Final Exam 2 (20%)

1 like 0 dislike
8.8k views

A string p is a prefix of a string s if the leading characters of s are identical to p. For example, "abc" is a prefix of "abcde". Develop a function prefix that checks if a C string p is a prefix of another C string s.

p是s的前綴若s開頭的一段字串等於p。例如，"abc"是"abcde"的前綴。寫一個程式 判斷字串p是否字串s的前綴。

Example input 1:

abc
abcde

Example output 1:

abc is a prefix of abcde

 

Example input 2:

bc
abcde

Example output 2:

bc is not a prefix of abcde

 

[Exam] asked in Final Exam
ID: 42299 - Available when: 2018-01-17 14:00 - Due to: Unlimited
retagged by | 8.8k views

37 Answers

0 like 0 dislike 
Hidden content!
#include   * * ** ** *  **
#include * *  * *   * *  **
 ***  ** *  ****** 
  *  * *** *    *    *

int prefix(char a[], char b[]){
int i, j,n;
int cnt=0;

n=  * *    ** **

*  *  *   **  *  * ****    *    *  **  **
   * ** **** **  * **   * *** *  == b[i]){
     *  **  ** ******** *** * **  **  **   * * ** * * *****
* * *    ** * *    *   * ** ** *

******   * *  *  *   
if (cnt == n){
 *   ****       * *   ** * ***   *    * **   **** ** * 1;
* ***  *  *   *** * **   * ******** * ******   * * *
   *****  * ***  ** * *  * 
 *  ****** **** *  **     *   *  **** *       *     *****    0;

}

int main()
{
****  *  *  ***     **** s1[100], s2[100];
       * * ******   * *    i,j;

  ** ***    *** *** ** ** ***  *  ** * s1);
****  * **  ** *  *** *** *******    * ** * * * s2);
*  * **    * **   (prefix(s1, s2)){

* *  *** * ** ***  ** *    ** * ** **  * **   *       **  ** *  is a prefix of %s", s1,s2);
***  *        * **  **     *** * *   ***** *
* * ******  *   **  * * ***** ** ****  * ** **  **** 
  ** ** * ****  * *  *    * ** * **  ** *  *    *   * * ** *     *   ** *  *   is not a prefix of %s", s1,s2);



}
answered by (323 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <string.h>

int main(){
  * *     *  * *** *    **  * *** c;
**      * **** *  ****  *    ***  a[100],b[100];
* * **     ** *  * *  * *** ** * * %s",a,b);
 *  ** *  *  * *     * ***  * * *   *  *** *** 
***  ** ** * * ** * ******** * * * **   *  *    * ** * * 0;
* *   **  **  * ** *  * * **** ** ****  %d",strlen(a),strlen(b));
*****  ** ***  * ** **     ** *  *  * *
***  * *   ******  *  ****   * * * *** *   * **  *   *  **********  * *  * **   *  ***** *****
   ** **** *    *** * * * * *** *  * ** *** *   ********* ** * *   * **    ***  **   *   ***  ***  ****** * *  is not a prefix of %s",a,b);
  * **     *    ***** **** *  * *** ** ****   **   *   ***  * *        **    ** * * *******    *** *  **  ** ******** ** 
** **  *** * ***     * ***     *  * *  * *  *****  * * **   ***   *  **  ** ** **  *
***   * *  ***     * *  *** **   * *   **  * * * ****  * ** * * * * **** ****** * if(c==strlen(a)-1)
****  *** * *    * *  * *  *      *   *** ** ** ** *   *    ** *     * *   * * ** *       ***   * ****** is a prefix of %s",a,b);
    }
 *** *   **   * * ***  *  ** * 0;
}
answered by (-498 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <string.h>
int main()
{
* *** **   *  *  * ***  *   n,count;
       **   * *  * ** ** * *    *  ** *****  *   
  **  *   * *****   ***** *  *** *  **   %s",a,b);
** * *  ***  **** *   *   * ** *** 

* *    ** * * ***   ***      **   *     ** **    
**  *  ** * ** **  *   *  *  *
 ** *  * ***** **  **  * *  *   * **** **  *  *    *  *** * *  *
**        ** ***  * ********  **

