[Exercise 03] Caesar Cipher Decoder

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You have received an encrypted message from Julius Caesar-- the message is ebiil.  You are asked to decipher the message in order to understand what Caesar trying to say to you.

Hint

Luckily, Caesar has given you a hint, he says: 'I, myself, encoded the message by shifting every word backwards by 3.' 

Solution

Write a program that receives 5 characters 'ebiil'. Then decode those characters into 5 new characters.

Example

#include <stdio.h>

int main(int argc, char *argv[]) {


	char a;
    	char b;
	 	
	scanf("%c%c", &a, &b);
	
	//decode the message how??
	
	printf("%c%c", a,b);
	
	return 0;
}

Input

ebiil

 

 

 

 

 

 

 

 

 

 

Output

hello

** REMEMBER ** 
This is an online-compiler, don't put anything except the codes. If you want to make a comment, please use // or /* */

[Exercise] Coding (C) - asked in Chapter 2: Syntax structure of the C language by (5.9k points)
ID: 26955 - Available when: Unlimited - Due to: Unlimited
edited by | 7.8k views

22 Answers

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Hidden content!
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**   *  **  *   return 0;
}
100/100 answered by (449 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
commented by (4.3k points)
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Hidden content!
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100/100 answered by (153 points)
0 0
Case 0: Correct output
Case 1: Wrong output
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
#include  ** *  * **  **
#include     * ** **  **

/* run this program using the console pauser or add your own getch, * **    * ******  **  or input loop */

int main(int argc, char *argv[]) {
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**    ** ************  **** = e+3;
****** **  * **  ***  *   *  *  * ***   
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* **     *     * **    *  **** 
  **   ***  **** * **     ****** *  0;
}
100/100 answered by (281 points)
edited by
0 0
Your program receives only 2 characters, and it doesn't move characters' positions.

Try to make it receive 5 characters, and move their positions forward by 3.
commented by (5.9k points)
0 0
This exercise expects only 'hello'. However, your code has.....

printf("Put the words you want to decode:");

Kindly consider delete this part :)
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
**     * *  ******  *  ** * 
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int     **  * ** char * ****  {
/*
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a = a+3;
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}
100/100 answered by (273 points)
edited by
0 0
prog.c:28:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:32:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:32:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
0 0
Your program can end at
  
    return 0;
}
------------------------------------------
You don't need to put

INPUT

ebiil

OUTPUT

hello
commented by (5.9k points)
0 0
Case 0: Correct output
Case 1: Wrong output
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
*****    *   *** *** *
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/* run this * *   the ** * *    or add your own *  *  **     *  **     **   * or  **   *   */

int ***     ** char ***     {
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}
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* *     *  *   * * 0;
50/100 answered by (252 points)
0 0
prog.c: In function 'main':
prog.c:19:2: error: expected declaration or statement at end of input
  return 0;
  ^~~~~~
commented by (4.3k points)
0 0
Great job using an array and a loop. There are two mistakes found in your code. Please check
1.     printf("\n\n%s", code);  <--- in order to make it match the fixed output '\n\n' should be deleted
2.     At the end of your code, there's something missing.
commented by (5.9k points)
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Hidden content!
*  **  ***   * * ****

* **   **  *****   *  

*    ** **  **  **   *   *  *     * *  **      * ***  * ** *** *  ** * *  ***   *  

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* *    *   * * 

   * ****  *   * *              * **  * *    *    ** * ***   * * * *  **

* = *    
*
**   b + **

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*
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*
*
100/100 answered by (268 points)
0 0
It's correct lol you can't judge me
commented by (268 points)
0 0
Well, that's because your output doesn't match with the fixed answer. Please take a look at this
printf("%c%c%c%c%c\n", a1, b1, c1, d1, e1);

Hint: You should delete something  :)

By the way, great job.
commented by (5.9k points)
0 0
printf("%c%c%c%c%c", a1, b1, c1, d1, e1);

How's that?
commented by (268 points)
0 0
That's correct.
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
*  *   ***  ** *   
* ***   *   ** **  *

int    *  argc, char  ** *  * {
  **** *    * * char  * *
*      * * **   char  ***
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**  *  * **       
* ****     **  ** ** * * ** input the letter to ** *  * **   
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*   * **  ***  *    ** =   **   + 3;
  * **     * *    *  *  = * ** + 3;
* * * ** *  *     ** = *  **  + 3;
*  ** * *   *   letterc =    * + 3;
* * **   *    ** * = *** * + 3;
***    ** ** 
 *  *    **     *** **  *   ****** **   * ** * * * *** * **    *    
 **   **    ***   
* ** * *  ** return 0;
}
100/100 answered
reshown by
0 0
-----------Re-judge-----------
Case 0: Wrong output
commented by (4.3k points)
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     hello

