Final Exam 2 (20%)

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A string p is a prefix of a string s if the leading characters of s are identical to p. For example, "abc" is a prefix of "abcde". Develop a function prefix that checks if a C string p is a prefix of another C string s.

p是s的前綴若s開頭的一段字串等於p。例如，"abc"是"abcde"的前綴。寫一個程式 判斷字串p是否字串s的前綴。

Example input 1:

abc
abcde

Example output 1:

abc is a prefix of abcde

 

Example input 2:

bc
abcde

Example output 2:

bc is not a prefix of abcde

 

[Exam] asked in Final Exam
ID: 42299 - Available when: 2018-01-17 14:00 - Due to: Unlimited
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Hidden content!
#include    *   * ****  * 
#include ******    ** **  * **
**  *  ** * * *   *** * 
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int prefix(char a[], char b[]){
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}
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Hidden content!
#include <stdio.h>
#include <string.h>

int main(){
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}
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Hidden content!
#include <stdio.h>
#include <string.h>
int main()
{
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}
answered by (-284 points)
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prog.c: In function 'main':
prog.c:8:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s %s",&prefix,&word);
             ^
prog.c:8:16: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
     scanf("%s %s",&prefix,&word);
                ^
prog.c:10:15: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     for(i=0;i<strlen(prefix);++i)
               ^~~~~~
prog.c:10:15: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:10:15: note: include '<string.h>' or provide a declaration of 'strlen'
prog.c:18:6: error: expected '(' before 'printf'
      printf("%s is a prefix of %s",prefix,word);
      ^~~~~~
commented by (4.3k points)
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Hidden content!
#include<stdio.h>
#include<string.h>
int main()
{
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    }


}
answered by (-329 points)
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prog.c: In function 'main':
prog.c:5:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
             ^
prog.c:5:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
               ^
prog.c:7:8: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     l1=strlen(a);
        ^~~~~~
prog.c:7:8: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:7:8: note: include '<string.h>' or provide a declaration of 'strlen'
commented by (4.3k points)
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prog.c: In function 'main':
prog.c:6:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
             ^
prog.c:6:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
               ^
commented by (4.3k points)
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Hidden content!
#include<stdio.h>
* * * ** ** *     ****  
int main(void)
{

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printf("%s is a prefix of %s",pre,word);
return 0;
}
answered by (-249 points)
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prog.c: In function 'main':
prog.c:8:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&pre);
             ^
prog.c:9:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&word);
             ^
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&pre);
             ^
prog.c:9:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&word);
             ^
commented by (4.3k points)
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commented by (4.3k points)
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Hidden content!
#include <stdio.h>
#include <string.h>
#include <ctype.h>
int main ()
{
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*** * *         **** *** ** *  0;
}
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Hidden content!
#include <stdio.h>
#include  * *** **   * *
#include * ****   * ** ** **

int main()
{
**  ****  ** * ** ****    **  * **  a[100];

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****** * * **** *** *  
******  * ** ** **** **** ***  * 0;
}
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Hidden content!
#include<stdio.h>
 * **   *  * *  
int main()
{
*   * *    **  *** ****  **  i,n;
** *   * * *  *  **  *     * p[100],s[100],a[100]={};
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**   ** *    *   *     *  *    
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 ** *    *   *  *  *** * *  * 0;
}
answered by (54 points)
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Hidden content!
#include<stdio.h>
#include<string.h>

int main()
{
    int i;
    char a[100];
    char b[100];
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 ***  *   *  * *********          **  * *      ***  *   ***** ***  *  ** ***    * * * ****  ***   *  ***   *   *****  *** *   **     * ***** ** *  is a prefix of %s",a,b);
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 **   *   * *  * **     *  * * * ***** * **   **** **  * *** ** **    * **** ** **     **    *** ****
***** **   **** * * ** ******* * *   **  *    *  ***
}
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Hidden content!
#include<stdio.h>
#include<stdlib.h>
#include<string.h>
#define n 100

int aa(char a[],char b[]){
* **  *** *    * * **   *  *   ** i;
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     *     * *** * * * **    *
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}

int main(){
 * *  *  * *  ** *  **** *    *   c[n],d[n],e[n];
*  * ** *  * * ** * **    ** i;
*****  * *   **    *   **  **   *** *   %s",c,d);

*   * *****       ***  ***** **** 
 * *  * *        ** *  ** * *    *     ******    ***    * *  ***  is a prefix of %s",c,d);

  *** ***    ****     *   ** *
 * *****    * * * *   *** ** ** * ** *        *** * *  **** ** is not a prefix of %s",c,d);


}
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