[Exercise 03] Caesar Cipher Decoder

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You have received an encrypted message from Julius Caesar-- the message is ebiil.  You are asked to decipher the message in order to understand what Caesar trying to say to you.

Hint

Luckily, Caesar has given you a hint, he says: 'I, myself, encoded the message by shifting every word backwards by 3.' 

Solution

Write a program that receives 5 characters 'ebiil'. Then decode those characters into 5 new characters.

Example

#include <stdio.h>

int main(int argc, char *argv[]) {


	char a;
    	char b;
	 	
	scanf("%c%c", &a, &b);
	
	//decode the message how??
	
	printf("%c%c", a,b);
	
	return 0;
}

Input

ebiil

 

 

 

 

 

 

 

 

 

 

Output

hello

** REMEMBER ** 
This is an online-compiler, don't put anything except the codes. If you want to make a comment, please use // or /* */

[Exercise] Coding (C) - asked in Chapter 2: Syntax structure of the C language by (5.9k points)
ID: 26955 - Available when: Unlimited - Due to: Unlimited
edited by | 5.9k views

22 Answers

0 like 0 dislike 
Hidden content!
  * **       ** *  * **   *

int    * argc, char **** {
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*  * * * **   int number;
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** * *   ***   
   ** *  * ** return 0;
}
100/100 answered by (449 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
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**     ** *   *   **      {

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100/100 answered by (153 points)
0 0
Case 0: Correct output
Case 1: Wrong output
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
#include ***  *****   *   *
#include   ****** * * * **** *

/* run this program using the console pauser or add your own getch,       *   **      ** or input loop */

int main(int argc, char *argv[]) {
***  * *  *   * *  ** *    *** a;
   * ** * * ***     ********  b;
*   * *   * * *** **** ** * ** *   c;
  *  *  ** *  * * ***     d;
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* *  * ** ** **   ** ** * 
* ***    * *    **  *  * = getchar();
  **** * **   ****   *** = a+3;
  * **********    *   * **   ** * **  **
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* * *  *  *   *** *  *  **  = b+3;
**  ****  **  ***   * ** *****  *  
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**  ****  *   ** **  * *   ** = d+3;
*** *** *  ** **  **  * *  *     * 
**  *   **** * * *     *   * = getchar();
  **** * * *  *      **  = e+3;
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  ***  * * * * *  *** *  
  *   *  * *** ** * * ***  *   ** 0;
}
100/100 answered by (281 points)
edited by
0 0
Your program receives only 2 characters, and it doesn't move characters' positions.

Try to make it receive 5 characters, and move their positions forward by 3.
commented by (5.9k points)
0 0
This exercise expects only 'hello'. However, your code has.....

printf("Put the words you want to decode:");

Kindly consider delete this part :)
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
   * **** ** *   * 
    *       **  ** 

int   * *  * ** char  ***    {
/*
   *  **      * */

 * * * ***

   **  *    * *   *   ** ****        *  **  * ********  **** *  ** **
a = a+3;
b = * 
c = ** *
d = d+3;
e =  * *

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*   * *** *  ***** *  *
* ** ** * *  * * *   **  ***** 0;
}
100/100 answered by (273 points)
edited by
0 0
prog.c:28:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:32:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:32:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
0 0
Your program can end at
  
    return 0;
}
------------------------------------------
You don't need to put

INPUT

ebiil

OUTPUT

hello
commented by (5.9k points)
0 0
Case 0: Correct output
Case 1: Wrong output
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
*** *        ** *    *
**  ***   * ** *  **** * 

/* run this * * * *** the ** **     * or add your own   * *  **  * * **** ** *     * or *     * */

int ** **   **   char     ** {
* ***** ***** int num,   ***
*      *   *   * *     * 
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***  *    ** *    * *  * **   ** *** ** 
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{
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}
  * *****  ** *   *  * ***** *   ***
** *   * *   * * 0;
50/100 answered by (252 points)
0 0
prog.c: In function 'main':
prog.c:19:2: error: expected declaration or statement at end of input
  return 0;
  ^~~~~~
commented by (4.3k points)
0 0
Great job using an array and a loop. There are two mistakes found in your code. Please check
1.     printf("\n\n%s", code);  <--- in order to make it match the fixed output '\n\n' should be deleted
2.     At the end of your code, there's something missing.
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
 *  **   *  **   * * ** *

*    *   ****  ****  ***   *

 *  *  **  **        *  *  **  * *  *** *   **   ** ***   ** **** **   ** * **      
 
 ***  *** *  *  *   **    **  
 
    *    * 

   *      * *  * *

* * * ** *   ** * **   * * * * *   * * *    * *        *  ** ****  **** *
 
  = *  * 
*
*  * b + **

  = c + **

   = d + 

 * *   
*
***   ******  *  *      *  *  ** *    * *  ** 

     * *
100/100 answered by (268 points)
0 0
It's correct lol you can't judge me
commented by (268 points)
0 0
Well, that's because your output doesn't match with the fixed answer. Please take a look at this
printf("%c%c%c%c%c\n", a1, b1, c1, d1, e1);

Hint: You should delete something  :)

By the way, great job.
commented by (5.9k points)
0 0
printf("%c%c%c%c%c", a1, b1, c1, d1, e1);

