Final Exam 2 (20%)

1 like 0 dislike
17.5k views

A string p is a prefix of a string s if the leading characters of s are identical to p. For example, "abc" is a prefix of "abcde". Develop a function prefix that checks if a C string p is a prefix of another C string s.

p是s的前綴若s開頭的一段字串等於p。例如，"abc"是"abcde"的前綴。寫一個程式 判斷字串p是否字串s的前綴。

Example input 1:

abc
abcde

Example output 1:

abc is a prefix of abcde

 

Example input 2:

bc
abcde

Example output 2:

bc is not a prefix of abcde

 

[Exam] asked in Final Exam
ID: 42299 - Available when: 2018-01-17 14:00 - Due to: Unlimited
retagged by | 17.5k views

37 Answers

0 like 0 dislike 
Hidden content!
#include    * **    ** * *
#include **  ******   * *
* ** **  ** *  **     *
*   *  **  ** *

int prefix(char a[], char b[]){
int i, j,n;
int cnt=0;

n=    * * * 

**** *     *** *      *   *  *  **  * *
  **   *  ** *   * * *  *****   == b[i]){
 * *  * * * ** * **     ** ****  ** *  *  ***    *   **    
** *  * **  *  ** ** *   

** * * *** ****      
if (cnt == n){
 * *    * * ****  *   * *   **  ***** *   *   **  ***  1;
** * ***   **   *******    *      **   ** **
    *      **  * * **    **** **
* ** ****  **  * *  *    ** * * *   * * * ** *****    *  *    0;

}

int main()
{
* **   * *    ****    s1[100], s2[100];
 ** **  ***   ******  *  i,j;

* *  ***    ******    **  ****  *** * s1);
 * **  *   *  **   *  * ********  ********  **** s2);
** * * *  ****  *** **   (prefix(s1, s2)){

     ** **  * * **  *******   * * ** * * ******  * ** * ** *  is a prefix of %s", s1,s2);
 **  * ** **  *  *   ** * *    *  *     * * ***
  *      ** *** *    *** *** ** ** ****    *  *     * 
 *****     ***  **  *     *  *  **  *      ***  **   *** *   *   * *    ** * is not a prefix of %s", s1,s2);



}
answered by (323 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <string.h>

int main(){
  **  **  * **  *** * ** *   *   * c;
  *   *   *      ***  ****   a[100],b[100];
***** *   *  *** *  *  **** ** * *  *   %s",a,b);
*     **   * **   **  *  *  *    **    * *
 ** ***    ***  *   *  *** *  ****    ***  *        0;
 *   ****   *    *       *     ******  * %d",strlen(a),strlen(b));
** ** * *  *** ******   ** ** *  ****  *  *  *   **
 ***  ***  *    * *  *** ***    **** *   * *  *    *  *  *    **  *   ** *   *  * **   * *
  * **   * ***   ***     *  *  * ********* ** * *  * *  **      ** ********* ** **  *     *   * *** **** * * *** is not a prefix of %s",a,b);
* **   *  **  ***  *  **  ** **  ******** **** * *** * * ** * *  **** * *   * ******   **  * *    *** **  
***** ** *** *       ** **           *   * ***  **  * ** ** ** ** **** **** *  *
       **    * ***   *****   ***  **     * ** **        *   *** **  **  *   *  * ** if(c==strlen(a)-1)
** **  **** *****  * * ****  *   *  *  *  * ** * **  **    **  * * *    ** *  *  ***  **  *     * *    **  * * **  * * *    **     is a prefix of %s",a,b);
    }
*  ***  ** * **** *  * *     0;
}
answered by (-498 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <string.h>
int main()
{
 * **  *  **      *       *****    n,count;
**** **  **  *** *  *** *   *  *  * ***   ** ** 
*     **  * * ****    **    ****  * * * * %s",a,b);
** *** * ***  ** *   ** * **  ***

**  *   **     * **  *  ***** ****  * *  ****** 
*   ** ** * *  ****       
*** * ***  *  *  *   ***  ** ***    *    *  * * * **  **  *******
* *  *****  **   *   **  ** 

