Final Exam 2 (20%)

1 like 0 dislike
14.1k views

A string p is a prefix of a string s if the leading characters of s are identical to p. For example, "abc" is a prefix of "abcde". Develop a function prefix that checks if a C string p is a prefix of another C string s.

p是s的前綴若s開頭的一段字串等於p。例如，"abc"是"abcde"的前綴。寫一個程式 判斷字串p是否字串s的前綴。

Example input 1:

abc
abcde

Example output 1:

abc is a prefix of abcde

 

Example input 2:

bc
abcde

Example output 2:

bc is not a prefix of abcde

 

[Exam] asked in Final Exam
ID: 42299 - Available when: 2018-01-17 14:00 - Due to: Unlimited
retagged by | 14.1k views

37 Answers

0 like 0 dislike 
Hidden content!
#include   *  *   *  * 
#include * **   ** *  **  * *
**   *** *   ** **   
* *  *       * * ***  

int prefix(char a[], char b[]){
int i, j,n;
int cnt=0;

n= *   *** *  **

  ** * **** ** * * ** ***  ******* ****  
     * *  *   *   * * ***** == b[i]){
*  ****   *   *  **  ** * **** *** * *   *  ** ***   *** ***    
*** ****  *** *** ******  

***     ****    *   * 
if (cnt == n){
   *  *    * *** * ***  ***         * ******* ** *   * *** **   1;
     * *     * *** * * * * **** *   **** * *** * **
*    * * ** *  * **  * **** *  
*    *        **  **  * *  ****  ****  *      *     * 0;

}

int main()
{
 * * **      ********  *   s1[100], s2[100];
  *******   **** *  * i,j;

  **** * * * *  *****   * * *  ** *  s1);
  * *** ***  * * *   **  *     *   *  ** *   ** s2);
 **** ** ** *** *    *** (prefix(s1, s2)){

 * * **  *  *    *** * *  ********* * ****   *** ***  **   is a prefix of %s", s1,s2);
 * *  *   *  * ***       **  *** * * *   * ****  
* **** *   *  * * ** **** *******   **    *  ** ** 
 * ** * **  * *      **** ****** *  *  **    ** *****   * *   ** *  ** **  ** * *  is not a prefix of %s", s1,s2);



}
answered by (323 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <string.h>

int main(){
   * **** ***  ** *** **  * c;
**  * *** ** *     ***  *  **    a[100],b[100];
 *  *  *  ***** ****   *  *  * ** ** **     %s",a,b);
*****  *** * *   * *****  ***  * **** * ***
**    **   ****   **** ****  * ******* ** ** *  **  * *  0;
*  * * *   *  **  **  * ***  ** ** *   %d",strlen(a),strlen(b));
  **  * *   *  **      *   * *  ******* ****  *
*   * * *  *  * **** ****  * * *     ** * ** ***    *   *   * * *** *  **   *  * ***
 *  * ****       **  ***** *  *   *****   ** * * *    *****     ******   **** *** ** ** ** *** * * ***** *    ********   ** *  is not a prefix of %s",a,b);
**    * * **     *  *    *      ***      ** ** * * ** *    * **    *******   *  **   *  ***  **  * 
 *   ***  ****   * * * * * *****    ***     **   * ***  *        ** ***  *
 * ***  **  ****  * *****   **   **   ****  *** **** *  ** * * **   ** * *  ***** ** if(c==strlen(a)-1)
* * **  *  ****     *** * **  **   ** * **   ***     * *** *****   **   *  ** *   ** ***  *   *** **    ** *   ******* is a prefix of %s",a,b);
    }
***** ************      * 0;
}
answered by (-498 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <string.h>
int main()
{
*  *     *   *  ** *    *  n,count;
  **   ***** **   * *****    * *   **  * ** **  * **
*  **  ***    *  ** *    *  *  * %s",a,b);
 **** *    **  *** *  ******    *  * 

 *  *******   * * * * * **  *  *   * ******   ******    
**  ** *   ** **** *  ** ** *** 
 ** *  ******    *  ***      ***  * * ****   * ** **** *
 * ***   * *     * *  * 

