[Exercise 03] Caesar Cipher Decoder

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You have received an encrypted message from Julius Caesar-- the message is ebiil.  You are asked to decipher the message in order to understand what Caesar trying to say to you.

Hint

Luckily, Caesar has given you a hint, he says: 'I, myself, encoded the message by shifting every word backwards by 3.' 

Solution

Write a program that receives 5 characters 'ebiil'. Then decode those characters into 5 new characters.

Example

#include <stdio.h>

int main(int argc, char *argv[]) {


	char a;
    	char b;
	 	
	scanf("%c%c", &a, &b);
	
	//decode the message how??
	
	printf("%c%c", a,b);
	
	return 0;
}

Input

ebiil

 

 

 

 

 

 

 

 

 

 

Output

hello

** REMEMBER ** 
This is an online-compiler, don't put anything except the codes. If you want to make a comment, please use // or /* */

[Exercise] Coding (C) - asked in Chapter 2: Syntax structure of the C language by (5.9k points)
ID: 26955 - Available when: Unlimited - Due to: Unlimited
edited by | 7.8k views

22 Answers

0 like 0 dislike 
Hidden content!
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int  ***  argc, char * **  * {
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  *   * ***    return 0;
}
100/100 answered by (449 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
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100/100 answered by (153 points)
0 0
Case 0: Correct output
Case 1: Wrong output
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
#include **     *** ** * *
#include *** *   ***   

/* run this program using the console pauser or add your own getch, * *  ****     ** * ****** or input loop */

int main(int argc, char *argv[]) {
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**  * *  *   ** **    *   *** = b+3;
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*  *   **   ****** ***  *  
*   *  *  ** ** ** * * *  * *   * * 0;
}
100/100 answered by (281 points)
edited by
0 0
Your program receives only 2 characters, and it doesn't move characters' positions.

Try to make it receive 5 characters, and move their positions forward by 3.
commented by (5.9k points)
0 0
This exercise expects only 'hello'. However, your code has.....

printf("Put the words you want to decode:");

Kindly consider delete this part :)
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
*  *  **  * *  **   
** *****   *   *   **   *** 

int ***  **   char  **    {
/*
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* *  * ** 

***  *** **** *** ******* *  * * * **  *   *     ***  ** **  *  **  
a = a+3;
b = *
c = * * 
d = d+3;
e = **

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* *  *** *    *    
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}
100/100 answered by (273 points)
edited by
0 0
prog.c:28:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:32:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:32:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
0 0
Your program can end at
  
    return 0;
}
------------------------------------------
You don't need to put

INPUT

ebiil

OUTPUT

hello
commented by (5.9k points)
0 0
Case 0: Correct output
Case 1: Wrong output
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
 * ** * * ** *  *    *  
*** *   *  * *** *** *

/* run this  ***    ** the  * * * ***  or add your own *    * **   **   *   *** *  or **  * */

int * * ***     char **     {
*    *         int num, *    
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}
* *  * **   ** ** *   * ******  ***    
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50/100 answered by (252 points)
0 0
prog.c: In function 'main':
prog.c:19:2: error: expected declaration or statement at end of input
  return 0;
  ^~~~~~
commented by (4.3k points)
0 0
Great job using an array and a loop. There are two mistakes found in your code. Please check
1.     printf("\n\n%s", code);  <--- in order to make it match the fixed output '\n\n' should be deleted
2.     At the end of your code, there's something missing.
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
 *  *    *  * *  ** 
*
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** **  *   **      *      *  *  *   *       **       *    * *    **  * *  ***  *  
 
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*** **    *  *   *      * *   ***   * *     * **  ** ****    **  *
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  * = c +  

** = d + **
 
**  *    
*
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*
* *** *

100/100 answered by (268 points)
0 0
It's correct lol you can't judge me
commented by (268 points)
0 0
Well, that's because your output doesn't match with the fixed answer. Please take a look at this
printf("%c%c%c%c%c\n", a1, b1, c1, d1, e1);

Hint: You should delete something  :)

By the way, great job.
commented by (5.9k points)
0 0
printf("%c%c%c%c%c", a1, b1, c1, d1, e1);

