[Exercise 03] Caesar Cipher Decoder

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You have received an encrypted message from Julius Caesar-- the message is ebiil.  You are asked to decipher the message in order to understand what Caesar trying to say to you.

Hint

Luckily, Caesar has given you a hint, he says: 'I, myself, encoded the message by shifting every word backwards by 3.' 

Solution

Write a program that receives 5 characters 'ebiil'. Then decode those characters into 5 new characters.

Example

#include <stdio.h>

int main(int argc, char *argv[]) {


	char a;
    	char b;
	 	
	scanf("%c%c", &a, &b);
	
	//decode the message how??
	
	printf("%c%c", a,b);
	
	return 0;
}

Input

ebiil

 

 

 

 

 

 

 

 

 

 

Output

hello

** REMEMBER ** 
This is an online-compiler, don't put anything except the codes. If you want to make a comment, please use // or /* */

[Exercise] Coding (C) - asked in Chapter 2: Syntax structure of the C language by (5.9k points)
ID: 26955 - Available when: Unlimited - Due to: Unlimited
edited by | 10k views

22 Answers

0 like 0 dislike 
Hidden content!
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* ** *    **   * return 0;
}
100/100 answered by (449 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
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100/100 answered by (153 points)
0 0
Case 0: Correct output
Case 1: Wrong output
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
#include *****  ** ***   * 
#include  *** * * *      * 

/* run this program using the console pauser or add your own getch, *   **** ******* *  *     or input loop */

int main(int argc, char *argv[]) {
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* *  **  ** * **  **** *      = a+3;
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}
100/100 answered by (281 points)
edited by
0 0
Your program receives only 2 characters, and it doesn't move characters' positions.

Try to make it receive 5 characters, and move their positions forward by 3.
commented by (5.9k points)
0 0
This exercise expects only 'hello'. However, your code has.....

printf("Put the words you want to decode:");

Kindly consider delete this part :)
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
   **    ** *  *  * ***
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int  *** *  ** char  *  {
/*
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**   ** * *    * **   * 0;
}
100/100 answered by (273 points)
edited by
0 0
prog.c:28:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:32:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:32:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
0 0
Your program can end at
  
    return 0;
}
------------------------------------------
You don't need to put

INPUT

ebiil

OUTPUT

hello
commented by (5.9k points)
0 0
Case 0: Correct output
Case 1: Wrong output
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
*    ****    ** * **
** * ** *  * *** *** * * ** 

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}
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** * **  *   *   0;
50/100 answered by (252 points)
0 0
prog.c: In function 'main':
prog.c:19:2: error: expected declaration or statement at end of input
  return 0;
  ^~~~~~
commented by (4.3k points)
0 0
Great job using an array and a loop. There are two mistakes found in your code. Please check
1.     printf("\n\n%s", code);  <--- in order to make it match the fixed output '\n\n' should be deleted
2.     At the end of your code, there's something missing.
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
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*    **  ****   ** * *
*
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**   b + **

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** = d + * 
 
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*
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*
100/100 answered by (268 points)
0 0
It's correct lol you can't judge me
commented by (268 points)
0 0
Well, that's because your output doesn't match with the fixed answer. Please take a look at this
printf("%c%c%c%c%c\n", a1, b1, c1, d1, e1);

Hint: You should delete something  :)

By the way, great job.
commented by (5.9k points)
0 0
printf("%c%c%c%c%c", a1, b1, c1, d1, e1);

How's that?
commented by (268 points)
0 0
That's correct.
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
**  * * ****  **    *  
  *    *   *  ** ** 

int   * **   argc, char *** ** {
  *   **      char *** *
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**  ***  ***       *    ****      input the letter to **      *  **
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* * * * ** **  * letterc = ***   + 3;
*  **   * * *  *   = ****  + 3;
  ** **  *   *  * 
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   *      ** **  
 *** * *  * ** return 0;
}
100/100 answered
reshown by
0 0
-----------Re-judge-----------
Case 0: Wrong output
commented by (4.3k points)
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     hello

