1 like 0 dislike
8.5k views

A string p is a prefix of a string s if the leading characters of s are identical to p. For example, "abc" is a prefix of "abcde". Develop a function prefix that checks if a C string p is a prefix of another C string s.

p是s的前綴若s開頭的一段字串等於p。例如,"abc"是"abcde"的前綴。寫一個程式 判斷字串p是否字串s的前綴。

Example input 1:

abc
abcde

Example output 1:

abc is a prefix of abcde

 

Example input 2:

bc
abcde

Example output 2:

bc is not a prefix of abcde

 

[Exam] asked in Final Exam
ID: 42299 - Available when: 2018-01-17 14:00 - Due to: Unlimited

retagged by | 8.5k views

37 Answers

0 like 0 dislike
Hidden content!
#include * * * * **** *
#include * ** * ***
* **** ** * ** *
*** * * ** * *

int prefix(char a[], char b[]){
int i, j,n;
int cnt=0;

n= ** * * ** *

** *** * ** * ** ** * * **** ****
* ** ***** ** * * ** *** ** == b[i]){
* ** * * * *** ***** ** * * * *** ***** * **
*** * ** * * ****** * *

* **** * *** *
if (cnt == n){
******* ** ** ** *** * * * ******* * **** ** 1;
* ***** ** * * * ***** *** * ** *
* ** ** **** ** *
* * ** *** * * ** * ** * ** ** * * * 0;

}

int main()
{
* ***** ** * * s1[100], s2[100];
* *** * ** ******* * i,j;

** **** ** ** *** *** * ** **** s1);
* * * * ** **** * * * *** ** ***** * s2);
** * ******* * ** ** (prefix(s1, s2)){

** *** * ** ** * * ** * *** ** ** * * *** *** is a prefix of %s", s1,s2);
*** * ** ** * * ** *** * * * ** * *
* * ***** ** * ** ** ** * * * * * * ******
* * * ** ***** * ** ** * * * * ** * *** ** ** * * **** * * *********** is not a prefix of %s", s1,s2);



}
answered by (323 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <string.h>

int main(){
*** ** * *** *** ** ** ** c;
* * * ** ****** * * **** * a[100],b[100];
*** * * ** *** * *** * * ** %s",a,b);
***** ** ****** * ** * ** *** * ** ******* * ***
*** *** **** * * * * ***** *** *** * * * ** 0;
** * * * * ***** * * * *** %d",strlen(a),strlen(b));
** * ** * * * * ** * ** * **** * * *
** ** * * ****** ** *** *** ** *** ** *** ** ****** ** * * * *** ****** ** ** *
* * * ** ** * ***** ** **** ** * * **** *** ** *** * *** *** **** ** ** ****** * * ** ** * * is not a prefix of %s",a,b);
* * * ** * * *** * *** ** * * * *** ******** **** *** ** * * * * ** * * ** ***
* * *** * **** * * *** * ***** * ***** * * * ***** * *** * ** *
* * * * *** * *** ** *** *** ** * * ** * * ** * *** * if(c==strlen(a)-1)
** *** *** ** ** * ** **** * * ** * *** ** * * ** **** ** ** *** ** * ** * * * * * ** * ** is a prefix of %s",a,b);
    }
* ******* ******* * ** * **** 0;
}
answered by (-498 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <string.h>
int main()
{
* **** **** * *** ** **** n,count;
** * * ** * *** * ** ** *** * * **
* **** * ** * * ******* %s",a,b);
* * * ** ** *** ** **** **

* ****** * * * * * * ** * * * ** *
*** ** * *** * **** * * *
* **** ** ** ** *** * * *** * * * ** *** * ******
** * **********

* ** * **** * * * * ** (strcmp(a,c)==0)
* ***** * ** *** * *
* * *** *** ** ** **** * **** * * * *** * * ** * * is a prefix of %s",a,b);
* *** * ** * ****** *
** ** * ***** * **** * **
**** *** **** **
* * * ** ** **** ** * *** * **** ** * * * ** * * ** is not a prefix of %s",a,b);
** ** ***** * *** * *
* * **** * ** ** ** * ** ** 0;
}
answered by (-284 points)
edited by
0 0
prog.c: In function 'main':
prog.c:8:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s %s",&prefix,&word);
             ^
prog.c:8:16: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
     scanf("%s %s",&prefix,&word);
                ^
prog.c:10:15: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     for(i=0;i<strlen(prefix);++i)
               ^~~~~~
prog.c:10:15: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:10:15: note: include '<string.h>' or provide a declaration of 'strlen'
prog.c:18:6: error: expected '(' before 'printf'
      printf("%s is a prefix of %s",prefix,word);
      ^~~~~~
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
#include<string.h>
int main()
{
**** * **** *** ********* * a[100],b[100];
* ** * *** * * * * ********* * **** * * * * * **
    int l1,l2;
* ** * * ** * * ***
** * **** * * * ** ** * ** * *
** ** * ***** ** * ***
* ** *** * * *** ** * * * **** * * ****** ** ***** is not a prefix of %s",a,b);

