Final Exam 2 (20%)

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A string p is a prefix of a string s if the leading characters of s are identical to p. For example, "abc" is a prefix of "abcde". Develop a function prefix that checks if a C string p is a prefix of another C string s.

p是s的前綴若s開頭的一段字串等於p。例如，"abc"是"abcde"的前綴。寫一個程式 判斷字串p是否字串s的前綴。

Example input 1:

abc
abcde

Example output 1:

abc is a prefix of abcde

 

Example input 2:

bc
abcde

Example output 2:

bc is not a prefix of abcde

 

[Exam] asked in Final Exam
ID: 42299 - Available when: 2018-01-17 14:00 - Due to: Unlimited
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Hidden content!
#include     *** *  **
#include    ** ** * *** 
** ***   ****** ***
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int prefix(char a[], char b[]){
int i, j,n;
int cnt=0;

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}

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}
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Hidden content!
#include <stdio.h>
#include <string.h>

int main(){
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    }
**   *****  ** *****   **** ***** * 0;
}
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Hidden content!
#include <stdio.h>
#include <string.h>
int main()
{
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}
answered by (-284 points)
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prog.c: In function 'main':
prog.c:8:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s %s",&prefix,&word);
             ^
prog.c:8:16: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
     scanf("%s %s",&prefix,&word);
                ^
prog.c:10:15: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     for(i=0;i<strlen(prefix);++i)
               ^~~~~~
prog.c:10:15: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:10:15: note: include '<string.h>' or provide a declaration of 'strlen'
prog.c:18:6: error: expected '(' before 'printf'
      printf("%s is a prefix of %s",prefix,word);
      ^~~~~~
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Hidden content!
#include<stdio.h>
#include<string.h>
int main()
{
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    }


}
answered by (-329 points)
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prog.c: In function 'main':
prog.c:5:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
             ^
prog.c:5:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
               ^
prog.c:7:8: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     l1=strlen(a);
        ^~~~~~
prog.c:7:8: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:7:8: note: include '<string.h>' or provide a declaration of 'strlen'
commented by (4.3k points)
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prog.c: In function 'main':
prog.c:6:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
             ^
prog.c:6:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
               ^
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Hidden content!
#include<stdio.h>
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int main(void)
{

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printf("%s is a prefix of %s",pre,word);
return 0;
}
answered by (-249 points)
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prog.c: In function 'main':
prog.c:8:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&pre);
             ^
prog.c:9:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&word);
             ^
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&pre);
             ^
prog.c:9:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&word);
             ^
commented by (4.3k points)
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Hidden content!
#include <stdio.h>
#include <string.h>
#include <ctype.h>
int main ()
{
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* * **  ******* * **** **  * *    0;
}
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Hidden content!
#include <stdio.h>
#include  ****** **    **
#include *   *  *  * 

int main()
{
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*  *  ** **** *  * *   *  *** *
*  *     * *  *  ** * *  ******** 0;
}
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Hidden content!
#include<stdio.h>
 * ***  ***    ** *     
int main()
{
* *    ** ****  *   * **  * i,n;
****   ** * ***   **  * *  ** p[100],s[100],a[100]={};
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     *  ****         *** * ** 
  *   ** ****   * * ** *****  ** *    * * *   * * ***   * *
 **   *** *** ***** *     * *  0;
}
answered by (54 points)
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Hidden content!
#include<stdio.h>
#include<string.h>

int main()
{
    int i;
    char a[100];
    char b[100];
** *  **   *  *** ** *    ***   ** * *  *** **   
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    for(i=0;i<strlen(a);i++)
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*       ** **   **         **** * ** *  **  *  * *** * ** *******    *    **   ****   *    **  ***
***   * *  *   **** * ** ** ** *** * ** ***** **     *   
}
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Hidden content!
#include<stdio.h>
#include<stdlib.h>
#include<string.h>
#define n 100

int aa(char a[],char b[]){
     * *   ** *  *  *  *****  * *  *  ** *   i;
*    * *  **  *****     *   ***    *  (a[0]!=b[0]){
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}

int main(){
  * * ***   * *    *** ** *      c[n],d[n],e[n];
* *  * ****** **      *       i;
**  ** * ** * **  **  * **  **** * * * * *   %s",c,d);

* **  * *** **  *   *  **** **** 
* *** *** **** * * * ****    * * * ****    *        ** * ***   *   is a prefix of %s",c,d);

 ** **  * * *   **      **** 
** * ** ** **  * ** *   * *    ****  * * *  *  *  ***  **    * * *        ** is not a prefix of %s",c,d);


}
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