3 like 0 dislike
3k views

You have received an encrypted message from Julius Caesar-- the message is ebiil.  You are asked to decipher the message in order to understand what Caesar trying to say to you.

Hint

Luckily, Caesar has given you a hint, he says: 'I, myself, encoded the message by shifting every word backwards by 3.' 

Solution

Write a program that receives 5 characters 'ebiil'. Then decode those characters into 5 new characters.

Example

#include <stdio.h>

int main(int argc, char *argv[]) {


	char a;
    	char b;
	 	
	scanf("%c%c", &a, &b);
	
	//decode the message how??
	
	printf("%c%c", a,b);
	
	return 0;
}

Input

ebiil

 

 

 

 

 

 

 

 

 

 

Output

hello

** REMEMBER ** 
This is an online-compiler, don't put anything except the codes. If you want to make a comment, please use // or /* */

[Exercise] Coding (C) - asked in Chapter 2: Syntax structure of the C language by (5.9k points)
ID: 26955 - Available when: Unlimited - Due to: Unlimited

edited by | 3k views

22 Answers

0 like 0 dislike
Hidden content!
***** * * ** * *

int * *** argc, char **** {
* * * ** * * *** */

** * * * ** int number;
* * * * * char a;
****** **** *** * *** **** b;
* * * ***** *** * * c;
*** * * ** * * ** d;
* * * * * * * *** e;
****** *** * **
* * ** ** **** forgert how to shift word * ** * * * *
** **** * * * * * ****** * ** * * * ** *** * **** ** * * * * * ***
** ** ** *
* * * * *** the message how??
* ***** * * *
* * * ** ***** ** * * ** * ***** ** * * **
* * * ** *
** ** *** * * return 0;
}
100/100 answered by (449 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
0 0
Case 0: Correct output
Case 1: Wrong output
0 like 0 dislike
Hidden content!
* * * ** * *****
*
** * * * {

*** *** *
= * * ****
**
= * ** *
= ****
= ***

= *
* =
= **
* = *

* * * **
**** *
** * **
* ****
***
*
* *** *
*
100/100 answered by (153 points)
0 0
Case 0: Correct output
Case 1: Wrong output
1 like 0 dislike
Hidden content!
#include * * ** * *
#include ** * ** * *

/* run this program using the console pauser or add your own getch, * ** ******* * * or input loop */

int main(int argc, char *argv[]) {
** * *** *** ** ** ** * a;
** ** * * ** * * b;
** ** *** * * ***** ** ** * c;
********* * * * ** *** * d;
** ** * **** ** ** * e;
* ****** * ***
***** * * * * ****** * * * * ** * the words you want to * ***** ******
*** *** **** * * **
* * * ** **** *** * = getchar();
*** ** ** *** ******* * = a+3;
** * ** * *** * ***** ***** * **
** * * ** * * * *** = getchar();
* * ** * ** * ** * * * = b+3;
* ** * *** * * * ** *** **
* *** * * ***** * * = getchar();
* * * * **** * * **** * = c+3;
* * **** ** ***** *** * * **
* * * * **** ** *** *** *** = getchar();
* * ** ** * ***** * ** * *** = d+3;
*** ** * ***** * * ** ** **
** * * **** * * ***** * = getchar();
** ** * * * * *** * = e+3;
**** * ** ** * * *
*** * * * * ***** * * * * ** *** * ***** * *** *
* ** * * ** ** ** * ******** ** * ** * * * &a, &b, &c, &d, **** *
** * ** * *** * ** *
* *** * ***** * * * the message how??
* * * ** *** * *** **
** ** * **** * * *** *** ** * ** * **** ** a, b, c, d, e);
* * ****** * * ** * ** **
* **** ** * * *** * 0;
}
100/100 answered by (281 points)
edited by
0 0
Your program receives only 2 characters, and it doesn't move characters' positions.

