Final Exam 3 (20%)

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You are requested to help in writing a program to perform addition of two large number up to 50-digits. In C there is no builtin datatype for large number, but we can use characters and array to solve the problem.

Input: The input will contain two positive integers are separated by a blank, the two positive integers do not exceed 50-digits.

Output: Sum.

寫一個程式輸入兩個大數(最大50個位數)，計算其總合。C語言不提供大數資料型態，但我們可以用字元和陣列來解決這個問題。

Example input:

999999999999999999999999999999 999999999999999999999999999999

Example output:

1999999999999999999999999999998

 

[Exam] asked in Final Exam
ID: 42300 - Available when: 2018-01-17 14:00 - Due to: Unlimited
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32 Answers

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Hidden content!
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#include<stdio.h>
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prog.c: In function 'main':
prog.c:7:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[50]' [-Wformat=]
     scanf("%s%s",&a,&b);
             ^
prog.c:7:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[50]' [-Wformat=]
     scanf("%s%s",&a,&b);
               ^
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prog.c:28:1: error: expected identifier or '(' before '}' token
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Hidden content!
#include <stdio.h>
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Hidden content!
#include<stdio.h>
#include<string.h>

int main()
{
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Hidden content!
#include <stdio.h>
#include <string.h>
int main()
{
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prog.c: In function 'main':
prog.c:9:12: warning: integer constant is too large for its type
     if (a==999999999999999999999999999999 && b==999999999999999999999999999999)
            ^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
prog.c:9:10: warning: comparison between pointer and integer
     if (a==999999999999999999999999999999 && b==999999999999999999999999999999)
          ^~
prog.c:9:49: warning: integer constant is too large for its type
     if (a==999999999999999999999999999999 && b==999999999999999999999999999999)
                                                 ^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
prog.c:9:47: warning: comparison between pointer and integer
     if (a==999999999999999999999999999999 && b==999999999999999999999999999999)
                                               ^~
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#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include <ctype.h>


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}
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prog.c: In function 'main':
prog.c:13:14: warning: format '%[^
   ' expects argument of type 'char *', but argument 2 has type 'int (*)[50]' [-Wformat=]
    scanf("%[^\n]*c%",&a);
              ^
prog.c:13:19: warning: spurious trailing '%' in format [-Wformat=]
    scanf("%[^\n]*c%",&a);
                   ^
prog.c:14:14: warning: format '%[^
   ' expects argument of type 'char *', but argument 2 has type 'int (*)[50]' [-Wformat=]
    scanf("%[^\n]*c%",&b);
              ^
prog.c:14:19: warning: spurious trailing '%' in format [-Wformat=]
    scanf("%[^\n]*c%",&b);
                   ^
prog.c:17:17: warning: passing argument 1 of 'strlen' from incompatible pointer type [-Wincompatible-pointer-types]
    for(i=strlen(a),j=0;1<=0;i--,j++)
                 ^
In file included from prog.c:4:0:
/usr/include/string.h:394:15: note: expected 'const char *' but argument is of type 'int *'
 extern size_t strlen (const char *__s)
               ^~~~~~
prog.c:22:18: warning: passing argument 1 of 'strlen' from incompatible pointer type [-Wincompatible-pointer-types]
     for(i=strlen(b),j=0;1<=0;i--,j++)
                  ^
In file included from prog.c:4:0:
/usr/include/string.h:394:15: note: expected 'const char *' but argument is of type 'int *'
 extern size_t strlen (const char *__s)
               ^~~~~~
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prog.c: In function 'main':
prog.c:14:18: warning: passing argument 1 of 'strlen' from incompatible pointer type [-Wincompatible-pointer-types]
        n1=strlen(a);
                  ^
In file included from prog.c:3:0:
/usr/include/string.h:394:15: note: expected 'const char *' but argument is of type 'int *'
 extern size_t strlen (const char *__s)
               ^~~~~~
prog.c:15:18: warning: passing argument 1 of 'strlen' from incompatible pointer type [-Wincompatible-pointer-types]
        n2=strlen(b);
                  ^
In file included from prog.c:3:0:
/usr/include/string.h:394:15: note: expected 'const char *' but argument is of type 'int *'
 extern size_t strlen (const char *__s)
               ^~~~~~
prog.c:19:20: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'int' [-Wformat=]
            scanf("%d",a[i] );
                    ^
prog.c:24:20: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'int' [-Wformat=]
            scanf("%d", b[i]);
                    ^
prog.c:46:21: warning: format '%d' expects a matching 'int' argument [-Wformat=]
            printf("%d");
                     ^
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prog.c: In function 'main':
prog.c:19:20: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'int' [-Wformat=]
            scanf("%d",a[i] );
                    ^
prog.c:24:20: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'int' [-Wformat=]
            scanf("%d", b[i]);
                    ^
prog.c:46:21: warning: format '%d' expects a matching 'int' argument [-Wformat=]
            printf("%d");
                     ^
commented by (4.3k points)
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Hidden content!
#include  *     * *  
#include ** **     *   * *
#include * * *     *  *
int main ()
{
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prog.c: In function 'main':
prog.c:14:23: warning: passing argument 1 of 'strlen' from incompatible pointer type [-Wincompatible-pointer-types]
     for (i=0;i<strlen(A);i++)
                       ^
In file included from prog.c:2:0:
/usr/include/string.h:394:15: note: expected 'const char *' but argument is of type 'int *'
 extern size_t strlen (const char *__s)
               ^~~~~~
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prog.c: In function 'main':
prog.c:11:5: error: expected ';' before 'return'
     return 0;
     ^~~~~~
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Hidden content!
#include<stdio.h>

