[Exercise 03] Caesar Cipher Decoder

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You have received an encrypted message from Julius Caesar-- the message is ebiil.  You are asked to decipher the message in order to understand what Caesar trying to say to you.

Hint

Luckily, Caesar has given you a hint, he says: 'I, myself, encoded the message by shifting every word backwards by 3.' 

Solution

Write a program that receives 5 characters 'ebiil'. Then decode those characters into 5 new characters.

Example

#include <stdio.h>

int main(int argc, char *argv[]) {


	char a;
    	char b;
	 	
	scanf("%c%c", &a, &b);
	
	//decode the message how??
	
	printf("%c%c", a,b);
	
	return 0;
}

Input

ebiil

 

 

 

 

 

 

 

 

 

 

Output

hello

** REMEMBER ** 
This is an online-compiler, don't put anything except the codes. If you want to make a comment, please use // or /* */

[Exercise] Coding (C) - asked in Chapter 2: Syntax structure of the C language by (5.9k points)
ID: 26955 - Available when: Unlimited - Due to: Unlimited
edited by | 1.1k views

22 Answers

0 like 0 dislike 
Hidden content!
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}
100/100 answered by (449 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
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100/100 answered by (153 points)
0 0
Case 0: Correct output
Case 1: Wrong output
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
#include * ***  *    * 
#include * * ***** ***  *

/* run this program using the console pauser or add your own getch,  * ***   *  **     or input loop */

int main(int argc, char *argv[]) {
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**   *        ** * ****  *  = a+3;
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**  **** **  ** **  * **  * *  *  = b+3;
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    **  * *   * ** * * **** *
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}
100/100 answered by (281 points)
edited by
0 0
Your program receives only 2 characters, and it doesn't move characters' positions.

Try to make it receive 5 characters, and move their positions forward by 3.
commented by (5.9k points)
0 0
This exercise expects only 'hello'. However, your code has.....

printf("Put the words you want to decode:");

Kindly consider delete this part :)
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
 * *  *   * **   * * 
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int *  **   *** char *   * {
/*
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***       

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a = a+3;
b =  **
c =    *
d = d+3;
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}
100/100 answered by (273 points)
edited by
0 0
prog.c:28:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:32:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:32:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
0 0
Your program can end at
  
    return 0;
}
------------------------------------------
You don't need to put

INPUT

ebiil

OUTPUT

hello
commented by (5.9k points)
0 0
Case 0: Correct output
Case 1: Wrong output
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
   *     *   * * * * 
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}
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50/100 answered by (252 points)
0 0
prog.c: In function 'main':
prog.c:19:2: error: expected declaration or statement at end of input
  return 0;
  ^~~~~~
commented by (4.3k points)
0 0
Great job using an array and a loop. There are two mistakes found in your code. Please check
1.     printf("\n\n%s", code);  <--- in order to make it match the fixed output '\n\n' should be deleted
2.     At the end of your code, there's something missing.
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
  *  *       *** *** 

*   *****  * *** * ** * * ***

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**     * *

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*
100/100 answered by (268 points)
0 0
It's correct lol you can't judge me
commented by (268 points)
0 0
Well, that's because your output doesn't match with the fixed answer. Please take a look at this
printf("%c%c%c%c%c\n", a1, b1, c1, d1, e1);

Hint: You should delete something  :)

By the way, great job.
commented by (5.9k points)
0 0
printf("%c%c%c%c%c", a1, b1, c1, d1, e1);

How's that?
commented by (268 points)
0 0
That's correct.
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
   *    * * **  * * *
 **      *  ***  * * 

int *    argc, char  *** *   {
** *  **  * * char * ** 
*  *** * *  **** char **  
*** *          char *  *  
**     ***   char   * * 
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*** *  *   *   ** ** *  * * input the letter to   *** *** * 
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  * * *        **      ** **  **  ** **    * *****  *  *     *  **    ** * ** *   ** ***  **  ****** ** 
 * *** * ** * * **  = ****  + 3;
       *  ** **  ****  = * ** + 3;
** ** * **      * * *    =     *  + 3;
**    *    * * letterc = *** + 3;
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* ** **  * ** * 
*   *    *      **  * **   ***** * **   *** *  * *  *  * * ***     * * 
 **   ** **  *  
*** **    * **  return 0;
}
100/100 answered
reshown by
0 0
-----------Re-judge-----------
Case 0: Wrong output
commented by (4.3k points)
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     hello

