1 like 0 dislike
18k views

A string p is a prefix of a string s if the leading characters of s are identical to p. For example, "abc" is a prefix of "abcde". Develop a function prefix that checks if a C string p is a prefix of another C string s.

p是s的前綴若s開頭的一段字串等於p。例如,"abc"是"abcde"的前綴。寫一個程式 判斷字串p是否字串s的前綴。

Example input 1:

abc
abcde

Example output 1:

abc is a prefix of abcde

 

Example input 2:

bc
abcde

Example output 2:

bc is not a prefix of abcde

 

[Exam] asked in Final Exam
ID: 42299 - Available when: 2018-01-17 14:00 - Due to: Unlimited

retagged by | 18k views

37 Answers

0 like 0 dislike
Hidden content!
#include ** * ** **
#include * * * * ** **
** ** * ***** *
****** * * * * * *

int prefix(char a[], char b[]){
int i, j,n;
int cnt=0;

n= * ** * *

** *** * **** * * ** **
* * *** **** * * *** ** * * == b[i]){
* * * * * * ** * ** ** ** * *** ***********
* * ** *** * * * ** **

* * * * * *
if (cnt == n){
*** ** ** * ** * * * **** ** * * * ** *** 1;
** * * ** * * * *** *** * ** **** *** * * ** *
* * * * ** * * ***
* **** ***** * * ***** ** ** * ******** *** * 0;

}

int main()
{
** ********* * ** s1[100], s2[100];
* ** * ** * **** ** * i,j;

* *** * * ** ** * * ** *** ***** ** s1);
* * * ***** * **** * * * * * *** ***** * s2);
* * *** ****** * * * (prefix(s1, s2)){

* ***** **** * *** * * **** * * ** ** *** ** * is a prefix of %s", s1,s2);
* * * ** ** **** * * ** * * * * ** ** *
* *** * * * ** * *** ** *** ** ****
* * *** * ** * * * * * * *** * *** * * * ** * * * *** is not a prefix of %s", s1,s2);



}
answered by (323 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <string.h>

int main(){
* * ** ** ** ** * * c;
* * *** *** * * *** *** *** * a[100],b[100];
****** ** ************* * ** %s",a,b);
** * * *** * *** * * ***** **** *
* * ** ** *** **** ***** ****** * ** ** *** * * * 0;
** ** ** ** ** *** * *** * %d",strlen(a),strlen(b));
** * ** *** * * *** *** * ** * *** * **
** **** *** ** * *** * ** * *** * ***** * ** **** **** * ** ** * **
** * * * *** ** ** * * * * *** * **** *** *** * * ***** ** * * * ** * * ****** * ** ** *** * * * **** is not a prefix of %s",a,b);
* * ** * * ** * ** ** * * * * ** ** *** * * ** *** ** ***** * * * ** **** ** ** **** * *
* * * * ** ** * * ** ** *** * ** * ** * ***** * *** * *** *** ** **
** ** **** * ** *** * * * * **** * ** * * * ** ** **** ** * if(c==strlen(a)-1)
** *** * * ** * **** ** **** * ** **** ****** * * ***** * ** *** * * * **** ***** ** * ***** **** is a prefix of %s",a,b);
    }
* **** ** ***** * *** * 0;
}
answered by (-498 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <string.h>
int main()
{
* * * ***** * * * ** * * ** * * n,count;
* * * * * * * * * *** * ** ****** * * *
**** * ** *** * *** ** * **** %s",a,b);
* ** ** ***** * *

** ** * * * * *** * * * ** * ** ** *
* ** *** ** * ** *
* * ******** * **** *** * * *** ** ** *** ** ** *
* ** * * ***** * * **

* * * ** * ** * * (strcmp(a,c)==0)
* * ** * * **** **
** ** * * *** ****** * ** * ***** * ** * * * ********* **** is a prefix of %s",a,b);
* * ** * ** **
* * * * *** * * **** *
** * * * * ** ********
* ***** * ** *** * * ** * ** * * *** *** * *** * * is not a prefix of %s",a,b);
*** * ** ***** * *** *
*** ** * * ** * 0;
}
answered by (-284 points)
edited by
0 0
prog.c: In function 'main':
prog.c:8:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s %s",&prefix,&word);
             ^
prog.c:8:16: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
     scanf("%s %s",&prefix,&word);
                ^
prog.c:10:15: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     for(i=0;i<strlen(prefix);++i)
               ^~~~~~
prog.c:10:15: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:10:15: note: include '<string.h>' or provide a declaration of 'strlen'
prog.c:18:6: error: expected '(' before 'printf'
      printf("%s is a prefix of %s",prefix,word);
      ^~~~~~
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
#include<string.h>
int main()
{
** * * ** * * * * ***** a[100],b[100];
*** ** ** * * * ** ** * *** ********* ** *
    int l1,l2;
* *** * ** * * ** * **** * *** *
* **** ** * * * * * *** * *****
* **** * * *** * * *** ** ** * *
* * * * ** * ** * * * * *** **** * * ** * ** is not a prefix of %s",a,b);