Anyway, great job. Full marks.
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
*  *   *****  *   *
   **    * * ********  **

int        argc, char *argv[]) {
  **  *    ****   char *    *
 *** *  *** * char letteri;
 **      *   *** char  * *
   *  *      **  char * ** 
 *** * *  ***   char *  ****
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*   **     ***  * *  **   **  ** ** input the letter to encode: **** * *  * *  *  *
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** **     *      ** **  +3;
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**           * *  *** ***  ** +3;
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**     * * **  
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* *    *** * *  *   *  * * ** * *  * ** *   * ***  ***** * ** ** ** **
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** **   *  *    *  return 0;
}


INPUT
 *     *   *  *  
* ** * **   
OUTPUT
* **   **** **  * * *
100/100 answered by (269 points)
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     hello

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
commented by (5.9k points)
0 0
prog.c:27:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:30:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:30:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
 *    ** **  ****     *  **
 * *    **     ***

int * **  argc, char * ** {
**  * * **** char *    
******** *     char     
*   **   ** * *  char *  *
 **  *  *  *  *  char  **  *
    ***   *  ** char * **** 
 *** *  *  *  *  
*  *  * *  *** *  * **** * **   input the ****  to    * **  ** * *  
** *   *** * * *  
**  *  * *  * ** *  ** *  *  * ***  * * **  **  ** *     * * * **  ** * *      **       * ** ** **** ***  * **
*  ** ***  * * *  
**  **    ** *  letter = letter + 3;
* *  * *   **   ** =   *   + 3;
  **   * *** ** *   **  =  ****** + 3;
 ** *  *  * ** **** = **   + 3;
* ** ***  * *   **   = **  * + 3;
 *** ** **      ***  
 * *    *  ** ** *  **  * * **  * *    letter is *  **  *   *   ** ***   ****   *** *   *  *  **
*   *  * * *  ***   
  *** * ** * return 0;
}

INPUT
** **   * ** **
  ** ** * 
**
*   *   ** *** *
100/100 answered by (290 points)
reshown by
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     The encrypted letter is hello

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
commented by (5.9k points)
0 0
prog.c:26:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:29:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:29:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
#include  ** *  ****  * * * 

int main(int argc, char *argv[]) {
****  ** *     ** * **** * **** lettera;
    **      ** ** ** ** *** ***  letterb;
 ****   **   * **  *  * ***  ****   letterc;
******    *** *   *  ***   * letterd;
  * ****  * * * **        lettere;
****   *****  * ** ** * *  **
 * * * **  ** * ****   ** *   * **  * %c %c %c *  * * * **  *           *  **** **  *   *** * ** * * *  *  **** **  ** 
* *   * **    * * *   *****   ***  = lettera + 3;
   ******  **  ** *  * * *      = letterb + 3;
* ****   ***  *      ********* *  = letterc + 3;
 ** **   *** **     * * ******     = letterd + 3;
*** * * **     *      ** * ***** = lettere + 3;
**  *** ***** ** ** *   *    *   **  **     *  * *     ****
   ***** ***** *    ** *    * * ***** * %c %c %c *****   ***   * letterb,  **** *  * * * *    * 
  *  ** *     *  *      *
 *      * *   ***** * * ** *  0;
}

***  *
* ***   
** ****  *  * 
      
//hello
100/100 answered by (271 points)
edited by
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: e b i i l
     h e l l o

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
commented by (5.9k points)
0 0
prog.c:25:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:28:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:28:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:10:5: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
     scanf("%c %c %c %c %c", &lettera, &letterb, &letterc, &letterd, &lettere);
     ^~~~~
prog.c:10:5: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:10:5: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:17:5: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
     printf("%c %c %c %c %c", lettera, letterb, letterc, letterd, lettere);
     ^~~~~~
prog.c:17:5: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:17:5: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
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