3 喜歡 0 不喜歡
9.6k 瀏覽

You have received an encrypted message from Julius Caesar-- the message is ebiil.  You are asked to decipher the message in order to understand what Caesar trying to say to you.

Hint

Luckily, Caesar has given you a hint, he says: 'I, myself, encoded the message by shifting every word backwards by 3.' 

Solution

Write a program that receives 5 characters 'ebiil'. Then decode those characters into 5 new characters.

Example

#include <stdio.h>

int main(int argc, char *argv[]) {


	char a;
    	char b;
	 	
	scanf("%c%c", &a, &b);
	
	//decode the message how??
	
	printf("%c%c", a,b);
	
	return 0;
}

Input

ebiil

 

 

 

 

 

 

 

 

 

 

Output

hello

** REMEMBER ** 
This is an online-compiler, don't put anything except the codes. If you want to make a comment, please use // or /* */

[練習] Coding (C) - 最新提問 分類:Chapter 2: Syntax structure of the C language | 用戶: (5.9k 分)
ID: 26955 - 從幾時開始: 無限制 - 到幾時結束: 無限制

修改於 用戶: | 9.6k 瀏覽

22 個回答

0 喜歡 0 不喜歡
內容已隱藏
#include<stdio.h>

int main (int argc,char *argv)
{
    char a;
* * ******* * ** ** * b;
* ** ** ** * ** *** ** ** c;
* ** * ** * **** * * ** * d;
*** *** **** ***** e;

* **** * ** * ** ** * * * ** ** *** * *** * * * * ** *****

* *** * ** * * * * *
* ** * **** * ** ** * **
** * * ** * * * *** *** * *
*** *** *** * ***** * **
* ** ** * * * ***

**** ** ** ** * **** ***** * **** * ** *** ** ** ***
****** ** * ** ** 0;
}
100/100 最新回答 用戶: (244 分)
0 0
Case 0: Correct output
Case 1: Wrong output
0 喜歡 0 不喜歡
內容已隱藏
#include * * ** * *
int main(int argc, char *argv[]) {


* * * * * char a;
**** ** * * * *** *** b;
* ** ** ****** * ** * * ** c;
** *** * ** **** * ** d;
* * * * * ** * e;
* * * *** * ***** * * ***
** ** ** * ** * * ******* * * * ** ** ******* * **** * ** * * **
** * *
* * * * the message how??
* * ** * *
* * * ** * ** * ** * * *** ** * * * ** * **
** ** ** ***
*** * ** return 0;
}
100/100 最新回答 用戶: (221 分)
0 0
prog.c: In function 'main':
prog.c:10:2: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
  scanf("%c%c%c%c%c", &a, &b, &c, &d, &e);
  ^~~~~
prog.c:10:2: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:10:2: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:14:2: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
  printf("%c%c%c%c%c", a+3,b+3,c+3,d+3,e+3);
  ^~~~~~
prog.c:14:2: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:14:2: note: include '<stdio.h>' or provide a declaration of 'printf'
0 0
Case 0: Correct output
Case 1: Wrong output
0 喜歡 0 不喜歡
內容已隱藏
int main(int argc, char *argv[]) {


