1 like 0 dislike
12k views

A string p is a prefix of a string s if the leading characters of s are identical to p. For example, "abc" is a prefix of "abcde". Develop a function prefix that checks if a C string p is a prefix of another C string s.

p是s的前綴若s開頭的一段字串等於p。例如,"abc"是"abcde"的前綴。寫一個程式 判斷字串p是否字串s的前綴。

Example input 1:

abc
abcde

Example output 1:

abc is a prefix of abcde

 

Example input 2:

bc
abcde

Example output 2:

bc is not a prefix of abcde

 

[Exam] asked in Final Exam
ID: 42299 - Available when: 2018-01-17 14:00 - Due to: Unlimited

retagged by | 12k views

37 Answers

0 like 0 dislike
Hidden content!
#include * * ** * **
#include **** **** * *
****** ****** ** ** * *
* ** *** * ** **

int prefix(char a[], char b[]){
int i, j,n;
int cnt=0;

n= * * *

* ** * *** * *
*** * * ** * *** ****** * * == b[i]){
** * * * *** ** * **** * * *** ** * **
* * ** * * * *

*** ** * ** * **
if (cnt == n){
* * ** ** * ** *** *** ****** * ** *** * 1;
** **** * * * ** * * * *** * * * * ** * *
** ** * * **** * ***
** * * *** *** **** * ***** * **** * * ** ** ** *** * 0;

}

int main()
{
*** * * ***** * *** * s1[100], s2[100];
*** * * * ** * i,j;

* ***** * *** ** * ** *** s1);
* ** * ** *** ** ** ** ** ** * ** ** s2);
* * ** * * * ***** * (prefix(s1, s2)){

* **** ** ***** * ** * * ** ** *** * ** **** is a prefix of %s", s1,s2);
* ** *** ** * *********** ** ** ****
* * ** * * * * *** **** ** * * * * ** *
* * ** *** *** ** *** * *** * **** **** *** * * * ** * * is not a prefix of %s", s1,s2);



}
answered by (323 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <string.h>

int main(){
* * * * ** * * * c;
** * ** * ** **** * * * ***** a[100],b[100];
** *** ** * *** ** * ** * * %s",a,b);
** ** ** * *** * ** * ** * ***** *
*** * ** * *** ** * * **** * ** 0;
* ***** * * ** * *** * * ** * * * * %d",strlen(a),strlen(b));
* ** * * ** ** * * * * *** ** ** * * ***
*** ** *** *** * * * * * * * *** * *** ** * * ** *** * * * ** ** ***** ***
* **** ** * ** * * ** ***** ** * * ***** ** * ** ** ** * ** * * *** * * * * * * ** ** *** **** ** is not a prefix of %s",a,b);
*** **** * * * * * *** * **** * ** ** ** * ** **** ***** * ** * * ** ** * ** ** * * ** *
** *** * **** ** * ** * * ** ** ** * * * * * * * ***** ** ** **
** * * * * ** * * * ****** ** * * * ** *** **** ** * if(c==strlen(a)-1)
* ****** ** ** *** ** * ** * * ******* * * *** **** * * **** ** ***** ******** ** * ** * * ** is a prefix of %s",a,b);
    }
* **** * * * ** * * * * 0;
}
answered by (-498 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <string.h>
int main()
{
* * **** * *** *** ** n,count;
* ** * ** * ** ***** * ** * *** ** * *
* ** ** *** *** ***** * ** **** * **** %s",a,b);
** *** * * ** ** * *** **

*** * * ***** * *** * ****** *** ** *
* *** * ** ** ****** ** * *
***** ** * * * * **** * ** ** *** ** * * * * *
* ******* * * * * * ** *

***** *** ** ** * ** ** * (strcmp(a,c)==0)
* * * ** ** * ** * ****
*** ** * ** * * * * * * *** * *** **** * * ** ** * is a prefix of %s",a,b);
* * * ***** * ** * * *
** ** * * ** * ****
*** * * ** ** *** * **
* ** **** *** * * ** * * *** ** * ** *** * ****** is not a prefix of %s",a,b);
* ** ******* * *** * *** *
* * * *** * * **** * 0;
}
answered by (-284 points)
edited by
0 0
prog.c: In function 'main':
prog.c:8:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s %s",&prefix,&word);
             ^
prog.c:8:16: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
     scanf("%s %s",&prefix,&word);
                ^
prog.c:10:15: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     for(i=0;i<strlen(prefix);++i)
               ^~~~~~
prog.c:10:15: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:10:15: note: include '<string.h>' or provide a declaration of 'strlen'
prog.c:18:6: error: expected '(' before 'printf'
      printf("%s is a prefix of %s",prefix,word);
      ^~~~~~
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
#include<string.h>
int main()
{
* * ** *** * *** a[100],b[100];
****** * * *** * * ** **** ** * ** ** *
    int l1,l2;
* ** ** ** *** ** * * ****
****** ** ** * * * ***** * * *
* ** ******* **** ** ** ** **
*** ** *** * ****** ***** * * **** ** * ** ** ** ** * is not a prefix of %s",a,b);

