[Exercise 03] Caesar Cipher Decoder

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You have received an encrypted message from Julius Caesar-- the message is ebiil.  You are asked to decipher the message in order to understand what Caesar trying to say to you.

Hint

Luckily, Caesar has given you a hint, he says: 'I, myself, encoded the message by shifting every word backwards by 3.' 

Solution

Write a program that receives 5 characters 'ebiil'. Then decode those characters into 5 new characters.

Example

#include <stdio.h>

int main(int argc, char *argv[]) {


	char a;
    	char b;
	 	
	scanf("%c%c", &a, &b);
	
	//decode the message how??
	
	printf("%c%c", a,b);
	
	return 0;
}

Input

ebiil

 

 

 

 

 

 

 

 

 

 

Output

hello

** REMEMBER ** 
This is an online-compiler, don't put anything except the codes. If you want to make a comment, please use // or /* */

[Exercise] Coding (C) - asked in Chapter 2: Syntax structure of the C language by (5.9k points)
ID: 26955 - Available when: Unlimited - Due to: Unlimited
edited by | 2.4k views

22 Answers

0 like 0 dislike 
Hidden content!
****    *  ******* * ** 

int   * * argc, char ** ** {
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}
100/100 answered by (449 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
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* *             ** ** {

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100/100 answered by (153 points)
0 0
Case 0: Correct output
Case 1: Wrong output
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
#include *   *  *  * **  
#include * *  * *      **

/* run this program using the console pauser or add your own getch, * * * ** *      ***** or input loop */

int main(int argc, char *argv[]) {
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*  ****   *  ***  *  *    * * ** c;
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*  * *  ** * ** *    **** *   = a+3;
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   ****  *  ******* *   ** ** 0;
}
100/100 answered by (281 points)
edited by
0 0
Your program receives only 2 characters, and it doesn't move characters' positions.

Try to make it receive 5 characters, and move their positions forward by 3.
commented by (5.9k points)
0 0
This exercise expects only 'hello'. However, your code has.....

printf("Put the words you want to decode:");

Kindly consider delete this part :)
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
* **  **** * **   *  
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int   **  ** char ****  {
/*
***  * *** * */

***  ****   *

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a = a+3;
b =   
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* *** * **** ***   *
***   *  *  **  ********   * **  0;
}
100/100 answered by (273 points)
edited by
0 0
prog.c:28:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:32:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:32:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
0 0
Your program can end at
  
    return 0;
}
------------------------------------------
You don't need to put

INPUT

ebiil

OUTPUT

hello
commented by (5.9k points)
0 0
Case 0: Correct output
Case 1: Wrong output
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
 *    * * *    ** * 
* *  **   * * *** *** 

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}
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  **   * *   ****   0;
50/100 answered by (252 points)
0 0
prog.c: In function 'main':
prog.c:19:2: error: expected declaration or statement at end of input
  return 0;
  ^~~~~~
commented by (4.3k points)
0 0
Great job using an array and a loop. There are two mistakes found in your code. Please check
1.     printf("\n\n%s", code);  <--- in order to make it match the fixed output '\n\n' should be deleted
2.     At the end of your code, there's something missing.
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
***   *   *    * *  **
 
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*   *** ** * **      *  *   ***   * *       ***     *  ** ** **   * * * ***  ***       * *** *
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* = c +   

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*   *    

******    ** ******* * * **   **  *  ***

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*
*
100/100 answered by (268 points)
0 0
It's correct lol you can't judge me
commented by (268 points)
0 0
Well, that's because your output doesn't match with the fixed answer. Please take a look at this
printf("%c%c%c%c%c\n", a1, b1, c1, d1, e1);

Hint: You should delete something  :)

By the way, great job.
commented by (5.9k points)
0 0
printf("%c%c%c%c%c", a1, b1, c1, d1, e1);

