1 like 0 dislike
17.5k views

A string p is a prefix of a string s if the leading characters of s are identical to p. For example, "abc" is a prefix of "abcde". Develop a function prefix that checks if a C string p is a prefix of another C string s.

p是s的前綴若s開頭的一段字串等於p。例如,"abc"是"abcde"的前綴。寫一個程式 判斷字串p是否字串s的前綴。

Example input 1:

abc
abcde

Example output 1:

abc is a prefix of abcde

 

Example input 2:

bc
abcde

Example output 2:

bc is not a prefix of abcde

 

[Exam] asked in Final Exam
ID: 42299 - Available when: 2018-01-17 14:00 - Due to: Unlimited

retagged by | 17.5k views

37 Answers

0 like 0 dislike
Hidden content!
#include * * *** **
#include * * * * * **
** ** * ** * ***
**** * *

int prefix(char a[], char b[]){
int i, j,n;
int cnt=0;

n= ** * *

* *** * *** *** * * ** ** * ***
* * ** * ***** *** * ** * **** * == b[i]){
* *** ** ** **** * **** ** * ******** * * * **
** ** ***** * * *** ***

***** ** * **
if (cnt == n){
* ***** * **** * *** * * ****** * *** * 1;
** ****** * ** ** ** *** * ** *** * * * *
* * *** * ** *** *** *** ***
* *** ** * * * ** ****** ** ** * * ** * ** 0;

}

int main()
{
* **** ***** * * * s1[100], s2[100];
* * * *** **** i,j;

*** * ******** * ** *** * **** *** ** s1);
* * ** *** ** * ** ** * * * * *** *** s2);
******* ***** *** (prefix(s1, s2)){

* ** * ** ** *** ** * *** * **** ** * * ** * is a prefix of %s", s1,s2);
** ** ** ***** ** * * ** * * ** * *****
* ****** *** * * * * * * **
* * ** * ** *** * ** * *** * * * ** *** * * * * * * * ** * is not a prefix of %s", s1,s2);



}
answered by (323 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <string.h>

int main(){
** **** * * * * ** * * ** c;
** ** ** * * *** ** * * a[100],b[100];
** * *** **** * ******** ** * %s",a,b);
** * ** ** * * *** * * * * *
* ** * * * * *** * * * **** ** **** *** * ** ** 0;
**** * * * ** * ** * * ** %d",strlen(a),strlen(b));
***** *** ** ** * * * * * ** **** ** *
* *** * * * * * * * * * *** * * ** * * ** * ** * ** *** * ** **
** ** * * ** ** * * **** * * * ** *** * * ***** ** ** ** ** * ** * * * ** *** is not a prefix of %s",a,b);
** * *********** * * ** ** * * ***** * * *** * * * ** * ** * * * **** * **** ** * ** * **
*** * * ** ** ** *** **** * * * ** * * ** ** * * * ** ** **
* * ** *** ** ** ** ***** ** * ** * ** ** ***** *** ** * if(c==strlen(a)-1)
* * * * *** * ** *** ** * * * * *** * ** ** *** ** *** * ** *** * * * ** ** * ** ** * *** * is a prefix of %s",a,b);
    }
* ** * ** 0;
}
answered by (-498 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <string.h>
int main()
{
** * * * ** ** ******* * n,count;
* ** ** * *** *** * * * *** * * **
***** * ** *** ** * ** ** * ** * %s",a,b);
*** * *** *** * * * **

* * * ***** ** **** ** ***** * * ** *
* ******* ********* * ***
*** * **** * * * * ** ** ** * *** *** ** ***** ****
** ** * ** *** ** ** *

** * * * *** * ** *** * (strcmp(a,c)==0)
*** * * * * *** *******
* *** **** *** ** ***** *** ***** *** * ** ** * is a prefix of %s",a,b);
**** * * ** * ** * * * **
*** *** **** * *** ***
* * ** ******* ** * *
**** * ** ** ** * *** * * * * * * * *** ** ** ** is not a prefix of %s",a,b);
* ***** * * ** * ***
* ********* * ** * * * 0;
}
answered by (-284 points)
edited by
0 0
prog.c: In function 'main':
prog.c:8:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s %s",&prefix,&word);
             ^
prog.c:8:16: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
     scanf("%s %s",&prefix,&word);
                ^
prog.c:10:15: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     for(i=0;i<strlen(prefix);++i)
               ^~~~~~
prog.c:10:15: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:10:15: note: include '<string.h>' or provide a declaration of 'strlen'
prog.c:18:6: error: expected '(' before 'printf'
      printf("%s is a prefix of %s",prefix,word);
      ^~~~~~
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
#include<string.h>
int main()
{
** **** *** * * ** * a[100],b[100];
* ***** * ** * * ****** ** * * ***** *
    int l1,l2;
** ** *** * * ** ** * * *
** *** * ** * *** *** * ** *
** ******* * * * * * * ** * * *** *
** * *** ** *** ** **** * * *** * *** ** *** * is not a prefix of %s",a,b);