*   *   *** ****      *   *** (strcmp(a,c)==0)
*   * ** *  ** ********   
*  **  ** *    *** *  ** **  *  *  * *** ***   ****  ** *  ** **   is a prefix of %s",a,b);
 *****  * * *     *    * *** *
  ** * * * **  **   ** ***
** ** * *** *    *    * **   *
   **   * ***   *  **   **   *** ** **  * ****  * * ***  ** * **** is not a prefix of %s",a,b);
*** * * **  *    * **   *
***  **     ** * ** *** *  *  *  0;
}
answered by (-284 points)
edited by
0 0
prog.c: In function 'main':
prog.c:8:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s %s",&prefix,&word);
             ^
prog.c:8:16: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
     scanf("%s %s",&prefix,&word);
                ^
prog.c:10:15: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     for(i=0;i<strlen(prefix);++i)
               ^~~~~~
prog.c:10:15: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:10:15: note: include '<string.h>' or provide a declaration of 'strlen'
prog.c:18:6: error: expected '(' before 'printf'
      printf("%s is a prefix of %s",prefix,word);
      ^~~~~~
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>
int main()
{
****    *  * **  *    *        a[100],b[100];
** *     *     ** * * * **   ****     **   * ****  *
    int l1,l2;
   *  ***** **** **  ***   *   **
**  **  ***  ***** ** *  *** * ** * 
  *   *  *    ***  **  *     *** ***     *
* * ** * *   *    **    ** * ***    * *  * *   ***   *** *     * **   is not a prefix of %s",a,b);

    }
 **** * ******   *  *  * * if(l1<=l2){
  **  ** *  *   *****  *  * ** * * ** * * *  * prefix=1;
   * ***   **  ** * ** ****  *** *** *  ** * **  **** i=0;
** *****  ***  ** *  * ** *** *** ** ** *  ***   ****   *** *******    ** 
** ** * * *** *****    *  *  *            * * * *** **   **** **  *          * *   * * (a[i]!=b[i]){
       ***** ***   **     ** *  *  *     * * * *  *****  * *** *   * **   * **    **   **  ****** * * 
*******   ***** *** ** *   * ****    *  ***** * ** * *     * * * **  *  **  * **       * **   ** *    
* ** ***  ***  * *       ****  * ** ** * **** *  **  **  ** * **** * **   **       


* *  *    *  * * **** * **  ******  * *** *  *   *
*  * **       *** *    * * **    * **  *  ****     * *  *** *  
 *   ***  **    * * **   *  * ** ** ***  **   * *  * ** ***     * *** ******* ** *** ** *  is not a prefix of %s",a,b);
  * * * *   ****     * ***  *      ** **   *   *
 **    **   ****   * ****  **     **** ** ** * ** *
    *  **  *** ***        * *****  ** * *      **** *** * *** **  ** is a prefix of %s",a,b);


    }


}
answered by (-329 points)
0 0
prog.c: In function 'main':
prog.c:5:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
             ^
prog.c:5:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
               ^
prog.c:7:8: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     l1=strlen(a);
        ^~~~~~
prog.c:7:8: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:7:8: note: include '<string.h>' or provide a declaration of 'strlen'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:6:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
             ^
prog.c:6:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
               ^
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
* * * ***** **** * ** **
int main(void)
{

* *   **        *  * *** *** pre[100];
* ** *  **** **  ** *  ** *  word[100];
*  ***  *   * *    **   ***          * * %s",pre,word);
 *** * **  * * ** * * ** *  **** *  *
**        ***   *   ***** *    *  ***   *   ***

** * * * ** *****  * ** ***** i;
**  * *      *****   *** *  ***  * ***  *** * *  * * *
 ** ******** *********   **
  *  *****     ** **  ** * ** ***** * **  **   ***     *  *    **   
***    ** **   *   **    **   * ******** * * *** * ** 
     ****   *   * ** *   ** * *  * * *  *   ***** *   ***  *   **    ******** * **  ****   * *      is not a prefix of %s",pre,word);
 ** *  *   ** *** ** * ** * * ****      * *    **      *  **** ** *  **  ** ** * *  **** * 0;
  *  ***   ** **   *   **  **  *********  *   *   ***

