[Exercise 03] Caesar Cipher Decoder

Question

You have received an encrypted message from Julius Caesar-- the message is ebiil.  You are asked to decipher the message in order to understand what Caesar trying to say to you.

Hint

Luckily, Caesar has given you a hint, he says: 'I, myself, encoded the message by shifting every word backwards by 3.' 

Solution

Write a program that receives 5 characters 'ebiil'. Then decode those characters into 5 new characters.

Example

#include <stdio.h>

int main(int argc, char *argv[]) {


	char a;
    	char b;
	 	
	scanf("%c%c", &a, &b);
	
	//decode the message how??
	
	printf("%c%c", a,b);
	
	return 0;
}

Input

ebiil

 

 

 

 

 

 

 

 

 

 

Output

hello

** REMEMBER ** 
This is an online-compiler, don't put anything except the codes. If you want to make a comment, please use // or /* */

Answer 1

Hidden content!
  **  * ***** *  ** *

int *  *  argc, char  *    {
 ** ***     ***   *    *  ****    */

 * **** *  int number;
***  *  **** char a;
  *      **** ***   *   **  *** * b;
 *     ** *     * ****   * * **  c;
    *** *  *****  *   *   ** *   d;
 ***  * *   **     *  **** *  *    e;
 * * *    *  * *  *  *  
* *  **  ** **   * * forgert how to shift word  **   *    ***     ** ** 
 ** ** ***      *  *  **  *  * *  ** *  *  **** ** *      *      ***  **** ** *  **
 * *  * ** 
  *     ****   *  the message how??
*  *  *   * * * 
* ** ***   ** ***  ** *** ***   * **  *  **   * * ** *    
  **    ** * 
*  *  * *      return 0;
}

Comments

Case 0: Wrong output
Case 1: Wrong output

---

Case 0: Correct output
Case 1: Wrong output

Answer 2

Hidden content!
****   *  ***   ****
 
*      * *   *** *   ** ** {

* ** * *    
*  =  *  **
* *   *  
   =    *   
  =  ** *** 
  =  **   

* = * **
* = *
** = *  
  =  *  

  *  *  
 *  ***
* ** ****
** * *  * *
**  * 
 
* *  *  ***       **  *
 

Comments

Case 0: Correct output
Case 1: Wrong output

Answer 3

Hidden content!
#include   ***** ***    *
#include  ***** * * *  ***

/* run this program using the console pauser or add your own getch,    ***   ** **** ** or input loop */

int main(int argc, char *argv[]) {
 *****  *****   *** *** **      a;
 *   *  ***** *** *  **  * b;
    *    * * *  **  ** *   *  c;
 ** * ** * **  ** ***  **    d;
      *   * *    ** ** * * *  * e;
*   ** * ** **   * *** *** * *
 **  ***** *** * **  *  ****** ** *  *   the words you want to   *  *** 
 ***  **   **** **  *  *** **
   ** ** ** *** *** ***  ** = getchar();
 ** ***    * *    * ** *  = a+3;
***** **     *** *   * *** *** *  *
    **  ********** ** **  ** = getchar();
*   *** *** *  *  *  *    **  * = b+3;
   **  *     * *     **** ***  *  
  * *   *    *  **   *** = getchar();
 *** *    *  * * * ***  = c+3;
 * * ****   * *    ** * *  *** ***  * 
** *  **   * *   *  *   *  = getchar();
     **** *  **    * *  ***  = d+3;
*  ******     *     *   *******
  *    *    ** **  *  ** * **  = getchar();
 *  *  ** * *  **  *******  = e+3;
*   * * *  ***  *** *   *  ***   ** *
***** ** *    *   ***    *** * **    * * * *  **  *** *   ***    * 
***  * * ** *   *   ** *      *   *    **** * *   &a, &b, &c, &d, * ****  
* *  * ****     **   *  * *  *
***  *   **  *** *** *  ****      the message how??
  ** *  *** *   * *  *    **
  ** *        *  ** *   * * *   * * *     *****     ** a, b, c, d, e);
 **   *  ***  *** ** **** *
 * *     *  ** * **   *    * * *  0;
}

Comments

Your program receives only 2 characters, and it doesn't move characters' positions.

