1 like 0 dislike
13.1k views

A string p is a prefix of a string s if the leading characters of s are identical to p. For example, "abc" is a prefix of "abcde". Develop a function prefix that checks if a C string p is a prefix of another C string s.

p是s的前綴若s開頭的一段字串等於p。例如,"abc"是"abcde"的前綴。寫一個程式 判斷字串p是否字串s的前綴。

Example input 1:

abc
abcde

Example output 1:

abc is a prefix of abcde

 

Example input 2:

bc
abcde

Example output 2:

bc is not a prefix of abcde

 

[Exam] asked in Final Exam
ID: 42299 - Available when: 2018-01-17 14:00 - Due to: Unlimited

retagged by | 13.1k views

37 Answers

0 like 0 dislike
Hidden content!
#include *** * * * * *
#include *** * ** ****
* * * * * ** *** *
* ** * ***** *

int prefix(char a[], char b[]){
int i, j,n;
int cnt=0;

n= * *

* ***** *** ******** ** ****
** * * ** * * * * * **** == b[i]){
* ** * * * ***** ** ******** ** ** * ** * *** **
* * * * * **** ** * *

*** * * ** *
if (cnt == n){
** * * ** ** ** ** * ***** * ** ******** ** * * * ** ** 1;
** * * * * *** * ** ** ** * ** *** * * *
* ** *** ** ** * **
** * *** ***** * ******* * * * * *** * * 0;

}

int main()
{
* ***** ** * s1[100], s2[100];
** ** * * * * * ** i,j;

* ** * *** *** * * * ** * ** s1);
********* ** * * ** * * **** ** **** * s2);
** *** * *** * * (prefix(s1, s2)){

** *** ** * * *** * * *** * **** ** * ******* is a prefix of %s", s1,s2);
* ** ** ******* ****** * * ** * ** ** *
* * ** **** **** * *** * * * * * * **
* * * * ** **** * * *** * * ** ** ** * * ** * ****** ** * *** is not a prefix of %s", s1,s2);



}
answered by (323 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <string.h>

int main(){
* * * ** * * ********* c;
* *** ** * * ***** *** a[100],b[100];
*** ***** ** ** ***** *** * %s",a,b);
* *** * * ***** ** ** ** ** *
* *** * ** ** * ** * * *** * ** ***** * * 0;
* * * * ****** ** ** **** * %d",strlen(a),strlen(b));
** * * ** ** * * ** * ** ** * **** *
**** * ** * *** ** * * ** * * * ** * *** **** ** * * **** ** *** ** ** *
* *** * **** *** * ** ** * * * **** ** ** * ** ** ***** * ** * * *** ******* * *** * * *** is not a prefix of %s",a,b);
***** **** ** ****** *** *** **** * * ** * * * ** * * * **** * * ******** ** ** * *
**** * *** * ** **** ***** *** ***** * * *** ** * **** ** ****
* *** * * * **** * * * ** **** * ** * *** * *** ** ** * * *** * if(c==strlen(a)-1)
*** ***** * ****** ***** *** **** * ** ** * *** * ** * * * *** * * * ***** ****** *** * is a prefix of %s",a,b);
    }
** *** ** * *** * * ** 0;
}
answered by (-498 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <string.h>
int main()
{
***** * * ** ** **** * ** n,count;
** * ** ** * * ** * *** *** * ** *
** * **** * ** * *** * * %s",a,b);
* *** * ****** * * * * * *

****** ******** * * **** ** * * ******* * *****
** * * ***** * *****
* ** * *** * ** * * * * ** * ***** * **** ** **
* * ** ** ** *** ** *** **

* ***** * *** ** **** * * ** (strcmp(a,c)==0)
*** * * **** *** *
******* * *** **** * ** * ** * ****** ** * ** * **** ** * is a prefix of %s",a,b);
**** * ** *** * *** * *
* **** ****** **** * ** *
******** * * ** * ** **
****** * * * ** * *** * * * * * * ** ** * * * is not a prefix of %s",a,b);
*** ** * ** *** * *
* ** ** ** ** ** ****** ** 0;
}
answered by (-284 points)
edited by
0 0
prog.c: In function 'main':
prog.c:8:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s %s",&prefix,&word);
             ^
prog.c:8:16: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
     scanf("%s %s",&prefix,&word);
                ^
prog.c:10:15: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     for(i=0;i<strlen(prefix);++i)
               ^~~~~~
prog.c:10:15: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:10:15: note: include '<string.h>' or provide a declaration of 'strlen'
prog.c:18:6: error: expected '(' before 'printf'
      printf("%s is a prefix of %s",prefix,word);
      ^~~~~~
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
#include<string.h>
int main()
{
** * **** ** * * a[100],b[100];
* * ** *** *** * * * ** * **** * *
    int l1,l2;
* ** ** * ** *** **** *
**** * *** * * * ***** *
* ** *** * * * *** * * *** ***
****** ** ****** ******* ** ** * ** * * * **** * ** *** *** is not a prefix of %s",a,b);

