[Exercise 03] Caesar Cipher Decoder

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You have received an encrypted message from Julius Caesar-- the message is ebiil.  You are asked to decipher the message in order to understand what Caesar trying to say to you.

Hint

Luckily, Caesar has given you a hint, he says: 'I, myself, encoded the message by shifting every word backwards by 3.' 

Solution

Write a program that receives 5 characters 'ebiil'. Then decode those characters into 5 new characters.

Example

#include <stdio.h>

int main(int argc, char *argv[]) {


	char a;
    	char b;
	 	
	scanf("%c%c", &a, &b);
	
	//decode the message how??
	
	printf("%c%c", a,b);
	
	return 0;
}

Input

ebiil

 

 

 

 

 

 

 

 

 

 

Output

hello

** REMEMBER ** 
This is an online-compiler, don't put anything except the codes. If you want to make a comment, please use // or /* */

[Exercise] Coding (C) - asked in Chapter 2: Syntax structure of the C language by (5.9k points)
ID: 26955 - Available when: Unlimited - Due to: Unlimited
edited by | 2.4k views

22 Answers

0 like 0 dislike 
Hidden content!
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}
100/100 answered by (449 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
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100/100 answered by (153 points)
0 0
Case 0: Correct output
Case 1: Wrong output
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
#include  * *** * **
#include  *  *    *** ** 

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int main(int argc, char *argv[]) {
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}
100/100 answered by (281 points)
edited by
0 0
Your program receives only 2 characters, and it doesn't move characters' positions.

Try to make it receive 5 characters, and move their positions forward by 3.
commented by (5.9k points)
0 0
This exercise expects only 'hello'. However, your code has.....

printf("Put the words you want to decode:");

Kindly consider delete this part :)
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
  ***   *** *      * *
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int * *      char    * * {
/*
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*** * *  **** *** **   * **  *** **  * *  *        ** * **  *   * *
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}
100/100 answered by (273 points)
edited by
0 0
prog.c:28:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:32:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:32:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
0 0
Your program can end at
  
    return 0;
}
------------------------------------------
You don't need to put

INPUT

ebiil

OUTPUT

hello
commented by (5.9k points)
0 0
Case 0: Correct output
Case 1: Wrong output
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
 *** * **   ** * *  
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50/100 answered by (252 points)
0 0
prog.c: In function 'main':
prog.c:19:2: error: expected declaration or statement at end of input
  return 0;
  ^~~~~~
commented by (4.3k points)
0 0
Great job using an array and a loop. There are two mistakes found in your code. Please check
1.     printf("\n\n%s", code);  <--- in order to make it match the fixed output '\n\n' should be deleted
2.     At the end of your code, there's something missing.
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
    ***  ** ** **  *   
*
*** * * ***** *******   *  *  
 
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     *     
 
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100/100 answered by (268 points)
0 0
It's correct lol you can't judge me
commented by (268 points)
0 0
Well, that's because your output doesn't match with the fixed answer. Please take a look at this
printf("%c%c%c%c%c\n", a1, b1, c1, d1, e1);

Hint: You should delete something  :)

By the way, great job.
commented by (5.9k points)
0 0
printf("%c%c%c%c%c", a1, b1, c1, d1, e1);

How's that?
commented by (268 points)
0 0
That's correct.
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
*  * **     *  **   ** *
     * * **       **** *

int * **  argc, char ****** {
** **   *   * * char   * 
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*** **          *  ***  **** input the letter to *  * * * *
*   *    ** *  
* ***** *         ***  ** * * * *       ***      *******   ** * *    *   **** ***  ** *  ******** *    ** ** **  
*   **  **       *** = *  + 3;
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*    **  ***    **  =  **** + 3;
* * ****   **   *  letterc = *  * + 3;
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*   *  *  **     *** *** ** *  * *  ***   * ** * *  *   ***   *   **  ** * 
 *   ** **  ***  
 ** **  *     return 0;
}
100/100 answered
reshown by
0 0
-----------Re-judge-----------
Case 0: Wrong output
commented by (4.3k points)
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     hello

