[Exercise 03] Caesar Cipher Decoder

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You have received an encrypted message from Julius Caesar-- the message is ebiil.  You are asked to decipher the message in order to understand what Caesar trying to say to you.

Hint

Luckily, Caesar has given you a hint, he says: 'I, myself, encoded the message by shifting every word backwards by 3.' 

Solution

Write a program that receives 5 characters 'ebiil'. Then decode those characters into 5 new characters.

Example

#include <stdio.h>

int main(int argc, char *argv[]) {


	char a;
    	char b;
	 	
	scanf("%c%c", &a, &b);
	
	//decode the message how??
	
	printf("%c%c", a,b);
	
	return 0;
}

Input

ebiil

 

 

 

 

 

 

 

 

 

 

Output

hello

** REMEMBER ** 
This is an online-compiler, don't put anything except the codes. If you want to make a comment, please use // or /* */

[Exercise] Coding (C) - asked in Chapter 2: Syntax structure of the C language by (5.9k points)
ID: 26955 - Available when: Unlimited - Due to: Unlimited
edited by | 3.5k views

22 Answers

0 like 0 dislike 
Hidden content!
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int *** * * argc, char ** *** {
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*  *  *** ** return 0;
}
100/100 answered by (449 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
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100/100 answered by (153 points)
0 0
Case 0: Correct output
Case 1: Wrong output
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
#include *  * * *  
#include *  ***  *** ***** 

/* run this program using the console pauser or add your own getch,  * *  **  * ** ***   * or input loop */

int main(int argc, char *argv[]) {
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*  * *  * *  **  *   *** = a+3;
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 **  *****   * **** ** ****  
*** **** *****   * *     ** *     *     0;
}
100/100 answered by (281 points)
edited by
0 0
Your program receives only 2 characters, and it doesn't move characters' positions.

Try to make it receive 5 characters, and move their positions forward by 3.
commented by (5.9k points)
0 0
This exercise expects only 'hello'. However, your code has.....

printf("Put the words you want to decode:");

Kindly consider delete this part :)
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
 ***  * ** * ****    **
** *  *  *  *  **   **  * *

int   **  * ** char  * *** {
/*
**    ** *** */

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a = a+3;
b = * *
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}
100/100 answered by (273 points)
edited by
0 0
prog.c:28:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:32:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:32:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
0 0
Your program can end at
  
    return 0;
}
------------------------------------------
You don't need to put

INPUT

ebiil

OUTPUT

hello
commented by (5.9k points)
0 0
Case 0: Correct output
Case 1: Wrong output
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
*   **  * * **  **  **
  *  * * * * * * * *** 

/* run this ***    *  the  ***  * *** or add your own ***    *  *** **   **  *   ** or * * *   */

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}
*** ** ***** ** * ** *    * *    ** ** **
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50/100 answered by (252 points)
0 0
prog.c: In function 'main':
prog.c:19:2: error: expected declaration or statement at end of input
  return 0;
  ^~~~~~
commented by (4.3k points)
0 0
Great job using an array and a loop. There are two mistakes found in your code. Please check
1.     printf("\n\n%s", code);  <--- in order to make it match the fixed output '\n\n' should be deleted
2.     At the end of your code, there's something missing.
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
*** *     ** * **    * *
*
*  *    *   * ******  ****
 
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** = *   *
*
* *  b + * 

 *  = c +   

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**        
*
* * ****** **   *  *****   *        *   
 
**    * 
*
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100/100 answered by (268 points)
0 0
It's correct lol you can't judge me
commented by (268 points)
0 0
Well, that's because your output doesn't match with the fixed answer. Please take a look at this
printf("%c%c%c%c%c\n", a1, b1, c1, d1, e1);

Hint: You should delete something  :)

By the way, great job.
commented by (5.9k points)
0 0
printf("%c%c%c%c%c", a1, b1, c1, d1, e1);

How's that?
commented by (268 points)
0 0
That's correct.
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
* * * * *** * **
*  *  ***** ** **  **

int  **  * argc, char * *** {
 * * **   * * *  char  ** 
* *  *** *  ****    char *** *
**  ** *    * char  *   
*     *  *  *  *   char *   **
*   **         char *     
    * ***  * 
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*** ** ** ***   *  *** =   ** + 3;
** *  * * ***        =   **   + 3;
** *  *   * *    =   *  + 3;
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**   * *** *       ***   = ***** + 3;
  **  **   *** 
* ***    * *  *** *  *    *  **** ** *       *** * ****    *  **   * *** 
* **    *  *** *  
   * ** **** *  return 0;
}
100/100 answered
reshown by
0 0
-----------Re-judge-----------
Case 0: Wrong output
commented by (4.3k points)
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     hello

