Final Exam 2 (20%)

1 like 0 dislike
6.8k views

A string p is a prefix of a string s if the leading characters of s are identical to p. For example, "abc" is a prefix of "abcde". Develop a function prefix that checks if a C string p is a prefix of another C string s.

p是s的前綴若s開頭的一段字串等於p。例如，"abc"是"abcde"的前綴。寫一個程式 判斷字串p是否字串s的前綴。

Example input 1:

abc
abcde

Example output 1:

abc is a prefix of abcde

 

Example input 2:

bc
abcde

Example output 2:

bc is not a prefix of abcde

 

[Exam] asked in Final Exam
ID: 42299 - Available when: 2018-01-17 14:00 - Due to: Unlimited
retagged by | 6.8k views

37 Answers

0 like 0 dislike 
Hidden content!
#include  * ***  ***   
#include *  **  * * * *
** *  **  *  * ** **
* *** **   ** * 

int prefix(char a[], char b[]){
int i, j,n;
int cnt=0;

n= ** *  * * *  *    

** *    *   ** ***   * *  **  ** ***  *
 * *** **   *   * * *****  * *** * * == b[i]){
*        ** **  * ** *** * *  * * *  *  * *    **  * ***  *  * *
 ** * *** ***   **   ** * 

*    * *** *** * ***  * ** 
if (cnt == n){
 ** * **   ** *  ** ******  ***   * *   * *****  ****   *  1;
   **** ** * * ***    *  **  ***  *******   ***
 *   ******   *    ***   **    * *   
* * ****    ***     **  **********   *  ***  ** ** * *   *** 0;

}

int main()
{
   *  * ********* *    * s1[100], s2[100];
*  * ** *** ** *  *     i,j;

 *  ** *  * ***** ***    **   *      *** **** s1);
* *      *    **     * *** * *   ** ** ********   s2);
*  * **  ** **  ***   (prefix(s1, s2)){

**** *    **   ** * **   *****   ***   *  **** * ***   ****   is a prefix of %s", s1,s2);
 **     *  ***      ** * * * *** *** * **** 
   ** **** ** ** **    **   *** *  ***** ***
  **     ** ****     ***   *  ** * **  **   ***     ** **** * *  * *   **  * *  is not a prefix of %s", s1,s2);



}
answered by (323 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <string.h>

int main(){
 ** *    *         ** * **  * c;
* **********    * * *** *    * * a[100],b[100];
       *   * * ** * **   *   * ** *    * * %s",a,b);
 *** ***   **   *  **   *  * **     *     *   
*  ** *****    * *    **  * *** *** *   * * *  *****   0;
* *  *    *** **    **   *** *  *  *  **** %d",strlen(a),strlen(b));
* *  * ******  * * *   *  * *     **  *   *  ****** 
  ***  ** ** * *  * *** * * *  **   *** *      ***  ******* *  *  *  **   *   *****   
*** * ** *     ***   * **    **  * * ***    *   ** ** **  *  ** *  ***  **    * *** **** *** *   * **** *  ***   * * **** is not a prefix of %s",a,b);
*   ***   * *    * **  *** * * * * ***  **    ****    ***** ****     *     * **  *   **    *   ******* **  
 **  ** * ***** *  * *  *  ***  *    ***** **** *  *  ****** * *
*      *     ***  * **   *******     *** * * * *    **  *  *  **    *   *********  * if(c==strlen(a)-1)
  * *  ****** * ****   ***  * ** *  ****  ** * ****           ** * *  *      *   ***  * *  * **  *  **  *  *  *  *    * is a prefix of %s",a,b);
    }
*********  ***   ***  **  ** 0;
}
answered by (-498 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <string.h>
int main()
{
*  *** * **   ***  **  *** ** n,count;
 ***   **    *  ** **** *** *   *** **      ***    *  
** ****  **** *** **  **    *********** %s",a,b);
   *** *  ***    * **    ***** * *  

