1 like 0 dislike
15.8k views

A string p is a prefix of a string s if the leading characters of s are identical to p. For example, "abc" is a prefix of "abcde". Develop a function prefix that checks if a C string p is a prefix of another C string s.

p是s的前綴若s開頭的一段字串等於p。例如,"abc"是"abcde"的前綴。寫一個程式 判斷字串p是否字串s的前綴。

Example input 1:

abc
abcde

Example output 1:

abc is a prefix of abcde

 

Example input 2:

bc
abcde

Example output 2:

bc is not a prefix of abcde

 

[Exam] asked in Final Exam
ID: 42299 - Available when: 2018-01-17 14:00 - Due to: Unlimited

retagged by | 15.8k views

37 Answers

0 like 0 dislike
Hidden content!
#include *** ** * ***
#include *** * * * ** *
** * * * ** **
** **** ******

int prefix(char a[], char b[]){
int i, j,n;
int cnt=0;

n= *** * * ***

*** * ** * * ** *** ** * * ** *
****** ***** ** * * == b[i]){
** ** * ** *** ****** **** * * ** * * **
* * *** * * ** *** * *

* * * *** * **
if (cnt == n){
** * **** *** * * * **** *** ** * ** * * * 1;
** *********** ** * ** * * * *** * * * * **
* ** * * * ** ** * * * ** *
* **** * * ** ** * **** ** ** ** * **** 0;

}

int main()
{
* ****** ******* s1[100], s2[100];
* * *** ** i,j;

** *** ** ***** ** * ****** s1);
* * ** *** ** ** ** * * * * * s2);
* * ** * * ****** ** (prefix(s1, s2)){

* * * *** * ** ** *** * * * ** **** * is a prefix of %s", s1,s2);
** ** ** * * * * ** ** ** ***** *
*** * * * ****** *** * * ***
** ** *** *** ****** *** * * ***** ** * ***** * * ***** * * is not a prefix of %s", s1,s2);



}
answered by (323 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <string.h>

int main(){
*** ** *** * * * * c;
*** * * **** ***** a[100],b[100];
**** * * ** *** *** ******** %s",a,b);
** * *** * *** **** *** * *** * * *
* * * ** ** * ****** ** * ** ** ** **** * * 0;
* * * * ** * *** **** *** * * *** %d",strlen(a),strlen(b));
* * **** ***** * * * * **
***** **** ** *** *** ****** ** ** ** *** ** ************* ***** * ** * ** *
* *** * ** ** ** ****** * *** * * ** * * * * * **** *** * * *** ** ******** **** * * is not a prefix of %s",a,b);
* **** * ** **** * * * * * * * * ** *** * * * * ** ** * ** ** **** * *** * ** * * ** * *
*** **** ******** * * * * *** * **** * * *** * * ** * ****** * * ** * ** **
** ** * *** ******* * *** ** * * * ** * ******* * * * ** ** * * if(c==strlen(a)-1)
** ***** * * * * ***** ** * * * ** ** * * * **** **** ** * * ** * * **** **** * *** ** *** * is a prefix of %s",a,b);
    }
* *** **** * * *** * * 0;
}
answered by (-498 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <string.h>
int main()
{
* * ** *** *** * * ** n,count;
* * ** **** * ****** *** * * * * * * *
** * * ** ** * * * ** ** * %s",a,b);
* * ** * ** * * ***

*** ** ** * * * * * * ***** ** **** * **
*** * * ** * *** **
* ** ** ** ** * * ** * ** * ** * * ** * ***** * ******** * *
** * ** *** * ** * *

** * *** ** * ** (strcmp(a,c)==0)
* *** * ** * ** *
*** ** * * *** * * ***** * **** ** * ** **** is a prefix of %s",a,b);
*** * ** ** ** * *
* * * * ** * * ** * *** *** * **
* * *** *** * * * ** *
*** * ** ** **** ** ** ** *** * * * ** *** * * ** * * ** * is not a prefix of %s",a,b);
* **** * * * ** ** * * * ***
** *** ** **** 0;
}
answered by (-284 points)
edited by
0 0
prog.c: In function 'main':
prog.c:8:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s %s",&prefix,&word);
             ^
prog.c:8:16: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
     scanf("%s %s",&prefix,&word);
                ^
prog.c:10:15: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     for(i=0;i<strlen(prefix);++i)
               ^~~~~~
prog.c:10:15: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:10:15: note: include '<string.h>' or provide a declaration of 'strlen'
prog.c:18:6: error: expected '(' before 'printf'
      printf("%s is a prefix of %s",prefix,word);
      ^~~~~~
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
#include<string.h>
int main()
{
** * ** **** * ** *** * a[100],b[100];
** ** * * **** ** ** ** * * * * **
    int l1,l2;
** * * ******** ** ** * **
* * * ** ** * * * *** ***
**** ** * *** * ***** *
** * *** ****** * ** * *** * ** * ** ***** * ** ** **** is not a prefix of %s",a,b);