   ** **** **          *  ** (strcmp(a,c)==0)
*****  * *     **** **  **** 
 *** * ****  *  *  *  * **      *   **  *** * **   *          is a prefix of %s",a,b);
 ** ****      **  **   ***
 *  *   * **** *    ** *   *   *
 *  * * * ***   ** **** 
 * * **  *** * ** ** **** * **** ** *    ** **  *     *  *  * *  is not a prefix of %s",a,b);
      *  * * ***** ** **  *
 *  **   ** * *  *  *  ** *** 0;
}
answered by (-284 points)
edited by
0 0
prog.c: In function 'main':
prog.c:8:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s %s",&prefix,&word);
             ^
prog.c:8:16: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
     scanf("%s %s",&prefix,&word);
                ^
prog.c:10:15: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     for(i=0;i<strlen(prefix);++i)
               ^~~~~~
prog.c:10:15: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:10:15: note: include '<string.h>' or provide a declaration of 'strlen'
prog.c:18:6: error: expected '(' before 'printf'
      printf("%s is a prefix of %s",prefix,word);
      ^~~~~~
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>
int main()
{
 *       * *** *     *** **   a[100],b[100];
*    * ****     ****  ****    *** *****       ** **  
    int l1,l2;
     ** ***    ***    ***** * **   
 *       ** * ** **  ** ******** *  * 
 ** * ****   *   *   *    ******* ** 
   * ****   *   *  * * *  *  *   *****    *   * * ** * * is not a prefix of %s",a,b);

    }
 **      *  **** * ** *     if(l1<=l2){
*  *   *   ****** **   * *    *****   **    *  ** ****     prefix=1;
  * * *** * ** ****** * *     *     *    * ********* * ***** **  i=0;
**** ** ** *  *  *** *  * *   ***  *** * * ***   * * **    *   ** * * *
 ****  *     * ** **  ** *  * **    *  * **  * **  **** * ******* *  *  **  * ** ** **   (a[i]!=b[i]){
 **  *****   *    *  *  ****   *    * ****** ***  *    *** ****  * *  ** **   *  ***     *****  *       *    ** **  *
 *  **    *          ****  *** * *  * *     *** ** **    *   **  *** * * **  ** **   * * * *  * ***  * ****  *   
* **  ***  **  ***    ***  **  ***  ** ***  ** ** ** * ** ***  **    *  **    


  *   **   ******** * *    ****  *  ** **   **** **    ** *
 *  *      * * * *      * **  ****** *   *  **  *  ** * *  *****   * 
* **       **  ** ** ***  * *** **   **  ** * **  *   *   ** ***  ***  **  * ** *  **************** is not a prefix of %s",a,b);
******* * *    ****  ** *****      * **   ** *  * **  *** *** 
*****  * * ** *   * ** * *****   * ***  **  **   **   *   *
** **  ***  ******* * **  *  *  *     *  * *  ** ***     **   * **  is a prefix of %s",a,b);


    }


}
answered by (-329 points)
0 0
prog.c: In function 'main':
prog.c:5:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
             ^
prog.c:5:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
               ^
prog.c:7:8: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     l1=strlen(a);
        ^~~~~~
prog.c:7:8: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:7:8: note: include '<string.h>' or provide a declaration of 'strlen'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:6:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
             ^
prog.c:6:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
               ^
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
*  **  * **   *  * 
int main(void)
{

*** *  *    **  **    ***  *** pre[100];
    * *     * * * **         word[100];
 **   * *  *****  **  **  *  * *  %s",pre,word);
*  * ******  ** * *  **  ** **  ***   *
 * ** * * **   *  *  *  * *   *** **    *

***** *  * * * ** * **    *  * i;
*  * * ****** * ***    * *  ****     *** * *    **
 ***  * *     * ***  **  *  ** 
  **  *** * *** * **  *   ** * ***  ** ** *  * * * **      *   * 
***  * ** * *   * * **  *     ** *  * *    *  ***  * *  
  * * * * *****    ***** **    *   *****  * *   *  *  ****** **** ** *     ** * * * *   is not a prefix of %s",pre,word);
    * ** ***    *  * * **  *  * * ***  ***  * * *  **  * *  **  ******     *     *      ** 0;
****   *  ** ******** * * *** ** ** ** ***   * ** 

