[Exercise 03] Caesar Cipher Decoder

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You have received an encrypted message from Julius Caesar-- the message is ebiil.  You are asked to decipher the message in order to understand what Caesar trying to say to you.

Hint

Luckily, Caesar has given you a hint, he says: 'I, myself, encoded the message by shifting every word backwards by 3.' 

Solution

Write a program that receives 5 characters 'ebiil'. Then decode those characters into 5 new characters.

Example

#include <stdio.h>

int main(int argc, char *argv[]) {


	char a;
    	char b;
	 	
	scanf("%c%c", &a, &b);
	
	//decode the message how??
	
	printf("%c%c", a,b);
	
	return 0;
}

Input

ebiil

 

 

 

 

 

 

 

 

 

 

Output

hello

** REMEMBER ** 
This is an online-compiler, don't put anything except the codes. If you want to make a comment, please use // or /* */

[Exercise] Coding (C) - asked in Chapter 2: Syntax structure of the C language by (5.9k points)
ID: 26955 - Available when: Unlimited - Due to: Unlimited
edited by | 10k views

22 Answers

0 like 0 dislike 
Hidden content!
****    **** *** *  *

int  *  argc, char ***** {
    *  ** *** * *   *  * ** *  */

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* *  *  * ** return 0;
}
100/100 answered by (449 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
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100/100 answered by (153 points)
0 0
Case 0: Correct output
Case 1: Wrong output
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
#include   **  *    ** * *** 
#include **    *  * *   * 

/* run this program using the console pauser or add your own getch, **** *  * ** **  **** or input loop */

int main(int argc, char *argv[]) {
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* *  * * ****    ** *  * * **  b;
* ******** **   ** ***   c;
* *  *      **  *  **    ***** d;
*  ** **    ***    * ****** e;
*   *** *   * **     ***   
*   ***** ****  *  * *   *  ** *  ** *** * the words you want to     **** ***  *
* *   **  ** *  *** **** *   
* *  **  ** *   ** *  **  * = getchar();
** * **** *  * ** **  * **** = a+3;
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  ***      *    ***   **  = b+3;
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**  **       *   *  * **    **  * *  * 
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*  *  *   ***      ** * **    **
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 **  ****  *     * ***  *  = e+3;
******  * *    * *    *    * * * *  
**  * **** *** *  ** *  *    ****   * *  *   * **  ******** * *
* * * * ** * * * ***    * * ** **   *  *   ** **      &a, &b, &c, &d,  **   
** ** *    ****  *   ***  * *
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****       ***  **      * ***  * * *** ****  **  a, b, c, d, e);
 ** * *** *    *   * ** * 
** **  **** *    **    * *    **   0;
}
100/100 answered by (281 points)
edited by
0 0
Your program receives only 2 characters, and it doesn't move characters' positions.

Try to make it receive 5 characters, and move their positions forward by 3.
commented by (5.9k points)
0 0
This exercise expects only 'hello'. However, your code has.....

printf("Put the words you want to decode:");

Kindly consider delete this part :)
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
 * ***  ***  * **  ** *
**  *** ** *   

int **  *     *  char *****  {
/*
*  *  *  ***** */

   *  * *

* * * *  ***     * *** * **   **  *  *** *   **  * ** * ****** * * *  
a = a+3;
b =  *  
c = ****
d = d+3;
e =   

* **  the   *  ***
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* **    ****  ***   *  * *** ** 0;
}
100/100 answered by (273 points)
edited by
0 0
prog.c:28:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:32:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:32:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
0 0
Your program can end at
  
    return 0;
}
------------------------------------------
You don't need to put

INPUT

ebiil

OUTPUT

hello
commented by (5.9k points)
0 0
Case 0: Correct output
Case 1: Wrong output
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
   *   **  * ** * ** *
    *  *  ****** ** **  

/* run this  * *  ** ** the  * *  *** or add your own     ***** ***     *     or *     * */

int * ***   *  char * *    {
*    *       * *  int num,  *** *
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{
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* ***   * *    *  **  * 
}
* ***  *   ** * * *** **   ** *  ***   *  
   ***    **     *   0;
50/100 answered by (252 points)
0 0
prog.c: In function 'main':
prog.c:19:2: error: expected declaration or statement at end of input
  return 0;
  ^~~~~~
commented by (4.3k points)
0 0
Great job using an array and a loop. There are two mistakes found in your code. Please check
1.     printf("\n\n%s", code);  <--- in order to make it match the fixed output '\n\n' should be deleted
2.     At the end of your code, there's something missing.
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
**** *  * *  * * **
*
  ***  * * **   ** **** **
*
    *   **  *     *  * **  * *     *  * * ***   ***   ** * ***  *  *   **  ***  *
 
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*
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*      *  **     * 
*
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**  = * *  *

*  * b + *

 *  = c + *

   = d + **
*
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*
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****
100/100 answered by (268 points)
0 0
It's correct lol you can't judge me
commented by (268 points)
0 0
Well, that's because your output doesn't match with the fixed answer. Please take a look at this
printf("%c%c%c%c%c\n", a1, b1, c1, d1, e1);

Hint: You should delete something  :)

