1 like 0 dislike
10.7k views

A string p is a prefix of a string s if the leading characters of s are identical to p. For example, "abc" is a prefix of "abcde". Develop a function prefix that checks if a C string p is a prefix of another C string s.

p是s的前綴若s開頭的一段字串等於p。例如,"abc"是"abcde"的前綴。寫一個程式 判斷字串p是否字串s的前綴。

Example input 1:

abc
abcde

Example output 1:

abc is a prefix of abcde

 

Example input 2:

bc
abcde

Example output 2:

bc is not a prefix of abcde

 

[Exam] asked in Final Exam
ID: 42299 - Available when: 2018-01-17 14:00 - Due to: Unlimited

retagged by | 10.7k views

37 Answers

0 like 0 dislike
Hidden content!
#include ** * *** *
#include *** **** * * *
********** * *** *
* *** ***** *

int prefix(char a[], char b[]){
int i, j,n;
int cnt=0;

n= * ***

*** ** * * * * ** ** *
* ***** ** ** * * ** == b[i]){
** * * ** * * * * ** * ** ** * * * ** * *** *
***** * ** *** ** ** * **

*** * ****** * *
if (cnt == n){
** * ** ** *** * ***** * * * ***** * ** * * * * * * * 1;
** ** ** ** *** * ** ** * ***** * * ***
** ** ** **** ** * *
* *** * ** *** ** * **** ** ** * *** * *** ** ** 0;

}

int main()
{
* * * s1[100], s2[100];
* *** ** * * *** * i,j;

*** * * * **** ** * *** ** * **** s1);
* ** * * **** * * * * * * * * *** s2);
** ** * * (prefix(s1, s2)){

** *** * ** * * * * * * ** ** * * * * ** ** *** is a prefix of %s", s1,s2);
***** * * ** ** ** ** ** ** **** ** **
** ** * ** * ****** ** ** ** **
**** ** * * * * * ** * **** *** ** * * * * * *** * * * ** * is not a prefix of %s", s1,s2);



}
answered by (323 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <string.h>

int main(){
** * * ** * * ***** c;
* *** *** ** ** **** a[100],b[100];
* ** **** * * * * * ** ** %s",a,b);
** ** * * * ** * ** ** *** ** * * ** * *
** * *** * ** ** * * *** *** *** ** * * 0;
***** * ** ** ** *** * ** * * * %d",strlen(a),strlen(b));
* * * **** ** * ** ** * * * ** * * *
** * *** *** * * **** * *** ** * * * * * * * * * ** *** * **** ** **
** ***** **** * * * * * * **** * * * * *** ** **** * * * * ** ** * * * * * * * * * ** **** is not a prefix of %s",a,b);
** * * ***** * * * ** ** **** * **** ** * * * * * * ** **** * *** ** * * * ** * * * * *
* ****** *** * * * ** * * ** * ******** * * ** * ****** ***** ****
** *** ******** * ****** * ** * * ** * ** ** ** * *** * * if(c==strlen(a)-1)
* ***** * *** ** ** * ** ** * * *** ** *** * *** ** * ***** * * * * * **** * * * * is a prefix of %s",a,b);
    }
** * * * *** * * *** ** * 0;
}
answered by (-498 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <string.h>
int main()
{
***** * *** *** * ** ** n,count;
** ** * * **** * ** * ** * ** ** *
* ** * ** ****** * * * %s",a,b);
* * ** * ** ** * * * *

* * *** * * **** * * *** ** ****
* * * *** ** ** *
*** * ** *** ****** *** * * ** **** * *
**** ** * ** *** * * **

** ** * ** ** * ** *** (strcmp(a,c)==0)
** * *** ** ** * * **
*** ***** ** ** **** **** * *** ******* **** ** * ** is a prefix of %s",a,b);
* * ** * * ** *** ***** *
* * * *** * *** *** **** *
* ***** * * * *
* * * ** * *** ** * *** * ** * ***** * **** ** ***** is not a prefix of %s",a,b);
*** * * * *** *** * *
*** **** ** ***** * * 0;
}
answered by (-284 points)
edited by
0 0
prog.c: In function 'main':
prog.c:8:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s %s",&prefix,&word);
             ^
prog.c:8:16: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
     scanf("%s %s",&prefix,&word);
                ^
prog.c:10:15: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     for(i=0;i<strlen(prefix);++i)
               ^~~~~~
prog.c:10:15: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:10:15: note: include '<string.h>' or provide a declaration of 'strlen'
prog.c:18:6: error: expected '(' before 'printf'
      printf("%s is a prefix of %s",prefix,word);
      ^~~~~~
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
#include<string.h>
int main()
{
* * * * * ******** * a[100],b[100];
*** **** ** * **** ** * ** ** * * *
    int l1,l2;
* ** ** * ******** ** * * ***
*** * * ** ** * * ***** **
**** * *** * * **** ** * * ** ***
**** *** * ** * ** ** ** * ** ** ** ***** * * ** ** * ** is not a prefix of %s",a,b);

