[Exercise 03] Caesar Cipher Decoder

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You have received an encrypted message from Julius Caesar-- the message is ebiil.  You are asked to decipher the message in order to understand what Caesar trying to say to you.

Hint

Luckily, Caesar has given you a hint, he says: 'I, myself, encoded the message by shifting every word backwards by 3.' 

Solution

Write a program that receives 5 characters 'ebiil'. Then decode those characters into 5 new characters.

Example

#include <stdio.h>

int main(int argc, char *argv[]) {


	char a;
    	char b;
	 	
	scanf("%c%c", &a, &b);
	
	//decode the message how??
	
	printf("%c%c", a,b);
	
	return 0;
}

Input

ebiil

 

 

 

 

 

 

 

 

 

 

Output

hello

** REMEMBER ** 
This is an online-compiler, don't put anything except the codes. If you want to make a comment, please use // or /* */

[Exercise] Coding (C) - asked in Chapter 2: Syntax structure of the C language by (5.9k points)
ID: 26955 - Available when: Unlimited - Due to: Unlimited
edited by | 1.1k views

22 Answers

0 like 0 dislike 
Hidden content!
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}
100/100 answered by (449 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
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100/100 answered by (153 points)
0 0
Case 0: Correct output
Case 1: Wrong output
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
#include  *   ***** *  *
#include *****  **  *  ***

/* run this program using the console pauser or add your own getch,   * * *  * * *   **  ** or input loop */

int main(int argc, char *argv[]) {
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*** * *** *   *   ** *     ** * **
**   ***   ** * ** **  *   ** 0;
}
100/100 answered by (281 points)
edited by
0 0
Your program receives only 2 characters, and it doesn't move characters' positions.

Try to make it receive 5 characters, and move their positions forward by 3.
commented by (5.9k points)
0 0
This exercise expects only 'hello'. However, your code has.....

printf("Put the words you want to decode:");

Kindly consider delete this part :)
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
  ** *  *** **** * *** 
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int  **     char * ** * {
/*
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a = a+3;
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c = **
d = d+3;
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** *  * **  * ****   
** **      ** *  **  *  *   * * 0;
}
100/100 answered by (273 points)
edited by
0 0
prog.c:28:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:32:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:32:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
0 0
Your program can end at
  
    return 0;
}
------------------------------------------
You don't need to put

INPUT

ebiil

OUTPUT

hello
commented by (5.9k points)
0 0
Case 0: Correct output
Case 1: Wrong output
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
* *  ** **** *  * **  *** 
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******    ***     * ** *** **
}
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50/100 answered by (252 points)
0 0
prog.c: In function 'main':
prog.c:19:2: error: expected declaration or statement at end of input
  return 0;
  ^~~~~~
commented by (4.3k points)
0 0
Great job using an array and a loop. There are two mistakes found in your code. Please check
1.     printf("\n\n%s", code);  <--- in order to make it match the fixed output '\n\n' should be deleted
2.     At the end of your code, there's something missing.
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
* ***   *    * *  *
*
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**  = d + 
 
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*****   ** ***  * ***  *  *  *  *   *

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100/100 answered by (268 points)
0 0
It's correct lol you can't judge me
commented by (268 points)
0 0
Well, that's because your output doesn't match with the fixed answer. Please take a look at this
printf("%c%c%c%c%c\n", a1, b1, c1, d1, e1);

Hint: You should delete something  :)

By the way, great job.
commented by (5.9k points)
0 0
printf("%c%c%c%c%c", a1, b1, c1, d1, e1);

How's that?
commented by (268 points)
0 0
That's correct.
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
 ** * *  * ***   * **  * * *
     * **  ***** **

int   **   * argc, char *  *** {
* *** ** *   * char     **
**   *** *  ** *  **  char **  *
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*  *  **   * **** ******  *  input the letter to ******         
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  *  * *  **          =  ****** + 3;
* **  *    *  ** ** letterc =  * ** + 3;
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  ** **   **  **  
***  *  **  ** * * *  ****** * *  ******     *       **   *           *  * 
*    *  * **** * 
 *  ***  ** * return 0;
}
100/100 answered
reshown by
0 0
-----------Re-judge-----------
Case 0: Wrong output
commented by (4.3k points)
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     hello

Anyway, great job. Full marks.
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
       * ***** * * * *  
*  *** *** ** * ** * 

int   *  argc, char *argv[]) {
* * ******  * * *  char  *** **
*** * * **  ** char letteri;
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*   ** *    
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* **** ** *** 
         *  ** return 0;
}


INPUT
**   **  *  ** * * 
    ** ***
OUTPUT
  *** *****
100/100 answered by (269 points)
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     hello

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
commented by (5.9k points)
0 0
prog.c:27:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:30:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:30:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
*  *  *   ** ** ** ** 
   **   * *  *   * *  *

int **  argc, char  ***** {
 **** **  * *     char     
   *  *  * *   char * * 
*   * *   **   char *    *
**  *  ** * * char      **
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* **  **   ** *  
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****   **  **  ** 
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 *     ** ** *  * * * = * ** + 3;
 *  ** *  * **    * *  =  ** * + 3;
 ****  *  ***  **  = * ** + 3;
  ***    **** * 
****   * *  ** * *   **** ***   * **  letter is  **** * * *   * ***  *  *       **   **   *
** **  **  ** 
  * *    ****   return 0;
}

INPUT
 ****   *   **  *
* *** * * * *
 *   
*   ** *    ****
100/100 answered by (290 points)
reshown by
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     The encrypted letter is hello

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
commented by (5.9k points)
0 0
prog.c:26:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:29:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:29:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
#include *    **  *** **   

int main(int argc, char *argv[]) {
*  **   *   *** *  *  ****  lettera;
 *****    * ***   * * * *    * *  letterb;
*  ** **** * ** *   *  **  *  * letterc;
 *  *** **    *** ***   * * *   letterd;
*** * *      **   ***  * **** **  *   lettere;
   ****  *  *  ** * ****
** *  ** * ****   * **   *  * * *    **** %c %c %c * * *  ** *** * *  *   *    ** ***  *  ** *****   **   *       *  ********    
* * * **      * * ** ** *   *** *  = lettera + 3;
  * * * * * ***** * **    *  ****  * = letterb + 3;
 * *   ******  ***  *  *****  ** * * = letterc + 3;
**    **  *   * **   **  ***  **  *  = letterd + 3;
*  ******  **  * *    ** * *****  = lettere + 3;
* ** ** ** * * * **  **  ** **   *   *  *  **  ****  ** *  
 **   * *  *** *    **  ***        *  %c %c %c  *** **  *  ** ** letterb,     * **** ** **
*** *** **   *  **  * * **
**     *  * *  *** *  *  * * * ** 0;
}

    * 
 **
 *      **  
  * *
//hello
100/100 answered by (271 points)
edited by
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: e b i i l
     h e l l o

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
commented by (5.9k points)
0 0
prog.c:25:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:28:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:28:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:10:5: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
     scanf("%c %c %c %c %c", &lettera, &letterb, &letterc, &letterd, &lettere);
     ^~~~~
prog.c:10:5: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:10:5: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:17:5: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
     printf("%c %c %c %c %c", lettera, letterb, letterc, letterd, lettere);
     ^~~~~~
prog.c:17:5: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:17:5: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
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