[Exercise 03] Caesar Cipher Decoder

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You have received an encrypted message from Julius Caesar-- the message is ebiil.  You are asked to decipher the message in order to understand what Caesar trying to say to you.

Hint

Luckily, Caesar has given you a hint, he says: 'I, myself, encoded the message by shifting every word backwards by 3.' 

Solution

Write a program that receives 5 characters 'ebiil'. Then decode those characters into 5 new characters.

Example

#include <stdio.h>

int main(int argc, char *argv[]) {


	char a;
    	char b;
	 	
	scanf("%c%c", &a, &b);
	
	//decode the message how??
	
	printf("%c%c", a,b);
	
	return 0;
}

Input

ebiil

 

 

 

 

 

 

 

 

 

 

Output

hello

** REMEMBER ** 
This is an online-compiler, don't put anything except the codes. If you want to make a comment, please use // or /* */

[Exercise] Coding (C) - asked in Chapter 2: Syntax structure of the C language by (5.9k points)
ID: 26955 - Available when: Unlimited - Due to: Unlimited
edited by | 6.4k views

22 Answers

0 like 0 dislike 
Hidden content!
 **   *   **    ****   

int *  * * argc, char  * **   {
  *   *    * **  *  *** **      */

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** ** * ****   ****** *** *   * c;
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*      *    **  
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* * * **      *  
 ***    ***  return 0;
}
100/100 answered by (449 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
* * *  *    *****  ** **
*
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** *  * *   *
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*  = *  
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100/100 answered by (153 points)
0 0
Case 0: Correct output
Case 1: Wrong output
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
#include   * ***  ** *   *
#include **   *** **    *  

/* run this program using the console pauser or add your own getch, * **** ** *  * *      * or input loop */

int main(int argc, char *argv[]) {
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 * *** **  * * **    ***  *****  b;
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 ***  ****     **    * *  ***  d;
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**   **   ******  * * * *
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    **** * *  **   *** *  ***  
    ***  ****  *** *  * *  *   = getchar();
* *** * * ** ** **  * * ***  * = a+3;
   * * *** * ***   *   * ** *** **  **
   *  ******    ** ***  ****   = getchar();
* **** *    *  * * ***  * *** = b+3;
  *    **  **   ***   * *  * * ***  **
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  * * **     ***** * * **  = c+3;
***  **  *   *   *  *  * *   **** * 
    * *  ***** *     * *  * * = getchar();
 * * ***  ** **  **  *  **  = d+3;
 **   * ** * ** *** *********   * 
 * *  *    *    ** **  *  *  * * = getchar();
 *** *  *   ** ****** ** * = e+3;
 *** *  *  *    *** * ***  **
  ** * ** **** *  * *** *  * *   ** * *  **  *** **    
*   ****  *   *   ** * **** *    *  ** ***  **** **  ******* &a, &b, &c, &d,  ***       
* * *      ** *  * *** * * *  ***
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* **     * ** * *   *** **
*   * **** *  *  ** *   * **** *  * * *  ** * * *  * a, b, c, d, e);
**  **   *****   ** *  ** * *  
* *** **   **  **  * *  * *  ** * 0;
}
100/100 answered by (281 points)
edited by
0 0
Your program receives only 2 characters, and it doesn't move characters' positions.

Try to make it receive 5 characters, and move their positions forward by 3.
commented by (5.9k points)
0 0
This exercise expects only 'hello'. However, your code has.....

printf("Put the words you want to decode:");

Kindly consider delete this part :)
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
    * ******   *   *
    *  * * ********* ** *

int ****** **  char  * *   {
/*
 ** *  * ****  */

* * *  *  

 ** ** **      **** * ** **     *    *     *  ****  ** **   *  *  *
a = a+3;
b =    
c =   * 
d = d+3;
e = **

* * *** the * *  * *
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*  * * *  *****    **** ***  * 

********   *    **   * * *
   * *** *     *   *  * *** *  ** 0;
}
100/100 answered by (273 points)
edited by
0 0
prog.c:28:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:32:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:32:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
0 0
Your program can end at
  
    return 0;
}
------------------------------------------
You don't need to put

INPUT

ebiil

OUTPUT

hello
commented by (5.9k points)
0 0
Case 0: Correct output
Case 1: Wrong output
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
*****   * * **  ** 
* *  **   ***** *** *   

/* run this   ***    * the * * *   * *  or add your own *           * ***     *  *  or  **   ** */

int    *  ** char ****  {
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*  **     ** *  
* *   * ** *   *** *    **    * ** **
*  ****   *   for  ** =       ** ** ******
{
****  **   *** *   * = ** ** *  *
* **  *        if   * ** **   **
** * * * * *  *   = ** *     *
** *  * *  **    * * ****  *
}
 ** *   * ***   ***  ****  **   ****  *  
*** * **     *     * 0;
50/100 answered by (252 points)
0 0
prog.c: In function 'main':
prog.c:19:2: error: expected declaration or statement at end of input
  return 0;
  ^~~~~~
commented by (4.3k points)
0 0
Great job using an array and a loop. There are two mistakes found in your code. Please check
1.     printf("\n\n%s", code);  <--- in order to make it match the fixed output '\n\n' should be deleted
2.     At the end of your code, there's something missing.
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
 **       *  *  *  **  

* **   *    *     ** * 
 
  **      *    ** *    *  **  ***  *   *  * **  * *   ** **  ** *******   *      * *   **
 
*     *  * * * * * *  * **  *
*
**  *   * * ** 

  * * **  ** *  *    *
 
*    * *   **   * *  * * **    ** *     * **    ****        *    *  *

   =  * *

*  b + * 

* = c +  

 *  = d + **
*
  *     **
 
    *   ***** ** *  ** **     * * **    *  
*
      
 
*
100/100 answered by (268 points)
0 0
It's correct lol you can't judge me
commented by (268 points)
0 0
Well, that's because your output doesn't match with the fixed answer. Please take a look at this
printf("%c%c%c%c%c\n", a1, b1, c1, d1, e1);

