[Exercise 03] Caesar Cipher Decoder

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You have received an encrypted message from Julius Caesar-- the message is ebiil.  You are asked to decipher the message in order to understand what Caesar trying to say to you.

Hint

Luckily, Caesar has given you a hint, he says: 'I, myself, encoded the message by shifting every word backwards by 3.' 

Solution

Write a program that receives 5 characters 'ebiil'. Then decode those characters into 5 new characters.

Example

#include <stdio.h>

int main(int argc, char *argv[]) {


	char a;
    	char b;
	 	
	scanf("%c%c", &a, &b);
	
	//decode the message how??
	
	printf("%c%c", a,b);
	
	return 0;
}

Input

ebiil

 

 

 

 

 

 

 

 

 

 

Output

hello

** REMEMBER ** 
This is an online-compiler, don't put anything except the codes. If you want to make a comment, please use // or /* */

[Exercise] Coding (C) - asked in Chapter 2: Syntax structure of the C language by (5.9k points)
ID: 26955 - Available when: Unlimited - Due to: Unlimited
edited by | 5.6k views

22 Answers

0 like 0 dislike 
Hidden content!
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}
100/100 answered by (449 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
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100/100 answered by (153 points)
0 0
Case 0: Correct output
Case 1: Wrong output
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
#include * *  *     *** *
#include  * *     *      

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int main(int argc, char *argv[]) {
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*  * *****  *      **     * 
* **  *****    *****    * * 0;
}
100/100 answered by (281 points)
edited by
0 0
Your program receives only 2 characters, and it doesn't move characters' positions.

Try to make it receive 5 characters, and move their positions forward by 3.
commented by (5.9k points)
0 0
This exercise expects only 'hello'. However, your code has.....

printf("Put the words you want to decode:");

Kindly consider delete this part :)
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
*     ***         * ** 
**  **  **  ** * * *  

int * **   char *     {
/*
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* * *  ** ** 

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b = **
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}
100/100 answered by (273 points)
edited by
0 0
prog.c:28:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:32:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:32:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
0 0
Your program can end at
  
    return 0;
}
------------------------------------------
You don't need to put

INPUT

ebiil

OUTPUT

hello
commented by (5.9k points)
0 0
Case 0: Correct output
Case 1: Wrong output
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
*** * ** ***** * * ****
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}
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             * ** *   0;
50/100 answered by (252 points)
0 0
prog.c: In function 'main':
prog.c:19:2: error: expected declaration or statement at end of input
  return 0;
  ^~~~~~
commented by (4.3k points)
0 0
Great job using an array and a loop. There are two mistakes found in your code. Please check
1.     printf("\n\n%s", code);  <--- in order to make it match the fixed output '\n\n' should be deleted
2.     At the end of your code, there's something missing.
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
         **     ****  
*
* ** **** * *   * **  
 
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*    *   *

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100/100 answered by (268 points)
0 0
It's correct lol you can't judge me
commented by (268 points)
0 0
Well, that's because your output doesn't match with the fixed answer. Please take a look at this
printf("%c%c%c%c%c\n", a1, b1, c1, d1, e1);

Hint: You should delete something  :)

By the way, great job.
commented by (5.9k points)
0 0
printf("%c%c%c%c%c", a1, b1, c1, d1, e1);

How's that?
commented by (268 points)
0 0
That's correct.
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
    **    ** ********* ***
  ** * ******* ** * * * * 

int ****    argc, char ***** ** {
**  *** *  * ** char     **  
**   *   *****  char  ***
*     ******* char    *
* * * *  * *   *  char ***
** **     *  * char ****  
  **        *  
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*   **    ***   ****  = ** *  + 3;
*          * *   * * * =   * ** + 3;
** * *  * * * **  =  * ** + 3;
* **  *  *   letterc = ***   + 3;
*** **     **  *  *** * = * *  + 3;
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*  **   ** *   *** **  *  *****  **  * * **   *** *  ***             ** * 
  * * * **** 
**  ****  *** ** return 0;
}
100/100 answered
reshown by
0 0
-----------Re-judge-----------
Case 0: Wrong output
commented by (4.3k points)
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     hello

