Final Exam 2 (20%)

1 like 0 dislike
2.3k views

A string p is a prefix of a string s if the leading characters of s are identical to p. For example, "abc" is a prefix of "abcde". Develop a function prefix that checks if a C string p is a prefix of another C string s.

p是s的前綴若s開頭的一段字串等於p。例如，"abc"是"abcde"的前綴。寫一個程式 判斷字串p是否字串s的前綴。

Example input 1:

abc
abcde

Example output 1:

abc is a prefix of abcde

 

Example input 2:

bc
abcde

Example output 2:

bc is not a prefix of abcde

 

[Exam] asked in Final Exam
ID: 42299 - Available when: 2018-01-17 14:00 - Due to: Unlimited
retagged by | 2.3k views

37 Answers

0 like 0 dislike 
Hidden content!
#include       ****   *
#include    * ** * * ***
* * **   * * ** * 
** ****** **   * 

int prefix(char a[], char b[]){
int i, j,n;
int cnt=0;

n=  ***  *  **

* * * *        **  *** *  **  * ** ** *   *
***   **  ***   * *    * * * *   == b[i]){
*****    *** *** **       ** ***  ***   ** *   ***** ** 
    *   * * *  ***  ** * * *  **

  ***** * * *   *
if (cnt == n){
******   **  **** **** ** ***   * *  ****   **** *   * * * * 1;
 ** * *** ** ******** *   *  **  **  *** **    **  *****  ****
 * **  *******  *** *  *   * 
*  *  * ***      * **   * * *** *****  ***   ** **  * ** 0;

}

int main()
{
  **  ** * * *** * s1[100], s2[100];
 **  ******   ** **** i,j;

 *   * ***   * *    *    ***** *   *  ** ** s1);
  *       ** ****  * ***  * * ****    *   *   ** s2);
*** *  **   * *   (prefix(s1, s2)){

 ** ** *      *** * ** ** *   *   **  ** **** *** ** **   is a prefix of %s", s1,s2);
    * ** *   *   ** ***** *   * ** *  *   * ** ** 
*** ** * ***  ***  ***  *****   ** * * *   *    
* * ** * *  * * * **   * **  ** ***  **  * **** *  * *  * **   ** ******   ** *  is not a prefix of %s", s1,s2);



}
answered by (323 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <string.h>

int main(){
    *   * **  * * ** * * *  ** c;
* * ***** **     * **  ** *   *  *  a[100],b[100];
*  **    * * **      * * ** ** *** %s",a,b);
 * * *  * * *****  ** * ***  * **  **   ** * * 
 *   * *  **  * *  *  **** *  *  *      *  * * **** 0;
 **** * **  *  ** **       **  *******  %d",strlen(a),strlen(b));
* *  **   * **** * *  *** ****   **   * *  ***   ***  *
 * * *     *  *  ***  ******* ****    *  ** ** ** ***    ** *  **  ** *   ** * * * *  *** 
** ** *  *  *** **  ****  ** ** *  *****  *   * *  ****   * ***    *  * ****   * *   * * **  *  *   ***** * *   *     ***   ****  is not a prefix of %s",a,b);
    *   **** *   *  *   * **   *  **  *** **   ** ** *     **** *   *    ****** ***   ***   *** *** * *   *** * **  * * * 
   * * **     **  ******  *   * ** ** **  *  * *  * *  *** *  **    ** **  *   * **   
* ** **** *   **  *** * **  ***** * **  * ** **** ***    *   ***   **  ****  if(c==strlen(a)-1)
** *  * * ***  *** *   *   *  *   *** * * * * ****      ** * *    * **** *  ***** ******* *** * ** *   **** ** *  *     *  is a prefix of %s",a,b);
    }
 *  ** *    * **  * *  *****  0;
}
answered by (-498 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <string.h>
int main()
{
  * * *   * **** *      ***   * *     n,count;
 *   ***  *  * *****  *    ** *  **  * *  * **
 ***   *  **   *  * **   ** **  * ** * %s",a,b);
 ********* **  ** *  *  *  * *  *   

* *** * **  *   ***    * * * **  *** * ** **  *
   *  **  ** * * ** *  *  ****
*    *    * ***   * * * ** ***** ** * *    *      *  *****  ** **   * * *
**   **   *  * **  *  *********   

