Final Exam 3 (20%)

1 like 0 dislike

You are requested to help in writing a program to perform addition of two large number up to 50-digits. In C there is no builtin datatype for large number, but we can use characters and array to solve the problem.

Input: The input will contain two positive integers are separated by a blank, the two positive integers do not exceed 50-digits.

Output: Sum.

寫一個程式輸入兩個大數(最大50個位數)，計算其總合。C語言不提供大數資料型態，但我們可以用字元和陣列來解決這個問題。

Example input:

999999999999999999999999999999 999999999999999999999999999999

Example output:

1999999999999999999999999999998

 

[Exam] asked in Final Exam
Available when: 2018-01-17 14:00 - Due to: Unlimited
retagged by | 93 views

32 Answers

0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include *    *     ** *  
#include      **   * *  
char a[100],sum[200],space,i;
int main()
{
    **   * * *  *  *  *         **  *  * * *

*      *** **   **     * **** * * * * *  **   *  * *
 * ** ****** * **   * * ** **           ** ****  ** *  *****   '){space=i;}
  * *   * **  ***   *  * *

*  * *  *    **  ** * **  *****      *** * ****  **
  * *  * *** *  **** * ****  ***        ****    *  **   * ** *** * ** **** *
**   * **    ** * ** ** * ** * 


*   ** **** **  * ** ** * *  ** 0;
}
answered by (-242 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (3.7k points)
0 like 0 dislike 
Hidden content!
 **********  ***** **
 **  *  **   **    * **  **
 ****  **** **    ******   
int main(){



}
answered by (-32 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (3.7k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>
int main (void)
{
     *  ** ** * ***  ***** *** num1[51],num2[51];
  * * * * ** *  * *    *  i,m;
**** *   *  * *  **   *  *  * ** arr[51]={0};
    ***   **  *  * * ** *** 
 **  *   **** * * ******  * **** %s",num1,num2);
   for (i=0;i<(strlen(num1));i++)
    {
*  * **   *   ** ** **** ***** *     ***      * ******  **    ** ****  ***  *********
    }
* * *  *  * ** **    *  ***   * (i=0;i<(strlen(num2));i++)
*      ** *     ** ** ** **
 *  * *   *  *  **   * ** *   * ***  ******  **  *******          *  * ***   ***      *  *** ***
* * * * * *****     * * *** **  
 ***   **  ** * * *     * (i=0;i<=50;i++)
 * ***** *** **  * * ***  ***** 
**    ** ** ** *   * ***   **** *** ** **   *** *   ** **  **   
      **  * * * *  * ** *** ***   * *** **    *******  **
** **  ** *   * *  **   *  **   **** ** *****  * ****  * ** * ***     **  ** ********** *
 ** *****       **   * *   ***   **   ** *   *   ******** * *  ****    * *  *   *    * ****  
*** *  ** *  ** ********   *  **** * *** ** * **** ** *
    }
****** * *   *  ** * ** *    * *   * ** * *** 
    {
*   *** ** *** *    * *    *  *** ***    ***  **    *  * ***
*   ** * *  ****** ***   *  * *** ** ** ****   ****  *  **  
  ***    *        * * * * * *   * ***** * * ***  **   * * * *******   * ** *    **    *  *** *
 * * ***         * ******** ***  **  *  ***   ******* ***   *
 *  ** *** *  * *  **   *  ***** * ****** * ****  ******   
* *  ** **  **   ** ***    **** *  * *** *   **    
 ** * *  *   *  ** *   ***      *  *** *    ***  ** *  ** * * ***  ** * *  **   ***  *******
*** **  ***   **  ***** **   *** **  * ***    ***  *  *   * * * *****    * **    ****    **  * *  **** ***** 
********  **   ** **    **    *  *  *  * ***  **  *   *  *
    }
 *  * * * *     *  ***** ** ****** 0;