   *   *** **   ********  *
printf("%s is a prefix of %s",pre,word);
return 0;
}
answered by (-249 points)
0 0
prog.c: In function 'main':
prog.c:8:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&pre);
             ^
prog.c:9:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&word);
             ^
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&pre);
             ^
prog.c:9:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&word);
             ^
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <string.h>
#include <ctype.h>
int main ()
{
  ** ** ** * * * *  * **** pre [100],a[100];
   * *   ***** * *   ** *** *  n ,i;
*  * * **  * *  ***  *      ***     *   ***  
 * *** *  *     ** **  **  **   **  
*    *  ***  * ***  * * * ***   * *  * **** * ** 
  * **** * * *** ** **   *    **
********* ** * ****   *****   * **** *    *  * *** *    *   (n=0;n<strlen(pre);n++)
  *  ******  **  ****** *  * * ******  *  *** **  *  
**  * *  *   * ** *** ***** **   **  * ***     ***** *******  * *****  ** ***   * (pre[n]==a[n])
****  * ***   * * *    * * ** **** *     **    *  **   * * *     ** *  ** ** *   * * * * ** *     is a prefix of %s",pre,a);
 * *    **   * * *  **    **           * *** *** * **  * * * * **    * *  ***   ** ***
 *   * * * *** *      * *  * * *     ** * *  ***** *   **   * *  ******* *  *   *   *  ***  * * * **  ***  ****  *** *** *   is not a prefix of %s",pre,a);return 0;
 ** *****  **  *  *** **
  * **  *  **  *** ** ***    * * * **** *** *    *    ** * * *** *  *   *  *** * *

***** * ****   * *  ** * 0;
}
answered by (-32 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include    *  * *** *  *
#include **    **  ** 

int main()
{
*  *   **  ** *   ** **  * * ** a[100];

 ** *    * * ** * ** * ***** *  *** b[100];

  * * ********  ******* ** *    *****  *  %s", a, b);

******  **       ** **  *  * len_a = strlen(a);

  *  *   **  *     *  *  i = 0;

 **  * * ***   *   ***   flag = 1;

     * **  ** * ***      *******   = 0; i < len_a; i++)
   *   * **  * * *   * * 
 *   *   * ***   *    * *   *  ** *  **      ***  *** != b[i])
****   ***   **** *   **** * *  ****      * **
  **  *  *****  *  * ** *  *   ****  *  *  *  * * * **  * * *   **   **    *  *  * * = 0;
  ***** **   * ** **     * ***** * **** ** *** *   *
** * *   *      *     **   

 *    *** **   ** **    ** == 0)
***   ***  * *  ****** *** ****  *  
     **** *   ***   * * * *    ****  **    ***  *****  ***  *** ***** * is not a prefix of %s", a, b);
  * ** *    * * * *   *  * 
 ** ***  *** *** ****  *  **  **
  ** ** *   **** * * *
** **** *****  *   ***        * *   *** *** *****     **  * * is a prefix of %s", a, b);
  * * **     *   ** ******
** *  * * ****  *    * *    ** * 0;
}
answered by (-285 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
*  * ****   * ** *  *
int main()
{
**  * ** *   * *  * *** ****  *  i,n;
 ** * * ** *    ** ***  p[100],s[100],a[100]={};
  * ****   *       * **   * *  * * *   ** ** * %s",p,s);
 *****    ** ** *   *** **** *  *   *
*  **  *      **     *     *** ** * **  *
* * ** *   *   * * *  *** **  *   ** *    ** *
 * ** ****   ****  *  ** **   *      ** **  **
   ***  * * ***   ****  * ****   ***      **  **       **  *  *****    is a prefix of %s",p,s);
*     ***  *   * ******   *
 *   * ** * *   **** ****  
     ******* * *       *** ** * ***  *  *** ****** *   *    *  is not a prefix of %s",p,s);
*  *        * **  ** *     * * 
 * * **    * **  *  *   *  *******  * * *   **  **** * ***
***   * ** ***     **  *  *   0;
}
answered by (54 points)
edited by
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>

