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You have received an encrypted message from Julius Caesar-- the message is ebiil.  You are asked to decipher the message in order to understand what Caesar trying to say to you.

Hint

Luckily, Caesar has given you a hint, he says: 'I, myself, encoded the message by shifting every word backwards by 3.' 

Solution

Write a program that receives 5 characters 'ebiil'. Then decode those characters into 5 new characters.

Example

#include <stdio.h>

int main(int argc, char *argv[]) {


	char a;
    	char b;
	 	
	scanf("%c%c", &a, &b);
	
	//decode the message how??
	
	printf("%c%c", a,b);
	
	return 0;
}

Input

ebiil

 

 

 

 

 

 

 

 

 

 

Output

hello

** REMEMBER ** 
This is an online-compiler, don't put anything except the codes. If you want to make a comment, please use // or /* */

[練習] Coding (C) - 最新提問 分類:Chapter 2: Syntax structure of the C language | 用戶: (5.9k 分)
ID: 26955 - 從幾時開始: 無限制 - 到幾時結束: 無限制

修改於 用戶: | 4k 瀏覽

22 個回答

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內容已隱藏
#include<stdio.h>

int main (int argc,char *argv)
{
    char a;
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** ** * ** *** * ** *
** *** * * * ** * *

** * **** * * * * **** * *** ** * * ** ****
* **** ** ** * ** * * * * * 0;
}
100/100 最新回答 用戶: (244 分)
0 0
Case 0: Correct output
Case 1: Wrong output
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內容已隱藏
#include ******** ***
int main(int argc, char *argv[]) {


* * * * ** char a;
*** ****** * **** * * b;
* * ** * ** * * * * ** * c;
* *** * * *** * ** * ** * d;
* **** * * * e;
* *** ** ** * ***** * ** ** ***
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** * ** * *
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* * * *
****** ** ** *** * * * * ** * * ******
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* * * * * return 0;
}
100/100 最新回答 用戶: (221 分)
0 0
prog.c: In function 'main':
prog.c:10:2: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
  scanf("%c%c%c%c%c", &a, &b, &c, &d, &e);
  ^~~~~
prog.c:10:2: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:10:2: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:14:2: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
  printf("%c%c%c%c%c", a+3,b+3,c+3,d+3,e+3);
  ^~~~~~
prog.c:14:2: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:14:2: note: include '<stdio.h>' or provide a declaration of 'printf'
0 0
Case 0: Correct output
Case 1: Wrong output
0 喜歡 0 不喜歡
內容已隱藏
int main(int argc, char *argv[]) {


* *   char a;
* ** * **** * ** b;
* *** *** * char c;
* ** * ** *** d;
** * * ** ** ** * * e;
** *** ** ** ** *** * *** * *  
    * * * %c %c %c %c *** ** **** **** *** ** * **
* **  
    * *** **** * **** *** * * ** * ***** ** *** * **** ** ** * **** *
* ** * *** *** * ***
*****   *** **** * *
* *** *** ** ****** * *
***** * * * **** * *
**** ** * * * * *
* ** * *** * * ** ** * ** * ****
* * **** ****** * * * ****
* * **** * ** ** 0;
}
50/100 最新回答 用戶: (244 分)
0 0
prog.c: In function 'main':
prog.c:10:2: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
  scanf("%c %c %c %c %c %c", &a, &b,&c, &d,&e);
  ^~~~~
prog.c:10:2: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:10:2: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:10:25: warning: format '%c' expects a matching 'char *' argument [-Wformat=]
  scanf("%c %c %c %c %c %c", &a, &b,&c, &d,&e);
                         ^
prog.c:12:6: warning: assignment makes integer from pointer without a cast [-Wint-conversion]
  if(a="e",b="b",c="i",d="i",e="l")
      ^
prog.c:12:12: warning: assignment makes integer from pointer without a cast [-Wint-conversion]
  if(a="e",b="b",c="i",d="i",e="l")
            ^
prog.c:12:18: warning: assignment makes integer from pointer without a cast [-Wint-conversion]
  if(a="e",b="b",c="i",d="i",e="l")
                  ^
prog.c:12:24: warning: assignment makes integer from pointer without a cast [-Wint-conversion]
  if(a="e",b="b",c="i",d="i",e="l")
                        ^
prog.c:12:30: warning: assignment makes integer from pointer without a cast [-Wint-conversion]
  if(a="e",b="b",c="i",d="i",e="l")
                              ^
prog.c:14:2: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
  printf("hello");
  ^~~~~~
prog.c:14:2: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:14:2: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:18:5: warning: incompatible implicit declaration of built-in function 'printf'
     printf("errol");
     ^~~~~~
prog.c:18:5: note: include '<stdio.h>' or provide a declaration of 'printf'
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內容已隱藏
* ** * * *

