[Exercise 03] Caesar Cipher Decoder

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You have received an encrypted message from Julius Caesar-- the message is ebiil.  You are asked to decipher the message in order to understand what Caesar trying to say to you.

Hint

Luckily, Caesar has given you a hint, he says: 'I, myself, encoded the message by shifting every word backwards by 3.' 

Solution

Write a program that receives 5 characters 'ebiil'. Then decode those characters into 5 new characters.

Example

#include <stdio.h>

int main(int argc, char *argv[]) {


	char a;
    	char b;
	 	
	scanf("%c%c", &a, &b);
	
	//decode the message how??
	
	printf("%c%c", a,b);
	
	return 0;
}

Input

ebiil

 

 

 

 

 

 

 

 

 

 

Output

hello

** REMEMBER ** 
This is an online-compiler, don't put anything except the codes. If you want to make a comment, please use // or /* */

[Exercise] Coding (C) - asked in Chapter 2: Syntax structure of the C language by (5.9k points)
ID: 26955 - Available when: Unlimited - Due to: Unlimited
edited by | 3k views

22 Answers

0 like 0 dislike 
Hidden content!
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**   ** * *  return 0;
}
100/100 answered by (449 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
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100/100 answered by (153 points)
0 0
Case 0: Correct output
Case 1: Wrong output
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
#include *** *    **    ****
#include  *  ***** *** 

/* run this program using the console pauser or add your own getch, ** ****  * **  *   *** or input loop */

int main(int argc, char *argv[]) {
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*     *     *  * *    *     
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}
100/100 answered by (281 points)
edited by
0 0
Your program receives only 2 characters, and it doesn't move characters' positions.

Try to make it receive 5 characters, and move their positions forward by 3.
commented by (5.9k points)
0 0
This exercise expects only 'hello'. However, your code has.....

printf("Put the words you want to decode:");

Kindly consider delete this part :)
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
***  *      * **  ** ***
    * * *  **  **  **   *

int    *   * char       * {
/*
***  ***    */

* * * ** ***

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a = a+3;
b =  
c = *  *
d = d+3;
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* *    * *   *  *  *  ** ***       * *

*  **      **   
***  * * **********  *  *  *   **  0;
}
100/100 answered by (273 points)
edited by
0 0
prog.c:28:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:32:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:32:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
0 0
Your program can end at
  
    return 0;
}
------------------------------------------
You don't need to put

INPUT

ebiil

OUTPUT

hello
commented by (5.9k points)
0 0
Case 0: Correct output
Case 1: Wrong output
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
*** *  **** ** * ** ***
*   * * * * **     

/* run this *  ***      the * *    *** or add your own  *       * **  * *  *  * or * *  **  */

int  *  *      char * ** {
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}
* ***    *  *    ***      ** **    * *      
** * * ** *     *      * 0;
50/100 answered by (252 points)
0 0
prog.c: In function 'main':
prog.c:19:2: error: expected declaration or statement at end of input
  return 0;
  ^~~~~~
commented by (4.3k points)
0 0
Great job using an array and a loop. There are two mistakes found in your code. Please check
1.     printf("\n\n%s", code);  <--- in order to make it match the fixed output '\n\n' should be deleted
2.     At the end of your code, there's something missing.
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
 *   *  *** *  * *  *
 
 **    *  ***   ** *  * **
 
*     *       *     *  **   *        *** * ****  ** ** ***    ***   **  *     **  *  
 
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* * *    * ****  ** *   ***  **** **   * *  **  * ** *  *   *        

* =  *   
 
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*  = d + **

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      * *   **  *  ****    *  ** *  * * *  **
*
  *    **
100/100 answered by (268 points)
0 0
It's correct lol you can't judge me
commented by (268 points)
0 0
Well, that's because your output doesn't match with the fixed answer. Please take a look at this
printf("%c%c%c%c%c\n", a1, b1, c1, d1, e1);

Hint: You should delete something  :)

By the way, great job.
commented by (5.9k points)
0 0
printf("%c%c%c%c%c", a1, b1, c1, d1, e1);

