[Exercise 03] Caesar Cipher Decoder

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You have received an encrypted message from Julius Caesar-- the message is ebiil.  You are asked to decipher the message in order to understand what Caesar trying to say to you.

Hint

Luckily, Caesar has given you a hint, he says: 'I, myself, encoded the message by shifting every word backwards by 3.' 

Solution

Write a program that receives 5 characters 'ebiil'. Then decode those characters into 5 new characters.

Example

#include <stdio.h>

int main(int argc, char *argv[]) {


	char a;
    	char b;
	 	
	scanf("%c%c", &a, &b);
	
	//decode the message how??
	
	printf("%c%c", a,b);
	
	return 0;
}

Input

ebiil

 

 

 

 

 

 

 

 

 

 

Output

hello

** REMEMBER ** 
This is an online-compiler, don't put anything except the codes. If you want to make a comment, please use // or /* */

[Exercise] Coding (C) - asked in Chapter 2: Syntax structure of the C language by (5.9k points)
ID: 26955 - Available when: Unlimited - Due to: Unlimited
edited by | 5.6k views

22 Answers

0 like 0 dislike 
Hidden content!
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*  **     *  ** return 0;
}
100/100 answered by (449 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
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100/100 answered by (153 points)
0 0
Case 0: Correct output
Case 1: Wrong output
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
#include   *  *  * * * * ** **
#include  ***  * *   * * * 

/* run this program using the console pauser or add your own getch, *****  *     * * * ** or input loop */

int main(int argc, char *argv[]) {
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**       * **    * * ***** ***    = getchar();
*  *  * ***** ** ****   = a+3;
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**  * ***** ** ** *   *  * * = c+3;
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  *     *****  ** * ***  **
**** ** ** * * *   **     **  * 0;
}
100/100 answered by (281 points)
edited by
0 0
Your program receives only 2 characters, and it doesn't move characters' positions.

Try to make it receive 5 characters, and move their positions forward by 3.
commented by (5.9k points)
0 0
This exercise expects only 'hello'. However, your code has.....

printf("Put the words you want to decode:");

Kindly consider delete this part :)
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
* *** **  * **     *
* ***    *      *     * 

int ** **  ****  char *   * {
/*
****  **   */

   *   **

* **  * ** * * **  *   *   * *   **  * *    *  ***   *   *   * ***
a = a+3;
b = * 
c =  ** 
d = d+3;
e =   

*  *** the ****  **   
**     * *** *    
**** * *   *  *** * *** ***  ** 

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** ** *  *       *** ** *   0;
}
100/100 answered by (273 points)
edited by
0 0
prog.c:28:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:32:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:32:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
0 0
Your program can end at
  
    return 0;
}
------------------------------------------
You don't need to put

INPUT

ebiil

OUTPUT

hello
commented by (5.9k points)
0 0
Case 0: Correct output
Case 1: Wrong output
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
****   *** *  ***  *
        * **    ***

/* run this * ***    the  *    *** *  or add your own * ** **  ****   *      * ****  ** or   *  */

int  *   * *** char * **  {
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}
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****  ** *** *   **  * 0;
50/100 answered by (252 points)
0 0
prog.c: In function 'main':
prog.c:19:2: error: expected declaration or statement at end of input
  return 0;
  ^~~~~~
commented by (4.3k points)
0 0
Great job using an array and a loop. There are two mistakes found in your code. Please check
1.     printf("\n\n%s", code);  <--- in order to make it match the fixed output '\n\n' should be deleted
2.     At the end of your code, there's something missing.
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
**** * *** **  *  *  
*
***  *  ***   *   **  *
 
*   * *** *****      *   ** *  *           *   *   *** ***  ** *       *     * * **
 
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*
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  = c +  

*** = d +  

       *
*
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* * 

**
100/100 answered by (268 points)
0 0
It's correct lol you can't judge me
commented by (268 points)
0 0
Well, that's because your output doesn't match with the fixed answer. Please take a look at this
printf("%c%c%c%c%c\n", a1, b1, c1, d1, e1);

Hint: You should delete something  :)

By the way, great job.
commented by (5.9k points)
0 0
printf("%c%c%c%c%c", a1, b1, c1, d1, e1);

