[Exercise 03] Caesar Cipher Decoder

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You have received an encrypted message from Julius Caesar-- the message is ebiil.  You are asked to decipher the message in order to understand what Caesar trying to say to you.

Hint

Luckily, Caesar has given you a hint, he says: 'I, myself, encoded the message by shifting every word backwards by 3.' 

Solution

Write a program that receives 5 characters 'ebiil'. Then decode those characters into 5 new characters.

Example

#include <stdio.h>

int main(int argc, char *argv[]) {


	char a;
    	char b;
	 	
	scanf("%c%c", &a, &b);
	
	//decode the message how??
	
	printf("%c%c", a,b);
	
	return 0;
}

Input

ebiil

 

 

 

 

 

 

 

 

 

 

Output

hello

** REMEMBER ** 
This is an online-compiler, don't put anything except the codes. If you want to make a comment, please use // or /* */

[Exercise] Coding (C) - asked in Chapter 2: Syntax structure of the C language by (5.9k points)
ID: 26955 - Available when: Unlimited - Due to: Unlimited
edited by | 5.6k views

22 Answers

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Hidden content!
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}
100/100 answered by (449 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
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100/100 answered by (153 points)
0 0
Case 0: Correct output
Case 1: Wrong output
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
#include * * *      **** 
#include  **   *  ******** **

/* run this program using the console pauser or add your own getch,  *  *  ** * *   * ** or input loop */

int main(int argc, char *argv[]) {
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* *  * **** *  * **  ****  * = e+3;
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*    * *** ******  * **
****    ** * ****  *   * *** **** 0;
}
100/100 answered by (281 points)
edited by
0 0
Your program receives only 2 characters, and it doesn't move characters' positions.

Try to make it receive 5 characters, and move their positions forward by 3.
commented by (5.9k points)
0 0
This exercise expects only 'hello'. However, your code has.....

printf("Put the words you want to decode:");

Kindly consider delete this part :)
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
***  *   * ** *  **** **
*** **  ***** * *    **

int *    *  char   ** *  {
/*
** *  ** *  */

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*  *** * ***  *  * *   **  **       *    ** *  *     *   * *   **
a = a+3;
b = * 
c = ***
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e =     

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*****  *** **   **  *
*** ****    **** ** *    * **   ** 0;
}
100/100 answered by (273 points)
edited by
0 0
prog.c:28:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:32:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:32:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
0 0
Your program can end at
  
    return 0;
}
------------------------------------------
You don't need to put

INPUT

ebiil

OUTPUT

hello
commented by (5.9k points)
0 0
Case 0: Correct output
Case 1: Wrong output
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
 * **  **   *  **** 
 ***  * *  ***  *  *

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int **  *  char  *** {
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}
**  * *  * *    *   ***   * **   ***  **
** * *   *** *   * 0;
50/100 answered by (252 points)
0 0
prog.c: In function 'main':
prog.c:19:2: error: expected declaration or statement at end of input
  return 0;
  ^~~~~~
commented by (4.3k points)
0 0
Great job using an array and a loop. There are two mistakes found in your code. Please check
1.     printf("\n\n%s", code);  <--- in order to make it match the fixed output '\n\n' should be deleted
2.     At the end of your code, there's something missing.
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
**** ** **  * * **** *** 
 
***     * *  * **   * *
 
  **  **  *   *** *    *   *       *       * ** **  ***    *** ** *        * * **  

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 * = d + *
*
**     * 
*
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*
**     
*
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100/100 answered by (268 points)
0 0
It's correct lol you can't judge me
commented by (268 points)
0 0
Well, that's because your output doesn't match with the fixed answer. Please take a look at this
printf("%c%c%c%c%c\n", a1, b1, c1, d1, e1);

Hint: You should delete something  :)

By the way, great job.
commented by (5.9k points)
0 0
printf("%c%c%c%c%c", a1, b1, c1, d1, e1);