Try to make it receive 5 characters, and move their positions forward by 3.
0 0
This exercise expects only 'hello'. However, your code has.....

printf("Put the words you want to decode:");

Kindly consider delete this part :)
1 like 0 dislike
Hidden content!
* * * * *** ** *** *
* ** * * ***** *

int ** ** char ** {
/*
* ** **** */

* * *

****** ** ** *** **** * ** * * ** * ***** **** *** *
a = a+3;
b = ***
c =
d = d+3;
e = *

** the * ***
***** * ***** **
* * **** * ** * *** * * *** *

* *** * * ** ** *
* * ***** **** * ** * * 0;
}
100/100 answered by (273 points)
edited by
0 0
prog.c:28:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:32:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:32:1: error: unknown type name 'OUTPUT'
0 0
Your program can end at
  
    return 0;
}
------------------------------------------
You don't need to put

INPUT

ebiil

OUTPUT

hello
0 0
Case 0: Correct output
Case 1: Wrong output
1 like 0 dislike
Hidden content!
** ******* ** *
* ** *** *** *

/* run this *** * ** the * *** or add your own * * * ******** * * * or * * * */

int * ** char * * {
* ****** ** int num,
* * * ** * * **
**** **** ***
** ** * ** * * ** **
* **** * for **** = * * * * *** *
{
** ** ***** * * * = *
** ** * * * if ***
* * * *** * * = * * ***
* * ** * * * * ***
}
* ** * * * ** ** * * ** ** * ** * * *
* **** * * * 0;
50/100 answered by (252 points)
0 0
prog.c: In function 'main':
prog.c:19:2: error: expected declaration or statement at end of input
  return 0;
  ^~~~~~
0 0
Great job using an array and a loop. There are two mistakes found in your code. Please check
1.     printf("\n\n%s", code);  <--- in order to make it match the fixed output '\n\n' should be deleted
2.     At the end of your code, there's something missing.
1 like 0 dislike
Hidden content!
** * * *****
*
* *** ***** ******
*
* ** * * * * ** ** ** * * * * * ** *** * ** * * *

* * * ** * ****
*
*** * * * *

* ** ** * *

*** *** ** * * *** * ** ****** * * * * *** ** * * * * ** **
*
= *

* b + *

** = c +

= d +

*

* * ** ** * *** ** *** * ** *

* *

*
100/100 answered by (268 points)
0 0
It's correct lol you can't judge me
0 0
Well, that's because your output doesn't match with the fixed answer. Please take a look at this
printf("%c%c%c%c%c\n", a1, b1, c1, d1, e1);

Hint: You should delete something  :)

By the way, great job.
0 0
printf("%c%c%c%c%c", a1, b1, c1, d1, e1);

How's that?
0 0
That's correct.
1 like 0 dislike
Hidden content!
**** *** * ***** *
** ** ***** ** * **

int ****** argc, char * {
****** * * * char *
**** * **** char **** *
* ** *** *** * char *** *
** *** char * *
* ** ** * char * *
* *** *
*** *** *** * *** **** ** input the letter to * * **** *
* ** * **
** * * ** ** * * ** * ** ** ***** ** ** *** *** * * * * * ** ****** * *** ** * ** *** * *
* *** ** ** * ** = * + 3;
* * * * ** * *** = * + 3;
* **** * ** *** = *** + 3;
* ** * ** letterc = * ** + 3;
** * * * * * = * + 3;
*** ** * ** * *
***** * * * * * * * * * ** ** **** **** * ** ** * * * * ** *
* * **
* ** *** return 0;
}
100/100 answered
reshown by
0 0
-----------Re-judge-----------
Case 0: Wrong output
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     hello