By the way, great job.
commented by (5.9k points)
0 0
printf("%c%c%c%c%c", a1, b1, c1, d1, e1);

How's that?
commented by (268 points)
0 0
That's correct.
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
  * ** *  *** *  *** ***  
* * *   *   * ** * ** * 

int      argc, char *  *  {
   *   * * * ** char ** * *
* *   * *   *** char *    *
*   ***** *** * char *** *** 
   *** * *     char **  
***** * *  * **  char * *  
**  * ** *  ** *  
* *    * **  *   **   ***   * **   input the letter to *** *  *   *
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**   * *  ** *   ***  * * *  *  ** * * *  *  **   *    *  * ** * ***       **** ** *** ***  *  ** * **
*   *    *** *      =    **  + 3;
*   **      * *  * * * = *    + 3;
 *    *  * ****   * * =    *  + 3;
  *  **    **  letterc =  *  * + 3;
** *  **  ***  **   =   *  + 3;
   **** * *  **   
***  **  * **   *  *  *  * *  *    ** **** ** * * **   * *    * * * ** * * *** 
   * ***** *  *  ** 
**** *   *  * return 0;
}
100/100 answered
reshown by
0 0
-----------Re-judge-----------
Case 0: Wrong output
commented by (4.3k points)
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     hello

Anyway, great job. Full marks.
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
   *   ****   ** ****
**       *  ** * * *

int ** argc, char *argv[]) {
***** * *  **    char  ***  
 **    *   *  char letteri;
 *   * * ** *  char     **
* * **    ** * * char *    *
 *  * *  * * char * *** 
**   **  **** 
 * *   * ** *  * ** ** * **  input the letter to encode: **     ***   **** 
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*** * ***** *    * *   ** **** * ***  *   * **  *  *****   * **  ** *** **** *   *** **  *** ***  * *   * 
   **   *  * *  *  **   +3;
** **  * ** *** *    * +3;
** *** * *     *** * *** +3;
 **   *   * *    *  * *** * +3;
   * * *   * * *      *** +3;
  **   *  ** 
***  *  * * ***   
**    * ** *     ** * *   *  *   ** **  *  * *   * ****  *** *
 *****    **  
  *  *    ** **** return 0;
}


INPUT
* *   * * **** ** 
  * **  **** 
OUTPUT
*     *  * ***
100/100 answered by (269 points)
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     hello

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
commented by (5.9k points)
0 0
prog.c:27:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:30:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:30:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
*   *  **    ***     ***
** ** **  * * * * *  *

int **** argc, char   **** {
* ** *  * * **  char      
 * ** ***         char  * *
** ** *   ** * char ***  
 *** *    ****** char   **
 ****  **    * char *  ** 
*    **  * * * 
  **      *   *    **    * input the ** * to * ** * *   **  *  ***
 ** **  *  * *  
   *******    *      ** ** ***  * **  *       *  *        * ** * * ** *   **  **  * **  ****  
* * *  *    ** 
 * ** * **    * letter = letter + 3;
** **  ** ** *  ** ** =  ** + 3;
   *  * * * *  *  *   = *  *  + 3;
** *** ** * **** ** =   ** + 3;
** ** **   **** *  * =  *** + 3;
*  **     *** *   
**  * *      *   *   ****  ***  *  ***    letter is    * ***  *          *  *  **     *  *    ** 
** ***   ******* * 
      **   *  return 0;
}

INPUT
 *      *** ** ****  
*  * ****      
  
 **  *    *
100/100 answered by (290 points)
reshown by
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     The encrypted letter is hello

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
commented by (5.9k points)
0 0
prog.c:26:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:29:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:29:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
#include * *  **     **

int main(int argc, char *argv[]) {
  *     **   ***** *  *** * lettera;
 ******* **** * *** *    **** * letterb;
 * * **  *  ** *  *** letterc;
* *** * *** ****      * ****    letterd;
 ***  *    *   *      *  * *   *  ****  lettere;
      *    * * ** * ***** 
 *** * *** ******* ***   * *  * *   * *** %c %c %c * ***  **   ** * ****      *    **   ******  * *    *  ***          *     
      **** * ** * **  * ***** = lettera + 3;
*    * * *  * ***   * **    = letterb + 3;
***** **    *      *   ***  *** = letterc + 3;
******  *   ***    * * * ** *   **   = letterd + 3;
***** *  *     * * * ***   * *  = lettere + 3;
 **      * * ***  *  **    *   ****  * *  ****    *   
** *    *** *  ** *  * ** *       **  %c %c %c   *    * ** letterb,          *        ******
*** *   **   * ***** *  * 
 ****** *  *  ***   * ** ****  * 0;
}

*   **
* * *
  ****  *** * **
 **  *
//hello
100/100 answered by (271 points)
edited by
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: e b i i l
     h e l l o

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
commented by (5.9k points)
0 0
prog.c:25:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:28:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:28:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:10:5: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
     scanf("%c %c %c %c %c", &lettera, &letterb, &letterc, &letterd, &lettere);
     ^~~~~
prog.c:10:5: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:10:5: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:17:5: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
     printf("%c %c %c %c %c", lettera, letterb, letterc, letterd, lettere);
     ^~~~~~
prog.c:17:5: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:17:5: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
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