[Exercise 03] Caesar Cipher Decoder

Question

You have received an encrypted message from Julius Caesar-- the message is ebiil.  You are asked to decipher the message in order to understand what Caesar trying to say to you.

Hint

Luckily, Caesar has given you a hint, he says: 'I, myself, encoded the message by shifting every word backwards by 3.' 

Solution

Write a program that receives 5 characters 'ebiil'. Then decode those characters into 5 new characters.

Example

#include <stdio.h>

int main(int argc, char *argv[]) {


	char a;
    	char b;
	 	
	scanf("%c%c", &a, &b);
	
	//decode the message how??
	
	printf("%c%c", a,b);
	
	return 0;
}

Input

ebiil

 

 

 

 

 

 

 

 

 

 

Output

hello

** REMEMBER ** 
This is an online-compiler, don't put anything except the codes. If you want to make a comment, please use // or /* */

Answer 1

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#include ** *  * * * * * ***
int main(int argc, char *argv[]) {
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**  *  * **** *  *****   *  * letterz;
**  * **** *   ***** ***  letterx;
  *     *  *  *****  ***  ***   letterc;
* **  ***   ** *** **   *  *   *  letterv;
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** *  **  *  *   *****   *** *   *********       *     *    ****  *  **    ***  **     * *****   **  *  ** *   ** *
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  * *  * ** * ***** **     **    *** = letterx + 3;
  **  *   *** *  **** **   *** *  = letterc + 3;
**  *****  *******  *   ** **  = letterv + 3;
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* * *  *  **  * *
* *     * *  **  ******  ** *  0;
}

Comments

Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output

---

Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     hello

Anyway, great job. Full marks.

Answer 2

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 *  *** * ***** char   ** 
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* *  *** ** ***  e = ** *  
*** ** * * ***** 
***  *  ** a += 3;
   *    * *  *  * b += 3;
*      *  **     c += 3;
 ** ***  *  *     d += 3;
 *  ***  *** e += 3;

*  **  * ** * ** * * ** * 
 * * **** **** * **  * * 
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   ****   ** **    *  *   * 
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****** * **  *** 
*    *   * *    
*   *  *** * 
   **  *** *****  *  *  * * ** 0;
}

Comments

Case 0: Correct output