Final Exam 2 (20%)

1 like 0 dislike
6.8k views

A string p is a prefix of a string s if the leading characters of s are identical to p. For example, "abc" is a prefix of "abcde". Develop a function prefix that checks if a C string p is a prefix of another C string s.

p是s的前綴若s開頭的一段字串等於p。例如，"abc"是"abcde"的前綴。寫一個程式 判斷字串p是否字串s的前綴。

Example input 1:

abc
abcde

Example output 1:

abc is a prefix of abcde

 

Example input 2:

bc
abcde

Example output 2:

bc is not a prefix of abcde

 

[Exam] asked in Final Exam
ID: 42299 - Available when: 2018-01-17 14:00 - Due to: Unlimited
retagged by | 6.8k views

37 Answers

0 like 0 dislike 
Hidden content!
#include    *  ** *    ***
#include   ********* **     *
** **  *  *   *  ** 
***   * * **  ** *  **  

int prefix(char a[], char b[]){
int i, j,n;
int cnt=0;

n=  ****** ***  *

 **  *      ***     **    * * * **** 
**    **   *   *  *  *** ** ***     == b[i]){
  *  **   ** **  *   *  **  *   * * *    *** *** 
  *  *   * **** *  ***    **** 

     * **  *** * *   
if (cnt == n){
  ** ***  *  **** **  ***   *     ** **** *  *  *  * * *  *** 1;
  *   ***  *     *  **     * *  **** * **** *  * ***
***  *** *** ** * ***  *** *** 
  ********* **  *  **   * *  *** *  ** * ***** *   * 0;

}

int main()
{
  ** **     * *  **   *   s1[100], s2[100];
**   **     * *******  i,j;

  *    ** **    ** * **   **  *  *****     *  s1);
  *  *  **  *  *   ** *  **    ***  ** s2);
   * *  **** ** *    (prefix(s1, s2)){

*  **  ***** *  *  * * *** ***** ****   ** * *  **  **  * is a prefix of %s", s1,s2);
        ***  ***   ****  * * ***** *  * * **   *
 * *******  * *    *** *  * ** * **      *    **
   * * * * ***  *  * *********  **** * ** *** *** *   *       *** is not a prefix of %s", s1,s2);



}
answered by (323 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <string.h>

int main(){
*  ** **** ** *     *  * **  c;
***** ***   *   ***   * * * a[100],b[100];
*  ***   * ***   * * ** **   **  * * * * %s",a,b);
   *  ****  * ****** **     *** ***   
***** *  * *   *  **    **** *  *    ** ***  *  *  *** *** 0;
  * *  ** *     *    ***** *  * **** %d",strlen(a),strlen(b));
**  **    *  **** *  ** *    *  *****       * 
*     *   **  *       ***    * **    ***   *   * * *  **   *  *   * ** *  *   **  *   ** 
 * **     ***** **   * **** ** *****  * **** **  * * ** *  * * ****  *  * *   *******       *  * *  **** * **   *   *** is not a prefix of %s",a,b);
 **   *     ** * ** **       * ****  *   **        **   ** * * *   ****** * **   *    **    ** * ***  *  *    ***** 
*** * *** *  *      ****** * * * **** ****  ** *     *  ** ** * *          * ** *** 
**** * ***      *** **     * ** * ***  *  **  ***  **  ** ****  * **  * * ** * * *** * if(c==strlen(a)-1)
  * *  **** * **     ********  ***  *  * *** *    ******* ***   **  *           *  ** **    * **  ****** *  ***  ** *  is a prefix of %s",a,b);
    }
**    **** ** * * * * **  ***       0;
}
answered by (-498 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <string.h>
int main()
{
   *  **   ****      *  **** *  n,count;
* *     ****  *   ****   * **  ** ******* ***   * * *
* * **   *   ****     ****  ** * ** *   %s",a,b);
      *       **  **   **  * *** *

   **   ** * * ***** *  *  *****   **    * ***
  **  * ** ******  **  * 
 **** *    *  **** ******   * *** ***** *** *  *    *   *   ***
   *** ***  *   * *  *******  *

