[Exercise 03] Caesar Cipher Decoder

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You have received an encrypted message from Julius Caesar-- the message is ebiil.  You are asked to decipher the message in order to understand what Caesar trying to say to you.

Hint

Luckily, Caesar has given you a hint, he says: 'I, myself, encoded the message by shifting every word backwards by 3.' 

Solution

Write a program that receives 5 characters 'ebiil'. Then decode those characters into 5 new characters.

Example

#include <stdio.h>

int main(int argc, char *argv[]) {


	char a;
    	char b;
	 	
	scanf("%c%c", &a, &b);
	
	//decode the message how??
	
	printf("%c%c", a,b);
	
	return 0;
}

Input

ebiil

 

 

 

 

 

 

 

 

 

 

Output

hello

** REMEMBER ** 
This is an online-compiler, don't put anything except the codes. If you want to make a comment, please use // or /* */

[Exercise] Coding (C) - asked in Chapter 2: Syntax structure of the C language by (5.9k points)
ID: 26955 - Available when: Unlimited - Due to: Unlimited
edited by | 3.6k views

22 Answers

0 like 0 dislike 
Hidden content!
   * *   *  **  ** *   * 

int * *  argc, char ****  {
* *   * *    ***** *** *  ** * ***  */

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*   * ***** *  char a;
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*  *     * ** *** the message how??
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 **  ** * ** 
 * ***   * * * * return 0;
}
100/100 answered by (449 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
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100/100 answered by (153 points)
0 0
Case 0: Correct output
Case 1: Wrong output
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
#include          *  
#include *   **  **** *   

/* run this program using the console pauser or add your own getch, *  ** * *****  *** ***  or input loop */

int main(int argc, char *argv[]) {
   *** *  **** * *  * ***  *****    a;
   *   * **** **      * * *   ** b;
** *   * **** *  ** *   *  c;
** *       ***   *     ** ***     * d;
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*   * **    ** **  ** * *** = a+3;
**** *** *  ** ** * ******  **  * 
****     *  *  * * * ** **    = getchar();
*** *  **** *   *** *    * * *  = b+3;
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  *  ***  **     ****    * = c+3;
** ******* *  *  *** ** **     *  
**  ****  * **      * ** *   ** = getchar();
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  *** * * * ****   ** **  *  *   **
*  *****  * **    * * **  = getchar();
*** *** ****   *  * * ****** = e+3;
** *   *   ** * * *  ***   *   ** * *
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**   * *    ** **   *** * *  *   ** *  **    ***  &a, &b, &c, &d,  * **     
* *  **  **  *****   ***   * 
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***  * * ****   ** * ****   *     * *     * ** * *     a, b, c, d, e);
* *  * ** ***  *     *  *  
**   * * ****    ****  * ** 0;
}
100/100 answered by (281 points)
edited by
0 0
Your program receives only 2 characters, and it doesn't move characters' positions.

Try to make it receive 5 characters, and move their positions forward by 3.
commented by (5.9k points)
0 0
This exercise expects only 'hello'. However, your code has.....

printf("Put the words you want to decode:");

Kindly consider delete this part :)
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
* ** *****  ******  *
*** ** *** *  * *  * *

int  *  * **  char *  * {
/*
** *      ***  */

   *  * ** 

* **   **   ****  * *  * ** ***      **        **  *          ****  
a = a+3;
b = * *
c =  *
d = d+3;
e =  * 

*   * the * **  ****
*   ****  **  ** ***
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** * **  * ***** *   
*  *  *  *   * * *  *  * **** 0;
}
100/100 answered by (273 points)
edited by
0 0
prog.c:28:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:32:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:32:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
0 0
Your program can end at
  
    return 0;
}
------------------------------------------
You don't need to put

INPUT

ebiil

OUTPUT

hello
commented by (5.9k points)
0 0
Case 0: Correct output
Case 1: Wrong output
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
**   ** *** *** *  *
*    * * *  *  * *   * ** *

/* run this   *  * *  the  *   * ***   or add your own **  * ** ** ***  ** *    * or    **  */

int  * ***    * char  ***  {
**  **      ** int num,  * *
**  * ** * * *  **  
    *   *****   
* **  * * *   *** **** ** *   **     **   ** 
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{
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*  ** * * **  * * if ***     * ****  ** 
**  ** ***  ** * *** =     ***** 
 * **** *** *   *  ** **
}
   * ** * **   ***** ****     ** *** *  * *  
***    * **  ** 0;
50/100 answered by (252 points)
0 0
prog.c: In function 'main':
prog.c:19:2: error: expected declaration or statement at end of input
  return 0;
  ^~~~~~
commented by (4.3k points)
0 0
Great job using an array and a loop. There are two mistakes found in your code. Please check
1.     printf("\n\n%s", code);  <--- in order to make it match the fixed output '\n\n' should be deleted
2.     At the end of your code, there's something missing.
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
* *      *** ***** * 
 
* ****    * * **  * *   **
 
**  *    ****  ** **   ** *     ** *  ** *     *  * *   ***     ** *    * * *  * 

* *  * *    * * **    * *  *
 
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*
    = * *  
 
   * b + **

  * = c +  

   = d +  
 
*     
 
  *** ***  *  ***  * **          * *  ** 
*
  ** 
*
100/100 answered by (268 points)
0 0
It's correct lol you can't judge me
commented by (268 points)
0 0
Well, that's because your output doesn't match with the fixed answer. Please take a look at this
printf("%c%c%c%c%c\n", a1, b1, c1, d1, e1);