** ** * * * {

* *
* = *****
= ** *** *
= * ** *
** = *
* = * ***

e = **
* = ***
= *
* = **

**** **
*** **
* ****
**** *
* * **

* * * ** **** *** *
*
100/100 最新回答 用戶: (183 分)
0 0
Case 0: Correct output
Case 1: Wrong output
0 喜歡 0 不喜歡
內容已隱藏
* * *** * *** ***

* ** * * * ** ** {

** * *
= ***
= * **
* = * **
* = ***
* = *****

e =
= *
* =
=

*** *
* * **
** **
** * **
**** *

* ** ** ** ** ******* *
100/100 最新回答
0 0
Case 0: Correct output
Case 1: Wrong output
0 喜歡 0 不喜歡
內容已隱藏
#include ** * ** * *
#include * *** * ** *

int main(int argc, char *argv[]) {
** ** *** ** *** ** * * letterj;
*** * * ****** * * *** *** letteri;
* * ** ** * ** ****** letterm;
* * *** * ** **** *** * lettere;
* * * * * *** * ** lettern;
*** *** *** * * * **
* * ** * * ** **** * * **** ** input the letter to encode: ");  
** ** *** * * **
*** * *** ** **** **** ** * * *** ** * *** * * * &letterj, ****** *** &letterm, ** ******* * *
*** * ** * ******* * **** * +3;
* * ** * * ****** *** ** +3;
*** ** ** * * *** * ** * +3;
* * * ** ** * ** * +3;
**** * ** *** * * ** *** * * ** +3;
* ** ** * ***** *****
*** * *** * ** * * *
* *** * ** ** ** ** ** ** * * * * *** *** ***** * *** lettere, lettern);
**** ** ** *** *
****** ** * * * * ** 0;
}


INPUT
*** **** *** **
** * ** * ** *
OUTPUT
* ******* * *
100/100 最新回答 用戶: (243 分)
0 0
prog.c:27:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:30:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:30:1: error: unknown type name 'OUTPUT'
0 喜歡 0 不喜歡
內容已隱藏
** ** ****** ** *

int ** argc, char * {


** * ** char a;
** **** * * **** ** * ** * * * char b;
* ***** ****** ** * ** * * *
*** ** * * * * * ** **** ** ** * * * ***
* ** * * *
* * ** * * * the * * how??
* * * * * *
* * ** * * *** * ** **** * a,b);
** ** * **
** *** * ** * *** 0;
}
50/100 最新回答
0 0
Case 0: Wrong output
Case 1: Wrong output
0 喜歡 0 不喜歡
內容已隱藏
#include * **** * ** ** *

int main(int argc, char *argv[])
{
* * * * ******** letterj;
** * **** * ***** **** letteri;
*** * * *** ** ** *** * letterm;
* ** ** ** ***** lettere;
* ******* ** ** * ** lettern;
** ** * * ** * ** *
* * * * * * * *** ** *** * * ** input the letter to encode: * ** * **
*** * * ** ** ** * * * ** *** * * ** ** * * ** * * * * * * * * * ** *****
* **** * * ** * * *
** * ** ** *** ** ****** * * = letterj +3;
** ** * ***** **** ** *** = letteri +3;
* * ** ** * ** * ** *** = letterm +3;
* ***** * ** * *** * * ** = lettere +3;
** *** *** *** * * ** ** = lettern +3;
* * *** * * * * *
***** * **** * ** ** *** ** ******** **** *** lettere, lettern);
** ** * * *** * * *

