3 like 0 dislike
9.3k views

You have received an encrypted message from Julius Caesar-- the message is ebiil.  You are asked to decipher the message in order to understand what Caesar trying to say to you.

Hint

Luckily, Caesar has given you a hint, he says: 'I, myself, encoded the message by shifting every word backwards by 3.' 

Solution

Write a program that receives 5 characters 'ebiil'. Then decode those characters into 5 new characters.

Example

#include <stdio.h>

int main(int argc, char *argv[]) {


	char a;
    	char b;
	 	
	scanf("%c%c", &a, &b);
	
	//decode the message how??
	
	printf("%c%c", a,b);
	
	return 0;
}

Input

ebiil

 

 

 

 

 

 

 

 

 

 

Output

hello

** REMEMBER ** 
This is an online-compiler, don't put anything except the codes. If you want to make a comment, please use // or /* */

[Exercise] Coding (C) - asked in Chapter 2: Syntax structure of the C language by (5.9k points)
ID: 26955 - Available when: Unlimited - Due to: Unlimited

edited by | 9.3k views

22 Answers

0 like 0 dislike
Hidden content!
*** * * **

int * * argc, char ** {
* ** * * * * **** */

* ****** * * int number;
* * ** * * char a;
* *** ***** * ** * b;
* * **** * **** *** * * * *** c;
***** ** * *** * * * * d;
** ***** ******** * * * e;
** **** * *** *
* * * * *** * forgert how to shift word *** * *****
* *** * * *** **** * ** *** ** * * * * ** * *** ** * ****
** *** * ****
* * *** ** * * **** the message how??
** **
**** * * * * **** ** * ** ** ** * ** *****
*
** **** * return 0;
}
100/100 answered by (449 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
0 0
Case 0: Correct output
Case 1: Wrong output
0 like 0 dislike
Hidden content!
* *** ****** ** *** * *
*
* ** * * * * ** ** {

* * ***
= ** *
* * * *
** = **
* = ***
= ** *

= ***
* = *
* =
* =

* *****
* * *
*** * *
** **
* **

** * * * * * **
*
100/100 answered by (153 points)
0 0
Case 0: Correct output
Case 1: Wrong output
1 like 0 dislike
Hidden content!
#include ** * * ***
#include **** * *** * **

/* run this program using the console pauser or add your own getch, * ** * *** * ** or input loop */

int main(int argc, char *argv[]) {
** ***** * *** * * *** ** a;
*** ** *** ** * * * * b;
** * * ** **** * * * **** * c;
** *** ** ** * * ***** d;
** * * **** ** **** * * * * * e;
** ***** ** *
* *** ** * *** *** * * * * the words you want to ** ***
* ** * * ** ***
* ***** ***** * = getchar();
* **** * * * *** *** = a+3;
* * **** * ** *****
** * ** *** ** *** * * = getchar();
* * ** ** * **** ** = b+3;
** * *** ** *** ** ** **
** *** * * *** ** ** = getchar();
* ** * ****** ** ** * = c+3;
* *** ** ** *** * *** *** *
* *** * * * ** = getchar();
* ** * * ** * ** * ** = d+3;
* * * * ********** *** ** * ***
* *** **** * * ** * = getchar();
* *** * ** ** ********* = e+3;
** ** * *** ** *** * ** ** *
** **** * * * * * *** * * **** * ** ** * ****
** ** * * * *** * * * * *** ** ** * ****** ** &a, &b, &c, &d, ***
*** *** * * * ** *
** ** ******** * * * the message how??
* ** **** * * *
* ** * ****** **** ** ** * ** * ** * a, b, c, d, e);
** * * ****** ** **
* * * * ** * ** * * ** **** 0;
}
100/100 answered by (281 points)
edited by
0 0
Your program receives only 2 characters, and it doesn't move characters' positions.