*    **  * * * **  *** *   ** * (strcmp(a,c)==0)
  *   * * ** * ****** **  
 **   *** *  *   ** ***  *   ***  ** **** **** **  **  * *  * *  * is a prefix of %s",a,b);
**  ****   *** ** * *     
*   ** * * **    ** ******** * *
* *** *******   * *  *** ** *  **
 * **** ****       **** * * ***  **    ****   ****    ****  ** is not a prefix of %s",a,b);
 *  ****    **  * *  **       **  
 * **   * *** ** *** *  ***  * * *   0;
}
answered by (-284 points)
edited by
0 0
prog.c: In function 'main':
prog.c:8:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s %s",&prefix,&word);
             ^
prog.c:8:16: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
     scanf("%s %s",&prefix,&word);
                ^
prog.c:10:15: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     for(i=0;i<strlen(prefix);++i)
               ^~~~~~
prog.c:10:15: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:10:15: note: include '<string.h>' or provide a declaration of 'strlen'
prog.c:18:6: error: expected '(' before 'printf'
      printf("%s is a prefix of %s",prefix,word);
      ^~~~~~
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>
int main()
{
   ** * ** * *** *  ***  ** **  a[100],b[100];
* ****  * **   *******    *  * * * *  ***     **
    int l1,l2;
  *** *** *  *  *   ** *             * 
* ***** * **   **   * *   **  *****
***  ***** ** ** **   **    *
 ***   ** *  ** ** *    ** * *    *     ** *  *   ** ***** * *** *  is not a prefix of %s",a,b);

    }
 ***   *       * * *    **    ** if(l1<=l2){
 **   **  ***  *****  *  *** *  *  ***    * * *  *   prefix=1;
 ***  * *** *****      *  * * ** * *  ** **  **  *****   * * i=0;
*** ***   ***  ** * * * *****  *    **   *** ******** **  * ** **
*    *  ***** ** ******** *********   **** **    *  * ****** *   **    *          (a[i]!=b[i]){
* **** * ***  ****   * ** * **     ** * ** ** * **** *    * * ** *   ** *   *  ** *  ** * * * *   *****
**** **  * ***     ***  * * ***    ** * * **   **   **      *  **   **  *****   **     *  * ***  *   *   *** *  *  * **
* * *   **    ***   ** * *    * *  **   *    *  * **  * **** **  ** * **  * * ***


*     ***  *    **  ** *     * ***    * * **** ***  * *
   *** ** *   * *   * * * * *  *   ** * ***   ** * *  * **  ** 
  * ***       **  *  *** ****       * **    **   *  ** * **    * * * ** *  * **       *** **  is not a prefix of %s",a,b);
 *  * **** *  ****  **** ****  ** *  ** * ** ***  ** ** 
* ** **  ****     **  *   ***  *  ****   **** *   *   ** 
 ** *** **** **    *     * *******   *    **  *  *  *** * *    is a prefix of %s",a,b);


    }


}
answered by (-329 points)
0 0
prog.c: In function 'main':
prog.c:5:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
             ^
prog.c:5:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
               ^
prog.c:7:8: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     l1=strlen(a);
        ^~~~~~
prog.c:7:8: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:7:8: note: include '<string.h>' or provide a declaration of 'strlen'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:6:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
             ^
prog.c:6:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
               ^
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
  *** **   *  ** *   *
int main(void)
{

* *   ** *   * *     *** *** * pre[100];
   *** *          *  * * ***  * word[100];
*  *   *    **  *  ** **     * *    %s",pre,word);
*  ** * ****  * *  ** * * ** *  *       * 
  ** ** *    ***    **   *    *  ***

******  *   * * ***     *  i;
  * **    * **  *   *  ** * *   * * ***    ***      
* *   *  * *  **        
*  * **    ** **       ****   ** *  **  ** * ** **       **** * *
     *** ** * * *  ** *** ** ***  **  * *
  *  **** **  *****    ****      ** *  *  **  ** *  ***  ******   ***    *  *  *** *   *  **  *   is not a prefix of %s",pre,word);
   *    * * ****** *** * ***   * * *  ** ********   *       *  ****  * * ** *  * * *  ** 0;
* **** * *  *  *** * ***      * *  * * *  *** ****   * **