int main() {
    char a[50], b[50], sum[50];
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**  * * *  * * *  *  *** *   *  *   **  * **  *  * * **** **** **    * && a[i]<=57) {
*       * **  ** * * * * * * **** * ***    * * ***** ****** *  *    * *      * * **    * * *
      ****** *   * ** *   *** ** * * * ******* **  ******
****  ***  ***     **  *  *  **      **** *** *** *** * *  * * && b[i]<=57) {
***    * **  * * *   ****        *****     **       ** *  ***  ***  * *  **  ******  ***   
 ***  ***  * *   **  * * * *     * *  * *   *   ** *** *
    }

    for(j=50;j>0;j--) {
* *   **********  ** *****   * ***  *  *  **   **  *  *   *  ******* * * ** * {
* *** **  *  ***   ***    *  *  * *  *     * *    ** * * ** ** ***  * **** ****        **** *
** * *  **  *** *     *   *   **   *      * * *  *    *
**   *   * ***  * **   **** *   ** ***  ** *   *    ****  ** if(sum[j]+a[j]+b[j]==10) {
 *****  ***** **  * *    * *  ***  *** ****  *** ** * *****     * * ** *****  **  *
*  ** **   ** ** **    *****     ** *  ** *    * ******   ***  *  * *  * ****  *  *  **   *  ** 
*    * ***   * *** ** **  *  **** **** **   *  * ***  **
* *  *   ** **     *  *  * ** *   **  ****  * * * *  ***  if(sum[j]+a[j]+b[j]>10) {
 * ***       ** **   ** ***    ***   ** *   *    * **  * *  * *   **  **   **   ** * ****    * * *  
   * * *    ** ** ** ****  **    ***      ** **   ****  **   ** ** *   *** ** *    ** *
 *** *    * * ***   *  **   *  ****** ** *   *  *  * *
    }

    for(j=0;j<50;j++) {
  * ***  *   **    ** *  * ***   *** *** **  ** **   *   {
* **   ****** * * ** ** * * *  * **  ** **  *  ** * *   **   * **** *    ***** *
*  ** ** * *  **   * *   ** ***   ***  * *      * ***  **
    }

    for(;j<=49;j++) {
   *****  ** * *** *** ** * *** ** * *****  * * *** * ***    *****  **  * sum[j]);
    }
}
answered by (-120 points)
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commented by (4.3k points)
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