Anyway, great job. Full marks.
commented by (5.9k points)
1 like 0 dislike 
Hidden content!
 ***      ** **  **      
 * *     *        ***** 

int   *  *  argc, char *argv[]) {
  ***     *   *  char   ** 
**  *    ** * char letteri;
** ** *    ** char  *   *
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 ** *     ***** * char * * ** 
     *  ** 
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* * **    **  ***** 
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**  *      ** *****        * * +3;
**  *** **  *    * ** *   * +3;
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**  ** **** ** 
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 *    **** **    ** 
 * **  *       ** return 0;
}


INPUT
* *   *****  ** 
  **   * * ** 
OUTPUT
* *****   **
100/100 answered by (269 points)
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     hello

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
commented by (5.9k points)
0 0
prog.c:27:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:30:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:30:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
     *  * *    **** *  **
 **** *   *   ** * ** * 

int * * * argc, char ***   {
** *     **   * char **  *
   **       * ** char  *    *
*    **** ** * * char   ** 
 *   ** ** * * *  char *** * 
  *  ** **  * *    char    *
 *   * *  *    *  
  *** ***      * *    * ** *  ** *  input the * * * to ***  ** ** * **  * *** 
 *   * *   ** ** 
 *** *  *  *** *    *  *   *** **  *        *        * **    *      ** ** * *   ** ** * *  **     
*  ***       *** 
******  **  letter = letter + 3;
 ** * * *     * ** =  ** + 3;
 * ***      *  **** = * * + 3;
***   * *    * * **  * ** = **  + 3;
*   ***   * *** * **** = *****  + 3;
*******  *  * 
 ***** *** ** *   * * * ***   * ** * letter is   *  ***  ***  *****   ****** * ***** ** * * *   *
**** *  *   * 
   **      ***  return 0;
}

INPUT
 * ** * ***  ***
  ***** **    
  ** 
   *  * *   ***  *
100/100 answered by (290 points)
reshown by
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     The encrypted letter is hello

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
commented by (5.9k points)
0 0
prog.c:26:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:29:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:29:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
1 like 0 dislike 
Hidden content!
#include    * * ** *  **** 

int main(int argc, char *argv[]) {
      ***  *   *   **** * * * lettera;
*   * ****      ** ***** *  letterb;
    ** ** *  * *** * * *  * letterc;
 **  *   *  *  *  *****  *   *   letterd;
* **    * * * *** * * *  ** *  lettere;
 ***  **  * * *   *    *  **
****  *    * **  *  *   * * *  ** ***** * * * %c %c %c   ****  ** *    ** *****       **   **  **  **** *      *     *       **** * *  
* *  **   ** * *    *** = lettera + 3;
*  *  * ** ** **** *  ** ******    = letterb + 3;
 **     **** *** * *   *  *    = letterc + 3;
***  ******  *   *  **** *     *  * = letterd + 3;
** * *******  ** * **   *    ** = lettere + 3;
* ****    ** *  *****  *  ***   *   *    ** *  ** **  
 * ********* *** *** * ****   ** ***     %c %c %c   * **    * *   * letterb, *****   ***   * * *
  ** ****      * ***  * * **
  **   *  *  * *****   *** ** * 0;
}

   * 
 *  
    *   **     **
**** 
//hello
100/100 answered by (271 points)
edited by
0 0
Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: e b i i l
     h e l l o

Also, it's an online compiler, if you want to make a comment don't forget to use //. For example, //input ebiil
//output hello

Anyway, great job. Full marks.
commented by (5.9k points)
0 0
prog.c:25:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:28:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:28:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:10:5: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
     scanf("%c %c %c %c %c", &lettera, &letterb, &letterc, &letterd, &lettere);
     ^~~~~
prog.c:10:5: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:10:5: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:17:5: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
     printf("%c %c %c %c %c", lettera, letterb, letterc, letterd, lettere);
     ^~~~~~
prog.c:17:5: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:17:5: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
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