[Exercise 03] Caesar Cipher Decoder

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You have received an encrypted message from Julius Caesar-- the message is ebiil.  You are asked to decipher the message in order to understand what Caesar trying to say to you.

Hint

Luckily, Caesar has given you a hint, he says: 'I, myself, encoded the message by shifting every word backwards by 3.' 

Solution

Write a program that receives 5 characters 'ebiil'. Then decode those characters into 5 new characters.

Example

#include <stdio.h>

int main(int argc, char *argv[]) {


	char a;
    	char b;
	 	
	scanf("%c%c", &a, &b);
	
	//decode the message how??
	
	printf("%c%c", a,b);
	
	return 0;
}

Input

ebiil

 

 

 

 

 

 

 

 

 

 

Output

hello

** REMEMBER ** 
This is an online-compiler, don't put anything except the codes. If you want to make a comment, please use // or /* */

[Exercise] Coding (C) - asked in Chapter 2: Syntax structure of the C language by (5.9k points)
ID: 26955 - Available when: Unlimited - Due to: Unlimited
edited by | 2.4k views

22 Answers

0 like 0 dislike 
Hidden content!
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int **  argc, char    * ** {
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** * *  ******** return 0;
}
100/100 answered by (449 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
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100/100 answered by (153 points)
0 0
Case 0: Correct output
Case 1: Wrong output
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
#include *    ****** * *
#include ****  *****    **

/* run this program using the console pauser or add your own getch, **** *  **   ** ****  *  or input loop */

int main(int argc, char *argv[]) {
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**** * * * *** * ***  *    *** = e+3;
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 * *  * *  ***   * * ** ***
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}
100/100 answered by (281 points)
edited by
0 0
Your program receives only 2 characters, and it doesn't move characters' positions.

Try to make it receive 5 characters, and move their positions forward by 3.
commented by (5.9k points)
0 0
This exercise expects only 'hello'. However, your code has.....

printf("Put the words you want to decode:");

Kindly consider delete this part :)
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
 * *   * ***   ** ***
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int   * **  char **    * {
/*
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*    **    

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a = a+3;
b = *  *
c = ***
d = d+3;
e =   *

    the **    ** 
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* **  *  * *    ** *********

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 *    * ** *  **   ** *  *** 0;
}
100/100 answered by (273 points)
edited by
0 0
prog.c:28:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:32:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:32:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
0 0
Your program can end at
  
    return 0;
}
------------------------------------------
You don't need to put

INPUT

ebiil

OUTPUT

hello
commented by (5.9k points)
0 0
Case 0: Correct output
Case 1: Wrong output
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
**     * ***       
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/* run this  *   ** ** the * *  * or add your own  * **    *** *  *       * ** * or     */

int **  ** *  char ***   {
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}
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*   *   *** *     0;
50/100 answered by (252 points)
0 0
prog.c: In function 'main':
prog.c:19:2: error: expected declaration or statement at end of input
  return 0;
  ^~~~~~
commented by (4.3k points)
0 0
Great job using an array and a loop. There are two mistakes found in your code. Please check
1.     printf("\n\n%s", code);  <--- in order to make it match the fixed output '\n\n' should be deleted
2.     At the end of your code, there's something missing.
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
  * **  ** *** *
 
 * **   * * ** * ** ***
 
    * *    *      *    *   **  **        ***  *        *** * **    * ** * *  * *      **** **

*   *****      *     ** ** 
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*** =     

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    = c + 

*  = d + **

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*** * * ***** *   * ** * * *    ** 

* *
100/100 answered by (268 points)
0 0
It's correct lol you can't judge me
commented by (268 points)
0 0
Well, that's because your output doesn't match with the fixed answer. Please take a look at this
printf("%c%c%c%c%c\n", a1, b1, c1, d1, e1);

Hint: You should delete something  :)

By the way, great job.
commented by (5.9k points)
0 0
printf("%c%c%c%c%c", a1, b1, c1, d1, e1);