Hint: You should delete something  :)

By the way, great job.
commented by (5.9k points)
0 0
printf("%c%c%c%c%c", a1, b1, c1, d1, e1);

How's that?
commented by (268 points)
0 0
That's correct.
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
** ** ** *  **    **  
* **     * **   ** *

int  * * ** argc, char *  *  {
*     * * * *  char  **** 
 **** **  **  char *** * *
 *   *   *  * char    ***
  * * **        char  ** *
  * *  **** * char  * * * 
* ***    * ******* 
***    * * *    * ***  ** *  ** * input the letter to *  * ** *      
  ** *     ******  
*  **  *****   ***  * ** ***   *   *     **   ***    *    **  *  ** * *   *** **  * *   **    * ****** 
*** * ***  ** **     * =  **  + 3;
 ***    **    * **   =      + 3;
   *     *  * ***   =  *     + 3;
 * ** *** ** **   letterc =     ** + 3;
 ** **   * *    * *   = * *   + 3;
* * *   ** **  * 
*   **  ** *  * ***** ****   ***   ***  *    *  *       *      *   **  ****
  ** * * * *   
   * *****  return 0;
}
100/100 answered
reshown by
0 0
-----------Re-judge-----------
Case 0: Wrong output
commented by (4.3k points)
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     hello

Anyway, great job. Full marks.
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
*   *   *  ** *** ** 
****      ****  **  * * 

int * *  **  argc, char *argv[]) {
  ** ***   ** * ** char **** 
 * ** ** * ***  char letteri;
****  * *  * **    char   *  
*  *     *  char *  *** *
***  *   ****** char *** *
* ** * *     * 
** *** *** **  ***   *** **    input the letter to encode: * *   * ** **  * *
* ****   * * ** 
 ** *  * *  ***  *   *  * **   ** * **     * *   *****  **  * *  * **    **      *** **  ***  * *
 * *  *    * *      ***  * * +3;
***  *  * * *  ***  ** *  *  +3;
* * **  * *  * * *   ** ****  **  +3;
** * * *  ** *   * *     +3;
** * ** *  * * *  *  *****  +3;
*   *   *  *** 
 *   *   * * * *   
*  **  * ***  * * ****** ** *    ****  **  * *   *   *****    *  * * 
  **  *   **    * 
**  * *  *   return 0;
}


INPUT
 *** **** *  * 
*   ******
OUTPUT
   *  *  * *  ***
100/100 answered by (269 points)
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     hello

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
commented by (5.9k points)
0 0
prog.c:27:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:30:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:30:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
***      * **  *** **
 ****   * * ****  ***  

int   *   argc, char   *  {
*    *   ** ** * char *  
* ** *** ** *  * char ***  
 *   ** **  * char *** *
  **    **  char **  *
  *      * * ** ** char  * **
  * *  *  *   
*  *      ***     * **   *        input the * **  to  *** *     **  ***
* *    ** ** *   
    ** *  ***** *  **** *  ** ****** *        *   *** ** ** * ** *** **   **  *** * * *        *  **    
 *         **  
 ***  **  * *   letter = letter + 3;
****  *** **    **  ** *  =  ** * + 3;
**  * *       **   =     + 3;
**    **  ** *    = ****   + 3;
   *    * *  ***  *** = ** + 3;
** ***  *       
**  * **  * * *   **    *** *  * * letter is   ** ***  ***  **  ** *   ** *      *   *
* *  *** *    ** ** 
*       ***      * return 0;
}

INPUT
****  * ** ****** *  
 *      * * **
 *  
  ** * * **   *  * *
100/100 answered by (290 points)
reshown by
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     The encrypted letter is hello

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
commented by (5.9k points)
0 0
prog.c:26:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:29:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:29:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
#include   **      *  *  

int main(int argc, char *argv[]) {
  *    ***  * * *** ** * lettera;
 *   * ***     * *   **** *  letterb;
  *  ** *  *     **     letterc;
     ***  * **  *   *** **** * letterd;
********** *   *******    * * * lettere;
 *        *** ****   *  ****
*  ** *  * *  *** *  **  **  *   *  ****** %c %c %c *  *** * ***     * * *   *     ***   *   * *** *  *   ** *    *  * * *  *** 
** ** *  ** *  ** ***   *    = lettera + 3;
  *** * *          ***     * ** = letterb + 3;
  *   ***  * ****     ****    * *  * *  = letterc + 3;
* **  *  ** *       ****** * * * = letterd + 3;
**  * ***  ****   *  * **   * *  = lettere + 3;
     *  * * *    * ****  *****  *** **   *  * * ****
 ** *   *       * **     *  * *** *  * ** * %c %c %c ****** **  * * * * letterb, *    *  * ** *     **
  * * *  *    *  ***  *** * 
   * *  ** ***  *    * ***** * 0;
}

*     
   ***
 **   **    **
   * **
//hello
100/100 answered by (271 points)
edited by
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: e b i i l
     h e l l o

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
commented by (5.9k points)
0 0
prog.c:25:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:28:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:28:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:10:5: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
     scanf("%c %c %c %c %c", &lettera, &letterb, &letterc, &letterd, &lettere);
     ^~~~~
prog.c:10:5: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:10:5: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:17:5: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
     printf("%c %c %c %c %c", lettera, letterb, letterc, letterd, lettere);
     ^~~~~~
prog.c:17:5: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:17:5: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
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