Final Exam 2 (20%)

1 like 0 dislike
11.3k views

A string p is a prefix of a string s if the leading characters of s are identical to p. For example, "abc" is a prefix of "abcde". Develop a function prefix that checks if a C string p is a prefix of another C string s.

p是s的前綴若s開頭的一段字串等於p。例如，"abc"是"abcde"的前綴。寫一個程式 判斷字串p是否字串s的前綴。

Example input 1:

abc
abcde

Example output 1:

abc is a prefix of abcde

 

Example input 2:

bc
abcde

Example output 2:

bc is not a prefix of abcde

 

[Exam] asked in Final Exam
ID: 42299 - Available when: 2018-01-17 14:00 - Due to: Unlimited
retagged by | 11.3k views

37 Answers

0 like 0 dislike 
Hidden content!
#include ****** **   ** ***  
#include **    **  *
  * **** **** * ******
   *  *  * **   *

int prefix(char a[], char b[]){
int i, j,n;
int cnt=0;

n= * * **    *  

* **  *    *  * *****    ****** *
 *** ** *   *** **** ***   **   *  == b[i]){
 ** *  * *** **  *   *   *    *   * * * * * **  *   *   * ** * 
 ** ***   **  * ** **  * *

* ****   ** * * *   **
if (cnt == n){
       *   *     ***    *** *   ***  *** * * * * **   1;
*** ***  ** ****     * *   *  **  **  **   *** 
 * *  *** * *   ***** *****    *
* *   * ** *  ** * *     *   * ***     * **  * *  * *  ** **   *  *   * 0;

}

int main()
{
*   *   ** *  ****  ** s1[100], s2[100];
*    *   **** **   **      i,j;

   *  *  *** * ** ***  *   *  ***      *  s1);
*** *  *  * ***      *   * * ***** ** **** * *   s2);
     * * *    * *  * (prefix(s1, s2)){

****** ** *****  * *  ** *  *     ***  ** ** *** * ** *   is a prefix of %s", s1,s2);
 *  * *  ** *   * ** *   ***** **   ** ** * **** 
**   ** * *   * ** **** **  * *   *   ***        **
*   * **  *   * ***** *    * ***** **** **  * * **       * *  *  **** *****    ***     is not a prefix of %s", s1,s2);



}
answered by (323 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <string.h>

int main(){
* *   *      ********* ***** * c;
*** **  **** * **  * * * *  *  *   a[100],b[100];
* ** *  *   * *** *** *****     ** *  *  ** %s",a,b);
*    ** ** * *     ***     **  * * *   * * ***** 
***   * * * * * * **   * ***  **   *   *   *****  *   * 0;
 **  ** * ********  **** *    *   ******    %d",strlen(a),strlen(b));
    ** * ** ***  ** ***     ** *   *      ****   *  *
* * * **    ***       ********** * **  *** ***** **      ****  **   ** *  ********  *  *
  **  *** * ** **       ** *** *  * *   * * * **    *  *   **  **  * ** ***      ** * **  ** * ******** *  * ** * ** * ** is not a prefix of %s",a,b);
 **** ** *** * ***  *  *   *  * *  * ***** **** * * *  **    ** *   * *** **** ** *  **   * *** *   * **
 **  ***   *  *   **  *  **    *   * *  * ****  *   * *  *   **** * *   **    * ****  
*  * *** *   *   ** ***  * *   *   ***   *****  ****** ** * *  * *** * * *    ******* if(c==strlen(a)-1)
         *** ** ****   * **    **     ** *  * *   ** * **** * ** *** ***    * * *** *   **  *** *  **  *  * *** *    ***      **  * is a prefix of %s",a,b);
    }
* ****  *  * ** * *    **** *** 0;
}
answered by (-498 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <string.h>
int main()
{
* *   *   ******* ***   * *** *** n,count;
*  *   *     * *  **    **     **  **    ** * ** **  ***** 
  * *   * *  *    ***  * * **  **** * *  %s",a,b);
* ***   *    ** *** ********  *  *

**    ***   *  *  **   **  ** * ****  ** *  ** **    *** * *
  * **    *  * *   * **  *    *
***   *** * ******   * ***  **  *****  ** **     * *   *** ** * *  * *
  ****** * ***   **  ** *

