[Exercise 03] Caesar Cipher Decoder

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You have received an encrypted message from Julius Caesar-- the message is ebiil.  You are asked to decipher the message in order to understand what Caesar trying to say to you.

Hint

Luckily, Caesar has given you a hint, he says: 'I, myself, encoded the message by shifting every word backwards by 3.' 

Solution

Write a program that receives 5 characters 'ebiil'. Then decode those characters into 5 new characters.

Example

#include <stdio.h>

int main(int argc, char *argv[]) {


	char a;
    	char b;
	 	
	scanf("%c%c", &a, &b);
	
	//decode the message how??
	
	printf("%c%c", a,b);
	
	return 0;
}

Input

ebiil

 

 

 

 

 

 

 

 

 

 

Output

hello

** REMEMBER ** 
This is an online-compiler, don't put anything except the codes. If you want to make a comment, please use // or /* */

[Exercise] Coding (C) - asked in Chapter 2: Syntax structure of the C language by (5.9k points)
ID: 26955 - Available when: Unlimited - Due to: Unlimited
edited by | 7.9k views

22 Answers

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Hidden content!
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}
100/100 answered by (449 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
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100/100 answered by (153 points)
0 0
Case 0: Correct output
Case 1: Wrong output
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
#include *** *     *
#include * **** *   * *

/* run this program using the console pauser or add your own getch,   * *  ***   ** *  * * * or input loop */

int main(int argc, char *argv[]) {
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*  **   **   **** **
** * *  * * ********  * ***  0;
}
100/100 answered by (281 points)
edited by
0 0
Your program receives only 2 characters, and it doesn't move characters' positions.

Try to make it receive 5 characters, and move their positions forward by 3.
commented by (5.9k points)
0 0
This exercise expects only 'hello'. However, your code has.....

printf("Put the words you want to decode:");

Kindly consider delete this part :)
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
 **     *****  **   *
* **  *    **  *  * * *** *

int   *  **  **** char ****  {
/*
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a = a+3;
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**  *  ****   ***** *  
*  ****** **  * ** *  0;
}
100/100 answered by (273 points)
edited by
0 0
prog.c:28:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:32:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:32:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
0 0
Your program can end at
  
    return 0;
}
------------------------------------------
You don't need to put

INPUT

ebiil

OUTPUT

hello
commented by (5.9k points)
0 0
Case 0: Correct output
Case 1: Wrong output
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
* **  * ****  *   *  
 *   *   ** *  *** * ** * 

/* run this  * * ** the        ** or add your own    *        *  ******  *  *  or  * *** */

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50/100 answered by (252 points)
0 0
prog.c: In function 'main':
prog.c:19:2: error: expected declaration or statement at end of input
  return 0;
  ^~~~~~
commented by (4.3k points)
0 0
Great job using an array and a loop. There are two mistakes found in your code. Please check
1.     printf("\n\n%s", code);  <--- in order to make it match the fixed output '\n\n' should be deleted
2.     At the end of your code, there's something missing.
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
****  * **    *  **    
*
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*    * * *   **    * ** *  *   *  *  *   *   * * * * **** ***** *   *      ***  *
 
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*
         
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*
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100/100 answered by (268 points)
0 0
It's correct lol you can't judge me
commented by (268 points)
0 0
Well, that's because your output doesn't match with the fixed answer. Please take a look at this
printf("%c%c%c%c%c\n", a1, b1, c1, d1, e1);

Hint: You should delete something  :)

By the way, great job.
commented by (5.9k points)
0 0
printf("%c%c%c%c%c", a1, b1, c1, d1, e1);

How's that?
commented by (268 points)
0 0
That's correct.
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
 **      ** *   *     
   *       ***   

int  * ** argc, char    *** {
  * **  *   *** ** char   * **
 ** *  * ***    char *** *
*** * *  *  *  char *  *
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* * * ** *    ** * = *    + 3;
**    **   ** *** **   = ****** + 3;
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* * * *   **  *** letterc = *** + 3;
**    *** * ** * * *** = *  *   + 3;
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 *** *      ***  ** *** * *   * *** * *** **   * *    **      *  ***  * * * *
      **  *    * ** 
   ***    * ** return 0;
}
100/100 answered
reshown by
0 0
-----------Re-judge-----------
Case 0: Wrong output
commented by (4.3k points)
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     hello

Anyway, great job. Full marks.
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
* * *  **  *** * * *     *
  ***** *   **  *** * **

int ** ***  argc, char *argv[]) {
**   *    * * char   * **
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*  *    *****   *** *  * * +3;
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****** *     * **   *   **** +3;
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}


INPUT
    * *** *  ***
 ** ***  * *
OUTPUT
* * *** *****
100/100 answered by (269 points)
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     hello

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
commented by (5.9k points)
0 0
prog.c:27:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:30:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:30:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
* ** ** * *  *  * *  *
 *     * ** *        *  

int  **  * argc, char *** **  {
*   ***** *** char * *  
 **** * * ***  char     **
 **** ** ** * char ** * 
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**  * * ***    char   ** *
 **  *  ** ** 
  *   * *     ** **      input the  *   to ** *  * *  *  *  ** 
* *****  *   * **** 
    * *    * * ******** * ***  * * ** * **    ** * ** **  ***  **    *       **** *  * * **** ****
*****   *****  
**  *    ***** letter = letter + 3;
******     *  ****   *  * = * *** + 3;
*  * *    * *   **** =  ** * + 3;
**     ***  **  **    = **    + 3;
  *   *    *    * *** =  ***  + 3;
 **  *** *  **  * 
******* *  *    *   **  ***  ***  *  * letter is    ** ****   *** ** **  * *** ** *   *  
     *      
*    *  * * * return 0;
}

INPUT
*  * *   ** * *
* *   **  **** 
** *
  *  * **    * *   *
100/100 answered by (290 points)
reshown by
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     The encrypted letter is hello

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
commented by (5.9k points)
0 0
prog.c:26:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:29:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:29:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
#include   **** *     

int main(int argc, char *argv[]) {
* * *   ** ***   * *** **    *  lettera;
*  ** ** ** * *  * * **  ** letterb;
**  *  * *    * **  ****** * * *  letterc;
  * ** * **  ** * ***    * * *   letterd;
* *  **** * *   *****  *  *   ** lettere;
*** ***  ***      *  * *    
**  *    **  *       ** *  **    ****   %c %c %c       *  * *  ** *  *  *  ***  ***    ** ****  * ** *  ****   ** ** ** *** 
 ** **     *  *** *** **     = lettera + 3;
**   **     **** * * *  * *   ** **** = letterb + 3;
*  *  * ***** **   *   ***    = letterc + 3;
  * ********  ** *  ** ** *  ****** = letterd + 3;
 * **  *    * * ** ****** ** * *    = lettere + 3;
 * *    ******   * ****  * *** *    * *  * ***    *
**  * *  ******* ******  *    * ** * * %c %c %c ** *   *     * letterb,  * *      *      *    
* **** * ** * *   **   *  ** 
*   **** ** *   ***** ***  ** ** *   0;
}

  **   
  *  
*  *  * ** *
*  *  
//hello
100/100 answered by (271 points)
edited by
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: e b i i l
     h e l l o

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
commented by (5.9k points)
0 0
prog.c:25:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:28:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:28:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:10:5: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
     scanf("%c %c %c %c %c", &lettera, &letterb, &letterc, &letterd, &lettere);
     ^~~~~
prog.c:10:5: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:10:5: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:17:5: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
     printf("%c %c %c %c %c", lettera, letterb, letterc, letterd, lettere);
     ^~~~~~
prog.c:17:5: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:17:5: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
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