    }
* **** ** * ** * if(l1<=l2){
* * ** ** ** ** * * ***** *** *** * prefix=1;
* ** * * **** **** * * *** * *** * **** ** * * i=0;
* ** * **** * * **** ** ** *** * *** * *** *** *
* * ******* * ** ** ** * ** * *** ** *** * * * * * ** (a[i]!=b[i]){
** **** * ** *** * *** * * * * ** ** * ** ** * ** ***** **** * ** * ** * *** *** * **
*** * ** * ** * * ****** *** * * * ** ***** * * **** * ** * * * ***** ***** * * *
* * *** *** ** * * * * * * ** ** * *** * ** *** * * *


** * ** ** * ** *** * **** *** ** * *
* *** * * * ** * *** *** * ** ***** ** ** * * *
* ** ** ****** * ** ** * * * ** * * * ** * *** * * * **** * * * is not a prefix of %s",a,b);
* ** * ****** ** * * ** * * * * * * ****
****** *** **** * ******** * * * **** ****** *** ****
** ** *** **** ** * * * * *** * ***** **** **** is a prefix of %s",a,b);


    }


}
answered by (-329 points)
0 0
prog.c: In function 'main':
prog.c:5:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
             ^
prog.c:5:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
               ^
prog.c:7:8: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     l1=strlen(a);
        ^~~~~~
prog.c:7:8: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:7:8: note: include '<string.h>' or provide a declaration of 'strlen'
0 0
prog.c: In function 'main':
prog.c:6:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
             ^
prog.c:6:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
               ^
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
* ***** * * * * * *****
int main(void)
{

*** * ** * **** pre[100];
** ** ** * * ** word[100];
* *** **** *** * *** ****** ** %s",pre,word);
* *** ***** *** * * * **** * *** *
**** * * * * * *** * * *** * ****

** **** ** * * ***** i;
** *** * * ** * * * ** ** * * * * * ** *
* ** ****** ** * * * *
* * ** * * **** ** * * * * * * ** *** *** ***
* **** * * ***** ** * * * * *** * * ****
*** ***** * **** * * *** * ** * * * ** * * * * *** ** *** ** ** ** ** * * is not a prefix of %s",pre,word);
* ** * ***** * * ** * ** * ***** *** * ** ** * ** * *** ** ** * 0;
** * * * ** ** * *** * * * ***** *

* * * ** * * *** * ** *
printf("%s is a prefix of %s",pre,word);
return 0;
}
answered by (-249 points)
0 0
prog.c: In function 'main':
prog.c:8:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&pre);
             ^
prog.c:9:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&word);
             ^
0 0
prog.c: In function 'main':
prog.c:8:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&pre);
             ^
prog.c:9:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&word);
             ^
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <string.h>
#include <ctype.h>
int main ()
{
*** ** * * ** * ** * *** pre [100],a[100];
* ** ** * * * ** n ,i;
** **** ** * ** ** * * * ****
* * ** * ** * ** * * *** * **** * ***
*** * * * * ** * * ***** * ** *** * * *
** ** **** * * * **
** *** * ** * ** ** * *** ** * ** ******** * ** (n=0;n<strlen(pre);n++)
** ** *** ********* * ** **** ** * **** * *
* * * * * * * **** * **** * * * * * * ****** ****** ** * * **** * (pre[n]==a[n])
***** * * ** * ** * ** *** **** * ** *** *** * * *** ***** * ** ** *** * * * * **** is a prefix of %s",pre,a);
** ** * * ** *** * * ** ****** ** * ** ****** * ** ** *** *** * **
** ****** ** * ** ** *** **** ** * * * * * ***** ** * * * ** ** ** ** **** *** *** ******* * is not a prefix of %s",pre,a);return 0;
* * *** ** ****** * * ****
* ***** * ** **** ** * *** * * ****** * * * *** **** * * * ****

** ****** ** ** * *** **** * 0;
}
answered by (-32 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include ** ** ******* *
#include ***** ** *

int main()
{
* ** ** * ***** *** ** ** ** a[100];

* ** * * * * ** * ** ** b[100];

**** * ** ** ** **** * *** * %s", a, b);

*** * * * * * ** * len_a = strlen(a);

*** ** ** *** * * i = 0;

**** *** ** ** **** flag = 1;

* *** ***** * ** ** * = 0; i < len_a; i++)
* ** **** **** **
*** ** * **** ** ** ** *** *** ** * * ****** **** != b[i])
*** ** * * * * ** *** * *** * *** *** * * * *
* * ** * * * * * * ** ** ** ** * *** *** * *** *** * ** ** ** = 0;
** ** * * * ** ** ** ****** ** ** * * **
** ** **** ** **** *** * **

