[Exercise 03] Caesar Cipher Decoder

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You have received an encrypted message from Julius Caesar-- the message is ebiil.  You are asked to decipher the message in order to understand what Caesar trying to say to you.

Hint

Luckily, Caesar has given you a hint, he says: 'I, myself, encoded the message by shifting every word backwards by 3.' 

Solution

Write a program that receives 5 characters 'ebiil'. Then decode those characters into 5 new characters.

Example

#include <stdio.h>

int main(int argc, char *argv[]) {


	char a;
    	char b;
	 	
	scanf("%c%c", &a, &b);
	
	//decode the message how??
	
	printf("%c%c", a,b);
	
	return 0;
}

Input

ebiil

 

 

 

 

 

 

 

 

 

 

Output

hello

** REMEMBER ** 
This is an online-compiler, don't put anything except the codes. If you want to make a comment, please use // or /* */

[Exercise] Coding (C) - asked in Chapter 2: Syntax structure of the C language by (5.9k points)
ID: 26955 - Available when: Unlimited - Due to: Unlimited
edited by | 9.7k views

22 Answers

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Hidden content!
* ** **** **   **** 

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* ***   *  *  return 0;
}
100/100 answered by (449 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
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100/100 answered by (153 points)
0 0
Case 0: Correct output
Case 1: Wrong output
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
#include **** * **  **  
#include * *  *   ** *   *

/* run this program using the console pauser or add your own getch,   ***      *********   or input loop */

int main(int argc, char *argv[]) {
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* * ** * ***  ** ***  *  **   * = e+3;
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* * * * * ** **  ** **** * *** *
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}
100/100 answered by (281 points)
edited by
0 0
Your program receives only 2 characters, and it doesn't move characters' positions.

Try to make it receive 5 characters, and move their positions forward by 3.
commented by (5.9k points)
0 0
This exercise expects only 'hello'. However, your code has.....

printf("Put the words you want to decode:");

Kindly consider delete this part :)
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
    **  * *   ** * *
***  *     *   *  *  * 

int ***** * *  char  *   {
/*
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}
100/100 answered by (273 points)
edited by
0 0
prog.c:28:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:32:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:32:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
0 0
Your program can end at
  
    return 0;
}
------------------------------------------
You don't need to put

INPUT

ebiil

OUTPUT

hello
commented by (5.9k points)
0 0
Case 0: Correct output
Case 1: Wrong output
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
**    **  ******  **  
* * **     ** ****   

/* run this **     *   the  *     **** or add your own   *  ** **          * or *  * *   */

int **   * char *    {
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}
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***   * *  * * **   ***  0;
50/100 answered by (252 points)
0 0
prog.c: In function 'main':
prog.c:19:2: error: expected declaration or statement at end of input
  return 0;
  ^~~~~~
commented by (4.3k points)
0 0
Great job using an array and a loop. There are two mistakes found in your code. Please check
1.     printf("\n\n%s", code);  <--- in order to make it match the fixed output '\n\n' should be deleted
2.     At the end of your code, there's something missing.
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
*  *** *  *    *** 

    *  ***  ** * ** * ** **

* *    *       *      * * ** **    * * **    * ** ***** *   *  *  ***    ****  **  
 
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**  =      *
 
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***     *  *   *  *  * ****        *  ** *   

** *  
*
100/100 answered by (268 points)
0 0
It's correct lol you can't judge me
commented by (268 points)
0 0
Well, that's because your output doesn't match with the fixed answer. Please take a look at this
printf("%c%c%c%c%c\n", a1, b1, c1, d1, e1);

Hint: You should delete something  :)

By the way, great job.
commented by (5.9k points)
0 0
printf("%c%c%c%c%c", a1, b1, c1, d1, e1);

How's that?
commented by (268 points)
0 0
That's correct.
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
** **        ** * ***  ** 
**  ***  **      *** * 

int     argc, char  * *** {
**** *   *  *  char  * 
** *  **   **   char     *
* **  *  **** char    
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*** * **** ***   *  char    ** *
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 **     ****  *   * * *  * *  input the letter to ** *  *   
*  **   ** *  
******   * *   ** * ** ***** * * ***** *** *   *   ***** *  *   *  *  *  ** ** *  *    ** * * *   *   *  
  ** *  **      *** = *      + 3;
 *        *  * *      = **  *** + 3;
 ** * * * *** *  ** = *  **  + 3;
 *** * *   *    ** letterc =  ***** + 3;
**   *   ** *** *     * = *   + 3;
     *     *     
 ** *  *  *** *  * ** ***  ** * * * * **** * **  * *  *       ** **  
**** ** *  *    
***  **     **  return 0;
}
100/100 answered
reshown by
0 0
-----------Re-judge-----------
Case 0: Wrong output
commented by (4.3k points)
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     hello

