[Exercise 03] Caesar Cipher Decoder

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You have received an encrypted message from Julius Caesar-- the message is ebiil.  You are asked to decipher the message in order to understand what Caesar trying to say to you.

Hint

Luckily, Caesar has given you a hint, he says: 'I, myself, encoded the message by shifting every word backwards by 3.' 

Solution

Write a program that receives 5 characters 'ebiil'. Then decode those characters into 5 new characters.

Example

#include <stdio.h>

int main(int argc, char *argv[]) {


	char a;
    	char b;
	 	
	scanf("%c%c", &a, &b);
	
	//decode the message how??
	
	printf("%c%c", a,b);
	
	return 0;
}

Input

ebiil

 

 

 

 

 

 

 

 

 

 

Output

hello

** REMEMBER ** 
This is an online-compiler, don't put anything except the codes. If you want to make a comment, please use // or /* */

[Exercise] Coding (C) - asked in Chapter 2: Syntax structure of the C language by (5.9k points)
ID: 26955 - Available when: Unlimited - Due to: Unlimited
edited by | 3k views

22 Answers

0 like 0 dislike 
Hidden content!
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 * *   ** *   return 0;
}
100/100 answered by (449 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
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100/100 answered by (153 points)
0 0
Case 0: Correct output
Case 1: Wrong output
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
#include  **  ****      * 
#include ******   **  * 

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int main(int argc, char *argv[]) {
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}
100/100 answered by (281 points)
edited by
0 0
Your program receives only 2 characters, and it doesn't move characters' positions.

Try to make it receive 5 characters, and move their positions forward by 3.
commented by (5.9k points)
0 0
This exercise expects only 'hello'. However, your code has.....

printf("Put the words you want to decode:");

Kindly consider delete this part :)
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
*      *   * *     *
***      ***    **  *** *

int *   ** * *   char ** *** {
/*
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b = ** 
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**  ** ***    * * *  ** ***  *     0;
}
100/100 answered by (273 points)
edited by
0 0
prog.c:28:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:32:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:32:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
0 0
Your program can end at
  
    return 0;
}
------------------------------------------
You don't need to put

INPUT

ebiil

OUTPUT

hello
commented by (5.9k points)
0 0
Case 0: Correct output
Case 1: Wrong output
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
 *** *  * * ***********
*     ** ***** * * *   

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int  ** *  *   char ** {
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}
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50/100 answered by (252 points)
0 0
prog.c: In function 'main':
prog.c:19:2: error: expected declaration or statement at end of input
  return 0;
  ^~~~~~
commented by (4.3k points)
0 0
Great job using an array and a loop. There are two mistakes found in your code. Please check
1.     printf("\n\n%s", code);  <--- in order to make it match the fixed output '\n\n' should be deleted
2.     At the end of your code, there's something missing.
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
**** *** *** ** **  

  ***     ** * * *  * **  
*
*    *   *****   *  *  * *       * *  *   ***** * * *  *  * *** ** *    ***    *
 
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**    b + *

*  = c + 

*  = d +  
*
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*   **  *  ****  *    *   * **     ***  * ****
 
   *
100/100 answered by (268 points)
0 0
It's correct lol you can't judge me
commented by (268 points)
0 0
Well, that's because your output doesn't match with the fixed answer. Please take a look at this
printf("%c%c%c%c%c\n", a1, b1, c1, d1, e1);

Hint: You should delete something  :)

By the way, great job.
commented by (5.9k points)
0 0
printf("%c%c%c%c%c", a1, b1, c1, d1, e1);

How's that?
commented by (268 points)
0 0
That's correct.
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
  ***    ***  ** *  **
*           **    * 

int   ****  argc, char ** **  {
   * *   **** ** char * * *
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*   **  *** * ****  ** *   input the letter to *      **** ***
***  *  *   **  
** *  *  * *  * ** ***   *  **  **   *** **  ***  ** * *  ** * *  ** *   *  **** * * * * *     *** * ** **
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*** **  **      *** * * =    *  + 3;
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* * **   *    ** * = ** + 3;
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*   **  *     *  *    ****** *  *   ** *   *****     *  * * *   ** *
*       **** * 
 *  ****  *** **  return 0;
}
100/100 answered
reshown by
0 0
-----------Re-judge-----------
Case 0: Wrong output
commented by (4.3k points)
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     hello