    }
*** ** *** *** *** if(l1<=l2){
**** * * ** ** * * *** ** * * *** * *** prefix=1;
*** ** * *** * *** *** * ********* ** ** **** i=0;
* *** *** ** ** ** * * ** ** * **** * * * ***
***** * * ** * * **** * **** * ** *** *** * ** ** * ****** * ***** (a[i]!=b[i]){
** ***** ** * * * * * * * * * * * ** * **** * * *** ** * ** * ***** * *** * *** * *
** ** * ** * *** ********* *** ** *** ********** ******* * * * **** * * * **
*** ** * * *** * ** ** * * * * * *** ** * ** * * ******** **


** *** * ******* * ** *** ** *** * * * ****
** * *********** **** *** * * **** ** ** ** ** ***
*** ** * * * *** *** ** ***** *** **** ** * * * * ** * * * * * *** is not a prefix of %s",a,b);
* * * ** ** * * ** * *** * **** ** *
***** * * *** *** * ** * ** ** * ** ** *
*** * ** * * * * * ******* *** *** **** ** *** * * *** * is a prefix of %s",a,b);


    }


}
answered by (-329 points)
0 0
prog.c: In function 'main':
prog.c:5:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
             ^
prog.c:5:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
               ^
prog.c:7:8: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     l1=strlen(a);
        ^~~~~~
prog.c:7:8: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:7:8: note: include '<string.h>' or provide a declaration of 'strlen'
0 0
prog.c: In function 'main':
prog.c:6:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
             ^
prog.c:6:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
               ^
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
**** * * *** *
int main(void)
{

* * * ** *** *** * pre[100];
**** * * *** * * word[100];
* *** ** ** * ******** * * %s",pre,word);
** ** *** ***** * ******** ********
** *** * * ** ** ** ** *** *

* ** ** * *** ** * * i;
* **** * * * * * * ** * ** * * * ** **
*** **** * **** **
*** * ** * *** ** * * * *** ***** * ** ** ** * *
** *** * ** ***** * *** * * ***** *****
*** ***** * *** ** ** *** ** * * *** **** * ** * ** * * * *** is not a prefix of %s",pre,word);
* *** * ** ** * **** *** *** * * **** * * *** ** * * 0;
** *** * *** * * * * ****** *** * **** * *

** * * * * *** ***** * *
printf("%s is a prefix of %s",pre,word);
return 0;
}
answered by (-249 points)
0 0
prog.c: In function 'main':
prog.c:8:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&pre);
             ^
prog.c:9:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&word);
             ^
0 0
prog.c: In function 'main':
prog.c:8:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&pre);
             ^
prog.c:9:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&word);
             ^
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <string.h>
#include <ctype.h>
int main ()
{
*** ****** * ** * ** ** * pre [100],a[100];
* * * ***** * ** * ** * n ,i;
***** * * ****** ** * * * *
* * *** * * ** ** * *
*** ** ** ** * * * ** * * * ** * ***** * ** **
* ****** **** ****
** * * *** ** ** ***** * * ********** ** **** **** *** (n=0;n<strlen(pre);n++)
* ** * * ** *** * * *** * *** *** *** *** **** * *** ***
***** * * * ******* ** ** * * * * ** ** * *** * **** * ** * ** (pre[n]==a[n])
**** * **** ** ** * * ***** **** ** **** * * * * * ** ** *** **** ** * *** is a prefix of %s",pre,a);
* ****** * * * ** * * * **** ** ** * **** * **** ** *
* ** ** * ** * * * * ***** *** * ** * * * * * ** ** * **** **** * * * * *** ** * *** ** * is not a prefix of %s",pre,a);return 0;
* * *** ** * * *** *
* *** * * **** *** * * * * ** * * **** ** ** * ******* * * ** *

* *** ** *** * * * ** ** 0;
}
answered by (-32 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include ** * * ***
#include ** * **** **

int main()
{
*** ** * ******* ** * ** a[100];

* * * ***** * ***** b[100];

** * ** ** * * ** * ** * %s", a, b);

** * *** *** ** *** len_a = strlen(a);

* * * ** *** ** ***** i = 0;

* * ******* ***** * * ** * ** * flag = 1;

* * * ** * * ** **** ** = 0; i < len_a; i++)
* *** *** **** ***** *
* *** * * ** *** *** * ***** * ** ** ***** **** ** != b[i])
* *** *** ****** ** * **** *** * **** *** **
* * ***** * ** ******** * * * * *** * * ***** * ****** * **** * = 0;
*** ***** * **** * *** * * ** * * ** * * *** *** ***
* *** * * **** *

