[Exercise 03] Caesar Cipher Decoder

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You have received an encrypted message from Julius Caesar-- the message is ebiil.  You are asked to decipher the message in order to understand what Caesar trying to say to you.

Hint

Luckily, Caesar has given you a hint, he says: 'I, myself, encoded the message by shifting every word backwards by 3.' 

Solution

Write a program that receives 5 characters 'ebiil'. Then decode those characters into 5 new characters.

Example

#include <stdio.h>

int main(int argc, char *argv[]) {


	char a;
    	char b;
	 	
	scanf("%c%c", &a, &b);
	
	//decode the message how??
	
	printf("%c%c", a,b);
	
	return 0;
}

Input

ebiil

 

 

 

 

 

 

 

 

 

 

Output

hello

** REMEMBER ** 
This is an online-compiler, don't put anything except the codes. If you want to make a comment, please use // or /* */

[Exercise] Coding (C) - asked in Chapter 2: Syntax structure of the C language by (5.9k points)
ID: 26955 - Available when: Unlimited - Due to: Unlimited
edited by | 1.1k views

22 Answers

0 like 0 dislike 
Hidden content!
   ****    *  *  *  

int  * *** argc, char ** *  {
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** *   *** * return 0;
}
100/100 answered by (449 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
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100/100 answered by (153 points)
0 0
Case 0: Correct output
Case 1: Wrong output
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
#include * ******     * *** 
#include     **  * *****

/* run this program using the console pauser or add your own getch,  * * *  * * *  **   or input loop */

int main(int argc, char *argv[]) {
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***   *  * *  ******** ***   *   
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*** *** ***      *** *  = e+3;
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}
100/100 answered by (281 points)
edited by
0 0
Your program receives only 2 characters, and it doesn't move characters' positions.

Try to make it receive 5 characters, and move their positions forward by 3.
commented by (5.9k points)
0 0
This exercise expects only 'hello'. However, your code has.....

printf("Put the words you want to decode:");

Kindly consider delete this part :)
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
 ** ** ***** ** *    *
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int    * **  *  char   ***   {
/*
*** * *** **  */

*** * *** * 

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a = a+3;
b = *   
c = **
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*  * ***  *    ***  *
* *    *  *       ****   ** **  **  0;
}
100/100 answered by (273 points)
edited by
0 0
prog.c:28:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:32:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:32:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
0 0
Your program can end at
  
    return 0;
}
------------------------------------------
You don't need to put

INPUT

ebiil

OUTPUT

hello
commented by (5.9k points)
0 0
Case 0: Correct output
Case 1: Wrong output
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
****  *    * **** *
**   *********  *** * 

/* run this       *  the    **   * or add your own      ** ** ****      *     **   or    * * */

int **    *   char * *    {
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}
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 ** ***  *     ***  0;
50/100 answered by (252 points)
0 0
prog.c: In function 'main':
prog.c:19:2: error: expected declaration or statement at end of input
  return 0;
  ^~~~~~
commented by (4.3k points)
0 0
Great job using an array and a loop. There are two mistakes found in your code. Please check
1.     printf("\n\n%s", code);  <--- in order to make it match the fixed output '\n\n' should be deleted
2.     At the end of your code, there's something missing.
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
** *  *   *** *** * * 

   **  *          * ***** * 

 ** * *  ** ** *   *   *    *   ** * ** *  ** *    *  * ***   * *** *** ** *   * **   *  * 

*  *  **           *  
 
**      *   

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**  * ***  *      *   ** *** ****     ***** * ** *    **    *  * * *       ** 
*
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* * b + **

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  = d + **
*
*       
 
***  *****  **   * ****** *   * * *** *     
*
**     *
*
*
100/100 answered by (268 points)
0 0
It's correct lol you can't judge me
commented by (268 points)
0 0
Well, that's because your output doesn't match with the fixed answer. Please take a look at this
printf("%c%c%c%c%c\n", a1, b1, c1, d1, e1);

Hint: You should delete something  :)

By the way, great job.
commented by (5.9k points)
0 0
printf("%c%c%c%c%c", a1, b1, c1, d1, e1);