** ***   char a;
* * * * * ** * *** **** b;
* ** ** * * char c;
* * * * * ** * * * d;
* **** * ** *** *** ** ** e;
* * * * * * * * ** * * * ***  
    *** **** *** %c %c %c %c *** * * * * * **** *** *****
* *  
    *** * * ** * **** ** * * *** *** * ***** * * ** **** ** * ** **
* ** *** ** * ***
**** **   *** * * * * * * **
* * * * * *** *
*** * * ** ** **** *** **
** ** *** * ** * ** *
** ******** *** * * * * ** * * * *** **
** * ** ** * * * *
**** ** ** ** 0;
}
50/100 最新回答 用戶: (244 分)
0 0
prog.c: In function 'main':
prog.c:10:2: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
  scanf("%c %c %c %c %c %c", &a, &b,&c, &d,&e);
  ^~~~~
prog.c:10:2: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:10:2: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:10:25: warning: format '%c' expects a matching 'char *' argument [-Wformat=]
  scanf("%c %c %c %c %c %c", &a, &b,&c, &d,&e);
                         ^
prog.c:12:6: warning: assignment makes integer from pointer without a cast [-Wint-conversion]
  if(a="e",b="b",c="i",d="i",e="l")
      ^
prog.c:12:12: warning: assignment makes integer from pointer without a cast [-Wint-conversion]
  if(a="e",b="b",c="i",d="i",e="l")
            ^
prog.c:12:18: warning: assignment makes integer from pointer without a cast [-Wint-conversion]
  if(a="e",b="b",c="i",d="i",e="l")
                  ^
prog.c:12:24: warning: assignment makes integer from pointer without a cast [-Wint-conversion]
  if(a="e",b="b",c="i",d="i",e="l")
                        ^
prog.c:12:30: warning: assignment makes integer from pointer without a cast [-Wint-conversion]
  if(a="e",b="b",c="i",d="i",e="l")
                              ^
prog.c:14:2: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
  printf("hello");
  ^~~~~~
prog.c:14:2: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:14:2: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:18:5: warning: incompatible implicit declaration of built-in function 'printf'
     printf("errol");
     ^~~~~~
prog.c:18:5: note: include '<stdio.h>' or provide a declaration of 'printf'
0 喜歡 0 不喜歡
內容已隱藏
* ** ** *** * *

* * * * * ** * * {

* * *
= * * ** *
* = ** *
* = ** ** **
* = ****
** = *

e = *
* = *
* =
= **

** * *
* * *
*** *
* * **
* * * ***

** **** *** * ** * ******* *
*
100/100 最新回答 用戶: (183 分)
0 0
Case 0: Correct output
Case 1: Wrong output
0 喜歡 0 不喜歡
內容已隱藏
* ** * *** *

* ** * *** ** * {

* * *
= * ****
* = * * * *
* = *
** = *** *
** = ** * * *

e = **
* = *
* = **
* = **

** ***
* *
* * *

* * * *

* * * * * ** * ** ***** **
**
100/100 最新回答
0 0
Case 0: Correct output
Case 1: Wrong output
0 喜歡 0 不喜歡
內容已隱藏
#include ** ******
#include ** ** * * *

int main(int argc, char *argv[]) {
*** ** * * * ** ** * letterj;
* * * * * * *** * ***** * letteri;
** * ** ***** * * *** * ***** letterm;
* * ** * * * ** lettere;
* * * * ** ***** lettern;
* * ** * ** * ** * * *
* ** ** ** * * ** * * ** ** ** input the letter to encode: ");  
* * ** * * * * *
* * * * ** * * ***** * **** * ********** ** * * * &letterj, * * * **** &letterm, ** * ** ** ** * * * *
* ***** ** * * * * * * * * +3;
* * * *** * * **** * *** +3;
* * * ** ** * * **** *** * * +3;
*** * ****** * * * * ** **** +3;
* ** ** * ***** ** * * +3;
* *** * * ** * ***
* ****** * ***** * * * *
** **** * * ** ** ** * * * *** **** ** **** ****** * lettere, lettern);
** * * * * *
** * * * *** * * * * 0;
}


INPUT
** * **
* *
OUTPUT
* * ** * *
100/100 最新回答 用戶: (243 分)
0 0
prog.c:27:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:30:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:30:1: error: unknown type name 'OUTPUT'
0 喜歡 0 不喜歡
內容已隱藏
**** *** *** ****

int * * argc, char * * {


** * *** char a;
**** *** ** *** **** **** ** *** char b;
* * * * ** * *** ** * * ****
**** * ** * * * ***** * * * * * * * ** *** *
** * *
* ** ** ** * the * ** how??
** ** * *
* **** ** * * ** *** * * ** a,b);
***** ***
** * ** * ** 0;
}
50/100 最新回答
0 0
Case 0: Wrong output
Case 1: Wrong output
0 喜歡 0 不喜歡
內容已隱藏
#include ****** **** *

int main(int argc, char *argv[])
{
** **** * **** letterj;
* * * * **** ** * ** * ** letteri;
** * ** * *** ** **** ** * * letterm;
* ***** * **** * ** *** lettere;
** * ****** * * *** * * lettern;
***** ** *** ** *
* * ** ** **** ** * * input the letter to encode: * * * ** *
* ** * * ** **** *** * ** * *** ** * *** * *** * * ** ** * * ******* * * * * ***
** * * * *** * * *
*** **** ** **** * ** = letterj +3;
* * * ** ** * *** = letteri +3;
* ** ** **** ** * **** ** = letterm +3;
** ** *** ** ** * * ** ** = lettere +3;
** **** * * * ***** ** = lettern +3;
* * * ** * *** *** **
** *** ** * ** ** * ******** *** ** * * ** ** lettere, lettern);
** ***** * ** **

