1 like 0 dislike
4.9k views

A string p is a prefix of a string s if the leading characters of s are identical to p. For example, "abc" is a prefix of "abcde". Develop a function prefix that checks if a C string p is a prefix of another C string s.

p是s的前綴若s開頭的一段字串等於p。例如,"abc"是"abcde"的前綴。寫一個程式 判斷字串p是否字串s的前綴。

Example input 1:

abc
abcde

Example output 1:

abc is a prefix of abcde

 

Example input 2:

bc
abcde

Example output 2:

bc is not a prefix of abcde

 

[Exam] asked in Final Exam
ID: 42299 - Available when: 2018-01-17 14:00 - Due to: Unlimited

retagged by | 4.9k views

37 Answers

0 like 0 dislike
Hidden content!
#include *********
#include *** * ******
** * * * ** **
*** * **** ** * *

int prefix(char a[], char b[]){
int i, j,n;
int cnt=0;

n= ** * **

* * ****** * ** ** ** ** * *******
**** ** * **** *** * == b[i]){
* * ******* **** * * ** **** * **** ** * ** * *
*** * ***** ** * ** **

** *** * * ****
if (cnt == n){
** * * * **** * ****** * ** * ** * * * 1;
**** * ******* * **** **** * * ***** ** * * * * ** * *
* *** * ****** ****** * *
**** * **** **** ** ** ** ** * * ***** ** 0;

}

int main()
{
** ******* s1[100], s2[100];
* * ** * ** * ** * i,j;

** * * * ** ***** * ** * *** s1);
* * ** *** * ** * * * * *** ** ** *** ** * s2);
** *** * * * * *** (prefix(s1, s2)){

**** *** * **** *** * * * * * ** * * * * *** is a prefix of %s", s1,s2);
* ** * ** ** * * ** * ** *** *
* **** ** *** ***** *** * *** * *** *** *
**** *** * ** * * ** * * ** ** *** *** * * *** ** ** * ** * * * ** * ** * ** is not a prefix of %s", s1,s2);



}
answered by (323 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <string.h>

int main(){
* * * *** * * ** * *** ** c;
** ** * * * **** * a[100],b[100];
* ** **** ** * ** * **** * ** * * %s",a,b);
****** ** ** * * ** * * * ** **
* ***** ****** * * * ** * * ** * * *** ** * 0;
* * * * * ** ***** * ** * * * ***** * %d",strlen(a),strlen(b));
** * *** ** * * * *** * * *** **
** **** *** *** *** * * * ** ** ** * * * * * * * ** ***** * * * *** **
*** ** *** ****** ** ** * **** ** * * * ** * *** ******* ** * ***** ***** ** * ** * * *** is not a prefix of %s",a,b);
* ** * * *** *** *** * ** ** * * ***** * * * ** * ** * *** ***** * ** ***** * * * *
* ** * **** * ** **** *** * **** * ** **** **** * * * ** ** ** ****
** * * * * ** *** * * * ** * * *** ***** ** *** * * **** *** * if(c==strlen(a)-1)
* * * * **** ** ** * ** *** * * ** * **** ** ***** **** ** * **** * ** ****** * ** * ** is a prefix of %s",a,b);
    }
** ********* ** **** *** 0;
}
answered by (-498 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <string.h>
int main()
{
* **** * * *** * ***** n,count;
** * *** *** * * ** ** *** **** * * * ***
* * * * * * *** ** *** * * *** %s",a,b);
** * ** *** * * ** *

* * ** **** ***** * ** * * **** ****** *
* *** *** * * * ****** *
* ** * * ** * * * * * *** * * * ** * ****** *
** *** *** ** *** * ** * *

***** ** **** * ** ** (strcmp(a,c)==0)
** *** ** * ** * * *
* * ** ** **** * ** **** * ********* ** ** ** ** * * is a prefix of %s",a,b);
** ** ** ** * ***** ****
** * ** ***** * * * *** *
* **** **** ** *
*** * *** ** * ***** * **** ** ** * ** ** *** * * is not a prefix of %s",a,b);
*** **** ** * * * ******
***** ** **** * *** * *** * 0;
}
answered by (-284 points)
edited by
0 0
prog.c: In function 'main':
prog.c:8:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s %s",&prefix,&word);
             ^
prog.c:8:16: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
     scanf("%s %s",&prefix,&word);
                ^
prog.c:10:15: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     for(i=0;i<strlen(prefix);++i)
               ^~~~~~
prog.c:10:15: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:10:15: note: include '<string.h>' or provide a declaration of 'strlen'
prog.c:18:6: error: expected '(' before 'printf'
      printf("%s is a prefix of %s",prefix,word);
      ^~~~~~
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
#include<string.h>
int main()
{
* * ** ****** * * ******** a[100],b[100];
* * *** ** *** **** *** * ** *** * *
    int l1,l2;
* * * ** * ***** **** * *
** *** *** *** * ** * * * * *
* *** * *** * * * * * *
***** * ** ****** * ** ****** ** **** is not a prefix of %s",a,b);