How's that?
commented by (268 points)
0 0
That's correct.
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
*** *     *  ** ** * 
*** *      **   *** * 

int *** * argc, char ** * {
*  **  *   ** * char ****
   *  ****  *  * ** char *  
*   **     *  char *     * 
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*     * * ** ** 
 * ***  *****  *   *   **  * *   input the letter to   *   *   * * 
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*    *** ** ** = *  * + 3;
* *  *  *****  **  * = **** + 3;
  **** **  **      *  = ***   + 3;
*  ** *  * letterc =   *** + 3;
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   *      
*  *** *  ** ** *   **    * * * * **  * **     *  * *   *    *  ***
*  * *   *  *   
 *** **    return 0;
}
100/100 answered
reshown by
0 0
-----------Re-judge-----------
Case 0: Wrong output
commented by (4.3k points)
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     hello

Anyway, great job. Full marks.
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
** *    ***  *  **   **
**   *   * *   * **

int      argc, char *argv[]) {
 ***   *     * * char *  
*     **    * char letteri;
*  **   **  * * * char  ***
 *   ***   **   char **  ***
 *    ** * char ****  
    *  ** * *** 
* **    * ****    **  **   **   **  input the letter to encode: *  * * * *  ** ***  
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***** **  * *   * **   ** *      ** ** ** *** * **  *   * * *** *** * ***  *  *   ** ** * **  ** ** *** 
** * * **  * **       **  *** +3;
*  *   *  *   *** **  * ***** +3;
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* ** *   **** * ** ****  *  +3;
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***  ** *   **  
*   *   *** ** 
** * *  ****    *** ***  ** *******    * ******  *   *  *   * * 
   *    * *   ** 
**  ***    ***    return 0;
}


INPUT
*** * *** * *  *  
**  * *    *
OUTPUT
*** ****** *  * **
100/100 answered by (269 points)
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     hello

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
commented by (5.9k points)
0 0
prog.c:27:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:30:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:30:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
***  ****  ****   *   
**        ** **** * 

int  ***   argc, char *****    {
  *      *  char ** 
*       *  *  ***  char   *
**  *     * char * *** 
    ***  **    ** char **** *
** *  *    **  char ***   
******   * *    
*    *  * **     * ***  *  * * * input the *     to * ** ***  * **     *   *  
 *  *  **   *     
  * *** * *  *** ***   * * **   **  * ** ****  **       *    **   ***  ***   *****  *  *   *
***  * **  *   
* ** *** * **** letter = letter + 3;
**   ***   ** *   *   = ** ** + 3;
*  * ***    * *  ***  =   ** * + 3;
**        ** * **  = ***   + 3;
 *  *   *    * * ****** =   ** + 3;
      *   * *  
 ***     * **  *    * * * ***  ****** letter is *     **  **  *  **    * ***  *  *  **   * 
 ****** *  **  
 * *      * ***  return 0;
}

INPUT
***  ****          **
****  *** ***
*    
*  *****
100/100 answered by (290 points)
reshown by
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     The encrypted letter is hello

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
commented by (5.9k points)
0 0
prog.c:26:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:29:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:29:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
#include       **   *** ****

int main(int argc, char *argv[]) {
 *************   **   ***  *** ** lettera;
 * * *   *  ** * **** ****** letterb;
*       * *** **   ** ** *   letterc;
*   ***** * *    ***   ** ** letterd;
 *   **  * ******* *  *  *    lettere;
 *  *   **      **    *  * *
 * **  *  * *   ******  ** * ***** *    %c %c %c  **** ** *** **  **   *  **** *  * ** **** ***  * ** *      **  *    *** 
    * * **  **      **    *    = lettera + 3;
  * ** *  * *** *** ** *** * = letterb + 3;
 * ** **  ********** *** ****   ** = letterc + 3;
   ***  **   *   * *   ** *    = letterd + 3;
 *  **  *  *   *  ***  ** * **** * ** = lettere + 3;
 ***** *******    *   **** * * *** ** ******  ****
*  **  **  ** ** *  *     *   * * * ** %c %c %c *  ** *     ****  letterb,    * ***       * *  
    *****   **** **   * **   * 
  **     ******  * **  *  *****  *** 0;
}

    
  * *
    **  *  * 
**  * *
//hello
100/100 answered by (271 points)
edited by
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: e b i i l
     h e l l o

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
commented by (5.9k points)
0 0
prog.c:25:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:28:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:28:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:10:5: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
     scanf("%c %c %c %c %c", &lettera, &letterb, &letterc, &letterd, &lettere);
     ^~~~~
prog.c:10:5: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:10:5: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:17:5: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
     printf("%c %c %c %c %c", lettera, letterb, letterc, letterd, lettere);
     ^~~~~~
prog.c:17:5: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:17:5: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
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