[Exercise 03] Caesar Cipher Decoder

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You have received an encrypted message from Julius Caesar-- the message is ebiil.  You are asked to decipher the message in order to understand what Caesar trying to say to you.

Hint

Luckily, Caesar has given you a hint, he says: 'I, myself, encoded the message by shifting every word backwards by 3.' 

Solution

Write a program that receives 5 characters 'ebiil'. Then decode those characters into 5 new characters.

Example

#include <stdio.h>

int main(int argc, char *argv[]) {


	char a;
    	char b;
	 	
	scanf("%c%c", &a, &b);
	
	//decode the message how??
	
	printf("%c%c", a,b);
	
	return 0;
}

Input

ebiil

 

 

 

 

 

 

 

 

 

 

Output

hello

** REMEMBER ** 
This is an online-compiler, don't put anything except the codes. If you want to make a comment, please use // or /* */

[Exercise] Coding (C) - asked in Chapter 2: Syntax structure of the C language by (5.9k points)
ID: 26955 - Available when: Unlimited - Due to: Unlimited
edited by | 5.5k views

22 Answers

0 like 0 dislike 
Hidden content!
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int **** argc, char *  *   {
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}
100/100 answered by (449 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
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100/100 answered by (153 points)
0 0
Case 0: Correct output
Case 1: Wrong output
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
#include    *  **  ***
#include * *** *  ** ** 

/* run this program using the console pauser or add your own getch, *     * *  ***  ***    or input loop */

int main(int argc, char *argv[]) {
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*  ** ****    *  *****    * **** 0;
}
100/100 answered by (281 points)
edited by
0 0
Your program receives only 2 characters, and it doesn't move characters' positions.

Try to make it receive 5 characters, and move their positions forward by 3.
commented by (5.9k points)
0 0
This exercise expects only 'hello'. However, your code has.....

printf("Put the words you want to decode:");

Kindly consider delete this part :)
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
   ***      **** **   ***
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int  **   * char *    {
/*
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*** *   ** * 

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b =   
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* ****** **** * * ***** ***  0;
}
100/100 answered by (273 points)
edited by
0 0
prog.c:28:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:32:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:32:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
0 0
Your program can end at
  
    return 0;
}
------------------------------------------
You don't need to put

INPUT

ebiil

OUTPUT

hello
commented by (5.9k points)
0 0
Case 0: Correct output
Case 1: Wrong output
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
* *  * ***  ** ** * 
 *    *  **** **   

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int   *      * char ***   {
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 ***     * *  * * 0;
50/100 answered by (252 points)
0 0
prog.c: In function 'main':
prog.c:19:2: error: expected declaration or statement at end of input
  return 0;
  ^~~~~~
commented by (4.3k points)
0 0
Great job using an array and a loop. There are two mistakes found in your code. Please check
1.     printf("\n\n%s", code);  <--- in order to make it match the fixed output '\n\n' should be deleted
2.     At the end of your code, there's something missing.
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
*  * * * **     ** *
*
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*  =  * *
*
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* = d + *

   * *  *

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*
****  *
 
 *
100/100 answered by (268 points)
0 0
It's correct lol you can't judge me
commented by (268 points)
0 0
Well, that's because your output doesn't match with the fixed answer. Please take a look at this
printf("%c%c%c%c%c\n", a1, b1, c1, d1, e1);

Hint: You should delete something  :)

By the way, great job.
commented by (5.9k points)
0 0
printf("%c%c%c%c%c", a1, b1, c1, d1, e1);

How's that?
commented by (268 points)
0 0
That's correct.
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
   ** *********  ** **
*  **    *  *  *   * * ** *

int *    argc, char   * * {
* * ** *  ***  char  ***    
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     * *   * *  *  *  *   input the letter to *   *     * 
*** **    * ** * 
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* * ** *  *    * * ** =  *** * + 3;
** ** *  *     *** *  = *** + 3;
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   *** * *   *  * ** *   **   ****  ****  **  ** * **** * **     ** *
 *   ****     * *   
* ***  * ***  return 0;
}
100/100 answered
reshown by
0 0
-----------Re-judge-----------
Case 0: Wrong output
commented by (4.3k points)
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     hello

Anyway, great job. Full marks.
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
  **** * *    * ** *  ** 
*     *   *****  **      

int     * * argc, char *argv[]) {
* *     * * * *  char    ***
   *   ** ** * char letteri;
 **  **   ** * * * char   *  * 
* **   *  *** char   *   
 *    * *   char * ** *
 *** *   * * ** 
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* * * *  **    * * * ** +3;
* *   **  * * ***  * ****   ** +3;
* ***   * *    
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           * return 0;
}


INPUT
*   *  ** * **   
  *    *  * **
OUTPUT
* *** *   *  ** *
100/100 answered by (269 points)
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     hello

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
commented by (5.9k points)
0 0
prog.c:27:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:30:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:30:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
   * *     ** ****   
* ***    *** * *   *

int * * *   argc, char   ** {
*  *** *     *  char     * *
** *  * * ** * char  **
* * **   ** ** char ****   
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  *       ***  
* ** * * *** *  * * ** * *  *  input the  *** to  * **  ** *  ****  * 
     * ** ****   
****   ***** *  *  **     *     * ** ****  *  *  ***   ***  *   * **   *     *      * * ** **    *   **  *******
   *      * ** 
 **     **    letter = letter + 3;
* *   *   ****** *   * * = * ** + 3;
 ***  **    *   ** ** ** =   *** + 3;
* *    *   * * *  * * *   = *  *** + 3;
    * * * *      = * ** + 3;
   **** *** * *  
*** * *  * *  ******   * ** **  * * letter is *  **   **  * * * * ** * * ** * *    
 *  ***   * *  * 
  **   ***  * return 0;
}

INPUT
 ***** *******  *
* * *     ** 
*
 **  *  * *   *  ***
100/100 answered by (290 points)
reshown by
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     The encrypted letter is hello

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
commented by (5.9k points)
0 0
prog.c:26:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:29:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:29:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
#include  **** *****   

int main(int argc, char *argv[]) {
* ** *  *  *   *** *  *  **    lettera;
**** * **   ******  *     **   *** letterb;
**  *  ******     ******* ** * ** letterc;
* *   ** ** * *** * * **           letterd;
** *** ******    ****  **    * lettere;
 **   *  ** ** ***** ***  
  **  *  * ** ** ** ***     * ** %c %c %c * *  ****   **  ***    * *  **      **   * * ** * * **  ** * * ***  * 
****  * ** **  * *  ** ***  = lettera + 3;
 **        ** * * **    ****  = letterb + 3;
* ** *** ******   *  **   * = letterc + 3;
 ** *    ***** *   **    **  ***   = letterd + 3;
*** *    *  *  * **   *  ** = lettere + 3;
** ***   *  **** **** * * * *  * * **  *** *    ****      
  ******* *** ***   * * ***   * *   * %c %c %c ** *   *    ****   letterb, **       **** *  *
 *  * * ******* ***** **   **   *
 * ** *  * * *   *   ** *  * ** 0;
}

 * **
** * *
  * ***   * **
*    
//hello
100/100 answered by (271 points)
edited by
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: e b i i l
     h e l l o

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
commented by (5.9k points)
0 0
prog.c:25:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:28:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:28:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:10:5: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
     scanf("%c %c %c %c %c", &lettera, &letterb, &letterc, &letterd, &lettere);
     ^~~~~
prog.c:10:5: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:10:5: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:17:5: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
     printf("%c %c %c %c %c", lettera, letterb, letterc, letterd, lettere);
     ^~~~~~
prog.c:17:5: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:17:5: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
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