  *  * * ** ****  *  
printf("%s is a prefix of %s",pre,word);
return 0;
}
answered by (-249 points)
0 0
prog.c: In function 'main':
prog.c:8:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&pre);
             ^
prog.c:9:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&word);
             ^
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&pre);
             ^
prog.c:9:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&word);
             ^
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <string.h>
#include <ctype.h>
int main ()
{
*  *   ***** ******  ** **** *** pre [100],a[100];
  *   * *****  * *  ** *   ***   n ,i;
  ***    * *  ** **** ****** ***** **** *
*** * *        **   * *  *  * **      ** *
  *   ** * *  **** **  * *   **  * ** ***  ** * ** 
* ***** *    * * *  * *
**   ** **    *   * **   ** * **  * * * *  *   * ** ** *** (n=0;n<strlen(pre);n++)
        *  ** * ** *  ***    *****    **  *    *     
  *    * ** * *    ***     *  ***  ****  **  **      * * **    * **** * (pre[n]==a[n])
* **** ***   **    **  * ** **** *  * ** *     ***** ** ***  * ** ** *  ** **  * **  ***    *  * * is a prefix of %s",pre,a);
*    * * *    ****  ** ** * * **    * *** ***  *** **  *** *  * **   ****  ** *  
**   ***  ** * * ** ****  *   *** *   ***   * *******   *** *  *    *   *    **  * * *    *** * ****  *  ***     ** ** is not a prefix of %s",pre,a);return 0;
**  ***  *  ****  **  **   ***
 * ***** *    * **  *   ** *** ***   **  *     *  ** **  ** **  ** ***  *   * *** * * * 

***  *** **   ** ****    ** *** 0;
}
answered by (-32 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include  ****  **   ** 
#include  ***  *** * *  

int main()
{
  *   **  ******  ***   ***  *   * a[100];

  **   ** * *  ** * ****** ** b[100];

*   * ***** * * * * *  ** *  * ****   ** %s", a, b);

  *** **   *  **** *    len_a = strlen(a);

*** * * * * **  ** *  **   i = 0;

 ** * * * * * *** **      * flag = 1;

  ** * * ** * *     * * *   * *   = 0; i < len_a; i++)
*     *  * * *******  * *  * *** *
****  *     *    ****   ** *  ******    * * ** *   *   *  != b[i])
*** * * *     **     * ***** *  * *****   ***  *   *
* **     ** * *** * *   ****  **  * *  ****** ******* **   *  **** * *** **   *      **   = 0;
** **** * *  * * ***  ** *   *   * * *     *     * * *******   **
     * * *  **  * *  **   

** * ****  * * **  **** *  == 0)
 **     ** *   * * *  ***   ***
 * * **   *** * * * **  ** *    **    * *  * **** * **  * * **  *   is not a prefix of %s", a, b);
   *** *** *  ****   *****  *  
****** *    ***   *  **  
 **  * * ** ******* **
* **** ** * **  **** ***** **** *  **  * *     ** **   *  **  * is a prefix of %s", a, b);
  * **  **    *** *  
** * *** **  ***  *   ** ** 0;
}
answered by (-285 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
** ** **  *   *   *
int main()
{
****  * **  ******   ***   ** * ** i,n;
 ******** * *  *    *  * *** ** p[100],s[100],a[100]={};
*  **  * * ** **  **  *   *  **** * %s",p,s);
 ** *  **  *** ******  * **** *   **   
*** * ***  **** *  * *  * ** ** **  * *
     ** * *    *  *  **   ****    ** *** **      * *
 * ***   ***  *   *** ***  ** ***    
 *    **  **      ***  * * *  *  ** ******** ** *  ***  * *   **   is a prefix of %s",p,s);
**  *** *      ******  *  **  *
**** ******    *   ****** **
    * *   *  * ** * *      **    ** ** * * * *** * *  **  **   * ****  *** is not a prefix of %s",p,s);
 **        * *    * *      * 
 ** ** ** ****** ****  * *    * * * *** * ***** * ***** *   **
 * **  *  ** * ** * *  *   * * * 0;
}
answered by (54 points)
edited by
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>