Anyway, great job. Full marks.
1 like 0 dislike
Hidden content!
*** ** * ** ** * *
** **** * * **

int argc, char *argv[]) {
** * **** char *
**** * *** char letteri;
** * * ** *** char **
* * ** **** char ***
**** * * * char * *
* * * ****
* * * * ** ** **** ** * input the letter to encode: * * * ** **
*** *** * ** *
*** ** ** * * ***** *** * * * * * ** * * * * **** * *** **** * * *****
* *** * *** * * *** +3;
*** *** * * ** **** * * +3;
**** **** * * * ** * +3;
* ** * * **** *** ***** +3;
** *** ** * * * * * ***** * +3;
*** * ** ** * *
* *** * * ****
* ** * ** **** ** * * ** * **** *** ** * **** * * * * * **
***** * *** ****
*** * *** return 0;
}


INPUT
** * **** * *
* ***** **** *
OUTPUT
*** *
100/100 answered by (269 points)
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     hello

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
0 0
prog.c:27:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:30:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:30:1: error: unknown type name 'OUTPUT'
1 like 0 dislike
Hidden content!
** * *** * * *
** * ******* ** ***

int * * * argc, char {
*** **** char ***
* * ***** char *
* ** * * * ** char * *
** ** *** * char * *
** ** char *
******* * **** **
*** * * * ***** *** input the * * to ** * * ***** *
* ** *** ***
**** * ** * ***** * **** * *** * * * *** * * * * * **** * * *** ** * ** * *
***** * ***
** * *** letter = letter + 3;
** ** * *** = ** + 3;
* *** * * * * * = *** + 3;
** * ** *** = * ** + 3;
***** * ** * ** *** * = *** * + 3;
******** ****
* ** * ** * * * *** *** letter is ** * *** * * ** ** * ** *** ***
**** ** * *
* ** **** * return 0;
}

INPUT
* ** *
* ** ***
*
** ** ****
100/100 answered by (290 points)
reshown by
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     The encrypted letter is hello

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
0 0
prog.c:26:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:29:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:29:1: error: unknown type name 'OUTPUT'
1 like 0 dislike
Hidden content!
#include * * ** *

int main(int argc, char *argv[]) {
** * * *** **** ******* lettera;
*** * * ***** * * *** letterb;
*** * * ** * * ** * ** **** letterc;
*** * * * * * * * ***** letterd;
* * *** ** * * * * lettere;
* *** *** * ***** **** *
* * * ** * ** * ** ** ** ** ** ** * %c %c %c * *** * ** *** * * * ** * * * * * * * *** * *
* * ** ** ** * * ** * **** = lettera + 3;
** * ** ** * ** * ** * = letterb + 3;
* **** ** * * **** ** **** = letterc + 3;
** * ** ** ** *** **** * ** = letterd + 3;
** * ** * ** *** **** ***** * = lettere + 3;
* ** ** * * * ** ** * * * *** ****** *
* * ** * ** **** * ****** * * %c %c %c * * * * ** ** * letterb, * * *
**** ******** ** ** **
** ** ** ** **** **** * * 0;
}

* *
* *
*** * **
* *
//hello
100/100 answered by (271 points)
edited by
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: e b i i l
     h e l l o

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
0 0
prog.c:25:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:28:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:28:1: error: unknown type name 'OUTPUT'
0 0
prog.c: In function 'main':
prog.c:10:5: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
     scanf("%c %c %c %c %c", &lettera, &letterb, &letterc, &letterd, &lettere);
     ^~~~~
prog.c:10:5: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:10:5: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:17:5: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
     printf("%c %c %c %c %c", lettera, letterb, letterc, letterd, lettere);
     ^~~~~~
prog.c:17:5: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:17:5: note: include '<stdio.h>' or provide a declaration of 'printf'
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.127.90
©2016-2025

Related questions

0 like 0 dislike
2 answers
[Normal] Essay (Open question) - asked Dec 12, 2017 in Chapter 2: Syntax structure of the C language by 許哲瑋 (449 points)
ID: 37081 - Available when: Unlimited - Due to: Unlimited
| 425 views
12,783 questions
183,443 answers
172,219 comments
4,824 users