    }
* ** * * * * * * *** * if(l1<=l2){
* ** * * ** * * ** * * *** * * * ** * * prefix=1;
* ***** * ** ** *** * * **** ** i=0;
** *** **** * *** *** * ** * ***** ** *** * ** * ******
* ** * *** *** * * ** ** * * * * *** * * ** * ** * ** * * ** * (a[i]!=b[i]){
** * * * * ** *** **** * ***** * * ****** ******* ** ** * ** * * ***** ***** ** ** * ** **
*** * ** ** * * * * * * ****** * * * ** ** ** *** *** *** * *** ** * ** * * * **
* * ** ** ** ******** * ** ** * * * * * * * **** * *** * * *** * *


** *** ****** * * * * **** ******** * ** ** * * ** **
* * *** * * * **** ** ** * * ***** ** ****** *** **** *
* * ******** * * ** *** * * **** * *** * * * * * ** * * ***** is not a prefix of %s",a,b);
* * * * ** * * * * * **** **** * * ** **** *
** *** * * *** * ***** ** ** * *** ** * *
*** ** *** * ** ** *** ** * * * * * ** *** * * ******* * is a prefix of %s",a,b);


    }


}
answered by (-329 points)
0 0
prog.c: In function 'main':
prog.c:5:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
             ^
prog.c:5:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
               ^
prog.c:7:8: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     l1=strlen(a);
        ^~~~~~
prog.c:7:8: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:7:8: note: include '<string.h>' or provide a declaration of 'strlen'
0 0
prog.c: In function 'main':
prog.c:6:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
             ^
prog.c:6:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
               ^
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
*** ** ** * * **
int main(void)
{

* * *** * ** * * * * pre[100];
** ** *** * ** *** * * * word[100];
***** ** ** ** *** ** ** * * * %s",pre,word);
** * * * * ** * * * * * *******
** ** * * * ** ** ** * * * * * ****

* * *** * * ****** i;
**** * **** * * * *** ***** * ** * ** * *
** * ** ** ** ** ** * *
* ** * * **** ***** * ** **** ******* ******* * * * * *
** * ***** * * ***** * * * * *** ** **
***** * ** * ** *** *** ** * *** * * * ** * ** * * **** * *** *** *** * ** is not a prefix of %s",pre,word);
* * * * * * * ** ** * * ** * ** * *** *** * ** * * * ** *** * * ***** 0;
* *** **** ** ** ** *** *** ** ** * *

* ***** * * * * ** * *** *
printf("%s is a prefix of %s",pre,word);
return 0;
}
answered by (-249 points)
0 0
prog.c: In function 'main':
prog.c:8:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&pre);
             ^
prog.c:9:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&word);
             ^
0 0
prog.c: In function 'main':
prog.c:8:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&pre);
             ^
prog.c:9:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&word);
             ^
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <string.h>
#include <ctype.h>
int main ()
{
* ***** * ** ** * * ** pre [100],a[100];
*** ** * *** * * * *** * n ,i;
* ** * ** * ******* ** ** ** * *
***** * ***** * * * ****** *** **
* ** * *** **** **** *** * * * * **** * *
** * * * ** * ** ***
* * * ******* * * * ** ** * * ** ** ** * (n=0;n<strlen(pre);n++)
** * ** * * * * ** * ***** * * * * **
* * * ** * * ****** * * ** **** ******* ******** * ** * *** * (pre[n]==a[n])
* * ** * * *** * ** ** ** ** ***** **** * * * *** * * * * ** is a prefix of %s",pre,a);
** *** ** * * ** ** ** * * **** **** * ** *** *** ** * * * * * * * **** **
* * **** * * * ****** * * * *** ** * ** * **** **** **** * * **** ** **** *** * ** * * ** * is not a prefix of %s",pre,a);return 0;
** * **** * * ***
* ** * ** * * ** * ***** * ** ************** ***** ** ** **** **

* * ** * *** **** * ******* 0;
}
answered by (-32 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include *** *** *
#include * ** * ** *

int main()
{
***** * * * * * * ** a[100];

*** * *** **** ** * b[100];

* ** ** * ***** **** * ** %s", a, b);

* * * * ** ***** len_a = strlen(a);

* * * ** * * ** * i = 0;

*** **** * ** * ** * * * flag = 1;

* ** * *** * * = 0; i < len_a; i++)
* * ********* ***** * ***
** * ************ ** *** *** ** *** * *** * ** * != b[i])
* *** * **** *** *** ****** **
** * *** * ******* * *** ** ** * * * * * ** ** ** *** **** ** * = 0;
* ** **** * *** * ** * ** ****** *** * * **
***** ** *** ****