 *** *  *   * ***   **     * ** * (strcmp(a,c)==0)
    *  * ***** ** *    *
***   * * **  ***  * *     **  * *  *   * * *** *    ** * *  is a prefix of %s",a,b);
* *  ** **   *  ** ***      
** ** **       *  * **        
*    *       **   **** ***** *
 * * **  * ** *    *    **   **********  *  * * **    *  *** is not a prefix of %s",a,b);
*** ***** ***  * **  * *  * **  
 ** *  **   ******   ***   * *  0;
}
answered by (-284 points)
edited by
0 0
prog.c: In function 'main':
prog.c:8:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s %s",&prefix,&word);
             ^
prog.c:8:16: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
     scanf("%s %s",&prefix,&word);
                ^
prog.c:10:15: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     for(i=0;i<strlen(prefix);++i)
               ^~~~~~
prog.c:10:15: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:10:15: note: include '<string.h>' or provide a declaration of 'strlen'
prog.c:18:6: error: expected '(' before 'printf'
      printf("%s is a prefix of %s",prefix,word);
      ^~~~~~
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>
int main()
{
   ***  *     *** *** **  ***  a[100],b[100];
* * ** **   ** * **** * *** *****  **  *  *  *  
    int l1,l2;
* ***  *     * * ***  ** *****  ********
  ** ***  * * **  ***** *   ***    *  ****
* * *****      *  **** *  **  *  * * *** 
** **     ***** *  ** * **  **   *   ***  ***** ****** **  *    **    ***    is not a prefix of %s",a,b);

    }
     *      ** * **  *  ****     * if(l1<=l2){
  * *  *    ***** * ** * ** *** * *  *  *      *  *      prefix=1;
* ** ***  *   **  * *     *   *    **** ***  *** *   i=0;
***** ***   * **   *  * *  *   ***  **  * **    ** *  ***** *    ***  * 
   * *     *  *** * ** *   *  * * * *****  ** **** *** ******* *  *****     * ***** ** (a[i]!=b[i]){
* *    *****   *  *  **     * ***** *    *  **    ** ** * ********* **  * *   * **  *  **  ** * *  ***  **    **
* ** **   ****  ** **   * **** *   ** *  ** *  * *  * ** **  ******  * *  ** *** ***  ***     *****  * *  *  * 
* **** * ** *   *** * *  ** *** ** *** ** *** ***      ** * * ** * ** **  * *


*  ***     *** *  ** *  * **  *   **** **** *  *  *  **** 
 * *   **   * * **  * *  **    * * ** **  ** ****** * *
*  ********   ** * *  ****** * *  * * ** *  *  *    ** *  * ****       *** *  * **  ***  is not a prefix of %s",a,b);
  *  *   ***  ***   *****  **** *    *** * **   *
 *   *   * * *  *   * ****   * *  * * ** *  * *  **** *
 *  ** **** * *   ***  *  ** *   **      *   * *  ****  ** **   is a prefix of %s",a,b);


    }


}
answered by (-329 points)
0 0
prog.c: In function 'main':
prog.c:5:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
             ^
prog.c:5:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
               ^
prog.c:7:8: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     l1=strlen(a);
        ^~~~~~
prog.c:7:8: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:7:8: note: include '<string.h>' or provide a declaration of 'strlen'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:6:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
             ^
prog.c:6:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
               ^
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
 *   *   * *  * ** **   *
int main(void)
{

 *    **  *** *  *   * ****  pre[100];
*** * *   * ** ** *** *   *** * * * word[100];
* *  ** ** * ***  * ****  ******  **** %s",pre,word);
*    *    *  *** *  * ****  * *  * * 
 *** ** *  ** **** **     **  ** * * *  ** *    *

*   *** **    ** ***    * * i;
  *** ****  * *** ** *  **  * ***    *  *** *   *
 *** **   ** ***  * ***** *** 
* **** ***  * *** *****  ***  *   *  *  *     **  ** ***** *
 *  **  **  * ** *   * * *   ** *  *** *** ***   * *
 ******  * * *  *** ****** *       **  ** **  * ***      **     ***   ******* *** * **  ***  is not a prefix of %s",pre,word);
*  *****  **** * **** **      *       **   **** * * ***    * ** *** * ** *  * 0;
  **  *** *** * ** **  *  * **** ** ** * *****