    }
*** *** * ******** * ** if(l1<=l2){
* *** ** * * * *** * ** ** *** ** * * ** * ** * prefix=1;
* * *** * *** * **** * * * * * **** *** * * * i=0;
***** * * **** ** * * **** * ******* * *
* * *** * * ***** * * * * * ***** *** * ** * * * * *** *** (a[i]!=b[i]){
* **** *** * ** *** * * ** ** ** * * * ** *** *** *** *** * * ** ** * * * * * *
* *** * * * ** * * *** ** * * ** * *** * * ** ** **** ** ***** *** *** *** *** ** * ** *
*** * * ** * ** *** * * *** * ** ** *** *** ** ** **** **** **** * * * * *


* *** * * * * ** * * *** *** **** *** **** *** ** ****
*** ** * * * *** ** * ** * * * *** * *
*** ** * * * * *** ************ *** * * *** ** * **** ** ** ***** * ** is not a prefix of %s",a,b);
*** * ** *** * * * *** * ** *
** * * * **** ** * * * * ** * **** ***
* * * * * ** * **** * *** * * * ****** * * ** is a prefix of %s",a,b);


    }


}
answered by (-329 points)
0 0
prog.c: In function 'main':
prog.c:5:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
             ^
prog.c:5:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
               ^
prog.c:7:8: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     l1=strlen(a);
        ^~~~~~
prog.c:7:8: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:7:8: note: include '<string.h>' or provide a declaration of 'strlen'
0 0
prog.c: In function 'main':
prog.c:6:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
             ^
prog.c:6:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
               ^
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
* ** * ** * * *****
int main(void)
{

* ** * ****** * **** pre[100];
* ***** * * *** *** **** word[100];
* * * ** * *** ** * *** * *** ****** %s",pre,word);
**** * * * * **** ** *** **
*** * ** * * ** * *** * ** ***

* * ** * * * *** ** * ** i;
**** * ** *** ** * *** * ** * * *
** ** * * * ** * ***
* *** * ***** * ** *** *** *** * *** ***
* * * * ** ** * * ***** * * * * *** ** ***
** **** ** ***** ** * ***** *** ** * **** * * *** *** ***** *** ********* * is not a prefix of %s",pre,word);
* * ** * ***** * ** ** *** ** ** * **** **** * * ** ** ** * * 0;
* * * * ** * ** * *** ** ** * * ** *

* ***** * * *******
printf("%s is a prefix of %s",pre,word);
return 0;
}
answered by (-249 points)
0 0
prog.c: In function 'main':
prog.c:8:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&pre);
             ^
prog.c:9:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&word);
             ^
0 0
prog.c: In function 'main':
prog.c:8:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&pre);
             ^
prog.c:9:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&word);
             ^
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <string.h>
#include <ctype.h>
int main ()
{
* ** ** * ** * * pre [100],a[100];
* * **** ** **** n ,i;
* *** * * * ** * * * *********
*** * * * ****** * * **
** * * ** * * *** *** * * * * * * ***** **
**** **** ** ** *
* * ** * * *** *** ** ** * ** * * ** ********* * (n=0;n<strlen(pre);n++)
* * ** * ** ** * *** * * **** * ** **
* * * * * ** ** * * * * * * **** ****** * * * ** * * * *** (pre[n]==a[n])
* **** ** * * * ** * *** *** * ** * *** *** * ********* **** ** * * **** ** is a prefix of %s",pre,a);
* ** ***** * *** ** ** * * ** *** *** * * * ** * **** *
* * * * * ****** ** * * **** * * **** * * ** **** * ** * * ** ** ** * *** * * ** * is not a prefix of %s",pre,a);return 0;
* ** ***** * *** * * * *
*** * * **** * * *** * * * **** ***** *** ** ** * **** ***

* * * **** * * *** 0;
}
answered by (-32 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include * * *** * **
#include *** * ***

int main()
{
***** * * * *** ***** * a[100];

** ** ** * **** * * b[100];

* * **** * ** ******** * * * * %s", a, b);

** * ** *** ** * * * len_a = strlen(a);

* * *** ** *** * i = 0;

** * * ** ** * flag = 1;

* * * * * **** * ** * * = 0; i < len_a; i++)
* * * * * * * * **
* ** ** * * * *** *** ** *** ** ** ** ** * * * * **** != b[i])
** * *** * * ** * * * ** ***** *** ** *** **
* * ** * * * *** ****** ** ** ***** * *** * * ** ** * * * *** ** = 0;
* * * ** **** *** ** * ** **** * * ** *
* **** * **** ** *

