1 like 0 dislike
2.2k views

A string p is a prefix of a string s if the leading characters of s are identical to p. For example, "abc" is a prefix of "abcde". Develop a function prefix that checks if a C string p is a prefix of another C string s.

p是s的前綴若s開頭的一段字串等於p。例如,"abc"是"abcde"的前綴。寫一個程式 判斷字串p是否字串s的前綴。

Example input 1:

abc
abcde

Example output 1:

abc is a prefix of abcde

 

Example input 2:

bc
abcde

Example output 2:

bc is not a prefix of abcde

 

[Exam] asked in Final Exam
ID: 42299 - Available when: 2018-01-17 14:00 - Due to: Unlimited

retagged by | 2.2k views

37 Answers

0 like 0 dislike
Hidden content!
#include *** * * **
#include * * * * * * **
* ** * * **
* * ** ** ** * * ***

int prefix(char a[], char b[]){
int i, j,n;
int cnt=0;

n= * * **

* ** ** * * * *** ** ** *
* *** **** * * * * * * == b[i]){
** *** ** ** ** * ** ** ** ** * * * * *** ** *
****** * **** *** ** * *

* ** * * * * **
if (cnt == n){
* * * * * * * * ** *** ** ** *** ** * *** 1;
* * * * **** * ***** * ** ** **** * ***
***** * *** ** **** *
**** **** *** *** * * ** * ** ** * * * ** * * 0;

}

int main()
{
* ** ***** ******** * ** s1[100], s2[100];
* *** * * ** ** * i,j;

***** *** *** **** * * ** *** s1);
** *** * * *** * * * * ** ** * * * s2);
* * * ** * * (prefix(s1, s2)){

** * * **** * ** * **** * ** * * * *** * * * * * * * is a prefix of %s", s1,s2);
* ** * ****** ******* *** *** *
** *** * * ** * * * * * *** **
* * * ** ** * * * ****** ** ** * * ** ** ** * *** * ** is not a prefix of %s", s1,s2);



}
answered by (323 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <string.h>

int main(){
* * * *** * * c;
****** * ** * *** * a[100],b[100];
* * ** * * ** *** ** *** %s",a,b);
* *** *** ** ** * ** * ** **
* ** * * ** * ** * *** * *** *** * ** ** * 0;
**** *** * ** ** *** * ***** %d",strlen(a),strlen(b));
* **** ** ** * * * * **** * ** *** * * * *** *
******* * ** ** * **** ** *** *** * * * ** *** ***** ***** * * * * ** * ****
** *** * ** **** *** ** * * ** * ** **** ** ** * * *** ********* * * *** ** ** * ***** * * * * * * *** is not a prefix of %s",a,b);
* ** **** * * ****** ** *** * * ** ** * ***** **** ** * * * * * ** *** *** ** * ** ** * * * *
**** * * * * * ** ** ** ***** * * * **** *** * * *** **** *
*** ** *** ****** * *** * *** * ** * *** ** * * * *** ** if(c==strlen(a)-1)
***** * * **** ** * ** ** * * *** *** * * * ** * *** ** ** **** * ***** * * * * ***** is a prefix of %s",a,b);
    }
** * ** ** * ** * * *** 0;
}
answered by (-498 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <string.h>
int main()
{
* * * **** *** *** n,count;
** * * ** ** ** ** ** * * * * * **
** **** * * ** ** * ** ** %s",a,b);
** ** ** ** * ** ** * *

* *** * ** ** ** * * *** * ** * ** * *
** * ** ** * ** ** *** *
** *** * * * ** * * ** *** ** * * ** ** * *
* ** * * ** * * * ** *

* **** *** ** * * * * * (strcmp(a,c)==0)
** *** ** * ** ** **
** **** * *** * ** ** * ****** * * *** ** *** * is a prefix of %s",a,b);
* * **** ***** ********
* * *** ******* * * * **
** ** ** *** *** *
*** ** ** * ** * ** * * ***** ** **** ** * * * * * is not a prefix of %s",a,b);
* *** ** *** **
*** ***** * ** * *** * 0;
}
answered by (-284 points)
edited by
0 0
prog.c: In function 'main':
prog.c:8:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s %s",&prefix,&word);
             ^
prog.c:8:16: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
     scanf("%s %s",&prefix,&word);
                ^
prog.c:10:15: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     for(i=0;i<strlen(prefix);++i)
               ^~~~~~
prog.c:10:15: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:10:15: note: include '<string.h>' or provide a declaration of 'strlen'
prog.c:18:6: error: expected '(' before 'printf'
      printf("%s is a prefix of %s",prefix,word);
      ^~~~~~
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
#include<string.h>
int main()
{
* * **** * ****** ** * * a[100],b[100];
*** * ***** * ** * * *** * ***
    int l1,l2;
** * ** ** * * * * ** * *
** * ** * ** ***** ** * ** * **
* * ** *** *** *** ** ***
*** *** *** ******* * * * *** * * * * ** * * * is not a prefix of %s",a,b);

