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You have received an encrypted message from Julius Caesar-- the message is ebiil.  You are asked to decipher the message in order to understand what Caesar trying to say to you.

Hint

Luckily, Caesar has given you a hint, he says: 'I, myself, encoded the message by shifting every word backwards by 3.' 

Solution

Write a program that receives 5 characters 'ebiil'. Then decode those characters into 5 new characters.

Example

#include <stdio.h>

int main(int argc, char *argv[]) {


	char a;
    	char b;
	 	
	scanf("%c%c", &a, &b);
	
	//decode the message how??
	
	printf("%c%c", a,b);
	
	return 0;
}

Input

ebiil

 

 

 

 

 

 

 

 

 

 

Output

hello

** REMEMBER ** 
This is an online-compiler, don't put anything except the codes. If you want to make a comment, please use // or /* */

[練習] Coding (C) - 最新提問 分類:Chapter 2: Syntax structure of the C language | 用戶: (5.9k 分)
ID: 26955 - 從幾時開始: 無限制 - 到幾時結束: 無限制

修改於 用戶: | 7.3k 瀏覽

22 個回答

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內容已隱藏
#include<stdio.h>

int main (int argc,char *argv)
{
    char a;
* *** * ***** * * *** * b;
** ****** * * *** * c;
* **** * *** * ** * d;
* *** * * *** ** ** e;

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* ***** ** * * ** * *** *
* * *** ** * * **** **
** * *** * *** **** * **

* * ** * * * ** *** ** ** * * * **** ***
* * ** *** * * * * ** * *** 0;
}
100/100 最新回答 用戶: (244 分)
0 0
Case 0: Correct output
Case 1: Wrong output
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內容已隱藏
#include *** ** ** * *
int main(int argc, char *argv[]) {


*** * ** * * char a;
* ** ** * *** * ********** * * b;
* **** * ** * * * c;
** ** *** * * * * * * * * d;
***** *** *** * ** ** * * e;
*** * * * * *** * * * *** **
**** ** ** *** **** *** * ****** * * * ** * * * ** ** * *
** * ***
** * ** ** ** the message how??
* * *** *
** ** * * * * * **** ****** * * * * ** * * ***
* * * * * **
** * * * return 0;
}
100/100 最新回答 用戶: (221 分)
0 0
prog.c: In function 'main':
prog.c:10:2: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
  scanf("%c%c%c%c%c", &a, &b, &c, &d, &e);
  ^~~~~
prog.c:10:2: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:10:2: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:14:2: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
  printf("%c%c%c%c%c", a+3,b+3,c+3,d+3,e+3);
  ^~~~~~
prog.c:14:2: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:14:2: note: include '<stdio.h>' or provide a declaration of 'printf'
0 0
Case 0: Correct output
Case 1: Wrong output
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內容已隱藏
int main(int argc, char *argv[]) {