How's that?
commented by (268 points)
0 0
That's correct.
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
*    **     ** ** 
*       * ** *   * * *

int *  ***  argc, char ** *  ** {
 ****  * * ***    char  **   
* ******     **** char * ****
* * *  * * * char *  *
**** ** *  * char *   * *
****** *  **** * char ** 
* *  *  ** * 
 *  * ***   ** **  *     ** *    ** input the letter to *  * * * 
 * *** *  *    
  *** *  * * **   * * *** *  * *** *     ** **    *       **** ** ** *     * * **   *   **  *****    ** **** ** *
* ***  *    * **    *    =  **  + 3;
****     *  *  *   * ** =  * ** + 3;
 ****  **  *   *  *   * *  =   + 3;
  ** * **  ** *** letterc = ** *** + 3;
** **  * *   * ** *** = **  + 3;
* **      ** * 
* **** *  *   * *      **     *  * **  **   *        * **     * ** *   * * 
 * *    * **    
 *      **  ** return 0;
}
100/100 answered
reshown by
0 0
-----------Re-judge-----------
Case 0: Wrong output
commented by (4.3k points)
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     hello

Anyway, great job. Full marks.
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
* ** *   **** *****  
  * * *     * *** * ** **

int * *  ** argc, char *argv[]) {
****      ***   *  char       
* * * **     * * * * char letteri;
 * ****  ** *    char   ** *
**  *  ** * * char   **
** * *     **** *  char  **** *
*  * ** ***** * 
* ** **  ***     ** ** **   *  input the letter to encode: * **** * **   * * *
   *  * **** * 
* * *    * ***  *  *      * *  *  *    *****  *     **   ** *   **** ** ** ****  ***** ** *     ******** * *
*  ***   * *     * * **   +3;
 *     *   *******  ****  +3;
*   *  *   **  * *     ** ** +3;
  *    *  **     * ***** *   +3;
* *****        *  ***  *** +3;
 *   *  * ** *  
*       *   ** * 
*   ****  * ** * ** *** *       **  ***   **  *  *   ** * *    **  ****
 *  ***   ** **  
 ** *  ****  ** return 0;
}


INPUT
 * * ***   * *
  * * * **  **** 
OUTPUT
   **** **  ** *
100/100 answered by (269 points)
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     hello

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
commented by (5.9k points)
0 0
prog.c:27:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:30:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:30:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
 ****   * * *    ****  * 
   ** **   * **  * **

int  ***  argc, char ** * * {
    ** * **   * char ***** 
 ****    ** *   char **  ***
* * *       ** char **  *
   **   * *** * char * *  
*****  *  *   **  char   ** 
* ****  * ****** 
****      ***   ** ** *  *     * input the  *  to  *   * *   *** * * 
   ****    ** *  
****  ** * *  * * ******  *  ****** *   *  **      * * **   ** *  *** *  * ***  ** *  *** * **
 **     *     
     *      letter = letter + 3;
*  * *  **   *     *  * = *  ** + 3;
*****   *   *****  = **    + 3;
*    *     **   * *   =  ** * + 3;
 * ** *  ***  ** * *  * =   ** + 3;
*   * ** *  **  
* *   *** ***   *  * *   * *  *  *  * letter is  ** *   *      *   *   ** *   * **  *       *
  **  ****   
* *     * * **   return 0;
}

INPUT
*  ***     * * 
  **** *      ***
* **
    ** **** * *
100/100 answered by (290 points)
reshown by
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     The encrypted letter is hello

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
commented by (5.9k points)
0 0
prog.c:26:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:29:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:29:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
#include  *** *  *** *    

int main(int argc, char *argv[]) {
**   *   ** ***   * *            lettera;
  *   *    ***   ** *** *** * ***   letterb;
***    * **   *   *****  ***  letterc;
***** ****  *  * **** *    *  letterd;
 ****  ***   **  **  *** **** lettere;
 *  *   ****** **  * *  **
***      * * *** *  **  **  ** *** *    %c %c %c  ***     *   *  *****   * * ******   *      *    *** ** *** ***** *     * 
  * * ****** * *  ******  **   ******  = lettera + 3;
 * * ** ** ** **** * ** **   = letterb + 3;
***    **  *  *** ****     ** **  = letterc + 3;
 **   * *   *** ** *        **   * = letterd + 3;
*   * *  ***  *  ****  * *  **    * = lettere + 3;
 *****   ******* *  *    ** ****    ** * *** * *  * * *  
* * ***** ******   ***  * *** * ***   * %c %c %c   * * ** **** letterb,   **** ** *      **
* *  ** *** * *** *** **   **
   *        * *  *  *****  *   *  0;
}

   * 
  * *
***** * * * **  
   ***
//hello
100/100 answered by (271 points)
edited by
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: e b i i l
     h e l l o

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
commented by (5.9k points)
0 0
prog.c:25:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:28:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:28:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:10:5: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
     scanf("%c %c %c %c %c", &lettera, &letterb, &letterc, &letterd, &lettere);
     ^~~~~
prog.c:10:5: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:10:5: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:17:5: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
     printf("%c %c %c %c %c", lettera, letterb, letterc, letterd, lettere);
     ^~~~~~
prog.c:17:5: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:17:5: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
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