[Exercise 03] Caesar Cipher Decoder

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You have received an encrypted message from Julius Caesar-- the message is ebiil.  You are asked to decipher the message in order to understand what Caesar trying to say to you.

Hint

Luckily, Caesar has given you a hint, he says: 'I, myself, encoded the message by shifting every word backwards by 3.' 

Solution

Write a program that receives 5 characters 'ebiil'. Then decode those characters into 5 new characters.

Example

#include <stdio.h>

int main(int argc, char *argv[]) {


	char a;
    	char b;
	 	
	scanf("%c%c", &a, &b);
	
	//decode the message how??
	
	printf("%c%c", a,b);
	
	return 0;
}

Input

ebiil

 

 

 

 

 

 

 

 

 

 

Output

hello

** REMEMBER ** 
This is an online-compiler, don't put anything except the codes. If you want to make a comment, please use // or /* */

[Exercise] Coding (C) - asked in Chapter 2: Syntax structure of the C language by (5.9k points)
ID: 26955 - Available when: Unlimited - Due to: Unlimited
edited by | 6.5k views

22 Answers

0 like 0 dislike 
Hidden content!
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*  **  ** **  **   return 0;
}
100/100 answered by (449 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
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100/100 answered by (153 points)
0 0
Case 0: Correct output
Case 1: Wrong output
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
#include *  ** *******
#include   *     **  * * 

/* run this program using the console pauser or add your own getch, * *   ******** ***** *** or input loop */

int main(int argc, char *argv[]) {
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}
100/100 answered by (281 points)
edited by
0 0
Your program receives only 2 characters, and it doesn't move characters' positions.

Try to make it receive 5 characters, and move their positions forward by 3.
commented by (5.9k points)
0 0
This exercise expects only 'hello'. However, your code has.....

printf("Put the words you want to decode:");

Kindly consider delete this part :)
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
* *  *** * *** ** 
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int         char  *  ** {
/*
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a = a+3;
b = **
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* *** ****     * ****
**     *  ** * * * ****    *  * 0;
}
100/100 answered by (273 points)
edited by
0 0
prog.c:28:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:32:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:32:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
0 0
Your program can end at
  
    return 0;
}
------------------------------------------
You don't need to put

INPUT

ebiil

OUTPUT

hello
commented by (5.9k points)
0 0
Case 0: Correct output
Case 1: Wrong output
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
** * **   **   * * *** 
******    * * **  ******   

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*   **  **          * ** * * ** *   * *  * * *  *
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50/100 answered by (252 points)
0 0
prog.c: In function 'main':
prog.c:19:2: error: expected declaration or statement at end of input
  return 0;
  ^~~~~~
commented by (4.3k points)
0 0
Great job using an array and a loop. There are two mistakes found in your code. Please check
1.     printf("\n\n%s", code);  <--- in order to make it match the fixed output '\n\n' should be deleted
2.     At the end of your code, there's something missing.
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
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*
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* = d + **
 
* * *     
 
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***  * 
*
100/100 answered by (268 points)
0 0
It's correct lol you can't judge me
commented by (268 points)
0 0
Well, that's because your output doesn't match with the fixed answer. Please take a look at this
printf("%c%c%c%c%c\n", a1, b1, c1, d1, e1);

Hint: You should delete something  :)

By the way, great job.
commented by (5.9k points)
0 0
printf("%c%c%c%c%c", a1, b1, c1, d1, e1);

How's that?
commented by (268 points)
0 0
That's correct.
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
**** * *  *** **  *  ** 
** *  *     **  ** *  *

int  ***** argc, char      * {
   *    * *  char  * 
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*  *    *    * *   char   ** 
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*    **   * * ** 
**  *** * *    * *  *** * **    input the letter to *    *** * * *
* **  * ** 
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** **    * *    ** ** =    **  + 3;
* * * *      letterc =  *    + 3;
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* * *     *  **     **  *   *  * **** ***   ***   *    ***   *   *  *  *  
   *  * *  **  
*  * *  *   * ** return 0;
}
100/100 answered
reshown by
0 0
-----------Re-judge-----------
Case 0: Wrong output
commented by (4.3k points)
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     hello