Hint: You should delete something  :)

By the way, great job.
commented by (5.9k points)
0 0
printf("%c%c%c%c%c", a1, b1, c1, d1, e1);

How's that?
commented by (268 points)
0 0
That's correct.
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
 *  * * **  ** * ***
   **     **   *   

int   * ** argc, char  *** {
** *    * *   ** char * *
 *   * *  **    char * **  
  *  * *  ** * *   char * * 
*   * *  ****** char  ** **
*   *    *  * * char ***  
* **          *** * 
   **  **  * **    * *   **   input the letter to   ***   ***
 *** **  * * *   
 **  *   *   * * *** * *  * **    *    *   *   *  *       * * * *** ****** ***  ** **  * **  * ** **
  * *  **      **   * * * = **** + 3;
******   *** ** *   * =    ** + 3;
 *  ** * * ***  ***** = * *   + 3;
 *** *    *   ** ** letterc = * ** + 3;
*    *     * * ** ** =       + 3;
 * *  ***      *  * 
** * ***  * *   **      *  * * ****  **  * **      **  *                 * * ** 
  ***  *    *    
*  *    * * * return 0;
}
100/100 answered
reshown by
0 0
-----------Re-judge-----------
Case 0: Wrong output
commented by (4.3k points)
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     hello

Anyway, great job. Full marks.
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
 *   **  ****   *****  **
**  ***   *** *   * ** * 

int   *   argc, char *argv[]) {
   **   * ** char ****
 *  *  *   **  char letteri;
*  * * *     char   * **
*  *  **** * *  ** char  **   
*  ***      *  * char  *** 
** **       * **  
****     **     ***** ****** * input the letter to encode: * *  **      *   
 * * **  ****  
    ** *    **       *  **    ***     *    *  *  *  ***    * *  * *  *      *  *    ******   ** * * ***  *   
   ***** *  *   * *  * *  **  * +3;
   ** * **     **  *     *   *** +3;
 ****     ******   *  *  * +3;
*** * *     ** * +3;
***   *         *      +3;
     *  **  * 
 * * *      ** 
**** *        **  ***** **  *   *      ** * *   ** ***  *  * **    ** 
 * * **      ** 
   **** * *  ** return 0;
}


INPUT
*  ** *  **  ** *
 ** * * **   
OUTPUT
 *** * *   **
100/100 answered by (269 points)
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     hello

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
commented by (5.9k points)
0 0
prog.c:27:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:30:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:30:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
*  *** *   *    * *** **  
** **** ******   ***  * 

int *  *  argc, char   {
 * ***  *** * char  **   
**   * **     *  char  ***** 
 * **    *  * * * char * * 
*** *  ** char      
 ****  *  **** * * char *****  
     ** *    * 
*   ** *     * **  **  *       input the  **  to **  *  *  ** *******
   *    * *   
 ** * * *  **  * * * *   ** * **     * *      *  ***  *   * * **** **     ** **   **   * * * *  ****
 * ** ** *  *  ** 
  * * ***  letter = letter + 3;
** *       *        * = * **  + 3;
 * ***** *  ******* * ****** = **  + 3;
 **    **     *  **  = *    *  + 3;
* ****    *   *   *  = *  * + 3;
**  ** *   ** 
****** **** **   * *   ***  ** ** **   ** letter is      ** **** *   * *    *    *   **           
 ** *  * * *    * 
**   * **  * return 0;
}

INPUT
  *        * *** 
   **  **  *
** *
*** * ****  * *
100/100 answered by (290 points)
reshown by
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     The encrypted letter is hello

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
commented by (5.9k points)
0 0
prog.c:26:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:29:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:29:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
#include **  * * ****  * *

int main(int argc, char *argv[]) {
*  * *  ** * ********  * **  * * *** lettera;
*    ******  **   * * **** **   * letterb;
   *    ***  ** **  **  *  letterc;
***   ** ** * * * *   ** *** *    letterd;
** * ** **** *  **  ** *  *  * * lettere;
 * *** * *   *  ***   **   
* *  * *   * * **   *  ** *  ** *  * ** %c %c %c * *  * *  *** *  * * *   *** **    *   *     ** **    *    * * * 
 **  *  ***** ****       ***   ** = lettera + 3;
*    * * * ***     ***  ***** = letterb + 3;
***   ** *  *        ***   **  = letterc + 3;
    *  *   ** * **     ***  ****  = letterd + 3;
  *   * *  *  **  **  * **    = lettere + 3;
 *  *** *   ***  ***  ** * * ** ** **  *    *    * **
 *    *******  ****  *   *     * ** * **  * %c %c %c  *   *  *  *  letterb,      ** * *** * * 
 *     *  ** **** ** *    *** *
 * ***   *   ** ** * * * * **  *  *  0;
}

 *  
*  
 **    ** **  *
 *   **
//hello
100/100 answered by (271 points)
edited by
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: e b i i l
     h e l l o

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
commented by (5.9k points)
0 0
prog.c:25:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:28:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:28:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:10:5: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
     scanf("%c %c %c %c %c", &lettera, &letterb, &letterc, &letterd, &lettere);
     ^~~~~
prog.c:10:5: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:10:5: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:17:5: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
     printf("%c %c %c %c %c", lettera, letterb, letterc, letterd, lettere);
     ^~~~~~
prog.c:17:5: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:17:5: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
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