[Exercise 03] Caesar Cipher Decoder

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You have received an encrypted message from Julius Caesar-- the message is ebiil.  You are asked to decipher the message in order to understand what Caesar trying to say to you.

Hint

Luckily, Caesar has given you a hint, he says: 'I, myself, encoded the message by shifting every word backwards by 3.' 

Solution

Write a program that receives 5 characters 'ebiil'. Then decode those characters into 5 new characters.

Example

#include <stdio.h>

int main(int argc, char *argv[]) {


	char a;
    	char b;
	 	
	scanf("%c%c", &a, &b);
	
	//decode the message how??
	
	printf("%c%c", a,b);
	
	return 0;
}

Input

ebiil

 

 

 

 

 

 

 

 

 

 

Output

hello

** REMEMBER ** 
This is an online-compiler, don't put anything except the codes. If you want to make a comment, please use // or /* */

[Exercise] Coding (C) - asked in Chapter 2: Syntax structure of the C language by (5.9k points)
ID: 26955 - Available when: Unlimited - Due to: Unlimited
edited by | 3.5k views

22 Answers

0 like 0 dislike 
Hidden content!
***    **  *  * ** 

int     argc, char *   {
****     *               * * ** */

* *  * ** *  ** * int number;
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  *  ***  **** return 0;
}
100/100 answered by (449 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
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100/100 answered by (153 points)
0 0
Case 0: Correct output
Case 1: Wrong output
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
#include    * **   *  * 
#include  *    ***    **

/* run this program using the console pauser or add your own getch, **** * **  ** ** * or input loop */

int main(int argc, char *argv[]) {
** * *  **  ** *  *  ** * **   * a;
***    *****  *   *** ***     b;
  *****      ** *  *   *  * c;
 *  **  *   *   *** ****** ***  d;
 *  *** * * * ** ********* ***   e;
* ***       * * ***** * ** 
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** *  **  *   **  ** **
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  *   * * ** * ****     ** = a+3;
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* ***    *  *   * * * *  * * ** = getchar();
 ** *** **      ***** * *  = b+3;
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*   * *   *  ****   **  ***   *   = getchar();
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** ***  *** ** *  * * ** *   **  * 
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*  *  **     ** * ** * ** = d+3;
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   ** ** *  *** ** ******  *  = e+3;
*  ** ***   *** * *    * *** * **** * 
*** *    * ********* ****** ****** ** * **  * ** **  * ******
** ***    *   *****  * ** ** * * ***** *** *****   ** *  &a, &b, &c, &d, *** ****
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**** * *     * ** * ***   
 *   ****  * * **    ** **  *     0;
}
100/100 answered by (281 points)
edited by
0 0
Your program receives only 2 characters, and it doesn't move characters' positions.

Try to make it receive 5 characters, and move their positions forward by 3.
commented by (5.9k points)
0 0
This exercise expects only 'hello'. However, your code has.....

printf("Put the words you want to decode:");

Kindly consider delete this part :)
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
*** *  ***  **  * **
**       *** * *  * ***  

int    **   char *** * {
/*
***  * *** */

    *    * 

* * ******** *** ** ****    *  * * * ****   ** **  *     *  *   * ** 
a = a+3;
b = * **
c = **  
d = d+3;
e =  *

****  the * **    ***
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  **  **   * * **  * * * **** 

*******  *    *** *  *
*** ********   **   * * **  * *  0;
}
100/100 answered by (273 points)
edited by
0 0
prog.c:28:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:32:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:32:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
0 0
Your program can end at
  
    return 0;
}
------------------------------------------
You don't need to put

INPUT

ebiil

OUTPUT

hello
commented by (5.9k points)
0 0
Case 0: Correct output
Case 1: Wrong output
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
*     * *****  * * *  
*  **  * * ****     ***

/* run this ***** * the ***     * or add your own **    * * ** * *** ***   * or *   *   *  */

int  * ** *** char *  {
   *** * *  **  * int num,  *
*  *     **     ** 
        * *   * 
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        ** * **  for  * =  *   *  ** ***
{
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*** * *    *** *  if *  ** * *** *  * 
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*  *** *    *     * * *****
}
   *  **    *    ** **   ** **** **     * 
   * *     ***  *   **   0;
50/100 answered by (252 points)
0 0
prog.c: In function 'main':
prog.c:19:2: error: expected declaration or statement at end of input
  return 0;
  ^~~~~~
commented by (4.3k points)
0 0
Great job using an array and a loop. There are two mistakes found in your code. Please check
1.     printf("\n\n%s", code);  <--- in order to make it match the fixed output '\n\n' should be deleted
2.     At the end of your code, there's something missing.
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
  ** *  **  *   * **
*
*  *     * ****    ** *
 
 *  **     **** * *    **  * *    * **  *  **    ** *** *   * * **  **   **  *

****  * *    *** **       
 
** * * *  * * 

         * * * * *  **

 *  * *  * * *  *  * * * **  * *  *   **     *   **  *   **   ***  *  * ** **

    = * * 

 *  * b +  

*  = c + *

 ** = d + **
 
 ** *     

**  **  * ****     *  **   * * **    *    * 

* * **  

 *
100/100 answered by (268 points)
0 0
It's correct lol you can't judge me
commented by (268 points)
0 0
Well, that's because your output doesn't match with the fixed answer. Please take a look at this
printf("%c%c%c%c%c\n", a1, b1, c1, d1, e1);

