1 like 0 dislike
13.1k views

A string p is a prefix of a string s if the leading characters of s are identical to p. For example, "abc" is a prefix of "abcde". Develop a function prefix that checks if a C string p is a prefix of another C string s.

p是s的前綴若s開頭的一段字串等於p。例如,"abc"是"abcde"的前綴。寫一個程式 判斷字串p是否字串s的前綴。

Example input 1:

abc
abcde

Example output 1:

abc is a prefix of abcde

 

Example input 2:

bc
abcde

Example output 2:

bc is not a prefix of abcde

 

[Exam] asked in Final Exam
ID: 42299 - Available when: 2018-01-17 14:00 - Due to: Unlimited

retagged by | 13.1k views

37 Answers

0 like 0 dislike
Hidden content!
#include ** * ***
#include * * ** *** *** *
* ** * * * * **
* * **** * **

int prefix(char a[], char b[]){
int i, j,n;
int cnt=0;

n= ***** *

**** * * ** * **** * *
* *** * *** * ** == b[i]){
* * * * ** * * * ** ***** * * * * ***** *
* ******** * * * **

******** ***** * *****
if (cnt == n){
* * ***** ** * * *** ** ** ********** ** * 1;
*** ***** *** * * * * ** * ** ** ***** * *
** * *** * * * ** * ** **
* * **** * * *** *** * * ** *** **** * * * * ** * 0;

}

int main()
{
*** ** ***** ***** s1[100], s2[100];
*** ** * *** ** ** i,j;

** *** ** * **** * ******* * ** * s1);
* * ******** * *** * ****** **** * * * s2);
*** *** * **** (prefix(s1, s2)){

* ****** ** * ** * * *** * * * * ******** ** *** * is a prefix of %s", s1,s2);
* **** ** * ***** * **** * *
*** * *** * ** * * *** ** * * ** * *
* ** * * ** *** * * ** * * * * * * *** ** * * * ** ** * ** *** is not a prefix of %s", s1,s2);



}
answered by (323 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <string.h>

int main(){
*** * ** * ** *** **** c;
* * *** *** ******* ** a[100],b[100];
* ** * * *** * * * * ** * * %s",a,b);
** * *** * ** * *** *** ** * * **** * * ***
* ****** *** ** * * *** ** * ** ** * ** **** * * ** 0;
* * ***** * *** ** * * * ** * %d",strlen(a),strlen(b));
* * * * ** * *********** * * ***** * * *
* *** *** * * ** *** * * ** ***** * * * * * ****** * * ** * * ** * *** ** ** * * ***
***** ** * ** * * ** * *** * ** * ** * * **** *** ** * *** * * * * * ** ** ** ** **** is not a prefix of %s",a,b);
* *** ** * * * *** * * ** * * * * *** ***** * **** * * * *** *** * * * ***** * **
**** *** * ** * *** ** * *** * * * *** * ** * ** *** ** * *
* * * * * * ***** ** **** ** * * ** **** * ** * * * ***** * * * **** * if(c==strlen(a)-1)
** * ***** * * * ****** *** * ** ** ** * * * * * * ** *** ** *** * * ** ** ***** *** * *** is a prefix of %s",a,b);
    }
************** *** * ** * 0;
}
answered by (-498 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <string.h>
int main()
{
** ******** ** ** ** n,count;
* * * * * ** * * *** ** * * ** * * ** *
* ** ** * * * ** * * * **** * * %s",a,b);
******* ***** **** ** *

** * ** * ******** * ** * *** ** * ***
* ** * * ** *** *
** *** ** ** * *** ** ** * *** ** **** * ** ******* ** * *
* * * ** * **** ****

* * *** * ** * (strcmp(a,c)==0)
** ** *** * * * *
* ********* ** ** * ** ** * ** ** ** * * * ***** is a prefix of %s",a,b);
***** * * * *** * *** *
* ** * *** *** * * * **
* ** *** * * ** ** ** **
*** ** * ** **** * ** * ********* * * * ** **** ** is not a prefix of %s",a,b);
** *** ******* * ** **
* ** **** * * ** * ** * ** 0;
}
answered by (-284 points)
edited by
0 0
prog.c: In function 'main':
prog.c:8:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s %s",&prefix,&word);
             ^
prog.c:8:16: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
     scanf("%s %s",&prefix,&word);
                ^
prog.c:10:15: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     for(i=0;i<strlen(prefix);++i)
               ^~~~~~
prog.c:10:15: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:10:15: note: include '<string.h>' or provide a declaration of 'strlen'
prog.c:18:6: error: expected '(' before 'printf'
      printf("%s is a prefix of %s",prefix,word);
      ^~~~~~
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
#include<string.h>
int main()
{
* * * ** *** * * * ** a[100],b[100];
* * *** ******** *** * * * **** *** ** * *
    int l1,l2;
*** ** *** **** ** *
** ** * * * ** * *
* ** ** **** * *** ** *** *
*** **** **** ** *** * ** ** ** * ** ** ** ***** * ** is not a prefix of %s",a,b);

