[Exercise 03] Caesar Cipher Decoder

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You have received an encrypted message from Julius Caesar-- the message is ebiil.  You are asked to decipher the message in order to understand what Caesar trying to say to you.

Hint

Luckily, Caesar has given you a hint, he says: 'I, myself, encoded the message by shifting every word backwards by 3.' 

Solution

Write a program that receives 5 characters 'ebiil'. Then decode those characters into 5 new characters.

Example

#include <stdio.h>

int main(int argc, char *argv[]) {


	char a;
    	char b;
	 	
	scanf("%c%c", &a, &b);
	
	//decode the message how??
	
	printf("%c%c", a,b);
	
	return 0;
}

Input

ebiil

 

 

 

 

 

 

 

 

 

 

Output

hello

** REMEMBER ** 
This is an online-compiler, don't put anything except the codes. If you want to make a comment, please use // or /* */

[Exercise] Coding (C) - asked in Chapter 2: Syntax structure of the C language by (5.9k points)
ID: 26955 - Available when: Unlimited - Due to: Unlimited
edited by | 8.7k views

22 Answers

0 like 0 dislike 
Hidden content!
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}
100/100 answered by (449 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
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100/100 answered by (153 points)
0 0
Case 0: Correct output
Case 1: Wrong output
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
#include   * ** *    *
#include * ** ****  *  **  

/* run this program using the console pauser or add your own getch,   ***** ** ** ** **** * or input loop */

int main(int argc, char *argv[]) {
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}
100/100 answered by (281 points)
edited by
0 0
Your program receives only 2 characters, and it doesn't move characters' positions.

Try to make it receive 5 characters, and move their positions forward by 3.
commented by (5.9k points)
0 0
This exercise expects only 'hello'. However, your code has.....

printf("Put the words you want to decode:");

Kindly consider delete this part :)
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
** ** *** *   * *  **
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int **    * char    ** {
/*
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** * *** *

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}
100/100 answered by (273 points)
edited by
0 0
prog.c:28:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:32:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:32:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
0 0
Your program can end at
  
    return 0;
}
------------------------------------------
You don't need to put

INPUT

ebiil

OUTPUT

hello
commented by (5.9k points)
0 0
Case 0: Correct output
Case 1: Wrong output
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
*** ** ** *        *  *
*   *  *  **   *  *

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}
*   * **  *  ***  *** * ** ** * ***  ** **  *
**  * *       *  * 0;
50/100 answered by (252 points)
0 0
prog.c: In function 'main':
prog.c:19:2: error: expected declaration or statement at end of input
  return 0;
  ^~~~~~
commented by (4.3k points)
0 0
Great job using an array and a loop. There are two mistakes found in your code. Please check
1.     printf("\n\n%s", code);  <--- in order to make it match the fixed output '\n\n' should be deleted
2.     At the end of your code, there's something missing.
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
  * * * **   *  *  *
 
** ***    ***  ** ******
 
*  * *  **      * *       **  * *   *    *       *  * **     **  *** **  **  * * *   *

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* =    

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*   * *
*
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* **   *

*
100/100 answered by (268 points)
0 0
It's correct lol you can't judge me
commented by (268 points)
0 0
Well, that's because your output doesn't match with the fixed answer. Please take a look at this
printf("%c%c%c%c%c\n", a1, b1, c1, d1, e1);

Hint: You should delete something  :)

By the way, great job.
commented by (5.9k points)
0 0
printf("%c%c%c%c%c", a1, b1, c1, d1, e1);

How's that?
commented by (268 points)
0 0
That's correct.
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
*     *  *****    **  *
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int *  *  * argc, char  *    {
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** * * * *  ***     =  *  + 3;
*  *     **  * *** =   *   + 3;
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 ***     * **  
**  ** * ** *  **** * ***  * * * *       ***   **  *         * * *
***    *  ***  
    * *  *** return 0;
}
100/100 answered
reshown by
0 0
-----------Re-judge-----------
Case 0: Wrong output
commented by (4.3k points)
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     hello

Anyway, great job. Full marks.
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
  **   * ***    **  
***** *  ** *   ** ***  

int   *  * argc, char *argv[]) {
 *****     *  char *    *
* *** *      *   char letteri;
 **  * *    *** char  * *   
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* *  *  *  **** 
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* * ** * *   * *** * **    * +3;
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***       *   * 
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   **** *     return 0;
}


INPUT
 ** ****** ** *  * 
   **   **** **
OUTPUT
 ***** ** * ***** *
100/100 answered by (269 points)
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     hello

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
commented by (5.9k points)
0 0
prog.c:27:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:30:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:30:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
*** ***  *  ****  *   **
 ***  **   *     * *** * 

int   ** * * argc, char *  * {
  *   *  ****  * char ** 
 ****   ***  * * * char *** * 
*   **     * *  ***  char    * 
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*  * * *     ** *  
****   ** *  *** *   *      input the   *  to  *    *    * **   
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 * *** *     **** * 
   ***  **** **** letter = letter + 3;
 *  *  ** ****  ** =  * ** + 3;
*  *       * * *  *   =  * *    + 3;
     *   ** *  *    =    **  + 3;
 *     **  * *  *  ** * * =  *  + 3;
    *  * **   * 
***   * ***   *       *   ** * *  *     letter is  *   ****  **       ** *  *  **  *   * **  *****
  **** **  * 
 *  *    * **   return 0;
}

INPUT
 ****      ** ***  
* *  *      
*  **
** * *   *  ******
100/100 answered by (290 points)
reshown by
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     The encrypted letter is hello

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
commented by (5.9k points)
0 0
prog.c:26:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:29:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:29:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
#include  ***    *** **    

int main(int argc, char *argv[]) {
*** ** * *** ** * * *     * lettera;
  * *     *** **     ** letterb;
* **** *       **   *  **      * letterc;
*    ** *  **   ** ***  *  letterd;
      **  * *      *   *  *  * lettere;
*  **   *    * * ****  * *  
 * *        * * **   *      * *   **      * ** %c %c %c ******  * *     *** *  ** ***  * ** * *  * **  ***** * *  *  * * * *     
    *   ** * ***** *  *  **   * = lettera + 3;
* ** **  ** *     *** * = letterb + 3;
* *   *  * ** ** ****  *   *** = letterc + 3;
 ***    *  **** *** ***** * * **  * = letterd + 3;
* *  * * ** ******  *  ** * **  ** = lettere + 3;
*  **  *  * **** ***  ***** *  **      *    ***    
* *          ***** ***    * *     *** **** %c %c %c *   ****  * **** letterb, *  * *  *      ***
 **** *  ***     **  *  * 
 *  *** *   * **  *  *  * **  *  *** * 0;
}

 *  **
     *
 *   ** *** 
*  ** *
//hello
100/100 answered by (271 points)
edited by
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: e b i i l
     h e l l o

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
commented by (5.9k points)
0 0
prog.c:25:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:28:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:28:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:10:5: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
     scanf("%c %c %c %c %c", &lettera, &letterb, &letterc, &letterd, &lettere);
     ^~~~~
prog.c:10:5: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:10:5: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:17:5: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
     printf("%c %c %c %c %c", lettera, letterb, letterc, letterd, lettere);
     ^~~~~~
prog.c:17:5: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:17:5: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
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