Anyway, great job. Full marks.
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
    * ***  ***     ***
   ** *    * ***       

int *  *** argc, char *argv[]) {
  **  *** * * * char  *    
    ***  * **   *  char letteri;
**  *     * * char * *  *
*  * *    *      char  ****
*****     ** **   char * * **
*** *   *  * 
* ***     *       ** ** *   input the letter to encode: ***** **  ***** *
 *   *     *    ** 
*** **  ** * ***  * ****  * *** *        ***  * **   ***   *** *    ******** ** * **   **** *   * **
 ***       * ** ***  +3;
*  *  ***   **   * **     +3;
  **  *   *  *     ** *   +3;
 * **  ***    * *** * *  * +3;
*****  * *  **     **   ** +3;
 ** **   ***** 
* *****  * * ** 
 ***  * **** * * *  * * ** * *** *   * ****       **  *  * *    **  
*      ***   
***   *  **** return 0;
}


INPUT
*** ****  **** *   
* * * * * ***  
OUTPUT
***** * ****    ***
100/100 answered by (269 points)
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     hello

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
commented by (5.9k points)
0 0
prog.c:27:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:30:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:30:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
*  ** *      ***  
* *  **   ** * ***  * ****

int ****  argc, char  * *  {
**     ***  *  char     * 
  **  *   * *   char *  **  
  *  *  ** **  char ** 
*  **** *  *  * * char **    
* *  **    *  char * *   
**      * * 
   **   *   *   *   *  ** *      input the  **  *  to  * * ****    ** **** 
     *  ******* 
   ** ** **  *   * * **  * **  *** ***** *   * **   **      ***** **** * *  * *** ****  ** **  *   *   ** 
 ***   ** ****  
*   **  *   * letter = letter + 3;
* * ** * *    ** **    * = **** + 3;
 ** ***    ** **  *   =  *   + 3;
 **** *  * ******     * = ** ** + 3;
********   * **** **   =   *  + 3;
*   *** **  ** 
*  *** ** ***        * *   * * *** * *  *   letter is ***   * * **      ** ***   * *  ** **   *****      **
  * * **  *   ** 
* * *   *****  return 0;
}

INPUT
   *** *     **
**  * *    ***
 * **
 *   * *   * ***
100/100 answered by (290 points)
reshown by
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     The encrypted letter is hello

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
commented by (5.9k points)
0 0
prog.c:26:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:29:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:29:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
#include    *  *  *** * ***

int main(int argc, char *argv[]) {
   *  *  * *    * * ***** lettera;
 ** **   **   ****  *     **** letterb;
****    * ******** *   ** letterc;
 *** *   *** *   * *** *      letterd;
******   *** *     * **      lettere;
** * *   *  *   **   **   
**  *    ******** * *  ** ** * ** * *     %c %c %c * *  *  *  ***  *    * **   **  *  * *  ***  **        *   *  *   ***   
*  ** ***  *      * **   * *** **** = lettera + 3;
******* *  *     * ** ** **       = letterb + 3;
***  *  ** *  * ****   *      **  ** = letterc + 3;
 *****  ** * * **  ***    * ** **  ** = letterd + 3;
    * ****   ***  **      **  *** = lettere + 3;
    * * *  ********   *     *   *** * *   ***  * * * 
** * *  * **    *    * ******   %c %c %c *  ***   ***  *  ** letterb, * ****  *    ** * 
****   ******   * **** 
 *** ** ***  *  *** *  ** 0;
}

*** *
**   
* *   *  ****
 **** 
//hello
100/100 answered by (271 points)
edited by
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: e b i i l
     h e l l o

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
commented by (5.9k points)
0 0
prog.c:25:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:28:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:28:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:10:5: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
     scanf("%c %c %c %c %c", &lettera, &letterb, &letterc, &letterd, &lettere);
     ^~~~~
prog.c:10:5: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:10:5: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:17:5: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
     printf("%c %c %c %c %c", lettera, letterb, letterc, letterd, lettere);
     ^~~~~~
prog.c:17:5: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:17:5: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
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