**** *** **** ** * ** * * == 0)
** * * * ** ** *
** * ** * * * ********* * * ** * * ** *** * is not a prefix of %s", a, b);
* *** * **** * * **** *
** * * ****** ******* * *
*** * **** * * *** ** ****
**** * ** * * ** * * ** ** ** ** *** ** *** is a prefix of %s", a, b);
*** *** *** ** *
* ** ** * * * ** * ** ** *** ** 0;
}
answered by (-285 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
******* **** **
int main()
{
* *** ** * ** * ** i,n;
* * ** *** * ** * * * ** p[100],s[100],a[100]={};
** ** * * * * * * * ** %s",p,s);
******** ** * ** * * *** **** **
** ******** *** * * *
** ** ** * ** ** **** ** * * ****
** ** * ** * * ** * ***** **
*** ** ******* * * * * ***** ** ** *** * *** * *** * is a prefix of %s",p,s);
* ** *** *** * ** *
** ** * **** * **** * * *
**** ** * **** * *** * **** *** * * ***** **** *** is not a prefix of %s",p,s);
* ** ****** ** ** * * *
* ** * * * * * *** ** **** * * ** * **** * **
** * *** ***** * * * ** 0;
}
answered by (54 points)
edited by
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
#include<string.h>

int main()
{
    int i;
    char a[100];
    char b[100];
** * ***** ****** ** ** *** * * * **
    scanf("%s",b);
    for(i=0;i<strlen(a);i++)
* * * ** *** * ** * * *** * *
* *** ** ****** * * ** * *** ***** * *** * *** * * * ** **** * != b[i])
*** ***** *** ***** ** *** * ** * * * * * * * ** ** * ** ** ***** * * * ** **
** * * * * * * ** * *** * * * * *** *** * ** ***** *** *** * *** * * *** * ** * ** * ***** * *** ** ******** * * * * * *** * is not a prefix of %s",a,b);
*** **** * ** * * * ** * *** * ** ** * * **** ** ** ** ** ** ***** ** *** ** * * ** *** * **** **
**** ***** ** ** * * **** ****** ** * * *** * *** * **** * * * ** ** ** * **
** * ** *** ****** ** * *** * * * *** ** * **** * *** * ***** * ** * * == b[strlen(a)-1])
*** ** ** * ** * ** ******* ***** * * * ** * * * * **** ** ****** ** * *
** * * * ** * **** ** * * * * *** * *** * * * * * * * * * * ***** ***** * ** * ****** * * * *** ****** * ** * is a prefix of %s",a,b);
***** * * * *** *** *** * ** *** * * * **** * **** *** *** *** ***** ** **** *** *
* ***** *** *** *** ** * ** * * **** ** *** * * * *** * *** * * **** **
***** ** * * *** * * *** ** * * * *** * * * **
}
answered by (-301 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
#include<stdlib.h>
#include<string.h>
#define n 100

int aa(char a[],char b[]){
* * * ** ** ***** ******* i;
** * ** * * * ** ****** * (a[0]!=b[0]){
******* **** * * ** * ** *** ** *** ** * * 0;
* * ** * * **** * ** ** * * *
* * **** * * *** * * ** * **** ** * *****
** ** * * ** * ** ** **** ** ** * * * ** ***** * * ** a[i]==b[i])
* * ** * * ** * * * * * ** * * * *
* * * * **** ** * * ** * * *** ** *** * ** * * ***** ***** ****** 1;
** * ** ** *** * ** * * ** * * * * ****** ** * ** * *
* * * * * ***** * * * * ** * ** *
** ** * * ** ** ** ** ** **
**** ** * ** * **** * * * * * * 0;

}

int main(){
* ** **** *** * ** * *** * c[n],d[n],e[n];
** * ** ** **** ** ***** i;
* * ** *** ******* **** * * ** *** %s",c,d);

* * *** ** * * ** *** * * * **
* * * **** *** ** ** ** * * * ** ** * *** *** ** ** * * ** is a prefix of %s",c,d);

* * **** * ****** ** *
* * * * * *** * * * ** *** * * * ****** **** * is not a prefix of %s",c,d);


}
answered by (-32 points)
edited by
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:104.23.197.95
©2016-2026

Related questions

1 like 0 dislike
37 answers
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42302 - Available when: 2018-01-17 14:00 - Due to: Unlimited
| 16.1k views
2 like 0 dislike
31 answers
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42301 - Available when: 2018-01-17 14:00 - Due to: Unlimited
| 15.1k views
1 like 0 dislike
32 answers
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42300 - Available when: 2018-01-17 14:00 - Due to: Unlimited
| 18.9k views
2 like 0 dislike
30 answers
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42298 - Available when: 2018-01-17 14:00 - Due to: Unlimited
| 13.1k views
0 like 0 dislike
4 answers
[Exam] asked Jan 19, 2018 in Final Exam
ID: 43460 - Available when: 2018-01-20 09:00 - Due to: Unlimited
| 3.4k views
12,783 questions
183,442 answers
172,219 comments
4,824 users