[Exercise 03] Caesar Cipher Decoder

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You have received an encrypted message from Julius Caesar-- the message is ebiil.  You are asked to decipher the message in order to understand what Caesar trying to say to you.

Hint

Luckily, Caesar has given you a hint, he says: 'I, myself, encoded the message by shifting every word backwards by 3.' 

Solution

Write a program that receives 5 characters 'ebiil'. Then decode those characters into 5 new characters.

Example

#include <stdio.h>

int main(int argc, char *argv[]) {


	char a;
    	char b;
	 	
	scanf("%c%c", &a, &b);
	
	//decode the message how??
	
	printf("%c%c", a,b);
	
	return 0;
}

Input

ebiil

 

 

 

 

 

 

 

 

 

 

Output

hello

** REMEMBER ** 
This is an online-compiler, don't put anything except the codes. If you want to make a comment, please use // or /* */

[Exercise] Coding (C) - asked in Chapter 2: Syntax structure of the C language by (5.9k points)
ID: 26955 - Available when: Unlimited - Due to: Unlimited
edited by | 7.4k views

22 Answers

0 like 0 dislike 
Hidden content!
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***** ** ***  return 0;
}
100/100 answered by (449 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
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100/100 answered by (153 points)
0 0
Case 0: Correct output
Case 1: Wrong output
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
#include *   * * ** *
#include *** * ** **

/* run this program using the console pauser or add your own getch, * **** *    * ***** or input loop */

int main(int argc, char *argv[]) {
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*  * ****    ***   **  
*    * **  *****    ***  ** * *  0;
}
100/100 answered by (281 points)
edited by
0 0
Your program receives only 2 characters, and it doesn't move characters' positions.

Try to make it receive 5 characters, and move their positions forward by 3.
commented by (5.9k points)
0 0
This exercise expects only 'hello'. However, your code has.....

printf("Put the words you want to decode:");

Kindly consider delete this part :)
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
  *      * ** **  
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int          *   char **** {
/*
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}
100/100 answered by (273 points)
edited by
0 0
prog.c:28:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:32:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:32:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
0 0
Your program can end at
  
    return 0;
}
------------------------------------------
You don't need to put

INPUT

ebiil

OUTPUT

hello
commented by (5.9k points)
0 0
Case 0: Correct output
Case 1: Wrong output
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
   ** **  * **  *** 
* *  ***  ** *  *  

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50/100 answered by (252 points)
0 0
prog.c: In function 'main':
prog.c:19:2: error: expected declaration or statement at end of input
  return 0;
  ^~~~~~
commented by (4.3k points)
0 0
Great job using an array and a loop. There are two mistakes found in your code. Please check
1.     printf("\n\n%s", code);  <--- in order to make it match the fixed output '\n\n' should be deleted
2.     At the end of your code, there's something missing.
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
 *    *** * ****** *
*
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*
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*** = d + *
*
* *    

** **  ** *  *  *      *      *  * **  *   
*
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100/100 answered by (268 points)
0 0
It's correct lol you can't judge me
commented by (268 points)
0 0
Well, that's because your output doesn't match with the fixed answer. Please take a look at this
printf("%c%c%c%c%c\n", a1, b1, c1, d1, e1);

Hint: You should delete something  :)

By the way, great job.
commented by (5.9k points)
0 0
printf("%c%c%c%c%c", a1, b1, c1, d1, e1);

How's that?
commented by (268 points)
0 0
That's correct.
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
* ** *  *  * * ******    *
**   **   ** *   ** *  **  *

int * * argc, char  **   {
* * ** ** *** char  ****   
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* *****     * ****   * *   =    + 3;
* * **  *   **   *  =   * + 3;
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****** ** ***** **** * =  *      + 3;
*  ** **   * * *  * 
   *  **   *  *     *  * **   *   *  *** *      ***     ** ** *   *  
 * * *   * * *   
* * *  * * return 0;
}
100/100 answered
reshown by
0 0
-----------Re-judge-----------
Case 0: Wrong output
commented by (4.3k points)
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     hello

Anyway, great job. Full marks.
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
      * ** ** * **
 ***     * ******   * * *  

int  *** * argc, char *argv[]) {
*  *     *   *  char ****  *
* * **    *  * char letteri;
    **    ** * *   char ** *
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**      ** char **** 
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** *  * *** * * ***  *** **  +3;
**  **  * * *       ** * * +3;
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****** * *   *   *  * *****  **** ** ***** * **  ** *****   ****    *   *
 * * *  ** 
 *        ** * return 0;
}


INPUT
  ****   ** * *  **
  * *     *** *
OUTPUT
* *       **   *****
100/100 answered by (269 points)
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     hello

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
commented by (5.9k points)
0 0
prog.c:27:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:30:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:30:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
***     *   ** * **  
  * **  ** * *  *** ** 

int  *** * argc, char ** *** {
  * **    ****** char * * *
 *     *  ***    char   **
**  ***  ** * char **  
***   * * ** char   ** 
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***** *  ** *    
** ***  *  **   *****  * * input the     to * **    * *  * ***   
*  ***   *  *****  
 * ** *          ***   *** **  ****  ***  ** * *   *** *         ** * ***  ******   *     
**** * ** *****  * 
 *****  ****  letter = letter + 3;
  **   * * **  *** * =  * ** + 3;
*  * *  *  *    ** *  =   ** * + 3;
* * *** **  **  *  *   ** =  *    + 3;
 *  **  ** ***  **   = * *** + 3;
* ** *  *   ***** 
****    *   * * ******* *   * **  letter is **** ** * ***     ** * * * * * **   **  * ** 
    *  ** *** 
  **  * **    return 0;
}

INPUT
**  * **  *  **   
   *   ** * *
*   
***** ** * * *
100/100 answered by (290 points)
reshown by
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     The encrypted letter is hello

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
commented by (5.9k points)
0 0
prog.c:26:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:29:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:29:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
#include  * *  ** * *

int main(int argc, char *argv[]) {
*     ** *  **** **       * * lettera;
 ** **  *  ** **  *  **   **  *  * letterb;
***  *  ****    ** ******   * letterc;
* **   *   ** *  ** * * **  letterd;
*****   *  **   ***** *  ** *** lettere;
****** *  *  *** *  *  *
  ****   *  * ** **  *  ****    ** *** %c %c %c  ** *** * **  *  *  **  *   * * ** *     **    *  * ** * *      * *** ****  
* ********       *   ****   * = lettera + 3;
**   **  ** **  ****  * * *  **   = letterb + 3;
   *****  **      ****     *   = letterc + 3;
 *  *  * **   * * ***   *   * = letterd + 3;
***   **    *     **  * *    * = lettere + 3;
**** **  **   * ***** ** ** *  **  *   **       
** **** ***  **  *  *           ******* %c %c %c * *** * *     *** letterb,  *** * * * **    ** * *
 *    **  * *  *     **     **
*  *  * * **  * **  * ** ***** 0;
}

       
****
** * ****
  * 
//hello
100/100 answered by (271 points)
edited by
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: e b i i l
     h e l l o

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
commented by (5.9k points)
0 0
prog.c:25:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:28:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:28:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:10:5: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
     scanf("%c %c %c %c %c", &lettera, &letterb, &letterc, &letterd, &lettere);
     ^~~~~
prog.c:10:5: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:10:5: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:17:5: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
     printf("%c %c %c %c %c", lettera, letterb, letterc, letterd, lettere);
     ^~~~~~
prog.c:17:5: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:17:5: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
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