[Exercise 03] Caesar Cipher Decoder

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You have received an encrypted message from Julius Caesar-- the message is ebiil.  You are asked to decipher the message in order to understand what Caesar trying to say to you.

Hint

Luckily, Caesar has given you a hint, he says: 'I, myself, encoded the message by shifting every word backwards by 3.' 

Solution

Write a program that receives 5 characters 'ebiil'. Then decode those characters into 5 new characters.

Example

#include <stdio.h>

int main(int argc, char *argv[]) {


	char a;
    	char b;
	 	
	scanf("%c%c", &a, &b);
	
	//decode the message how??
	
	printf("%c%c", a,b);
	
	return 0;
}

Input

ebiil

 

 

 

 

 

 

 

 

 

 

Output

hello

** REMEMBER ** 
This is an online-compiler, don't put anything except the codes. If you want to make a comment, please use // or /* */

[Exercise] Coding (C) - asked in Chapter 2: Syntax structure of the C language by (5.9k points)
ID: 26955 - Available when: Unlimited - Due to: Unlimited
edited by | 1.1k views

22 Answers

0 like 0 dislike 
Hidden content!
 ** **   ******  

int * *    argc, char ***    {
*   ** ** *   * * * *   * ***  * */

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*****  * *  *  *    
   ** *  * return 0;
}
100/100 answered by (449 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
**  *  *    *** ***** 

* *   ** *   *    {

***** *   ***
*  =     **  * 
*        **
** =  * *****
** =     *   
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* = **
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* **      ***    **** **
100/100 answered by (153 points)
0 0
Case 0: Correct output
Case 1: Wrong output
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
#include *** *  * *  **  ** **
#include *****  *  *  ****** 

/* run this program using the console pauser or add your own getch,  **  *   **  ****    or input loop */

int main(int argc, char *argv[]) {
 * * ****  **  *  * ** *** a;
* ***   **  *  ****** * **  *   b;
   *** * * *       * ***** * *   c;
 * *** **   *  *  * **  * ** * d;
***   ** * * * *  ** ***** * *     e;
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    ***    ** **** **** = getchar();
******  *** **** **      *  ** = a+3;
  * ****   ** ***  * *** ****** *** ** 
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 *  **  *   **   * * ***      = b+3;
  *****   ****  * **    *  **  
*** *  *** * *    ***    = getchar();
* ***** *** ****   ***  *   * ***  = c+3;
  ******      ** * **    * *  **  *
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** ** **  *      * ***   *  = d+3;
*** *****   *** ****** *   ** *** *   
* *  ***  ****  * *  * = getchar();
*** *  * *    * ** * * **  * = e+3;
 *  ******   * *** ** ** * *  *  ** 
** **   ******   *    **** *  * * **** * ** * * * *  *     * ***
    *  * **** ** *** * **    *** * *   *  *****  * ** ** &a, &b, &c, &d,   ****
    ****  ***    ** **  
**** * **     **   *  *  ** the message how??
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****** *   * * * *  * *   * *****  * ** *  *** * * a, b, c, d, e);
   **  ***  *   ***     
******* **   ***       ***  *   0;
}
100/100 answered by (281 points)
edited by
0 0
Your program receives only 2 characters, and it doesn't move characters' positions.

Try to make it receive 5 characters, and move their positions forward by 3.
commented by (5.9k points)
0 0
This exercise expects only 'hello'. However, your code has.....

printf("Put the words you want to decode:");

Kindly consider delete this part :)
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
 ****  ***    *  *     * 
* *    *  * **** **  

int   **   *  char    * {
/*
 **     * *  */

**   ** 

 * **  **  ***  ** ***  * **** ***  ***  *  *** *******
a = a+3;
b = **
c =   
d = d+3;
e = ***

**** the   **   * 
***** * *  *   * ****  * *
 ** *  ****   *** ** *    ** *   * 

 * *   *  **  ****  **
         * *   *   **   *   *  **    0;
}
100/100 answered by (273 points)
edited by
0 0
prog.c:28:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:32:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:32:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
0 0
Your program can end at
  
    return 0;
}
------------------------------------------
You don't need to put

INPUT

ebiil

OUTPUT

hello
commented by (5.9k points)
0 0
Case 0: Correct output
Case 1: Wrong output
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
  **  *  **  *   * *
* **    ** * **   * *

/* run this *  *    * the ***   * * or add your own * * *   ** * * **  **   *   or *  *     */

int **    ** * char *      {
 *     *    *  int num,  ** *
*  *      * *  *    *  * ** 
   **  *** ** 
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* *  **    *   ** for ** = * *   *  ** * 
{
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******      * ** if ****  ** * *  
  *****  ** *   *  * =  **      *  
* ***      *   **    * ***
}
   ***** ** *    ****     * **  ** **  **
 * *  * ** *    * 0;
50/100 answered by (252 points)
0 0
prog.c: In function 'main':
prog.c:19:2: error: expected declaration or statement at end of input
  return 0;
  ^~~~~~
commented by (4.3k points)
0 0
Great job using an array and a loop. There are two mistakes found in your code. Please check
1.     printf("\n\n%s", code);  <--- in order to make it match the fixed output '\n\n' should be deleted
2.     At the end of your code, there's something missing.
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
*   *   **   **  

*** *  * **    * * **
 
*           ****  *   **  **** *  *     **   ***  *   ****      * ****      * ** * **     *