}
answered by (-168 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
commented by (3.7k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>
#define n 50
int main()
{
**   * *  *   **** **     ** * a[n],b[n];
*   * **** ***   **  *** ** * *      *  * * *  *  *  *
 * ** * * *   *   *  **  l1,l2;
**** *   * *  * ****  **** *  * i=0;
** *** *******  ** *** **   *    
  *  *** *  ** *      **** **  * ** 
 * *****  *   ** ** *   * **  *      **   **  * ** * *** 
       *** **  * *** *   **   **  * ****** **** ** * *
 *       *  ** **  ** ****    ******  *     **** *  



   ***    * * **   ***** * **  **     * *** *   *** **    *** * *  *** *** *  * * * * ********  **** **  * ** ** **





**  *       **  **   * ** * * *   * **** *   *  * **** *** * 



}
answered by (-329 points)
edited by
0 0
prog.c: In function 'main':
prog.c:7:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[50]' [-Wformat=]
     scanf("%s%s",&a,&b);
             ^
prog.c:7:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[50]' [-Wformat=]
     scanf("%s%s",&a,&b);
               ^
commented by (3.7k points)
0 0
prog.c:28:1: error: expected identifier or '(' before '}' token
 }
 ^
commented by (3.7k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (3.7k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (3.7k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (3.7k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (3.7k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <stdlib.h>
#include <string.h>

int main()
{
**     *  *** *  *   ***   ** ***** ** a[50];

  ****    **  * ** ** ** ** * b[50];

*  *  **  **  ****  **     *** c[51] = {0};

****    * * *****  ****     ** * * **      *  a, b);

***** *  ** **  *  **   *     i = 0;

**  *  ** *    * ** * * *    ** len_a = strlen(a);

 *   * *** ***  * ** *           len_b = strlen(b);

*     *  * *** **  *** **  * *  = 0; i < len_a; i++)
* **    ***   ** *  ***
**** ***  * ** *  **  ** **    *  ******** *  *   * *   = a[len_a - i - 1] - '0';
    *  ***       *** **   
** **   *****  *   ** * * *    = 0; i < len_b; i++)
  **  ** *  ***   * ** *** *
 **      *** ***  ** *  * ***   * * * *     ** **  ***     *  += b[len_b - i - 1] - '0';
 *   *  **  *  ** *   *  **  

    **    *** * *  * *   *  **** = 0; i < 51; i++)
*** *  *   ***     *      
* *********** **** ********  *****    **  **    *   ** > 9)
*   ** * *  ** *****   * ******* *  *     *    
  *     ** * **  *  * *  ***  ***  **** **  * *     *  ** * *  ** **** *  * **  ***    + 1]++;

***   *  * * * ***  * * ** *     *  *   * *   ***  * * *** *  *  *  * ** ** * * * %= 10;
  ** * ******  ***  *  * *  ****  ** * * *** * ** *  *
*    * ******* ** ** * ***

 * ** * ***  *  *  * * nonzero = 0;

* * *** *    *  *  ****** *** *   = 50; i > -1; i--)
*** *   ***  * ***   **        
*** *     *  ***  *     *** **  *   * * * * *** ****   ***  != 0)
***  ** *   **   * *  ****     *  *  **  *  ** * * *  *   
 * **   ** *** ** * **  *    ** ** *  *   * * ***   **   ** *** ***  *  ** *** ***  = i;

  ** * **  ** **    *** **   *  ***    ****   **  **  * * *        *     *   ** *  * ****  * *  
**       * *   ** **** ** ***  * *   *** *********** *   *
    }

**********    **   *  *     *** = nonzero; i > -1; i--)
 *****  *    *  *  ****   
**   ********   * **   *    *   *  **  *  *  **** *     ** ***** c[i]);
   *  ***    *   *** * * *** ** 
* **  * *    ** *  *    ** ****** 0;
}
answered by (-285 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (3.7k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>

int main()
{
    int i,e,begin=0;
    char a[51],b[51];
    int c[52]={0};
    scanf("%s",a);
    scanf("%s",b);