    }
** * ***** * * ** **** * if(l1<=l2){
* ** **** * ** **** * ***** *** * * * prefix=1;
* * * ******* * * ****** * ** ** * *** * i=0;
* ** *** ** *** **** * * **** *** ** * * * * * *** ** * **
*** ****** * ** ** ** ** * * ** * * * * ** ** ** * ** * * ** (a[i]!=b[i]){
* * ** * * * ** * * * ** *** * * **** **** * *** ** *** **** *** * * **** *****
* *** ** ******** ***** ** *** * * *** * ** * ** * *** * * * *** * **** *** *****
*** **** * ** *** *** * ** ***** **** * **** *** ** * ** *


**** *** ** * * **** ******* *** * ** * *
**** *** ** ** ***** * * * ** ** ** * * ** **** *** *
* ** * * * * * * * * **** ***** ** **** * * * * * * * * * * **** is not a prefix of %s",a,b);
** * ***** ** ** ** * ** ****** ****** * * * *
***** * * ** *** *** * ***** * * * ****** ******
* * * * **** *** * * ** ** ** ** * ** * ** ** * is a prefix of %s",a,b);


    }


}
answered by (-329 points)
0 0
prog.c: In function 'main':
prog.c:5:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
             ^
prog.c:5:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
               ^
prog.c:7:8: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     l1=strlen(a);
        ^~~~~~
prog.c:7:8: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:7:8: note: include '<string.h>' or provide a declaration of 'strlen'
0 0
prog.c: In function 'main':
prog.c:6:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
             ^
prog.c:6:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
               ^
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
** *** ** ** ***
int main(void)
{

* * ** * * * * * *** pre[100];
*** * *** *** * * * word[100];
* * * * ** *** * * * * * ** *** %s",pre,word);
** * * * * ** * * * * * ****** * * * *
*** * ** * * ** **** * ** *** ***

* * * * * ** **** * i;
** * ** *** ** * * * * * ** * ** * * *
* **** *** * * *** ******
** ** * * * * * * * ** ** * * *** * * * ** * *
** ** * ** *** *** ******** *** * * **
**** * * * *** ** **** * * ** * ** *** *** * **** * * * *** ** ** * ** is not a prefix of %s",pre,word);
* * * * * * ******* ** * **** * * *** *** *** **** * *** * ** 0;
** * * * *** ****** ***** ***** *

* * ** **** * ** ** ** **
printf("%s is a prefix of %s",pre,word);
return 0;
}
answered by (-249 points)
0 0
prog.c: In function 'main':
prog.c:8:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&pre);
             ^
prog.c:9:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&word);
             ^
0 0
prog.c: In function 'main':
prog.c:8:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&pre);
             ^
prog.c:9:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&word);
             ^
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <string.h>
#include <ctype.h>
int main ()
{
*** *** * * * *** * * * ** pre [100],a[100];
** * * ** * * * n ,i;
****** * *** * * ** * ** * ** **
* ************ * * * ***
** * ** * * * * * ** *** * * ** * ***
* * ** ***** *****
**** ** ** **** ** ** ** * * ******* * ** (n=0;n<strlen(pre);n++)
* * ** ** * **** ** **** ** * **
* ** ** *** *** ** ** * * *** ** *** **** * * *** *** ** * * *** (pre[n]==a[n])
* ***** * ** * * * * * ** * * ** *** * * *** *** *** ** ** * ******* * is a prefix of %s",pre,a);
**** * *** ** * ** * * *** *** * ** * * * ** * * * *** *****
** * * ** * **** * ***** ***** * ** ** * * * ** * ***** ** * * * * * *** ** * * * * * * * *** * is not a prefix of %s",pre,a);return 0;
* ** **** *** **** *** *
* * ** *** * * * * ** * * * ***** *** *** ****** * ** * * *** ** *

** ** *** * * ** ** 0;
}
answered by (-32 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include ** * ** * *
#include ** *** ***** *

int main()
{
** ** *** * ***** **** * a[100];

* * ** * * *** **** *** ** ** b[100];

** * **** ** **** *** ** ** %s", a, b);

* * * * * * ** * ***** * len_a = strlen(a);

* ** * *** * ** * *** i = 0;

** *** *** * * ****** * flag = 1;

* * * * * * * = 0; i < len_a; i++)
* ** ** * ** * * *
* * *** * * ** * *** * **** * ** != b[i])
* *** **** **** * * * * ** * * *** **** *
****** * **** * * ** * ** * * * * *** * ** ** * * ****** * * * = 0;
* * * ** * ** **** * * * ** * * *** *******
***** * ** * *** ** ***

