[Exercise 03] Caesar Cipher Decoder

Question

You have received an encrypted message from Julius Caesar-- the message is ebiil.  You are asked to decipher the message in order to understand what Caesar trying to say to you.

Hint

Luckily, Caesar has given you a hint, he says: 'I, myself, encoded the message by shifting every word backwards by 3.' 

Solution

Write a program that receives 5 characters 'ebiil'. Then decode those characters into 5 new characters.

Example

#include <stdio.h>

int main(int argc, char *argv[]) {


	char a;
    	char b;
	 	
	scanf("%c%c", &a, &b);
	
	//decode the message how??
	
	printf("%c%c", a,b);
	
	return 0;
}

Input

ebiil

 

 

 

 

 

 

 

 

 

 

Output

hello

** REMEMBER ** 
This is an online-compiler, don't put anything except the codes. If you want to make a comment, please use // or /* */

Answer 1

Hidden content!
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*  ** *      * * int number;
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 *  * *    
* *    *   * return 0;
}

Comments

Case 0: Wrong output
Case 1: Wrong output

---

Case 0: Correct output
Case 1: Wrong output

Answer 2

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Comments

Case 0: Correct output
Case 1: Wrong output

Answer 3

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#include  * **     ** *   * ***

/* run this program using the console pauser or add your own getch,  ***  *   ******  ****   or input loop */

int main(int argc, char *argv[]) {
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*   *** **  ** * ** * *   **   = getchar();
**** * *     * **         ** = b+3;
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*     *        * **  ** **   = getchar();
**     ** ***  * *  *  *  * = c+3;
***  * *     ** * *   *    *    * * 
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* *        ***  *  ***   *
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}

Comments

Your program receives only 2 characters, and it doesn't move characters' positions.

Try to make it receive 5 characters, and move their positions forward by 3.

---

This exercise expects only 'hello'. However, your code has.....

printf("Put the words you want to decode:");

Kindly consider delete this part :)

Answer 4

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*   * *** * ** * * * **
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int  ****    char  * **  {
/*
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*   * *  *   

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a = a+3;
b =  
c =     
d = d+3;
e = *

*** *** the * *  * * *
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    *** ******    *  ****
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}

Comments

prog.c:28:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:32:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:32:1: error: unknown type name 'OUTPUT'

---

Your program can end at
  
    return 0;
}
------------------------------------------
You don't need to put

INPUT

ebiil

OUTPUT

hello

---

Case 0: Correct output
Case 1: Wrong output

Answer 5

Hidden content!
  ***   * *   *****
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/* run this * ***   * the *  * ** * or add your own ****   **** ***   *  ******* or ****      */

int ***** * ** char  ***   {
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*    **   **  *** for   =   * *   * * * *
{
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* ***  ** *  *  **  ** *
}
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*** *    *   ***    *   0;

Comments

prog.c: In function 'main':
prog.c:19:2: error: expected declaration or statement at end of input
  return 0;
  ^~~~~~

---

Great job using an array and a loop. There are two mistakes found in your code. Please check
1.     printf("\n\n%s", code);  <--- in order to make it match the fixed output '\n\n' should be deleted
2.     At the end of your code, there's something missing.

Answer 6

Hidden content!
**        **     **
*
    *  ****    * *

*  ** **  *  **   *  *   *   **    *  ***    ***  *  ***** ** * ** ***    **     *   *

** **    *     **  * * *
*
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***  *      *    *
 
  *  *** * ** ** ** **      * **   *  **  *        * *  * ***      *  **  * *  

 * =     
*
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  * = d +  
*
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**   ***  ** * *  ***** *** ***  ** *      *

**** 

 

Comments

It's correct lol you can't judge me

---

Well, that's because your output doesn't match with the fixed answer. Please take a look at this
printf("%c%c%c%c%c\n", a1, b1, c1, d1, e1);

Hint: You should delete something  :)

By the way, great job.

---

printf("%c%c%c%c%c", a1, b1, c1, d1, e1);

How's that?

---

That's correct.

Answer 7

Hidden content!
    *    **  *    * 
**    ** * ** **** *

int   *** argc, char     *   {
 * *** *  * *    * char    ***
  * ***    **** * char  *  *
**  *** *    * * char   **  * 
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 * **  **   *   * char * * **
***** *    *    
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* *        ** *** 
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** * * ** ** ****** *  *  =   * * + 3;
*  **  *   ****     *   = ****   + 3;
*  * * **      *  * * **  = * *  *  + 3;
****  * ** *  letterc = ** *** + 3;
 *****      *   * ***   = **  + 3;
 ***   * *     
****  * *       *   *   * * *   *  * *  *  ** *  ****  *  **   *   **** 
**** **        * * 
     ** *  * ** * return 0;
}

Comments

-----------Re-judge-----------
Case 0: Wrong output

---

Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     hello

Anyway, great job. Full marks.