**   *    * ** * ** * *****  *  ** * ** *     *  * **  *********    *** *  * * **** 
    for(i=0;i<strlen(a);i++)
*   *** * ** *     **    ***** ***   * ** *    * * * *  
       * * * ****    *  *  **** ***   ***   ***   ** *  *  * * * *   * **  **   ** ** * **
       **    * *  *        **      ******* *    
    for(i=0;i<strlen(b);i++)
    **  *    **     *     ****   * **  ** ** **   * **
* *** * * * ***  ****  *****  *  **  ***  ** ****     *  **  **   ** **     *  * *** ** * 
* *   * ***  *   *       ****  ***  **  *** **  * ** **** **
    for(i=0;i<50;i++)
     **  ***  * ****   * ****   *  *** ** ***** ** **    * *  **
 **   * *** *** *  *** *   *  *   ***    * * ** * *  ***  * *        *  * *  ***** > 9)
 ****        *** ***   ** **          **  * * ** * * ** *  *     ** * **  **  ******* ***  * *  ***** ** **  *
   **** * *  ***  *     * ** **  ** *  * * *  *  **  ** *** * ***   **  *** **  *  *  **  * ** *  ** ***  ** ******  *   **            *  ** *** 
 *  *  ****  *  * *** ***  *      ** ***         ** *     * **** *** **   **** ** ****  *   *   ***   ***      * *  *****  *  * ** ******
 ** ***  * **  * ************ *   * *   **** **   *** *  **   *****  **  *   * ***    **  ** ** *   ***  * 
*  *       * ******     *  **  *   *   ****      *   *
    for(e=51;e>0;e--)
  ***   **  *  *  ***** *   ***   *  * *******   *  *
 ** **   *** ** *** *   ** * * ** *  * * ** ** **    *** *  ** ****  ****  **  *     * != 0)
  *    ****  *        **       ** *   *******  *   ***     * **    ** *    *  *  *   **** *   *    ***** *** * *
* ** **** ***    **  **           **  * *  ** **       **** *  * **     * * * **   * * * * * *  ** *   ***** *** *   *  ****      *** 
 *  **   ***  *       * * * * * * *  ***  * *******    *     **** * *** *** **   *    ** ** **** ** ***     *  *****    * ****  *  * *    *
* *   * ******* * ***  **   * **     **    * * *    *  **  ****  * ****  ****** * * ***     **** **   **  * **   
* ** ***     * ******  *    * *     * ***** *** *  *  *
*   *   ****   * ** *      *      ****  * *****     *  *  *  **** **   *  * * **   * * ***  
    for(i=begin;i>=0;i--)
*  ** **** *   **** *    *  ****   ** * ****** **** 
**  *   * ***********  **** ** ***      *   **  *** **   ****  ***  ******  *  **  ***** * *  *   ** *     * *  ** 
** *    *** ** * * * * *    *** *** ** * ***** ** *
}
answered by (-301 points)
edited by
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
commented by (3.7k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (3.7k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
commented by (3.7k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
commented by (3.7k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
commented by (3.7k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
commented by (3.7k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <string.h>
int main()
{
 * *  **   **** *  ***     ***  i,j,k,l;
** * * ********* **** *** **  a[100];
** *    *** ***   *  * *** b[100];
***  **** *  ** ** *  ***  **   * * * ***   *   ***     *
          *  *      * ******** *  *  *** *   * *  * ****  *    &&   *      *** ** *
* *  *  * *  ************   
*   **  * ** **** ****   ****    *  * *   * ** **  *   * * *  ** *  * * ***   **   *  * ** *
**   *  *  **    ** *** *
  **** **   ***  ** * ** **  **   0;
}
answered by (-191 points)
0 0
prog.c: In function 'main':
prog.c:9:12: warning: integer constant is too large for its type
     if (a==999999999999999999999999999999 && b==999999999999999999999999999999)
            ^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
prog.c:9:10: warning: comparison between pointer and integer
     if (a==999999999999999999999999999999 && b==999999999999999999999999999999)
          ^~
prog.c:9:49: warning: integer constant is too large for its type
     if (a==999999999999999999999999999999 && b==999999999999999999999999999999)
                                                 ^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
prog.c:9:47: warning: comparison between pointer and integer
     if (a==999999999999999999999999999999 && b==999999999999999999999999999999)
                                               ^~
commented by (3.7k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include <ctype.h>


   int main()
   {
  *  *  ****  *  *** ** *** **** ** ** **     a[50],b[50];
* **      * ** **** *  ***   *  ** *** * *** *   c[51];
* * **  ******* *     ***    *  ** ** ***  **  * n1, n2;
******  ** * *   * *  *     ***** *** *  ***** *  * i,j;