int main()
{
    int i;
    char a[100];
    char b[100];
  * ** * ***  * **  *  ** **    * **** * *  ****  * *   
    scanf("%s",b);
    for(i=0;i<strlen(a);i++)
   **** *   **    *  **  **  *    **     *     ** *** 
   * ** * * *  *   *****   * **  ** * **  **  *  ****      **** ** *** *    != b[i])
*  * *     * **** *  *  ****  *   ** **  * *       *  * ** * * *   *   **  *      *** **** *  ** *   ***  
***  ****   ***   * ** * ** *   * *****  * ******    *****  ***  ** * *** *****  *   ****  ***  * * ***  * *** ****     ***   * *********  ** ** is not a prefix of %s",a,b);
 ***    ***** ** *   *** ***** **   * * ** *  ** * ** *    **  ****     *  * **   * *  * *** *   **     ***  * *  * *  *****   ** **    ** 
  * * **    ** *    * * *  ** **** ** **** **  * ***  *** ** *** ***** *  ** *   **        * * ** 
****   *  *    * **    * *  **** * **    **  **  **    ** *** * **   *** ***  * ** ***  ** *   == b[strlen(a)-1])
*** ******  * *    * *  * * **  ****** ***   **** **     *  *      * * *  ***** *  *  * ***  *  * 
**   ***   **** **    *   *   *   ** * ***   *     *  *  *  ** *  ******* **  *  * *    ***  ********  * *   *** * * * * * ** **  *  ***    * * **** is a prefix of %s",a,b);
  *****     * *   * * *   * * * **  * *** * *        * **        **  ****  *** ** * *** *  *    **     ***    *    *    *    **    ** * * 
** **    ****          * * *     *** *   ***   ** **   * *   *** ***  *   ** * * ** ***  *    ** **   * * 
 * ** ** ***    *** **  * *   *   * ***  *   
}
answered by (-301 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<stdlib.h>
#include<string.h>
#define n 100

int aa(char a[],char b[]){
** ***  *** * ** **     *  **   * * *   i;
* *** * ***     *  * *****  * * *** **** (a[0]!=b[0]){
*    **   ****  ***  *    * *        *  *   *******   *** 0;
* *****   ***     * *   * * * *  ** ***
**  **  * **  * ***  ** *  * * *   ** **  *   **      *  *
****    *    ** *  * * *     *   **    *  * **** * *  *    ** *** a[i]==b[i])
***  ** * *    *   *   ** **  * * ** *   * *   ** * *
*    ***   ***  *****  *** **  *   *   *********   * *  * **  *** * * *** **  1;
***  **** *  ** * * **  *    ** ******* *****   ********* ** *   * ***  * ** * 
 *** *     ***    * ***   *** * * *  * **  * * ***  * ** **
 * ******** ** **  ***  *   **
 * *   **    * *     * ****  * 0;

}

int main(){
**   **       ** ** ***  * * *** c[n],d[n],e[n];
**  *     ***  **     * *   i;
 **    ** *  ** * **   ****** ***   * * %s",c,d);

*     **  **** *  *    **** ** **
** *    * * *   * *  * *   ** *  **  * * *    ***  *  *** *********  *  * is a prefix of %s",c,d);

*****  *****   ** ***
*******    ****  * * ** *  * ** *    *  **   * **  *    is not a prefix of %s",c,d);


}
answered by (-32 points)
edited by
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.100.234
©2016-2025

Related questions

1 like 0 dislike
37 answers
Final Exam 5 (20%)
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42302 - Available when: 2018-01-17 14:00 - Due to: Unlimited | 9k views
2 like 0 dislike
31 answers
Final Exam 4 (20%)
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42301 - Available when: 2018-01-17 14:00 - Due to: Unlimited | 7.9k views
1 like 0 dislike
32 answers
Final Exam 3 (20%)
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42300 - Available when: 2018-01-17 14:00 - Due to: Unlimited | 9.2k views
2 like 0 dislike
30 answers
Final Exam 1 (20%)
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42298 - Available when: 2018-01-17 14:00 - Due to: Unlimited | 7.1k views
0 like 0 dislike
4 answers
[Makeup] Final Exam 2 (20%)
[Exam] asked Jan 19, 2018 in Final Exam
ID: 43460 - Available when: 2018-01-20 09:00 - Due to: Unlimited | 1.7k views
12,783 questions
183,442 answers
172,219 comments
4,824 users