****** *** * 0;
}
100/100 最新回答 用戶: (220 分)
0 0
Case 0: Wrong output
Case 1: Wrong output
0 喜歡 0 不喜歡
內容已隱藏
** ** ** * * *** **

** * **** ** * * {

****
= * * ** *
= * *
i = *** ****
= * *
* = ** * *
e = ***
= *
* = *
* = *

**
* **
* ********
* **
**** *

* ** * * ** ** **** ** *
*
100/100 最新回答 用戶: (283 分)
修改於 用戶:
0 0
prog.c:1:16: fatal error: stdio: No such file or directory
 #include<stdio>
                ^
compilation terminated.
0 0
prog.c: In function 'main':
prog.c:6:5: error: 'cin' undeclared (first use in this function)
     cin >> a;
     ^~~
prog.c:6:5: note: each undeclared identifier is reported only once for each function it appears in
prog.c:11:5: error: 'cout' undeclared (first use in this function)
     cout << a << endl << endl;
     ^~~~
prog.c:11:18: error: 'endl' undeclared (first use in this function)
     cout << a << endl << endl;
                  ^~~~
0 0
prog.c: In function 'main':
prog.c:6:11: warning: too many arguments for format [-Wformat-extra-args]
     scanf("c", &a);
           ^~~
prog.c:11:14: warning: format '%c' expects argument of type 'int', but argument 2 has type 'char *' [-Wformat=]
     printf("%c", a)
              ^
prog.c:12:5: error: expected ';' before 'return'
     return 0;
     ^~~~~~
0 0
prog.c: In function 'main':
prog.c:6:11: warning: too many arguments for format [-Wformat-extra-args]
     scanf("c", &a);
           ^~~
prog.c:11:14: warning: format '%c' expects argument of type 'int', but argument 2 has type 'char (*)[5]' [-Wformat=]
     printf("%c", &a);
              ^
0 0
Case 0: Correct output
Case 1: Wrong output
0 喜歡 0 不喜歡
內容已隱藏
#include * * ** *****
#include ** *** *** *

int main(int argc, char *argv[]) {
** * **** ** ** ** * ****** letterj;
* * ** * ***** * *** *** * * * letteri;
*** ****** * * letterm;
** ** ** * ***** * * ** ** *** lettere;
** **** * * * * lettern;
* * * *** * * * *
* *** * ***** * * * ** * *** * input the letter to encode: * ****  
* * * * **** * * * * **** * * ** * * * *** * *** ** ** ***** ** * ** * ****** ** ** ** * * ** ** *
* * ** ** * **** *
****** ** * letterj = letterj +3;
*** * *** * *** ** * = letteri +3;
** ** * * * ** **** ** = letterm +3;
* *** *** ** ** ***** *** * = lettere +3;
* * * * *** * * ******** = lettern +3;
* *** * * * *
* * * * *** * * * * * * * ** *** ***** **** **** * * **** lettere, lettern);
* * **
* *** ** * * * * * *** * * 0;
}
100/100 最新回答 用戶: (220 分)
0 0
Case 0: Wrong output
Case 1: Wrong output
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[正常] 開放式問答 - 最新提問 12月 12, 2017 分類:Chapter 2: Syntax structure of the C language | 用戶: 許哲瑋 (449 分)
ID: 37081 - 從幾時開始: 無限制 - 到幾時結束: 無限制
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