Answer 8

Hidden content!
* *** *   ***  **   * *
  *   *  * *    * 

int * *  ** argc, char *argv[]) {
**  ***    *    *  char   ***
*  ***     ***    char letteri;
 ***  **  * *     char * **  
 *   ** ****  char   ****
* * *     * **   char ***   *
***     *   
*   *** ***    *    ***  * *** * * input the letter to encode: *  ** **        
*    * ***   * 
*      *  ** *  * ** **  *    * * ****   *   *  * ** *   ***   *** *    *  **  * *  **   *  ** *  *** *  *  
*  * *** * ***   * ****** * +3;
*****   **     * *** *   +3;
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* *** **     * *   * *   *  * +3;
*  *     *** *    * ** **   +3;
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*  **  * **  * * ** * * **  *********   ****     * ** *  *  ***   * ***   
      *   *****  
  *  *  ** **** return 0;
}


INPUT
*** *****  * *
*  * *  * *  *
OUTPUT
* ********  *  

Comments

Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     hello

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.

---

prog.c:27:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:30:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:30:1: error: unknown type name 'OUTPUT'

Answer 9

Hidden content!
** ** ** *  ****** * 
* *** ** *   * ** **   

int  *   argc, char ** *    {
  *   *   ** **** char  **** 
*** **   ** *   char   * *
** **       *    char  **
 * **** * **  * char **    
 * *   * * **** char * *   
**  * * *  
*** * * *   ** *    *  * input the     to *     **   * * 
**    *    ** 
* **  * **** * * *  *   * ********* *  * *    *  * ****  *   **  **    *  *   * * *  ***  ***  * **** *     
* ** *     ** ** 
  ** *   *** * letter = letter + 3;
**** * **   *    *  ** =     *  + 3;
* ***  ****  * *  * = *** + 3;
    * *** *   *   =   ** + 3;
****  **  * ***** ****  =      + 3;
*****  ***** ** 
***   **  **** *  *  **   *     *** letter is    *  ****  ** **  *   *** **  * *    *** 
*   **     * **  * 
  ***      *   return 0;
}

INPUT
* *******    * 
 **** *** * ** *
 *   
     *     **  *   

Comments

Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     The encrypted letter is hello

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.

---

prog.c:26:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:29:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:29:1: error: unknown type name 'OUTPUT'

Answer 10

Hidden content!
#include *** ******  ** *

int main(int argc, char *argv[]) {
  ** **    *   * **  ***  lettera;
  *     ** *  *** * *    *  * letterb;
**     *  ****  *   * * *  *     letterc;
 * ***   ** * **  **   **   * ** letterd;
 ***   *  *****   * * ****  * ***     lettere;
   ********  * *  *** **   *
 *****   **  * * **    *   **  ** *  **    %c %c %c **   ** **** ****    *** * * * * * * *    *  ******** *       *  *  
** **** **  ** * *** *   ***  **** = lettera + 3;
 ** **** **** *  *   * * ***  ** *  = letterb + 3;
*   ***** *****   *   *  **    *   = letterc + 3;
**  * *** ******  * ** ***  = letterd + 3;
*  **** *** **  ** **  **  *  = lettere + 3;
  * *** *  *  * *** *******   * * *    * *  **  
* ** *** **   *    *** ***  *  **  %c %c %c  * **      **** letterb,    **   * * *    
 *  ***   **  *  *** *** *  **
 ***   *   ** *** * *  ** * 0;
}

   *
      
* *    **  ***
** ** 
//hello

Comments

Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: e b i i l
     h e l l o

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.

---

prog.c:25:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:28:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:28:1: error: unknown type name 'OUTPUT'

---

prog.c: In function 'main':
prog.c:10:5: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
     scanf("%c %c %c %c %c", &lettera, &letterb, &letterc, &letterd, &lettere);
     ^~~~~
prog.c:10:5: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:10:5: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:17:5: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
     printf("%c %c %c %c %c", lettera, letterb, letterc, letterd, lettere);
     ^~~~~~
prog.c:17:5: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:17:5: note: include '<stdio.h>' or provide a declaration of 'printf'