1 like 0 dislike
8.6k views

A string p is a prefix of a string s if the leading characters of s are identical to p. For example, "abc" is a prefix of "abcde". Develop a function prefix that checks if a C string p is a prefix of another C string s.

p是s的前綴若s開頭的一段字串等於p。例如,"abc"是"abcde"的前綴。寫一個程式 判斷字串p是否字串s的前綴。

Example input 1:

abc
abcde

Example output 1:

abc is a prefix of abcde

 

Example input 2:

bc
abcde

Example output 2:

bc is not a prefix of abcde

 

[Exam] asked in Final Exam
ID: 42299 - Available when: 2018-01-17 14:00 - Due to: Unlimited

retagged by | 8.6k views

37 Answers

0 like 0 dislike
Hidden content!
#include *** ** **** ***
#include * * * * *
* **** ** ******
*** * *** *

int prefix(char a[], char b[]){
int i, j,n;
int cnt=0;

n= * * ***** *

** * * **** * ** * **** **
***** *** * * ** *** *** * == b[i]){
*** *** ** * *** ** * ** *** ** * * ** ***
* * **** * *** * *** * **

* ** *** ******
if (cnt == n){
* ** *** ** **** * *** ** * ** * ** * ** *** 1;
*** * * ** * ** ******** * * * ** * * * * *
* ****** * * * *** *
*** ** * * * ** * * * * **** *** * * ** * 0;

}

int main()
{
* *** ***** * * * s1[100], s2[100];
**** ** * **** ** i,j;

*** * * * * ** * ** *** * * s1);
** * ** ** * * * * * * * *** **** * s2);
*** * ** * ** (prefix(s1, s2)){

* * * * * ** * ** * ***** ** * *** **** is a prefix of %s", s1,s2);
***** *** * * * * * ***** ** ********
** * * * * * **** * **** **** * *** ** * *
** ** * **** * * ** * *** * * **** * * ** ** * * * * ** ** is not a prefix of %s", s1,s2);



}
answered by (323 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <string.h>

int main(){
* * ******** * * * c;
*** * * ** * * *** a[100],b[100];
* ** ** *** *** * *** *** %s",a,b);
** * ** ** * * * ** ** * ********* *****
* * * *** ** **** * **** *** * *** 0;
** *** *** ** * * * ***** %d",strlen(a),strlen(b));
** **** * *** * *** *** ** * ***
* ** *** *** * *** * ** * * ** * * **** **** ** ** * * * * ** * **
* * * * *** *** **** ** * *** *** * * **** * * * * * * **** * * ** *** * ******* *** * ** * *** is not a prefix of %s",a,b);
* * *** * * * *** * * * ** ** ****** * * ** ** ***** * **** * ** * ** * ** ** * **** **
* ** ****** * * *** * ***** **** ** * * ** ** * *** * ** * * ****** * *
** *** *** * * * * * * * * ** ** * * ** *** * *** ****** ** if(c==strlen(a)-1)
**** * ** ** *** ** * * ** **** ** * **** ** ** ****** * ** **** ****** * * ** ** ** * *** * * is a prefix of %s",a,b);
    }
**** ****** ** ** * ** 0;
}
answered by (-498 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <string.h>
int main()
{
* * ****** ** * * * ** * n,count;
**** ** * * * * ** *** * * ***
* * * * ** * * *** ** ** * ** %s",a,b);
* * ***** ** *** *** * * * *

*** * **** * *** * * ****** * * * ******
* * * * ** *** *
******** ****** * * ** ** * *** * ****
** **** * * ** * ** ** * *****

** *** * * * * (strcmp(a,c)==0)
*** *** *** * * * *** ** **
*** *** ** ** ****** ** * **** ** ** ** * ** ** ** * is a prefix of %s",a,b);
* * * *** * ** ***
* * * ** * ** **
*** *** * * * **** * * *
* * ** * * *** * ** * ** ** **** * * * * * ** * is not a prefix of %s",a,b);
* *** ****** *** * * ***
** ** *** ** * * * 0;
}
answered by (-284 points)
edited by
0 0
prog.c: In function 'main':
prog.c:8:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s %s",&prefix,&word);
             ^
prog.c:8:16: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
     scanf("%s %s",&prefix,&word);
                ^
prog.c:10:15: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     for(i=0;i<strlen(prefix);++i)
               ^~~~~~
prog.c:10:15: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:10:15: note: include '<string.h>' or provide a declaration of 'strlen'
prog.c:18:6: error: expected '(' before 'printf'
      printf("%s is a prefix of %s",prefix,word);
      ^~~~~~
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
#include<string.h>
int main()
{
*** **** * * **** * * * a[100],b[100];
* * * * * * * *** * *** ** * * *** *** ** * * **
    int l1,l2;
* * * *** ** ** * *** ** ** * * * *
**** ** ** ***** *** ** ** ***
* *** *** *** **** * * ** * * ***
* *** * ** * * *** ******** *** ** * ****** * * * ** * is not a prefix of %s",a,b);

