[Exercise 03] Caesar Cipher Decoder

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You have received an encrypted message from Julius Caesar-- the message is ebiil.  You are asked to decipher the message in order to understand what Caesar trying to say to you.

Hint

Luckily, Caesar has given you a hint, he says: 'I, myself, encoded the message by shifting every word backwards by 3.' 

Solution

Write a program that receives 5 characters 'ebiil'. Then decode those characters into 5 new characters.

Example

#include <stdio.h>

int main(int argc, char *argv[]) {


	char a;
    	char b;
	 	
	scanf("%c%c", &a, &b);
	
	//decode the message how??
	
	printf("%c%c", a,b);
	
	return 0;
}

Input

ebiil

 

 

 

 

 

 

 

 

 

 

Output

hello

** REMEMBER ** 
This is an online-compiler, don't put anything except the codes. If you want to make a comment, please use // or /* */

[Exercise] Coding (C) - asked in Chapter 2: Syntax structure of the C language by (5.9k points)
ID: 26955 - Available when: Unlimited - Due to: Unlimited
edited by | 5.9k views

22 Answers

0 like 0 dislike 
Hidden content!
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}
100/100 answered by (449 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
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100/100 answered by (153 points)
0 0
Case 0: Correct output
Case 1: Wrong output
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
#include   * **** * 
#include *   *** * *    *

/* run this program using the console pauser or add your own getch,  ** *  *    * **   ***  or input loop */

int main(int argc, char *argv[]) {
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** *    *   * * ***** * ****** * c;
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******  ***   *   **   **   * 
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}
100/100 answered by (281 points)
edited by
0 0
Your program receives only 2 characters, and it doesn't move characters' positions.

Try to make it receive 5 characters, and move their positions forward by 3.
commented by (5.9k points)
0 0
This exercise expects only 'hello'. However, your code has.....

printf("Put the words you want to decode:");

Kindly consider delete this part :)
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
 *** *  ** ** ***** *  * 
**    *  * * *   *   * *  *

int ****    * char *  **  {
/*
  ** **  * */

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a = a+3;
b = ***
c =  ** 
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* ** ***** *  ** *  **  ** 0;
}
100/100 answered by (273 points)
edited by
0 0
prog.c:28:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:32:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:32:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
0 0
Your program can end at
  
    return 0;
}
------------------------------------------
You don't need to put

INPUT

ebiil

OUTPUT

hello
commented by (5.9k points)
0 0
Case 0: Correct output
Case 1: Wrong output
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
*   **        *
**  *       *   **** *

/* run this ****** *  * the  ** * ***   or add your own  **  * *    *** * *  *   * ** or     * */

int * ** *   char  *   {
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}
* ***    * *** ** * ***  ***  *  *  *** **  * * *
**  ***  *  *  0;
50/100 answered by (252 points)
0 0
prog.c: In function 'main':
prog.c:19:2: error: expected declaration or statement at end of input
  return 0;
  ^~~~~~
commented by (4.3k points)
0 0
Great job using an array and a loop. There are two mistakes found in your code. Please check
1.     printf("\n\n%s", code);  <--- in order to make it match the fixed output '\n\n' should be deleted
2.     At the end of your code, there's something missing.
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
  **  *  *  **   *****   
 
****     *  *  ******* 

 * *  * ****   ** *   *  * *  ***   * ** *     **    *** *** ** ******        **  **

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*  b + *

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* = d + **
 
*  *   **
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* ** *  *

*
100/100 answered by (268 points)
0 0
It's correct lol you can't judge me
commented by (268 points)
0 0
Well, that's because your output doesn't match with the fixed answer. Please take a look at this
printf("%c%c%c%c%c\n", a1, b1, c1, d1, e1);

Hint: You should delete something  :)

By the way, great job.
commented by (5.9k points)
0 0
printf("%c%c%c%c%c", a1, b1, c1, d1, e1);