Anyway, great job. Full marks.
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
      *   ** **   **
**      **  * *  * ***   

int  * *  argc, char *argv[]) {
*  ***     ** char  **** 
* *** *  ** *  ** char letteri;
***  **   * * **  char  *   *
  * * * *  ** char  *** 
 **    *    * ** char   * *
*  * * * *  **** 
*** * *   *  ** ******* * * *   input the letter to encode:  **** *    *
  ***        * 
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*  * *  ****   * ***  *  +3;
***  * * **** * * * *  *  +3;
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 *  ****    **** *  ** **    +3;
* ****     ** ** *     ****** * +3;
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     ***  * * *  
    ***    * *   ***   **     *  ***** * *  *   * *  *   * ***
* *   * * * **   
*** *     ***    return 0;
}


INPUT
 * * * *      * 
** * *** **   
OUTPUT
 ** *** ***** *
100/100 answered by (269 points)
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     hello

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
commented by (5.9k points)
0 0
prog.c:27:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:30:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:30:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
*  * * * * * ********
  *   ** ** * ** * **

int  * * argc, char *    {
 ** ****  **** char ** * *
 ** *   * *  ** char  *  
* * * * *   *   char  * * **
 * ** ***   char * ** 
    ** *   ****  char *   **
* *  *     *  ***  
 * ***     *   ***** **** **  ** input the  * to *        *        * **
*  * ** *  *     
*  *      ***         **   ** **  *  * ** *   *  *    ** *** ** *** *   *  *    ******   * * *   * ***
 ******    *  **  
*  ***   *   *  letter = letter + 3;
*  *  *  *   *    =     + 3;
**** **    *  *         = * **  + 3;
         *  *     *    =   * * + 3;
 * * *   * *   * ***  = *   + 3;
  *** ** *  ***    
  * *** * *  * ****** **** * *    ***  letter is  ****      *  * **** *****   ***** *  ***
*   *  * ****  
   **  *  ***    return 0;
}

INPUT
   ** * **  *  ***
   ** ** * 
    
***  **        *
100/100 answered by (290 points)
reshown by
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     The encrypted letter is hello

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
commented by (5.9k points)
0 0
prog.c:26:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:29:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:29:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
#include *** ** **   *   ***

int main(int argc, char *argv[]) {
*  *      *** *   *  *  ***  lettera;
****  *** ***    *** ***   * * letterb;
*  *  * * *     *****  ******  letterc;
*   * *** * ****      ****** letterd;
  *     *** **     ***    lettere;
*   * * *** *  *    *  ***  *
        *  ** **  **   * **  * *       %c %c %c  *  *    *      *    * *** ** ***   **  ** * ***   * *  *  *        * * * 
*  * * *    * *   ******** *  = lettera + 3;
*   * *  * * *  ** *  * *  * ****  = letterb + 3;
*    ** ***  * *** **      * ** *** = letterc + 3;
*   * ** *** * ** * *** *  ****** = letterd + 3;
 * * * ** *   * *   ** * * = lettere + 3;
 ** ****      * **  * *      ****    * ** *** ***        
* *   * *   *      *    *  * *   *   **   ***  %c %c %c  ****  *   *** letterb,   **  ***  * * * 
** *** *   *  *  *******   
* ***     *   *** ** * *  * 0;
}

  *  *
* ** 
 * **  * **
* ***
//hello
100/100 answered by (271 points)
edited by
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: e b i i l
     h e l l o

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
commented by (5.9k points)
0 0
prog.c:25:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:28:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:28:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:10:5: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
     scanf("%c %c %c %c %c", &lettera, &letterb, &letterc, &letterd, &lettere);
     ^~~~~
prog.c:10:5: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:10:5: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:17:5: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
     printf("%c %c %c %c %c", lettera, letterb, letterc, letterd, lettere);
     ^~~~~~
prog.c:17:5: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:17:5: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
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