    }
* ** * * ** * **** if(l1<=l2){
** ** * * * ** * * * * ** **** *** ** ** prefix=1;
* ** **** * ** ** * * *** * * * * ** * * i=0;
**** * ** * *** * * * * ** * ** * * ** * ** ** ** **
***** * *** * ** ********* * **** **** * * ** * ** ** * ** *** ** * * (a[i]!=b[i]){
* ** * ** * * * ** *** * * * *** *** ** ** * * * * * *** ** * ** * * * *** ****** *** * * **
* ** ** ** *** * * * * * **** ** ** * **** ** ** ** ** * *** ****** *** * * *** * **
* * *** ** ** * * ** * * * * **** * **** ** * * * * * ** * ** *


* * ** ****** ***** * * * * **** * * *****
** * * * * * * * ** * * * **** * * * ***** * * **
* * ****** *** * ****** ** * * * * ** * ** * * * ** * ** ***** * ** * * * is not a prefix of %s",a,b);
* * ** *** **** *** * ** *** ***** * * **** *
* * ******** **** * ** * **** * ** ***** * * ** * * ****
** * ***** * * **** *** * * * * *** * * *** ***** is a prefix of %s",a,b);


    }


}
answered by (-329 points)
0 0
prog.c: In function 'main':
prog.c:5:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
             ^
prog.c:5:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
               ^
prog.c:7:8: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     l1=strlen(a);
        ^~~~~~
prog.c:7:8: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:7:8: note: include '<string.h>' or provide a declaration of 'strlen'
0 0
prog.c: In function 'main':
prog.c:6:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
             ^
prog.c:6:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
               ^
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
* * * * **
int main(void)
{

* ***** * ** * *** * * ** ** pre[100];
* ** * ** ** *** *** ** ** * word[100];
**** ***** ** ** * *** *** * ** %s",pre,word);
*** ** *** ** ** * * ** *** ***
* ** * * ** ** * *** * ** *** *

*** * * * ** ** *** i;
* * **** * * ** *** * ** ***** * ***
* **** ** * ******** **
* ** * * ******* * ** ** *** * * ** * * *** **
**** *** *** * * * * * * * ** * **** * * *** **
* * * * * * **** **** ***** * * **** * * * ******** * * * * ** **** * ** is not a prefix of %s",pre,word);
**** * ** * ** ** ** **** * ** *** * * * *** ** * * ** * * 0;
***** ** *** * * ** * * ** ** * * ***

** ** * * **** * *
printf("%s is a prefix of %s",pre,word);
return 0;
}
answered by (-249 points)
0 0
prog.c: In function 'main':
prog.c:8:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&pre);
             ^
prog.c:9:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&word);
             ^
0 0
prog.c: In function 'main':
prog.c:8:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&pre);
             ^
prog.c:9:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&word);
             ^
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <string.h>
#include <ctype.h>
int main ()
{
* * * *** **** * * * * pre [100],a[100];
*** * * *** *** **** * * ** n ,i;
**** * ** * ** * * *** * *
**** * * * * ** * * * * *
**** *** ***** * * ** **** ** * ** * *
** * * * *** * * **
** ** * * *** *** * * ** * **** (n=0;n<strlen(pre);n++)
*** ** * * **** * * ** * ** * ** * * * * * * *
* ** * ** * ** **** * ***** * ** * * * *** * **** ** *** * ***** (pre[n]==a[n])
* * ** ** * * *** ***** * *** * * * ** * *** * * **** ** * *** * ** is a prefix of %s",pre,a);
* ** ** * ** ** *** * * * ** *** ** ** * *** ******* ***
* ** * * * * ** * * ** ****** ** * * * * *** *** * * ***** *** * * *** ***** is not a prefix of %s",pre,a);return 0;
**** * ** *** * *
* ****** * ** * ** * *** * * * *** ** *** * *** * **** ***** * ** **

* * ** * ** ** * * **** 0;
}
answered by (-32 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include *** ** *****
#include ** **** ** *

int main()
{
* *** *** * ****** * * a[100];

* * * * * * * *** * b[100];

** * * **** *** *** * * %s", a, b);

** *** * * ** **** **** len_a = strlen(a);

* ****** ********** ****** ** * i = 0;

*** ** * ** **** * * flag = 1;

* *** * ** * ** ***** **** ** = 0; i < len_a; i++)
* **** * ** ** * *******
** * * *** ** * * ** * ** * * ** ** *** != b[i])
*** * * * ** *** * * * ** *** ** *** * ** *
* * * * * * * ** * ** * * ** * *** ***** * **** * *** ** ** ******** *** ** = 0;
* * *** * ** ** * **** ** * *** ** **** *
* *** ** * * * **