How's that?
commented by (268 points)
0 0
That's correct.
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
   ** * * *       ** *  
  *   *   *      ** * 

int  *** *  argc, char * * {
  *       * *   char * 
    *    ***  char *  *    
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**    *   *  char  *   ** 
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* *  * *  *  
*  * *     ** **   ** *  ***** ** input the letter to  ** **  ****
*        **  
*  * * **** * *  *******  *  ** *   ** *  ** * *          ** *   *       **  **  * ****  ****  * *  *   ***
**   * *     * * = ** *  + 3;
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*  **    ***     * = *  * + 3;
** **  ** *  letterc = * * + 3;
** **  *   * ***     ** =   *  * + 3;
   **   ***  ** 
***         *    **   *   *** ***** *  * **   *   **   * *    **
*       * ** 
*   * *      ** return 0;
}
100/100 answered
reshown by
0 0
-----------Re-judge-----------
Case 0: Wrong output
commented by (4.3k points)
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     hello

Anyway, great job. Full marks.
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
 **     **  * *** * *   
 * **     **** ***  

int ***** argc, char *argv[]) {
 **     ** char ** **
* ** * *  *   char letteri;
  ** **  *  * * char *******
    ****  ****  char      
* ****   *** *  ** char **  
 ** * * ** *   * 
**  *    *  *** * ***  * *  ***  input the letter to encode: ****        **
*  **  *        
*** ***  * ***  **** * * ***   *    * **  *     * * * **     ***   *             *   *   **     ** * * *  *
*     **    *   * *  * * +3;
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*  * *   ** * ** * **** +3;
*  * * * * **   
*  ***  *    * * 
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* ** **    
**  *  * **   return 0;
}


INPUT
**  **    
  *** **  **
OUTPUT
***** * **   ***
100/100 answered by (269 points)
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     hello

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
commented by (5.9k points)
0 0
prog.c:27:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:30:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:30:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
  * *    * ***    * ** 
*** *    * ** ***   *   ****

int *   * argc, char * ***   {
 **  *     ***** char *   
**  *  *     * char  * **
** *    *    char ***   **
*  **   *   ****  char   ***
* * *  **  **   char   *    *
    *  ***** *   
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* * * **    * *  
*** * *  ***  * **** ** **    **  ***   *  *    * * *  * **   **    ***    ** * *** *  * **  *     **
  **  ** ** *   
  ** *  ***  * letter = letter + 3;
*   ** * * ***   * ** = * ** + 3;
  *    **  **      ** =  ** * + 3;
 *    *    *    ***    =  *  * + 3;
 *** *  * **    **  =    * + 3;
 * * * * **    
 * **   ** ***  ** *  * *** ** **   letter is  * * * ***   **   *    * *  * ** ***  *   
*** **  **  *  
*  *   ** * **  return 0;
}

INPUT
  ***    ****
** ** *  *  * 
 *****
 * **  ** ** * * *
100/100 answered by (290 points)
reshown by
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     The encrypted letter is hello

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
commented by (5.9k points)
0 0
prog.c:26:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:29:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:29:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
#include *****  *   * * 

int main(int argc, char *argv[]) {
* ** *   ** *  * **  **  *   lettera;
**** **** **  ** ** * ***** letterb;
* * * *   ****   ***** ***   *   letterc;
 * *  *   *  ******* ** *  * * letterd;
 *** * **   * ** * ***** *  * lettere;
**** ** ******  ** *   *  * 
 *  **  *  ***    * * *  *   * **** %c %c %c  ****   **   *  ***** ** *    * **   *   *   *    * ***  **     * ******  
 * ** * *** *  *** * * * *  = lettera + 3;
   *****     *     ***** ****** = letterb + 3;
     * **** * *   * *   **  *   **** = letterc + 3;
** **  ***  *  **    *  * *  ** = letterd + 3;
 *   **   * ** *      ***   *  ** *   = lettere + 3;
 *  **   **   ****  ** *   ***** *  **     ***  ** 
** **   *** *      ****   * *  * *     ****  %c %c %c  *   * *  ** * letterb,   **  *   *  * *
*   *   ***        * * *  ** **
 ******** *   ***   ***  **  *   0;
}

   ** *
 ** * 
* ** ** ****  *
*****
//hello
100/100 answered by (271 points)
edited by
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: e b i i l
     h e l l o

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
commented by (5.9k points)
0 0
prog.c:25:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:28:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:28:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:10:5: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
     scanf("%c %c %c %c %c", &lettera, &letterb, &letterc, &letterd, &lettere);
     ^~~~~
prog.c:10:5: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:10:5: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:17:5: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
     printf("%c %c %c %c %c", lettera, letterb, letterc, letterd, lettere);
     ^~~~~~
prog.c:17:5: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:17:5: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
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