*   * ** *** ****  *** * * *
printf("%s is a prefix of %s",pre,word);
return 0;
}
answered by (-249 points)
0 0
prog.c: In function 'main':
prog.c:8:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&pre);
             ^
prog.c:9:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&word);
             ^
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&pre);
             ^
prog.c:9:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&word);
             ^
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <string.h>
#include <ctype.h>
int main ()
{
*** **  * *     *  **** pre [100],a[100];
 ****  **  **  ***   **  **  n ,i;
 ** * *  *** * ** *** *  * **  * ***  *   
    *  ***** * *  * *******  ***    
    *  * * *  * * ***** *     *  **    * * *  **  
     ** * * *    * **** 
***   ****** *     ** * **** * ***      **     *** * **   (n=0;n<strlen(pre);n++)
 **** ***    ** **    ***  * *   *  * ***  ****   *** ****
*     * ** *  *   ****     *       **  * ** *  * *   * **   *****  **  *****   *  * (pre[n]==a[n])
**** *  *   * * *** *  ** ***  *  * *  * ** * * **** * *  *    **** **   * *    *   *  * * * is a prefix of %s",pre,a);
**     *     **** *******  * * **   *   * **       ** **  **   *** *  * * * **   *   **
    **  ** *****   * ***    *** *   *  *** * **   ** ***   *  *** *  ** ** * ** **   *  ** *** *  ***    ****   is not a prefix of %s",pre,a);return 0;
 **  ****   *    * *   * 
    * **    * ****** * **  *    * **      *  **** ** * *** **** * * * *   **

   * *   * **     **** *** *** 0;
}
answered by (-32 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include * * **** **   **   
#include * * ** *  ** *** *

int main()
{
  ****          *** *  *  a[100];

  * ****    *    ****  *  ** b[100];

*   ***  ** *     ** * * ** ***    *  %s", a, b);

 * * ****   ** ** ** * ***    *  len_a = strlen(a);

   * **** **** ******* * * * i = 0;

   *  *  ****   *  *** *   flag = 1;

**      **      *** * ** * * = 0; i < len_a; i++)
    * * * *   *     ** **  * * 
*  *  *** * **  * ***  *   ** ** *     *  * * ** * * != b[i])
 ** * * *  *       *** *  *  *** * * ******** * ****  ******
* *   * ***** **** ***  ** *   **   **   ** *  *   ** * * *  **   **    *** **  *      = 0;
***** *    **    *    *  ** * ** **   **  * ***    * *   *** *
* **** *      ** **** ****

*  **  *    **** * *   * * ** *****   == 0)
*  *     **    *  *   * * *****
*   * * **   ** **   ***    *   *    * * * *    **  ** ** ***** *** **   *  is not a prefix of %s", a, b);
** ** **   * *****  * **
**** ** * *   ******  *  *
    * **** **   * * *** ** * 
  ******  ***  *   *    ***  * *  *** ***     ** * * *  **  *** is a prefix of %s", a, b);
 ** * *** *  ** *  **** * * ****
****    ***  * *    * *  *** 0;
}
answered by (-285 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
  **  **   * ** * *
int main()
{
** *** **    *    * ** ** ** * ***** i,n;
**** *       *  **  * * * *  ** p[100],s[100],a[100]={};
 ****    ******    * ***  ***** ** **  %s",p,s);
  * *****  **  *   *** ***       
*  * * * ***  ** *  ****   ***     
   ** * ****   ** *      * **** *  *  *******  **
 *   *  * **  **  *  *      * *** 
   ****  *** * ***  ******* * *   ** ** *  *     * *** *** *    **  **** is a prefix of %s",p,s);
**  ** ******* *  ***  * * 
*  * *****    *      *** * *
 ** ***   **         ** * *** **   *    ** *      * * * *** **   *** * is not a prefix of %s",p,s);
 * ***   * ****    * **
 *** ******  * ** *  *    **  ***   **   * * * **  *******  ** * *
****  **** **   ****  ** **** * *   0;
}
answered by (54 points)
edited by
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>

