1 like 0 dislike
15.5k views

A string p is a prefix of a string s if the leading characters of s are identical to p. For example, "abc" is a prefix of "abcde". Develop a function prefix that checks if a C string p is a prefix of another C string s.

p是s的前綴若s開頭的一段字串等於p。例如,"abc"是"abcde"的前綴。寫一個程式 判斷字串p是否字串s的前綴。

Example input 1:

abc
abcde

Example output 1:

abc is a prefix of abcde

 

Example input 2:

bc
abcde

Example output 2:

bc is not a prefix of abcde

 

[Exam] asked in Final Exam
ID: 42299 - Available when: 2018-01-17 14:00 - Due to: Unlimited

retagged by | 15.5k views

37 Answers

0 like 0 dislike
Hidden content!
#include ******* * * ** ***
#include ***** * *
* * ** **** * *
** *** * * ** *

int prefix(char a[], char b[]){
int i, j,n;
int cnt=0;

n= **** *** ***

* * **** ** * ** * ****** * *
***** *** ** * ** ** * == b[i]){
* * ** **** ****** * * **** * * * *** ** *
* ** * ** ** *

* * ** * *
if (cnt == n){
***** * * ** *** * * * ** ** * ** ** * * * ** 1;
** ***** *** * * ** **** *** ** * ** **** *
* * ****** * * * * **
**** * * * * * ** * * * * *** * * * * ** * * * 0;

}

int main()
{
* ** * * ** s1[100], s2[100];
* *** * *** * ** i,j;

***** **** * * *** **** ** *** * *** s1);
* ** *** **** * * * * ** * *** ** s2);
* **** **** * (prefix(s1, s2)){

*** * *** ** *** ** ** ** **** * * * * * ** is a prefix of %s", s1,s2);
* *** * **** ** **** * **** * * *** * * *
***** ** **** * * *** * * *** * **
*** ** **** *** ** ****** *** * * * ** * * * *** ** ** * ** is not a prefix of %s", s1,s2);



}
answered by (323 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <string.h>

int main(){
* *********** *** *** ****** c;
* * *** * **** ** * * ***** * a[100],b[100];
****** * ** **** ** ** * * * * * * %s",a,b);
***** ***** * * *** ****** * * ** * **
***** * ** **** ** * ** * ** * ** **** ** **** * 0;
** * * * ** * ** ***** * * * %d",strlen(a),strlen(b));
** * * * * ** * * *** * ****
** ** ** * * * ***** **** * ** ** * ** ** **** ** ** * ** ** * * * * ***
* * * ***** * * * ** * * ** * ** ** * ** ** ***** ***** *** * *** ** *** * * *** ** ** * * * * ** * * is not a prefix of %s",a,b);
* * * * ** * * * ** * ***** ** ** * ** * * * **** **** ** ** * * * **** * *** * *** * ** * ** *
* * * * **** ** ** *** * ** ** *** ******* * ** * * *** *
* **** ** *** * ******* *** * ** * ** * * * * * * * * *** * * if(c==strlen(a)-1)
***** ** * *** ** * ** * * ** * * ***** ** **** ** ** * * ** * * * ** * * ** * * *** * is a prefix of %s",a,b);
    }
* *** * ** ** 0;
}
answered by (-498 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <string.h>
int main()
{
* ** * ** ** * * *** ** n,count;
* * ****** * ** ** * ** ** * ** * *
* * * **** * * * *** ** *** %s",a,b);
** * * * * * * * * * *

** * * * * * * ** * ** ***** * *** *
* * ** *** ** *** ** **
* * * * ** * ** *** * * * * * * ***** ** * **** *
* * * * * * * *

* * * * * ***** ** (strcmp(a,c)==0)
*** **** * * * *** * *
*** * ** *** ** * * * * * ** * * * * ****** ****** is a prefix of %s",a,b);
** *** ** *** * * * * ** **
* * *** ** ****** * **
* * * *** * * ***
*** **** * ** * ****** * * * ** ** ** * ***** ** * * * ** * is not a prefix of %s",a,b);
* * ** ** ** *
* * ****** * * * ** *** * 0;
}
answered by (-284 points)
edited by
0 0
prog.c: In function 'main':
prog.c:8:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s %s",&prefix,&word);
             ^
prog.c:8:16: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
     scanf("%s %s",&prefix,&word);
                ^
prog.c:10:15: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     for(i=0;i<strlen(prefix);++i)
               ^~~~~~
prog.c:10:15: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:10:15: note: include '<string.h>' or provide a declaration of 'strlen'
prog.c:18:6: error: expected '(' before 'printf'
      printf("%s is a prefix of %s",prefix,word);
      ^~~~~~
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
#include<string.h>
int main()
{
***** **** * * ** ** a[100],b[100];
******* ** * *** * * * * * * * ** * ***
    int l1,l2;
* * * ** * ** ** * ** ***
* ** * ** * ******* * **** *
** * ***** * *** ** * * **** **
** * * **** *** * *** * ** * * ** ** * * is not a prefix of %s",a,b);

