[Exercise 03] Caesar Cipher Decoder

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You have received an encrypted message from Julius Caesar-- the message is ebiil.  You are asked to decipher the message in order to understand what Caesar trying to say to you.

Hint

Luckily, Caesar has given you a hint, he says: 'I, myself, encoded the message by shifting every word backwards by 3.' 

Solution

Write a program that receives 5 characters 'ebiil'. Then decode those characters into 5 new characters.

Example

#include <stdio.h>

int main(int argc, char *argv[]) {


	char a;
    	char b;
	 	
	scanf("%c%c", &a, &b);
	
	//decode the message how??
	
	printf("%c%c", a,b);
	
	return 0;
}

Input

ebiil

 

 

 

 

 

 

 

 

 

 

Output

hello

** REMEMBER ** 
This is an online-compiler, don't put anything except the codes. If you want to make a comment, please use // or /* */

[Exercise] Coding (C) - asked in Chapter 2: Syntax structure of the C language by (5.9k points)
ID: 26955 - Available when: Unlimited - Due to: Unlimited
edited by | 8.7k views

22 Answers

0 like 0 dislike 
Hidden content!
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* ***        * return 0;
}
100/100 answered by (449 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
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100/100 answered by (153 points)
0 0
Case 0: Correct output
Case 1: Wrong output
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
#include    *  ********* 
#include * * **  *  ** *

/* run this program using the console pauser or add your own getch,  **  *  **   **  *   or input loop */

int main(int argc, char *argv[]) {
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}
100/100 answered by (281 points)
edited by
0 0
Your program receives only 2 characters, and it doesn't move characters' positions.

Try to make it receive 5 characters, and move their positions forward by 3.
commented by (5.9k points)
0 0
This exercise expects only 'hello'. However, your code has.....

printf("Put the words you want to decode:");

Kindly consider delete this part :)
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
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int  * * ** char    *** {
/*
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}
100/100 answered by (273 points)
edited by
0 0
prog.c:28:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:32:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:32:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
0 0
Your program can end at
  
    return 0;
}
------------------------------------------
You don't need to put

INPUT

ebiil

OUTPUT

hello
commented by (5.9k points)
0 0
Case 0: Correct output
Case 1: Wrong output
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
***     * ********  
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int *****   *   char ***  {
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}
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        ***     **  0;
50/100 answered by (252 points)
0 0
prog.c: In function 'main':
prog.c:19:2: error: expected declaration or statement at end of input
  return 0;
  ^~~~~~
commented by (4.3k points)
0 0
Great job using an array and a loop. There are two mistakes found in your code. Please check
1.     printf("\n\n%s", code);  <--- in order to make it match the fixed output '\n\n' should be deleted
2.     At the end of your code, there's something missing.
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
**** *    *  * ** * *  

*    *  * * *   ***    
 
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*     **  *       * ** *  * **    **** *  * *** **   *** * ** *    *  *    
 
* * =   * 

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** = c +  *

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*
*      
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**  ***   ** *   ** *   * *      *  *  ***
 
 **** 

*
100/100 answered by (268 points)
0 0
It's correct lol you can't judge me
commented by (268 points)
0 0
Well, that's because your output doesn't match with the fixed answer. Please take a look at this
printf("%c%c%c%c%c\n", a1, b1, c1, d1, e1);

Hint: You should delete something  :)

By the way, great job.
commented by (5.9k points)
0 0
printf("%c%c%c%c%c", a1, b1, c1, d1, e1);

How's that?
commented by (268 points)
0 0
That's correct.
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
 * *    * *       * * 
       *    * *  *** * * *

int   ** argc, char *     {
 **  ** **  * * char  *   * 
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** *    * * **     * =    ** + 3;
** *     ***  *    =  ****   + 3;
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* ****      *   
****  **   * **   ****     *** **  *  ** * * *  ***  *   *   **** * * 
 ** ***** * ** *  
  *  *  ** return 0;
}
100/100 answered
reshown by
0 0
-----------Re-judge-----------
Case 0: Wrong output
commented by (4.3k points)
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     hello

