1 like 0 dislike
6.9k views

A string p is a prefix of a string s if the leading characters of s are identical to p. For example, "abc" is a prefix of "abcde". Develop a function prefix that checks if a C string p is a prefix of another C string s.

p是s的前綴若s開頭的一段字串等於p。例如,"abc"是"abcde"的前綴。寫一個程式 判斷字串p是否字串s的前綴。

Example input 1:

abc
abcde

Example output 1:

abc is a prefix of abcde

 

Example input 2:

bc
abcde

Example output 2:

bc is not a prefix of abcde

 

[Exam] asked in Final Exam
ID: 42299 - Available when: 2018-01-17 14:00 - Due to: Unlimited

retagged by | 6.9k views

37 Answers

0 like 0 dislike
Hidden content!
#include * * * * **
#include ***** **
* * * *** ** * *
*** * *** ** ****

int prefix(char a[], char b[]){
int i, j,n;
int cnt=0;

n= * *** ****

* * ***** * *** **** ** ** **
* * ** *** **** * ** ** ** *** == b[i]){
** **** ** ** * * *** * *** *** * ****
* * * * * * **** *****

*** ***** ** *
if (cnt == n){
* *** * ** * * *** * ** *** ** ** * *** ** * ** * 1;
* ***** * ******** *** ** * * * ***** ** * *
**** *** * * * * * ** * ***
* * * **** *** ** ** ** * ** ** ** ** 0;

}

int main()
{
* *** ** * ** * ** * * * s1[100], s2[100];
**** ** * ** * ** i,j;

**** ** * *** *** **** *** ****** * *** s1);
* *** ** * * ** ** * ** * ** * * * * s2);
****** *** ***** ** * (prefix(s1, s2)){

** **** **** * * * * ** *** * **** * ***** is a prefix of %s", s1,s2);
*** *** ***** **** ** * * * **** * * *
** *** * * ** * ** * ** * ****** * ** *
**** * * ** ** *** * * * * * * * * ****** *** * * ** *** * ** is not a prefix of %s", s1,s2);



}
answered by (323 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <string.h>

int main(){
* *** * ** * ** *** * c;
** * ******** * ** *** * a[100],b[100];
** *** * * *** * ** ** ** %s",a,b);
****** ** ** ** * *** *** * ** *
* * ** **** *** * ** * ** **** * ******* *** * ** * * ** 0;
* ** ** * ** ** * ** **** **** * %d",strlen(a),strlen(b));
* ** *********** * * ** * **** * ** * **
* * * * *** ** *** * * * * ** * * ****** * * * ** * **** * * ** ** *
* ** ** * *** ****** ******** * ** * * ****** *** * * * * * ** * ***** *** *** *** ** * *** * *** ** is not a prefix of %s",a,b);
** *** ** *** ***** * * * * * * * ** ** * * * * * **** *** *** *** * * * * ** *** ** * * **
* * ** * * **** ** * ** ** ** * *** * * * *** * * * * **** ** ***
** * ** ***** * **** ** ** * * * ** * ***** **** if(c==strlen(a)-1)
* * * * * **** * **** * *** * * **** *** **** ** *** * ** *** **** ** * *** ** * *** * * * * * ***** * is a prefix of %s",a,b);
    }
** * * *** * ** ** *** *** 0;
}
answered by (-498 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <string.h>
int main()
{
*** *** *** ** * ** ** ** n,count;
******* * * * * ** ***** * * * **** * * *** ***
* * * * * * ******* ***** * * *** %s",a,b);
** * * * * ** * *

*** **** * ** * **** * ** * ** * ** ** *** * **
* *** ** *** * *
* * ** * * * **** ** * * **** ******* *** * *** *
* *** * * * ** * * *

* * * *** *** * * ** (strcmp(a,c)==0)
*** * * * ** *** *
** * * * * ** * * * *** * * * ** * ****** * * * * is a prefix of %s",a,b);
*** *** * ***** * ** *
* * * * ** * *** **
* * * * ** * *** *
* *** ****** *** *** * ** * ** ** **** * * ** ****** is not a prefix of %s",a,b);
***** ** ** ***** ** ***
* ** ** * *** ***** ** *** 0;
}
answered by (-284 points)
edited by
0 0
prog.c: In function 'main':
prog.c:8:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s %s",&prefix,&word);
             ^
prog.c:8:16: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
     scanf("%s %s",&prefix,&word);
                ^
prog.c:10:15: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     for(i=0;i<strlen(prefix);++i)
               ^~~~~~
prog.c:10:15: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:10:15: note: include '<string.h>' or provide a declaration of 'strlen'
prog.c:18:6: error: expected '(' before 'printf'
      printf("%s is a prefix of %s",prefix,word);
      ^~~~~~
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
#include<string.h>
int main()
{
* * * ** ** *** ** a[100],b[100];
** ** ****** *** ** **** * * ** *
    int l1,l2;
* * * * ** * ** * * ** * ** * *
* ** * * ** *** * ******** * *
** * ** ** * * ** * **
* ** ** * *** ** * *** * * ** * * ** *** ** **** **** is not a prefix of %s",a,b);