 ***  *    ******   ** **  ** **  
printf("%s is a prefix of %s",pre,word);
return 0;
}
answered by (-249 points)
0 0
prog.c: In function 'main':
prog.c:8:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&pre);
             ^
prog.c:9:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&word);
             ^
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&pre);
             ^
prog.c:9:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&word);
             ^
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <string.h>
#include <ctype.h>
int main ()
{
* ***  **     * **  *  **  * *** pre [100],a[100];
 ***    ** *    * *** *     * n ,i;
  *   *    *   **** **  *  ** **  ***  
**  *** **    *     ** ***     * *  **
**   *** ***   **   ** *    *    * **  **  **   *
* ** *** * * ** ***   *  * * ** *
 *   ** **   **  *      ***  * *** * *  **** *** *******  (n=0;n<strlen(pre);n++)
*   ** **   **   ** * ******     **** * ***   * *
** * *****  **** * ** * *  * **** ****     ***** **  *** ****  ** * *   *****  * (pre[n]==a[n])
* * *** *** ***    *  ****     *****  **** ** *  ** * ***    * ** *  * ***** * * * *   **  is a prefix of %s",pre,a);
 *** *   ******* ** * ** * **   **** *** *** *   ***       *  * * *  * ** *  
**  *   *  **   * *       ** *  ****  *   **  *  * *** ** * **    **   ** *        ** * ***   *       **** *** is not a prefix of %s",pre,a);return 0;
** ** ***** **  *****   * *
** * ** * * ********* ***     ****  *  **  ** *  * * *     * *  * * * **** **

*  *   **    * * ** **  ** 0;
}
answered by (-32 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include * ** **   **** 
#include *       ****  ** 

int main()
{
    *  *  ***  *    * *    *   **  *  a[100];

* **** *  ****  *** *  ***   b[100];

**    **    ** * *  ***   ***  %s", a, b);

 *  **** ***  **  *    **  * len_a = strlen(a);

 *** **  * ***   **  **  *      i = 0;

*** ***  * ** * *****       flag = 1;

 ******* ** * * * ***   ** = 0; i < len_a; i++)
*  *** * * ****   *  *     *
*   *  * * ** * ***** *** ***  *** ** ****     *   ***** *   * *   != b[i])
 **  ** *  *   * *  ***  * * **  *  * ** **   *  * * *
* * * ****     **  ** *** * *   *****   ****  * *  **    **    **       * * *   * = 0;
   *     *   ** *   *    *   ***** *  **    **     *  
*   *   ****  ***  *** *

* ****   *   *    ***    * *  == 0)
   *   **  * *   * *  
** *  *  *  * *   ****** *  *      **       * * *** ** *   * * * *  is not a prefix of %s", a, b);
 **  ** * *   *  ** * * * 
* * ** *      *  * * ** * *
* *      *   * *  *  *  
 **     *  *** * ** * *  * *   *   * * * *   * **** *** *    * ** *    *  is a prefix of %s", a, b);
   *  *  * ** *    * * *  *
  **  * *    * *** ** *** *** *  0;
}
answered by (-285 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
*  *    *** * *  ***** 
int main()
{
*      *   *  ******* *  ** * ** i,n;
 * **   **  ****  ** *   **  *    *  p[100],s[100],a[100]={};
 ** *   ** * **   ** *    * *** **  * **** ** %s",p,s);
* *  **  **  * ****** ** *    ** *
  *  ***     **** *** **  **   ***    
  * * * *****  **  ** * **  *   * *      * ** ****** *
****  * ***    *    *  **    ** ** * ** *
 *  ***  **  * *    ***      *****  * ***  * ***   **** * *  * ***    ****  is a prefix of %s",p,s);
* *** * * **  * *  *  * 
*    ******     *      * * 
  ****** ** **  ** *  *    *  **   *** * ** ** **  *    * ** ******  **  is not a prefix of %s",p,s);
  *** **   **** **     **  
 **   ****    **** **  **  ******* * *    *** ****   **   *  
**   *  *   *    *     *   * 0;
}
answered by (54 points)
edited by
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>