**** ** *  **  *** *****  (strcmp(a,c)==0)
*  * **  * *  *  * *   ** 
 ** * *******       *  * *** * *    **  *** *****  **  *  ** * * * is a prefix of %s",a,b);
  * * **   *   ** ***   * 
 * *  **   *  **    ** ** 
* ** **      **********  * * * 
**** * **     ***  **  * *  *   **   * *    ** * *    * **** *  * *** * is not a prefix of %s",a,b);
* **  * **     **  *    
*****  ** **** *   *   * **** 0;
}
answered by (-284 points)
edited by
0 0
prog.c: In function 'main':
prog.c:8:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s %s",&prefix,&word);
             ^
prog.c:8:16: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
     scanf("%s %s",&prefix,&word);
                ^
prog.c:10:15: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     for(i=0;i<strlen(prefix);++i)
               ^~~~~~
prog.c:10:15: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:10:15: note: include '<string.h>' or provide a declaration of 'strlen'
prog.c:18:6: error: expected '(' before 'printf'
      printf("%s is a prefix of %s",prefix,word);
      ^~~~~~
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>
int main()
{
* ** ****  *  **** ****** ** *  **  a[100],b[100];
*   ***  *** ** * * *  *   *  * **   * **** *       
    int l1,l2;
*  ** ****      ****    **     **     
**   ** * * ** *     ****  * * **
**       **** ***   **   ** *       **
******         **  *  * ** *    **   * ** *    * * *     * **    ***** ** is not a prefix of %s",a,b);

    }
* *      *  *** *   * ** ** if(l1<=l2){
********  ** *** * **   ** *     *** * ** *** * *        * * prefix=1;
* *** * ** **  ********  ** * * *    * ** *  * **      ***  i=0;
**  *   * ***** ** **** ****  * ****** **  **  **   ** * **     **  *  
** **    **   *** * * * *** ** ** * ***  **** **    * ***** ** ***   * **  * *  ******** (a[i]!=b[i]){
   * **** *     * **** *** ***  *   * * *    **  *** ****   ** ****  * * ***  *****       *        *  * * *   **   ****  
*    ** ***      * ***   * *    * *     *****  *    **   * *  *****    ** *   ***   **  * *  *   **** *** *    * *
 * *   * *   **     * * * * *   **   **  *  **** ****  ***  ********    **  


 **   ***  * *    *** ** **  *    ***      ****  *** **
*** ****** * ** *   * * ***    ** ****** **** * * * ** * *  *** **
  ** ** **** **** *  **  ***    *  ****  *  *  *    **    * *  ** * * ***   **  **  **  is not a prefix of %s",a,b);
  * * ****  ** ***   **  ** *****  ***  *** *  * * * **    *
 *   * *     * * * *   ** ***    ****** ** **   **     * 
*  * * * **  **  **  **  * *  * *** ** ** * * * * **** ** **** is a prefix of %s",a,b);


    }


}
answered by (-329 points)
0 0
prog.c: In function 'main':
prog.c:5:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
             ^
prog.c:5:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
               ^
prog.c:7:8: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     l1=strlen(a);
        ^~~~~~
prog.c:7:8: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:7:8: note: include '<string.h>' or provide a declaration of 'strlen'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:6:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
             ^
prog.c:6:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
               ^
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
 ** **  ***    *   *  **** 
int main(void)
{

  ***   *  *      ******   * **  pre[100];
* ** ****  **  **  *  **  * ***** word[100];
** *  **  * * *   * ** *  *   *  * * %s",pre,word);
     *  *** ** * ** **   *     *  * * * * 
** *    *  ***  *   ******  * **     *    *

  *  * ***  ***   ***  **  i;
  * * * * * ** *****  ** *** ****** * *******   
**  *   *  *** * *    ***  *  * * *
 * * **   ***   * * ****** **         ** **     * * * * ** ** * * *    
** *  ****** * ** *   **  *  ** ******  **** *   *  * *
 ******  **   * ** *  ** *    ** * ** * ********  ** **  ** *  * *  *  **  ***** **** ** is not a prefix of %s",pre,word);
 *   *   **    **  *   *********  * * ** *** *    * *  ** * * ****  *   ** ** *** 0;
***  **  * *  *   * *  *  **** **   *****  * **   *   

