1 like 0 dislike
10.3k views

A string p is a prefix of a string s if the leading characters of s are identical to p. For example, "abc" is a prefix of "abcde". Develop a function prefix that checks if a C string p is a prefix of another C string s.

p是s的前綴若s開頭的一段字串等於p。例如,"abc"是"abcde"的前綴。寫一個程式 判斷字串p是否字串s的前綴。

Example input 1:

abc
abcde

Example output 1:

abc is a prefix of abcde

 

Example input 2:

bc
abcde

Example output 2:

bc is not a prefix of abcde

 

[Exam] asked in Final Exam
ID: 42299 - Available when: 2018-01-17 14:00 - Due to: Unlimited

retagged by | 10.3k views

37 Answers

0 like 0 dislike
Hidden content!
#include ** ** * *
#include * ** ** *
* *** *** *** * *
** * **** * *

int prefix(char a[], char b[]){
int i, j,n;
int cnt=0;

n= ** * * * **

* * * * * *** * * ** * ** *** * ***
*** * * ** ***** * * ** * == b[i]){
** *** * ** *** *** ** ** ** ** * **** *** *
** ** * * *** * ** ** *

* * * ** *
if (cnt == n){
* * * *** * * ** *** * ** *** * **** 1;
***** * ****** * * **** ** ** ****
* * * ** ** ** ****** *
* * ******* * * * *********** **** *** * * * * 0;

}

int main()
{
**** ***** * * * * s1[100], s2[100];
**** * ** * i,j;

* ** * *** * ** * * *** * ** *** s1);
* * ** * ** ***** **** * *** * *** * * **** s2);
*** ** * ** **** (prefix(s1, s2)){

** *** * ** **** ** * ** ** * * * * * * ***** ** *** is a prefix of %s", s1,s2);
** * * ** ** * *** * * *** * * * **
* ****** ** ** *** * * ** * ** * **** **
** * * * * **** * * ** *** ** ** *** ** ** *** *** *** * is not a prefix of %s", s1,s2);



}
answered by (323 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <string.h>

int main(){
* ** * ** * * * ** * c;
*** * * ******* ***** a[100],b[100];
******* * ** ********* * **** ** * * * %s",a,b);
** * * * * * * * * *** * ** ******** ** *
* * * * * * *** * ** * ****** * * *** ** * *** ** * 0;
**** ** * ** * ** *** * *** * *** %d",strlen(a),strlen(b));
**** * *** * * ** ******** *** ****
* ** ***** ** *** ** ** * *** *** ** ** ***** ** ** * * *
** * * * ** **** ******* * ** * *** ******* * * * *** *** * * * *** * * ** ***** *** * * is not a prefix of %s",a,b);
* * * ** ** * * * ****** ** * * ** * * * ** *** * * *** * * * * * * ** * * * ** *
**** ** ** **** * * * *** * * ** * * * ** * * ** ** * * *** *****
**** ** *** * * *** **** * * * * * * ** ****** ** * * ** ** * * if(c==strlen(a)-1)
*** ** *** * ** ** ** * * ******* * * * * ** ** * * * * ** * * * * * ***** *** *** * ** is a prefix of %s",a,b);
    }
** * **** ** ** * 0;
}
answered by (-498 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <string.h>
int main()
{
** ** **** **** ** * ** * n,count;
* * * **** * *** * * *
** * *** ** * **** * * * * * %s",a,b);
***** **** ***** *** * *** ** **

* * * * *** **** * ****** * **** ***
* ** ** * *
* * * * * ** *** ** *** ** ** *** *** ** * * * **
** **** ** **** * * * ** *

** **** * * *** * * (strcmp(a,c)==0)
* ** * *** * ** *** ** *
* ***** * *** ** * *** * ******* * * ** ** **** * * is a prefix of %s",a,b);
* *** ** * **** * * *
* **** ** ***** **** ***
*** ***** ** **** ** ** * *
** * * * * ***** ** * *** *** * ** ***** *** *** * * ** * is not a prefix of %s",a,b);
* *** ***** * ** *
** ** * ** * ** *** * 0;
}
answered by (-284 points)
edited by
0 0
prog.c: In function 'main':
prog.c:8:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s %s",&prefix,&word);
             ^
prog.c:8:16: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
     scanf("%s %s",&prefix,&word);
                ^
prog.c:10:15: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     for(i=0;i<strlen(prefix);++i)
               ^~~~~~
prog.c:10:15: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:10:15: note: include '<string.h>' or provide a declaration of 'strlen'
prog.c:18:6: error: expected '(' before 'printf'
      printf("%s is a prefix of %s",prefix,word);
      ^~~~~~
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
#include<string.h>
int main()
{
* ** ** * * * * * a[100],b[100];
** *** * *** ** ****** *** * * * ***
    int l1,l2;
*** * ** ** ** *** ** * * ****
* * ** *** * ** ******
** ** * * * *** * ** ***
* * * ** * ** ** *** ** * * * *** **** ** *** * ** ** ** * is not a prefix of %s",a,b);

