[Exercise 03] Caesar Cipher Decoder

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You have received an encrypted message from Julius Caesar-- the message is ebiil.  You are asked to decipher the message in order to understand what Caesar trying to say to you.

Hint

Luckily, Caesar has given you a hint, he says: 'I, myself, encoded the message by shifting every word backwards by 3.' 

Solution

Write a program that receives 5 characters 'ebiil'. Then decode those characters into 5 new characters.

Example

#include <stdio.h>

int main(int argc, char *argv[]) {


	char a;
    	char b;
	 	
	scanf("%c%c", &a, &b);
	
	//decode the message how??
	
	printf("%c%c", a,b);
	
	return 0;
}

Input

ebiil

 

 

 

 

 

 

 

 

 

 

Output

hello

** REMEMBER ** 
This is an online-compiler, don't put anything except the codes. If you want to make a comment, please use // or /* */

[Exercise] Coding (C) - asked in Chapter 2: Syntax structure of the C language by (5.9k points)
ID: 26955 - Available when: Unlimited - Due to: Unlimited
edited by | 6.7k views

22 Answers

0 like 0 dislike 
Hidden content!
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}
100/100 answered by (449 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
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100/100 answered by (153 points)
0 0
Case 0: Correct output
Case 1: Wrong output
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
#include    **  *    ** 
#include *      * * ** *

/* run this program using the console pauser or add your own getch, **     * * ****   ***  *   or input loop */

int main(int argc, char *argv[]) {
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 *  *** ** *   *  *** ** 
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}
100/100 answered by (281 points)
edited by
0 0
Your program receives only 2 characters, and it doesn't move characters' positions.

Try to make it receive 5 characters, and move their positions forward by 3.
commented by (5.9k points)
0 0
This exercise expects only 'hello'. However, your code has.....

printf("Put the words you want to decode:");

Kindly consider delete this part :)
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
* ** ***** * ** *
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int *  *   * *  char ** *  {
/*
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      * *** 

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b =   **
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}
100/100 answered by (273 points)
edited by
0 0
prog.c:28:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:32:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:32:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
0 0
Your program can end at
  
    return 0;
}
------------------------------------------
You don't need to put

INPUT

ebiil

OUTPUT

hello
commented by (5.9k points)
0 0
Case 0: Correct output
Case 1: Wrong output
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
 *** ** ** **   * *** 
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}
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50/100 answered by (252 points)
0 0
prog.c: In function 'main':
prog.c:19:2: error: expected declaration or statement at end of input
  return 0;
  ^~~~~~
commented by (4.3k points)
0 0
Great job using an array and a loop. There are two mistakes found in your code. Please check
1.     printf("\n\n%s", code);  <--- in order to make it match the fixed output '\n\n' should be deleted
2.     At the end of your code, there's something missing.
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
* *    **  * *     *** * *
 
** ** *    * **  ** * * ***

***     *    ** *   *   * * **   *  **     *  * * **   *  *  **  *   ** * *  * *    *    
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* = c +  *

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** * *      * *  **  *   * * *   * **    
*
* *    

**
100/100 answered by (268 points)
0 0
It's correct lol you can't judge me
commented by (268 points)
0 0
Well, that's because your output doesn't match with the fixed answer. Please take a look at this
printf("%c%c%c%c%c\n", a1, b1, c1, d1, e1);

Hint: You should delete something  :)

By the way, great job.
commented by (5.9k points)
0 0
printf("%c%c%c%c%c", a1, b1, c1, d1, e1);

How's that?
commented by (268 points)
0 0
That's correct.
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
  ** * *   *** ** *  *
 *   ** **    *   * *   

int *  argc, char ***    {
*** *  ** ******** char *    
 *  **  **  * * char   ** 
** ******   **  char    * 
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*     * *   *** 
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*****  ** ** *  * ** =  * ** + 3;
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**    * ****  * 
*****   ** **   *    *****   ***  *  **       *     * *   **  ** 
 *             *  
 *   * *      ** return 0;
}
100/100 answered
reshown by
0 0
-----------Re-judge-----------
Case 0: Wrong output
commented by (4.3k points)
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     hello

Anyway, great job. Full marks.
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
****  ** **    ** **   
** * *  ***    * * *

int  * ** argc, char *argv[]) {
  * *      ***  char *** **
*  *  * *  *** * * char letteri;
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** * *    ** char  *  
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** **** *  ****  
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**  * *  * * ***    +3;
*  ******    * *  ****    +3;
*   ****   *** *     * * **** * *  +3;
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** * *    ******  
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*   *      * * *  
 * *    *  * return 0;
}


INPUT
 ****  *** **   **
   ** ******
OUTPUT
* * *  * *  *    **
100/100 answered by (269 points)
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     hello

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
commented by (5.9k points)
0 0
prog.c:27:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:30:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:30:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
***   **  **    
  *  * *** **  * **   *

int * **** argc, char *     {
 ****  * *    char  * 
** * *   *   ** char **  * 
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** * *  ** ***  char *  * ** 
****  *** *  char * **
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*     ** * * **** * **** ** *    input the ** to * *  *    **** * *   
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 *  **   ******  * * ** =  * *  + 3;
*   * * * *         =  *    + 3;
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****** ** **    *   =  ***   + 3;
******  *    * 
 ** * ***  * * *  * ** *  * *    ***  letter is  ****  * ***   * * * * *   *   **  * *  *  *   
 * **   *  
   * *  *** *   return 0;
}

INPUT
****** ****  **
 ** *  *   
  *****
*** *    *** * ** *
100/100 answered by (290 points)
reshown by
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     The encrypted letter is hello

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
commented by (5.9k points)
0 0
prog.c:26:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:29:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:29:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
#include * **  * * ** *

int main(int argc, char *argv[]) {
  **** *  **  *   *     * lettera;
***     ** ** * ******** ******* letterb;
* * *  ****    ***** ** *  letterc;
  ** * **   **** *    *****  letterd;
*  ** *  *     ** *   * *** * * lettere;
****** *  ** **   *  *** 
  **  ****  ** ***    **   *** ***** *  *   %c %c %c * *   * * **   ***** ***          *    * *    * ****** *  * *** * *   
 ** *  *     ***  ***    *  *  *  *   = lettera + 3;
* *  *  *  *   **  ***** ******* *  = letterb + 3;
*   *** *    *  * ** **      *  ** = letterc + 3;
* *** **  * *** * * **   ** *   = letterd + 3;
 * *  ***  ***  **    * ** ***** ** = lettere + 3;
** *     **  * ******    *   **   **** *******
  ** * **** * ***        ******   **    %c %c %c     ***  ** * * letterb,     **  * * *  * *** 
 **   **** **       **  **   *
*    **  **   *   **  *** * 0;
}

 * ** 
 * **
**     *  *** * 
*  **
//hello
100/100 answered by (271 points)
edited by
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: e b i i l
     h e l l o

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
commented by (5.9k points)
0 0
prog.c:25:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:28:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:28:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:10:5: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
     scanf("%c %c %c %c %c", &lettera, &letterb, &letterc, &letterd, &lettere);
     ^~~~~
prog.c:10:5: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:10:5: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:17:5: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
     printf("%c %c %c %c %c", lettera, letterb, letterc, letterd, lettere);
     ^~~~~~
prog.c:17:5: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:17:5: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
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