    }
* * ** ** *** * * * * if(l1<=l2){
* * *** * ** ****** * ** ** * *** * prefix=1;
*** * ** * * ** **** * * ** * ** * * *** i=0;
*** * * * **** *** * * * *** ** * * * ** ** **
* * * * ** **** * *** ** * ** * * * ** * * * * * * * * * *** * * (a[i]!=b[i]){
* ** **** ** * * *** ** * * * ******* ** * * ** * *** ** * *** **** ****** * * * ** *
* ****** *** * *** * ** * ** * * *** ** ** ** * *** * ** * ******* * * * ** ** * **
**** * * * ** * * * * * ** * * * * ** ** *** ** * ** * ** **


** ** *** ****** ** * * **** * ***
*********** ** * * * * * ** ** * *** * ***** **** *
* * * ***** * ** * ** ** * ** ** * * ** ********** ** * *** ** * * **** is not a prefix of %s",a,b);
** * * ** ** ** * * ** * *** * *** ***** * **
** ******* * * *** * * ** * ** **** * *
** * * * * ********* * ** **** * * * *** * * * * * **** is a prefix of %s",a,b);


    }


}
answered by (-329 points)
0 0
prog.c: In function 'main':
prog.c:5:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
             ^
prog.c:5:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
               ^
prog.c:7:8: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     l1=strlen(a);
        ^~~~~~
prog.c:7:8: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:7:8: note: include '<string.h>' or provide a declaration of 'strlen'
0 0
prog.c: In function 'main':
prog.c:6:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
             ^
prog.c:6:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
               ^
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
* * *** * * **
int main(void)
{

* * * ** ** * ** * ** * pre[100];
** ****** ** *** * *** * word[100];
* * ** * * ** * **** *** ** %s",pre,word);
* *** * *** ******* ***** * * **** *
* **** * *** * * * ***** * * * ** **** * *

** ** * * * ** * * * * i;
* * *** ***** * ** * * ** *
** ** *** * * *** * * *
* * * * * * ***** * * * ** * **** * **
*** *** ** * * ** * * ** * * ** **** **
* * * * * ** ** *** * * * * * * * * * **** ********* * ** ** ******* is not a prefix of %s",pre,word);
**** * * ** * * * * * ***** * * * * **** * 0;
* **** * * * *** ** * **** * * *

* *** * * **** **
printf("%s is a prefix of %s",pre,word);
return 0;
}
answered by (-249 points)
0 0
prog.c: In function 'main':
prog.c:8:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&pre);
             ^
prog.c:9:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&word);
             ^
0 0
prog.c: In function 'main':
prog.c:8:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&pre);
             ^
prog.c:9:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&word);
             ^
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <string.h>
#include <ctype.h>
int main ()
{
**** * ** * ** * **** * *** pre [100],a[100];
* ** **** **** * ** * n ,i;
* *** ** * * **** * ** ****
*** * * * ** *** ** ** **
* ***** * ** *** ** *** ** ** **** ** ***
** * *** * * *
* * ** * ** ** * * *** * * * *** *** * (n=0;n<strlen(pre);n++)
** * ** * ** * * ** * ** *** * * ** * * **
**** * *** * * * ** ** * * * *** ***** ******* * * ** ***** *** * ** * ***** (pre[n]==a[n])
* ** * ***** *** * * * * * ** * * ******* * * * * ** * * ******** * is a prefix of %s",pre,a);
* ** **** ********** * * * * * ** * * * ****** ** ** * * ** ** *
* * ** * * ** *** *** * ****** * ** ** * ** * ** * ** * *** **** **** * * *** *** ** * * * * * * *** **** * is not a prefix of %s",pre,a);return 0;
** * * * * * * * * *
* * * * ** * * * * ** * ***** * ** **** ********** ** *

** ** *** ** * ** * 0;
}
answered by (-32 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include ** * **** **
#include * *** ** * *

int main()
{
** * * * ******** ** a[100];

** **** * * * * ** b[100];

* * ** * ** * *** * ** *** %s", a, b);

** * * ***** ** ** len_a = strlen(a);

** ** ** *** * ** * * i = 0;

**** * * * * * **** * * flag = 1;

* ***** *** **** * * * ** *** = 0; i < len_a; i++)
** * ** *** *** ** ***
** * * * *** * * * ** * * * * * * ******* *** * ** * * != b[i])
** * * **** ***** * ** * * **** * ** *** **
** ** * * ** * ** * * ** * **** * **** * **** *** ** * ** = 0;
* * * *** *** * *** * * **** * *** ****** ** *
* ** ** *** *** * **