How's that?
commented by (268 points)
0 0
That's correct.
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
*  ** * *  *  *   *** 
 * *** ***   *   *  ***  

int  **   argc, char  * ** {
* *    *    *  char *** 
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*   *     *  * 
** ***  * * * **   **  *  ** * input the letter to ****     ***  
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** ****   ** **   = ** ** + 3;
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**** **** *** *   ** **  **  ****   ****   *****  *  *** *  * ** * **  
*   ** * *  * 
 **    ***   * return 0;
}
100/100 answered
reshown by
0 0
-----------Re-judge-----------
Case 0: Wrong output
commented by (4.3k points)
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     hello

Anyway, great job. Full marks.
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
 * *  * *   * * *     
*        ** ** **  

int *     argc, char *argv[]) {
*  * **  * * * *** char *** **
 *  *    * * *  char letteri;
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***   *     * *   
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**** *   ****  
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* * * *     ** * 
    *** ** return 0;
}


INPUT
    ***   **  ***
   * ** ***  ***   
OUTPUT
**** ****   **
100/100 answered by (269 points)
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     hello

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
commented by (5.9k points)
0 0
prog.c:27:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:30:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:30:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
 * * **  *** *   *
 ** **   *     **   

int  *  argc, char *  * * {
******  ** *   ** char **  
 *   *       * ** char *    *
*   *   *  *  char     *
*    ** * * **  char *** * **
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* * * *  ***  *   
**  *  *  **** * ***   ** input the  **  *  to *  *    * *  *  ** **  
  **  ** *** 
* *** *    ** *   *    *  *  *   *    * ** *   *  *   * *** ****  * **      *  * * *  **        **  ***
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*   ****** *    ** * letter = letter + 3;
    * *   *  ** ***  = ***** + 3;
******* *  *  *       * =   * *  + 3;
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*   *  * * ***   **  =   ** + 3;
*** **   * *  
        * * *    *     *  * **  * *    letter is ***  * *    *   *    **  ** ** ** **  *   **
** * *     *   
** * *    ** *  return 0;
}

INPUT
* ***  *** **   
**** *     
 *  ***
****    * * *
100/100 answered by (290 points)
reshown by
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     The encrypted letter is hello

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
commented by (5.9k points)
0 0
prog.c:26:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:29:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:29:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
#include *    * * *  *****  

int main(int argc, char *argv[]) {
** *   * **   **  *   **** * ** * lettera;
*  **  * *****  ** ** ****  letterb;
 **   * *  ***  *  *** *     * letterc;
* **  **  **** *    *    * ****  letterd;
   *  * *    *    ***  **      ** lettere;
  * **** * **** *** ***  **
     **** * * ** ***  *    * ****** *   * %c %c %c     ****   ** * **** *     * * * *      **** *  *  *  *** * ***** * * 
 ** *  ** * **** ** * ** * * ** = lettera + 3;
 *  ** * **  * ****  ** * *** **** = letterb + 3;
   *  *   **  ** ** *** * * **  * *** = letterc + 3;
     **  ** *  * ****    *  * ** = letterd + 3;
   * * ** * *** *    **  * *  *     **  = lettere + 3;
**    **   *  *   * ** *** *** ** *  *  * *   * ** 
*** * **  **  *  ******* ***  *      %c %c %c *  *  *** *  **   letterb, **    ** **   * *** 
 **** *  **  *  *****   *
***   ** *  ***** **      ******** 0;
}

* **  
   ***
   ****   ** *
 ** * 
//hello
100/100 answered by (271 points)
edited by
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: e b i i l
     h e l l o

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
commented by (5.9k points)
0 0
prog.c:25:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:28:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:28:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:10:5: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
     scanf("%c %c %c %c %c", &lettera, &letterb, &letterc, &letterd, &lettere);
     ^~~~~
prog.c:10:5: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:10:5: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:17:5: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
     printf("%c %c %c %c %c", lettera, letterb, letterc, letterd, lettere);
     ^~~~~~
prog.c:17:5: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:17:5: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
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