1 like 0 dislike
2.2k views

A string p is a prefix of a string s if the leading characters of s are identical to p. For example, "abc" is a prefix of "abcde". Develop a function prefix that checks if a C string p is a prefix of another C string s.

p是s的前綴若s開頭的一段字串等於p。例如,"abc"是"abcde"的前綴。寫一個程式 判斷字串p是否字串s的前綴。

Example input 1:

abc
abcde

Example output 1:

abc is a prefix of abcde

 

Example input 2:

bc
abcde

Example output 2:

bc is not a prefix of abcde

 

[Exam] asked in Final Exam
ID: 42299 - Available when: 2018-01-17 14:00 - Due to: Unlimited

retagged by | 2.2k views

37 Answers

0 like 0 dislike
Hidden content!
#include * * ** *
#include **** ** * **
* * **** ** *
* *** ** * ** ** *

int prefix(char a[], char b[]){
int i, j,n;
int cnt=0;

n= * * ****

*** ****** *** ** *** * ** * ****
* ** ** ***** ** **** * == b[i]){
** ** **** ** *** ** * **** ** * *** * * ***
*** ******* ** ** ****

** * *** * ** *
if (cnt == n){
* * ** **** * * *** * ** * * * *** * 1;
*** **** ** ** **** **** *** * * * * * *
* ** *** * *****
* * * * * *** * * *** ** * * *** * * *** 0;

}

int main()
{
* **** **** ** ** s1[100], s2[100];
* * * ** i,j;

* * * ** * * **** * *** * s1);
* *** ** * * * * *** * * * * *** *** * s2);
** * *** * *** * ** * (prefix(s1, s2)){

** * * * ** ** *** ** * * * * * *** **** * ** * is a prefix of %s", s1,s2);
*** ** *** ** ** * **** * * * *** * * ***
* * ** * ** ** * **** * * ** ** **** * *** * *
** *** * *** * ** ** * * * ** ** ** ** ** * *** *** ***** is not a prefix of %s", s1,s2);



}
answered by (323 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <string.h>

int main(){
** ** * * ** * *** c;
** * *** **** ** ** a[100],b[100];
** ** * ** * *** ****** %s",a,b);
* * * * * *** * ******* * **** * **** **
* ** * * **** * ** ** * **** *** ** * 0;
* * ** * *** ** * * *** *** *** * ** ***** %d",strlen(a),strlen(b));
** * ** * * *** ******* * ** *** * * *
* ** * * * ** * * * *** * * ** * *** * *** ****** * * * * * **
* * * * * * ***** * * ** ** * * ***** * * * * * * ** *** * ** ** ** * * * **** ***** ** **** * * ** * * is not a prefix of %s",a,b);
** *** *** * ** *** *** **** * ** * *** ** ** * **** * * ** * * * * ******* * * ** * * *
* *** * ** * *** ** * * *** ** * ** * * ** ** * ** ** ** *
* ** ** *** *** * * **** * **** *** * ** *** ** ****** **** *** **** if(c==strlen(a)-1)
** * * ** * * * * * * * * * ** * * * ** * * * ***** * * ** * **** ** * ** ** ** * * * * is a prefix of %s",a,b);
    }
* * * *** * * * ***** * 0;
}
answered by (-498 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <string.h>
int main()
{
* *** * * * **** * * *** * n,count;
* ****** *** *** * * ** ** ** *** ** *
* ** ** * * * * * * * * ** * * * %s",a,b);
* * * * * **** * ****** ** * *

* *** *** ** ********** **** * ** ***
** ****** *** * **
* * ** ** ****** * * ** ** * ** **** ***** *
* ** * * **** ** **

**** ** *** * ** ** (strcmp(a,c)==0)
** *** * * ***** ** ** *
* * **** * **** * ** *** * * * * ***** ** * ** ** is a prefix of %s",a,b);
* * * * * * **** **
****** ** * * * * ** * *
* *** * * **** *** * **
** * *** ** ** * * * * * *** ** ********* * ** * ** * **** is not a prefix of %s",a,b);
* ** *** * * **** **
** **** * * * **** *** ** * 0;
}
answered by (-284 points)
edited by
0 0
prog.c: In function 'main':
prog.c:8:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s %s",&prefix,&word);
             ^
prog.c:8:16: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
     scanf("%s %s",&prefix,&word);
                ^
prog.c:10:15: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     for(i=0;i<strlen(prefix);++i)
               ^~~~~~
prog.c:10:15: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:10:15: note: include '<string.h>' or provide a declaration of 'strlen'
prog.c:18:6: error: expected '(' before 'printf'
      printf("%s is a prefix of %s",prefix,word);
      ^~~~~~
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
#include<string.h>
int main()
{
** **** * * ** * ** a[100],b[100];
***** ******** * ** * * *** ***** *
    int l1,l2;
* *** * ***** *** * ***
***** ****** ** ******* * ****
** * * ** * *** * *** * **
** ** ** * *** * * * ** * ** **** **** * ****** ********** is not a prefix of %s",a,b);