* ** * * * *** ** * == 0)
*** ** * * * * ** **
** ** * ** * *** *** * *** * ** *** *** * * **** is not a prefix of %s", a, b);
**** * * * * * ** *
*** * * *** *** * ****
* * * * ** ** * **
* ****** *** *** * ************ * ** * ** * * *** is a prefix of %s", a, b);
* * * * * * **** **
* ** * * ** ** ** ** * * 0;
}
answered by (-285 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
**** ** *** ** * *
int main()
{
* ** * * ** * i,n;
* * ** *** ** ** ** *** * p[100],s[100],a[100]={};
* ******* * *** ** ** ** *** * *** %s",p,s);
*** * * *** * **** * ** ** *
* **** * *** *** * ** ** *** *
* ** *** * *** ** * ** * * *** *** *
** * **** * * * * ******
* ***** ** * * **** * * ****** ***** ** ****** is a prefix of %s",p,s);
* ** ** ** **** ***
****** *
**** * **** ** *** ******* * *** *** ************ * ** * * is not a prefix of %s",p,s);
****** ** * * * * *
* ** * ** * ** * *** * ** * ** *** **
*** * ** * *** *** * ** 0;
}
answered by (54 points)
edited by
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
#include<string.h>

int main()
{
    int i;
    char a[100];
    char b[100];
****** * * ** * * ** ** * * ** * * ** ** **
    scanf("%s",b);
    for(i=0;i<strlen(a);i++)
* *** ** **** * * * * * * **** * * ** * *
* ** ** * ** ** ** * * ** *** * ** * ** * ** ** ** != b[i])
* * * * * **** **** * ** ** ** ** ** * * * * *** * * ** ** ** * * *** * * ** * *
* * * * * ** * * * *** ** * **** **** * ** * ** *** * * ** ** *** * *** ** * * * ** * * * **** * * * * ** **** ** ** is not a prefix of %s",a,b);
* * * *** * *** * ** ** * * ** * ** ** ** ******* *** * **** ** *** * * * ** ** * ** * * ** ***
* * *** ** ** * * * ** ** ** **** * * * * * ** *** * *** * * * *** ****** * * *
**** *** *** **** * **** ** * **** * ***** ******** * ** ** ** ** ** ***** * == b[strlen(a)-1])
*** ** * ***** * *** * **** ** * * ** ****** * ***** ******* * ** ** * * **** * * **
*** * ** ** * ** * **** * ** ****** ** * ** * *** ***** * * * *** * * *** * * ** ** ** * ** *** * **** * * * * ** * is a prefix of %s",a,b);
* * ***** ** ** * * *** ** * ** ** *** ** * * ***** ** * * * * *** *** ** ** * ** ******** ** * * * **
* * ** * *** * * * * * * ** * * * * * * ***** * **** ** **** * * ******** **** * * *
** **** * * **** * * ** ***** ** * ** *
}
answered by (-301 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
#include<stdlib.h>
#include<string.h>
#define n 100

int aa(char a[],char b[]){
* *** * ***** * * * ** i;
**** **** * * * *** (a[0]!=b[0]){
** ** * ***** * * * ** *** * * * ** * 0;
* * * ** *** *** *** ** * * *
** * *** ** ******* *** * * ****** * ****
**** ** *** ***** ***** * ** * * * ** ** ******** * a[i]==b[i])
** ******* * *** *** * ** ** *********
** ** * ** ** * ** * *** **** ** ****** *** * * ***** * 1;
* * * *** * ** * * * * ***** * * ** * * * * * ** * * * * * * *** * **
** * ** ** * *** ** * *** *
* *** * ** ** *** ** *****
* * * ** * ** *** * * * 0;

}

int main(){
* * * ** * ** * ** c[n],d[n],e[n];
**** ** * *** * * ***** *** i;
** *** ** ** * ** * * *** * ** %s",c,d);

** * * ** ** ** ***
* * ** * ** *** * *** ***** * ** ** ** ** * ** * is a prefix of %s",c,d);

*** **** * **
* ** ***** * ** * * * ** * * ***** * * ** * * **** is not a prefix of %s",c,d);


}
answered by (-32 points)
edited by
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.214.38
©2016-2025

Related questions

1 like 0 dislike
37 answers
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42302 - Available when: 2018-01-17 14:00 - Due to: Unlimited
| 12.6k views
2 like 0 dislike
31 answers
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42301 - Available when: 2018-01-17 14:00 - Due to: Unlimited
| 11.6k views
1 like 0 dislike
32 answers
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42300 - Available when: 2018-01-17 14:00 - Due to: Unlimited
| 13.5k views
2 like 0 dislike
30 answers
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42298 - Available when: 2018-01-17 14:00 - Due to: Unlimited
| 10.3k views
0 like 0 dislike
4 answers
[Exam] asked Jan 19, 2018 in Final Exam
ID: 43460 - Available when: 2018-01-20 09:00 - Due to: Unlimited
| 2.6k views
12,783 questions
183,442 answers
172,219 comments
4,824 users