* * * * * ** 0;
}
100/100 最新回答 用戶: (220 分)
0 0
Case 0: Wrong output
Case 1: Wrong output
0 喜歡 0 不喜歡
內容已隱藏
** * ** ** ****

* * ** ** * * ****** {

* * *** **
= *** ***
= ** *
i = * *
* = * ** **
* = ******
e =
* = **
* = *
* =

* ****
* * *
*** ***
* ****
* * * ***

* ** ** ***** * * *** **** * ***
100/100 最新回答 用戶: (283 分)
修改於 用戶:
0 0
prog.c:1:16: fatal error: stdio: No such file or directory
 #include<stdio>
                ^
compilation terminated.
0 0
prog.c: In function 'main':
prog.c:6:5: error: 'cin' undeclared (first use in this function)
     cin >> a;
     ^~~
prog.c:6:5: note: each undeclared identifier is reported only once for each function it appears in
prog.c:11:5: error: 'cout' undeclared (first use in this function)
     cout << a << endl << endl;
     ^~~~
prog.c:11:18: error: 'endl' undeclared (first use in this function)
     cout << a << endl << endl;
                  ^~~~
0 0
prog.c: In function 'main':
prog.c:6:11: warning: too many arguments for format [-Wformat-extra-args]
     scanf("c", &a);
           ^~~
prog.c:11:14: warning: format '%c' expects argument of type 'int', but argument 2 has type 'char *' [-Wformat=]
     printf("%c", a)
              ^
prog.c:12:5: error: expected ';' before 'return'
     return 0;
     ^~~~~~
0 0
prog.c: In function 'main':
prog.c:6:11: warning: too many arguments for format [-Wformat-extra-args]
     scanf("c", &a);
           ^~~
prog.c:11:14: warning: format '%c' expects argument of type 'int', but argument 2 has type 'char (*)[5]' [-Wformat=]
     printf("%c", &a);
              ^
0 0
Case 0: Correct output
Case 1: Wrong output
0 喜歡 0 不喜歡
內容已隱藏
#include * * *****
#include * * * * **

int main(int argc, char *argv[]) {
** * * * * letterj;
* * * ** * *** * * *** * letteri;
* ** ** * * ***** *** letterm;
* *** ** *** *** lettere;
******* ** *** ** ** lettern;
* * ******* ****
* ** ** * ** * ** * * ** ** ** *** input the letter to encode: ** ***  
** *** ** *** * * ** * ** ** * * *** * ****** **** * **** ** *** * * * ** * * **** *** ****** ** ** *** **** * *** ***
**** ** *** ** * * * *
* ****** * * * letterj = letterj +3;
** * **** **** ** * ***** * = letteri +3;
* ** * * ***** * * * = letterm +3;
* * ******* ** * * ***** = lettere +3;
** ** * * ** **** *** = lettern +3;
** * * * * *** * * *
** ****** *** ** ** *** *** *** ** **** * ** ** ** * * * ** lettere, lettern);
*** * * ** ** ** *
** *** * ** ***** ** ** 0;
}
100/100 最新回答 用戶: (220 分)
0 0
Case 0: Wrong output
Case 1: Wrong output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:104.23.243.109
©2016-2026

相關問題

0 喜歡 0 不喜歡
2 回答
[正常] 開放式問答 - 最新提問 12月 12, 2017 分類:Chapter 2: Syntax structure of the C language | 用戶: 許哲瑋 (449 分)
ID: 37081 - 從幾時開始: 無限制 - 到幾時結束: 無限制
| 1.3k 瀏覽
12,783 問題
183,442 回答
172,219 留言
4,824 用戶