How's that?
commented by (268 points)
0 0
That's correct.
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
  * *  ** **   * **  ** 
**  *  * **   * *     

int ****** argc, char *** * {
   * **   ** * ** char  **  * 
      * * ** char * * **
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*** *  *   *    char *  * *
**  **  * * *  *  char *   **
** *  **   * *** 
** *  *      *** ***   ** ** *** input the letter to    *****  
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  ** **    ** ****  ** ** ** * ***  * ****** * *     * *  ***    *  ****   ***** ** *   * ** * * 
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*   * *  ** *    *** =     + 3;
*   *      *  **   =  * * + 3;
******    *    letterc = * ** * + 3;
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 *  * ** ***** * 
******  **   **  *   *  *   * *** *  *   *  *            * *       ** 
  * ****  ***    
  ***     *** ** return 0;
}
100/100 answered
reshown by
0 0
-----------Re-judge-----------
Case 0: Wrong output
commented by (4.3k points)
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     hello

Anyway, great job. Full marks.
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
 ** * * **    * * *
 **  *      ****    

int *  argc, char *argv[]) {
*  ***   **  * * char ***  * *
***  *   *** ** char letteri;
*  *   *  ** * ** char *** ** *
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**** *   ********* char ** ** * 
****** * *** 
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 * *   *****  
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* ** * * *     **** *  **  * *** +3;
*      ***   *  * * * +3;
*  * * *  *  * * ** * *  ** +3;
* * * * **  * ***   **** +3;
*** * ** *   * *  ***  *    +3;
* **** * **  
**** *    **  
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  ***   ****  
 * * *  ****  return 0;
}


INPUT
*  **    *   * * **
*  **    **
OUTPUT
  ***  *   ****
100/100 answered by (269 points)
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     hello

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
commented by (5.9k points)
0 0
prog.c:27:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:30:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:30:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
 *   *  *** ** * ****  *
* ***** ****   *    **  

int    * argc, char  * ** {
    * *       ** char *****
  * ***  *  * ** char **** 
 * ****         char   *** 
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** *  *  **   char *** *
*****       *  
 *  ***   *   *  *****  *** * *  input the  * to ** ** * *    * * **** 
**  *     ***  * 
** * *   * ***  * *  *  *   *  * ** * *  * *  * *   * **  *  **** *    ** * * ** *       ***
**    * *   * 
   *  ** **  letter = letter + 3;
* * * **  *   *   *   ** =   ***  + 3;
   ** **  *  **** **  *  = *  * + 3;
**  *  * **   **  **   = * *  + 3;
* **   ***  * ***** = * * + 3;
   *  **     
  * ***  ****   ** *  * *** **  * *** letter is     *****  *  *  *** *** *  *  ******  *       *
  *      *   *  
*       *   * return 0;
}

INPUT
*  *  ***   **   **
* *  ******  ** 
**
 *  *  * *  * * ** *
100/100 answered by (290 points)
reshown by
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     The encrypted letter is hello

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
commented by (5.9k points)
0 0
prog.c:26:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:29:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:29:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
#include ** ** * *  * *

int main(int argc, char *argv[]) {
**  *  * * **  *** *      ***   lettera;
* ****  *  ** **** *  **   * *** ** letterb;
   ***  *   * * * * ***** **  letterc;
** *   * * *** *  ** *  **  **  letterd;
  **** **   *  ** **  * ** ** lettere;
 * ***  **** *** *   * ** 
**  *** ** **  *  *  ***   * *  * *   *  *** %c %c %c ** * **  ** **     ** **   *     ***  *   **    * * *    ** **   *** 
      ** ****** ** *  ** ***  *   = lettera + 3;
*    **    ** **   *** *****   = letterb + 3;
**  ****    **    ***    * * ** * = letterc + 3;
 **** *  *  * *  ** * *** *   * * ***  = letterd + 3;
****** **  * * **   * * * *  **** = lettere + 3;
    **  *  *  ** ** **  **   *** ***  *** * * **  *  * * 
* *    * * **  ******  * **    *  *  ** ** *  %c %c %c * ** **** *    letterb,   *** * **  **** 
 ** *    *     *  ** * 
  * ** * *** **** *** ****  ** * 0;
}

 *  *
    *
**  * *   * * **  
** *  ***
//hello
100/100 answered by (271 points)
edited by
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: e b i i l
     h e l l o

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
commented by (5.9k points)
0 0
prog.c:25:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:28:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:28:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:10:5: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
     scanf("%c %c %c %c %c", &lettera, &letterb, &letterc, &letterd, &lettere);
     ^~~~~
prog.c:10:5: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:10:5: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:17:5: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
     printf("%c %c %c %c %c", lettera, letterb, letterc, letterd, lettere);
     ^~~~~~
prog.c:17:5: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:17:5: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
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