[Exercise 03] Caesar Cipher Decoder

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You have received an encrypted message from Julius Caesar-- the message is ebiil.  You are asked to decipher the message in order to understand what Caesar trying to say to you.

Hint

Luckily, Caesar has given you a hint, he says: 'I, myself, encoded the message by shifting every word backwards by 3.' 

Solution

Write a program that receives 5 characters 'ebiil'. Then decode those characters into 5 new characters.

Example

#include <stdio.h>

int main(int argc, char *argv[]) {


	char a;
    	char b;
	 	
	scanf("%c%c", &a, &b);
	
	//decode the message how??
	
	printf("%c%c", a,b);
	
	return 0;
}

Input

ebiil

 

 

 

 

 

 

 

 

 

 

Output

hello

** REMEMBER ** 
This is an online-compiler, don't put anything except the codes. If you want to make a comment, please use // or /* */

[Exercise] Coding (C) - asked in Chapter 2: Syntax structure of the C language by (5.9k points)
ID: 26955 - Available when: Unlimited - Due to: Unlimited
edited by | 5.8k views

22 Answers

0 like 0 dislike 
Hidden content!
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int * ** * argc, char * *   {
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  ****     * * return 0;
}
100/100 answered by (449 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
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100/100 answered by (153 points)
0 0
Case 0: Correct output
Case 1: Wrong output
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
#include ****  **** **   * 
#include ***    *  ** * ** 

/* run this program using the console pauser or add your own getch,  * **  ** * **   *  **  *  or input loop */

int main(int argc, char *argv[]) {
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***  ** ***** ** *  *     *   b;
 * *    * ** *   ***       ** * c;
  ***  * **  **** *   * * d;
*    *  ** * * * *** *** e;
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***  *** **   * * * ****   **  * **  * the words you want to       ** * * *
**  * *  ***  *   **      *     
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*** *  *  ** ***  ********* *  = a+3;
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**     ***** * * ** *     * ***  *** *
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***  * ****   * *    ***  *  = getchar();
** *      ***  **  *   * * ***** = e+3;
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  ** **** *** *   *     ****
 * * **** *  **    **   ***  *     0;
}
100/100 answered by (281 points)
edited by
0 0
Your program receives only 2 characters, and it doesn't move characters' positions.

Try to make it receive 5 characters, and move their positions forward by 3.
commented by (5.9k points)
0 0
This exercise expects only 'hello'. However, your code has.....

printf("Put the words you want to decode:");

Kindly consider delete this part :)
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
**  *    * * ***  *
**** * **   **  ** ** * 

int ****   ** *  char   ** ** {
/*
 ***  **    * */

*  ***  

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a = a+3;
b =  *
c = * 
d = d+3;
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**  **  *   *** ** * **
*  *** ***** * * ****  *      *

  *  ** **  **   
**  * *  * * *   **** * *  * ***** 0;
}
100/100 answered by (273 points)
edited by
0 0
prog.c:28:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:32:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:32:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
0 0
Your program can end at
  
    return 0;
}
------------------------------------------
You don't need to put

INPUT

ebiil

OUTPUT

hello
commented by (5.9k points)
0 0
Case 0: Correct output
Case 1: Wrong output
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
* **    *** ***   **
  ***   *  ** *     **** *

/* run this  ** ** **** the ****    *  or add your own *       ****  ***  * *    or **    */

int * ***  *  char *   * {
*  ** ***** int num,  ** 
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{
**   * **  **  ** *** = * ***
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*    *   * *  ** ***   =  ***  **** *
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}
 ** * ****      **    *    * **   * * * *  *   
*  *  ****    *  *  0;
50/100 answered by (252 points)
0 0
prog.c: In function 'main':
prog.c:19:2: error: expected declaration or statement at end of input
  return 0;
  ^~~~~~
commented by (4.3k points)
0 0
Great job using an array and a loop. There are two mistakes found in your code. Please check
1.     printf("\n\n%s", code);  <--- in order to make it match the fixed output '\n\n' should be deleted
2.     At the end of your code, there's something missing.
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
*** *  **  *** * 
*
* *   **  **  ****** **

     **      * ***    *  **  *   **     *   * *       *  *  * ***** ** * * * ** **    * * 
 
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***  * * ** *

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*
*  **    * **  * *    ******   * ****  *  **  *      *       *  *   * *** **
*
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*
*   b + **

   = c +  

  = d +  
*
        
 
   * * *  * *** ****      **      *  * *  ** * **
 
** **
 
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100/100 answered by (268 points)
0 0
It's correct lol you can't judge me
commented by (268 points)
0 0
Well, that's because your output doesn't match with the fixed answer. Please take a look at this
printf("%c%c%c%c%c\n", a1, b1, c1, d1, e1);

Hint: You should delete something  :)

By the way, great job.
commented by (5.9k points)
0 0
printf("%c%c%c%c%c", a1, b1, c1, d1, e1);

