Final Exam 2 (20%)

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A string p is a prefix of a string s if the leading characters of s are identical to p. For example, "abc" is a prefix of "abcde". Develop a function prefix that checks if a C string p is a prefix of another C string s.

p是s的前綴若s開頭的一段字串等於p。例如，"abc"是"abcde"的前綴。寫一個程式 判斷字串p是否字串s的前綴。

Example input 1:

abc
abcde

Example output 1:

abc is a prefix of abcde

 

Example input 2:

bc
abcde

Example output 2:

bc is not a prefix of abcde

 

[Exam] asked in Final Exam
Available when: 2018-01-17 14:00 - Due to: Unlimited
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37 Answers

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Hidden content!
#include <stdio.h>
#include <stdlib.h>
#include <string.h>


int isprefix(char prefix[], char txt[]){
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}


char prefix[100],txt[100],i;

int main(){
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}
answered by (-242 points)
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prog.c: In function 'main':
prog.c:24:16: warning: too many arguments for format [-Wformat-extra-args]
         printf(" is a prefix of ",prefix, txt);
                ^~~~~~~~~~~~~~~~~~
prog.c:29:16: warning: too many arguments for format [-Wformat-extra-args]
         printf(" is not a prefix of ",prefix, txt);
                ^~~~~~~~~~~~~~~~~~~~~~
commented by (3.8k points)
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Hidden content!
     * ****** **    **
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char prefix(char string1[],char string2[] )
{
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}
int main(void)
{
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}
answered by (-168 points)
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prog.c: In function 'main':
prog.c:37:11: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[1001]' [-Wformat=]
   scanf("%s\n",&chaine1);
           ^
prog.c:38:11: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[1001]' [-Wformat=]
   scanf("%s",&chaine2);
           ^
commented by (3.8k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (3.8k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (3.8k points)
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Hidden content!
#include<stdio.h>
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*  *     ****  ** *** *
int main(void)
{
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 printf("%s is a prefix of %s",str1,str2);
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}
answered by (-276 points)
0 0
prog.c: In function 'main':
prog.c:6:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'int *' [-Wformat=]
     scanf("%s%s",str1,str2);
             ^
prog.c:6:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'int *' [-Wformat=]
     scanf("%s%s",str1,str2);
               ^
prog.c:7:15: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     for(i=0;i<strlen(str1);i++)
               ^~~~~~
prog.c:7:15: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:7:15: note: include '<string.h>' or provide a declaration of 'strlen'
prog.c:7:22: warning: passing argument 1 of 'strlen' from incompatible pointer type [-Wincompatible-pointer-types]
     for(i=0;i<strlen(str1);i++)
                      ^~~~
prog.c:7:22: note: expected 'const char *' but argument is of type 'int *'
prog.c:10:23: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'int *' [-Wformat=]
             {printf("%s is not a prefix of %s",str1,str2);
                       ^
prog.c:10:45: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'int *' [-Wformat=]
             {printf("%s is not a prefix of %s",str1,str2);
                                             ^
prog.c:15:11: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'int *' [-Wformat=]
  printf("%s is a prefix of %s",str1,str2);
           ^
prog.c:15:29: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'int *' [-Wformat=]
  printf("%s is a prefix of %s",str1,str2);
                             ^
commented by (3.8k points)
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prog.c: In function 'main':
prog.c:8:15: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     for(i=0;i<strlen(str1);i++)
               ^~~~~~
prog.c:8:15: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:8:15: note: include '<string.h>' or provide a declaration of 'strlen'
commented by (3.8k points)
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Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (3.8k points)
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Hidden content!
#include<stdio.h>
#include<string.h>

int main()
{
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}
answered by (-140 points)
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Case 0: Correct output
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Case 2: Correct output
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Hidden content!
# include <stdio.h>
# include <string.h>
 int main(void)
 {
 *  ***  *      *  ***   *  ** *  * pre[100],str[100];
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    }
    return 0;
 }
answered by (-279 points)
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commented by (3.8k points)
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Hidden content!
#include<stdio.h>
#include<string.h>

int main()
{
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*    * *  **     **    * ** **
}
answered by (-284 points)
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Hidden content!
#include ** *** *  *  *  
#include **** *  ***  * 
#include ****  ******

int main()
{
***  ** ** ** ******** ***  prefix[100];
*** **  **  ****   *      **   word[100];
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  *  **  ********  *   ***  **
*****   * *  *  ***   **    ******    is a prefix of %s", prefix, word);
 *  **    **   ***       * 0;
}
answered by (-254 points)
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Case 0: Correct output
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Hidden content!
#include <stdio.h>
#include <string.h>
int main()
{
* **     *** ********   **** n,count;
     *** *   *****  **   *  **** a[100],b[100]={0},c[100]={0};
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 * **  * ** **   ** **** * ** * 
  *  * ***    *  **  * * * **   ** 0;
}
answered by (-191 points)
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Case 0: Correct output
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Hidden content!
#include<stdio.h>
#include<string.h>

int main()
{
*** * *   *  * ****** *  ****   String[50],string[50];
 *** * *  **   * ** * * *   a,b=0;
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** **   *  ***  *      
  return 0;
}
answered by (-107 points)
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Case 0: Correct output
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Hidden content!
#include <stdio.h>
#include    *    * * * **  
#include *** * *   *   **  

int main()
{
***  **  *      * *** *   a[100],b[100];
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   *      *    * **** *  *         * ** *    *****  ** * ******** is a prefix of %s",a,b);


 *   **  **     *  * * *     * * 0;
}
answered by (-255 points)
edited by
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Case 0: Correct output
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