* *** * ******** *** * * == 0)
*** * * ** ** * **
***** ** * * * * * * ** * ** ** * * *** * ** ** * * ** * ** * is not a prefix of %s", a, b);
* * ** ** *** *** *
** **** **** * * *
* * * ***** ****** *
* * ** * * ** * ******* ** ** ** **** ****** is a prefix of %s", a, b);
*** * * * * * ****
** * ** ***** ******* * * * **** 0;
}
answered by (-285 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
* ** ** *****
int main()
{
** ** *** * ****** **** *** * i,n;
* ** * ** *** * *** * ***** *** p[100],s[100],a[100]={};
* * * * ** ** **** * *** * * %s",p,s);
* * * ** ******** ** * * *
* * * * * * * *** ** * ** **
* * * * * *** ** *** *** * * **
* * ** ** ***** *** ** * **
* *** * *** ** ** ** * * ****** **** * * * *** **** * ** * is a prefix of %s",p,s);
* * *** ** ***** **** *
* * ** ***** * * ******* * *
* ******* * **** * ** * * ** *** ** *** * * ** * ******* is not a prefix of %s",p,s);
*** * * * * ** * *
* ******* * * ***** * ** ** * * * *****
****** * * * * **** ** * 0;
}
answered by (54 points)
edited by
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
#include<string.h>

int main()
{
    int i;
    char a[100];
    char b[100];
* * * * * ******* * * * * * * ****
    scanf("%s",b);
    for(i=0;i<strlen(a);i++)
*** * ** ***** * * **** * * * *
* *** * ** ** * *** * ***** * * * ** *** * * ** * ** *** ** *** != b[i])
*** * * * ** * * **** * * **** * * * *** *** * ** *** **** *** *** ** * ** * *****
** **** * ** ** * ** * ** ** * ** ** **** *** ** * ** * * ** ** * * **** ** ** * * * * **** *** *** * * is not a prefix of %s",a,b);
* * * **** ** ** **** *** **** * ** ********** ** ** ** * ** * * * ** * *** * * * *** *
* * *** ** * * * **** * ** * **** ** * ** **** * * **** * ** ** * ** ** * * * * **** *
* ** * ** ******* * * * * * ** ** ** * * * ** ** **** ** * == b[strlen(a)-1])
*** * ** **** * ** * * * * * * * **** * * * **** * **** * * * * ** * * *****
* *** ** * ** * ** * ** **** * ** * * * ** ****** * ** ** * * * * ** * ****** ** * * * * * *** *** ** ****** * **** * is a prefix of %s",a,b);
***** ** ****** *** ** ** ** * * * * * ** * ***** *** ** *** ** ******* ** *** * * ******** *
*** * * *** ** *** * *** * ** * ** ****** ** ***** * *** ** * ** *** * * ** ****
*** * ** ** ***** * * ***** * ** * *** **
}
answered by (-301 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
#include<stdlib.h>
#include<string.h>
#define n 100

int aa(char a[],char b[]){
* * ** *** ** ** * * * * * i;
****** **** * * *** ** (a[0]!=b[0]){
* *** * * * ****** * ** * * ****** * * ** * * *** * * 0;
* **** **** * ******** *
* *** * * ** *** **** * ** * **** * *
* *** **** * *** * * ** * ****** ** *** * * * *** a[i]==b[i])
* **** * * * * ****** * * * ** ** ** ** ****
* *** * * **** * * ****** ** * * ** *** ***** ** * ** *** * * 1;
* * * * ****** ** *** * * *** **** * * **** ***** * * ** ***** *
** * * * ********** * * ** *** ** * *
* * * *** * ** ** * *
* * * ** ** ** * * * ***** * * * 0;

}

int main(){
** * * * ** * * ** **** *** * c[n],d[n],e[n];
* *** *** * * * i;
* **** * * * * ** * ** %s",c,d);

****** ** *** ** ** ** * **
*** * * *** *** *** * * * * * ** * * **** ** ****** * **** **** is a prefix of %s",c,d);

* * ** *** *** * * * *****
****** * * * * ** * * **** * ** **** *** ** * * is not a prefix of %s",c,d);


}
answered by (-32 points)
edited by
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.100.185
©2016-2025

Related questions

1 like 0 dislike
37 answers
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42302 - Available when: 2018-01-17 14:00 - Due to: Unlimited
| 8.9k views
2 like 0 dislike
31 answers
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42301 - Available when: 2018-01-17 14:00 - Due to: Unlimited
| 7.8k views
1 like 0 dislike
32 answers
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42300 - Available when: 2018-01-17 14:00 - Due to: Unlimited
| 9k views
2 like 0 dislike
30 answers
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42298 - Available when: 2018-01-17 14:00 - Due to: Unlimited
| 7.1k views
0 like 0 dislike
4 answers
[Exam] asked Jan 19, 2018 in Final Exam
ID: 43460 - Available when: 2018-01-20 09:00 - Due to: Unlimited
| 1.7k views
12,783 questions
183,442 answers
172,219 comments
4,824 users