1 like 0 dislike
13.2k views

A string p is a prefix of a string s if the leading characters of s are identical to p. For example, "abc" is a prefix of "abcde". Develop a function prefix that checks if a C string p is a prefix of another C string s.

p是s的前綴若s開頭的一段字串等於p。例如,"abc"是"abcde"的前綴。寫一個程式 判斷字串p是否字串s的前綴。

Example input 1:

abc
abcde

Example output 1:

abc is a prefix of abcde

 

Example input 2:

bc
abcde

Example output 2:

bc is not a prefix of abcde

 

[Exam] asked in Final Exam
ID: 42299 - Available when: 2018-01-17 14:00 - Due to: Unlimited

retagged by | 13.2k views

37 Answers

0 like 0 dislike
Hidden content!
#include * * * **
#include * * * * ** **
** *** *** ***
* *** * *

int prefix(char a[], char b[]){
int i, j,n;
int cnt=0;

n= ** * *

** ** ** * * *** * * * *****
* **** * ** ** **** **** == b[i]){
*** ** *** ** * * *** ** ** ** * *** * ***
* * ** * * * *** * ***

****** * * * * *
if (cnt == n){
** ** ** * ** * **** * ** ** * *** * 1;
*** * ** ** * ** ** ** ** * ** **
*** * ** * * * *** ****
* * * * * ****** ** **** *** ******* * * 0;

}

int main()
{
*** * *** ** *** ** s1[100], s2[100];
* **** * * **** * i,j;

*** * ** *** *** *** * *** ** * * s1);
***** * * * ** ****** * ** * ** * * ** * * s2);
** *** *** * ** *** (prefix(s1, s2)){

** *** * *** ***** * * * * ** * * *** *** * * is a prefix of %s", s1,s2);
* ***** **** * **** * ** ** *** ***** *
* * * ** * ** *** * **** ** * * * * **
** ******* ***** * ** *** * *** * * * **** ** * **** ** ** is not a prefix of %s", s1,s2);



}
answered by (323 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <string.h>

int main(){
* * ** * **** ** *** c;
** **** * * *** ** * a[100],b[100];
* * * *** ** * *** *** * %s",a,b);
* * **** *** *** ** * * *** ** **
** ** * * **** * * * ** * ** ** *** ** * * 0;
*** ****** *** ****** * * * * ****** %d",strlen(a),strlen(b));
* * * * **** *** * * * **** * ***
** * **** * ** *** ** * ** *** ** ** ***** * ***** **** * * *** *** * ** *
** ** ***** ** **** **** ** * ****** *** ***** **** *** ** * *** ** * ** ** ** ** **** *** * **** ** is not a prefix of %s",a,b);
** * * * *** * ** *** *** ****** * ** * ******* ******* * * *** * *** ** *
** ** * ** ** *** ** ** * *** * * ** ** * ******* * * *
** **** * ***** ** * * *** * * ** * * ** *** *** * * * * * ** if(c==strlen(a)-1)
* * ** * * * **** * * ** ** * ** * * * * * ** ** * * ** * * * *** **** ** * * ** *** ** *** ** * ** is a prefix of %s",a,b);
    }
* * ** * * * * *** * 0;
}
answered by (-498 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <string.h>
int main()
{
**** *** ** ***** * ** * n,count;
** **** * * ** * ** **** * **** * *
* ** * * * * *** * ** *** ** %s",a,b);
* *** ** * ** **** * * **

******* * ***** * * * * *** * * * ** ** * *
***** * *** *** * ** ****
*** * * ********* * * * ******* **** * *** * * * *** * * *
* *** *** * * * *** **** *

**** *** * **** *** * * (strcmp(a,c)==0)
* * * ** ** ****** *****
* *** ***** * * * ***** * * ** * * ****** * * * * * is a prefix of %s",a,b);
* * ** ** ** *
*** ** * ***** ** * * * *** * **
* * * ** * ***
** ***** * * * *** * * * * * ****** * * *** is not a prefix of %s",a,b);
* *** ***** * * ****
** ** **** * * ** 0;
}
answered by (-284 points)
edited by
0 0
prog.c: In function 'main':
prog.c:8:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s %s",&prefix,&word);
             ^
prog.c:8:16: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
     scanf("%s %s",&prefix,&word);
                ^
prog.c:10:15: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     for(i=0;i<strlen(prefix);++i)
               ^~~~~~
prog.c:10:15: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:10:15: note: include '<string.h>' or provide a declaration of 'strlen'
prog.c:18:6: error: expected '(' before 'printf'
      printf("%s is a prefix of %s",prefix,word);
      ^~~~~~
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
#include<string.h>
int main()
{
* **** * * * ** * * ** a[100],b[100];
*** **** *** ** ** * * * * * * * ** *
    int l1,l2;
** ** ** * ** * * * ** **
** * ** ** *** ******** ***
** **** * * * * ** * ** * * * *
******* * * *** ** ***** * * **** *** * * **** ** * *** is not a prefix of %s",a,b);