*   * *** ** *   *   ** *  
printf("%s is a prefix of %s",pre,word);
return 0;
}
answered by (-249 points)
0 0
prog.c: In function 'main':
prog.c:8:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&pre);
             ^
prog.c:9:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&word);
             ^
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&pre);
             ^
prog.c:9:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&word);
             ^
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <string.h>
#include <ctype.h>
int main ()
{
 * * ********** * ****** * ** * pre [100],a[100];
*  *****    *   ** ***      *  * n ,i;
**  *  *    ***  ****   * *  *   *  * *****   
*** *** **  * * * **  *  *  * * * ** 
 **      * * ***       ** *   ******   ****
**** *  **    ** ***  * *     * 
***  ***  * ***    * * *  *** *  * * ****** *    * *  ** * (n=0;n<strlen(pre);n++)
* * **** * * * **** * *** ******   * * ***   ** * * ***
* **  ** * *    **  **  * *** *****   * * ***     * *  ***     *  * * ***** ***  * * (pre[n]==a[n])
 ** *** *** *  *  * *  * **   * **** ***  ** ** *** * ***   *   *  *   *   *** * *  **    **   ** *  is a prefix of %s",pre,a);
**   * * * * *** **  * ** *** **       *      **** **  * ****    * ** **    *  *
  ** ** ** * **** ** * * ***    *       * ******  * *  ********** *   **** *****  ** * *   ***  ***** ** * ** is not a prefix of %s",pre,a);return 0;
   ****  *   *****   ***
*** * **  * *    **** *** ** ***    *  *    * **   * *  ** *  *  ***    **  *** * ** 

        **     ** *** * * * *  0;
}
answered by (-32 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include   **   ** * **
#include *****    ** *** 

int main()
{
* ** **  ** **   *    ***   ** a[100];

       * **    *  *     * b[100];

****** * ***** *   *** * * ****  ** ***  %s", a, b);

* ** *      **  *  * ** ***** *   len_a = strlen(a);

* *   *    *** **  * **  *    i = 0;

****   ** * **    **   *** ** flag = 1;

   * **   * ****   *   ******** * = 0; i < len_a; i++)
 **** * *  *   ***  *** *  
*   *  ***  *  ****** ***  *******    ** * * **      *   * ****  != b[i])
  **** ** *  *  ****         ** **   **   *** * *   *  
   ** *   *  * ******  * *** *  *  * ** *** ***** *   ** *   *  *   ** * *****   * ** **  *   = 0;
** *  *  *  ** *** *   **  **  **   *  * ****  *** **
   *  ***** ******  *   

***   *  * *   ***  * *        **** == 0)
 *** *  *  * *   ***   *     *  
*** ***  *    ****  ** *****  **** * ** ***   * ******   *   * * *  * is not a prefix of %s", a, b);
 *   * *   **  ** *   * * * 
* ** ****  *** *** **   *
  * *  *** ***  *     **  ***
  * *   *  ******   *** * ********* ***   *** **      **           *** is a prefix of %s", a, b);
*     ** *          **  
****   ****    *** **    *   * 0;
}
answered by (-285 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
****    *** * * ** *
int main()
{
 ******   ** **   *** *     i,n;
   *   *   **  **   ***  ***** p[100],s[100],a[100]={};
  ***  *  ****   * * * ** ***    * ** ***  %s",p,s);
   *******  *    * *   * * **** *  *  * 
  *   * *     *** *       * **** *
*   * **   ** ***   *** **  * **   **     * ***   
 *** ** * *  * ***   * *** *   *      * ***  
       **** *   ** * * **  ** *  *** * * * * **  *  ** ** * *   *  ***   ** is a prefix of %s",p,s);
***   *  ** **  **  *   ** * * 
 * *  * * *  * ***     * *
 *  * *      *** *   *  ***  * *    **** ****   ** ** **  * * is not a prefix of %s",p,s);
 * *   **        * ** **
   * * *  * ** ***   * **** ** **** ***     *  * * *  
***** * *** *   * *    **  * *** * *  0;
}
answered by (54 points)
edited by
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>

