Final Exam 2 (20%)

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A string p is a prefix of a string s if the leading characters of s are identical to p. For example, "abc" is a prefix of "abcde". Develop a function prefix that checks if a C string p is a prefix of another C string s.

p是s的前綴若s開頭的一段字串等於p。例如，"abc"是"abcde"的前綴。寫一個程式 判斷字串p是否字串s的前綴。

Example input 1:

abc
abcde

Example output 1:

abc is a prefix of abcde

 

Example input 2:

bc
abcde

Example output 2:

bc is not a prefix of abcde

 

[Exam] asked in Final Exam
ID: 42299 - Available when: 2018-01-17 14:00 - Due to: Unlimited
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Hidden content!
#include * * *** ** **** 
#include *** * * *   *
*** *** *    *    **  *
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int prefix(char a[], char b[]){
int i, j,n;
int cnt=0;

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}
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Hidden content!
#include <stdio.h>
#include <string.h>

int main(){
* ******** * * * ** * * **  **** c;
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    }
* * **     * *   ***  ** **   *  0;
}
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Hidden content!
#include <stdio.h>
#include <string.h>
int main()
{
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}
answered by (-284 points)
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prog.c: In function 'main':
prog.c:8:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s %s",&prefix,&word);
             ^
prog.c:8:16: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
     scanf("%s %s",&prefix,&word);
                ^
prog.c:10:15: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     for(i=0;i<strlen(prefix);++i)
               ^~~~~~
prog.c:10:15: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:10:15: note: include '<string.h>' or provide a declaration of 'strlen'
prog.c:18:6: error: expected '(' before 'printf'
      printf("%s is a prefix of %s",prefix,word);
      ^~~~~~
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Hidden content!
#include<stdio.h>
#include<string.h>
int main()
{
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    }


}
answered by (-329 points)
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prog.c: In function 'main':
prog.c:5:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
             ^
prog.c:5:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
               ^
prog.c:7:8: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     l1=strlen(a);
        ^~~~~~
prog.c:7:8: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:7:8: note: include '<string.h>' or provide a declaration of 'strlen'
commented by (4.3k points)
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prog.c: In function 'main':
prog.c:6:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
             ^
prog.c:6:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
               ^
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Hidden content!
#include<stdio.h>
*     ***** *  *
int main(void)
{

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printf("%s is a prefix of %s",pre,word);
return 0;
}
answered by (-249 points)
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prog.c: In function 'main':
prog.c:8:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&pre);
             ^
prog.c:9:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&word);
             ^
commented by (4.3k points)
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prog.c: In function 'main':
prog.c:8:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&pre);
             ^
prog.c:9:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&word);
             ^
commented by (4.3k points)
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Hidden content!
#include <stdio.h>
#include <string.h>
#include <ctype.h>
int main ()
{
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}
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Hidden content!
#include <stdio.h>
#include   *  ** *** * * 
#include      *** *****  

int main()
{
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  **  *  ****** **   * * * 
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  ****  ** * **  *    *** ** 
   * *** **  ***  * * ** *** 0;
}
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Hidden content!
#include<stdio.h>
****      * **** *  ** * * 
int main()
{
  * * ** *** * *    * *    ** i,n;
 *** *  * *****  * * * **** **    p[100],s[100],a[100]={};
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   * **   *   * *   * *** **      ** *** *    *   * ***   **  *
***    *** * * **** ******* **    0;
}
answered by (54 points)
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Hidden content!
#include<stdio.h>
#include<string.h>

int main()
{
    int i;
    char a[100];
    char b[100];
*    **** **  ** ***  *        *   ** ***      *    *    
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* * **  **** ********   *** * * ** **  ** * * *  ****  ****** * * * ** * **   **    ******  * ***
**  * * * *** *  **     *    *  *  ***    ** *       
}
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Hidden content!
#include<stdio.h>
#include<stdlib.h>
#include<string.h>
#define n 100

int aa(char a[],char b[]){
 **   *   * *   ** ***    * **  *  i;
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     *   ****** **** ** *    
* * ** * **  ****   * **  ***  * *  * * 0;

}

int main(){
*   **** * **      *  * ** *   c[n],d[n],e[n];
**   * * **  **     ** * ** *   i;
*** * * * **  ***** ***   * *  %s",c,d);

 *  ** **** ** * *  **    * ** ***  
*** ** ** **  *    *  *    ****   ***   ***     **   *  *  * ***** is a prefix of %s",c,d);

*   **** *  **  * ** **  *  **  **
   ******* *****    *   ****   **   * ** *       *** * * ** *    ** * *  is not a prefix of %s",c,d);


}
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