1 like 0 dislike
13.2k views

A string p is a prefix of a string s if the leading characters of s are identical to p. For example, "abc" is a prefix of "abcde". Develop a function prefix that checks if a C string p is a prefix of another C string s.

p是s的前綴若s開頭的一段字串等於p。例如,"abc"是"abcde"的前綴。寫一個程式 判斷字串p是否字串s的前綴。

Example input 1:

abc
abcde

Example output 1:

abc is a prefix of abcde

 

Example input 2:

bc
abcde

Example output 2:

bc is not a prefix of abcde

 

[Exam] asked in Final Exam
ID: 42299 - Available when: 2018-01-17 14:00 - Due to: Unlimited

retagged by | 13.2k views

37 Answers

0 like 0 dislike
Hidden content!
#include *** * ** * **
#include * **** **
** ** ** * ** *
* * *** * ** ** * *****

int prefix(char a[], char b[]){
int i, j,n;
int cnt=0;

n= * ** *

* * ** * * * **** * * ** * *
* * * * ****** * ** * == b[i]){
* ** * **** * ** * * **** ** * ** *
* ** * * ** ** ** ***

* * * ** * * **
if (cnt == n){
*** * * * * * * * * * * **** * ** * 1;
* * *** * *** * ** * ****** * *** * ** *
** ******* * * ** * **** ***
** *********** * * * * * **** ** * * * *** 0;

}

int main()
{
* ** * ** * * ** * * s1[100], s2[100];
** * ** * ****** *** i,j;

* *** ** * *** * *** * s1);
* *** * * ** * ** * * * * *** s2);
** * * ** * * (prefix(s1, s2)){

**** * * ** ** * *** * * **** ** ** *** *** * *** * is a prefix of %s", s1,s2);
* ** ** * * ** **** *** * *** * *** *
*** ** * * ********** ** * ** *** *
* * * *** * * ** * *** * *** * ** **** * **** * * * **** ** is not a prefix of %s", s1,s2);



}
answered by (323 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <string.h>

int main(){
** * ** * ***** * * * ** c;
* ** ** ***** ******** * * a[100],b[100];
** * ** * * *** * **** %s",a,b);
*** * * ** * *** * *** * ** ** * * **
* **** * * * *** * ** * * ** ** *** *** * ** * 0;
** ** * ** ** * *** ********* ** *** %d",strlen(a),strlen(b));
**** * * ** * ****** *** * * * *** *
*** * ** * * *** * ** * * ** ** * ** *** * ***** * *** * ****** **
** * * **** ** *** * *** * * ** *** * *** ** ** **** ** *** ** *** * *** **** * *** **** * * ** ** *** * ** is not a prefix of %s",a,b);
** *** * ** *** * *** ***** * ** ** ** * ***** * **** ** * * ** * ***** ***** * * ** * * **
** * * ** * *** * ** ********** * ** ** *** ** ** * ** ****
*** * ** **** ** *** *** ** * ** * * ** * * *** **** if(c==strlen(a)-1)
* *** ** * * *** ** * ** ** **** *** ******* *** ****** ** * * * ** ** ******* ** **** * * is a prefix of %s",a,b);
    }
* *** * ****** * *** * * ** 0;
}
answered by (-498 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <string.h>
int main()
{
*** ** ** * **** * *** n,count;
* * ** * ** ***** * * ** ** *
** * * * ** ** * * * * ** *** * *** %s",a,b);
* *********** ***** * *** *

* *** ** ** ** * * * ** * * * * ** ** * * * *
*** * *** ** **** *** *
** * ** * * * * *** *** **** ****** ** * * ** *
* * ** ** * * * **

** ***** ** * ** * (strcmp(a,c)==0)
* *** * * * * ****
* * * ** *** ****** * **** * * * ***** * * * ** * is a prefix of %s",a,b);
** *** *** * ******* ** **
* * **** ** ** * * * ** **
* * * *** * *** * * *
**** * * * ** * * *** **** * *** * * * ****** is not a prefix of %s",a,b);
** ** * ** ****** *
* ** * * * * ** * **** 0;
}
answered by (-284 points)
edited by
0 0
prog.c: In function 'main':
prog.c:8:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s %s",&prefix,&word);
             ^
prog.c:8:16: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
     scanf("%s %s",&prefix,&word);
                ^
prog.c:10:15: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     for(i=0;i<strlen(prefix);++i)
               ^~~~~~
prog.c:10:15: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:10:15: note: include '<string.h>' or provide a declaration of 'strlen'
prog.c:18:6: error: expected '(' before 'printf'
      printf("%s is a prefix of %s",prefix,word);
      ^~~~~~
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
#include<string.h>
int main()
{
* **** *** ** * ****** a[100],b[100];
* ***** ***** * ***** ** *** * * *** * *
    int l1,l2;
*** ** ***** **** ** * * * * * *
* *** * ** ** ** ** * * * **
* * * * ** **** ** * * * * *
*** ** ** * ** *** ** * * * *** * ** ** ** * *** ** ** * is not a prefix of %s",a,b);