    }
* * ***** *** *** ** if(l1<=l2){
* * ** ** ** ** *** * ****** *** ****** **** * ** prefix=1;
* * *** ** *** ** * ** ** ** * * ****** * * * * * ** ** i=0;
* * * * * * *** *** * *** ***** * * * * * * *
*** *** * * ** * * ** * * *** ** * ****** * * *** * **** ** (a[i]!=b[i]){
* ***** * *** * ** * ** *** ** * * **** * ** * **** ** **** * *** *** ** *** * * **
**** * *** ** *** * ** * *** * * * * ** * *** *** ** * * ***** **** * *** *
* * * * * ** *** ** * ** ** *** * * ** ** * *** * ***


* *** ** **** * * ** *** * ** * * * **
** ** ***** * ******** * * ** ** ***** ** * **
* * ***** * * * * * ** *** * ***** * ** * *** * ******* ** * * * is not a prefix of %s",a,b);
* ** * * ** * ** ***** ****** *** ** * * *
*** ** * ****** **** * * *** * ** ***** ** **
***** ** * ** ******** * *** * * * * ** * * * is a prefix of %s",a,b);


    }


}
answered by (-329 points)
0 0
prog.c: In function 'main':
prog.c:5:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
             ^
prog.c:5:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
               ^
prog.c:7:8: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     l1=strlen(a);
        ^~~~~~
prog.c:7:8: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:7:8: note: include '<string.h>' or provide a declaration of 'strlen'
0 0
prog.c: In function 'main':
prog.c:6:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
             ^
prog.c:6:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
               ^
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
** * * *** ** * **
int main(void)
{

* * **** ** * ** * * pre[100];
*** **** ***** ** * *** word[100];
* * ***** ** * * * **** * ** * * * * %s",pre,word);
* * * * ** ******** * ** *** *
*** * **** * * * * ** * **** *** *

* ** * * ** * * * i;
** ** * *** ** * * * * * ** * * * **
*** *** *** * **** *
* ***** ****** ** * * ** * **** * *** * ** * * *
**** *** *** **** * * ******* *** **
** *** ** * ** * ***** * * **** * ** ** * * * **** ***** * *** is not a prefix of %s",pre,word);
*** ** * * * * * ** * * * ** ** *** ** **** * * 0;
* **** * * *** ** * ** ** **** ** * *

** * ** * * *** * * * *
printf("%s is a prefix of %s",pre,word);
return 0;
}
answered by (-249 points)
0 0
prog.c: In function 'main':
prog.c:8:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&pre);
             ^
prog.c:9:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&word);
             ^
0 0
prog.c: In function 'main':
prog.c:8:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&pre);
             ^
prog.c:9:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&word);
             ^
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <string.h>
#include <ctype.h>
int main ()
{
* * * *** * *** *** ** ** pre [100],a[100];
******* * ** * *** * * n ,i;
* * * *** *** * ****** * ** **
** * * * ***** * * * ** * **** *
* * ** **** * * ** *** ** * **** *
* * * **** ******* *** ** *
** * *** ** ** * * **** * * ** ** * **** * **** (n=0;n<strlen(pre);n++)
* * ********* * * ** * ** * ** * * * **
* **** * * * ** **** * * * * * **** * * * ** ** *** * ** (pre[n]==a[n])
* ***** * * **** ** ** ** ** * ** * ***** ** **** * ** *** * * * * * * is a prefix of %s",pre,a);
* * * ** ***** * * * ** ** * ** ** * ***** ****** *** * **** **** * **
* ** * * * ** * ** * ** * ** ** * ** ** * * ** ** * ** * **** *** * ****** * is not a prefix of %s",pre,a);return 0;
** * * ** ** * *** * * *
* *** *** **** ** **** * *** *** * * * * ** ** * * ****** * ** * *

** * ***** * * ** ** * 0;
}
answered by (-32 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include ** * * * ******
#include *** * * ** ***

int main()
{
** **** * ***** ** * ***** a[100];

** * ** ** ** ** b[100];

* ** * ** * ** *** *** * * *** *** %s", a, b);

* * * ** **** ** * len_a = strlen(a);

* ** ** * ** ** * * *** * * * i = 0;

** * * ** * ** ** * ** flag = 1;

** *********** ***** * = 0; i < len_a; i++)
** ***** * * * ** **
** * *** ** * * * * **** *** *** *** **** * **** != b[i])
* * * ***** * **** * * ** * ** * * * *** ** * *
** * * ** * * *** * ** * * * *** * * * * ** * *** * = 0;
****** * * ** ** ** ***** * * ** ** * * ***
** ** ** ****** * *** **