 *  **    ****** ***   *   (strcmp(a,c)==0)
 ****** ** ***   *  * *  ** * 
  *  *****  **    **      ***   ******  *  * * * ***  ** *   * * is a prefix of %s",a,b);
 * *   *      **  **   *
* * * **  * ** ** *** *
 *    * **  * *  ****  ******
  ******   * * * *** *****    * * *   *************  * **    *** ** is not a prefix of %s",a,b);
** **** *  ***    * ****   * 
 ** * * ****   ** *  * **** **** 0;
}
answered by (-284 points)
edited by
0 0
prog.c: In function 'main':
prog.c:8:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s %s",&prefix,&word);
             ^
prog.c:8:16: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
     scanf("%s %s",&prefix,&word);
                ^
prog.c:10:15: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     for(i=0;i<strlen(prefix);++i)
               ^~~~~~
prog.c:10:15: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:10:15: note: include '<string.h>' or provide a declaration of 'strlen'
prog.c:18:6: error: expected '(' before 'printf'
      printf("%s is a prefix of %s",prefix,word);
      ^~~~~~
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>
int main()
{
* **    *  * *      *  ***** * a[100],b[100];
  * *  ***  * **  *    *** * *  * **   *     *    ***  
    int l1,l2;
   * * ** * *  ***** *      ****  
*  *    * *      * * *    *  **** *
*  * *  *   *  * *   * *  * ***   *
 **  *** *** **** ***  ** ** *  **   *   * **   ****   *** is not a prefix of %s",a,b);

    }
**  **** ** *  ** ** *** ***   **  if(l1<=l2){
** * *** *** ****  ** **** **  ** * * ***  **** ** * ** prefix=1;
* * *** *  *    * *  *****   **** * ***  * * *        i=0;
   ***** ***  **** *****  **     * * * ***      **  **  *** * * **
   * **  * * *  *** *     ** ** *   *   * *       * **    * ** * * *** *******  * (a[i]!=b[i]){
  ***   *   ** *   *  **  ***   ** * * *   *    *  *  ****  ***    * * *  *********** ****  * ** *** * *   *   *  * *
* ****  **    * ** * * * *  ***** ** ** *  ***   *****   *** *  ****     * *  *  *       ** ***    *  * * ***  
* ******* *** ****   ***  ***  ** *   * * *  *  ** **** ** * ** ** 


      *  *   * * *    *** * **  *  * ***  **   ****  *   
**  * *  *** ** **** * ****  *** ** *  *****       *   **   * * *
** ***********  ** *  **   **     * * *  *** *    ******    * * ***     **  *    **  * *****   is not a prefix of %s",a,b);
 ********   * * *   *  **********    * ****  **  **
 * ******  *    ****   ***       * ** **  ******       *
  **   * ******    **       **  *** *   * ***  **  *   **** * * *  is a prefix of %s",a,b);


    }


}
answered by (-329 points)
0 0
prog.c: In function 'main':
prog.c:5:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
             ^
prog.c:5:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
               ^
prog.c:7:8: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     l1=strlen(a);
        ^~~~~~
prog.c:7:8: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:7:8: note: include '<string.h>' or provide a declaration of 'strlen'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:6:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
             ^
prog.c:6:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
               ^
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
**** * **    *    ****  
int main(void)
{

**    *    **  **** ****  *   pre[100];
**  * *   *   ** ** * * **  * word[100];
*   *  ***     **  * * ** *** *****  *  **  %s",pre,word);
*  ** *      ** *  *    ** * ***  * *  **
**   * *   * *   *** *  *** * **   *   ***** * *

****** * **** **  ** ** ** i;
 * ***      ** ***  *****  *   ** **   * ** *** *   
*  *  ***   * * ** ** **  
**** * * *    *  *  *  ******   *  ***** ***   * ***    **** 
    * ****  * *  ******  * ****   *  * * * * ** **   **   
* * *  **** **   *   ***    *  ** ****    ** *  *****    **** **** * **   *****  ***  *    ** *  is not a prefix of %s",pre,word);
     ** *   *   *  * *    ***  ** ***  ** *  *  *   * *** * **     *  ****    * **** 0;
   ** *   * *** **** ****   ***  ** *  * **  ** *   