Anyway, great job. Full marks.
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
     **  ** *  
***     *  ***  ****** 

int   ** argc, char *argv[]) {
       ****   char **  
**** * * * *** * char letteri;
* ****  *  **  char * *  
 * * ** * *    char    *
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*    *       **     ****   **    * input the letter to encode: **** * *  *    *
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*   ***  *     ** *  *** * ** *  *  *  **     * **** *  ** ***      * * *** * **  *  *** *  ** *  *       *   *
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*   **   ***  *  return 0;
}


INPUT
 *    ** *   ***  *
   ** * *  **
OUTPUT
  * *  *  ****
100/100 answered by (269 points)
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     hello

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
commented by (5.9k points)
0 0
prog.c:27:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:30:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:30:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
 *** *  * *   *  *  
  **  *  * *     * *    *   

int  * * argc, char ***   {
**  *  **   ** char  ** * *
******   *    char     **
     *     * char * * * 
***        *   * char  * * **
 *  *  * ** ** ** char *    
* *     *  **  
 *  *   * *  ***   **  *   **** input the * * to ***    **  * *  * * * *
 ****     *** ** 
***  **   * * *  * *   * ***   *  ***   **  * *  * ***   ****** *     ** * ** *  *   ***   **           ***
* *  **** ** ***  
* * ** ******* letter = letter + 3;
*  * ** *   ** ***  =   ***  + 3;
*  **** * ** * *       = *    + 3;
  ** **  **** ***   *  = *   *  + 3;
 ** *   *  * * **    ** =  ** * + 3;
*   *  * ** *** ** 
  * * **   ***    ** ******    * * *****  letter is  *  * *      ** ** *   **** ****   *  * * ***
   ***  *      
* ** **    *** * return 0;
}

INPUT
* *  * *   ** *  
**  **** ***
 **
*  **** *  ** *
100/100 answered by (290 points)
reshown by
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     The encrypted letter is hello

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
commented by (5.9k points)
0 0
prog.c:26:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:29:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:29:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
#include     * *        

int main(int argc, char *argv[]) {
 * ****** ***  * ** *****   lettera;
 * ****        ******     *  ** letterb;
 * *** * *   *  * * * **   ***   letterc;
**     **    ***** **  *  **    letterd;
 * ******    * ** *** * * * **  * lettere;
* * *   *** *     **  * * **
* *   ** *  * *** * ****   ** ****  *** %c %c %c  *   **    ** *    *    * ** * * *  ***   **** * ******  * ** **  ** * 
* *    * *  * * * **  ** *** *  = lettera + 3;
*    *** * *  *        *  * ** ** = letterb + 3;
 *  *   *  ** *** ** *      * = letterc + 3;
* * ***     *** * **  *  **  * = letterd + 3;
*   *   *      ***** *   * ** *   = lettere + 3;
** **** * *  *  **   ** *  ** *  ***       ****  ****
   **  **  *   * ** * * *    **** * ** * %c %c %c *** *  *  ** **   letterb,  * **  ****    * 
* ** **  * **   *** ** *** **  **
  * *  *    **  *  **  *  ** *   * 0;
}

*** ** 
 * *  
** *** **  ** 
 ***
//hello
100/100 answered by (271 points)
edited by
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: e b i i l
     h e l l o

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
commented by (5.9k points)
0 0
prog.c:25:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:28:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:28:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:10:5: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
     scanf("%c %c %c %c %c", &lettera, &letterb, &letterc, &letterd, &lettere);
     ^~~~~
prog.c:10:5: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:10:5: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:17:5: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
     printf("%c %c %c %c %c", lettera, letterb, letterc, letterd, lettere);
     ^~~~~~
prog.c:17:5: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:17:5: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
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