int main()
{
    int i;
    char a[100];
    char b[100];
 *  * *** * ** * **  *  *** **** ** *   *  ***  * ***
    scanf("%s",b);
    for(i=0;i<strlen(a);i++)
     * *  *  * ******  * *****  *     ** * *  *   *  
 **   *   **      **  * *   * * * *   * *  *  *  ** ** * **   * ** **   ** *  **  * **** *  **   != b[i])
**  * *    *  ***   **  **   * *** ***    *  ** **** *  **   *  *** *** ***    *    * ** **  **** ***  
   * ** * *     ** * *  *****  ** * *** * * * * **** *****  ** * ***       **  *      *    ***  *******  * **     *    *    *  ****  * * ** *   * *     is not a prefix of %s",a,b);
 *   *  *   * * * *  **  * * **  ** *  ****** **  * ****  ** * **       *     *    ***    *   *     **** *   * *   * * *****
 * ***   * **   *       *  * *    *** **   * ***** ** ** **  ****     *   *      * **  *   *   *  **  *
  * *   *  *   ** *** ********   * * ****** *   ** * ********    **  *  *  ** ** ***     *  *   == b[strlen(a)-1])
   *  *** * *  *       * *   ***   *    **     *   *  ****  ** **  *** *  *****   *** * * ** *  * **    * * *    
           ** * * **     *   * *  **   ** * *****    *** * ****  *** ***** **** *    * *  ** ** ** *** * **  ***  ****   **  *  * * ***** * * ***** is a prefix of %s",a,b);
*  * * ******* * ***  *** *   *** * ***     *  *  * * ** ***  *** * *** * *  *       *    ******    * * * *  * *****   ***  **    **  
  *  * *** * ***  ****  ***  **** * * *  * **  **** ***  ***** * ***  ***  * * *  ** ** * *****  *** *   *** **   *   **
**  *** *  * * *** *   * **  ****  * *    ***  *  **  **
}
answered by (-301 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<stdlib.h>
#include<string.h>
#define n 100

int aa(char a[],char b[]){
* ** ** * **  * *     **     ***   ** * i;
  **  *   **  * * ***  *** * *  *** (a[0]!=b[0]){
  ** **** *    **   ** * *  *  *  ** ***    * *  *  *****   * 0;
   ***   **  *  *   * *   *******  
  *      * *   * *   * ** *** ***   *** ******  
*****  ***  ***  *  * * ** *     *  *   **** * ***** *  *  ***     a[i]==b[i])
*** *  * * *  * *   *** ****  **   * ** * ** *    * 
****  * *    *   * ** *   ***        * ***  *  **     * **** * **** ** ** **   ****   1;
*    *   **    ** ** ***  * **  **    *   * *  *  * *** *   *     * *   **   *** *
****** * *  *  *  *     **   ***  * *   * ** **    **
* *  *  ** **   * ***    ****  *   
 ****  **** *  *** ** ** ** *** *** *  0;

}

int main(){
  ** ** **  * * ***  *** * c[n],d[n],e[n];
  ***   *   *****  * ***   * i;
  ***     *    ** *** ** * **  * ****    %s",c,d);

   **          * *** ** **   ****  * 
*****  **  *** **** * * *****   ****  ***     ** *   *******  *** *** is a prefix of %s",c,d);

******  *****   **   ** ** **
 ** * * ** ******* ** *  * **    * *       * **  ***  *  *    * * is not a prefix of %s",c,d);


}
answered by (-32 points)
edited by
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.126.168
©2016-2025

Related questions

1 like 0 dislike
37 answers
Final Exam 5 (20%)
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42302 - Available when: 2018-01-17 14:00 - Due to: Unlimited | 7.1k views
2 like 0 dislike
31 answers
Final Exam 4 (20%)
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42301 - Available when: 2018-01-17 14:00 - Due to: Unlimited | 6.1k views
1 like 0 dislike
32 answers
Final Exam 3 (20%)
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42300 - Available when: 2018-01-17 14:00 - Due to: Unlimited | 7k views
2 like 0 dislike
30 answers
Final Exam 1 (20%)
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42298 - Available when: 2018-01-17 14:00 - Due to: Unlimited | 5.3k views
0 like 0 dislike
4 answers
[Makeup] Final Exam 2 (20%)
[Exam] asked Jan 19, 2018 in Final Exam
ID: 43460 - Available when: 2018-01-20 09:00 - Due to: Unlimited | 1.3k views
12,783 questions
183,442 answers
172,219 comments
4,824 users