int main()
{
    int i;
    char a[100];
    char b[100];
*** * * ** *** *** *      * *  * * *     ****
    scanf("%s",b);
    for(i=0;i<strlen(a);i++)
 *   ***  **** ** **** **   * **  *****  ****** * * *
  ****  * ** * **      * **    *  ** *   ** **   **   * *  *  ** * *  ** *****   != b[i])
 **** ** ***  ** **  * ** *  **   *** *    **   *** ** * ** ****   ***   * * **    ** **  *** ** ** * *   * **
 * *  ** *** *    *** *  * * *   ** ****  ****** *** * *  * ***  * ****** * *** *****  **** ***  *      *  ***** **   * **** **** *  * * * ****  * **  ** * * is not a prefix of %s",a,b);
   ** **  * ** ***** ***    * *** ****** * * * ***    * ****** * *  *    * **  *** ***** * * * * ** **  ***  ***  * * ** ** ** *** ***  **  
*****    **** * *    **  * * *   *  *** ** ** *****     *  * **  ** ** * * *  ** ** ********** *    **   *
 ***  *  * ** *   *  *   ** *** ** *     * * * ** **     ** **    *      *     * ***  *** *  == b[strlen(a)-1])
 * ** * * ** *      * *** *  *  ******** * **  *** **   ** *         *   ****     **** **  *  * * *  * * *  ***
    *  * *   * *  **** *   * * * ** * ** ** **            *** * ** ***  ** *  *  *   ******   *   ** *  * * *  * * * **       * **    * * *  **  *** *** is a prefix of %s",a,b);
** ****** * ****  *       **    *** **  ********* * **** * *    *** *      *** *** *** *  **** *  **  * *  * *  *  * ** * *  ** * *  *
** **        * * *   ** **  *  *****   *  *      *  **  ***   ** *  * * ** *         ** * **** ****  ****  ***  
 ** *  * * *** * * **** *** *  *  * *     ***  **    ***
}
answered by (-301 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<stdlib.h>
#include<string.h>
#define n 100

int aa(char a[],char b[]){
          **  *****  * * *   *    * i;
 * * * *** * * *   * *  * *** ** * *** (a[0]!=b[0]){
***     *     * * **  **    *  *****  **    **** ***   0;
 * *   **  *  *    *** *   *     **** 
    ** *   * ** ***  *****  * *****  * ***  *  * ***
* *  *  **  **  **  *      **  ** * ** **** ***  ** **  **** *   *  a[i]==b[i])
** *  *** * *   ***   *  *     **   **      *  
 ***  **   ****   *      ** ***   ** * *   **** * *  ******     **  *** *** ******* 1;
 * * *** **  *  * * * *****   * **  ***   *** **** * **   **** **  *   * *  **  * *    
  **   ***  ******    *  ** * *    ** **      ** ** *  * * * *  * 
 **  * * *  * *   **  ** * ** * 
***  ******* * *   **** ***  *  * 0;

}

int main(){
 * ***** *  *** *   **    **** ** c[n],d[n],e[n];
 * *  ** **      *     **  * *  i;
  * *  *** ***     ***   *  * * * *        %s",c,d);

*   ****  *     ** * *   ***  *  *
 *  ***  * * *   *** * *  * * *  ***    ***  * ** * * * ** is a prefix of %s",c,d);

** ***    *  **  * *  * ***  *  **
***  * * * * ** *  ** *   ***  ******** *  **** *  * ** ***** *  is not a prefix of %s",c,d);


}
answered by (-32 points)
edited by
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.6.47
©2016-2024

Related questions

1 like 0 dislike
37 answers
Final Exam 5 (20%)
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42302 - Available when: 2018-01-17 14:00 - Due to: Unlimited | 1.9k views
2 like 0 dislike
31 answers
Final Exam 4 (20%)
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42301 - Available when: 2018-01-17 14:00 - Due to: Unlimited | 1.9k views
1 like 0 dislike
32 answers
Final Exam 3 (20%)
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42300 - Available when: 2018-01-17 14:00 - Due to: Unlimited | 2.1k views
2 like 0 dislike
30 answers
Final Exam 1 (20%)
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42298 - Available when: 2018-01-17 14:00 - Due to: Unlimited | 1.6k views
0 like 0 dislike
4 answers
[Makeup] Final Exam 2 (20%)
[Exam] asked Jan 19, 2018 in Final Exam
ID: 43460 - Available when: 2018-01-20 09:00 - Due to: Unlimited | 466 views
12,783 questions
183,443 answers
172,219 comments
4,824 users