Anyway, great job. Full marks.
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
* *    ***   **   *
 *  * *   **      *    **

int  ****  argc, char *argv[]) {
 ** *           char * **
 *** **  char letteri;
* * * ***  **      char  ** 
**   *   ****** char ** 
 ****  ***    char *    
 **  * *    * 
 * ** * *  ***   *  *  *   *  * input the letter to encode: ** * *    ** * * * *
*    * ***  **   
***     ** **  ****  *  **** *  *     ** *  *  **   ***  *   *      ** * ** ***   ****** * * * * *****       
* *   *    *    *   *  * **  +3;
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* ** * **     *   *  **  +3;
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*     *  * ** 
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** **** *  * 
    **  * **   return 0;
}


INPUT
   **** *   * *   *  *
  ** *** * *    *
OUTPUT
* ***   **   **
100/100 answered by (269 points)
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     hello

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
commented by (5.9k points)
0 0
prog.c:27:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:30:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:30:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
*      * * * *  *****  
 * **     * * * * **

int  *    argc, char  **  * {
 * * *   *** char *  * 
** *    * *** * char *  * 
  *       *****  char   ***
 ***    * *  * * char   ****
* *  ***     *   char *  ***
 * ** **  **   
*** ** *     *  **   *** * **   input the *    to  ***   *  *** ***   
*   ** **** * 
*** * *   * ** **  ** *   ***     *   * *  * *    ** **    * ** **  **     **         *  * ** *   ***
   **   * **  *  
*       *  *  letter = letter + 3;
** **     **             = *   + 3;
****** *  * ****  *  ** = *      + 3;
*  **   * * *  **  **  * = *   + 3;
 **   *   ** * *  ** * * =    * + 3;
  *  *  * *  ** 
 * *     **   * * *****   *    * ** letter is *** * *** **   * * * **  * *   * * **  ** 
****  * * **   ** * 
**** **  ***** * return 0;
}

INPUT
**    **** * * *
 **   **     * 
  *
****  ***  ********
100/100 answered by (290 points)
reshown by
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     The encrypted letter is hello

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
commented by (5.9k points)
0 0
prog.c:26:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:29:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:29:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
#include  ** *    *** **

int main(int argc, char *argv[]) {
    *   *   ** * * **** *  **     **** lettera;
 *   *  * ** *    **  * letterb;
* **   **** **** ***** *** *  letterc;
***** * **    * ** ***   *  *   * letterd;
 *   *** ***** ** ******    *****  lettere;
*    * *  **  *  **** *    **  
** *** *** *  * ***  **  *   ** *  **     %c %c %c * * *****  *    **  **** **  *      * ***     **** ** *** * * * ****  
     *    **** ***   * *** *** = lettera + 3;
 *  * ***  ****     ** *** **** *  = letterb + 3;
 * ** **** * * *** *        = letterc + 3;
  * * ** ***** * ****  **     *  = letterd + 3;
   **    * *** * ***   *   * **  = lettere + 3;
*  **** ***   ***   * *    * ******   **** * * **  *  *** 
 ***  **   **   ** *****   **  *     **       %c %c %c **         **   letterb,  * * *  **** *  ***
*     ** *  **       ** *
     * ** **  ** ***  *  ***  0;
}

* ** 
 * *
**** ** *   
** *  ***
//hello
100/100 answered by (271 points)
edited by
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: e b i i l
     h e l l o

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
commented by (5.9k points)
0 0
prog.c:25:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:28:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:28:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:10:5: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
     scanf("%c %c %c %c %c", &lettera, &letterb, &letterc, &letterd, &lettere);
     ^~~~~
prog.c:10:5: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:10:5: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:17:5: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
     printf("%c %c %c %c %c", lettera, letterb, letterc, letterd, lettere);
     ^~~~~~
prog.c:17:5: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:17:5: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
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