1 like 0 dislike
13.3k views

A string p is a prefix of a string s if the leading characters of s are identical to p. For example, "abc" is a prefix of "abcde". Develop a function prefix that checks if a C string p is a prefix of another C string s.

p是s的前綴若s開頭的一段字串等於p。例如,"abc"是"abcde"的前綴。寫一個程式 判斷字串p是否字串s的前綴。

Example input 1:

abc
abcde

Example output 1:

abc is a prefix of abcde

 

Example input 2:

bc
abcde

Example output 2:

bc is not a prefix of abcde

 

[Exam] asked in Final Exam
ID: 42299 - Available when: 2018-01-17 14:00 - Due to: Unlimited

retagged by | 13.3k views

37 Answers

0 like 0 dislike
Hidden content!
#include *** * *
#include *** ****** *
* * ** ** ** * *
**** * ** ***

int prefix(char a[], char b[]){
int i, j,n;
int cnt=0;

n= * ** * * *

***** ** ** * * * **** * * ***** ****
*** *** **** * * *** ** ** *** == b[i]){
* * * *** * * *** * *** *** ** * **** *** *
* *** * * *** *

* *** * ** * * **
if (cnt == n){
* * * * * * **** ** **** * * * ** ***** * *** 1;
*** ** ** ** * ** * * ** * * * * * *** * *
** * ***** ** ** ****** **
* *** ** ***** ** ** * * * * * ** *** * * * 0;

}

int main()
{
****** * * * * ** ** * s1[100], s2[100];
* * ****** *** * i,j;

* ** * ***** * ** ******** ** * * s1);
** ***** ** * *** * * * ** ** ** * * * s2);
* ** * ** ** ** *** * (prefix(s1, s2)){

* * * * * * *** * ** ***** ** * * *** ** is a prefix of %s", s1,s2);
** * ** ***** ** **** ***** **** *
* ****** * **** * ** * * ***
**** ** * ** ***** * *** * * ****** ** * * ** * ** ******* is not a prefix of %s", s1,s2);



}
answered by (323 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <string.h>

int main(){
* * ** ** * * * *** * * c;
* ***** ** * *** * a[100],b[100];
** * ** * *** * * * ** * * * %s",a,b);
* **** *** ** *** *** *** **** * ****
* *** * * ***** * * **** * ** * * ***** * ** 0;
*** * * * ** ****** ** * *** %d",strlen(a),strlen(b));
***** * ** ** ** ** * *** ** ****
* ** * * * **** * ** ** *** * * * * *** * **** * ** ** ***
* ** *** * ** * *** * **** ** ** *** * **** ** ** ***** * * *** * * * * ******* * ** ** * * **** is not a prefix of %s",a,b);
* * * * * *** * * *** ** ***** * * * * *** ** **** ****** **** * * *** * ** **** ** * * **
*** **** * * * ** * ** ***** * ***** * ** * * ** * * ** **
** * **** **** *** ** *** ** *** * * * * ** * *** * * * * * if(c==strlen(a)-1)
* *** * * * ** **** ** * **** * ***** * * * * *** * * * *** * * * ** * * * * * **** * * * is a prefix of %s",a,b);
    }
** * ** ** * ** 0;
}
answered by (-498 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <string.h>
int main()
{
* ** * * * ** ** * * n,count;
* * *** * ** * ** *** * ** *** *** ** * ** *
* * **** ** * *** ** **** * *** * %s",a,b);
* ** * ** **** * ***

* * * * * **** ******* **** * ** * * * *****
** ** ** ** *** ** * * *
** ** *** ******* ** ** * * ** * * **** *** *** *
* ** ** **** **

** ** * * ** * ** ** * (strcmp(a,c)==0)
* * * *** ** **
* ** * *** * ****** **** * ** * * ** **** * ** ** * is a prefix of %s",a,b);
* * * * * * * * * ** * *
* ** ** * * * * *** **
*** * ***** * ** *
* ** * * * *** * *** ** * * ** ** ******* * * * ** * is not a prefix of %s",a,b);
* ** *** ** * *
*** **** *** *** **** 0;
}
answered by (-284 points)
edited by
0 0
prog.c: In function 'main':
prog.c:8:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s %s",&prefix,&word);
             ^
prog.c:8:16: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
     scanf("%s %s",&prefix,&word);
                ^
prog.c:10:15: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     for(i=0;i<strlen(prefix);++i)
               ^~~~~~
prog.c:10:15: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:10:15: note: include '<string.h>' or provide a declaration of 'strlen'
prog.c:18:6: error: expected '(' before 'printf'
      printf("%s is a prefix of %s",prefix,word);
      ^~~~~~
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
#include<string.h>
int main()
{
** ** * * * * ** **** a[100],b[100];
* * * ** * * * ** * * * ** ** **
    int l1,l2;
**** * *** ** ***
* **** ** *** ** *** **
****** * * * *** ** * ** * **
* ** ****** *** *** * ** *** ** * * ** ** * * *** *** is not a prefix of %s",a,b);