How's that?
commented by (268 points)
0 0
That's correct.
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
** **  *  *** ** **    
* * *   * *    *  *     *

int *** argc, char * * * {
****  *  **   char  ** * 
*    ** *    **  char *  *
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*    * * *   *    * ***   * *    input the letter to     **   *     
* **  *  ***     
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**  *  *   * *      = **   *  + 3;
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*   *      **  * letterc =   *  + 3;
  * ** * * *** * ** = *  + 3;
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  *     *  *   **  * **  ** *  * **   *  **  * ***** **    * *          * *   
   *  *  * *   ***   
 ***  ***  *  return 0;
}
100/100 answered
reshown by
0 0
-----------Re-judge-----------
Case 0: Wrong output
commented by (4.3k points)
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     hello

Anyway, great job. Full marks.
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
* **     * ******  *  *
 *      *****    *    * *

int       * argc, char *argv[]) {
     *  * ** ** char    *
  *  *  ** char letteri;
  * **   * *   * char  * **  
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**   *    ****   char  **
* *****  ***  * 
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* *  *      *  
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** ***   * *** **  *   ** * +3;
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**  *   *  * ****   
***   ** *** 
   *  *     ** * ** **   ** ***  ****  ** * ****  **** **     * *    *
   ** * ** ** 
  * *  ****   return 0;
}


INPUT
   *** **    ** 
* ******  **   *
OUTPUT
****  * * ***    *
100/100 answered by (269 points)
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     hello

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
commented by (5.9k points)
0 0
prog.c:27:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:30:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:30:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
** *    *** *     ** 
*  * **      * *   **  

int  **      argc, char    *** {
  * **  *****   char   *
     * *  *  *  char    
**** *   *   ** char *  *
*     *   ** **   char  **  
**    **   ***   char  *
* ****    *** 
 ***  * *       *  ***  ** **  ** input the  ** to * ** ***  ** **  ** * **
    * **     * *   
 * * *  *  *     * * *   **      *   **** *   *   *** *  ** **   ** **  ****  *   **   ***     *  * **
*  ** *    ** 
 ***     * ******* letter = letter + 3;
* * **  * * *** * * ***   = *   * + 3;
 *** **  ** ******   * =  **   + 3;
 * *****  ** ***  *** = * **   + 3;
  * * * *  **   * *  =      + 3;
  ** **   *  **  
* *   *   *  ** * *** * *  letter is *    *  *  ***  ** *    *  *  *   * *     *
* ****   *      
*    *    **** return 0;
}

INPUT
**** *    *  ****
****** * * ** *
***   
** ** ** *  ** *  **
100/100 answered by (290 points)
reshown by
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     The encrypted letter is hello

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
commented by (5.9k points)
0 0
prog.c:26:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:29:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:29:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
#include       * **  ***  *  

int main(int argc, char *argv[]) {
*    * * *  **  ** ****** * *      lettera;
   ** ** *        **    *  letterb;
 *  *     * **   *     * **  **   letterc;
  *** * * ***** **    *  **  letterd;
 ***  *   * * ******    ***  *   ** lettere;
   * *  *  * *   ****  * *
* * **  *  *    *   **** * * * *   * *   %c %c %c    ******* ** *** **  ** **      *  *  * * *   *   *   **  **   
  * *   *  ** * *  ** * **  *   = lettera + 3;
*     * **** *   *   *  ***  ***  = letterb + 3;
******** * **** *** * *** ****   = letterc + 3;
   **   *  ** * ***  *  *      *  = letterd + 3;
*  *    *    *  * * * ** *** = lettere + 3;
**** * *****  ** * **  ** *  ***   **   **  
* ***  *   *  *** **** *  * ** ** *  ****   %c %c %c **  *   **** letterb, *****  ***  * * * ** *
*****    * * **    *** **    
* *  *  *    **  ** *   *   ***  **  0;
}

** ** *
  * **
** **    * 
  *    **
//hello
100/100 answered by (271 points)
edited by
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: e b i i l
     h e l l o

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
commented by (5.9k points)
0 0
prog.c:25:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:28:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:28:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:10:5: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
     scanf("%c %c %c %c %c", &lettera, &letterb, &letterc, &letterd, &lettere);
     ^~~~~
prog.c:10:5: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:10:5: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:17:5: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
     printf("%c %c %c %c %c", lettera, letterb, letterc, letterd, lettere);
     ^~~~~~
prog.c:17:5: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:17:5: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
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