    }
*** **** *** ***** *** ** if(l1<=l2){
* * ***** * * * * * * * * * ** * * ** * * * prefix=1;
* * * ********* ** *** * ** ** ** * ** * i=0;
* * ** ** ** *** * * ** * * ** * *** **** * * *
***** *** * * * ** *** * * * ** * * ****** **** ** ** * * * *** * * (a[i]!=b[i]){
** * * * ** * * ** * * ** * ** **** * * *** * * ***** ******* ***** * * * * * *
* * ** *** ** ** * ***** * **** ** ** **** * *** * ** * * ** ****** * ** **** **
** ** * * * * * *** * * * * * ** * ** ** *** * * *


** * ** ***** * * * ** * * * ** * **
*** *** ** * * ** * *** * *** ** **** ** *
**** * * ****** ** * * **** * * * * * *** * ** * * * * * *** **** ** ** * is not a prefix of %s",a,b);
** *** ** * * * **** ************ * * ** * * * **
* * * ** ** * * ** *** *** * ******** **
******** * * * * * ** * * ** * ** ** *** * * * * *** * ** * is a prefix of %s",a,b);


    }


}
answered by (-329 points)
0 0
prog.c: In function 'main':
prog.c:5:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
             ^
prog.c:5:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
               ^
prog.c:7:8: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     l1=strlen(a);
        ^~~~~~
prog.c:7:8: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:7:8: note: include '<string.h>' or provide a declaration of 'strlen'
0 0
prog.c: In function 'main':
prog.c:6:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
             ^
prog.c:6:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
               ^
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
* ** * **** *
int main(void)
{

**** * * ** *** **** ** * * pre[100];
* * * * *** **** * *** word[100];
* * * * * * * ** * ****** %s",pre,word);
* * * ** ** ** * ***** * * **
** *** * * ** * * ** ** ** ** **** * *

* ****** ** *** * i;
* * *** ** * * * * ** * * *** * ** *
* ****** * * * * * *
* * *** * * ***** ** ******* * ** * ** ***** ** * ***
* * * ** * * **** * ** ****** ** * ** * *
* *** ** * *** *** * ** *** *** * ** * * ** * * ***** ** * * ** ** * * * * is not a prefix of %s",pre,word);
* * ***** * * ** ** *** ****** ** ** * ** ** **** *** * ***** * * *** 0;
* * * * * * *** *** *** **** * * ** * *

* * * **** ** * * *
printf("%s is a prefix of %s",pre,word);
return 0;
}
answered by (-249 points)
0 0
prog.c: In function 'main':
prog.c:8:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&pre);
             ^
prog.c:9:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&word);
             ^
0 0
prog.c: In function 'main':
prog.c:8:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&pre);
             ^
prog.c:9:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&word);
             ^
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <string.h>
#include <ctype.h>
int main ()
{
* *** * * ** * * ** pre [100],a[100];
** * * * * ** ******* * n ,i;
* * **** * ** * * * ** ** **
* ** * ** * *** * * * * ** *
* * * ** ** ** * **** ** ** *
** * * * ** ** ***
*** * * * * * *** * * ****** * ********* (n=0;n<strlen(pre);n++)
** *** * *** * * * * * * ** * *** * * **
* * *** ** * ** * ** *** *** ** *** **** * * * ** **** *** (pre[n]==a[n])
***** * * ** * * * * * * *** * * * ** *********** * * *** *** * * is a prefix of %s",pre,a);
**** * ** * * ** * ** *** ** *** * * ****** * **** * ** * ** ***
* ** ** ** ******** * * * **** **** * * * * ** ** * ** * *** * * ** * ** * * * * * * * *** is not a prefix of %s",pre,a);return 0;
****** ** * * * *
** ******** * ** * * *** *** ** ** **** * * * * * * ** *

** * * * * * * ** * * * 0;
}
answered by (-32 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include ** **** * ***
#include *** ** ** *

int main()
{
*** * * ** *** ** ** ** a[100];

* ** * * ***** ** * b[100];

* **** * * *** * * ** *** %s", a, b);

* *** * ****** * ** * * * len_a = strlen(a);

* ************** * * ** i = 0;

* ** * ** * ** flag = 1;

* *** * * * ** * * * = 0; i < len_a; i++)
* *** *** * * * * * ***
**** ***** **** * * *** * * * *** ** ** != b[i])
* *** * ********* ** **** **** *****
**** * **** ** * ** ** ** ** *** * **** * * * ******* ** ** * * * * * ** * = 0;
* * ** *** * ** * *** *** * ***
** * * ***** ** * * ****

