[Exercise 03] Caesar Cipher Decoder

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You have received an encrypted message from Julius Caesar-- the message is ebiil.  You are asked to decipher the message in order to understand what Caesar trying to say to you.

Hint

Luckily, Caesar has given you a hint, he says: 'I, myself, encoded the message by shifting every word backwards by 3.' 

Solution

Write a program that receives 5 characters 'ebiil'. Then decode those characters into 5 new characters.

Example

#include <stdio.h>

int main(int argc, char *argv[]) {


	char a;
    	char b;
	 	
	scanf("%c%c", &a, &b);
	
	//decode the message how??
	
	printf("%c%c", a,b);
	
	return 0;
}

Input

ebiil

 

 

 

 

 

 

 

 

 

 

Output

hello

** REMEMBER ** 
This is an online-compiler, don't put anything except the codes. If you want to make a comment, please use // or /* */

[Exercise] Coding (C) - asked in Chapter 2: Syntax structure of the C language by (5.9k points)
ID: 26955 - Available when: Unlimited - Due to: Unlimited
edited by | 5k views

22 Answers

0 like 0 dislike 
Hidden content!
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}
100/100 answered by (449 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
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100/100 answered by (153 points)
0 0
Case 0: Correct output
Case 1: Wrong output
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
#include  * * * **  *  ****
#include ** **      *

/* run this program using the console pauser or add your own getch,   *****   * ** * or input loop */

int main(int argc, char *argv[]) {
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*   * ***    **   * ** ***
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}
100/100 answered by (281 points)
edited by
0 0
Your program receives only 2 characters, and it doesn't move characters' positions.

Try to make it receive 5 characters, and move their positions forward by 3.
commented by (5.9k points)
0 0
This exercise expects only 'hello'. However, your code has.....

printf("Put the words you want to decode:");

Kindly consider delete this part :)
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
* **    **  ******
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int  **   *** char * ** {
/*
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b =   
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****    *  ** *  **  ** *  * *  * 0;
}
100/100 answered by (273 points)
edited by
0 0
prog.c:28:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:32:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:32:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
0 0
Your program can end at
  
    return 0;
}
------------------------------------------
You don't need to put

INPUT

ebiil

OUTPUT

hello
commented by (5.9k points)
0 0
Case 0: Correct output
Case 1: Wrong output
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
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* * **** **    ** 0;
50/100 answered by (252 points)
0 0
prog.c: In function 'main':
prog.c:19:2: error: expected declaration or statement at end of input
  return 0;
  ^~~~~~
commented by (4.3k points)
0 0
Great job using an array and a loop. There are two mistakes found in your code. Please check
1.     printf("\n\n%s", code);  <--- in order to make it match the fixed output '\n\n' should be deleted
2.     At the end of your code, there's something missing.
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
 * *    ****  *  * *  * 
*
* ** * ** * *****   *  
 
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*  = c + 

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*     

*****  **** * *  * * **   *** * ***   * ** ****
*
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100/100 answered by (268 points)
0 0
It's correct lol you can't judge me
commented by (268 points)
0 0
Well, that's because your output doesn't match with the fixed answer. Please take a look at this
printf("%c%c%c%c%c\n", a1, b1, c1, d1, e1);

Hint: You should delete something  :)

By the way, great job.
commented by (5.9k points)
0 0
printf("%c%c%c%c%c", a1, b1, c1, d1, e1);

How's that?
commented by (268 points)
0 0
That's correct.
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
  ***   *  **  *   **** * 
 * **  *  *****      

int    argc, char  **** * {
 **** **    * **  * char  ** *  
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***   * *  **** char  ***** 
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   **  *   *   **** ***** ** *  input the letter to  * * *   *
*    * ** * *** ** 
*  *** ******  * ******* **  * *** ***  **  ** ** * *    *   *   *  ***** **      *   *** *   *   *    * ** **  ***  *
** * * *     * * =   **  + 3;
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*  ** ** *     ****** *   ***     **         ** * **** *  *  * 
* **  * * *    *  
****  *  * *   return 0;
}
100/100 answered
reshown by
0 0
-----------Re-judge-----------
Case 0: Wrong output
commented by (4.3k points)
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     hello