    }
** * * * * ***** if(l1<=l2){
* * ** * *** ** * * *** * *** * * * prefix=1;
* ** *** ** * * * *** * * *** * ** ** * * * ** i=0;
** * * * * ** * * * * *** ** * * *** ******* ** * ***
*** * ** * * ** ** *** ** ** * * *** ***** *** ** * * * (a[i]!=b[i]){
**** **** **** * * * * * **** * * * ** * ******** * *** ** * * * **** *
* * *** * **** * **** *** ** **** * * * ** * * ** ** *** * ******** * ** * ***
** * ** * * **** ** **** *** * ** * * *** *** * *** ** * *


*** *** *** * * * *** * * *** * * *
* ** * * * ***** ** * ** * ** **** **** * * ** * ** * ** *
***** * * * *** * * * *** * ***** * ** ** * * **** * * * * ** ** is not a prefix of %s",a,b);
* * * * ****** * *** * *** ** * ** * * * * * **
** * ** * * * * ** ** ** ** * ** ** * *** **
* *** *** *** ** ******* ******* ** ** * ** *** ** is a prefix of %s",a,b);


    }


}
answered by (-329 points)
0 0
prog.c: In function 'main':
prog.c:5:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
             ^
prog.c:5:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
               ^
prog.c:7:8: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     l1=strlen(a);
        ^~~~~~
prog.c:7:8: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:7:8: note: include '<string.h>' or provide a declaration of 'strlen'
0 0
prog.c: In function 'main':
prog.c:6:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
             ^
prog.c:6:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
               ^
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
* * * **** * **
int main(void)
{

** ** **** * * ** * ** pre[100];
* * * **** ** * ***** word[100];
* * * **** * ** *** %s",pre,word);
** ***** ** * ** ** * * ** * * *
** * ******* * ** **** ** *** ** *

* *** ** ** * **** i;
* ** * * ** ** ** * ** * ** * *
** * * * *** * ****
* ** ****** *** * *** * *** * * * *** ***** * ***
** *** * * ** ****** *** ** * * ***** ***
** ** * *** * ***** * * * *** ****** * ***** * * * ** **** *** * *** ** is not a prefix of %s",pre,word);
* ** * ** * * * * * * ** ** * * * *** *** ********* ** * ** *** ***** * 0;
* * * ** * * * * *** ** ** * **** ** * * ***

* * * * * ** ** * ** *
printf("%s is a prefix of %s",pre,word);
return 0;
}
answered by (-249 points)
0 0
prog.c: In function 'main':
prog.c:8:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&pre);
             ^
prog.c:9:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&word);
             ^
0 0
prog.c: In function 'main':
prog.c:8:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&pre);
             ^
prog.c:9:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&word);
             ^
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <string.h>
#include <ctype.h>
int main ()
{
* * * *** * ** *** * * ** pre [100],a[100];
*** * * ** * * *** n ,i;
*** *** *** *** * ** ***
** ** * * * *** ** ** ** * * *
**** * * * * ******** * * * **
** *** ****** * * *** * * *
** *** * *** * *** * * * * * *** ********* ** ** (n=0;n<strlen(pre);n++)
*** * *** * ** * * *** *** ** * * ** **
******* ** **** **** **** ** ** * ** * * * ** * *** ** ** * ** ** *** (pre[n]==a[n])
*** * *** * ** **** * * * *** ** * *** * * *** *** **** * *** * * *** is a prefix of %s",pre,a);
***** *** * * * * * * *** * ***** ** **** * * ** * *** * ** *
**** * * ***** *** ** * * * * * *** ** *** ** ** * * * * * *** * *** *** * * ** *** * * * *** * is not a prefix of %s",pre,a);return 0;
* ** * * ** ** ** **
* ** **** * * * * *** *** * ****** * * ** * * ** *

*** *** * * * * ** * * 0;
}
answered by (-32 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include **** **
#include *** ** *

int main()
{
* * *** ** ***** *** * a[100];

***** * * ** **** ** * *** * b[100];

*** * * **** ***** * * *** **** * * * %s", a, b);

******* ** * * * len_a = strlen(a);

* *** *** * * * ** * i = 0;

* * * * *** * ***** **** flag = 1;

* ** * ** * ** **** * ** *** = 0; i < len_a; i++)
***** * * *** * **** **
** **** *** ** ** ***** * * * ******* * **** * != b[i])
* ******* * * ** ** * * *** * ** *** ** *
** **** **** ** *** * * * ******* *** ** ** * * * ***** * **** ** = 0;
* ******* ** *** * ** **** * ***
* ** ** * * * *** * *

