[Exercise 03] Caesar Cipher Decoder

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You have received an encrypted message from Julius Caesar-- the message is ebiil.  You are asked to decipher the message in order to understand what Caesar trying to say to you.

Hint

Luckily, Caesar has given you a hint, he says: 'I, myself, encoded the message by shifting every word backwards by 3.' 

Solution

Write a program that receives 5 characters 'ebiil'. Then decode those characters into 5 new characters.

Example

#include <stdio.h>

int main(int argc, char *argv[]) {


	char a;
    	char b;
	 	
	scanf("%c%c", &a, &b);
	
	//decode the message how??
	
	printf("%c%c", a,b);
	
	return 0;
}

Input

ebiil

 

 

 

 

 

 

 

 

 

 

Output

hello

** REMEMBER ** 
This is an online-compiler, don't put anything except the codes. If you want to make a comment, please use // or /* */

[Exercise] Coding (C) - asked in Chapter 2: Syntax structure of the C language by (5.9k points)
ID: 26955 - Available when: Unlimited - Due to: Unlimited
edited by | 5.7k views

22 Answers

0 like 0 dislike 
Hidden content!
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}
100/100 answered by (449 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
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100/100 answered by (153 points)
0 0
Case 0: Correct output
Case 1: Wrong output
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
#include * **   ***      *
#include       ******* *

/* run this program using the console pauser or add your own getch,  ** **  *  ****   ** ***  or input loop */

int main(int argc, char *argv[]) {
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}
100/100 answered by (281 points)
edited by
0 0
Your program receives only 2 characters, and it doesn't move characters' positions.

Try to make it receive 5 characters, and move their positions forward by 3.
commented by (5.9k points)
0 0
This exercise expects only 'hello'. However, your code has.....

printf("Put the words you want to decode:");

Kindly consider delete this part :)
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
 ***    * **** ** ** * * 
*  **   *  *   *   

int   *  *  char  *** {
/*
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b = ***
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*  * *   * *     ** *
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}
100/100 answered by (273 points)
edited by
0 0
prog.c:28:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:32:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:32:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
0 0
Your program can end at
  
    return 0;
}
------------------------------------------
You don't need to put

INPUT

ebiil

OUTPUT

hello
commented by (5.9k points)
0 0
Case 0: Correct output
Case 1: Wrong output
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
*  **  ****  *****
**  ** * *   *** 

/* run this ***   *   the   *   * *  or add your own *  ** **********  *  **  **   or  *    * */

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}
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* *  **   *   *  * 0;
50/100 answered by (252 points)
0 0
prog.c: In function 'main':
prog.c:19:2: error: expected declaration or statement at end of input
  return 0;
  ^~~~~~
commented by (4.3k points)
0 0
Great job using an array and a loop. There are two mistakes found in your code. Please check
1.     printf("\n\n%s", code);  <--- in order to make it match the fixed output '\n\n' should be deleted
2.     At the end of your code, there's something missing.
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
* * ** * *  ** * *  *** ** 
*
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* * * b + *

** = c + 

 = d + *
 
**   *   *
 
** * ***   * **  *   * *  *  * ** *        

*   *
*
100/100 answered by (268 points)
0 0
It's correct lol you can't judge me
commented by (268 points)
0 0
Well, that's because your output doesn't match with the fixed answer. Please take a look at this
printf("%c%c%c%c%c\n", a1, b1, c1, d1, e1);

Hint: You should delete something  :)

By the way, great job.
commented by (5.9k points)
0 0
printf("%c%c%c%c%c", a1, b1, c1, d1, e1);

How's that?
commented by (268 points)
0 0
That's correct.
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
***   *   ** * *     
* *   *  **** * *  * *

int * *   argc, char  * ** {
***** **  **  char    * *
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*** * * ** ***   *    ******  * input the letter to  **    ** *  *
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*  **    *  * * ** =    * + 3;
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*  * **** * ***  ** =   * + 3;
* ******  ****  letterc = ***  + 3;
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* * * ***   *  * 
* **   ** **   * * *** * * * ***  *   * *   *  *  *  *   * *****  ** **  
  * **     **   
* * *   **    return 0;
}
100/100 answered
reshown by
0 0
-----------Re-judge-----------
Case 0: Wrong output
commented by (4.3k points)
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     hello

Anyway, great job. Full marks.
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
 *    *   **  *   
****  **  **      ** * 

int **   argc, char *argv[]) {
** **   * *    char    
       ** **  char letteri;
****  ***   **  *  char  **    
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*** **** * ** **   * char * *  *
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* ** * ** * *   
* ** * *   return 0;
}


INPUT
* **   *   * * *
 **  * ** *
OUTPUT
*     * *   ***
100/100 answered by (269 points)
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     hello

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
commented by (5.9k points)
0 0
prog.c:27:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:30:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:30:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
*   * *        ***  *
    ** *  *  * **   

int  **   * argc, char **    {
** ****   ** * * char   ***
**  * *   ***  *  char **  
*  ** **    * char *  * * 
* *** *** *   char  ** 
* ** * * **  * *  char *  * *
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***  *       * **** ** *  ** input the  ****  to **** * *** ** *   *  *
* * *** ****  *  
    **  * *       ** **    **  * **** **   **    * ***  **       * *  *    * ***     ** *  * *        *  *
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* * *  ***** *  letter = letter + 3;
 *   *   *   **** ** *  =  ** * + 3;
 *  ***  *   *** **** = *   + 3;
*   *   ***     * **    =   **  + 3;
* *  ***   **     *  * =  * ** + 3;
**    ******* 
* *  ** * *  * ****  **    ******* letter is  *  **** **  ** *    * *  ** *   *  **  ***  
   ***      * *  
** **    * * return 0;
}

INPUT
   *  **  *  **    *
 *****  * **   
 * ***
* * *    * **   **
100/100 answered by (290 points)
reshown by
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     The encrypted letter is hello

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
commented by (5.9k points)
0 0
prog.c:26:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:29:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:29:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
#include ****** *  *** *** **

int main(int argc, char *argv[]) {
 ** * *  ***  * ****    *      ** lettera;
*     **   *   *** * ***  * letterb;
 ****** * **** *     * * **   *    letterc;
* *  *   ***  * * *  * *   * letterd;
*  ** *  ***  *     ***   ***    lettere;
** *  *   * ** *  *  * * * **
    * **   ****   ***** ** *     ** ** %c %c %c * * *  * * **** ** * *  *  *  ***    * ***  *  *  * * * *  * **  ** 
   *      **   ** * ******     = lettera + 3;
   ** *   * ***  * ****   **     = letterb + 3;
  ******   *  ** * **** ****   = letterc + 3;
  *    * * **  **  * * ** * * *     = letterd + 3;
* * * *** *    ***** *    **  **  = lettere + 3;
 **     *   * *****       * ** ******* * ** ** **  **
 * ***** ***** *  ** **     *  ** **** ** ** %c %c %c ****   **   * * letterb,  *    *  * * * ** 
  * **** *** **** **  ** **   *
*  ** **** *   *** * * * *   ****  0;
}

  ****
* * *
 * * ****** *
**  *
//hello
100/100 answered by (271 points)
edited by
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: e b i i l
     h e l l o

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
commented by (5.9k points)
0 0
prog.c:25:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:28:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:28:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:10:5: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
     scanf("%c %c %c %c %c", &lettera, &letterb, &letterc, &letterd, &lettere);
     ^~~~~
prog.c:10:5: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:10:5: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:17:5: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
     printf("%c %c %c %c %c", lettera, letterb, letterc, letterd, lettere);
     ^~~~~~
prog.c:17:5: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:17:5: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
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