~
0 0
prog.c: In function 'main':
prog.c:6:11: warning: too many arguments for format [-Wformat-extra-args]
     scanf("c", &a);
           ^~~
prog.c:11:14: warning: format '%c' expects argument of type 'int', but argument 2 has type 'char *' [-Wformat=]
     printf("%c", a)
              ^
prog.c:12:5: error: expected ';' before 'return'
     return 0;
     ^~~~~~
0 0
prog.c: In function 'main':
prog.c:6:11: warning: too many arguments for format [-Wformat-extra-args]
     scanf("c", &a);
           ^~~
prog.c:11:14: warning: format '%c' expects argument of type 'int', but argument 2 has type 'char (*)[5]' [-Wformat=]
     printf("%c", &a);
              ^
0 0
Case 0: Correct output
Case 1: Wrong output
0 喜歡 0 不喜歡
內容已隱藏
#include ***** *** *
#include ** ********

int main(int argc, char *argv[]) {
* ** ** *** * *** * * letterj;
********* * ** ** * letteri;
* * ******* * ******** *** * letterm;
* * **** ** * * ** lettere;
***** * **** * ** ** ** ** lettern;
*** * ** *** * ****
* * * *** **** * *** **** ** *** input the letter to encode: * * * *  
** * ** * * * ** * ** * *** * **** * ** ** ** ** *** ** * * **** ** *** * ***** ** * * * * ***** * * * * **
** * * *** * * *
*** * ** letterj = letterj +3;
*** * * **** * ** * * * ** = letteri +3;
** *** *** * *** **** **** = letterm +3;
* * ** * * * * *** *** = lettere +3;
** * *** ** * * ******* * = lettern +3;
**** **** ******** ** *******
* *** * **** ** ******** * * ** * * * *** * ** * * *** ** lettere, lettern);
* * *
**** * * ** ** ** ** 0;
}
100/100 最新回答 用戶: (220 分)
0 0
Case 0: Wrong output
Case 1: Wrong output
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[正常] 開放式問答 - 最新提問 12月 12, 2017 分類:Chapter 2: Syntax structure of the C language | 用戶: 許哲瑋 (449 分)
ID: 37081 - 從幾時開始: 無限制 - 到幾時結束: 無限制
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