How's that?
commented by (268 points)
0 0
That's correct.
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
**    * *  ***  * 
 * *  *    *   *** * 

int *  * argc, char   **  {
** * * * *    * char *  *
***** *  ** char  * ***  
*      *    **  char  *  *
* ***** *  **  *   char  * ** *
*  *  **  *  *  char ** *
* *  **      * 
*****  ** *   *  *  ** *  **  *  input the letter to *  * **** ***
*   *     *   ** 
**  *     *  *** * *  ** ** ****    ***  * *  * *** * *  *  *** ****      *   *   *      *    **  **  ***
       * ** *      =  * ** + 3;
** **       *    ***  = **   + 3;
*   * **  **  *    * =   *** + 3;
 *** *      * ****  letterc =   *  * + 3;
*** * *    * *   **** * = *  * ** + 3;
 ** * * * **** * 
* ****  * * * ** **   ***  *     *** **   *  **       * * * **  *  * *  *  ** **
      ** *    
     **     *   ** return 0;
}
100/100 answered
reshown by
0 0
-----------Re-judge-----------
Case 0: Wrong output
commented by (4.3k points)
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     hello

Anyway, great job. Full marks.
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
*** * *   *  * * **** 
* *     *   *      

int   **   argc, char *argv[]) {
*  *        **  * char **  * *
     ****  * char letteri;
  *** * ***     char *** *
 ***   *  *   * char    *
*** *    * * char * 
 * ***   * ***  
**   *  * *     ****  *** **  input the letter to encode: * ****  **  *
*  * * **    
 *  *   *  *  * ***** *    *  *******  * ***** * *  * *****     * * *   *     *   *****  * * *    
**  * **    * * * *    ****  * ** +3;
** ** *      *   *   *** +3;
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* *  ****   * ****       ** * +3;
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* *  *    ***  * 
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* **   *   ***     
      *     *  return 0;
}


INPUT
   ***  * * *  ***
 ****   *  *  
OUTPUT
*    **   * *   *  *
100/100 answered by (269 points)
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     hello

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
commented by (5.9k points)
0 0
prog.c:27:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:30:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:30:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
 *  * * *********    *     
**  * *  *     *   *  * *

int   * * argc, char *     {
* *         *** char      
   * **  * ** ** char    * 
  **  * ***  **   char ****   
**  **  *      * char  *  
* *     * *** * char **   *
  **   * *     
**** *** **  ****  *  **     * * * *   input the * *   to *** **  *  ****    ***  
 * **** ***  
**  **  * * * * * *  **  ** *** * *         *  **    *  **     *** ** * *  *   *  *    *** *  **
* ***  * *******  
*** **  *   **  letter = letter + 3;
   *  * *  *   *    = * ***  + 3;
 *  ***    *   * * =      * + 3;
 ***  * *   **   *  = **    + 3;
* * *  *   * **   *  * =  ** + 3;
  *  * **   
* ****    ***  * *  * *** * ** * **  letter is  ****  ** *  **  **  * *  ***      ***  *  
 ***   * **  * * 
** *  * * ** return 0;
}

INPUT
******* *    ***  
    **  ***  *
*  ***
 **   *** ****** *
100/100 answered by (290 points)
reshown by
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     The encrypted letter is hello

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
commented by (5.9k points)
0 0
prog.c:26:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:29:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:29:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
#include **  ***** *      

int main(int argc, char *argv[]) {
    ***   ** ****  * ** *** lettera;
**    ***    *  *    ***** * ** letterb;
   * ****  * * * *  ***  ***  letterc;
*   * ** *** ***  *     ***** ** * letterd;
*     * * * *** **  ******    * lettere;
**   **  *  * *     *   
* **  *****  *   **    *** *    * *   %c %c %c **  **** ****  ** **  *** *** ***   ** *     * * * *****   *  * 
*  ***   *   * *    *** **  * **  = lettera + 3;
**       **       *  ****  * *** = letterb + 3;
 *   **  *     **  *** * ****   = letterc + 3;
****** * *   *     *****  *   = letterd + 3;
  **      ******   *  ****  **    = lettere + 3;
* ** * * **    **** *  *  * *   *** **     * * *         
***** * *  ** *  *  ***** **  *   ** ****  %c %c %c *    *     * *  letterb,    * *   ****   *** ** 
*   ****   * * * * * *
  * ****  ** ** ** * * *** ** 0;
}

  * 
 *  **
   **** * ******
   ***
//hello
100/100 answered by (271 points)
edited by
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: e b i i l
     h e l l o

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
commented by (5.9k points)
0 0
prog.c:25:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:28:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:28:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:10:5: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
     scanf("%c %c %c %c %c", &lettera, &letterb, &letterc, &letterd, &lettere);
     ^~~~~
prog.c:10:5: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:10:5: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:17:5: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
     printf("%c %c %c %c %c", lettera, letterb, letterc, letterd, lettere);
     ^~~~~~
prog.c:17:5: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:17:5: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
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