** **** * * ** ** * * == 0)
* * *** *** * * *
* ** * * * *** ** ** ***** * ** ** ** * ** ** * *** ** is not a prefix of %s", a, b);
* * * * ** ****
*** ***** *** ** ** **
* * *** ********* * * **
*** * ** ** **** ** ** * ** ** ** ** * * * ** ** is a prefix of %s", a, b);
* * ** ** * ** * **** *
* *** * * * ** * 0;
}
answered by (-285 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
****** * * **** ** ** *
int main()
{
* * *** * * ** ** i,n;
**** ** ** * ** *** * * * ** p[100],s[100],a[100]={};
** * * * * * * * * **** * %s",p,s);
** * **** **** * * *** **
* * * *** * * ** ***** ***
** * * * **** **** *** **** **** * **
** * * *** ********** *****
* ** ** **** * * ** * ***** ******* *** **** * *** ** is a prefix of %s",p,s);
** * *** * * **** *
* * * ** ** * *** * * *
** ** * ** ** * *** * ** ** * *** ***** * * * * ****** is not a prefix of %s",p,s);
* * * ** * ** * * *** *
*** ** ** * * * * ** * * * * **** *** * ** **
* * ** * ** ** ** ***** 0;
}
answered by (54 points)
edited by
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
#include<string.h>

int main()
{
    int i;
    char a[100];
    char b[100];
* * * * * *** * *** * ******* * * * * * * * *
    scanf("%s",b);
    for(i=0;i<strlen(a);i++)
* ***** **** * * ** *** ** ** ** * *
* ** ** **** ** * * ***** **** * ** * ***** *** ** ** ** * * != b[i])
***** **** ** * ** ** * * * * * *** * ** ******* ** ******** ****** *** ** *
** ** * ** ***** ** *** ** ***** * ** * * * *** * ** * ** * * * *** * ** **** * * ** * * * * * **** ** is not a prefix of %s",a,b);
* * * * **** ** * *** ****** * **** ** * * ** * * * * * * * * * *** * * ** *** * * * **** **
***** *** * * * * * * * * *** **** * ***** *** * *** * **** * * * ** *** * ** * **
*** * * *** * * * *** ** * * ***** * ** * ** * * * * * * ***** ** *** * == b[strlen(a)-1])
**** ********* ** **** ** **** ** * * * * *** *** *** * * ** *** ** *** * ***** * * **** *
* ****** * *** * ** * * * * **** * * * ***** * * ** *** * * ** ** ***** * ** ** ** * * *** * ********** is a prefix of %s",a,b);
** ** * * * *** ** * * ** *** * * ** **** *** * * *** **** ** ***** * * * * ****** ***** ** *** ***** * ****
**** ** * * * * * *** * * * * ** * * * * * * * * * * ** ** * ****** * ** *** * *
** ** **** * * ** * * *** ** * ** *** **
}
answered by (-301 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
#include<stdlib.h>
#include<string.h>
#define n 100

int aa(char a[],char b[]){
******** ** * ** **** *** *** * i;
** * * * ** * **** ** **** * (a[0]!=b[0]){
** * * * ** * * ** **** ** * * *** * * 0;
* * ** *** * *** ** *
*** ** **** ** *** * ******* ** * * * * * *
* * ***** ** ** *** * * **** * * **** * * * **** ** ** a[i]==b[i])
* **** * * **** * ** *** ** ** **
** * ***** * * * *** * * ** *** * *** * * * **** * *** * 1;
** *** ** * * ** * *** **** * * *** *** ** * *** * * * **** ** *** * * **
* * *** * ** *** *** ****** ** ** * * * ***
* * * ** * * * * * * ****
**** * * ** *** *** * * * 0;

}

int main(){
* * * * ** *** * * *** *** c[n],d[n],e[n];
* * * ** ** * ** i;
****** * * **** **** ** * * * %s",c,d);

* ** * **** * ** * * * * **
* ** * ** * * ** * ** * * * * * ****** * ** * * ** is a prefix of %s",c,d);

*** ** ** ** ** * ** * *
* **** **** ** ** * * * **** * ** * * ** * is not a prefix of %s",c,d);


}
answered by (-32 points)
edited by
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.71.254.39
©2016-2024

Related questions

1 like 0 dislike
37 answers
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42302 - Available when: 2018-01-17 14:00 - Due to: Unlimited
| 5k views
2 like 0 dislike
31 answers
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42301 - Available when: 2018-01-17 14:00 - Due to: Unlimited
| 4.4k views
1 like 0 dislike
32 answers
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42300 - Available when: 2018-01-17 14:00 - Due to: Unlimited
| 4.8k views
2 like 0 dislike
30 answers
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42298 - Available when: 2018-01-17 14:00 - Due to: Unlimited
| 3.7k views
0 like 0 dislike
4 answers
[Exam] asked Jan 19, 2018 in Final Exam
ID: 43460 - Available when: 2018-01-20 09:00 - Due to: Unlimited
| 943 views
12,783 questions
183,443 answers
172,219 comments
4,824 users