** ****** ** * * **** * ** == 0)
* ** *** *** *** *** ***
* * * ** ** * *** ** * * ** *** * * *** ** is not a prefix of %s", a, b);
** *** * *** ** ** *
* * * * ***** * * ** * **
* *** ****** *** * *** *
** * *** ** ** ** * *** ** * * * ** is a prefix of %s", a, b);
*** *** *** ****
** * * ** * **** *** **** 0;
}
answered by (-285 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
* ******* ** * *
int main()
{
* * * ** ** ** * i,n;
* ** ** ** * * p[100],s[100],a[100]={};
*** ** * * * ** *********** ** * %s",p,s);
* * * *** ** **** *
* * * * * *** *** * * * ***
** * * * * ** * *** * *** * ** * *** ****
**** **** * * * * ** * * **** *
** ***** * **** * * ** * ** ** ***** * *** *** * is a prefix of %s",p,s);
* ******* ****** * * *
* * ** ** * * * * *
* *** *** ** * ** * * *** * * * * ** ** * * * is not a prefix of %s",p,s);
* ** * **** * ***** * ***
** * *** ** ** * * * *** * * **** ** *
* *** ****** * * *** * **** * 0;
}
answered by (54 points)
edited by
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
#include<string.h>

int main()
{
    int i;
    char a[100];
    char b[100];
** * * *** ** **** ** * * * *********
    scanf("%s",b);
    for(i=0;i<strlen(a);i++)
* **** * *** ***** *** **** * * * * * * * *
* *** * *** **** ***** ***** * * * ** * ***** ***** *** * ** ***** ** != b[i])
* *** **** * ** * ** * * * ** ****** ** ** * *** ** * * *** *** ** ******** ** *** ** * **
* ** ** * * * ** * * **** * * * ** * * ** *** * * ***** ***** * * *** **** *** * ** * * ** ** *** is not a prefix of %s",a,b);
* *** **** ** * * ***** ** ** **** ** * * * *** *** *** * **** ** * * ** ** * * **** *
* * * ** * * * * * * ** ** ** * * *** * *** * * ** ** * * * ** * * * **
* ** **** * ** * * * * **** *** * * ** ******** * ** ** * * * ** == b[strlen(a)-1])
* ** **** *** ***** * ** * ** **** ***** * * * *** *** * * ** * *** * **** **** *****
** * * ** ** *** * **** ** ** * ***** * * * *** * * ***** * * * * * * * ** ***** ***** * ** * *** ** ** * is a prefix of %s",a,b);
*** * ** * * * * ** *** ** **** * * ** ** ** * *** ** ** * ** ** * * * *** * * ** ** * *** *** * * * * *
*** ** * ** *** ** * ********* * ** ** * ** ** ** *** ** ** * ** ** * * ** ** *
** ** ** * * * * ****** ***** * *** **** **
}
answered by (-301 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
#include<stdlib.h>
#include<string.h>
#define n 100

int aa(char a[],char b[]){
*** * *** *** * * *** ** * * i;
* * * * * ** * ** (a[0]!=b[0]){
* * * * * ** * ** * * *** * * * 0;
* * ** * * * * * * * ***
* * * * ** *** **** ***** * * * ** ***
** * *** * * ** ** ** * *** ** *** * * * *** * ** a[i]==b[i])
* ****** * * * *** *** *** * ** * ** * * *
*** * * ** * ** * ** ** * **** ** *** * ***** **** ** *** * * * *** * 1;
* ** ** * ** * *** * * **** * ** * ***** ** ** * ** **** * * ** *
** ** ***** *** ** ****** ** ** * * **
** * * ** * ****** * * *** ** ***
*** * * * * * * * ******* 0;

}

int main(){
* * **** *** * *** c[n],d[n],e[n];
* * ** * *** * *** * i;
* ** * * * * * ** *** * %s",c,d);

* * ** * ** * *** *** *** *
* * * ** ***** * * ** * ****** * * * **** * ** is a prefix of %s",c,d);

* * * ** * *** **** ***
*** * * * ******* * ** * * * ** ** ***** ** ** * is not a prefix of %s",c,d);


}
answered by (-32 points)
edited by
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.71.255.14
©2016-2025

Related questions

1 like 0 dislike
37 answers
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42302 - Available when: 2018-01-17 14:00 - Due to: Unlimited
| 8.8k views
2 like 0 dislike
31 answers
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42301 - Available when: 2018-01-17 14:00 - Due to: Unlimited
| 7.7k views
1 like 0 dislike
32 answers
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42300 - Available when: 2018-01-17 14:00 - Due to: Unlimited
| 8.9k views
2 like 0 dislike
30 answers
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42298 - Available when: 2018-01-17 14:00 - Due to: Unlimited
| 6.9k views
0 like 0 dislike
4 answers
[Exam] asked Jan 19, 2018 in Final Exam
ID: 43460 - Available when: 2018-01-20 09:00 - Due to: Unlimited
| 1.6k views
12,783 questions
183,442 answers
172,219 comments
4,824 users