Final Exam 2 (20%)

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A string p is a prefix of a string s if the leading characters of s are identical to p. For example, "abc" is a prefix of "abcde". Develop a function prefix that checks if a C string p is a prefix of another C string s.

p是s的前綴若s開頭的一段字串等於p。例如，"abc"是"abcde"的前綴。寫一個程式 判斷字串p是否字串s的前綴。

Example input 1:

abc
abcde

Example output 1:

abc is a prefix of abcde

 

Example input 2:

bc
abcde

Example output 2:

bc is not a prefix of abcde

 

[Exam] asked in Final Exam
ID: 42299 - Available when: 2018-01-17 14:00 - Due to: Unlimited
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Hidden content!
#include * * *  * *  **
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int prefix(char a[], char b[]){
int i, j,n;
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}
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Hidden content!
#include <stdio.h>
#include <string.h>

int main(){
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}
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Hidden content!
#include <stdio.h>
#include <string.h>
int main()
{
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}
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prog.c: In function 'main':
prog.c:8:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s %s",&prefix,&word);
             ^
prog.c:8:16: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
     scanf("%s %s",&prefix,&word);
                ^
prog.c:10:15: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     for(i=0;i<strlen(prefix);++i)
               ^~~~~~
prog.c:10:15: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:10:15: note: include '<string.h>' or provide a declaration of 'strlen'
prog.c:18:6: error: expected '(' before 'printf'
      printf("%s is a prefix of %s",prefix,word);
      ^~~~~~
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Hidden content!
#include<stdio.h>
#include<string.h>
int main()
{
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    }


}
answered by (-329 points)
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prog.c: In function 'main':
prog.c:5:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
             ^
prog.c:5:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
               ^
prog.c:7:8: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     l1=strlen(a);
        ^~~~~~
prog.c:7:8: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:7:8: note: include '<string.h>' or provide a declaration of 'strlen'
commented by (4.3k points)
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prog.c: In function 'main':
prog.c:6:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
             ^
prog.c:6:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
               ^
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Hidden content!
#include<stdio.h>
*       ** ** **  *****
int main(void)
{

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printf("%s is a prefix of %s",pre,word);
return 0;
}
answered by (-249 points)
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prog.c: In function 'main':
prog.c:8:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&pre);
             ^
prog.c:9:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&word);
             ^
commented by (4.3k points)
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prog.c: In function 'main':
prog.c:8:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&pre);
             ^
prog.c:9:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&word);
             ^
commented by (4.3k points)
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Hidden content!
#include <stdio.h>
#include <string.h>
#include <ctype.h>
int main ()
{
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}
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Hidden content!
#include <stdio.h>
#include   *  ** *  * *   *
#include   *** *    

int main()
{
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***   ** *** ** * ****  ** 
*** ********** * * *  * ** 0;
}
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Hidden content!
#include<stdio.h>
** *  * *  *** * **
int main()
{
*    * *   *  * ** *  *** *****  i,n;
     * *   **** * *    *** *  p[100],s[100],a[100]={};
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*    **  **  *  ** ***   * *  
     * ****    * *  * ** ****** **  * *  *  *** * *** 
* * * ***    * * * **   *     ** 0;
}
answered by (54 points)
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Hidden content!
#include<stdio.h>
#include<string.h>

int main()
{
    int i;
    char a[100];
    char b[100];
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    for(i=0;i<strlen(a);i++)
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 **  *  * * * *   *** *** **** **** ***  * ****   * ******* ***    *  *** * * * ** *  *** * *** *   **   *  * *    *   *  **  *  *  * *** *   ** 
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 * * *   ** * *** * ****  *  * *  *** *    *    ***  *  
}
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Hidden content!
#include<stdio.h>
#include<stdlib.h>
#include<string.h>
#define n 100

int aa(char a[],char b[]){
*** ******       * *  *  * **** *** i;
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***  ** *   **** ****** ****  ** **   *** * **   *  0;
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****  ****  * * * **** * **   ***  * ***   ** *  * * *  *  *****   ***  *   ***** ****          ** 1;
****   **    *  ** *  *  ****  **    *  * *  ***   ** *  ***  * ***  *  *** *
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      *   * *    *     *  **
 ****** ** * ******   *** * ********* *   0;

}

int main(){
* ***     *  *** * * ****   *  c[n],d[n],e[n];
* ***   *  * **   *** ** *******  i;
  **   **** *   ****  **   ** *     %s",c,d);

*** *  *    ***     *** *   *  * *
*   * **  * **   ***   ** * ** ***  * *      ****     ** *   *  is a prefix of %s",c,d);

** **  * **  **  ** **** *** 
* ** ***   * * *   ** **  *      *** *** *  ** *     ***   * *      is not a prefix of %s",c,d);


}
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