Hint: You should delete something  :)

By the way, great job.
commented by (5.9k points)
0 0
printf("%c%c%c%c%c", a1, b1, c1, d1, e1);

How's that?
commented by (268 points)
0 0
That's correct.
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
*  *  *     * *****   
** *** * ****   *    * 

int  ** ** argc, char    * * {
   **     * *   char   
** *   ** *** ***   char    *
 ***  **   ** ***  char   * * *
* *    *  * *  char    *  *
  *    *  char *  **
*   ** * *   *  
*  *    *  *  *   **  ** ***  input the letter to      * **    
* ***    ** ***  
     * **     ******  **  * *   **        ** *  ** * *  *  * ***  * *  **    **     * * *  * ****
* ****   *  ***    **  =      * + 3;
** **   ** *     *** =     * + 3;
  **           *    = *  *  + 3;
***  *  *   *    * letterc = ***  + 3;
*****   * * * **  *  = ***** + 3;
    *** **    * * 
** * *    *  **           **** ***  **     ****  ** *  *     *   
*  *  ** *  ***** 
 * ***  *    **  return 0;
}
100/100 answered
reshown by
0 0
-----------Re-judge-----------
Case 0: Wrong output
commented by (4.3k points)
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     hello

Anyway, great job. Full marks.
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
  * * *  *** * 
 ** * ** ** ** *  **   *

int * * *  argc, char *argv[]) {
*  ** * ******  char *  
  **** *  * **   * char letteri;
*     *  *      char *** 
  *****  **  **   char  *** 
   *   * *  *   * char *  ** *
 * * *   * *   
** *   *   ** * * **   **  input the letter to encode: ** *   *     * *** *
 ****     **  
 * ** * *   *  ****     **   *  *   *  ** * ***** ** * ***  * ****   *  ** ****   ****  ******     *   *     
 **  *   *    *   **  *   *  +3;
** **     *  *** *  *   *  * +3;
  ***  * *    *   *  *   * ** +3;
   * **  *        *****   +3;
* *   **  **   * *     **  * +3;
***     * **  **  
**     *  
**  *** *  ** *  *** *******  ** ** ** ** ** * * * *     * **  * ** 
 *   *   ****  *  
*     **   * ***  return 0;
}


INPUT
*  **  *      *
*  * **   *   *
OUTPUT
* * * **  *** **
100/100 answered by (269 points)
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     hello

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
commented by (5.9k points)
0 0
prog.c:27:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:30:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:30:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
* * * ** ****  *  * 
 * ** * *     ****  * 

int *      argc, char *   * * {
******  * ** ***  char  *****
**   *   ** ** * * char       
**  **  **    char  ** ***
 ***   *   ** * char *     
*  * *  ***   char ***
     * * *   
    * **  * * **       **  ***   input the  **  *  to    ** * *  **** * *  *
*  *  * *  *  
*     *** * **  *    * ****  * **  *  ** **  ** *   ***   * **  ** *  *   ********  * *** *        * ** 
*****  **  *     * 
 * * ** *     letter = letter + 3;
**  *    * * * **   * =      + 3;
  * * *     ***  * * *** = ** * + 3;
**** *  **      ***  = ** * + 3;
 *** *   ***  ***** =  * * + 3;
* **       *****  
** *  ** ***** * * * *   *    **  * * *    letter is  ****  * **   *  * ** * *   *  **    ***     ** * 
 *  ***  * * * 
 * **  *    *  return 0;
}

INPUT
  **  ****  
  *    **** ** 
****
    *** * ***
100/100 answered by (290 points)
reshown by
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     The encrypted letter is hello

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
commented by (5.9k points)
0 0
prog.c:26:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:29:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:29:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
#include  * *** **

int main(int argc, char *argv[]) {
 * *  * * *   ***   ***  * lettera;
  **    ****   ** ***  *    letterb;
*** * ****    *** *       * **** **** letterc;
 * * *  **   * *     ***** *** * * letterd;
*    *     * ******     *    lettere;
 **  ** **  * *** * *  * *  
*   ******  *   *** ***  ***  ** ** %c %c %c ** **   *  * **     ** *   *  **  ***   ***  ****   *    *** * ****   **  ** 
* *   * *  * * *    *** * *** **** = lettera + 3;
 *   ** *  *   * *****  *  **  * = letterb + 3;
** *  *  *** *  ****    **  *     = letterc + 3;
 ** ** *     * *  **  *****  *  = letterd + 3;
* ** ***    * ***** * *       = lettere + 3;
 *****  *** * *     ** *  *  **  ***    * ****  ** * ***
 ***  ********  * *    * *  * **   **  *   * %c %c %c  **    * **  letterb,   **    *  *  ** **  *
* * **  ** ** **     
  ** * * **  * *   *  ***  *  *  * 0;
}

  **  
* *   
 *   *     ** *
      * 
//hello
100/100 answered by (271 points)
edited by
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: e b i i l
     h e l l o

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
commented by (5.9k points)
0 0
prog.c:25:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:28:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:28:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:10:5: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
     scanf("%c %c %c %c %c", &lettera, &letterb, &letterc, &letterd, &lettere);
     ^~~~~
prog.c:10:5: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:10:5: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:17:5: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
     printf("%c %c %c %c %c", lettera, letterb, letterc, letterd, lettere);
     ^~~~~~
prog.c:17:5: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:17:5: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
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