 * * **** *** * **  *  ****   ** **** ******          **** 
*        **  ** *** ** *  *
   ** *  * * ******* *  ** **      ** ****       * *   *    ***  * *   *
 *  *     *  *  ***  **

 **   ** ***        *   * *   (strcmp(a,c)==0)
***  **** **** *  **  ** **
 *****         * **  **** **** *  * * ***     ****   **** * *     *    is a prefix of %s",a,b);
  * *    *  * ** * *  *  * *
**      *    ****  ***** * ***
*** **  *     **    
**  * * **  ****  * ** ***  ***** **  ** **    * **         **      *    is not a prefix of %s",a,b);
  ** ** *   * * * * *  ** *   ** 
**** *** ****  ****** *   0;
}
answered by (-284 points)
edited by
0 0
prog.c: In function 'main':
prog.c:8:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s %s",&prefix,&word);
             ^
prog.c:8:16: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
     scanf("%s %s",&prefix,&word);
                ^
prog.c:10:15: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     for(i=0;i<strlen(prefix);++i)
               ^~~~~~
prog.c:10:15: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:10:15: note: include '<string.h>' or provide a declaration of 'strlen'
prog.c:18:6: error: expected '(' before 'printf'
      printf("%s is a prefix of %s",prefix,word);
      ^~~~~~
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>
int main()
{
   * * **    ** **   * * a[100],b[100];
 **  * ***  ***   *** ** * *     *** ***** *  * *  
    int l1,l2;
*  ***  **** *** ** * **  * * **   ** *
  *  *   *   *** *   * *****  ** *    * 
 * *  *   **   ***  *  * ** * *** ** ** * * 
* * *   **** *  *  * ** * **** *   *    * *    * * *   **   *** *   *** is not a prefix of %s",a,b);

    }
   **  * *** *   **   ****   * if(l1<=l2){
**  **     *  ** * * *  **   ** *   ** * ** *     ******  prefix=1;
  * * ** ** * * * *  *  **  ** **  **** ** ****   * *      i=0;
 ***  *  ** *** ***    * *  ** **** * *** * ** *** * ** *** *   * *     * * 
**  *  *   ***  *         ***** ******* ***  ** *** ** **    *  *    **  ** ** (a[i]!=b[i]){
*      * * * *  **  *  *     * * ** * *****  **  *     * **   *** ***  *  ** *    **** ** *********  * *  *  ** *   * 
    * *  **  ***** *   **    **        * *** **** **   * * *      *** *  **** * *  *    *  **   *  
**    * **    ***  **   *** *** *  ** ***** ** * ** *  *  *   ***   *    *   * * * * 


 *  * *    *  *      **** * *   *** * *** * **  * * *    
  *   ** ** **   ** *   ***  *   ** **  *       *  * *  *   **  ***
  ***  **    *  **   ** **** *  *  **    * *** * * *  *** ****  * **  **** * ** *   * **** ** is not a prefix of %s",a,b);
   *** ***     *  **   ***   ***  * ***  *  *    ****  * 
**  ****  **** * *     * *   ***   **    ****** * **   *
 ** *****   ** *  *   * *  * *  **    *    **     * * *** **** *  * is a prefix of %s",a,b);


    }


}
answered by (-329 points)
0 0
prog.c: In function 'main':
prog.c:5:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
             ^
prog.c:5:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
               ^
prog.c:7:8: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     l1=strlen(a);
        ^~~~~~
prog.c:7:8: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:7:8: note: include '<string.h>' or provide a declaration of 'strlen'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:6:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
             ^
prog.c:6:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
               ^
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
*** **   * ******    
int main(void)
{

  ** **** ***   * *   * **** ** pre[100];
* * *** *    ****  *  *  word[100];
   * * ***  * *   *  **    *   **** *  ***  %s",pre,word);
 * *  * * ****   * *  *****   * ***   ****
 ***** * **     *    ** ** ** * ***    * 

