Final Exam 2 (20%)

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A string p is a prefix of a string s if the leading characters of s are identical to p. For example, "abc" is a prefix of "abcde". Develop a function prefix that checks if a C string p is a prefix of another C string s.

p是s的前綴若s開頭的一段字串等於p。例如，"abc"是"abcde"的前綴。寫一個程式 判斷字串p是否字串s的前綴。

Example input 1:

abc
abcde

Example output 1:

abc is a prefix of abcde

 

Example input 2:

bc
abcde

Example output 2:

bc is not a prefix of abcde

 

[Exam] asked in Final Exam
ID: 42299 - Available when: 2018-01-17 14:00 - Due to: Unlimited
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Hidden content!
#include *  *    *  * *
#include    * * *  *  * * 
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** *   **   * *  * 

int prefix(char a[], char b[]){
int i, j,n;
int cnt=0;

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}

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}
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Hidden content!
#include <stdio.h>
#include <string.h>

int main(){
*  ** **   *  **  ***  * ***** c;
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*** ** ** ******   *  *** ***  0;
}
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Hidden content!
#include <stdio.h>
#include <string.h>
int main()
{
**   ** * * ***    **  ** * **  * * n,count;
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}
answered by (-284 points)
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prog.c: In function 'main':
prog.c:8:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s %s",&prefix,&word);
             ^
prog.c:8:16: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
     scanf("%s %s",&prefix,&word);
                ^
prog.c:10:15: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     for(i=0;i<strlen(prefix);++i)
               ^~~~~~
prog.c:10:15: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:10:15: note: include '<string.h>' or provide a declaration of 'strlen'
prog.c:18:6: error: expected '(' before 'printf'
      printf("%s is a prefix of %s",prefix,word);
      ^~~~~~
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Hidden content!
#include<stdio.h>
#include<string.h>
int main()
{
** **  **  * **  **  ** * * a[100],b[100];
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    }


}
answered by (-329 points)
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prog.c: In function 'main':
prog.c:5:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
             ^
prog.c:5:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
               ^
prog.c:7:8: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     l1=strlen(a);
        ^~~~~~
prog.c:7:8: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:7:8: note: include '<string.h>' or provide a declaration of 'strlen'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:6:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
             ^
prog.c:6:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
               ^
commented by (4.3k points)
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Hidden content!
#include<stdio.h>
* **    *** ** *** ** * 
int main(void)
{

* ***** *     * *****  *  ** *  pre[100];
** * *   ****   **   **    word[100];
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* ** *      ** *** * * **   ***   *  *  *  *****    ***  

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printf("%s is a prefix of %s",pre,word);
return 0;
}
answered by (-249 points)
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prog.c: In function 'main':
prog.c:8:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&pre);
             ^
prog.c:9:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&word);
             ^
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&pre);
             ^
prog.c:9:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&word);
             ^
commented by (4.3k points)
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Hidden content!
#include <stdio.h>
#include <string.h>
#include <ctype.h>
int main ()
{
 *  **   * *** *  **   *  **  * * pre [100],a[100];
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** *  ***  ** * * * *     ****
 ** * * *  * * **  **  **  * **   * *  * ** *   *     *   *  * * **     **** ***   

*******      **** **      *   * 0;
}
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Hidden content!
#include <stdio.h>
#include *** * * **    
#include  *  ***    * 

int main()
{
   ***  *   ** * * *     * ** a[100];

 *  ****   *  **   *** ***** ** b[100];

 ** ***          *      *****     *  * * *  %s", a, b);

* *  ***    *    ** *  ******** len_a = strlen(a);

*    ***  * ** * ** *** ******* * i = 0;

  ****   *   ***  ****  flag = 1;

 *    * * ** ***  **   *  ** **  = 0; i < len_a; i++)
***  * * ***     ** ** * **** 
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* **   ** ****   * **** **** *    ***  * *      * ** 
   **   ****** ****  * *   

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 * * **  **** **** **  * **    
**   *  ***   * *  * ******  **  * * *** **  ******    * *   *  **  is not a prefix of %s", a, b);
 **  **  ** * * **** *** * 
  *   * ***    * *  ****** * * *
  *    *     *   * *
***  *****  *        *****   ****  * *   *** * ***      **      **    * ** is a prefix of %s", a, b);
* **   * *    *  ***  *  * 
*   ****  *   * * * ** *** *  **  * 0;
}
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Hidden content!
#include<stdio.h>
**   **  *****   ** * 
int main()
{
   *  *** ***  *** ** **      i,n;
**  *** *  *** ** **            p[100],s[100],a[100]={};
* ******* * * ** *    * * * * ****  %s",p,s);
   *   **  * ** ***  ***   **    
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   *   *    *   * * ***   ** *    ** *   **  ******
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 ***** ***  ** ** * * *  * 
***  ** * * **  *  *  **   *  ** * *  * * * ** **   
 ****     ****  *   ** *  * **   0;
}
answered by (54 points)
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Hidden content!
#include<stdio.h>
#include<string.h>

int main()
{
    int i;
    char a[100];
    char b[100];
   **   *** ** *   *   ****    **** ** **    ***  *
    scanf("%s",b);
    for(i=0;i<strlen(a);i++)
 ****  *  **  *** ** *    ** **  ******** ***   *
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  ***   **** *   *  * *   *****     **  **** ******     * ******** ** * ** *  * *** * *     * == b[strlen(a)-1])
* *   *        * * **  *  * ** **  *   **  *** *   **  **    **  *  ***   **** *   * *  ***   ***** ** * *   * 
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 **    * * *  * ****** * * *  *  *  ** ******  * *** **   * *  * * *  *** **   * **  ** ** ***  *      *  ***   *     * ** *******
**  *    *   * ***  *   * **  **   **    *  * ******  *   * *     ******   ** *  **  **    * ** ** **    **  *    *  
*   ******* ** * **   *    **** *  **  * *  *   ** *  
}
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Hidden content!
#include<stdio.h>
#include<stdlib.h>
#include<string.h>
#define n 100

int aa(char a[],char b[]){
**    *  *  *  ****** * **    **** ** i;
 *  *    * ***  **** ********* *  **   (a[0]!=b[0]){
   ** *** * * ** * *** * **         **       *  *  **  * 0;
**   * **********  *  ****** * *
* *  *      ***** **     ***** ***   * *   ***
** ***** ** ***       ** **** ******   ** *** * ***  *  ** a[i]==b[i])
**  ***  **** * ***  ****  *   * *** *  **  ***  **  
 **  ** **  ****  *  ** * **  * ***** * *  ** **** *****   ***   * *** * *  *** * * * * 1;
** * **   **   * *  * **    **   *** ** **   **  ***  *****  ** * **  **  *******
    * *****     ******   *   **   ** ***    **** *  *  **  *** 
 **** * *** * *        ***   **  ***
 ** **** **    * * * ** ** ***  **  ******   0;

}

int main(){
***  *  *  ***  * *  *  *  ** c[n],d[n],e[n];
 *   *  * * *** ***  **     i;
  **     **     **  * ****  ***** ***** %s",c,d);

   **** ** ** *  *** ***** *  ** * * 
* ********   * * *   **  * *  * *  * * *  ** * ** ** **     * *  is a prefix of %s",c,d);

 *     *****   * ******* *
*    **   ** * * * **   ** **  *  * **  **     *  ** *  ****    ****** * is not a prefix of %s",c,d);


}
answered by (-32 points)
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