    }
*** * * ******** * if(l1<=l2){
* ** * * * * * * ** ** * ** * ** * **** *** * ***** prefix=1;
*** **** * ** ** * * *** * * * * ** ** * * * * i=0;
** * * *** * * * * * * ***** * * * * ** * ** * * * * *
* * ** **** * ** * **** * * *** * ** ** *** ** ** *** * * **** ** * (a[i]!=b[i]){
*** ** ***** * ** * ** ** ******** *** * ** * ** *** * ***** ** * **** * * ** * * ***** * **
* ** *** * ** ***** * * ** * * ** **** ******* ** * * ** *** ** * ** **** *
** * ** * ** ** * ******* * * *** *** *** ** * ****


* * ***** *** * ** * * * ***** * *
* ****** * * * *** ** * * * ** * * * ** * **** *** *
** * ** * ** ** * * **** *** *** * * ** * * **** ** ** * * * is not a prefix of %s",a,b);
** ** ******** * **** * **** ** * *** *** ** ** ***
* * * ** ** ** ** * * *** ** *** *
*** *** * * *** * * * ***** ***** * ** ** ** * * ** is a prefix of %s",a,b);


    }


}
answered by (-329 points)
0 0
prog.c: In function 'main':
prog.c:5:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
             ^
prog.c:5:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
               ^
prog.c:7:8: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     l1=strlen(a);
        ^~~~~~
prog.c:7:8: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:7:8: note: include '<string.h>' or provide a declaration of 'strlen'
0 0
prog.c: In function 'main':
prog.c:6:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
             ^
prog.c:6:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
               ^
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
**** ** ***
int main(void)
{

* ** ** ** * * * * ** pre[100];
* *** * ** * * * * * word[100];
* * * * * ****** ** * * *** ** %s",pre,word);
* *** * **** * * ** * ****
* *** ** * * ***** ** *** ****

* ** * ***** ** * * *** i;
* ***** * **** ** *** * * * * *
* ** * * ** * * * ***
*** ******* * * ** * * * * * ***** * *** *
** ** * *** *** * *** ** * ******** *****
*** * ** * * ***** **** ** ** * * ** ** ** ** ** * ** * * **** * ** * * * * is not a prefix of %s",pre,word);
* ** * *** * *** * * ****** ** * * * *** * * * * ******** ** 0;
** ** *** * *** *** ** * ** * *** ** ** * ** *

* ** * * * * ** * **
printf("%s is a prefix of %s",pre,word);
return 0;
}
answered by (-249 points)
0 0
prog.c: In function 'main':
prog.c:8:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&pre);
             ^
prog.c:9:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&word);
             ^
0 0
prog.c: In function 'main':
prog.c:8:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&pre);
             ^
prog.c:9:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&word);
             ^
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <string.h>
#include <ctype.h>
int main ()
{
* *** *** * ** * * * * pre [100],a[100];
** * * *** * * n ,i;
* *** *** * * * * * ** * ****
* * * * ** * * ** ** *
** * *** ** *** * **** * * **
*** * * ** ******* * **
** * ** ** ** * * * * * * ** ** * * *** * (n=0;n<strlen(pre);n++)
* *** * * * ** * ** **** ** * ****** *
* ** ** ** ** * ** * * * * * * ** * ** * * *** * * * **** * * (pre[n]==a[n])
* *** * ** * * * * ** * *** * * * * *** * ** ** * * ***** * * * *** * ** * is a prefix of %s",pre,a);
* * * ** ****** * *** * ** ****** ** * * * ** *** * *** ** **
**** *** ** **** * ** *** ********* ** * * **** ******* ***** *** * * *** * * ** ** ** * is not a prefix of %s",pre,a);return 0;
* ****** ****** * * * ***
*** ***** * * * * * ** **** * ** * ** ** * * ** ** ****

* *** * * *** * ** 0;
}
answered by (-32 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include * * * ** * *
#include ** * *****

int main()
{
* * ** ** * *** * * * * a[100];

*** * *** * ***** * **** ** b[100];

* ** ****** *** **** ** * %s", a, b);

* * * * * * * ** ***** len_a = strlen(a);

***** * * * * **** * ** i = 0;

* *** * * *** * * **** ** * flag = 1;

* * * ** * ** * ***** ** = 0; i < len_a; i++)
** ** * * * ** *** ** ***** **
*** ** * * * ** * * ** ** ** *** ** * != b[i])
** * *** ** **** ***** ** * * ** * ****** *
** * **** ** * * ** * ** * * ** ***** ** ** ** ********** ** * *** ***** * = 0;
** * * **** * * * *** * * *
* * ** **** **** * *