* ******    *    ** ***  * ** *** **     * * **
    *    ***     *** * ***    *   ** ***** * **    *****     

   ** **  **  *     ** ** **  ***  *** * *     *** **  
       {
*  * **  *** *  * * *   ****  **  *  *  **  * ***   *     *         **  * * *   * **   ***   * ****  );
  ****** **       * * **** *        * *    * *

*****    *    ***      *** *** * *  * ***  ***** ** ** * * * 
* **** *      *** *  ***   * * **   ****** *  
* * **** ** ** ** **  *** ****   **  **  *  *  *******  ** * **  **   ***  *** *  * **  ****  ** b[i]);
*  **   ****** ** * * *** **  *  * *** *  **    ** *



  *  **     ******* *** ** *  **  *   * * *  ** * **  ** **   * * * *   
 **   *     **  **   * ** ** ***** *  **** *   **
 * **          *  * *  *** *** **   *    * * ***** *    ***** * ***  *  * ** ****  *      **     
***** ********    **  ***  *  **  * ***** * 
**       * **  *    *   **  *  * ***   ***** * ******     * * * **   ** 
 **   * **** * *    * * *******   * **** ***   *  *  
  ** ** *   * ****  ** *  ** ****** * *   **** **    *   *** * *** **  ***   *   * ***  *
 * *****  * * ****  **    *  ****     ***** 

*********   *       * * ****** *  ** ** *  * 
   *** *** *   **  * * * * * *   * *     * * *** * 
 *** *** ** *  *  ***  *    *   * * * ***** * * *   * ***  *       **** ***
*  **  **         * *  ***   *** *** **  *    * ***** ***     * * * *  *    ** 
       }

 * **  *****   * **   *     *  *** ***** ** **  **  ***** **** *
       {
**   ** *** ** *  *  **     ** **    *** ****     *   ** ** *   ***   * *    * ***  * * **** *
       }

* ******   **    *** **   *   *  **   * *  * *          *
 ** ** *  *  * * ****  ** * **  * * *           *   
*    *** * ***       *  **  *  *** **    *  **    ***    * **  *  *   * *** * *  *** **  ***  ****** * * *  *
  *** *   * ****    *  ** ****  ** *** *  * ** **    *