*   *  * * * **           
printf("%s is a prefix of %s",pre,word);
return 0;
}
answered by (-249 points)
0 0
prog.c: In function 'main':
prog.c:8:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&pre);
             ^
prog.c:9:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&word);
             ^
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&pre);
             ^
prog.c:9:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&word);
             ^
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <string.h>
#include <ctype.h>
int main ()
{
 **   * * * ** *   *   * **** pre [100],a[100];
*  **    ******  *  * *  *  * n ,i;
 **   *** * *    ****  * ******    ** *  
 *    ***  * * * *   ** ***** * ** ***  **
*    **  ********  * ** **   *   * * * *  **  ** *
  **  ** *  *  **  *  * *** **  
  **  ***  * * * *  *** *** *    **  **   ****   (n=0;n<strlen(pre);n++)
 *  ****  ** *** ***  ** ***  *****  **   ****
 * **** ****** *** *   ******* * *  * *** *  * **    * ** *  **  * * * **   **** (pre[n]==a[n])
* * * *    * **   **  *   **  ***  ***    ** * *     ** ***     * *  * ** ****    *  ** ** *   * is a prefix of %s",pre,a);
* *   ***   ***    ** *   **   *** ***   *  ** ** *****  *** ** *** **     *  ****
    ***   *** *      **** ***** **** * *****  *  * *  * * * *     *** *****   **   * ** * *   *   *  **  *** is not a prefix of %s",pre,a);return 0;
    * ***  ***** ** **  *
  *       *** **** **  ** * * *** * * ******* ****   *****  * *  *  *** *****    * 

**   * * ** *  *  *** ** ****  **** 0;
}
answered by (-32 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include * *  **   ******
#include    ***    

int main()
{
***   * **   ** *  ***   **   a[100];

* ** ** * **  *****  * * *** b[100];

 ***  *     *  *  ******** *  * *  *** ** * *  ** %s", a, b);

* **  ******   * ***** ** *****  *   len_a = strlen(a);

   *  *** * *  **    * *   * **  * i = 0;

 ***** *   ***      ****  flag = 1;

   * * **   ***      * * ** ***   = 0; i < len_a; i++)
** * *   * ***** * * *  * **
****  *  **   **     *    *   ***** ***  *** * *   * ***** != b[i])
 ** ********    ** *  *** ***  ***   * **  ***  * ***   * 
 *** **** *  **  **     ****  **      ***  *        *******   ******     **    **  = 0;
 *****  **  *********  ***   * **** * * *    ** **
      * * *** *  *   *  

    *    ** * * ** ******  ** * *   == 0)
***    **** * **  * * *
* * ** * *  * *** * *       *****     *  * *   ** ***  *    ** is not a prefix of %s", a, b);
***   *   *  ** *   **  
**  ** *   **   * *  **    ** 
**    **     *   **   * ** *
**  *   * *****     ** *  ** * *** **  **  **   **      *  ** is a prefix of %s", a, b);
*  **   *  *    **   ** *  * *
  ** * ****  *      *   **** ** 0;
}
answered by (-285 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
    ***  ******  * ** *
int main()
{
****   *    * ** ** ***   i,n;
*   ** * * *   **  *  ***   p[100],s[100],a[100]={};
 *** ** **** * **    *    *** **** *  *  %s",p,s);
** ** *********  * * *  * * * * * * ****
 *  * **    *  ****  ****  *** *  **   *
* **   ****   *  **  **     ***** * *******  *         *
*******      **    **   *** **  *  ** **
****   *   * * * * * * *  * **  ***  *   ** *     **    * *  *  *** *  is a prefix of %s",p,s);
*  * *   *       ** *  **  *
********       ****   * ********* 
*** * *   **            * ****          ** ****  **  *     *     is not a prefix of %s",p,s);
* **  ** ********   ** *** * 
****    *** ***    * * ** *  ** ** ** ** * * **   ***** * *
     ** *  ** *** * ** * * * **     0;
}
answered by (54 points)
edited by
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>