    }
** * * ** * *** ** if(l1<=l2){
* ** * * ** * * * ****** ** * prefix=1;
** ******* * * *** *** ** **** i=0;
* * ** * ** *** *** * * * * *** ******* ** ** **** *
* ** ** * ** ** ** * ** *** * * ***** **** ** *** * * ** * * ** ** (a[i]!=b[i]){
** * **** ** * ** **** ** * ** * * * **** *** **** **** ** *** ** *** * *** * * * ****
*** * *** * * * * * * ** * * * * ** * ** * * ** * **** * * * ** * *** **** *
* * * ** * * ** ********* ***** * *** ** * * ***** *** *


** * * ******* ** ** * * * ** ***** ** ****
* * * * ** * *** * **** ** * ** * * * ** * * ***
* ** *** ** ** * ***** ***** **** * ** ***** * * * ** * * * *** is not a prefix of %s",a,b);
****** * * * ** * **** * * ******** ** * * **
* ** *** * ** * * * ** ** ** *** * * *
* * * * * *** * ***** *** * * * * ** * ******* * * * is a prefix of %s",a,b);


    }


}
answered by (-329 points)
0 0
prog.c: In function 'main':
prog.c:5:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
             ^
prog.c:5:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
               ^
prog.c:7:8: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     l1=strlen(a);
        ^~~~~~
prog.c:7:8: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:7:8: note: include '<string.h>' or provide a declaration of 'strlen'
0 0
prog.c: In function 'main':
prog.c:6:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
             ^
prog.c:6:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
               ^
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
** ** ** ** ** *
int main(void)
{

** * ** * * * ** * ** pre[100];
** ** *** * * * *** **** word[100];
** **** ** * ** * ** ** * * ** *** %s",pre,word);
* * *** * * ***** **** * * ** *** * **
** * * ** ** * ** *** * * *** * *

** * *** * ** * *** * * i;
* ** ** *** *** *** *** ** ***
* * ** * ** * * * ** * *
**** ** * ** ** * *** *** ** ** ** ** * ** ** ** *
***** * * ** *** ****** * * * ** *
**** * ** ** ** * *** * * * * * ** * * * **** * * * ** ** *** * ** * is not a prefix of %s",pre,word);
* * * * * * ** ***** * * **** * *** ** * * ***** * *** ** *** 0;
********* **** * * * * **** ** ****** * **** ***

* * *** **** **** ** * *
printf("%s is a prefix of %s",pre,word);
return 0;
}
answered by (-249 points)
0 0
prog.c: In function 'main':
prog.c:8:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&pre);
             ^
prog.c:9:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&word);
             ^
0 0
prog.c: In function 'main':
prog.c:8:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&pre);
             ^
prog.c:9:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&word);
             ^
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <string.h>
#include <ctype.h>
int main ()
{
* * * * ***** ** * * * * pre [100],a[100];
**** ** * ** *** n ,i;
** ** *** ****** ** * *** * * *
** * * * ****** * *
** ** * ** * * * * * **** * * * ** * **
**** * * * * * * **** *
***** ** * * ****** *** * * * * ** * * (n=0;n<strlen(pre);n++)
*** ** * * * **** *** *** * * ******* ** *
**** * ** ****** ** ***** ** * * **** ** *** * *** * *** * * ** * (pre[n]==a[n])
** *** *** *** * * *** ** * *** * * * ** ** ** ** * * **** * * * *** is a prefix of %s",pre,a);
** ****** *** * * **** **** * ** * *** * * ** ***** * * **** * *** * *
* * ** ***** * ** ** ** * **** * * ** * *** * * * * * ** * **** *** * ** *** * * * ** * is not a prefix of %s",pre,a);return 0;
* * *** * * * ****
** ***** ** * ** * ** **** * *** ** * ***** *** * * ** ** ** * * *

** * ** * ** ******* ** ** * 0;
}
answered by (-32 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include * ** ***
#include **** *** ***

int main()
{
* ********* * * ** a[100];

*** ** * * ** ** * b[100];

* * *** ** * *** * ** * %s", a, b);

**** * ** * ** ***** ** * len_a = strlen(a);

* ** * * ** * ** i = 0;

** * ** ** * ** * ***** * flag = 1;

* ******* **** * **** * ***** = 0; i < len_a; i++)
*** ** **** ** ** * * *
* * **** * * ** ** ** ** * * *** * ** != b[i])
* ** * * * * ** **** * ** * *** ****
**** * * * * ** ** * * ** ** * ***** ** ** *** * * ** * * * * * = 0;
** * **** * * **** * * *** *** ** ** * * ** * *
* * ** *** *** *** * * **

