0 like 0 dislike
2.1k views

You are requested to help in writing a program to perform addition of two large number up to 50-digits. In C there is no builtin datatype for large number, but we can use characters and array to solve the problem.

Input: The input will contain two positive integers are separated by a blank, the two positive integers do not exceed 50-digits.

Output: Sum.

寫一個程式輸入兩個大數(最大50個位數),計算其總合。C語言不提供大數資料型態,但我們可以用字元和陣列來解決這個問題。

Example input:

999999999999999999999999999999 999999999999999999999999999999

Example output:

1999999999999999999999999999998

 

[Exam] asked in Final Exam
ID: 43460 - Available when: 2018-01-20 09:00 - Due to: Unlimited
| 2.1k views

4 Answers

0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>
#include <string.h>

char input[500],s1[500],s2[500],temp;

int i,space,sum[500],carry,temp2,flag=0;

int main(){
** ** * * * * * ** ** * * * ** ** *** %s",&s1,&s2);
*** * **** * * * ** **** *** * *

///get space
* * *** ** ** * * *** *** * ** ** * *** *
** * ** *** * * * * * ** ** * ** * ***** * '){space=i;}
    }

///get s1
* *** ** * * ** ** * * ** * ';i++){
* ** *** *** * ** *** **** ** * **** * ** **** * * *****
    }

******** * ***** * **** **** * ** * **
///reverse input
* **** * * * * ** ** *** **** ** * * * *
***** **** ** * ** ** * **** * ** * *** * ** *** * *
**** **** * *** * ** * * * * *** * * * * **** * ** ** ***
* * **** * *** *** * ** *** *** * * ** * * ** * **
    }

///get reversed s2
******** ** * ** * * ** ** * ';i++){
*** *** *** * **** * *** * *** * * *** * **
    }

///reverse s1

** ** ** * * ******* * * * *** * *
** * ** ** **** * **** * * * * * * *** **** * ** * * ** *

* * * ** ** * * ** ** * * ** ** ** * ** ** ** * *
* * ****** * ******* * * ** ** * * * * * * *
    }

///sum s1 and s2
* * * * * **** *
** * * ** * **** ***** ** ** * **
** **** * *** * ** *** * *** *** *** *** **** * ** **** * ***** **
* **** ** * ** * * * ***** * *** * ** ** * ***** **** **** *
* ** *** * ** ***** ** **** ** * * * ** ** ******* * * ******
******** *** ** * * ** * *** * * ***** * * * ***
* * * * * * ***** *** * * * * * ** ** * *

    }

* * ***** ***** ** ** * rev:%s\n",input);
* ** **** *** *** * * *** * rev:%s\n",s1);
** ** * * ** * ** ** **** rev:%s\n",s2);
* ** * * ** * * ** * * *** ** **** *** ****** * ***** * **** **** * * ** ****

///reverse output
* * * * *** ** * *** **** ** * *
* *** * * ** * * * *** * ** * ** * * ** *** ** *

* **** **** * * **** * **** * * **** * * * * *
** ** * * * *** ** * * * * * * ** ** ** * * *
    }

///print
** * *** ***** * **** ******* ***
* * ****** **** * ***** *** ** * ** * **** ** * * * ** * * * ***
* *** ** *** * ***** *** * * ** ** * * **** * * ** * ** * ** **** *
** * * ****** * **** * * * * * *** * ** ***** * * ** * * * * *** ** * ** ** ** * * ** ** * ** **** **
* *** ***** ** ***** * * ** ** **** *** *** * * *** * **** ** * **** *** ** * * * *
* ** ***** ** *** * *** ** * * **** ** * ****** ** ** ***** *