Try to make it receive 5 characters, and move their positions forward by 3.
0 0
This exercise expects only 'hello'. However, your code has.....

printf("Put the words you want to decode:");

Kindly consider delete this part :)
1 like 0 dislike
Hidden content!
** ******
* ** ****

int *** *** * ** char * * *** {
/*
* ** * */

* ****

*** * ** * ****** *** * ** ** * ***** * * ** **** * **
a = a+3;
b = **
c = *
d = d+3;
e =

** * * the ***** ****
* **** ** ** ***
* * * * * *** * * * * ** * **

* * ** *** ***
* * * ** * * * ** ** 0;
}
100/100 answered by (273 points)
edited by
0 0
prog.c:28:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:32:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:32:1: error: unknown type name 'OUTPUT'
0 0
Your program can end at
  
    return 0;
}
------------------------------------------
You don't need to put

INPUT

ebiil

OUTPUT

hello
0 0
Case 0: Correct output
Case 1: Wrong output
1 like 0 dislike
Hidden content!
* * ****** * *
** * * * ** * ***** *

/* run this ** * *** the ***** * ** or add your own * * * * ****** * * or * */

int *** * * *** char * {
* ** * * * int num, **
* **** * ** * * **** *
** ** *
* * * *** * ** * * *** *** *
** ** *** ** for * = ** ****** ** *
{
*** * * ** * * = * * *****
* ** * ** if * * **** **
* * * * * ** * ** = * *** ** *
* ***** * * * *
}
**** *** * * * * ** *** * *
**** ** * * * 0;
50/100 answered by (252 points)
0 0
prog.c: In function 'main':
prog.c:19:2: error: expected declaration or statement at end of input
  return 0;
  ^~~~~~
0 0
Great job using an array and a loop. There are two mistakes found in your code. Please check
1.     printf("\n\n%s", code);  <--- in order to make it match the fixed output '\n\n' should be deleted
2.     At the end of your code, there's something missing.
1 like 0 dislike
Hidden content!
*** * ** * * * **

* * * ** ** *

** * * * ** * * * * ** * **** ** * ** * * * * * *

* * ****

** * * * *

*** ** * *

* * *** * *** * * ** ** * * ** ** *** * * *** * ***

* = * *

b + *

* = c +

= d +
*
* * * **
*
** * * * * * * * ** * ** ** **

* ** *

*
100/100 answered by (268 points)
0 0
It's correct lol you can't judge me
0 0
Well, that's because your output doesn't match with the fixed answer. Please take a look at this
printf("%c%c%c%c%c\n", a1, b1, c1, d1, e1);

Hint: You should delete something  :)

By the way, great job.
0 0
printf("%c%c%c%c%c", a1, b1, c1, d1, e1);

How's that?
0 0
That's correct.
1 like 0 dislike
Hidden content!
** ** * *** ***
***** * ****** ** ** ***

int * ** argc, char ** * {
* * ** * char ****
* * * * * ** * char * * *
* ** *** * char ****
* * *** **** * char **
* *** *** * char ** *
* ***** * ** *
* **** *** * ** ** * ** input the letter to * ** * * **
*** ** *
* * * * * *** * *** *** * * * * * ** *** *** ****** * * * ** * *** **
** *** * ** * * *** = *** + 3;
*** *** ***** = * * * + 3;
* ***** * * ** * = *** + 3;
** * * * letterc = * + 3;
* ******* * **** ** = *** + 3;
* *** * *
* *** ** ***** * ** ** ** * *** *** * *
* * * *
*** ** **** return 0;
}
100/100 answered
reshown by
0 0
-----------Re-judge-----------
Case 0: Wrong output
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     hello