Anyway, great job. Full marks.
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
** **   * *** **    **   
 * * *   ****  * *  * 

int **   argc, char *argv[]) {
******   *   char  ** *
*  ** *  *    *   char letteri;
   *      ** *  char * * *
*  **    *  *  * char * *  *
***    *   *   char *   
* *  *  * **  
* *** **  *  **  *  * * input the letter to encode: * **   ** ****
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**** ** * **     ** **  ****   +3;
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* ***  ***    **    **  *  +3;
* ***** * ** ** 
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**  * **   **  ***     *      * ******  ** **  * ** *  * ** * *    ****  
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** *  ** ** return 0;
}


INPUT
* *   * **   *  
*  *     
OUTPUT
 **   *  ** **
100/100 answered by (269 points)
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     hello

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
commented by (5.9k points)
0 0
prog.c:27:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:30:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:30:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
 **  * ** * *    *
**  * ***   **  * * ***  

int *** argc, char * * *  {
**  ****** * *  * char  **   
 ** *  * *   * char **  *  
* ** ** * * **  char * * *
 **  * **  **  char   **  
*****  *    *  char   *   *
**** *** ** *** 
 * *** *   * *     *  *** input the      to ** *   ****   * ** *
 *  *** ** *** * 
 * * *    *    **  *      * *****    **      **  * *  * **  ****  ** ***   ***     *   ***    *
***   *** **  
** ** *    *   letter = letter + 3;
*     **  *   *  * = ****   + 3;
* ***  * *** *  * **** = * *   + 3;
 **** *    *** *  *    = * * * + 3;
*   * * * ** ** * =   *   + 3;
***  **    *** 
** * *  ** **      *****     * letter is   * **** *** *  **     ** * ***    *  **  ****
*  * *** **    
**  * * * **  *  return 0;
}

INPUT
 * * ** ******  ***
*    **  ******
 **
 **   *******    ***
100/100 answered by (290 points)
reshown by
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     The encrypted letter is hello

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
commented by (5.9k points)
0 0
prog.c:26:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:29:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:29:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
#include *  *  *  *    

int main(int argc, char *argv[]) {
******   *** *  * * * *   *   lettera;
 ** * ***    **  **      **    letterb;
*  * **   **   * * ** **** *  letterc;
** * * * * ***     *  **   letterd;
 * **  ** *        * * * * * lettere;
***   *   ***     ***  *** *
*  **  *  ***** *  * ******  ***   * *    %c %c %c *  ** *  * *     *** **       **  * **  *   * ** *  **      ** ***  * 
* * *   *  *********** ***  **   *   = lettera + 3;
 *   * *  ** * ** *   ** * ** * = letterb + 3;
   *   *   ** ***   ** **** *  = letterc + 3;
** *  **** **  *     ****    ** **** = letterd + 3;
 *****   *  *    *    * * *  *** = lettere + 3;
** *       * **  * * * *** ***  * * ***  * ***** * *   
* **  ***   *  ** ** *    *   * *  ** ***  %c %c %c **  * ** * letterb, *******   * ** ***
 ***  **  * *******  * ** **** **
 *** **** * *    **** **  ***    0;
}

 * ***  
* * *
 *  **   ***
 * **  
//hello
100/100 answered by (271 points)
edited by
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: e b i i l
     h e l l o

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
commented by (5.9k points)
0 0
prog.c:25:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:28:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:28:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:10:5: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
     scanf("%c %c %c %c %c", &lettera, &letterb, &letterc, &letterd, &lettere);
     ^~~~~
prog.c:10:5: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:10:5: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:17:5: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
     printf("%c %c %c %c %c", lettera, letterb, letterc, letterd, lettere);
     ^~~~~~
prog.c:17:5: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:17:5: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
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