    }
**** *** ** * **** if(l1<=l2){
** ** * * *** * * * **** *** * * * * ** prefix=1;
* * * * * ** *** ** ** * * * * * * * * i=0;
*** *** *** ** ** ** *** * * ** * * * * **** ** *** ** **
* ** * ** * * *** ** * ** * * *** *** ** * * * *** * * * * * * (a[i]!=b[i]){
* * ** **** **** * ** * * * *** * ** * * * * ** ** * **** ** *** ** * * ** * ***** ** *
*** * * ***** * * * * ** *** *** * **** **** ** * ** ** * ** * ** ****** * **
* *** * ** * ** * * * * ****** * ** **** * *** * ** *** ** *


** * ** * * ** ** *** * * * ** * * *
* *** * * * ** * * * * *** ***** * * * * **
* ** *** ** * ****** * ****** * *** ** ***** ** ** * ** ** * * * ** ** **** * * * is not a prefix of %s",a,b);
* ** ** *** * * ** * * * * *
**** ***** * * ** ** * * ** ** * *********
* * * *** * * ** * * * * ** * ******** ***** ***** ** * is a prefix of %s",a,b);


    }


}
answered by (-329 points)
0 0
prog.c: In function 'main':
prog.c:5:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
             ^
prog.c:5:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
               ^
prog.c:7:8: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     l1=strlen(a);
        ^~~~~~
prog.c:7:8: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:7:8: note: include '<string.h>' or provide a declaration of 'strlen'
0 0
prog.c: In function 'main':
prog.c:6:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
             ^
prog.c:6:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
               ^
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
* * * ** ** * **
int main(void)
{

*** * * * * *** ** ** pre[100];
* * *** ** * * ***** word[100];
* **** * *** *** ** * * ** **** * * ** %s",pre,word);
** *** ** * ** *** ** ** * ** * *
* * * ****** ** ** ** *** * ***

* * ** **** * * * i;
* **** * *** ** * * * * **** *** ** ** ***
* ** **** *** * **
* ** * *** *** * * ** **** * *** * * *
* * * * ********* * * * ** * ***
* * * * * ****** *** * * ** * ***** ** ** *** ** *** * * ** ** ** * * * * * * ** is not a prefix of %s",pre,word);
* * **** * * * * * ** * * * ** * **** *** * * * ** * * * 0;
**** ** * * * ** * ** ** * * * * ***** ******** *

* * ** *** * ** * **
printf("%s is a prefix of %s",pre,word);
return 0;
}
answered by (-249 points)
0 0
prog.c: In function 'main':
prog.c:8:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&pre);
             ^
prog.c:9:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&word);
             ^
0 0
prog.c: In function 'main':
prog.c:8:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&pre);
             ^
prog.c:9:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&word);
             ^
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <string.h>
#include <ctype.h>
int main ()
{
** * * * ** * * * pre [100],a[100];
* ** * ** * **** **** n ,i;
* ** *** ** * *** ** * * ** * *
* * ** * **** *** * ** **
* * * * ** * *** * ** * ***** * **
* **** * **** ** * **
* * ** ** *** * ** * * ** ** *** *** ** * * * * (n=0;n<strlen(pre);n++)
* ****** ** * * * * * ***** **** * *
**** ***** * * * ****** * * *** * * ***** **** * * *** *** * ** * (pre[n]==a[n])
** * * ** ** ** ** ***** * * * ***** ** * **** ** * *** ** ** * * * is a prefix of %s",pre,a);
****** * * * ** * * ***** * * *** * ***** * ***** ***** *** *
* * * *** * ****** * *** * * * ** *** * ** **** * * * * * * ** ****** * *** ** * ** * ** ** **** * is not a prefix of %s",pre,a);return 0;
** ** **** * * * *** *
* *** ** * ** ******* ** * ****** * ***** ** * *** ***** ***** * ****

* **** ** * ***** * ** *** 0;
}
answered by (-32 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include ***** ****** **
#include * **** * *

int main()
{
**** ** * * *** a[100];

* ** * * *** ** * ** b[100];

**** ** * * *** *** ** %s", a, b);

* * * * **** ** * ** len_a = strlen(a);

* * ** * **** ** *** i = 0;

* **** * *** ** * *** flag = 1;

* * ** * * * ** * ** * * * = 0; i < len_a; i++)
* *** **** * *** * * *
** * ** **** ** * ** * ***** ** *** * ****** != b[i])
* * ** * ** ** * * * ***** * *** ** * * ** **
* ** ** * * * * ** * * ** *** * * *** * * * * * ** ** ** * * ** * = 0;
** ***** * * * *** ** * **** * * *** * ** * *
* ** * * * ** * * * *