    return 0;
}
answered by (-393 points)
edited by
0 0
prog.c: In function 'main':
prog.c:13:14: warning: format '%[^
   ' expects argument of type 'char *', but argument 2 has type 'int (*)[50]' [-Wformat=]
    scanf("%[^\n]*c%",&a);
              ^
prog.c:13:19: warning: spurious trailing '%' in format [-Wformat=]
    scanf("%[^\n]*c%",&a);
                   ^
prog.c:14:14: warning: format '%[^
   ' expects argument of type 'char *', but argument 2 has type 'int (*)[50]' [-Wformat=]
    scanf("%[^\n]*c%",&b);
              ^
prog.c:14:19: warning: spurious trailing '%' in format [-Wformat=]
    scanf("%[^\n]*c%",&b);
                   ^
prog.c:17:17: warning: passing argument 1 of 'strlen' from incompatible pointer type [-Wincompatible-pointer-types]
    for(i=strlen(a),j=0;1<=0;i--,j++)
                 ^
In file included from prog.c:4:0:
/usr/include/string.h:394:15: note: expected 'const char *' but argument is of type 'int *'
 extern size_t strlen (const char *__s)
               ^~~~~~
prog.c:22:18: warning: passing argument 1 of 'strlen' from incompatible pointer type [-Wincompatible-pointer-types]
     for(i=strlen(b),j=0;1<=0;i--,j++)
                  ^
In file included from prog.c:4:0:
/usr/include/string.h:394:15: note: expected 'const char *' but argument is of type 'int *'
 extern size_t strlen (const char *__s)
               ^~~~~~
commented by (3.7k points)
0 0
prog.c: In function 'main':
prog.c:14:18: warning: passing argument 1 of 'strlen' from incompatible pointer type [-Wincompatible-pointer-types]
        n1=strlen(a);
                  ^
In file included from prog.c:3:0:
/usr/include/string.h:394:15: note: expected 'const char *' but argument is of type 'int *'
 extern size_t strlen (const char *__s)
               ^~~~~~
prog.c:15:18: warning: passing argument 1 of 'strlen' from incompatible pointer type [-Wincompatible-pointer-types]
        n2=strlen(b);
                  ^
In file included from prog.c:3:0:
/usr/include/string.h:394:15: note: expected 'const char *' but argument is of type 'int *'
 extern size_t strlen (const char *__s)
               ^~~~~~
prog.c:19:20: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'int' [-Wformat=]
            scanf("%d",a[i] );
                    ^
prog.c:24:20: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'int' [-Wformat=]
            scanf("%d", b[i]);
                    ^
prog.c:46:21: warning: format '%d' expects a matching 'int' argument [-Wformat=]
            printf("%d");
                     ^
commented by (3.7k points)
0 0
prog.c: In function 'main':
prog.c:19:20: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'int' [-Wformat=]
            scanf("%d",a[i] );
                    ^
prog.c:24:20: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'int' [-Wformat=]
            scanf("%d", b[i]);
                    ^
prog.c:46:21: warning: format '%d' expects a matching 'int' argument [-Wformat=]
            printf("%d");
                     ^
commented by (3.7k points)
0 like 0 dislike 
Hidden content!
#include     *** *   **
#include *  * * ***  **
#include  *** *      *  
int main ()
{
 * *  ** ***   *   * **** * *** * i,n,m,c=0;
        ** ** ***         *    A[60]={0};
   * ***  *  ***    **     * *  *** * * * 
   *  * ** *  *** * ** ****    ("%s ***  ** **
 **  **   * *** ** * * *  * * ** **  ***   ** ***   **  *** ***      
* *** ** ** * * * **** *** **  * 0;
}
answered by (-32 points)
edited by
0 0
prog.c: In function 'main':
prog.c:14:23: warning: passing argument 1 of 'strlen' from incompatible pointer type [-Wincompatible-pointer-types]
     for (i=0;i<strlen(A);i++)
                       ^
In file included from prog.c:2:0:
/usr/include/string.h:394:15: note: expected 'const char *' but argument is of type 'int *'
 extern size_t strlen (const char *__s)
               ^~~~~~
commented by (3.7k points)
0 0
prog.c: In function 'main':
prog.c:11:5: error: expected ';' before 'return'
     return 0;
     ^~~~~~
commented by (3.7k points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Wrong output
commented by (3.7k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>

int main() {
    char a[50], b[50], sum[50];
    int i,j,tmp=0;

    for(i=0;i<50;i++) {
 ****  * *   *   ***       *   ** *****  ** **       * *   ** *** * 
    }

   *  *   *** ** * *  ***  * * *** **    **  a);
 * *****     ** ** ***   *   ** * * * *** * b);

    for(;;) {
  ***  **  ** * ***     ***    * *     *  **  * * *****  ** * **  *** {
 * *** **** ****  *   *** *  **    ** *** ** **   **    *   * * *   ***  *   *      *
*   * ****** * **  *   ** **   * *   ****  **  *  * **  **   ***  ** **     * * **** * *  *  ** ***  *   
 * *     **** * ** *   *     *  *     ** *  ** ****** * *   *  ** **** *    ** ***   *   ** *
   **  ********* *** *  * **   *  ** *** * *     ***   ***
 ***  *  **   * *   *****   ***** * *      *   *  *   * ** *     {
 ****  *** *   * *   ***   *** * *** *** ****  **   ***  ***  *      ** * **  
 **      * * **** * ****    **  ***  ** *** * *  * **
    }

    for(;;) {
 **   *  * * *   *  ** *       * ***    *    *  *  ** *    * *  *   {
*   * * ****** ****   **  * ** *  ******* *   *     *  *    * ***** *  *     ** *** **  **
  *** ** * * ** * ** **    *       *  *****    ** **   * **  ***  *    ** * * *  ** *   
**** ***   **  *********  * *  ***       * *** *    * *  ** * * *** *  *****   ****
*  * * ** *** ***   * *  ***        *  * * *     ***  
 ***   *** ********  * *   *  * ***** ** ****  **  * **    *      {
**** * *  ** ***    *** ** *      *** **  *      ** * **  ***  ** * * **  *  ** ** * 
   ** * ** *            ** * * **    **  *** * *   *** 
    }