Anyway, great job. Full marks.
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
** **   *     *      * ** 
* * ** * ***  *   ** * *

int  ** argc, char *argv[]) {
 * **    **** **  char      *
  ***  **   *   char letteri;
   *** *   ** char ** ***
***** *    *  *      char   * 
** * **  ** *    char * ****
*  * *** * * 
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* *  * *  *  * ***    *    ***   *** *****   **   *** * **  *** * *  * *** **       * *** *  ***  *   * 
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   * * *    ***    * * **  ** +3;
*   ** ***  * *** *    **      +3;
  ******   ***   ***     * *  +3;
* * ***      * *** **   +3;
** * **   *** *  
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 * *  * **  **  
      *   * ** * return 0;
}


INPUT
 ***  * ****  * * **
 *   ** ****
OUTPUT
    * * **    *** *
100/100 answered by (269 points)
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     hello

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
commented by (5.9k points)
0 0
prog.c:27:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:30:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:30:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
       *  *   ******
 * **  * ** * ****  **

int * *   ** argc, char  *  {
 * ** * ** * char **  
* *    * *** * char *** 
  **  * *  *  * *  * char    * *
* ** *     * char *  
*** * *  **    char  **  
  *   * * * * 
  *** *   *  * *  **    * *** ** input the *** ** to  *  ** * *  * ***** ** 
*** **   *** * 
****** *   * *      ***** ***  *  * * *  *    **** *    **** ***  *    **   **     **         **  * *   
****   **** ** 
  ** **  ****  letter = letter + 3;
     *  **** * * **    = **    + 3;
 ******       **  * = *  * * + 3;
* * * *  *** *  ** *  = * ** + 3;
 **** ** **** *   **** =  * *** + 3;
 *** *    ***** **  
  ***  *  *** ** **    ***** * * * *  * letter is    * ** *** **   *    *  ** * * *** * *    
*    * *** *** *** 
   * * * *   * return 0;
}

INPUT
** * **    ***  
****** * ** *
** 
* *  * ** ***   *  *
100/100 answered by (290 points)
reshown by
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     The encrypted letter is hello

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
commented by (5.9k points)
0 0
prog.c:26:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:29:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:29:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
#include * **    ** ****  *

int main(int argc, char *argv[]) {
**       *  * * **  *** **  lettera;
 **  *  * *     * *      *    ** letterb;
  * * * **    * *  *  * letterc;
   *      **   ** ** ** * letterd;
** * *  **    *    * *** **    lettere;
 * **     * *****   * *  *
** ** ***** ** **  *     **** *  ** *** %c %c %c          *    ****       * *   *  ** ***     ****  *  *   **  ***** 
**   *   ****  *** * **  * = lettera + 3;
 *  ***   *   * *** **  ** ***    = letterb + 3;
**     * ** **  * *****  * *   = letterc + 3;
*   *  ** * * * * * ****  ** * *  = letterd + 3;
   *** *  *    *  *  ** ** ** = lettere + 3;
*   **    * * * ***    ****  **  * *  ** **    *  *  *  *   
**  * *  * **** **  *** ******** ** %c %c %c  **   *   ** * * letterb,     **  **   * *   * 
 *  *  * *  **** *******   **
*** *  **** ** *** *  *** ***  0;
}

  *  *
     
**  * *  *
   
//hello
100/100 answered by (271 points)
edited by
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: e b i i l
     h e l l o

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
commented by (5.9k points)
0 0
prog.c:25:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:28:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:28:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:10:5: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
     scanf("%c %c %c %c %c", &lettera, &letterb, &letterc, &letterd, &lettere);
     ^~~~~
prog.c:10:5: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:10:5: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:17:5: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
     printf("%c %c %c %c %c", lettera, letterb, letterc, letterd, lettere);
     ^~~~~~
prog.c:17:5: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:17:5: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
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