int main()
{
    int i;
    char a[100];
    char b[100];
**  *   *** * ** * **    **   *  * * **      *
    scanf("%s",b);
    for(i=0;i<strlen(a);i++)
 *  **  * ** *      *** *  *   * * **  *** ***  ****    * *   *
 **** **  **   * ****   *     * * *** ** * * * *    *   *  ** * ***   * * * * *  ** *  != b[i])
****  ** ** * * *     *  *  *** * **  ** *     **  * * ** * **    *       ****  *   **   **  ** * *
 *      * * *      **    ***  * * ***** **   ** ***  **  ********  ***  **  **  **   * *    *     *** * *** * * ****  * **  *  * **  * **  *  *    is not a prefix of %s",a,b);
* * *****   ** * **  *** ****  *    **** ***    ** ***     *  *****   *   ** * * * *   ******* * ****  * ***  *    *   * *** **** **
 * *  *  * * * *    **   ****   ***  ** *  * * * ** *   ***      ** * * *   **  * * * **** *  **  ** **    
 **  * **** *** ***   ***** ** *** *       *  *  * *** *  * ** ** *  **      * *        *   * *    **** == b[strlen(a)-1])
  ** * **    * **** ** **** ** * *  **  *** ** * ***   * *  **   *       ** ** ** *** *   **   *  ** * *
***    **  *** *  *** ***     * *   **** *** ** **  *   **  **   **  ***   **   ** **      *** **  ****          **  **     ***  * **   ****  ****   is a prefix of %s",a,b);
 * ** * *  * * * **  ** * *  **  * ** *  *** *  ***  * **   ** * ***  ***  * **  *  *   ** ** **  **    * **   * *** **  *      **
 *      * ** *   ***   **  * * **   *  * ** ***  * **  ** **  * *** *  *** * *  **** * **   **  *    **  *  **
   ***** *****    * ****** **  * *  *  *** * ** *  
}
answered by (-301 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<stdlib.h>
#include<string.h>
#define n 100

int aa(char a[],char b[]){
**** *    **   **    ** * * **      i;
**  **** ****  ****  * ** * *   * ** (a[0]!=b[0]){
  ** **   **** * *** * * * **  * *  **** ****** *** ** * 0;
* *    ***    * * * *   ***   ***** 
 ****  * * ****   *  ** ** ***  *  * * * 
** **     *  *  ***  **  ***** *  * ****  **   *** ***   ** *  a[i]==b[i])
** * * *** * * *  **  * *    *** * * *          * ***
  ***  **** *  ** *   *****  ***     ********** *         * **   * *    *  ***  * *  1;
   **  * ** *  * ****************  **  *      **  * ***  **  * ********  *  
* * *  ***  * *  *****    *  ****  ***  ** * *  * * **** * 
 *** *  *    ** *  *  * ** *** * 
*** **  *   *******  *  **  ** **   * * 0;

}

int main(){
*********  **  ** **    *    c[n],d[n],e[n];
   *       *  *  ** *     * ** i;
 *    *  *** * *  *  *  ** **   *    *  %s",c,d);

       *  **** **** ** * * **
 ** *  *** **  ** * ** *   *         *  *  * *  ** *** *** ***  * * ** is a prefix of %s",c,d);

*** *  * ******  ** *   *  * ** 
 ***  * *   *  * *  *  *   *** ***** *** ** * *   **  *       **  * ** *  is not a prefix of %s",c,d);


}
answered by (-32 points)
edited by
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.80.21
©2016-2025

Related questions

1 like 0 dislike
37 answers
Final Exam 5 (20%)
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42302 - Available when: 2018-01-17 14:00 - Due to: Unlimited | 11.3k views
2 like 0 dislike
31 answers
Final Exam 4 (20%)
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42301 - Available when: 2018-01-17 14:00 - Due to: Unlimited | 10.2k views
1 like 0 dislike
32 answers
Final Exam 3 (20%)
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42300 - Available when: 2018-01-17 14:00 - Due to: Unlimited | 11.7k views
2 like 0 dislike
30 answers
Final Exam 1 (20%)
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42298 - Available when: 2018-01-17 14:00 - Due to: Unlimited | 9.2k views
0 like 0 dislike
4 answers
[Makeup] Final Exam 2 (20%)
[Exam] asked Jan 19, 2018 in Final Exam
ID: 43460 - Available when: 2018-01-20 09:00 - Due to: Unlimited | 2.3k views
12,783 questions
183,442 answers
172,219 comments
4,824 users