    }
* * *** *** * * * * ** if(l1<=l2){
******* ** ** * * * ** **** ** * * * ** prefix=1;
** * **** * *** ** ** * * * * * * i=0;
* * * ** * ** * ****** * * ** ** *** **** *** * * ******
* ** * * *** * * * * * * * * ********* ** **** * * * (a[i]!=b[i]){
* * * ** * ******* * ** * *** * * * * ** * * *** * ** * *** *** *** * ******* * *** *** ** *** *
* ** *** ** ** ** ** * ** * * *** *** * ** **** * * * * * ** * ** * *** ** ** ** *
**** ****** * **** * * * ** ** * * * **** * ** * * * *** **** **


** * ** *** * * * * * * *****
***** ** * ** ** *** * * * * ******** * **
* * *** ** ** *** * ** **** *** * ** ** * * ** **** * ** ** ** * * * is not a prefix of %s",a,b);
* * * ** ** ** ** * ** *** ** *** ** *
* * ** * *** * * ** **** * * **** * ****
* *** * * *** * * ** * * * ** * * ** * is a prefix of %s",a,b);


    }


}
answered by (-329 points)
0 0
prog.c: In function 'main':
prog.c:5:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
             ^
prog.c:5:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
               ^
prog.c:7:8: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     l1=strlen(a);
        ^~~~~~
prog.c:7:8: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:7:8: note: include '<string.h>' or provide a declaration of 'strlen'
0 0
prog.c: In function 'main':
prog.c:6:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
             ^
prog.c:6:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
               ^
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
** * * * * *
int main(void)
{

* *** ** * ***** * * * * pre[100];
** ** * ** ** * word[100];
** ** ** * * ** * * ** * ** *** * %s",pre,word);
* * ** ***** * * * *** * * **
** * * * **** ****** * * ** * ** ****

** ********* ***** ** i;
****** ** ** *** *** ** * * ** **
** ** * *** * **** *** * *
** * ** **** ** * ** * ** * *** ** * **** *
** * * **** * * * * * * ** *** * *
* *** ** * * *** ** * ** * *** ** * * *** *** * ******* * * ** * is not a prefix of %s",pre,word);
* *** * * ** *** ***** *** * ** * * *** ** *** ** ******* * * ** **** * 0;
* ** * ****** * * ** **** *** * ** * **

**** * ***** * *
printf("%s is a prefix of %s",pre,word);
return 0;
}
answered by (-249 points)
0 0
prog.c: In function 'main':
prog.c:8:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&pre);
             ^
prog.c:9:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&word);
             ^
0 0
prog.c: In function 'main':
prog.c:8:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&pre);
             ^
prog.c:9:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&word);
             ^
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <string.h>
#include <ctype.h>
int main ()
{
** ** *** * * * * * pre [100],a[100];
* ** * * * * * ** * * n ,i;
** *** ** * ** **** ** ** * * *** *
** * ** * * **** ****
* *** * * ****** *** *** * * * * * ** * * ** ***
* * ** ***** ** *
* ** * * * ** **** * ** * *** ** * * * (n=0;n<strlen(pre);n++)
** * * ** ** * * * * * * ****** * * *
* * ** ***** * * ** * * * * * * * * *** * * * * * * *** ***** * (pre[n]==a[n])
******* * * *** * ******* ** * * ******* *** *** ** * * **** *** * **** * ** * * *** * is a prefix of %s",pre,a);
** *** * **** *** *** ** * * ******** * * * * ** * **** **** ****
* ** * **** * * * * * * * * * ** * ** ** * ** * ** * ** ** **** * ** * * ** * * is not a prefix of %s",pre,a);return 0;
***** ********* * ** * *
** * * * * ** * * * ** *** * ** * * **** * * * ** * * * *****

** **** ** * *** ** ** * 0;
}
answered by (-32 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include ***** ** * *
#include ** ** * * *

int main()
{
** **** * * * ***** a[100];

* * *** ** **** * * b[100];

** * ** * ** * * ** * %s", a, b);

***** * ** ** ** * * * ** len_a = strlen(a);

** * ** ***** * i = 0;

* ** *** * * **** flag = 1;

**** ** * ********* = 0; i < len_a; i++)
* ** * * * * ****
* * * * * * * * *** ****** * * ****** ** ** * != b[i])
* * **** * * ** ** ** * *** ** * ** * * *
** ** * * ** *** * *** * ** ** ****** * * ** ** * * *** **** *** * = 0;
* * *** * ** *** **** * * * ** ** ** ** * *** **
* ** * ****** *** ***