    }
* ** ** *** ** * if(l1<=l2){
* ** * * * ***** ****** * * * *** * *** * prefix=1;
* ** * * * * * ** * ** * * * ** * * * ** * *** * * i=0;
* * * * *** ** * * * * **** * ** * *** * ** ** **
* ** * * * * * * ** * *** *** ** ** ** ** *** ****** **** ** * * * (a[i]!=b[i]){
* ** ** * * * * ** * ** **** ***** * * ** * **** * * ** * * * * * * * *** ** * * * **
* * * ** ** ** *** ** *** * **** ** ** *** * *** *** * ** **** *** ** * * *** * * ** ****
* * * * ** *** * * * *** ** * ** * ** * * * * *** ** * *


*** *** * * * *** ****** *** * * * * **
** ******* ** ** ** ** **** * * *** **** * ***
* * *** **** * ** ******* ** * ** * *** * ** *** * * **** * ** *** ********* is not a prefix of %s",a,b);
*** ** * * **** * * *** * ** * *****
* * * ** *** * * * ** ** ** * ** * * * * * * *
* * ** *** *** * * * ** ** * **** * *** * is a prefix of %s",a,b);


    }


}
answered by (-329 points)
0 0
prog.c: In function 'main':
prog.c:5:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
             ^
prog.c:5:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
               ^
prog.c:7:8: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     l1=strlen(a);
        ^~~~~~
prog.c:7:8: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:7:8: note: include '<string.h>' or provide a declaration of 'strlen'
0 0
prog.c: In function 'main':
prog.c:6:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
             ^
prog.c:6:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
               ^
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
**** ** ** ** *
int main(void)
{

****** *** * *** ** ** pre[100];
**** * * ****** * * * * word[100];
** ** ** *** **** * * *** * %s",pre,word);
** * ***** * * * * ** * * *
** * *** * **** * * ** * * *

** * * **** * * i;
* * * ** ** ** *** * *** * ** **
*** *** *** * *
* **** ** *** ** * * * * ** * ** * * **** **
* * * *** * * * * * ** ** ** ** ** * ** ***
**** ***** ***** ** * ** * * * *** *** * * * ** ** ** ** * * *** is not a prefix of %s",pre,word);
* * * * * *** ** * * ** **** ** * * * * ** ******** * **** * * **** 0;
** ** **** * * * ** *** * * **** **

* *** *** * * * ****
printf("%s is a prefix of %s",pre,word);
return 0;
}
answered by (-249 points)
0 0
prog.c: In function 'main':
prog.c:8:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&pre);
             ^
prog.c:9:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&word);
             ^
0 0
prog.c: In function 'main':
prog.c:8:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&pre);
             ^
prog.c:9:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&word);
             ^
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <string.h>
#include <ctype.h>
int main ()
{
*** ** **** ** * * ** pre [100],a[100];
* ** *** **** ** * ** n ,i;
* **** * * * *** **** * ** * ** *
** *** *** *** *** * ** * *** ***
** * * *** *** ** *** **** * *
*** * ** * ** *** *
* ****** ***** *** ** ** * *** ** *** ** * * (n=0;n<strlen(pre);n++)
* * * ** *** * ****** *** * ** ** *
* * * **** ** *** *** ** ** ** ** ***** *** **** * * * * ** *** * * (pre[n]==a[n])
* *** * ** ** **** * * * **** *** * *** *** ********* **** *** * *** * * * ** is a prefix of %s",pre,a);
*** *** ** ** * **** *** * ** * *** * * * **** * * ** * * *
** * * ****** ** *** *** **** ** * * ** ** *** ** * ** * ***** * * ** *** * * ***** * * * *** is not a prefix of %s",pre,a);return 0;
* * ******* ** * * * *
*** ** * ** * * * * ** * * * * *** *** **** *** *** * ***** ** ** *****

*** * * ** ****** * * *** 0;
}
answered by (-32 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include * **** * ***
#include **** *** * * **

int main()
{
* * *** ***** **** * * ** a[100];

* ** ** * * * *** b[100];

**** *** * ** * ** * * * * ****** %s", a, b);

* **** **** * ** ** *** * len_a = strlen(a);

* * *** ** **** ** * * ** i = 0;

* * * * * * *** ***** *** flag = 1;

*** * ** * ** * ** * ** = 0; i < len_a; i++)
* ***** **** ** * *
** ** *** * *** * **** **** ** **** * * * * * *** * != b[i])
* *** * * * ****** ** * ** ** ** * **
* * * ** * * ** *** * **** **** * **** * ***** * *** * ** * * = 0;
* ** **** * * * ** ** ** ** *** ** * *** **
** *** * * * * ** * **