* *** ** **** * ** * ** ** *** * * * ** * ** *

    }
* ** *** ***** * ** ** * *** * * * ***
    return 0;
}
answered by (-286 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
prog.c: In function 'main':
prog.c:80:12: warning: multi-character character constant [-Wmultichar]
     printf('10');
            ^~~~
prog.c:80:12: warning: passing argument 1 of 'printf' makes pointer from integer without a cast [-Wint-conversion]
In file included from prog.c:1:0:
/usr/include/stdio.h:364:12: note: expected 'const char * restrict' but argument is of type 'int'
 extern int printf (const char *__restrict __format, ...);
            ^~~~~~
prog.c:80:5: warning: format not a string literal and no format arguments [-Wformat-security]
     printf('10');
     ^~~~~~
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 like 0 dislike
Hidden content!
#include<stdio.h>
#include<string.h>
int main()
{
* * ***** * * ** * string1[50];
* *** ** * ** **** **** string2[50];

* * * ** * *** *** ** * ** * **** string1);
* ** ** * **** * * ** ** *** string2);
* *** * ** * *** **** * arr[51]={0},i;

* ** * * ** ** *** * * i<strlen(string1); i++)
* ** ** * * ** * *
** * * * * * * *** **** * ** * * ** * * * * * += string1[strlen(string1) - 1 - i] - 48;
    }

*** * ** * * **** ***** i<strlen(string2); i++)
* * *** ** *** * * **
***** ***** *** *** * * * * ** ** * *********** * * * += string2[strlen(string2) - 1 - i] - 48;
*** ************** ** * ****

** ** * * ******** * * ***** * i<50; i++)
*** * * * ** * * * *** ***
* **** ** * *** **** *** * * * * * ** ** * ** * *** > 9)
***** ** ** * * * * * * *** ** * * ** *** * ****
* * * * * * * *** * * ** *** * ** * ** * ** * ** * * *** ** * ** * -= 10;
*** *** * ** * ** *** * * * *** ** ********** ** * ** * * * * **
* ** * * *** ** * *** * * * ** ** * * * *** *
* ** * * ** ** ** ***

**** ** *** * **** * * i>=0; i--)
*** ** * ** ** **** ******
** * ** ***** *** *** ** ** * * * ** != 0)
* ** * * ****** ** * ** **** ** * *** **** * * ** * * * ** ** *** * **
* * ** * * **** ****

* * * * * * *** * **** * i--)
***** * *** * * *** *** ** ***** * * * * ****** *** * **** ** arr[i]);
}
answered by (-168 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
int main (){
int s1,s2,l1,l2;
int num1[50],num2[50],sum[50];
printf("enter input 1: ");
* * * * ** *** **
printf("enter input 2: ");
* * * *** ** * *
for(l1=s1[l1]!='\0')
* * ** * ** * * ** *
for(l2=s2[l2]!='\0')
*** * ** * * ** ** *** **
int carry=0;
int k=0;
int i=l1-1;
int j=l2-1;
* ** *** * ******* *
{
* * * ** * ** ** ** ** * * * * *
* *** * *** ** ** *** * *
* ** **** ******* * *** ***** ** *** * * *** **** *****
*** * ******* **** * ** ******** ** ** * ** * ** * * *** ** ***** ** *** *** *****
** * * * ** * ****** *** **** * * * * * ** ******* * * * * * * **** ***** ** **
****** ****** *** * ** * if (j>=0)
* ** ***** * **** *** * * * * * ** * ** **** **
** **** * * **** * * * * ****** * *** *** * * * *** * **** * * * ** * **** * ** ** *
** *** * ** * ** ** ** * * ** *** * **** * * * * * * *** * * ** ** *** ***
* * *** * ** ***** ** * *** **** * ******* * ** if(carr>0)
** * ** * * * * * * **** ** ***** *
* *** * * *** ** ** ** ** ***** * * * * **** * ");
* * * * ** * * ** * * * **** **** *
}
for(k--;k>=0;k--)
**** ** ** *** ****
** ******** *** * * ***** **** **** ** *** * ***
* * * ***** * *
  return 0;
}
answered by (16 points)
0 0
prog.c: In function 'main':
prog.c:9:10: error: subscripted value is neither array nor pointer nor vector
 for(l1=s1[l1]!='\0')
          ^
prog.c:9:20: error: expected ';' before ')' token
 for(l1=s1[l1]!='\0')
                    ^
prog.c:9:20: error: expected expression before ')' token
prog.c:10:10: error: subscripted value is neither array nor pointer nor vector
   num1=s1[l1]-'0';
          ^
prog.c:11:10: error: subscripted value is neither array nor pointer nor vector
 for(l2=s2[l2]!='\0')
          ^
prog.c:11:20: error: expected ';' before ')' token
 for(l2=s2[l2]!='\0')
                    ^
prog.c:11:20: error: expected expression before ')' token
prog.c:12:12: error: subscripted value is neither array nor pointer nor vector
     num2=s2[l2]-'0';
            ^
prog.c:17:15: error: expected ')' before ';' token
 for(;i>=0;j>=0;i--;j--;k++)
               ^
prog.c:23:13: error: expected ';' before 'carry'
             carry=(num1[i--]+num2[j]+carry)/10;
             ^~~~~
prog.c:27:13: error: expected ';' before 'carry'
             carry=(num1[j--]+num2[j]+carry)/10;
             ^~~~~
prog.c:28:18: error: 'carr' undeclared (first use in this function)
         }else if(carr>0)
                  ^~~~
prog.c:28:18: note: each undeclared identifier is reported only once for each function it appears in
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>
#include <string.h>