    }
* *** * ** *** *** ** * * *** if(l1<=l2){
** * * *** * * ***** *** ** * prefix=1;
** * *** * * ******** ** ** * ** * * * * i=0;
* ** ** * ** ***** * ** * * **** **** * * * * * * ** **
*** ** ** * ** ** *** * * * *** ** **** * * ***** * ** *** * * ** (a[i]!=b[i]){
* ** *** * ******* * ** * ** ** * * ** ***** ** ** ** * * ** ** * * ** *** ** ** * * ** ** *
* *** * * *** * * * * *** * * ** *** *** ********* ** ** * ** *** ** * ** * * *
* *** * ** * * ***** * ** ** ** * ** ** * * * ** ** *


** ** *** ** * * *** ** ** ** * ** * ***** **** *
*** * * * * *** ** * * * * ** * **** * *** *
** * * * *** ****** ** ** ***** ** * * *** ** * *** **** **** ****** * is not a prefix of %s",a,b);
* * ** * * * * ** * *** ** *** ** * *
* * *** * * **** * ** **** * *** *** *
** * * ** * *** ** ****** *** * **** *** * * ** * * * ** is a prefix of %s",a,b);


    }


}
answered by (-329 points)
0 0
prog.c: In function 'main':
prog.c:5:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
             ^
prog.c:5:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
               ^
prog.c:7:8: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     l1=strlen(a);
        ^~~~~~
prog.c:7:8: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:7:8: note: include '<string.h>' or provide a declaration of 'strlen'
0 0
prog.c: In function 'main':
prog.c:6:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
             ^
prog.c:6:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
               ^
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
*** *** ** * **
int main(void)
{

* * **** ****** *** ** * * pre[100];
** ** * * ** * * * * word[100];
** * * ***** ** * ** ** * *** * * * * * * %s",pre,word);
* ** ** * ** ** ** ** * * * * ***
****** * *** * *** * * *** * *****

********* ** * * ** **** **** * i;
* * ** **** ** *** ***** ** * ** * ** ** **
** *** * * **** ** *
* * **** * *** *** ** * * * ***** * * * ********
* * ***** *** * ***** * *** ** * ** * * *
*** * ** *** ** * * *** * * * * ** * * * * * ** * * * ** * *** *** * * * is not a prefix of %s",pre,word);
* *** * * * * * * * * *** * ** ** * * ** * **** * ********* 0;
* **** **** * * * *** * ***** *** * * * ***

*** **** *** * * ** * *
printf("%s is a prefix of %s",pre,word);
return 0;
}
answered by (-249 points)
0 0
prog.c: In function 'main':
prog.c:8:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&pre);
             ^
prog.c:9:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&word);
             ^
0 0
prog.c: In function 'main':
prog.c:8:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&pre);
             ^
prog.c:9:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&word);
             ^
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <string.h>
#include <ctype.h>
int main ()
{
** *** ** * ** * pre [100],a[100];
** ** * * ** n ,i;
* ** **** ** * ** ********* * ** *** ***
** ********** * * * * * ** ** ** * *
** * * * ** ** * ** * * ** * * * ** **
** ***** * ** ** ***** * **
*** * * * * *** * ** * * * ** * * * * ** (n=0;n<strlen(pre);n++)
** * * * *** * * ** ** ***** * ** *** * * ** * * * ** **
* **** ** * * * * ** ** * * * * *********** ** * * * * (pre[n]==a[n])
** * * ** ** * * * **** ** ** * * * *** * *** * *** **** ******** ** ****** is a prefix of %s",pre,a);
****** * * * * ** ***** *** *** ** * * * ** ** * ***** *
* * *** ** ***** * * * ** * * *** * **** *** *** ** * * * * *** * * * * * ****** * * * ** ** is not a prefix of %s",pre,a);return 0;
*** * * * * ** **
* **** **** * *** * * * * * ** * ******* ********** * * * ** * *

** *** **** * *** ** ** *** ** * 0;
}
answered by (-32 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include * ********* **
#include ** ** * * *

int main()
{
** * * * * * * ** * * a[100];

* * * **** ******* *** * * * b[100];

* * * ** *** ** ** * **** %s", a, b);

* ** * **** ** * ** ****** len_a = strlen(a);

* * *** * ** * * * * i = 0;

* *** * * ** * ** ** * * * * flag = 1;

* * ** ** * * * *** * = 0; i < len_a; i++)
** ** * * ** ** *
* ***** * **** * ** * * * * * * ** * != b[i])
*** * *** * * *** *** *** ***
*** * * **** ** * **** * *** *** ** *** * * ** ** * * * * *** * = 0;
* * ** ** *** *** * *** ** * ** *
* * **** * * * * *