* *   *    * *****         *  **  *  ***   {
*  * * *  *** **** *  ********    ** ***  *****  * ***   * *  * && a[i]<=57) {
*  *  *  *** * ** *   ** *    * **   *  ***    ** ***  *****     * **** ** ** * *   *
*  **  * * ** ***  ** *****  *   ***  **********  * 
 ***** ** * * ** ***** * *    *  ** ***   * * *** ***  * ** *** && b[i]<=57) {
 **   * *  *  *    * *  ***    *       * ****   ** **** *    ***    *  **  **** **
     ***   ****** **  ***     * **  *  **  *****  * ***  * *
    }

    for(j=50;j>0;j--) {
  ****  **  *******   * ****       **  * **** * *    *  *     * *** * **  {
**   *  * **  **    ** ** *    * **** *** ****   **  * **   * * * **   *  *  *******  
* * ** * ***** * **  *    *** **  ********* *   **  *  ** *
***   *** ** ***   **** **** ** *        *   * *** * * if(sum[j]+a[j]+b[j]==10) {
******* *****    * *  * * **   * **  *     ** * ****  * ***  *  * *  * * * * *   ***  ** *   * * 
 ***   * * *   *    *  *  *******   *****  ** * **    ** ** *  * **  *           * ** *  *   *
*   * **  ** **    ** **  *    **   **   ** ***** *      
  ***    *   *             *****   *  *   ** * *** *  if(sum[j]+a[j]+b[j]>10) {
  ****   *  * **   *  *** *    *  ** ****   * * *** **   * ** **  * ****    *  *    * * *    ** * * *
 **** *  *** * *    ** *   *****  *    ** **   * * *   ** *  * ** ** **** *     **  *   * 
    *     *****      *  **   ** **  * ****** * *   * * *
    }

    for(j=0;j<50;j++) {
* * * * * ****  *   **  *  ** *****  **** **** *** *** **  *** {
 *  **  * ***  * * *** **   **  ****** * **** ***  * *  * **  **    * ** *     * **    ** 
**   ***  *  **  ** ****  ** ***** *   *  ***   *     *  * 
    }

    for(;j<=49;j++) {
*  * * ***  *    ***** *  ***    ** ***   * *  **    ***   **     *   **  sum[j]);
    }
}
answered by (-68 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (3.7k points)
Page:
Get it on Google Play Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.62.130
©2016-2019

Related questions

1 like 0 dislike
37 answers
Final Exam 5 (20%)
[Exam] asked Jan 16, 2018 in Final Exam
Available when: 2018-01-17 14:00 - Due to: Unlimited | 60 views
2 like 0 dislike
31 answers
Final Exam 4 (20%)
[Exam] asked Jan 16, 2018 in Final Exam
Available when: 2018-01-17 14:00 - Due to: Unlimited | 31 views
1 like 0 dislike
37 answers
Final Exam 2 (20%)
[Exam] asked Jan 16, 2018 in Final Exam
Available when: 2018-01-17 14:00 - Due to: Unlimited | 39 views
2 like 0 dislike
30 answers
Final Exam 1 (20%)
[Exam] asked Jan 16, 2018 in Final Exam
Available when: 2018-01-17 14:00 - Due to: Unlimited | 57 views
0 like 0 dislike
8 answers
[Makeup] Final Exam 3 (20%)
[Exam] asked Jan 19, 2018 in Final Exam
Available when: 2018-01-20 09:00 - Due to: Unlimited | 20 views
8,537 questions
68,152 answers
41,321 comments
1,610 users