***  *  **  *   *       
 
***   **     * *

**   *  * *    **
*
* ** ** ** *     * *    * ***** **   * *   * *  *   **    * **  *** **  *  *
*
* =    **
*
   b + *

  * = c +  

*  = d +  
 
* *      *

 ******   **  ***  *  *      *  *   *    *

 ***  **
100/100 answered by (268 points)
0 0
It's correct lol you can't judge me
commented by (268 points)
0 0
Well, that's because your output doesn't match with the fixed answer. Please take a look at this
printf("%c%c%c%c%c\n", a1, b1, c1, d1, e1);

Hint: You should delete something  :)

By the way, great job.
commented by (5.9k points)
0 0
printf("%c%c%c%c%c", a1, b1, c1, d1, e1);

How's that?
commented by (268 points)
0 0
That's correct.
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
 * * *  **** ** **
** * *    ** * *** ****

int ** * argc, char *      {
* *** *** ** * * char *     
  *   *  **  ** char * ** *
 *  *  *     ***  * char ** 
*      **** **  char   * * *
 *   *        *  char **  
* ** **  ***** 
 **  *     ***   **  * **     ***  input the letter to *   ** *   
 *  *  * *  **   
**  ***** ***  * *  *   *  ** *   * **   * *   *  ** *** *  **     *   * *  **** * * ** *** *****  *  **
  **    *   *  * *  = *  * + 3;
 * **** **  **   * * =  *  + 3;
*** ***** *  **  ***   =   ** + 3;
  **** *    **   letterc = ***   + 3;
 * * *     ** *  *   =    *** + 3;
** *   *   *** * 
****** *  ** * ** ****** ****   * * *** **  ** **    ***  *  **   *     * *  *
  * *  * *  ** 
 ****    * *  ** return 0;
}
100/100 answered
reshown by
0 0
-----------Re-judge-----------
Case 0: Wrong output
commented by (4.3k points)
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     hello

Anyway, great job. Full marks.
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
   *  ***   **** ***  *
 ***** *   ****  ** *** 

int   *    argc, char *argv[]) {
  **    ** **** char   ***
 *   *   ** *  char letteri;
*** *  *  ****** char  *  
 *  * *   **   * char   ***
** * * ** **** char *   
******** * * *   * 
  *     *** *    *  ** ***  * * input the letter to encode:   * *   * **
 **  *  ***  * * *   
 * ** * **     *   ** * *   **  * ********   *      * *  ** * * * *  *    *  * * * *  * *   **  *** ***
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  * * * *  **    *** * * +3;
**      * * ** *      *** +3;
 *** * *    *  
   ****    ****  
*  **** ** * * *    * * *    ***  * ** * *****     *    *   **    ** *
*  ***    **  ** 
 *       * * * return 0;
}


INPUT
 * *   **   *****
  * * * ** *
OUTPUT
*  *  *  *  * *
100/100 answered by (269 points)
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     hello

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
commented by (5.9k points)
0 0
prog.c:27:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:30:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:30:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
   *  * *    ***  ***  
      * ** ****  **  *

int **** * * argc, char  *  {
 **** * *   * char  ***  *
**  * ** *   **  char  **  *
 ****       ***  char    * **
***** * **  **** char    **
  ** **  ****     char  **
**  **        ** 
** ***  *    *  * **** ***    *  input the *    to *    * ** * *     *
         **  *  
 * *      * *     ***   ** ** *** **   **** ** *  ** ** * *** **   ** * **** * ** ** **       ** ***
  ***    ** * 
    *    ** *** letter = letter + 3;
 ***        ****   **  * = * **  + 3;
 * **   ***   * *  = * *** + 3;
  * *** *  *   *   ***  =  ** *  + 3;
*  * ***   *    *   * =  * * ** + 3;
  ****  * *  *  
   **     * **** *    *   ** ****    *    letter is  * ** ** ***** *   *   ***  * * * **  *  *  
*  ***  * **   **  
 ***       * ** *   return 0;
}

INPUT
*    *****   ** 
** ***   *    ***  
* ** *
*    ***  * *  * *
100/100 answered by (290 points)
reshown by
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     The encrypted letter is hello

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
commented by (5.9k points)
0 0
prog.c:26:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:29:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:29:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
#include  *  *  ****  ** ***

int main(int argc, char *argv[]) {
*** *  **  ** **   ** *  *  * lettera;
***    *   *   * *    ** letterb;
  **   *  ***  ** *   *   * ** letterc;
**** *   ***  * **   * * **  letterd;
  ** * **  * *** **** *  *   *** * lettere;
 *     * ** ** ** * *  
  **** ** *   * *  ******    * **** *  *  * * %c %c %c    **  ** ** * ***  *** ****  **    **  * **** * ** * *    ***    *  *  
  ***** * **  ***   * *  *  = lettera + 3;
***  * *   ***** * **** ** * ** * * = letterb + 3;
 ** *** ***  **   * ******** * = letterc + 3;
    **   ** ***  *** **** ** = letterd + 3;
     ** **   * ***  **   ***** *  = lettere + 3;
* **    *   **** *  * *   **   *  * ***  *  * 
 * ** *    ** ****    * * * * *  *  * * %c %c %c     * *** *    *    letterb, ***  * * *  ****
  * **  * *    ****  *   ***
 *  *  * *    ** *    ** * *    0;
}

**** *
*   
* ***** *
  *      
//hello
100/100 answered by (271 points)
edited by
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: e b i i l
     h e l l o

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
commented by (5.9k points)
0 0
prog.c:25:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:28:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:28:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:10:5: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
     scanf("%c %c %c %c %c", &lettera, &letterb, &letterc, &letterd, &lettere);
     ^~~~~
prog.c:10:5: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:10:5: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:17:5: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
     printf("%c %c %c %c %c", lettera, letterb, letterc, letterd, lettere);
     ^~~~~~
prog.c:17:5: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:17:5: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
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