How's that?
commented by (268 points)
0 0
That's correct.
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
  **  * ** ***    *  *  * *
*  * * ***  ** **** **  

int   **   argc, char * **  {
  **  * * *** * char * ***
 ** * ** *** char *** 
**    **  ** ***  char *****
 * *        * ** * char   *    
* ** **   *** **  char **** *
** **  *** * * *   
* ***   *     *  ***   **      * input the letter to   *** * **
**  *** * ***** 
*   **   ** *   * * * ** **    *  *   *** * * ** **  *     * *   * * * *** *  * *    **  * * *  
    * *   ** **  * * =  **   + 3;
*** *   ****   *     = **  + 3;
**   *   **  ******  = * * + 3;
***** * * * * *  * letterc =  * *  * + 3;
**  *   * ****  ** *  = *** + 3;
**    * *****  * 
 *  * **   *        *****  *    * *** *   *   * * *   **  *  * **  **   *
* ****  **      
 *      ****   return 0;
}
100/100 answered
reshown by
0 0
-----------Re-judge-----------
Case 0: Wrong output
commented by (4.3k points)
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     hello

Anyway, great job. Full marks.
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
 *     * *  * ** * ***
* *   * ****   **** **

int * * *  argc, char *argv[]) {
*  * * * *  ** char * ***
**  **   *  * ** char letteri;
  **** **   ** char **** *
*** * ** *   * **  char **** * 
*** **  *  **   char  **
* *** * *  *  
 * ****  ***      *     * input the letter to encode:    **  *    **** 
    **     ** ** * 
 * ***      * * *  **   * ********   * **** **   ******  ****  *   *  * * *  * ** * * *    *     ***   ** * * 
** * ** *  * ** * **** *  +3;
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**   *    ***   * *     * * +3;
 * ***    *   *       *   +3;
*  ** * ****  ** **    +3;
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*    *** **** ** 
         ** ***** **   *  *   * * **** ***  ****    ** *  *   **  ** 
***   *  *   *   
**    *   * ***** return 0;
}


INPUT
*    *   *  * * **    *
* **  ** * 
OUTPUT
* *******  ** **  **
100/100 answered by (269 points)
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     hello

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
commented by (5.9k points)
0 0
prog.c:27:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:30:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:30:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
  ** *    ** **  **   
        *     *****  *  

int  **** argc, char *** *  {
     * **      char     * 
     *** *    * ** char * ** *
******* ***  ** char  * *
  * ***   **** **  char       
 ** ***  *  * **  char   *  * 
**    *** *    * 
  *   *      *    *  ***  * *  * input the  * *   to *   ***** *   **** **
   * ***  * *** 
*       *      ** * ****   *    ** ** *   ******* * **   *** *  * * **  *** *   * *     *  *
 ** ** **  ***  *  
*  **    * *    letter = letter + 3;
* * ***   ***  *     *  * = **** + 3;
   * ***   * *** * ** = *  ** + 3;
***** *** **   *    = *  * + 3;
*** * ** **  * * = ***  + 3;
 * *  *  **  * 
  *      **  * * *** **   ** * * letter is  **  *******  **  * **      *    **   ***     ****  
    * **   *   *   
** *** *     *    return 0;
}

INPUT
*   * **** *  *  *
      *  **** * 
* *  
 * * **  *     ****
100/100 answered by (290 points)
reshown by
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     The encrypted letter is hello

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
commented by (5.9k points)
0 0
prog.c:26:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:29:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:29:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
#include  *** *      *****

int main(int argc, char *argv[]) {
*   *     **   * * * **    *  *   lettera;
** *  ** * * ****** * **   ** letterb;
*    ** ** **    *  * *  * * letterc;
  *** * * *  **  * ***** ** * ** letterd;
  * * *   * **** **** **** * ***   *  lettere;
*   * ***   *  *  * 
   *  ** * *     **  *  *  *    ** *  ***  %c %c %c  ** *** *      *   ****** *  ** * * *   *** * **  * *  ****  ** * *  ****  **** 
****    **  * * * *  *     *  * * = lettera + 3;
 *   **  * * ***  *** *  *    = letterb + 3;
 ** ** *** * * ***      * ** *** = letterc + 3;
  **  ***    ***  ** *     ***    = letterd + 3;
  *    *** *    ***  **  ** = lettere + 3;
*** ** * **   ** ** *  *   *****      *****    ***** *  *    *
* ** ***  **  ** ***  ***    ** *** * %c %c %c * * **** *  * **  letterb,  * ** **   * *        
  ** *  * ** ****   *     
* **     ****** *     * ***     0;
}

*** 
   *****
    *  *** ****  
 *   
//hello
100/100 answered by (271 points)
edited by
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: e b i i l
     h e l l o

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
commented by (5.9k points)
0 0
prog.c:25:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:28:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:28:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:10:5: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
     scanf("%c %c %c %c %c", &lettera, &letterb, &letterc, &letterd, &lettere);
     ^~~~~
prog.c:10:5: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:10:5: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:17:5: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
     printf("%c %c %c %c %c", lettera, letterb, letterc, letterd, lettere);
     ^~~~~~
prog.c:17:5: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:17:5: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
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