Try to make it receive 5 characters, and move their positions forward by 3.

---

This exercise expects only 'hello'. However, your code has.....

printf("Put the words you want to decode:");

Kindly consider delete this part :)

Answer 4

Hidden content!
 *   *   * * * ***  *  *
** * *   *     ** *  ** 

int  ***      char *  {
/*
  *  *     */

*  **** *

*   * ****** ** **** *** ****** * *   ** **   *  * * ** *** * * * ***  
a = a+3;
b = *  *
c =   
d = d+3;
e =  

 *  **  the *  *   **
**** **  ***  **    * 
 * *  *** **** *  *  *  ***  **  

****  * * * * * **  **  *
**   **  *  ** * *** **** * *   0;
}

Comments

prog.c:28:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:32:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:32:1: error: unknown type name 'OUTPUT'

---

Your program can end at
  
    return 0;
}
------------------------------------------
You don't need to put

INPUT

ebiil

OUTPUT

hello

---

Case 0: Correct output
Case 1: Wrong output

Answer 5

Hidden content!
* *** *        ** *  ** 
*   * *    *   **   

/* run this ***    ** the   ***   *** or add your own ** * **  ******   ** **   or  * *   */

int ***  *      char ** *  {
   **  ** ** int num, *****
   * * *   * * * **   ** **  
* **     ***  
 **    *   * *   * *  *     **** * ***** *
**  **   *** for *** = *    *      *   
{
 * ***   *  *   ** =  * * **
 *****  * if * *      **
 * **  * *  *   * *  =  **  ***
  *   *    **   **** ** ** *
}
 * * *  **      ******* * **   ** ** ** *  
 *  ** * * *    *  *  0;

Comments

prog.c: In function 'main':
prog.c:19:2: error: expected declaration or statement at end of input
  return 0;
  ^~~~~~

---

Great job using an array and a loop. There are two mistakes found in your code. Please check
1.     printf("\n\n%s", code);  <--- in order to make it match the fixed output '\n\n' should be deleted
2.     At the end of your code, there's something missing.

Answer 6

Hidden content!
***     * *  *****
 
  *      *** * *  *****
 
** *  *      *  * *    ****  *     * *           *    **** * *****  * ****  ** * *   *

**       *** * * *   
 
***     *     *

***  *  *  *  *    
 
**** *  *    *    * * * **    *   *  **  * **  *  * **    * *  * ** 

   =   * *

 *  b + *

 = c +   

   = d +  
 
 *  *    *
*
* ** **** * *  *** ***       **   *  

  *** 
*
* 

Comments

It's correct lol you can't judge me

---

Well, that's because your output doesn't match with the fixed answer. Please take a look at this
printf("%c%c%c%c%c\n", a1, b1, c1, d1, e1);

Hint: You should delete something  :)

By the way, great job.

---

printf("%c%c%c%c%c", a1, b1, c1, d1, e1);

How's that?

---

That's correct.

Answer 7

Hidden content!
    *    * ****** ** ** ****
  ***  ** ******  **** 

int *** * argc, char   {
** * * * ****  char **** * 
*   **    **   char *  *
*    *    *  *   char     * 
*  *  *** ** char *   * *
 *****  *       char  ***
 *  **  *** *** 
  *****    **   *  * *  *** * ***  input the letter to   *   **  *** 
****       *** * 
  ***  ** *    *  *  ** *** ** *** ***       *** * * ***** * *** **  *** ***    * ** * *****  ****
*  *   *  ***    *  * * =  ** *  + 3;
**        ** *  *  * =  ***  + 3;
* *****  *** *   ** =  **  * + 3;
 *  ***** *  ***    letterc =  ** + 3;
*        ** *  **   = **** ** + 3;
****   *   * 
**** *     **** * ** ****** * * *  *** *  *      * ***    * *      ** *  
** *  ***** * 
  ** ** **  return 0;
}

Comments

-----------Re-judge-----------
Case 0: Wrong output

---

Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     hello

Anyway, great job. Full marks.