*** ** * **** * * == 0)
* * * *** * * ** *
** ** *** *** * *** * **** *** * * * * * * * * **** is not a prefix of %s", a, b);
** * * * ** ** ***
***** ** ** *
*** * ** * * * ** *
* * * *** ** * * *** ** ** ******** ** * ** *** * is a prefix of %s", a, b);
** * ** * * * * * **** **
*** *** ** * * ** * **** 0;
}
answered by (-285 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
**** **** * ******
int main()
{
* * ****** * ** ** i,n;
* * ** *** ** ***** **** ** p[100],s[100],a[100]={};
* * * ** * ******** * * * * %s",p,s);
** *** ** * * * * *
* * * * * * ** * * * *** ** * *
** ******** * ***** * *** ******* ***
** * ****** ** ** * *** ** **
* *** ***** **** *** * * *** ** * * **** * * ***** * ** is a prefix of %s",p,s);
* * *** *** *** * * * *
* * ** ** ** ******** * **
* * ** ** * ****** * **** ** ** *** ** * ** * ** * * * is not a prefix of %s",p,s);
** ** *** **** ****
* *** * * *** *** * * ** * * ** * **
* ** * ** * * * *** * 0;
}
answered by (54 points)
edited by
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
#include<string.h>

int main()
{
    int i;
    char a[100];
    char b[100];
* * * ** ** * * * **** *** *******
    scanf("%s",b);
    for(i=0;i<strlen(a);i++)
** * ** * * * * ** * * ** * * * *
* * ** * ** * * ** ** ***** ** * ***** * ** ** *** ****** **** ** ***** ** != b[i])
* ** ** ***** ** * * * * * * * * *** * ** *** * ****** ***** * ** *** ** * * ******* ** *
* ** * ** ** ** ** ** * * * * *** * ** ** **** ** ***** ** *** **** * *** * * * * * ** *** * * ***** ** ** ***** * ** is not a prefix of %s",a,b);
***** ** ** *** * * ** *** * * * ** * * * * * ***** ** ** * * *** * * **** *** * ** * ****** ** ** ***** **
* *** * * *** *** * ***** * * ** * ** * ** * * ** * * *** ** * * * **** ** * *** *
**** **** * * ** ** * **** ** ** * * * * * *** ** * * * **** **** == b[strlen(a)-1])
** **** * ** * * ** *** ** *** * *** ** **** *** * *** *** ** ******** ** * * * *
**** * *** * * *** * * * * * *** * * **** * ******* ****** ** ******* *** * * * * * ** * * ** * * **** **** ** *** * * * is a prefix of %s",a,b);
** ** ** **** *** * * **** * * ***** ** * ** * * * * * ******* * * * ** **** * * * * * ** *** ** * *
** *** * * **** **** * * ** ** ****** * ** ***** * * * ** * *** *** *** ** * * **
* * * * * * ** ** * * ** *** *** **
}
answered by (-301 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
#include<stdlib.h>
#include<string.h>
#define n 100

int aa(char a[],char b[]){
* * ** * ** * * *** ** ** ** ** * i;
** * * *** * * ** * (a[0]!=b[0]){
*** ** * ** *** * **** * ** * **** ** ** ** * * 0;
** * ***** * **** ** * ***
*** ******** * *** **** *** * ** ** ** * * * *
*** ** *** * * *** * * * *** * ** ******* * * * *** * a[i]==b[i])
*** *** * * ** ** *** * * *** * * * * * *
* * * ** ***** * ** * * ** * * *** * ** * * * ** * * * * 1;
* *** * **** **** ** * *** ** * *** * * * ** ***** * *
* * ** * * * **** ****** *** ** * ** ** ** *
** * * * ** ** ** ** * ** *
** * ** * ***** * * ** **** 0;

}

int main(){
* * * * * *** *** * ** * * c[n],d[n],e[n];
* ** *** * *** i;
* * * * * *** **** *** * * * * * ** * %s",c,d);

* * *** * ** * ** ** ** *
**** ***** * * *** * **** * * ** * * * is a prefix of %s",c,d);

* * ** * * * ***
* **** ** ** * ** * ** **** ** *** * * * * * **** * is not a prefix of %s",c,d);


}
answered by (-32 points)
edited by
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:104.23.211.237
©2016-2025

Related questions

1 like 0 dislike
37 answers
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42302 - Available when: 2018-01-17 14:00 - Due to: Unlimited
| 11k views
2 like 0 dislike
31 answers
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42301 - Available when: 2018-01-17 14:00 - Due to: Unlimited
| 9.5k views
1 like 0 dislike
32 answers
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42300 - Available when: 2018-01-17 14:00 - Due to: Unlimited
| 11.1k views
2 like 0 dislike
30 answers
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42298 - Available when: 2018-01-17 14:00 - Due to: Unlimited
| 8.8k views
0 like 0 dislike
4 answers
[Exam] asked Jan 19, 2018 in Final Exam
ID: 43460 - Available when: 2018-01-20 09:00 - Due to: Unlimited
| 2.1k views
12,783 questions
183,442 answers
172,219 comments
4,824 users