**** * ***** ******* == 0)
** ** * * ****
**** ** * * * * * * * * * ** ** * * *** * * * * is not a prefix of %s", a, b);
* * * *** ** * * *** *
*** * ** ****** * *
***** * ***** * ***
* * * * ** * *** *** *** * * * ** *** ** * *** * * ** is a prefix of %s", a, b);
** ** * * * ** *
* *** * * ***** ** ****** 0;
}
answered by (-285 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
* * *** * **** *
int main()
{
* * * ** * **** * * *** * i,n;
*** * * * * * * ** * p[100],s[100],a[100]={};
* ******** * ** *** * **** *** ** * %s",p,s);
* ******* ***** **** * * ***
** * * * * * * * * ** **** **
** ** * * * *** ** * * * * * *** * * * * *******
** **** * * *** **** * * * **
** ** * * ** * * * *** *** ** ** * * *** *** is a prefix of %s",p,s);
******** *** * ** *
** *** ** ** * * **** *
*** ** * * * **** * ****** * * * * *** * * is not a prefix of %s",p,s);
* * ******
*** ** * * * * ** * * *** * * * * * **** * *
* * * * * * * ** * *** 0;
}
answered by (54 points)
edited by
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
#include<string.h>

int main()
{
    int i;
    char a[100];
    char b[100];
** *** ** * ** * **** **** ** * * ** * * ***
    scanf("%s",b);
    for(i=0;i<strlen(a);i++)
*** * * ** * * * * * * * *** *
** * *** * *** ** ** * * *** * **** * * ** ** *** *** * ** ** * ****** ** != b[i])
*** *** * * * * ** *** ** * * * ** *** * ** * * * * * *** ** ** ** ****
* *** * ****** * ** * *** *** * * * *** ** ** * * ****** * **** ** ***** *** ***** * * * *** ** * **** * ** ** * is not a prefix of %s",a,b);
*** * ** ** * ** * * ** ** * * * ** ***** * * * * *** * *** * *** * ****** * * * *** ** * ****** *** *** ** * * * ****
* * * ***** ** * * ** * **** ** **** * * * * * * ***** *** ** * ** * *
* ** ** * *** * * * * * * * ** * *** ***** * * * ** ** * * ****** *** == b[strlen(a)-1])
* * ** *** * * **** * * * *** ** ******* *** * * * ** * ** ** * ** ** * ** * ** **
** * *** * * * * *** * * *** * *** ** ** * *** * * * ** * * * ** * * * **** * * * * * * ** **** * * ** is a prefix of %s",a,b);
* ** * ** ** ***** * ** * * * ** * **** ****** * ** *** * ** * *** * * ** *** * * *** ** *** *************
** * * *** * * * * **** * ***** * ** * ** ** * * * *** * **** ** ** ***** * * *
** ************* **** **** ** **** *** * * * **
}
answered by (-301 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
#include<stdlib.h>
#include<string.h>
#define n 100

int aa(char a[],char b[]){
* ****** *** * * * * ** * * ****** ** i;
** ** *** * ***** * * *** ** (a[0]!=b[0]){
* * ** ** ** *** ** * * * ** **** * 0;
* **** ***** * * ** ** * *** *
* * *** * ***** ** * * ** * ** *
*** ** * ** ** **** * * * ***** **** * ** ** **** * a[i]==b[i])
* ****** * *** * *** * ** **** * ** *** **
* * ** *** ** *** * ** *** ** * ****** * ********** ** * * * * * ** 1;
* * * * * ** ** ** ***** ** * **** *** *** ** * ****** **** * ** * *
* **** ** * ** ** * *** * * ***** * *
*** *** *** *** * *** **
** * ** * * ** ** *** * * 0;

}

int main(){
** * * * ** ** ** * ** * * c[n],d[n],e[n];
* * ****** **** * i;
* ***** * * * ** * * * %s",c,d);

* ** * * * * * * ** ** ** *
* * ** ** ****** * * *** * **** * **** ** * * * * ** is a prefix of %s",c,d);

* ** * *** * * * * * **
** *** * ** ** *** * **** ********* * *** * * * **** ** is not a prefix of %s",c,d);


}
answered by (-32 points)
edited by
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.58.78
©2016-2024

Related questions

1 like 0 dislike
37 answers
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42302 - Available when: 2018-01-17 14:00 - Due to: Unlimited
| 1.8k views
2 like 0 dislike
31 answers
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42301 - Available when: 2018-01-17 14:00 - Due to: Unlimited
| 1.9k views
1 like 0 dislike
32 answers
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42300 - Available when: 2018-01-17 14:00 - Due to: Unlimited
| 2.1k views
2 like 0 dislike
30 answers
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42298 - Available when: 2018-01-17 14:00 - Due to: Unlimited
| 1.5k views
0 like 0 dislike
4 answers
[Exam] asked Jan 19, 2018 in Final Exam
ID: 43460 - Available when: 2018-01-20 09:00 - Due to: Unlimited
| 460 views
12,783 questions
183,443 answers
172,219 comments
4,824 users