Final Exam 2 (20%)

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A string p is a prefix of a string s if the leading characters of s are identical to p. For example, "abc" is a prefix of "abcde". Develop a function prefix that checks if a C string p is a prefix of another C string s.

p是s的前綴若s開頭的一段字串等於p。例如，"abc"是"abcde"的前綴。寫一個程式 判斷字串p是否字串s的前綴。

Example input 1:

abc
abcde

Example output 1:

abc is a prefix of abcde

 

Example input 2:

bc
abcde

Example output 2:

bc is not a prefix of abcde

 

[Exam] asked in Final Exam
ID: 42299 - Available when: 2018-01-17 14:00 - Due to: Unlimited
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Hidden content!
#include *  *   *   ** 
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int prefix(char a[], char b[]){
int i, j,n;
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}
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Hidden content!
#include <stdio.h>
#include <string.h>

int main(){
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}
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Hidden content!
#include <stdio.h>
#include <string.h>
int main()
{
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}
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prog.c: In function 'main':
prog.c:8:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s %s",&prefix,&word);
             ^
prog.c:8:16: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
     scanf("%s %s",&prefix,&word);
                ^
prog.c:10:15: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     for(i=0;i<strlen(prefix);++i)
               ^~~~~~
prog.c:10:15: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:10:15: note: include '<string.h>' or provide a declaration of 'strlen'
prog.c:18:6: error: expected '(' before 'printf'
      printf("%s is a prefix of %s",prefix,word);
      ^~~~~~
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Hidden content!
#include<stdio.h>
#include<string.h>
int main()
{
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    }


}
answered by (-329 points)
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prog.c: In function 'main':
prog.c:5:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
             ^
prog.c:5:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
               ^
prog.c:7:8: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     l1=strlen(a);
        ^~~~~~
prog.c:7:8: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:7:8: note: include '<string.h>' or provide a declaration of 'strlen'
commented by (4.3k points)
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prog.c: In function 'main':
prog.c:6:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
             ^
prog.c:6:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
               ^
commented by (4.3k points)
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Hidden content!
#include<stdio.h>
***    ****   *  *    ***
int main(void)
{

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printf("%s is a prefix of %s",pre,word);
return 0;
}
answered by (-249 points)
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prog.c: In function 'main':
prog.c:8:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&pre);
             ^
prog.c:9:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&word);
             ^
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&pre);
             ^
prog.c:9:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&word);
             ^
commented by (4.3k points)
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Hidden content!
#include <stdio.h>
#include <string.h>
#include <ctype.h>
int main ()
{
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***** ** *   **  *  * 
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*    * * *      ***          ***    0;
}
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Hidden content!
#include <stdio.h>
#include     *  ** *** * **
#include **    ** * **    *

int main()
{
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*   **** ** *  * *   * **** *
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 **  * *******      *****
** *** *  * * *  *   **  **   
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**   ***  *** ** ***** **   **
 ** **   *  ****   ***    * 0;
}
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Hidden content!
#include<stdio.h>
* ** ***  **** *    *  
int main()
{
  *  * * * * *** * ****** * i,n;
*  * *** ******  *     *     p[100],s[100],a[100]={};
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***  *** ********       **
 ** **   ****  * **   ** ****   *  ***** * ** **  ***  * ** 
**    **  ***** * ***  * **  * *** 0;
}
answered by (54 points)
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Hidden content!
#include<stdio.h>
#include<string.h>

int main()
{
    int i;
    char a[100];
    char b[100];
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*   ***   * **  *  *    *  *  ****   *** * *    *  **   * 
}
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Hidden content!
#include<stdio.h>
#include<stdlib.h>
#include<string.h>
#define n 100

int aa(char a[],char b[]){
     ****** * ***  *   **  **    *** i;
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  *  ***   ** ** ** **    ** **      ***** ** ******* *  * **   *   *    a[i]==b[i])
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 ***    **  *************     * * * **       *   ***
* *   *    * * *  ******* *  *
 * * ** *  ******  **** **  **    * *     0;

}

int main(){
*   *     *  * ** **** ** * *** * c[n],d[n],e[n];
 **  *   * *    **  ** **    i;
 *   ****  ****   *  ***  * ***   * ****  *   %s",c,d);

****    * *  *  **  ** *  *  * ** * 
* **  ** * **  *** * * **   **   ** ** **  * *  ***  * **   * *  ** * is a prefix of %s",c,d);

***** *      * *******
  *  **    ** *******      * * ** ******     * *  * *** ***  ** ** is not a prefix of %s",c,d);


}
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