*** *** * * * *** *** * * == 0)
****** * * ** ***
** *** * * * * ** * * ** ***** * * *** * ** * ** * * * * is not a prefix of %s", a, b);
* * * *** * ***
***** ***** * ** * * *
** * ** ******** ** *
** ** ** * * ** ** * ****** ** **** * * ** ** is a prefix of %s", a, b);
* * * * *** *
** *** * ** * * *** * 0;
}
answered by (-285 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
** *** * * * *
int main()
{
**** * ** * * ** * * ** i,n;
*** ***** ** * *** p[100],s[100],a[100]={};
** * * * * ** * * * ** ****** ** %s",p,s);
** * ** * * *** *** * ** *
* ** ** ** **** *** * * * *** *
*** *** ** ** * *** *** * * **** *****
** * ** **** *** * * * * *****
** * **** * * ** ***** * * * ** ** * * * * *** is a prefix of %s",p,s);
* * * * * ** * * **** * **
* * ** * * * ** ** ** **
** **** ** ** ***** * * * * ** ** * **** ** * * ***** is not a prefix of %s",p,s);
* * ***** ** * ******
* * * * * ***** ** ** ** * * ** **** * * ** **
** * ********** * * ****** ** 0;
}
answered by (54 points)
edited by
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
#include<string.h>

int main()
{
    int i;
    char a[100];
    char b[100];
** ** ** * * * * *** ** ** ** ** *
    scanf("%s",b);
    for(i=0;i<strlen(a);i++)
* * *** **** ********* * * *** ** * * **
* * * *** * * * * *** * * * * *** * * *** * **** ** ** * != b[i])
*** * ***** * ** *** * * * * **** * * *** * ** * * * ** * * * ** **
* ** ** **** ******* * * ** **** * * ** * * *** * ** * * *** * ***** * ******* **** ** ** *** ** *** * ** is not a prefix of %s",a,b);
* * * ** *** ******* ***** * * *** * * ***** ** * * ** * ** *** ***** * ** * * ** ***** **** *** **
** * * * * * * ****** ** * * ***** * * * *** *** ******** ** * * ** * * **
* * ** * ** *** ****** ** ** * * *** * ** * * * * ** ** **** *** * * == b[strlen(a)-1])
* ** ****** *** *** * * * * * * * * *** * ******** * ** * *** ** * *
** **** * ** * * ** **** *** *** * * * * * ***** ** **** * ** *** * * ** **** *** * * * *** * * * ** ** *** is a prefix of %s",a,b);
** * * * **** **** **** *** *** * **** * *** * * *** * * * ** ***** **** *** ** **** ** * * * ** ** * *****
*** * * * * * * *** ** * ** * *** ** * ****** * * * * *** ** * ** * * * ** * * * **
** ** * *** * *** * * ** ** ** * * *
}
answered by (-301 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
#include<stdlib.h>
#include<string.h>
#define n 100

int aa(char a[],char b[]){
** **** ** ** * * * ********* ** ** i;
* ** * *** ** **** **** (a[0]!=b[0]){
* * * * * **** * ** * * * * ** * * * ** * 0;
*** * * * *** * ** **** ***
***** * * * ***** * * * * *** * * *** * *
**** *** ** ** * * ******** ****** *** ** *** ** * *** ** *** * a[i]==b[i])
* * * *** * ******* * * *** ** * *** *
** * * *** ** * * * * * ** * * * ** *** *** * * ** * ********** ** *** * 1;
*** * ** * ** ** ** * * *** *** * ** * **** ** *** **** ** ****
* *** **** ** ***** * ** * ****** * * * ** ***
*** * * ******* *** ** * ****
* ** **** **** ** *** * ** 0;

}

int main(){
*** ** * * * **** **** c[n],d[n],e[n];
* * *** ** ** * * *** i;
* * ** ** * * *** * ****** ** *** %s",c,d);

*** ** ****** *** * * *
* *** * ** * * ***** *** ****** ** * * * * * is a prefix of %s",c,d);

* *** ** * *
* ** * *** **** * * * * **** * * * * * is not a prefix of %s",c,d);


}
answered by (-32 points)
edited by
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.130.92
©2016-2025

Related questions

1 like 0 dislike
37 answers
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42302 - Available when: 2018-01-17 14:00 - Due to: Unlimited
| 12.7k views
2 like 0 dislike
31 answers
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42301 - Available when: 2018-01-17 14:00 - Due to: Unlimited
| 11.7k views
1 like 0 dislike
32 answers
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42300 - Available when: 2018-01-17 14:00 - Due to: Unlimited
| 13.8k views
2 like 0 dislike
30 answers
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42298 - Available when: 2018-01-17 14:00 - Due to: Unlimited
| 10.4k views
0 like 0 dislike
4 answers
[Exam] asked Jan 19, 2018 in Final Exam
ID: 43460 - Available when: 2018-01-20 09:00 - Due to: Unlimited
| 2.7k views
12,783 questions
183,442 answers
172,219 comments
4,824 users