Answer 8

Hidden content!
***   *  ** *** * * **
   * *    *    *  ** **

int * **  argc, char *argv[]) {
*   *   *  ***  char **   **
   *  *  * *  char letteri;
 * **       *     char   *  
*  *  *  *     char   ** 
**   ** * *   char  ***
*** *** *  ** ** 
*  *  **  *  ** *  * *** *     input the letter to encode: *  ** * *  **
** * *  *  ***     
******  ***  * **** **** * ***   *     ** * *** *  ****** **    * *   ***     *    *  **** *  * *  
  * ****     **   *  *  **  *  +3;
    *** *  *     **    *  * +3;
*****    * *  * ****   *  +3;
   *   ***   * **  * * +3;
***      ****** *   *** *    +3;
 **  *  *  *   **  
 ***    * ****   
 * *  * * *   **   ** *** **** *  **   *** *  *       *    *** * **
*** * * *  * 
*  *** * ****** return 0;
}


INPUT
*     **   * **  **
 *  *** ** 
OUTPUT
** * * *  *  *** *

Comments

Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     hello

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.

---

prog.c:27:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:30:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:30:1: error: unknown type name 'OUTPUT'

Answer 9

Hidden content!
  **   ** *       **   
***** *  * ** * * *** * 

int    * argc, char    {
 * ***     *** char **  
*  *   **     *   char **   
*   * *  * **  char  *  *
*    * *  *    char   * *
****    ***  *  *  char    **
   ** * *** ** * 
**    * **** * ** ******     **  input the *    * to  *** ** *   ** *  * 
* * *    *    
* ***   ****   **         ** *    *   *** * * *          *      *   *   * ** ****     **** *** 
 ******    ***  
** *  * *** *  letter = letter + 3;
** *   *   ***    * *  = **** + 3;
   **  * ** *        *  = ***  + 3;
 * * ***  ** **  **  =  *  * + 3;
 ** * *  ***      ***  =    + 3;
*  * ***   * *  * 
    ****   *****      *****  * *  *   letter is  * *  ****  * *** * **    *** * **** **  * * *    *
  *     * * *  
****   *  *   return 0;
}

INPUT
* *    **   **  *
**   * * ** * 
*  *
     *** ** **** 

Comments

Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     The encrypted letter is hello

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.

---

prog.c:26:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:29:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:29:1: error: unknown type name 'OUTPUT'

Answer 10

Hidden content!
#include  *  * ** ** * **  

int main(int argc, char *argv[]) {
** * * ** ****** * *     ******     lettera;
 ** ***    * **  *  *   ****  letterb;
   *    ***    * ****   letterc;
**  *   ***    *  *  **  ** * letterd;
   *   * *         **  ** *** lettere;
**  * * * *  ****  *   ****   
  *    **** *   * *  *   *     *** *** %c %c %c *** **   ***  * * ** *   *** * *      **   * *  * * *  ** ** *****   *** 
****   **  *  **  * * *  ** * **  * = lettera + 3;
     *   *** ** *** ******** ***   *** = letterb + 3;
    *   ** * ** ***  * * ** * *  *    = letterc + 3;
*** *  *** * **    ** **     * *   ** = letterd + 3;
** * **  ***** *      ** *** = lettere + 3;
 ** **** ****** ***** ** **   * * ***  ***  *     *
***   **  *         **     ****  %c %c %c ** *  *       letterb, *  *** *       ** 
 *  **      ****    *  * * * **  
*  **  **  ***  *  *****    ** **  0;
}

 *  * 
**  *
  *** *   * * 
**   
//hello

Comments

Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: e b i i l
     h e l l o

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.

---

prog.c:25:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:28:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:28:1: error: unknown type name 'OUTPUT'

---

prog.c: In function 'main':
prog.c:10:5: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
     scanf("%c %c %c %c %c", &lettera, &letterb, &letterc, &letterd, &lettere);
     ^~~~~
prog.c:10:5: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:10:5: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:17:5: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
     printf("%c %c %c %c %c", lettera, letterb, letterc, letterd, lettere);
     ^~~~~~
prog.c:17:5: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:17:5: note: include '<stdio.h>' or provide a declaration of 'printf'