* * * * * * ** * *** == 0)
* ** ** ** * * **** **
** * * * * ** * * ***** ** **** *** ** * * * * ** ** is not a prefix of %s", a, b);
*** * ** * * * **** ** * **
* **** *** *** ** * *** *
* * * * ** * ****
** *** * * * * *** *** * * ** ** * * * ** * *** * **** ** * * is a prefix of %s", a, b);
**** **** ** * * **** **
** * ** ** * ** * * ** * 0;
}
answered by (-285 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
* * * * ** * * * **** * *
int main()
{
** ***** ** * * * i,n;
* ** * ** * * ** ** * ** p[100],s[100],a[100]={};
** * ** * * *** ** * %s",p,s);
*** ** * * * * * ** *
**** * * *** ** * * *
* * ** ***** * ** * * ****** * * * ***
* * ** ** * * * *********** * * *
* * * * * ***** ** **** * * * *** ** ** *** ** is a prefix of %s",p,s);
**** * * * * *** ** *
** * ** * *** ** ** *
* ** ** * *** * **** **** *** * * ** * * * ** *** * is not a prefix of %s",p,s);
* * ** ** *** *** *
* ** * ** * ****** * ** ** * * * ** *****
* *** * ** ** * * ****** ** 0;
}
answered by (54 points)
edited by
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
#include<string.h>

int main()
{
    int i;
    char a[100];
    char b[100];
* *** ** * * * * *** * ** **
    scanf("%s",b);
    for(i=0;i<strlen(a);i++)
*** *** ** * * * * ** * ********* ***** ** **
* * * ** ** ** **** * * ** * * * ** ** ** * * * *** **** **** ** != b[i])
***** * ** ****** ******** * *** ** ***** * ****** * * * * * * ** **** **
* ** * * * * * ** ** **** * *** ** *** * * *** *** * ** * * * * * *** ** * ** * *** * * * ** *** *** ** ** * **** is not a prefix of %s",a,b);
** * ** * ** * *** * ** ** ***** * ****** * *** * * * * **** ** * *** **** * **** * ** ** * * ** * **** *
** **** * * * * * ** ** * ** * ** *** ** ***** * * * ** * ** * ** ** ** ** ** ** ***
* * * * * * ** * * * * * *** * *** * * ** ** ** * ** *** * ****** * == b[strlen(a)-1])
* * * *** * ** ** * ** ** * * * ****** ** ** ***** * * ** * * * ** * *** *** *
** *** ** *** ****** * * * ** ***** ** * * * * * ** ** * ** **** * **** ** * * ** * *** * ****** * * * * * *** *** *** *** * is a prefix of %s",a,b);
* * * *** * * *** * ** *** * ** *** * *** ** **** ** *** * ** *** ** * * * ** ** ** ** ** ***** * * **
*** ** ** ** * ** * *** ** **** ** ** * ** **** * *** ** * *** * * *
* * * * ** * * * * * * ***** ** *
}
answered by (-301 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
#include<stdlib.h>
#include<string.h>
#define n 100

int aa(char a[],char b[]){
*** ** * ** * ***** * * * i;
**** * **** ** * **** * * ** * (a[0]!=b[0]){
* ** * * ** *** * * ** ***** * ***** * * * * * 0;
*** ** *** * * *** ** ** * **
** ** * *** ***** ***** * ****** ** * *
** ** **** ** * ** *** * * * * **** *** * **** ** a[i]==b[i])
***** * ** ** ** *** * * ** * * ***** * * *
* * *** * ** ** * ***** *** * *** * * *** * ** ** * 1;
* * *** * ** ** ***** *** ** * *** * ** * * * ** * * * ** ******* **
* ** * ** * ******** * ** * * * * *
* ** * ***** ** * * *** * *** ***
** * * * * *** ***** * **** 0;

}

int main(){
*** ** * * * ** ******* ** * * c[n],d[n],e[n];
** * **** * * * **** ** i;
* * ** * * **** * ** ****** * %s",c,d);

* * * *** ** *** * * ** * * *
** * *** ******* * * ** ********* ** *** * ** ** *** is a prefix of %s",c,d);

* ** ***** ** ** * *** ****
** * ** * * ** * *** * * ** ****** ** * ** * * * is not a prefix of %s",c,d);


}
answered by (-32 points)
edited by
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.71.254.168
©2016-2025

Related questions

1 like 0 dislike
37 answers
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42302 - Available when: 2018-01-17 14:00 - Due to: Unlimited
| 12.6k views
2 like 0 dislike
31 answers
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42301 - Available when: 2018-01-17 14:00 - Due to: Unlimited
| 11.6k views
1 like 0 dislike
32 answers
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42300 - Available when: 2018-01-17 14:00 - Due to: Unlimited
| 13.5k views
2 like 0 dislike
30 answers
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42298 - Available when: 2018-01-17 14:00 - Due to: Unlimited
| 10.3k views
0 like 0 dislike
4 answers
[Exam] asked Jan 19, 2018 in Final Exam
ID: 43460 - Available when: 2018-01-20 09:00 - Due to: Unlimited
| 2.6k views
12,783 questions
183,442 answers
172,219 comments
4,824 users