* ** * * * ** == 0)
** * ** * * * ** *** ** **
******** * ** **** **** ** * * *** * * ** is not a prefix of %s", a, b);
** * ** * ** ** * * * *
** ********* * * * *
* * * * * * * * ** *** *
* * * * ***** ******* * **** **** * ** ** * * * * *** * is a prefix of %s", a, b);
** * *** *** ** * * *
** ** ** * *** ** * *** ** 0;
}
answered by (-285 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
* *** * ** ** * *
int main()
{
**** * * **** * i,n;
* * * * ** * *** ** * p[100],s[100],a[100]={};
*** * *** * **** * * **** * %s",p,s);
****** * *** * ** **
* ****** *** * * * * * **** ***
* ** ** ** *** **** * ** ***** * ** ****
* * ******** ** ** *** * * *
* * ** *** **** **** *** * **** * *** * ** * * *** ***** is a prefix of %s",p,s);
* ** ****** *** * * ** **
* ** ** *** ** * ** ***
* ** *** ** ** ** * **** * * * **** * **** ******** is not a prefix of %s",p,s);
** ***** ** ** *
* * ** *** ** * **** * * * ******** ** ***
* * * * * * * * 0;
}
answered by (54 points)
edited by
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
#include<string.h>

int main()
{
    int i;
    char a[100];
    char b[100];
* ***** * *** * * ** * * * * * ** ****
    scanf("%s",b);
    for(i=0;i<strlen(a);i++)
* * ** * * * * * * ** ** * * ****** * *
* ** ** ** *** ** ** ***** ** * ** *** * ** * * * ** ** ** * * != b[i])
***** * * ** * * ** *** * ** **** **** ** * * ** ** *** * * * * * * * * ** *** * *
* * * ** * *** ** * * * * ** ** ***** ***** * * ******* **** **** *** ** **** ** ** ** ** * ** * ** ** * * * * * is not a prefix of %s",a,b);
***** * * * **** * * *** *** * * ****** ** * * ** * * * * * **** * ** *** * **** ** * * ** ** *** * *
* ** ** ** * *** * * ****** * ****** * *** **** *** * * **** ** * ** * **** ** * ** *
** * * *** ** ****** * ** * * * * * *** * ****** ***** ** * **** *** *** * == b[strlen(a)-1])
* * **** ** * *** *** ** ******* * **** **** *** * ***** ** * * * * * *** ***** *
** **** * * * ** * * ** *** *** * * * ** ** * * * ** * * ** ** * * * *** * ****** ** * * * * * *** ** **** ** * ** is a prefix of %s",a,b);
** * * * * ******** ** * * * ** * ** **** * **** ** * * * * * * *** **** ** * * * * *** ** * * ** ** ** ***
* * * * ** * * **** *** ******* * ****** * * ** * * ** * * ** *** ** * * ** * * ** **** *
** ******* **** * *** * ***** ** * * **
}
answered by (-301 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
#include<stdlib.h>
#include<string.h>
#define n 100

int aa(char a[],char b[]){
**** * * ** * ** * * * * * ** i;
* *** * ***** * ** * * ** (a[0]!=b[0]){
** * * ****** * * * * ** * * ** *** 0;
* ** * * * * * *
* ****** * ** * **** * * * * * ** * *
**** **** ** * * * ** * **** *** * **** * * * * ** * a[i]==b[i])
** * *** * ****** ****** *** * ** ** *
** ** ** * * * * * * * ** ** * * ** ** ** *** *** * ** * **** ** 1;
***** *** * * * **** ***** *** **** *** * *** ** * ******* **** *****
* ** **** *** ** * * *** **** * * * ** ******
** ** **** ******* ** *** *
** * *** ***** * * * ** ***** * 0;

}

int main(){
** * ** * * * *** *** * ** c[n],d[n],e[n];
** * * * * * ******* ** ** i;
**** * * ** * * * **** %s",c,d);

* ** * ** * ** *
**** * * ** * * * * * * * ** * ** *********** * * ** is a prefix of %s",c,d);

* ** * * ** *** ****** *
* * ** ** * * ***** *** *** * *** ** is not a prefix of %s",c,d);


}
answered by (-32 points)
edited by
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.68.87.148
©2016-2026

Related questions

1 like 0 dislike
37 answers
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42302 - Available when: 2018-01-17 14:00 - Due to: Unlimited
| 14.1k views
2 like 0 dislike
31 answers
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42301 - Available when: 2018-01-17 14:00 - Due to: Unlimited
| 13.4k views
1 like 0 dislike
32 answers
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42300 - Available when: 2018-01-17 14:00 - Due to: Unlimited
| 16.6k views
2 like 0 dislike
30 answers
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42298 - Available when: 2018-01-17 14:00 - Due to: Unlimited
| 11.5k views
0 like 0 dislike
4 answers
[Exam] asked Jan 19, 2018 in Final Exam
ID: 43460 - Available when: 2018-01-20 09:00 - Due to: Unlimited
| 3k views
12,783 questions
183,442 answers
172,219 comments
4,824 users