How's that?
commented by (268 points)
0 0
That's correct.
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
  *   *    ** *       *
  **  * * **** *  ***  * 

int ***   * argc, char ** * {
  *        **  char  * **
**    *  * *  *  char ** **
*   * * **   ** * char * *
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 * * * * *  
*  **   *  ****    *    *****  ***   * * *   *** *      **  *** ** **     **  ***  * **   **   ***
***  *    ** **    = * * * + 3;
* ***** * *    ****    **   = **  + 3;
***  ** *   *   *   = * * *  + 3;
* *   *   ** letterc = * ** + 3;
  * * * *   *  **  =   * *  + 3;
** ** *    * ***  
 ****   ***  *   *   * * ** ** **  *****  *** *  *  *  ****** * * ** * *
    *   * *** 
* * ** *    **  return 0;
}
100/100 answered
reshown by
0 0
-----------Re-judge-----------
Case 0: Wrong output
commented by (4.3k points)
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     hello

Anyway, great job. Full marks.
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
* *** * ** *         * 
* *    * * ** *  ***

int   *  argc, char *argv[]) {
****** **  *   char   ***
*  ** *  * *     char letteri;
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**     *     char *****
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* * * **  **    
*  * **   ****  *  ** *    ******* **  *    ** * **  * *  * ***     * ***  ***   * *** **   * *** *** **
* * *     **** **** ** *  +3;
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* **  *   * **     **   *** * +3;
* ** **  **    ***   * * +3;
*          **       *** ** +3;
**       * ***  
*     * **   
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** **    *** 
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}


INPUT
** **    *    
    **** **   ***
OUTPUT
  *** * *    *
100/100 answered by (269 points)
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     hello

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
commented by (5.9k points)
0 0
prog.c:27:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:30:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:30:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
**   * ** **** *   *** *
**     *     ** ** *   **  

int * * **  argc, char  *  **  {
***    *  **** char ****
 * * * *   *    char  ** *
    *    *** * * char  **  *
* ** * ** *  *  char  * *   
 *  **** **   *  char * * 
*    * *  *  *  ** 
 * *    ***   ****  * *  ** ***  input the  *   * to ***   ** *   *   
* **  *   ** * 
**   *  ** **  *** *   * **   *  ** **     *  * ***   *     ***    *        *   **** ** * *      ***
  ** *    * * * 
  *  *     ** * letter = letter + 3;
 **** * *  *  *       = **  + 3;
*  *     * *  *  ***  = *    + 3;
  **  * **  ** * = **  + 3;
*     *  * *  *    =  ***** + 3;
** **  * ***   
****    *** *   * *  **    ** *** letter is **  ****** **   **  *  ****     *     * ** *  * *
  *  ***  * 
*  *    *  ** return 0;
}

INPUT
     * ** * *** 
**  *  ***
    
 **** *  ***  ** **
100/100 answered by (290 points)
reshown by
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     The encrypted letter is hello

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
commented by (5.9k points)
0 0
prog.c:26:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:29:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:29:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
#include  ***  **   

int main(int argc, char *argv[]) {
*      ** *     *** *  ** *  lettera;
* **  * ** **   *****  * *  ** ** letterb;
      * *  **   **  *   * **    letterc;
  ***   *    ******* * * * ** * letterd;
  * *  **     **** *  *  * ** * lettere;
 ** ** *  ***    ** *** * *  * *  **
 *** *  *** *    **** **     ** *** *  * %c %c %c   ***  **   *  **  * * *  ** ** * *  ** ***      ***  *  * **** *   
  **  * ***    ***  * **   = lettera + 3;
  **  ****  *******  *   *** * = letterb + 3;
 **** *** **  ***  * *  * **** ***  = letterc + 3;
  * * *  *****   *** **   * ** *  = letterd + 3;
** * * ** **   *  **** **** *  **   = lettere + 3;
*  *** ** **   **** *   ***   * *  *  * ** *  * * * *  **   
*        *  *** **    ****  * ** *     %c %c %c    * ** ***  letterb,  **   *  * *  *  ** * 
 *  *** ***  *  **   *  ***
 * * **  ** *     * **  *   ***  * 0;
}

   ** *
    * 
* **  ***** * 
 ***
//hello
100/100 answered by (271 points)
edited by
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: e b i i l
     h e l l o

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
commented by (5.9k points)
0 0
prog.c:25:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:28:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:28:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:10:5: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
     scanf("%c %c %c %c %c", &lettera, &letterb, &letterc, &letterd, &lettere);
     ^~~~~
prog.c:10:5: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:10:5: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:17:5: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
     printf("%c %c %c %c %c", lettera, letterb, letterc, letterd, lettere);
     ^~~~~~
prog.c:17:5: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:17:5: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
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