*** * * * **** ** *** ** == 0)
* * * ** * * *
******* *** ** * * ** * * *** * * ** * * *** ** * is not a prefix of %s", a, b);
* ** ** * ** * * ** **
* *** * *** *** *** * ** **
* ** * * ** * *
* * * ** ** *** *** *** * ***** *** ******** **** * * * is a prefix of %s", a, b);
* ** * ** ** * * **
** * * * * ***** *** 0;
}
answered by (-285 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
* ****** *** * **
int main()
{
*** * * * *** **** *** ** * i,n;
***** **** **** ** * p[100],s[100],a[100]={};
* * ** * ** **** *** ** ** ** %s",p,s);
* ** ** * * *** * * ****
* **** * ** ** ** * ** *****
* ** * * * ** * * * * ***** * *** * ** ***
** * * * * * * ** ** * ** *
***** *** *** * *** **** *** * * * * * * is a prefix of %s",p,s);
* *** * **** ** *
***** * * * * ** * * **** *
* ** * ** ** * * * * * *** ****** * * * * is not a prefix of %s",p,s);
** * * * * **
* *** * * ** ******* *** ** *** * *****
** * * * * ** ** * 0;
}
answered by (54 points)
edited by
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
#include<string.h>

int main()
{
    int i;
    char a[100];
    char b[100];
* *** * ** *** *** *** * * * * **
    scanf("%s",b);
    for(i=0;i<strlen(a);i++)
** *** * * * * *** **** *** * ** *
** *** * * * ******** * * * ** * * ***** ** *** ** * * *** ** * ** != b[i])
**** *** *** ***** *** ** *** * * * * * * * *** *** ** * * ** * **** * * ** ** * * ** * ***
**** ***** * * ***** ** ** **** * ** * *** * * ** * ** ** * *** **** ** *** ** ************* * ** * * * * ** * * *** is not a prefix of %s",a,b);
** *** **** * * **** * ** * ** * * ** * * * * ** * *** * * ** * * *** * *** * ** ** *** ** *** * ***
* *** ** * ** * * *** * ** **** ** * * ***** **** ** *** ** ** **** ** * ** * **
** *** *** ** * * *** * ** ** ** * ** ** * * ** * * ** * * ** ** * * == b[strlen(a)-1])
* * ** * *** * *** ** *** * * *** *** * * * *** * *** * * ** ** ** ** * * * * ** *
* * ** * * ** *** *** * * * * *** **** * * ** **** * *** ** * ** ** * * * * * ***** * * * *** ** * * ***** ** ***** ** is a prefix of %s",a,b);
* *** ** ***** * * * * * ** ** *** * * * ** * * **** * ** ***** ** * **** * ** ** ****** * * * * **** * **
* ** ***** * **** ** * * ** * **** **** * ** * * **** *** ** * ** * **** * **** ********
** * * * * ***** *** * *** * *** ** *
}
answered by (-301 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
#include<stdlib.h>
#include<string.h>
#define n 100

int aa(char a[],char b[]){
* * * ** * * *** **** i;
* ** * * ** * ** *** *** ** (a[0]!=b[0]){
* **** * **** * * *** *** ** * * ** ***** * *** ** 0;
*** **** ****** *** **
****** * * * * ** ** * * ** *** * ** ** ****
**** ** * * *** * * ** ** * * * ** *** *** * * *** a[i]==b[i])
* ** * * * ** **** ** * * ** * ** * *** ** * **
******* * * * ** ** *** *** * ******* * ** **** ** ** * * * * * ** * 1;
* * ***** *** * * * **** * * * **** * * ** **** ** * *** * * * ****
* **** * *** *** *** * ******* ******
* * * **** * * ** * ****
* *** ** * * ***** *** *** 0;

}

int main(){
* * * *** * ******* * c[n],d[n],e[n];
*** * * * * * * *** i;
** **** * ** * ** * ** *** * %s",c,d);

* * *** * * ** ***
** *** ** * * * * *** * * *** ** * * * *** * * is a prefix of %s",c,d);

** * * ** * *** *****
*** * * ** * * * ***** ** ** * ** * **** * * *** * is not a prefix of %s",c,d);


}
answered by (-32 points)
edited by
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.7.77
©2016-2025

Related questions

1 like 0 dislike
37 answers
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42302 - Available when: 2018-01-17 14:00 - Due to: Unlimited
| 12.7k views
2 like 0 dislike
31 answers
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42301 - Available when: 2018-01-17 14:00 - Due to: Unlimited
| 11.7k views
1 like 0 dislike
32 answers
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42300 - Available when: 2018-01-17 14:00 - Due to: Unlimited
| 13.8k views
2 like 0 dislike
30 answers
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42298 - Available when: 2018-01-17 14:00 - Due to: Unlimited
| 10.4k views
0 like 0 dislike
4 answers
[Exam] asked Jan 19, 2018 in Final Exam
ID: 43460 - Available when: 2018-01-20 09:00 - Due to: Unlimited
| 2.7k views
12,783 questions
183,442 answers
172,219 comments
4,824 users