How's that?
commented by (268 points)
0 0
That's correct.
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
 *   *   *  * ***  **  
*     *  *  ******  * * *

int *  *  argc, char  ***  {
 **  * **  *  * char *  *** *
* *  * * *** ** char ***  *
***   * *** * char   
* *** ** *      char *  ** 
**  ****     ** char **    
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  **   * *   * ***  ****   ** input the letter to  * *  **   *
 ****     ** * * 
*  * *  * *** * **    ** *** * *    ** *      * **    * * * * *     ** ** * * **  **       *  ****   **     *** 
 **  **  *** *    **  =    *  + 3;
 ****      *     **   = *  *    + 3;
      *    **    **  * *  =  ** * + 3;
*  *  *   ** * letterc =  * *  + 3;
*  * *  * ****      * *  = ***  + 3;
 * *     *  ** 
   *     ***   ** ****  * **************    **** *  ******  *  *  *** * ***  *
*****  * ***** 
 * *    *   *  return 0;
}
100/100 answered
reshown by
0 0
-----------Re-judge-----------
Case 0: Wrong output
commented by (4.3k points)
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     hello

Anyway, great job. Full marks.
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
    *    **    *** * * *
 **  *     *****     ** 

int ** *  * argc, char *argv[]) {
*   *  ***   *  char **  **
**           *** char letteri;
**  ** * **** ** char    
* * **   * * char ***** 
*  * *    * * * char *    * 
* *       **     * 
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** * **   ****  * ** * **  +3;
* *     **** *   *  *  ** +3;
  *  **     ****  ***   * *     +3;
**   *  *  ** *   * * *** +3;
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* ***  * *   *   *     ** **** ** **** ******* *    *** * *** ***  *  **   
  **** ** * 
 **  * *   *  ** return 0;
}


INPUT
  * **  ** *  *  ** *
 **   **** *
OUTPUT
* * ** *    *
100/100 answered by (269 points)
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     hello

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
commented by (5.9k points)
0 0
prog.c:27:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:30:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:30:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
 ***** * **** ** * *  
  *  ** * *    * *      *

int *  *  argc, char      * {
*  *     * * char  **  
*****      ***** char *  
***      * * char ***  *
 *  *  *      ** char * **  
 *** *         * char   *    
  *          *** 
*** * *  *  * *  * *** **  *   * * input the ** **  to ** *   **         * 
*  *** *     
   * *  * ** * *  *  ****  * *** ** * *****    *  **  * ***    ** *   **   * *   *     * *   ** *  **** 
***     ***  *   
    **   * * letter = letter + 3;
** *     *** ***   = ** ** * + 3;
*  *   * *  * * *   *  = **    + 3;
 *** ** *    *    *  **  =     **  + 3;
*   *   * **** * *    * = *** + 3;
*        * * ** 
*  * *  ***      ***  ****  *  *** ** letter is  *   ** *** ****   *   ***  * ** * ** *
  ***   *** *  * 
   **** **    * return 0;
}

INPUT
** *** * * **  * *** 
*  ***   
 ***
* *** ** * *  * *
100/100 answered by (290 points)
reshown by
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     The encrypted letter is hello

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
commented by (5.9k points)
0 0
prog.c:26:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:29:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:29:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
#include  *   * * ***

int main(int argc, char *argv[]) {
*  ** ***  * ** *** *     lettera;
 *  ***     ** **  ***** ** ** letterb;
*    *   * **  ******** *  letterc;
 ****   *   ****  ** *   *** *    letterd;
*****   *****   * **** * *  *  * lettere;
 ** *  *   * *   *   **
 * ****  * * * * ** *  *** ***  ** *** *** %c %c %c **  ****   **** *** *   **   ** *    ** **       **  **   *** **  *  **** 
* ** *   *** ****  *  *** **** = lettera + 3;
*   *  ** * *  *  *    ****    = letterb + 3;
* *  ** *    **  * ** ** ** *  = letterc + 3;
   **    *    *  *  *****  *    = letterd + 3;
* **** *****   *   *** **** ** ** = lettere + 3;
* ****   *  *      *** **** *    *  *****   ************
 *  ** *  *  * **** * * *  ***   ** * %c %c %c    *      *** * letterb, *** *  * *** * * *
** *  ** ** ** ** * *** * * * 
****    * * ******   * ** ** * **  * 0;
}

     
  **
    ** ** *
*** *
//hello
100/100 answered by (271 points)
edited by
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: e b i i l
     h e l l o

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
commented by (5.9k points)
0 0
prog.c:25:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:28:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:28:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:10:5: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
     scanf("%c %c %c %c %c", &lettera, &letterb, &letterc, &letterd, &lettere);
     ^~~~~
prog.c:10:5: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:10:5: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:17:5: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
     printf("%c %c %c %c %c", lettera, letterb, letterc, letterd, lettere);
     ^~~~~~
prog.c:17:5: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:17:5: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
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