    }
****** ** * **** **** * ** if(l1<=l2){
**** *** * * * ** ** * ****** * ***** * *** * prefix=1;
* * * * * ** * **** * * ** *** ** * i=0;
* * * ** ** *** * * ** ** * * ***** * ** ** *
****** ****** * * ** * * * * * * * ** * ** * ** **** *** * * *** (a[i]!=b[i]){
****** ** ** * * ** **** *** * **** * * ***** ** *** * ** ** * * * * * * * ****
* **** * ** * ***** ** ** * * * * ** ** *** ** * * *** * ** * * * **** * * ** ***
* **** ** * * **** ** ** * ** *** * * * * * * * * **** *


* ** * * **** * * * **** *** *** ****
**** * *** ** * * ** **** *** **** ** * ****
** **** * ** * * * ***** *** * * * * ** * * * *** * * * ** * ** * ******* is not a prefix of %s",a,b);
*** ** * * * **** * * * * ***** * **
*** ** ****** ** * ** **** ** *** **** * ***
** * * * ** * ** ** **** * * * * ** ** ** ** ** * is a prefix of %s",a,b);


    }


}
answered by (-329 points)
0 0
prog.c: In function 'main':
prog.c:5:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
             ^
prog.c:5:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
               ^
prog.c:7:8: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     l1=strlen(a);
        ^~~~~~
prog.c:7:8: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:7:8: note: include '<string.h>' or provide a declaration of 'strlen'
0 0
prog.c: In function 'main':
prog.c:6:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
             ^
prog.c:6:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
               ^
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
** ** ** * *
int main(void)
{

*** **** ** * ***** * * * ****** pre[100];
* ** ***** ** * **** *** word[100];
* *** * * * * ** ** * ******* %s",pre,word);
* ** * * * * * ** **** *****
* ** *** * ** * * * ** ** *

** ** *** * * * * * * i;
*** ** ** * * *** ** ** ** ** *** *****
* * ** *** * **** * *
* ** * ** * *** ** *** *** * * *** ** * * * ** *
* * * ** * * * * ** * * * **** * ****
* * ** *** * *** ** ***** *** * * * * *** * ** * * ****** * ****** *** ** * is not a prefix of %s",pre,word);
**** * **** * * * ** ****** **** * ** * *** ** ** * * * * 0;
*** * ** * *** * * ** *** * ** **** * **

**** ** * * * *** ** * *
printf("%s is a prefix of %s",pre,word);
return 0;
}
answered by (-249 points)
0 0
prog.c: In function 'main':
prog.c:8:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&pre);
             ^
prog.c:9:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&word);
             ^
0 0
prog.c: In function 'main':
prog.c:8:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&pre);
             ^
prog.c:9:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&word);
             ^
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <string.h>
#include <ctype.h>
int main ()
{
* ******* ** * * * **** **** pre [100],a[100];
* ** * * * * * * * n ,i;
* * * ** * **** **** * * * * * *
* * * * ***** ** ** ** ***
* **** * * *** * * ** * ** *****
* *** ** * * * ***
** ****** * **** ** ** *** * * ****** *** (n=0;n<strlen(pre);n++)
* * ** ** * * ** * ** * * * * **
**** * *** ** * * **** *** **** ** ** * * * * * ** * * *** (pre[n]==a[n])
** ***** * * **** ******** **** * * ** * ****** * * ****** * * *** ** ** ** is a prefix of %s",pre,a);
* * * * ** * * * * *** ** * * * ** **** * ** * * * * * *
* ********* **** * * * **** *** * * * ** **** * *** * ** **** * * ** * * *** is not a prefix of %s",pre,a);return 0;
*** * * *** ** ***** * * **
** * * *** ** *** ** * * * * ** ** ** ** ** *** ** * ** *** **

** ** ** * *** * *** 0;
}
answered by (-32 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include ** * ** ***
#include ** * * ** *

int main()
{
* * * * ** **** * a[100];

** * * * ***** ** ** *** ** b[100];

** *** ****** * * ***** * * %s", a, b);

**** * ** * *** * * ** * len_a = strlen(a);

*** * ****** ** * * *** * i = 0;

*** * * ** * * ** * * flag = 1;

* ******** * ** ** * * * ** = 0; i < len_a; i++)
* * *** * *
* * * * ** *** * *** * ** ***** **** *** *** * * * * ** != b[i])
*** ****** **** * * * *** * * *** ********* * * *
* ***** ** * ** ** * ** ** **** * ** * *** ** ** ** ** = 0;
* * ****** ** * * ** ** ** * * * * * * * *** **
*** ** ***** * **