* ** * * * * * ******* == 0)
***** * * ** *** ** *
* ** ** * *** * * * *** * * * * * * ** * ** * ** is not a prefix of %s", a, b);
* * * * ** * ** *** * ***
** * ** **** ** *** *
* *** ** * **
** ** * *** * **** * **** ** ** * ******* * ** ** is a prefix of %s", a, b);
* * ** **** * * * ***
*** * ** * * ** *** 0;
}
answered by (-285 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
* *** * ** * * * *
int main()
{
* * *** **** ** * * * * i,n;
*** ** * * ** * * * *** p[100],s[100],a[100]={};
** * * *** *** ***** **** %s",p,s);
* ******* * * * ** * *** * * *** * *
** ***** * ** * * * * * * *
* * *** ** * ** * ** ** * * **
* * ** ** * ***** * ** * * *
* * *** * * * ** * ** ** ** * *** ** ** * is a prefix of %s",p,s);
** ***** ** * ** * ***
* ** ** * * ** ** *
** * * *** ** *** ** * * ** *** * * * * ** ** * ** ** is not a prefix of %s",p,s);
******** ** *** * ****
* * ** * * ** * ** * * * ** * * * ** *** * *
******** * * * * ** ****** 0;
}
answered by (54 points)
edited by
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
#include<string.h>

int main()
{
    int i;
    char a[100];
    char b[100];
*** * ** **** * **** ** ** **
    scanf("%s",b);
    for(i=0;i<strlen(a);i++)
**** ****** *** * *** * * * * * ** ***
*** **** * * * ** * ** **** *** * *** * *** *** * * ** * ** != b[i])
* * * ******** * * * * ******* * * * * * * * ** *** * * * * ***** * ****** * *** ** **
** * ** * * ** * * * *** * * ** ** **** * * * ** * *** **** ** ** * * * * * * * ** * * * * ** ** * **** * * ** * *** is not a prefix of %s",a,b);
** * * *** * ** * * *** * * * *** ** * ** ** * ** * ****** ******** * * ****** ** * * *** * ** **
** *** ** ** ***** * * ** * * * * * * ***** ** ** * ** ** * * ** ***** * * * * * * * ** **
* * * * ** * * ***** * ** *** * * * * **** * * ** *** *** * * * * *** == b[strlen(a)-1])
* * ** ** ** ** * ** **** ** * ***** ** ****** ******** * * **** ** *** ** ** ***
* * ***** * * * * ** *** * * * * * * *** * * * ***** *** * *** ****** * ** ** * * * * ** * *** * **** is a prefix of %s",a,b);
** * **** ** **** * ** ********* ***** * ** ***** * ** ******* **** *** *** *** *** ** ** * ** ** * *** * ** *** ***
**** ** **** ******* * * * **** * * * ****** **** ** * **** * *** ** * ** ** ******
** ** * ** ** ** ***** * * *** ** * *
}
answered by (-301 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
#include<stdlib.h>
#include<string.h>
#define n 100

int aa(char a[],char b[]){
* *** * ** * * ** *** *** i;
* ** * ** * * ** (a[0]!=b[0]){
** ** * ** * *** * * ** ****** * * ** 0;
**** ** * * * *** * *
**** * * ** ***** * * ***** *** * ** *
*** ** ** **** * ****** * * * * * * * *** * * * * **** a[i]==b[i])
* ** ** ***** ***** ****** * * * ** * *
* *** * **** * * * * * *** ***** ** * ** * * **** **** * ** * *** 1;
* ** ** * * * * *** ** **** ** ** * * * * * *** ** * * *** * * *** *
*** ********* * * ** * ****** * * * * * *
* *** * * * *** ** * *
* *** * * ** * * * ** **** 0;

}

int main(){
*** * * ******** * * * c[n],d[n],e[n];
***** * * * *** *** i;
* * *** ** ** * *** * ** %s",c,d);

* * ***** ** * *** * ** * *
*** * ** ******* * **** ** * * ** ** ** *** * * * * is a prefix of %s",c,d);

** * * * ** ******* * **
* * ** * ****** **** * **** * ** ** * *** * ** ** * * is not a prefix of %s",c,d);


}
answered by (-32 points)
edited by
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.50.50
©2016-2025

Related questions

1 like 0 dislike
37 answers
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42302 - Available when: 2018-01-17 14:00 - Due to: Unlimited
| 12.7k views
2 like 0 dislike
31 answers
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42301 - Available when: 2018-01-17 14:00 - Due to: Unlimited
| 11.7k views
1 like 0 dislike
32 answers
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42300 - Available when: 2018-01-17 14:00 - Due to: Unlimited
| 13.8k views
2 like 0 dislike
30 answers
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42298 - Available when: 2018-01-17 14:00 - Due to: Unlimited
| 10.4k views
0 like 0 dislike
4 answers
[Exam] asked Jan 19, 2018 in Final Exam
ID: 43460 - Available when: 2018-01-20 09:00 - Due to: Unlimited
| 2.7k views
12,783 questions
183,442 answers
172,219 comments
4,824 users