Anyway, great job. Full marks.
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
*****  ** **    *  *  **
   * ** * **    **** * 

int ** * argc, char *argv[]) {
 ** *    *   * char  **
  * * * *  **  char letteri;
 ** *  *  *  char   *** 
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*   * * **** *  char  * * *
*   *   * **  ** 
 *** *   * **  *  *      *  ** input the letter to encode: *  *  * **       *
* *  * ****** 
* *    ** * *** ***   ***    ** **   *  *** * *   ****  *      * **    * ** *  * * **  * **
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*  * *  ****** *     ****    +3;
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**** **** *** * ** * *  * +3;
*  *** *  * ***  * 
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**  *  **** *  ** **  **   ** **  ***** *  *****  * *   ** * *  ***
*  ****  * *   * 
  *  ** * **   ** * return 0;
}


INPUT
   *  *  * *  *  
     *  **
OUTPUT
*** *  *****
100/100 answered by (269 points)
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     hello

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
commented by (5.9k points)
0 0
prog.c:27:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:30:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:30:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
 *    ** **   *** ***
 ** *  *  * *  *  **** ** 

int  *    argc, char ** *** {
  *  * *   ***** ** char      
       *     *  char *  * 
*    ** *  ** * char *    **
**   *   * * char * * * 
 ** * **  *  char ****
 *  *     ** * 
*    *  *       * **   ** input the      to ** ** ***  **    **
    *    * *  
*   **    * * **       **    * ********  ***  **   * ***  ***** *    **** * * ****  ** * *   ** * * * *
 **  ** * ****   
 **       ***   letter = letter + 3;
*** *        * *  * *  =    *   + 3;
 * ***     *    ***  = **  * + 3;
   **** ** * *      =        + 3;
 *      * ***   * *  = ** *  + 3;
*  * *   * * *   
 * ***          * *      *   *   letter is   * * **  **  *** * ** * ** *  *  *  * *  **
  ***  *  * *  
  **** *  **  * return 0;
}

INPUT
** **   ***  *   
 **  *  * *
   
 *** * ** ****
100/100 answered by (290 points)
reshown by
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     The encrypted letter is hello

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
commented by (5.9k points)
0 0
prog.c:26:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:29:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:29:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
#include ***  * * ****   *

int main(int argc, char *argv[]) {
 ***    **  * ** *** *   * * lettera;
      *  *  **  **** **  **** letterb;
* *****  *  ** *  *****     letterc;
        * * *   * ***    ***** **  letterd;
** ****   * **  ** *****  ***  lettere;
**    *  * ***** * * *** *
*   *           *********  * *****  %c %c %c *   *** **     **  ***  *** ** * ***       *    *   ***      *  * * * 
    * * *** * **      *  *  *** *  ** = lettera + 3;
***  ******     **  ***** **  *** = letterb + 3;
  *    *******   *    **  *    *  = letterc + 3;
*** ***  *  * *     * *  * = letterd + 3;
** * * ** ** * * * **     ** ***** = lettere + 3;
****  ** * ***    *  ****   ***   **    **   **   * **  *  
**  ** * **  * *  * *   * ***** *   * * %c %c %c *   * ***  *   ** letterb, ***  * * ***  * *   
**    ** *         * ** 
   ***  *    * * ** ** *   ****  0;
}

* **  
  ***
   *     *  * 
  *** 
//hello
100/100 answered by (271 points)
edited by
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: e b i i l
     h e l l o

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
commented by (5.9k points)
0 0
prog.c:25:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:28:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:28:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:10:5: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
     scanf("%c %c %c %c %c", &lettera, &letterb, &letterc, &letterd, &lettere);
     ^~~~~
prog.c:10:5: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:10:5: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:17:5: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
     printf("%c %c %c %c %c", lettera, letterb, letterc, letterd, lettere);
     ^~~~~~
prog.c:17:5: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:17:5: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
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