* * **** * * * * ** **** * * == 0)
* * * * * * ** *** ** ** ***
** * *** * * ** ** * * ** * * * ** * * * * **** is not a prefix of %s", a, b);
** * * * ****
** * * * * ** * *
** * * * * * ** **
* *** ******* * *** ** * * ** *** *** *** ** *** ** ** ** is a prefix of %s", a, b);
**** ***** *** ** * *** **
** * ******** * ** ** 0;
}
answered by (-285 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
****** * * *
int main()
{
* * *** ******* * * * i,n;
* *** * * * ** ***** ** p[100],s[100],a[100]={};
* *** * * * **** ** ** * %s",p,s);
* * ** * ** * * * *** *******
** * ** ** ** * * *** * ** * * * **
*** * * **** * * *** * * * * ****
** * * ***** *** *** ** ***** *
* * * * *** ** * *** ***** * * **** * *** * ** is a prefix of %s",p,s);
* ** **** * * * * **
* ** *** * * * * * *
* * ** * * *** * * **** * *** ** * * * * * * * * is not a prefix of %s",p,s);
* * ** ** * **
* * * **** ** *** ** *** * * * * ** *
* ********* * ** *** * 0;
}
answered by (54 points)
edited by
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
#include<string.h>

int main()
{
    int i;
    char a[100];
    char b[100];
* * * * ** ** *** ***** ** * *** ** **
    scanf("%s",b);
    for(i=0;i<strlen(a);i++)
*** *** *** ** ** * * * * * ** * * * * *
* * *** * *** ** ** * * * ** * * * * *** *** ** * **** != b[i])
* * ** *** * * **** *** * ** * * ***** ** ** *** * * *** * ***** * ** * ** *
* *** * * ** ** ** ** **** * * *** * * ** ******** ** **** * * ** * ** *** *** **** * * ** ** * ***** * * * ** * ** ** is not a prefix of %s",a,b);
* * * * * ***** * ** * * * * ** * * ** * * *** * ** *** ** **** ** ** **** * * * * * *
** ** ** ****** ** ** * ** * * * * ** ** * *** * ** * * *** ** ** ** * *
** ** * * * * *** ** * ** * * * * **** ** * **** * * *** * * ** == b[strlen(a)-1])
*** ****** * *** *** * *** **** * * *** * ** *** * * * * ** * * **
******* ** ***** * * ** ** * * ** ** * ** * * **** * ** *** ***** * ** * * ** * *** *** ** ** * * * ***** is a prefix of %s",a,b);
* * *** * ********* * * ** *** ** *** ** * * ** ** * * ******* * * * ** * ** * **** *** ** **** *** * ** * ** ** *** *
** **** * * * * **** * *** * ***** * * ** ******** * * * * * ** * * ** * * ****** ** *
* * * * *** ** * * * ** *** ** **
}
answered by (-301 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
#include<stdlib.h>
#include<string.h>
#define n 100

int aa(char a[],char b[]){
*********** * * * ** **** * i;
***** * *** * ** ** * * ** * * * (a[0]!=b[0]){
** * * * ** * * * * * * ** * ** * * * ** *** * ***** 0;
* **** ***** ** *** **** * ** **
* * * * ** *** ** * * ** * ** * * * *
* ** * ***** ** **** ** * *** **** * * ** ** * * * * * a[i]==b[i])
* * * * * ** *** ***** *** * * * *
* * ** * * *** * * *** * *** * ** * ** * ** * * *** * ** 1;
*** * * ** ** * ** * ** * * ** * * * *****
** *** ** ******* **** *** * * ** * * **** * * ***
** * *** ** ** *** * * * **
***** * * ** *** ** * ** 0;

}

int main(){
* * * * ** ** c[n],d[n],e[n];
** *** * * * * *** ** * i;
*** * * * * * * ****** %s",c,d);

*** * ** ** *** * *** * * *
* * * * ** * ** * **** * ** * * * * * ** * is a prefix of %s",c,d);

* *** * ****** * * * ** * *
** *** * **** ** * *** * ** ** ** ** * ** *** is not a prefix of %s",c,d);


}
answered by (-32 points)
edited by
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:104.23.243.109
©2016-2026

Related questions

1 like 0 dislike
37 answers
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42302 - Available when: 2018-01-17 14:00 - Due to: Unlimited
| 14.3k views
2 like 0 dislike
31 answers
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42301 - Available when: 2018-01-17 14:00 - Due to: Unlimited
| 13.6k views
1 like 0 dislike
32 answers
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42300 - Available when: 2018-01-17 14:00 - Due to: Unlimited
| 16.9k views
2 like 0 dislike
30 answers
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42298 - Available when: 2018-01-17 14:00 - Due to: Unlimited
| 11.7k views
0 like 0 dislike
4 answers
[Exam] asked Jan 19, 2018 in Final Exam
ID: 43460 - Available when: 2018-01-20 09:00 - Due to: Unlimited
| 3k views
12,783 questions
183,442 answers
172,219 comments
4,824 users