* *** * * ** ** * ** ***** * *** == 0)
*** * ** ** * * * * * *
* * ** * * * ** * ***** *** *** *** * *** ** * ** is not a prefix of %s", a, b);
*** ***** *****
* * * ** * ** * **
**** ** **** * ***** *
** ** ** ** * * *** *** * ***** * * ** **** ** * is a prefix of %s", a, b);
* **** ** ** ** ***
** ** **** ****** * 0;
}
answered by (-285 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
* *** *** * * ****
int main()
{
*** ** * * *** ** ** *** i,n;
* *** ** ** * * * * * p[100],s[100],a[100]={};
** * ** ** ** * * * ****** ** * %s",p,s);
*** ** **** ******* * *** *
* ** * * ***** ** * *** *** *
** ** *** * *** ****** * * * * * * * * **
* * ** ** * ** * * ** ** ** *
** ** *** ** * * *** * **** * *** * * * *** is a prefix of %s",p,s);
** *** ** ** ** * * *** *
** * *** * * ** ** * **
* *** *** * ** * * **** * *** * *** * ****** * is not a prefix of %s",p,s);
* * **** * ** * **
*** ** **** ** *** * ** *** * ***** *** *
** ** * * ** ** ** *** * 0;
}
answered by (54 points)
edited by
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
#include<string.h>

int main()
{
    int i;
    char a[100];
    char b[100];
**** * *** *** *** * ** ** * * ** * * * *
    scanf("%s",b);
    for(i=0;i<strlen(a);i++)
** *** ** * ****** * * * * * ** * * ****
* * * **** *** ** ** ** **** ** * ** * *** * * * *** * * * * *** != b[i])
* * ** * ***** ** * **** * * ** * ** *** *** * ***** *** ** * * *** *** * * ** ** *** **
** **** **** * * * *** ** * * * ** *** * ** ***** ** * * ** *** * *** *** ** * * * ** ****** ** ** *** ** is not a prefix of %s",a,b);
* * * **** * *** * *** *** * *** * ** ** * * * **** * * ** * ** ** ** * ** * * * * ** * ** ** ** * ** * *
** * **** ** * ** * * * * * * ** * * ** * ** * *** ** **** *** ** * ******* ** * * * * *
**** *** ** * ** ***** ** * **** * ** * * ** * *** * * ** * * * == b[strlen(a)-1])
* ** ** * **** * * * *** * * *** ** *** ** **** * * * ** ** ** * * **** *** ** ****
** ******* ***** * * ** * ** ****** * * ** *** **** ******** *** * * * * ** ** * *** * * ** * * ** ** is a prefix of %s",a,b);
*** ** * ** * *** * * * ***** ** * * * ** *** ** ** ** * * ****** ** * *** * *** * ** * ***** ** * **** **
******* ** * ** *** * ** ** * **** *** * ***** ******* * **** ** * **** * * ** * ** *
*** **** ** ** * **** ** ** * * * * ****
}
answered by (-301 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
#include<stdlib.h>
#include<string.h>
#define n 100

int aa(char a[],char b[]){
** *** * *** **** ** * * ***** i;
** * ** * ** * **** * * (a[0]!=b[0]){
* ** **** * * * * *** * ** ** ***** *** * * ** 0;
**** * * ** ** *****
** *** ** ** *** * ****** * * * * ** ** ** ****
** ** **** *** ** ** * *** * ***** ** **** * ** * a[i]==b[i])
* **** ** * ** * ** ** **** * * * ***
* **** ** * * *** ** **** ** ** ** * **** * **** *** **** ****** ** 1;
**** ***** *** ** *** * ** ** * * * **** **** ** ** ** *** ** * * **** *** ** ****
* * *** ** ***** * * * * **** *** ** ** ** *
*** * ** ** ** * **** * * *** *
* * ** * * * * ** ** * * 0;

}

int main(){
** ** * * * c[n],d[n],e[n];
* * ** *** ** *** *** i;
*** * ** *** * * * **** ** * * * %s",c,d);

* * **** **** * ** *
* * * * * * * ** * ** * ** *** * ** * * * *** * is a prefix of %s",c,d);

**** **** *** * * * *
*** * * * * ** * * * * ** * * * ** * ***** * *** is not a prefix of %s",c,d);


}
answered by (-32 points)
edited by
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.100.203
©2016-2024

Related questions

1 like 0 dislike
37 answers
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42302 - Available when: 2018-01-17 14:00 - Due to: Unlimited
| 1.8k views
2 like 0 dislike
31 answers
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42301 - Available when: 2018-01-17 14:00 - Due to: Unlimited
| 1.8k views
1 like 0 dislike
32 answers
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42300 - Available when: 2018-01-17 14:00 - Due to: Unlimited
| 2.1k views
2 like 0 dislike
30 answers
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42298 - Available when: 2018-01-17 14:00 - Due to: Unlimited
| 1.5k views
0 like 0 dislike
4 answers
[Exam] asked Jan 19, 2018 in Final Exam
ID: 43460 - Available when: 2018-01-20 09:00 - Due to: Unlimited
| 446 views
12,783 questions
183,443 answers
172,219 comments
4,824 users