int main()
{
*** * ** *** **** ** * ** a[50],b[50];
* ** ** ** * * * * c[51]={0};
* ****** * * ** i;
***** * ** * ***** * * * * x=0;

* *** *** * * * * * * ** * * ** %s",a,b);

* ***** ** ** ** * ** * ** *** *
    {
**** * * ** * ** * *** ***** * ** ** **** ** * *** * *****
    }

*** ** * ****** ***** ** * *** ** *** * * *
* * ** * **** ** * * *
* * ** * ******* * ** *** ** * **** *** ** * ** **** ** * *
*** * * * * * *


***** **** ** *** ** ** *
* **** **** *** ** * **
* * ** * ** * * * **** * **** * * * *** ********* *** **** ** *
*** ** ***** * ** *** *** **** *** * * * ****
* * **** **** ** * * * * ** * ** ***** * * * * * ** * ***** *
***** * **** * * * * * *** * **** ** * ** * * * * ***** **** * * * * * **
**** * * * **** ** ** * ** * **** * * ** *
    }

******** * * *** **** ** ** *
* ***** *** ** * **
* * ** *** * * ** *** * * * * ** ** ******* * *** != 0)
******* *** **** * *** * * ** * ** *
* ** **** * ** ** *** ***** * * * *** ** * * ** * * ****** ****** * *
** * * ** * *** * ** *** ** *** *** ** **** *** *** *** ** * * ******
* * * * **** * * ** ** * ** ** *** * * * *****
    }

* * ** ** * **** * ** * ** *** * * ****
    {
****** ******* * * ** * * * * **** * * * * **** *
    }


*** ** * ** * * * ** * 0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.59.97
©2016-2025

Related questions

0 like 0 dislike
13 answers
[Exam] asked Jan 19, 2018 in Final Exam
ID: 43463 - Available when: 2018-01-20 09:00 - Due to: Unlimited
| 3.5k views
0 like 0 dislike
6 answers
[Exam] asked Jan 19, 2018 in Final Exam
ID: 43462 - Available when: 2018-01-20 09:00 - Due to: Unlimited
| 1.8k views
0 like 0 dislike
8 answers
[Exam] asked Jan 19, 2018 in Final Exam
ID: 43461 - Available when: 2018-01-20 09:00 - Due to: Unlimited
| 2.1k views
0 like 0 dislike
12 answers
[Exam] asked Jan 19, 2018 in Final Exam
ID: 43459 - Available when: 2018-01-20 09:00 - Due to: Unlimited
| 3.6k views
1 like 0 dislike
37 answers
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42299 - Available when: 2018-01-17 14:00 - Due to: Unlimited
| 10.6k views
12,783 questions
183,442 answers
172,219 comments
4,824 users