****** **** *** * * == 0)
** ** * * *** * * * ****
**** **** ** * * * * ****** ** *** * ** ** **** ** * is not a prefix of %s", a, b);
**** ** ** * *** ***
*** ** * * ** * * *** *
******* * * * * * * *
* *** * * ** * *** ** * **** ** ******* * * * * ** ** * is a prefix of %s", a, b);
*** ** *** ************** *
* ** ******* * * * *** *** 0;
}
answered by (-285 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
* * ** * * * * ***
int main()
{
** ** * * * * * ** i,n;
* * ** * ****** * * p[100],s[100],a[100]={};
***** * ********* ** ** * ** *** * %s",p,s);
** * **** * * ** ** * ** **
* * * * * * * ** *** ** * *** *
* ***** *** * * ** * * ******* **
* ** * * *** **** * * ** * ***
* * * ***** ** * **** ** ** * * **** ** *** * is a prefix of %s",p,s);
* ** * *** * * **
* ** * * * **
*** * * *** * ****** ** * * * * * * * * * ***** ** is not a prefix of %s",p,s);
**** ** * **
** ** * * *** *** ****** ** * ** **
* * **** * ** *** * **** * * * 0;
}
answered by (54 points)
edited by
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
#include<string.h>

int main()
{
    int i;
    char a[100];
    char b[100];
** ** * ** ** ** * ** ***** ** *** * * ** ** *
    scanf("%s",b);
    for(i=0;i<strlen(a);i++)
** *** * ****** *** * ***** ** ***** * *** *
**** ** * ** ******* ** *** ** ** ****** *** ** ** * ****** * * != b[i])
* ** **** * * ****** ** ** **** * * * * * ** ** *** * ** *** ** * **** ****** ****** * *
* * ** * *** **** ** ** ** ** * ** * **** *** *** * ** * ** ** * **** **** * ****** * * *** * *** * * * is not a prefix of %s",a,b);
* *** * * * *** ** * * * * *** * * * * ** **** * ** ** * * * * *** * * * *** * * ** *** *
* * * *** *** *** ** * * ** * * ** **** * * * * ******** * ** ***** ** * **** ****** **
*** * * *** * * *** * **** ***** * * * ** ** ** *** * * *** ***** * * * ** * == b[strlen(a)-1])
* ** ** ***** * ** *** * * ******** * * * ** * * * **** * * ** *** **** ** *
* ** * * ***** * * ** ***** ** * **** * ** * *** *** ***** * ** * * * * * * * *** **** ** * ** ** ***** is a prefix of %s",a,b);
* ** ** * * ****** *** ***** * * ****** ** * * * * ** ** * ** * **** ** * ****** ** * ** * ** * * ** * *
** * * * * * ** ********* **** * *** *** *** ** * * ** * * ** ** ** *
** *** ** *** * ***** ** **** * * *
}
answered by (-301 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
#include<stdlib.h>
#include<string.h>
#define n 100

int aa(char a[],char b[]){
* *** *** **** ** *** **** * i;
** * ***** ** *** ** * (a[0]!=b[0]){
** * * ** *** ** ** **** ** ** * * ** * 0;
*** * ** *** ** * * ** ** *
* * * * * ** *** * * ***** ******** ** *
* ** ** * * ****** * ***** * ***** ** * * *** a[i]==b[i])
** * * *** ** *** * * **** * ** * * * * * **** *
* * * ** *** ** * *** ** * * *** * * * * ** * * *** *** ******* ** ** * * 1;
* * *** *** **** * **** * * * * * ** ** **** ****
**** * * ** * * *** ** ** * * ** * ** * * * ** **
* **** * * ** ** * *****
* *** * * * ** * * ** 0;

}

int main(){
*** * * ** ********* * *** * c[n],d[n],e[n];
*** * *** ** * ** *** * * i;
* ** * ** * * * * * %s",c,d);

** ** * *** *** *** *** *
** * ***** * * ** * ** **** * ** ** * * * *** is a prefix of %s",c,d);

* ****** * * **** ** *
****** **** * * ** * * * * ** ** *** * ** * * *** * is not a prefix of %s",c,d);


}
answered by (-32 points)
edited by
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.58.199
©2016-2025

Related questions

1 like 0 dislike
37 answers
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42302 - Available when: 2018-01-17 14:00 - Due to: Unlimited
| 7.2k views
2 like 0 dislike
31 answers
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42301 - Available when: 2018-01-17 14:00 - Due to: Unlimited
| 6.2k views
1 like 0 dislike
32 answers
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42300 - Available when: 2018-01-17 14:00 - Due to: Unlimited
| 7.1k views
2 like 0 dislike
30 answers
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42298 - Available when: 2018-01-17 14:00 - Due to: Unlimited
| 5.4k views
0 like 0 dislike
4 answers
[Exam] asked Jan 19, 2018 in Final Exam
ID: 43460 - Available when: 2018-01-20 09:00 - Due to: Unlimited
| 1.3k views
12,783 questions
183,442 answers
172,219 comments
4,824 users