* * * * *** ** ** *** ** * * == 0)
** **** * * *** *
**** * * ** * ***** ** *** *** * * * * *** * * ** is not a prefix of %s", a, b);
* **** * **** * * ** ***** ***
* ** ***** *****
****** * * * * ***
* ** * ** * **** * * ** *** * * * *** * ** *** ****** ***** is a prefix of %s", a, b);
***** ** ** ** * *** *
* * * *** *** ** * *** ** **** 0;
}
answered by (-285 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
* * * *** *** * **
int main()
{
** * * * *** ***** * i,n;
**** **** * * *** *** p[100],s[100],a[100]={};
* * *** * *** * * * ** * ** %s",p,s);
*** * * ** * ** * * ** ** *
***** * * * **** *** * *
** *** **** **** **** * ** * * ******* *
* ********** **** * * ******** *
***** * ** ** ** * ** * * * ** ** * *** *** * * is a prefix of %s",p,s);
* ** * *** *** ** *
** ******* * * * ** * * *
** **** * ** * * * * * ** * * * ** * * * * ** is not a prefix of %s",p,s);
** **** * ****** **
**** ******** ** ** * * * **** ** ***** * ***
* * ** * * * * * * 0;
}
answered by (54 points)
edited by
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
#include<string.h>

int main()
{
    int i;
    char a[100];
    char b[100];
** ** * * **** *** * * ** ***** *
    scanf("%s",b);
    for(i=0;i<strlen(a);i++)
* * ****** * ** *** * * * * ****** *** *** * ** * **
* *** **** * * * * ** * * * * * *** * ** *** * * ** * * * *** ** != b[i])
* * * ** * * * ** *** ** ** ** ** * * ** * ** ** * * * **** *** * ** ** * * * * * ** * * *
** * ** * * ** * * *** **** **** * ** *** * ***** ** ** *********** ** * * ** * *** **** * * * * *** * ** * * * is not a prefix of %s",a,b);
* *** * ** ** ** ** * * ** ** ** ** * ** * *** * * ** *** * * ** ** * ** * * ** * ***** ** *** ** *** * * *
** **** **** * * ** ** ****** * *** ****** * ***** * ** * * * ** ** ** *** * ***** *
**** *** *** * ** **** ** ****** * ** * ** * ** * * * *** * ** ** ** ** * == b[strlen(a)-1])
* * ** * ** * * * ** ** * * **** * ** ** * * * * ** * *** *** * *** * ** ***
*** ***** ** ** * * ** *** * ** * ** * ** ** *** **** ** * *** *** * ** ** ** * *** ***** *** * ** * * ** *** * * * * ** * is a prefix of %s",a,b);
* ** * * ** ****** * ** * *** ** * * *** **** ***** **** *** * * ** ** ***** * * ** *** ** * ** * * * * * **
* ** *** * *** **** * ******** * * * *** * ** * ** *** * *** * * * ** ** ***
*** * ** * * *** ***** * ** * *** ****
}
answered by (-301 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
#include<stdlib.h>
#include<string.h>
#define n 100

int aa(char a[],char b[]){
* ** * **** * ** ** *** i;
* ** ** * * ** * **** ***** (a[0]!=b[0]){
****** * * * ** **** *** *** *** ** *** * * 0;
***** * * ** ** ******* * *
* ** * ** * * ** ** * * * * * * *
** *** * * * **** **** * * *** * * * **** ** a[i]==b[i])
**** * * *** ** ** ****** ** * **
***** ** ** * * **** * * * * * ** * ** *** * * ****** * ** **** * * ** ** * 1;
* ** ******* * **** * * *** * ** *** *** * * * * ** * * * *
*** ** * * ** * * * *** ***** ***** * ** *
* ******* * * ** * *
* *** ** ** ** * * * ****** * ** 0;

}

int main(){
* * ** * * **** * c[n],d[n],e[n];
* *** *** ** * * * ** * i;
* **** * * * *** ** * ** %s",c,d);

**** * * ***** ** * ** ** *
*** ** * * *** * ** * * * ** ** * ** ** ** * ** * is a prefix of %s",c,d);

** ** ***** * * * * * *
* ** ** * * * *** *** *** ** ** * * **** is not a prefix of %s",c,d);


}
answered by (-32 points)
edited by
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.130.71
©2016-2025

Related questions

1 like 0 dislike
37 answers
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42302 - Available when: 2018-01-17 14:00 - Due to: Unlimited
| 10.7k views
2 like 0 dislike
31 answers
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42301 - Available when: 2018-01-17 14:00 - Due to: Unlimited
| 9.3k views
1 like 0 dislike
32 answers
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42300 - Available when: 2018-01-17 14:00 - Due to: Unlimited
| 10.7k views
2 like 0 dislike
30 answers
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42298 - Available when: 2018-01-17 14:00 - Due to: Unlimited
| 8.3k views
0 like 0 dislike
4 answers
[Exam] asked Jan 19, 2018 in Final Exam
ID: 43460 - Available when: 2018-01-20 09:00 - Due to: Unlimited
| 2k views
12,783 questions
183,442 answers
172,219 comments
4,824 users