    }
*** * * ** *** ***** * * if(l1<=l2){
** ** ** ** * * ***** * ** * **** * * **** prefix=1;
* * *** * ** * *** * *** * * * * * * * * i=0;
* ** * * * ** * ** * * ** * * **** **** * *** * * * ***
**** *** * * ** *** * * * ** * ****** ** *** * * * * * * ******* (a[i]!=b[i]){
*** *** * *** * * * * ** * * ** * * * ** ***** *** *** *** * **
**** * *** * * ** * ** ** ** * ** *** *** ** ** * * * *** * * * * * * * ** * **
* * ** * ** * **** ** * * * ** ** ** *** *** * ***** **** * ***


*** * *** * * * * **** ** ** *** *
** * * * * ** *** * * * * * * *** ** **** **** * *
* ** * * **** * * ** *** ** * * * * ** *** * ** * ***** ** *** * * ** ********* is not a prefix of %s",a,b);
**** * * * ** * ** *** * ** ****
* ** ** ** * * * ** ** ** * ** * * ** * **
* * * * * * * * **** ** ** * * * * ******** * is a prefix of %s",a,b);


    }


}
answered by (-329 points)
0 0
prog.c: In function 'main':
prog.c:5:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
             ^
prog.c:5:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
               ^
prog.c:7:8: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     l1=strlen(a);
        ^~~~~~
prog.c:7:8: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:7:8: note: include '<string.h>' or provide a declaration of 'strlen'
0 0
prog.c: In function 'main':
prog.c:6:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
             ^
prog.c:6:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
               ^
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
** * * * * * *****
int main(void)
{

****** ***** * ** * * * ** pre[100];
** ** * **** ***** * word[100];
** ** ** ** ** * ** ******* %s",pre,word);
** * * ** *** * * ** ** * ** *
** * * ** * ** * * *** ** * ****

** * **** *** **** * * i;
* *** ** ** ** * * * * **** * * ****
** ** *** ** *****
** * *** * * * * * * * ** ** * ** * * * *
* * *** ** * * * *** ** * ** **** * *** *
***** *** * ********* * ** ** * ** ******* ** ** * **** * **** * * ** * *** *** is not a prefix of %s",pre,word);
** ***** ** * * **** *** * ** ** * * ****** ** * * * **** ****** * * ** 0;
*** ** * * ** * *** ** ******* ** * ***** **

*** * *** *** * *
printf("%s is a prefix of %s",pre,word);
return 0;
}
answered by (-249 points)
0 0
prog.c: In function 'main':
prog.c:8:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&pre);
             ^
prog.c:9:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&word);
             ^
0 0
prog.c: In function 'main':
prog.c:8:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&pre);
             ^
prog.c:9:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&word);
             ^
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <string.h>
#include <ctype.h>
int main ()
{
** * ***** * * ******* pre [100],a[100];
* ** ** ** * * ** *** * n ,i;
* * * * * ** **** **** *
** ** **** *** * * ** * ***
* * * ** * * * * * * * *** * * * * * ** * *
* ******* * * * ** ** * * *
* *** ***** * * ** *** * ** *** *** * ** (n=0;n<strlen(pre);n++)
**** ** ***** ***** * ** * ** * ** * ** **
* * * ** * * * * ** ** ** ** * *** ** **** ** * * * * *** (pre[n]==a[n])
******* * * *** * ** **** * *** **** ** ** ** ** ****** * * ** ******** *** * is a prefix of %s",pre,a);
** * * ** * * ** ** **** ** * ****** **** ** ** * * ** * ** *** *
** ** **** *** * * ** **** * **** *** * ******** * ** ******* * *** ** ** ** **** * ***** * is not a prefix of %s",pre,a);return 0;
* **** ** ** ***** * *
** ** * ** * ** * ****** ********** **** *** ***** * *** * * ****

*** **** * ** * * ** * *** 0;
}
answered by (-32 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include ** * * *** * *
#include * * * ** * *

int main()
{
** *** ** * ** *** * * a[100];

* ** * ***** * *** * *** **** b[100];

*** ***** ** * * *** * ** ** * * %s", a, b);

** * *** ** ** * * * len_a = strlen(a);

* ** * * *** * ***** ** ** i = 0;

** * ** * ** * * ***** flag = 1;

***** * ***** ** * = 0; i < len_a; i++)
** ** ** * ** ** * **** ********
* * *** ** * *** ** ** ** * * * ** ** ** != b[i])
** ** ** * *** *** * * * *** * ** ****** * * **
* * ** ** * * ****** * * * * * * ** *** *** ** ** ***** *** = 0;
* * *** * * **** * * * * * ** * ** ***
* ******* *** **