Anyway, great job. Full marks.
1 like 0 dislike
Hidden content!
** * * ** ****
* * *** ****** ***

int * * argc, char *argv[]) {
** * * * ** char ***
* * * * * char letteri;
* * * ** * * ** char ****
** ** * * *** * * char * **
** * ** char ***
* *** * *
** * * ** * ** * *** input the letter to encode: * * ** *
* ** ******
**** * *** ** * * * *** * * ** ** * *** * * ** * * * * * **** ******
** * * * *** * *** +3;
* * * * * * ***** ** +3;
** * ** ** *** ** +3;
** * * *** * * ***** ** +3;
* * ***** * * * * +3;
** * ** * *
** ** **
* * * *** * * ***** * * * *** * **** **** *** * *
* * * * ***
****** * * ** return 0;
}


INPUT
*** * * * * * *
* * * * ****
OUTPUT
**** * * **
100/100 answered by (269 points)
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     hello

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
0 0
prog.c:27:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:30:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:30:1: error: unknown type name 'OUTPUT'
1 like 0 dislike
Hidden content!
** ** * * * ** *
* * ** *** *

int * *** argc, char ** {
** ** ** ** * * char * ***
* ** * * * char *** *
* *** ** ** char *
** ** * char *
* * * char ***
** * * ** * *
*** * *** * * * * * ** input the * to **** * * * *
**** *** **
** ** ** * * * * * * * * * *** * * * * * *** *** * * ** * * **** ** * ** *** * ***
* * **
* * * ** *** letter = letter + 3;
**** * * * * ** = * + 3;
* ** * ** = * + 3;
*** ** * ** ****** * = * + 3;
** *** *** * * * = * + 3;
* ** * ** **
** ** ** * * **** * * ** * ***** letter is *** * ** * * ** *** * **
* * ** * **
* ** ** return 0;
}

INPUT
* **** *** * **
***** **
*
* * **** * ***
100/100 answered by (290 points)
reshown by
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     The encrypted letter is hello

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
0 0
prog.c:26:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:29:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:29:1: error: unknown type name 'OUTPUT'
1 like 0 dislike
Hidden content!
#include * *** ** * ** *

int main(int argc, char *argv[]) {
**** * * * * ** * * * ** lettera;
*** * *** * * * letterb;
***** ** * ** ** * * * letterc;
** * * * * *** * *** letterd;
* * * * * **** **** lettere;
* * * * * * * *
* ** ** ** *** * * * ** * *** * %c %c %c ** ** * * * *** * *** ** *** ** * *** *** * *** **
** * * ** ******** * * = lettera + 3;
* ** *** *** ***** ** = letterb + 3;
*** *** ** ** * * ** = letterc + 3;
* ** ** * ****** * ** ** * = letterd + 3;
* * ** * * ** **** * ** * ** = lettere + 3;
** * * * ** ** ** ******* * ** ***
**** ** * * * * * ** ** ** ** *** * %c %c %c * * ** ** letterb, * *** *** **
** * **** * *** ******
*** *** * * **** * ***** * * 0;
}

**
**
*** * * * ** *
* *
//hello
100/100 answered by (271 points)
edited by
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: e b i i l
     h e l l o

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
0 0
prog.c:25:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:28:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:28:1: error: unknown type name 'OUTPUT'
0 0
prog.c: In function 'main':
prog.c:10:5: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
     scanf("%c %c %c %c %c", &lettera, &letterb, &letterc, &letterd, &lettere);
     ^~~~~
prog.c:10:5: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:10:5: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:17:5: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
     printf("%c %c %c %c %c", lettera, letterb, letterc, letterd, lettere);
     ^~~~~~
prog.c:17:5: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:17:5: note: include '<stdio.h>' or provide a declaration of 'printf'
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:162.159.115.42
©2016-2026

Related questions

0 like 0 dislike
2 answers
[Normal] Essay (Open question) - asked Dec 12, 2017 in Chapter 2: Syntax structure of the C language by 許哲瑋 (449 points)
ID: 37081 - Available when: Unlimited - Due to: Unlimited
| 1.3k views
12,783 questions
183,442 answers
172,219 comments
4,824 users