int main()
{
    int i;
    char a[100];
    char b[100];
***   ** *   * ** **** * ***  *   * *  *** * ** * *   *   *
    scanf("%s",b);
    for(i=0;i<strlen(a);i++)
 *** ** *  **  **  *** ******* * *  ** ** ** ** * ** *  * *
         ***  * **  *    *  *** *  *** ******   ***  * **   **   ** ***  ***  *  **  *  *** *  != b[i])
 *  * *  *  *  **          *  *  *******  * * * **   **           *** *  *** **   ***  *** ** ****   * * 
*     * ** *  ** ** * *  *** * ***  ** *  * **  *  ****  * ** **  **       * * * **    *   **** ***     ** * ***** ***  * *  * *   *   *****  ** is not a prefix of %s",a,b);
 * ** *   ***     * ** *** ****   ***** *** **  *      *   * *    *  *** **  ** * **  * ** *    ***  ** ****    ***  * * *** * *  *** * *  *  
 *  ****    *  *  *** * ***  ** ** ** ** * **   ***  ***** ******* **  * *     **  *    *    * **** *  ** * 
  ** *   *   **    ******   **     ***         ** **  ** *    **** * * *      *******  *   == b[strlen(a)-1])
****     ****** **** * ** *  **** * ***** ** ***      * * * *      * ******* **  **     *  ***    *   * **  *
****** *    *******   *      **  *** *    *** **  *  **  ** *   * *   ****   * * **  * * * *   **   * ** *  ****  * * *    ** ****   *   * ***  is a prefix of %s",a,b);
   *   *   * ** ***          *  *  * *   * *  *  *** ****** ****   *    ** *  **   ** *****  * *** ***** ***        *****  *  **    *   *
*    * *     * ******   * * *** * * **  **** *****     ******* ***  **  *  *** *       *      
  **** **  *   ******* *      **     *** *    *  
}
answered by (-301 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<stdlib.h>
#include<string.h>
#define n 100

int aa(char a[],char b[]){
 ** *  ****  ** ***  **** *   * ** i;
****  **   *** *   ** *  *** **** (a[0]!=b[0]){
  * *  ***  * **    *       *      ** * * * *   *  ** 0;
  *  ****  *  ** ** *      ***     
* **  * *    **   ***  *   ****** *** * * * *  ** * *   *
*    **     *  * **   *  *****  **        *  * *     ****** ** * a[i]==b[i])
* **    ****   *** * * * ***** ** ** ** *   *  * * **  ****  * * 
  ** ***   *   **   * * * ***  * *****   **  * *  ** * ******  *   ** **  * * 1;
  *   * *       *     *  ***      *    *** ***    * **   *    *  *  *    ** * *  *  
  ****  *     *  * ****** * * *  *   * * **  *** 
  * *  **   *****  *    * * ***
**   ** * *  ***** * **  *    *  * * 0;

}

int main(){
** *  *** *  *   *   *   c[n],d[n],e[n];
*  **    **** *  ***  * *   *      i;
* * *      * ** ****  **    *     *  * ** %s",c,d);

***  * ***   * ** ** *  *** * **  
****   *    *  *         ** ** *** *  ***   * ** ***  **  ***     * ** * is a prefix of %s",c,d);

   ** ** ** ****  * *   * **
   ***  **  **  * * *** *   *  ***    *  **** *  * ***  **  * **** ** is not a prefix of %s",c,d);


}
answered by (-32 points)
edited by
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:104.23.243.108
©2016-2026

Related questions

1 like 0 dislike
37 answers
Final Exam 5 (20%)
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42302 - Available when: 2018-01-17 14:00 - Due to: Unlimited | 16.1k views
2 like 0 dislike
31 answers
Final Exam 4 (20%)
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42301 - Available when: 2018-01-17 14:00 - Due to: Unlimited | 15.1k views
1 like 0 dislike
32 answers
Final Exam 3 (20%)
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42300 - Available when: 2018-01-17 14:00 - Due to: Unlimited | 18.9k views
2 like 0 dislike
30 answers
Final Exam 1 (20%)
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42298 - Available when: 2018-01-17 14:00 - Due to: Unlimited | 13.1k views
0 like 0 dislike
4 answers
[Makeup] Final Exam 2 (20%)
[Exam] asked Jan 19, 2018 in Final Exam
ID: 43460 - Available when: 2018-01-20 09:00 - Due to: Unlimited | 3.4k views
12,783 questions
183,442 answers
172,219 comments
4,824 users