Anyway, great job. Full marks.
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
  ***   * * *  * *  ****   
* *      * *   *  **  *  * 

int   *   argc, char *argv[]) {
*   * **  **     char ** 
   *     *****   * char letteri;
** * **  ** *** char    ** 
 ****  **  *  * char   ***
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* **   *    * ***    *  ***** **  *  input the letter to encode:  *  *  **  * ****
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**        **  *    ***    * * *    *   ****    *** ** ***** *      *** ** ** **  *   *******         * 
*** * *  ** ** **  * ***     +3;
*  * **   **  **    *   * +3;
** * **   * **    *     *   *   +3;
* ****     **   *    *** *  *   +3;
**  **       *    *** * *  +3;
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     ** *  **  return 0;
}


INPUT
 *** **   *   * ****
*  *   * *
OUTPUT
* ** * * *   **
100/100 answered by (269 points)
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     hello

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
commented by (5.9k points)
0 0
prog.c:27:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:30:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:30:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
*  *     * *        
  *  * * ***  * *   ** * *

int  *    * argc, char     *  {
** *      ** * * char    * 
****    ****  char  *    
 ***  *   **  char *   
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  * * * ** *   char * * * *
  **  ** * * 
 ***  *    *    **** ***** ** input the *      to ***  * *      *  *** 
* *    **** 
********           *  *** *      *     ***  *         *  ** *  * *   *** ** *  *  *     *  * **
 *   *       *  * 
 ***      *   letter = letter + 3;
 **    **    *    ** =    * + 3;
********  * ** *  *  *  * = * **  + 3;
 ** ** *   *  *  = **  + 3;
 *** ***   * *   *    = **  + 3;
*          *    * * 
 * **  ****    * *  * *  * **** letter is *   * ** **  **** * **   *  *  **** **  *** *
*** * * *     *   
*  ** ** **    return 0;
}

INPUT
** ***** **
*  * * ** ** *
***
   * *******  * ***
100/100 answered by (290 points)
reshown by
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     The encrypted letter is hello

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
commented by (5.9k points)
0 0
prog.c:26:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:29:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:29:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
#include  **  * * *****

int main(int argc, char *argv[]) {
 ** *    **** ** ** ** ***  **  lettera;
*   ****  *     ****  ****    ***   ** letterb;
*  *** * ** ***   * *  * **    *** letterc;
* *  **  * ******  *  *    * letterd;
**  *** *  *   ** * * ***    **  lettere;
  * *** *  **** ******* **
   **********  ****** ** ** *     %c %c %c * *  *** **** * ****      * **  * * *    **  **     ****    ***** *  * * * 
  **   *  **  * **  **  **  **  **  = lettera + 3;
***   *     * **     ***  ** * = letterb + 3;
 ***** ** ** *   * * * *   **  = letterc + 3;
 ** *    *   **** ***   *** *  *  = letterd + 3;
 * * ** ** * * * * **   *** *   = lettere + 3;
 **   **** *  **    * **  ***** * *** **** *****
    **  ** *    ** *   ** * *    *    * %c %c %c     * ** ***   letterb,  ** *     **  **
  **  * ****  * ***   * **    * *
***  *** **** *  * ** * * * *  0;
}

**** 
** *
** * *** * **
* * *
//hello
100/100 answered by (271 points)
edited by
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: e b i i l
     h e l l o

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
commented by (5.9k points)
0 0
prog.c:25:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:28:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:28:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:10:5: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
     scanf("%c %c %c %c %c", &lettera, &letterb, &letterc, &letterd, &lettere);
     ^~~~~
prog.c:10:5: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:10:5: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:17:5: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
     printf("%c %c %c %c %c", lettera, letterb, letterc, letterd, lettere);
     ^~~~~~
prog.c:17:5: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:17:5: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
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