* ** ** **** * * * * == 0)
** ** *** * * ** *** *
** ******* * * *** *** * * * * *********** ** * ** is not a prefix of %s", a, b);
*** *** *** ** **
* ** *** * * ** * * *
** * * * ** * * *
* **** ** **** **** ** **** ** ** ** *** *** * * is a prefix of %s", a, b);
*** ** * *** **** **
*** * * ** * ** * * * 0;
}
answered by (-285 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
* *** ****** * ** *
int main()
{
* * * * *** * * **** *** * i,n;
* * * * * *** * p[100],s[100],a[100]={};
*** * * **** ** * ** *** * ** %s",p,s);
** * * * ** ** *** ****
** ** * * ** **** * *
** * * ** ** ** * * **** ** * ****** * **
* ***** ** * ** * * * * * * *
* ** * ******** ** *** * * ** ** * ** * **** is a prefix of %s",p,s);
**** **** *** ***
** ********* ** * * *
* * ** * *** **** * * * * * ** * * *** ** *** * * * * is not a prefix of %s",p,s);
**** ** ** *** * ****
**** * ** * ******** * *** *** * * **** *
* * * ** ** * ** *** ****** 0;
}
answered by (54 points)
edited by
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
#include<string.h>

int main()
{
    int i;
    char a[100];
    char b[100];
*** * * * ** ** * ** * ** * * * * * ***
    scanf("%s",b);
    for(i=0;i<strlen(a);i++)
**** * ** ** ******* ** ** *** *** ***** *
* ** ***** * * ** * *** * ** **** * * * * ** *** * ** ***** *** * * ** != b[i])
* * * * * *** *** * * ***** ** * * ***** * ** *** ** * * * * ** ** ** * *
** *** * ** *** * ***** * * * * * *** ** *** *** * * * * * *** ** * * ** * *** * * * * ** * * * **** * * ** * is not a prefix of %s",a,b);
* * ** * * **** ** ** ** * * * * **** **** * ** **** * * * ** * ** * ** * * ** ** *** **** * ** * ***** **** **
** * ** * * *** * **** * ** * * * * ******** * ** * ****** * ****** ** * * ** **** **
* ** ** * **** *** * * * * ** * ************ *** * ** * * ***** *** == b[strlen(a)-1])
* ***** * *** * * * ****** ** ** ** **** * * * * * *** ** * ** *** ***** * * **
* * ** *** *** * * * * ** * ** *** * ** ** * * * *** ******* ******* * ** ***** * * * * * * **** ** * ** **** *** * * ** is a prefix of %s",a,b);
**** * * ******* **** * ** * ** * * * *** * * *** *** * * * * * * **** * ** * ***** ** * * ** *** * *
** * * * ** * * * * ** * * **** * * ** *** * * **** * * * *** * * *
* * **** * ** ** ** ** * * ** **
}
answered by (-301 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
#include<stdlib.h>
#include<string.h>
#define n 100

int aa(char a[],char b[]){
* * ** ***** * * * * * ** ** **** i;
* ******** *** * *** * (a[0]!=b[0]){
*** **** ** * ** ***** ** ** * * * * ** 0;
*** * ** ******* * ***** ***
* *** * * * * ****** * * * * *
* ** *** * * ****** ** ** * * * **** ** * * * ** * a[i]==b[i])
* * *** * *** * * ******** * * * ** *
** * *** * ** **** ****** * ** ** * * ** * * * ** *** * ** * *** 1;
**** * *** * * * ***** **** * ** ** * * ** *** **** * ****** *** ** *
* * * ** * ** * * ** * * ** ** ** * ***** *
*** *** ** *** ****** * * ***
** * * * * * ** ** ** **** 0;

}

int main(){
* *** * * * * * * *** c[n],d[n],e[n];
* ** * * ** * *** i;
** * **** * * * ** *** * * * %s",c,d);

* ** * ** * **** ** *
* ** * * * **** *** *** ** * * * ** *** ** **** is a prefix of %s",c,d);

**** ** *** ** ****
***** ** * ** ** *** * * * * *** * *** * ** * ** * is not a prefix of %s",c,d);


}
answered by (-32 points)
edited by
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:104.23.243.108
©2016-2026

Related questions

1 like 0 dislike
37 answers
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42302 - Available when: 2018-01-17 14:00 - Due to: Unlimited
| 16.6k views
2 like 0 dislike
31 answers
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42301 - Available when: 2018-01-17 14:00 - Due to: Unlimited
| 15.6k views
1 like 0 dislike
32 answers
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42300 - Available when: 2018-01-17 14:00 - Due to: Unlimited
| 19.4k views
2 like 0 dislike
30 answers
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42298 - Available when: 2018-01-17 14:00 - Due to: Unlimited
| 13.5k views
0 like 0 dislike
4 answers
[Exam] asked Jan 19, 2018 in Final Exam
ID: 43460 - Available when: 2018-01-20 09:00 - Due to: Unlimited
| 3.4k views
12,783 questions
183,442 answers
172,219 comments
4,824 users