** * * *** *** == 0)
* *** ** ** * * *
** * ** * * * ** ** * **** ** * ** * ** is not a prefix of %s", a, b);
** *** ** ****
* * * ** *** *** ***
** * ** * * ** ** *
** * ** * ** ** * * * ** * **** *** * *** * ** ** * is a prefix of %s", a, b);
* * * *** * * * *
* ** * *** **** ******* * 0;
}
answered by (-285 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
* * * ** *** *
int main()
{
* ** * *** * * * *** * i,n;
** *** * *** * p[100],s[100],a[100]={};
** * *** ** ****** * * ** %s",p,s);
***** ***** * * ******* * ** ***
** **** ** **** * ** ** ** **
* **** * ******** * ** ***** *** * * ** ** * *
** * ***** *** **** ** * ** * ** *
* * * *** * * ** * *** * * * * * * *** * * ** ** ** ** is a prefix of %s",p,s);
** * * ** * * **** ***
* **** *** ** * * * * * *
*** ** ****** * **** **** ********* *** * * ** ** * * is not a prefix of %s",p,s);
***** * **** * * ***
**** ** * * *** * * * *** * * * ******* * *** ** **** **
** * ** ** ** ******* 0;
}
answered by (54 points)
edited by
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
#include<string.h>

int main()
{
    int i;
    char a[100];
    char b[100];
** ** * * * ** * ** *** ** * ** *
    scanf("%s",b);
    for(i=0;i<strlen(a);i++)
** * * *** * * * * ** ** * * ** *
******** * * * *** ** * * ***** * ** *** * * * ** ** * != b[i])
* * * * * ** * *** ** * * * *** * ** ** * ****** * ** * ** * * ** **** * * ***
* ** * * ** * * * **** * * *** **** ** * * * *** ** *** *** ********* * *** * * ** * * * ******** * ** * *** * * ** * is not a prefix of %s",a,b);
* * ** * * * ** * * ********* * ** *** * ** * **** ****** ***** * **** * *** ** *** ** *
**** * * ** * ***** * * *** * * ** * *** **** * * ** * * * * ** ** * * ** * ** *
* * * ** ** * ******* * * ** * *** ** * ** * ***** * == b[strlen(a)-1])
*** ** * ** ** * ** * * ****** *** * * ** ** * * * * * * * *** * *** ** ** ** * * ***
* ** * * ** * ******** * * ** ** ***** ** * ** * ** * *** * * * * ***** *** ** *** ** * ** * *** * * *** ****** * * is a prefix of %s",a,b);
* * *** ** * * ** * **** * ** * * * * ****** **** ** ** * * * ** * ****** ** * ** **** * ** **** ** * **** ****
* * *** * *** **** * *** * *** * *** * **** ** **** ** * * * **** *** ** * * * **
** *** * * *** * * * ** **** * * * ** * *** **
}
answered by (-301 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
#include<stdlib.h>
#include<string.h>
#define n 100

int aa(char a[],char b[]){
* ** * **** *** * * ** ******* * i;
** **** * * ** * * * **** *** (a[0]!=b[0]){
* * *** ****** ** ** ***** ** ** *** *** *** * 0;
** **** * * * ** * *** *
* ** *************** * ** ** * * * * * ****
** * * ****** **** **** * *** ***** * * **** ** ** ** a[i]==b[i])
** *** * *** **** * ** * ******* *
** * * ** *** * * * *** * * **** **** ** * *** **** ** * ** * 1;
** ** * ** * * *** *** **** * ** * **** ** ** * * *** * **
* ** ** ** *** ** * ** * *** * *** * **
** * * **** ** * *
**** * * *** * *** * ** ** 0;

}

int main(){
* * ****** ** ** ** ** *** c[n],d[n],e[n];
** ** * * * *** * * * * i;
** * ** ** *** ** ***** * ** %s",c,d);

** ***** * * ** ** ** ***
*** * ****** ** * * **** * * ** * * * * * * * ** ** is a prefix of %s",c,d);

* * *** ***** **** **
* * * * *** ***** * * ** * ** *** *** * is not a prefix of %s",c,d);


}
answered by (-32 points)
edited by
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.127.67
©2016-2025

Related questions

1 like 0 dislike
37 answers
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42302 - Available when: 2018-01-17 14:00 - Due to: Unlimited
| 12k views
2 like 0 dislike
31 answers
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42301 - Available when: 2018-01-17 14:00 - Due to: Unlimited
| 10.9k views
1 like 0 dislike
32 answers
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42300 - Available when: 2018-01-17 14:00 - Due to: Unlimited
| 12.1k views
2 like 0 dislike
30 answers
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42298 - Available when: 2018-01-17 14:00 - Due to: Unlimited
| 9.7k views
0 like 0 dislike
4 answers
[Exam] asked Jan 19, 2018 in Final Exam
ID: 43460 - Available when: 2018-01-20 09:00 - Due to: Unlimited
| 2.5k views
12,783 questions
183,442 answers
172,219 comments
4,824 users