*   char a;
* * ** * *** * **** b;
** *** ** * ** char c;
** * * *** ****** * * * d;
* ******* * * *** *** *** e;
** ***** ** ** ******* * ** * ****  
    ******** * %c %c %c %c * *** ** ** * ** * *** * * * * * * * ***
** **  
    *** * ** ** * **** * * ** * * * *** ** ****** * * ** ***** ** * *
* *** ** *** * * ** *
* * *   ****** *** *
** * ** * * ** * ** * *
* ** * *** **** * * * *** * *
** * * *** ** ** ***
** ** * * * * **** **** ** ** ** **
* * * * *** ****
* * ** ** * 0;
}
50/100 最新回答 用戶: (244 分)
0 0
prog.c: In function 'main':
prog.c:10:2: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
  scanf("%c %c %c %c %c %c", &a, &b,&c, &d,&e);
  ^~~~~
prog.c:10:2: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:10:2: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:10:25: warning: format '%c' expects a matching 'char *' argument [-Wformat=]
  scanf("%c %c %c %c %c %c", &a, &b,&c, &d,&e);
                         ^
prog.c:12:6: warning: assignment makes integer from pointer without a cast [-Wint-conversion]
  if(a="e",b="b",c="i",d="i",e="l")
      ^
prog.c:12:12: warning: assignment makes integer from pointer without a cast [-Wint-conversion]
  if(a="e",b="b",c="i",d="i",e="l")
            ^
prog.c:12:18: warning: assignment makes integer from pointer without a cast [-Wint-conversion]
  if(a="e",b="b",c="i",d="i",e="l")
                  ^
prog.c:12:24: warning: assignment makes integer from pointer without a cast [-Wint-conversion]
  if(a="e",b="b",c="i",d="i",e="l")
                        ^
prog.c:12:30: warning: assignment makes integer from pointer without a cast [-Wint-conversion]
  if(a="e",b="b",c="i",d="i",e="l")
                              ^
prog.c:14:2: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
  printf("hello");
  ^~~~~~
prog.c:14:2: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:14:2: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:18:5: warning: incompatible implicit declaration of built-in function 'printf'
     printf("errol");
     ^~~~~~
prog.c:18:5: note: include '<stdio.h>' or provide a declaration of 'printf'
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內容已隱藏
** * * ****

* * ** ** ** * {

* * * * *
* = ** **
= *****
* = ** **
= * * *
= ** *

e = ***
* = *
* = *
= **

* * **
***
**** *
* * ***
* * *

*** * * ** * ****** *
100/100 最新回答 用戶: (183 分)
0 0
Case 0: Correct output
Case 1: Wrong output
0 喜歡 0 不喜歡
內容已隱藏
** * * ***** **

**** ** ** * ** {

*** ****
= * *
* = * *
* = *
= ***
= ***

e =
* = ***
* =
= **

** *
* * *
**
** **
******

*** * * *** * * ** *
*
100/100 最新回答
0 0
Case 0: Correct output
Case 1: Wrong output
0 喜歡 0 不喜歡
內容已隱藏
#include * * ** *
#include * * ** *

int main(int argc, char *argv[]) {
* **** ** ** * * * ** letterj;
* *** * * * **** * ** letteri;
* * *** * * * *** * *** * * letterm;
* * * *** * * * * lettere;
*** * *** ** ** lettern;
** *** ** * * ** *
*** * ***** *** ** ** ** * * ** input the letter to encode: ");  
** ** * ** **** * ***
** **** ** * ** * ** ** *** * *** * * &letterj, ** * ** &letterm, ***** ** * * *
*** *** * * * *** * ** ** * **** +3;
*** *** ******** * *** **** * +3;
**** * *** *** * ** *** ** ** +3;
* * ** *** ** *** * * * *** **** +3;
** * * ** **** * ** * *** +3;
* ** * ** **** **
* * *** * * * ****
** * * * **** * * ** * * ** * ***** **** lettere, lettern);
* ***** * ** * ** ** * **
****** * * *** * 0;
}


INPUT
* * * ** * * *
* ** *****
OUTPUT
* ** * ** *** *
100/100 最新回答 用戶: (243 分)
0 0
prog.c:27:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:30:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:30:1: error: unknown type name 'OUTPUT'
0 喜歡 0 不喜歡
內容已隱藏
* ** * * * ****

int *** argc, char **** * {


* * * * *** char a;
* * * *** * *** **** **** char b;
* * * ** * *** * ** * *
** *** **** * *** ** * *** * * * *** **
*** *** **** *
* * ** ** * ** ** * the * how??
******* * ***
* * * * * ** **** ** * * a,b);
* * * *
* **** *** ** * 0;
}
50/100 最新回答
0 0
Case 0: Wrong output
Case 1: Wrong output
0 喜歡 0 不喜歡
內容已隱藏
#include * * * * **