Anyway, great job. Full marks.
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
**      **  *   *** * *
 *** * *      *** * * * 

int  *** argc, char *argv[]) {
 ** *   ***   ** char    
 ****   ** * *  char letteri;
** ** * *  ** char  * * 
 ** ** *  * * * char  ***
****  *     * * char ** 
* * *   * ***  *  
* ** ****** ****  *   * *  input the letter to encode: **  ***** ***    
* *** **   * * 
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**   * * ***   *  ** *** +3;
*** **    *** ** * *****     +3;
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*    *  *  * * **  
   ***  **      return 0;
}


INPUT
*** **  ** ** * 
* *      * ***
OUTPUT
   * **  *   **  **  *
100/100 answered by (269 points)
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     hello

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
commented by (5.9k points)
0 0
prog.c:27:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:30:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:30:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
** **    * ** **   
*** * **  ** *   ***    

int     argc, char  *  *  {
 ****    * * * char * *   
  *  *  * *  *  char **** * *
     ** ** ** *    char   *    
*  *    **   char * **
*  **     * * **   char * ** 
 *    **** **   ** 
     ***  *   * ***  * *** ** input the **   * to  * * *******   *   ** 
  **   **  *   
*****   *  * ** ** **** *     *** ** *  ***** ** *** *** **   **  **  * * ****   * ** *   **  ** ** ** *
* * *    *  * 
*****      *  *  letter = letter + 3;
**  *   *****      =  * *** + 3;
  **  *  * * *    *** =    + 3;
**** * *    *  **      =  ****  + 3;
**  * **    * *** *****  = * * *  + 3;
          ** * 
 ** * *** *  **  *   **  *****  ** * * *** letter is *  **  **** *   * * * ***   ****  * **  ** **  
****** ** *     *  
*  *   ******* return 0;
}

INPUT
* ****  *****   * * *
 ****** ****  * 
  ** 
*** ****** ** * *
100/100 answered by (290 points)
reshown by
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     The encrypted letter is hello

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
commented by (5.9k points)
0 0
prog.c:26:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:29:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:29:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
#include *  *   *   *** *

int main(int argc, char *argv[]) {
 *  *  * * ******   ** ** ** lettera;
  *****  ** *   **   *      letterb;
 * ***** * ***   *     **   ** letterc;
*  *        * *** **   ** **  letterd;
**** * *    ** * * *   ** **   lettere;
  * ****   *   * *** ** 
**   ***  ** ****** *     ** ** %c %c %c * *         ***   ***   ***  **      *  * * * * *** ** ***     * *    * 
**   *****  * *   * **  *  *  *  = lettera + 3;
**  *  **  *  ******  *    **  = letterb + 3;
   **** ***  * *  * **** **   * *** = letterc + 3;
* ****     *** * **    *  *** *   * = letterd + 3;
  *      *    * ********** * = lettere + 3;
 *** * *  * * *  * **      ***   * *  ***
   *** * * **   *    * * ****   * *    * *** *   %c %c %c   ****    *     * letterb,    * **    *   *
** * *   ***  *    **  ** ***
***     ** **   *   ********  *** 0;
}

** *  *
 * * 
*****    **  
 *****
//hello
100/100 answered by (271 points)
edited by
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: e b i i l
     h e l l o

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
commented by (5.9k points)
0 0
prog.c:25:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:28:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:28:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:10:5: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
     scanf("%c %c %c %c %c", &lettera, &letterb, &letterc, &letterd, &lettere);
     ^~~~~
prog.c:10:5: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:10:5: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:17:5: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
     printf("%c %c %c %c %c", lettera, letterb, letterc, letterd, lettere);
     ^~~~~~
prog.c:17:5: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:17:5: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
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