[Exercise 03] Caesar Cipher Decoder

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You have received an encrypted message from Julius Caesar-- the message is ebiil.  You are asked to decipher the message in order to understand what Caesar trying to say to you.

Hint

Luckily, Caesar has given you a hint, he says: 'I, myself, encoded the message by shifting every word backwards by 3.' 

Solution

Write a program that receives 5 characters 'ebiil'. Then decode those characters into 5 new characters.

Example

#include <stdio.h>

int main(int argc, char *argv[]) {


	char a;
    	char b;
	 	
	scanf("%c%c", &a, &b);
	
	//decode the message how??
	
	printf("%c%c", a,b);
	
	return 0;
}

Input

ebiil

 

 

 

 

 

 

 

 

 

 

Output

hello

** REMEMBER ** 
This is an online-compiler, don't put anything except the codes. If you want to make a comment, please use // or /* */

[Exercise] Coding (C) - asked in Chapter 2: Syntax structure of the C language by (5.9k points)
ID: 26955 - Available when: Unlimited - Due to: Unlimited
edited by | 6.7k views

22 Answers

0 like 0 dislike 
Hidden content!
*    *** **   ***    *

int  *  argc, char    * {
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****     * ** return 0;
}
100/100 answered by (449 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
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100/100 answered by (153 points)
0 0
Case 0: Correct output
Case 1: Wrong output
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
#include   **  * * ** ****
#include  *  ***  * **** 

/* run this program using the console pauser or add your own getch,    * *   * *** * * *   or input loop */

int main(int argc, char *argv[]) {
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*    *  *  *      ** *** * *  = a+3;
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**  *  *****   * ***  *  = e+3;
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****     *******       * *  **** 0;
}
100/100 answered by (281 points)
edited by
0 0
Your program receives only 2 characters, and it doesn't move characters' positions.

Try to make it receive 5 characters, and move their positions forward by 3.
commented by (5.9k points)
0 0
This exercise expects only 'hello'. However, your code has.....

printf("Put the words you want to decode:");

Kindly consider delete this part :)
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
*** *  *** **    * * 
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int * ***    * * char * *  * {
/*
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}
100/100 answered by (273 points)
edited by
0 0
prog.c:28:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:32:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:32:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
0 0
Your program can end at
  
    return 0;
}
------------------------------------------
You don't need to put

INPUT

ebiil

OUTPUT

hello
commented by (5.9k points)
0 0
Case 0: Correct output
Case 1: Wrong output
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
   * * ***  **   * *  ***
*** *** *  *  *    *    *

/* run this       * ** the ***      or add your own **  * *  ***   *         *  * or *    ** */

int  **** *    * char **  * {
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}
** **     *     * *   ***  *  *  * * *** ** *  *
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50/100 answered by (252 points)
0 0
prog.c: In function 'main':
prog.c:19:2: error: expected declaration or statement at end of input
  return 0;
  ^~~~~~
commented by (4.3k points)
0 0
Great job using an array and a loop. There are two mistakes found in your code. Please check
1.     printf("\n\n%s", code);  <--- in order to make it match the fixed output '\n\n' should be deleted
2.     At the end of your code, there's something missing.
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
 ****    ****   *   * 
*
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* *  *   *  *      **   ** **   *   *     **  * *    *   *       *  **  * *   *  *

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*
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100/100 answered by (268 points)
0 0
It's correct lol you can't judge me
commented by (268 points)
0 0
Well, that's because your output doesn't match with the fixed answer. Please take a look at this
printf("%c%c%c%c%c\n", a1, b1, c1, d1, e1);

Hint: You should delete something  :)

By the way, great job.
commented by (5.9k points)
0 0
printf("%c%c%c%c%c", a1, b1, c1, d1, e1);

How's that?
commented by (268 points)
0 0
That's correct.
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
* *      **  *  *** *   
**  * * ** ****       

int   *  ** argc, char  ****  {
 *  *  *  * char *  * *
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*   * * ***   ** ** =   *  + 3;
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**  *   *  * *** * ** =        + 3;
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**   ** ***  **  *   **         * *      *  *  *   * * ** *       ****** * *   
*  ** * *  **  
 ** *  *  **  * return 0;
}
100/100 answered
reshown by
0 0
-----------Re-judge-----------
Case 0: Wrong output
commented by (4.3k points)
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     hello

Anyway, great job. Full marks.
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
 * ** ** ***  * * * 
 *  **   * **** * *  *    

int   *  argc, char *argv[]) {
   * *** *** char    * 
 ***  *       * * char letteri;
 **** *** * ** char    
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*** ** **   **  char  * ** 
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* *     *    
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*  *   ** *    **  
**  **   ****  * return 0;
}


INPUT
** * *****  *
      * * ***
OUTPUT
****  ** *****
100/100 answered by (269 points)
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     hello

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
commented by (5.9k points)
0 0
prog.c:27:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:30:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:30:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
* * ** * *   * *    ***
*   *   **  *** *  *  * *

int * *    argc, char  ***  {
**        *** char ** **
* **** * *** * *  char  **** 
****** *   * * char * **  
* ** * ***  *  ***** char *** *
 ** *   * ** char * ** 
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*  **  *  **     *  
**  ***  * ****    * **** *  * *  *         *  *       ** *     *    ****** * **  * ***    ** *** *   
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**** ** ** **  letter = letter + 3;
*****      * *   ***  =   **  + 3;
   ** *      *   = **** + 3;
*    ****  *  *  ***     =  ** + 3;
 ***    ***  *   ****   =  *** * + 3;
    *    *  *  
   * *  * ***   * *  *** ** *    *  * * letter is   * * * ** * **  ** *     *    ** *  **    *
  *   *       **   
 ** *****  ***** * return 0;
}

INPUT
   * ****  *** * 
*  * *  ** *
*   *
 ***   * *
100/100 answered by (290 points)
reshown by
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     The encrypted letter is hello

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
commented by (5.9k points)
0 0
prog.c:26:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:29:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:29:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
#include *** ***       **  *

int main(int argc, char *argv[]) {
     *   ******   ** * ** ***  lettera;
 *****    ****   **     * *  letterb;
  *  **  ***     ** *   *     ** * letterc;
  ***   *  * *    * ** ** **   letterd;
 * *     *  * ** *    ** *    **    lettere;
***       **   ***   ******* ** 
* * *  **  **     **** **    **    *** * *  *** %c %c %c  ** ** **     **    **  * *      * ** **         *****  *  ***  ***** ** 
  * *** ****      ****** * ** = lettera + 3;
** *  *  ***   *  *      * = letterb + 3;
* * *** ** ***    ** ** *   *** = letterc + 3;
***  * *   *****  * * ** *** *** ** = letterd + 3;
*  * * *  ** ****** ***   *** **  = lettere + 3;
**** *  ** * **  *  ** ** **       **  *  * **** *******  *
   **** *    *   *         ** * *    * * * %c %c %c   *  ****     letterb, *  ** ** * * ** *  
    * *  **  **  **** *    *** 
*  * ***** ****** *   *   *****  0;
}

* *  *
* ***
*    **  **
* * 
//hello
100/100 answered by (271 points)
edited by
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: e b i i l
     h e l l o

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
commented by (5.9k points)
0 0
prog.c:25:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:28:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:28:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:10:5: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
     scanf("%c %c %c %c %c", &lettera, &letterb, &letterc, &letterd, &lettere);
     ^~~~~
prog.c:10:5: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:10:5: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:17:5: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
     printf("%c %c %c %c %c", lettera, letterb, letterc, letterd, lettere);
     ^~~~~~
prog.c:17:5: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:17:5: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
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