int main(int argc, char *argv[])
{
* **** ** ** letterj;
*** ******* * * * * *** *** letteri;
* ** * ** ** ** **** * letterm;
***** ***** ** * * ****** lettere;
* *** * * **** ** * lettern;
*** * ** * *** * **
***** * *** * * ** *** input the letter to encode: * * * * * *
* * ** ** *** ** ** ** ** * ** * * * * * * * ** * ** * * * * * *** *** * ** *
* *** * * * ** * *
* *** * ** * * * = letterj +3;
* **** * ** * * * *** * * * = letteri +3;
*** *** ****** * * * * ******* = letterm +3;
* * *** * ** * * * = lettere +3;
*** *** **** *** * = lettern +3;
* ** * * ** * ***
* ** * * * * * **** ** *** ** ****** ** * *** ** * * * lettere, lettern);
** * ** **** *** **

** ** * ** ** * 0;
}
100/100 最新回答 用戶: (220 分)
0 0
Case 0: Wrong output
Case 1: Wrong output
0 喜歡 0 不喜歡
內容已隱藏
** * ** * * ** *

* ** * *** * {

* *
* = * *
= *
i = ******
* = * *
* = *****
e = *
= *
* = **
** = *

**** *
*
* *
* *
* **

* * ***** ** ** ** ** *
*
100/100 最新回答 用戶: (283 分)
修改於 用戶:
0 0
prog.c:1:16: fatal error: stdio: No such file or directory
 #include<stdio>
                ^
compilation terminated.
0 0
prog.c: In function 'main':
prog.c:6:5: error: 'cin' undeclared (first use in this function)
     cin >> a;
     ^~~
prog.c:6:5: note: each undeclared identifier is reported only once for each function it appears in
prog.c:11:5: error: 'cout' undeclared (first use in this function)
     cout << a << endl << endl;
     ^~~~
prog.c:11:18: error: 'endl' undeclared (first use in this function)
     cout << a << endl << endl;
                  ^~~~
0 0
prog.c: In function 'main':
prog.c:6:11: warning: too many arguments for format [-Wformat-extra-args]
     scanf("c", &a);
           ^~~
prog.c:11:14: warning: format '%c' expects argument of type 'int', but argument 2 has type 'char *' [-Wformat=]
     printf("%c", a)
              ^
prog.c:12:5: error: expected ';' before 'return'
     return 0;
     ^~~~~~
0 0
prog.c: In function 'main':
prog.c:6:11: warning: too many arguments for format [-Wformat-extra-args]
     scanf("c", &a);
           ^~~
prog.c:11:14: warning: format '%c' expects argument of type 'int', but argument 2 has type 'char (*)[5]' [-Wformat=]
     printf("%c", &a);
              ^
0 0
Case 0: Correct output
Case 1: Wrong output
0 喜歡 0 不喜歡
內容已隱藏
#include ********* *
#include * * * ** **

int main(int argc, char *argv[]) {
* * * * ***** * * **** letterj;
** *** *** * *** * * letteri;
* * * ** *** ** **** * letterm;
** ** * * ** **** lettere;
* * * * * ** **** ** lettern;
** *** * ** * ****
*** * ** * ** * **** * * * * * * input the letter to encode: * **  
**** * * * * * * **** *** * * **** ****** ******* * * ** ** * *** ** ** *** * ** * ** ** ** * * *** *
* ** * ** ** *
** * *** ** letterj = letterj +3;
**** ** ** *** * * * * ** = letteri +3;
* *** * ** ** **** * *** = letterm +3;
* ** *** ** ** * * ** = lettere +3;
***** * * ** * ** *** * ** = lettern +3;
* **** ** ** *** * **
*** * ** * * ***** * **** ** ** *** ** ** *** * *** * * ** lettere, lettern);
* * ** *** * *
* * ** * **** * **** 0;
}
100/100 最新回答 用戶: (220 分)
0 0
Case 0: Wrong output
Case 1: Wrong output
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[正常] 開放式問答 - 最新提問 12月 12, 2017 分類:Chapter 2: Syntax structure of the C language | 用戶: 許哲瑋 (449 分)
ID: 37081 - 從幾時開始: 無限制 - 到幾時結束: 無限制
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