int main()
{
    int i;
    char a[100];
    char b[100];
   **  *   * *** * * **   **    ******   **   *   
    scanf("%s",b);
    for(i=0;i<strlen(a);i++)
**  *    *   ***        * ****  *  ***   * * *  *** * 
 *****    *****   * **    *   **** * *        *      ***   ** * ** *  *  ** ** != b[i])
* **  ***   * ** *  **** *  ** ****   * *  * **  ** * **  *    *      **       *  **  * * * * ** **    ***
 *****  * **  **  ** ** *  **     * * *    *    *   * **  * *      *  *     *   * *  ** ***  * *   *** **   * ***** **  * *       *  ** *****  * * *   *   **** * * is not a prefix of %s",a,b);
*** *** **   *** **** **  * *   **  * ****  * * *  *** *  * ****  **  *** *  ** **** * ***   * *** * * *****  ** ** ** * ** ****     *
 * **    **** *  * ****  * *     **  *  * * * * ***  *****   *  ****** *** *  ****     ** *   * **   ***
 ** ** *  ** ****  *      **   ** * ****    **** **   * **  *** **   *    ** *  ** ****   == b[strlen(a)-1])
  *** ***   *  **  * *  *   *  * *  * **  ***        *    *  *  * *      **** * *  *  ** *** * *   *** * **    **
*  * *   *** *          ***  **  ***** *   *  * *** **    ** **** ** *    **     **   ** *    ***  *      * * **  *       **   *   *  *  ** *   is a prefix of %s",a,b);
*   ********* *** *   **   **    **    ****** * ******  * *  ****  *    **   ****** **   * * *** *  ** **    * **  * ******** * * * 
*  * * **    *   *  *** * **   **    *   * * ***  *  * *   ** ***     * ** *   *  *    *****   *** * ** ** ***
  **    ** **    **      ***  * * *  ** *******  *  
}
answered by (-301 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<stdlib.h>
#include<string.h>
#define n 100

int aa(char a[],char b[]){
*** ** * ** * * *****   *   * ** ***  ** *  i;
   * *******  *  *** ***   * * (a[0]!=b[0]){
  *        *** * *  *      *  *** *  **   ** *** *****   0;
**   **  *   * ********* * *   *   *   
***   ********  ***   ***** **** * * **    *  ****** * 
 ** **          *   *    ** * *****  **   * ***   *    **  * ***  a[i]==b[i])
* *** * ******** ** * *   **  *  *** *         **   *  
****      * *    * * *     *  * * * *  * **  *** *  *  * **  *     * ***  * *   * 1;
 **  ***    ***  **** ** **** ** * *  ** *  *****   ** * ***    ***  *  *   
  * *  **  *  * *  **  ****  **  ** ** ***** *   *****
***     *     ** * *** *       ** 
 ***  **    * *** ***** * *   * **   0;

}

int main(){
   ** *  **  ** *****    *** c[n],d[n],e[n];
 * *  * * *  ** * **  **    ** i;
 ***  * **    ****  ****  ** *    * %s",c,d);

  *  *   *    * * ***** *** *   * * 
   * ******* *    ***  **    * ***   * *  * *   *     * * * * * is a prefix of %s",c,d);

** *  * **    *     * ****   * 
*******  *    *   *    ****       ** **** * * *** **  * ***  * *  is not a prefix of %s",c,d);


}
answered by (-32 points)
edited by
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.71.255.77
©2016-2026

Related questions

1 like 0 dislike
37 answers
Final Exam 5 (20%)
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42302 - Available when: 2018-01-17 14:00 - Due to: Unlimited | 13.2k views
2 like 0 dislike
31 answers
Final Exam 4 (20%)
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42301 - Available when: 2018-01-17 14:00 - Due to: Unlimited | 12.2k views
1 like 0 dislike
32 answers
Final Exam 3 (20%)
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42300 - Available when: 2018-01-17 14:00 - Due to: Unlimited | 15.1k views
2 like 0 dislike
30 answers
Final Exam 1 (20%)
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42298 - Available when: 2018-01-17 14:00 - Due to: Unlimited | 10.9k views
0 like 0 dislike
4 answers
[Makeup] Final Exam 2 (20%)
[Exam] asked Jan 19, 2018 in Final Exam
ID: 43460 - Available when: 2018-01-20 09:00 - Due to: Unlimited | 2.8k views
12,783 questions
183,442 answers
172,219 comments
4,824 users