  * *  * **   * **  * * ** i;
  ******    *** *  *** * *     ****     *  ***
*** *** ****   * * *  *  *  *
  *****  * ****** ** *** *   *  * **** *  ***    *** * ** *  * 
 *   *   ******    *** * *    * *   ****  * **       * 
  **   * **    * **** ***** ** * *** ** ** * ** **  * * **       ** **** * *  ** *** *** * **     is not a prefix of %s",pre,word);
*** *** * *** ****   * ** *    *   *** ****   ***    *   ***** ** *** * *   ****    0;
 ***  * ****   * *   *********   * *   * ** ** * * *   *  

 **  **   * ** **** **    * * **
printf("%s is a prefix of %s",pre,word);
return 0;
}
answered by (-249 points)
0 0
prog.c: In function 'main':
prog.c:8:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&pre);
             ^
prog.c:9:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&word);
             ^
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&pre);
             ^
prog.c:9:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&word);
             ^
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <string.h>
#include <ctype.h>
int main ()
{
  *  **  *   **    ** **   * *  pre [100],a[100];
 * * **     *** * *  *  **  *  n ,i;
  * **  *  **   **   ** **     *  ***  * **
*   ** *  * * ***  ***  *  ***  * *   * * 
*** * *  ** * *****    ***   *     *     * * *** *** ** **
 ** * **   *     ** *  * * 
* * * **  *    *   *  ** *   *** * *  **  **  * *** * *  ** *  (n=0;n<strlen(pre);n++)
 **  **   * * * ** * *     *** * * ***  *   
*** * * *** * ** * ** * ** *  *  *  *** ** * *****  *   *  *****  * ** ** *  *** * (pre[n]==a[n])
   *   *     *  ** *    *  **    * *** ****    **  *******   *******  *** * ** * *    **  is a prefix of %s",pre,a);
 ***    * *   * * * **   *  *** * *       **   *  *  **** ***** ******   ** *   * 
*  **   * *  **  ****        ***   *  ** **  *  *** ***     *  ****  *  ** *** **  * **   ***  **** ***  ** * **  ** * is not a prefix of %s",pre,a);return 0;
* ** * * ** *** *****   *   * *
* * * * *  *  * ** **  ***   ***** **  ** ***** *  *  **** ** ** **       

***** ****  * *   * *  *  0;
}
answered by (-32 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include   * ****   ***
#include ********* **   **

int main()
{
 ** ***   **    *   *   * *   * a[100];

 *   ** *   ***       **   *    * b[100];

*     ** **  **** *  ***    ****** ***** %s", a, b);

* *  **       *****   * *   * * *** len_a = strlen(a);

  *  ** **** *** *  **  ****  i = 0;

** * *  * ** *  *** * * **** ** flag = 1;

*  * ** ** ** *** * * *  * ** = 0; i < len_a; i++)
 ***      ****  ***   * 
******** * *** *   *  ****** **  * * ******   * * *  ****  ***** != b[i])
** ** **  * *  *      ** *    * * *  * ** *     **
 ** * **   *** **   * * * ** ***   ** ** * ** * *   *     * * * **  * ** ****  *   = 0;
**  *  *** **    ** ** ****     **  **  **   ** *
   *** **** *  * **   * 

  **  *   ****  * *    ****  ** == 0)
** * ** * **   * * *  
 **   ** **  ***     ** *   * * * *    ******  ******    *   *   *  * is not a prefix of %s", a, b);
*** * *   *   *  *       *
  * *  * ***    ****  *** ***** *
**** * **     * * * *  ***
  ***   **   *** *  *   *   **  * ****   ***    **  *    ** * **  * * is a prefix of %s", a, b);
*   * * *  * ** * *   * 
 ****** * **** * ** ** ** ** * 0;
}
answered by (-285 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
    ** *** *   * ** 
int main()
{
*  * ****  ****  **** *  *  i,n;
*  ** *      * * *** ** **** * p[100],s[100],a[100]={};
  **      *   *** * * * *  *  ** * **   %s",p,s);
   ** *   * * **   **  **    *  ** **  
  ** * *    ** * * * ** *  * * ****** * *
 **  ** *** * ** *   *** *** *    * **     ** * * 
 * **      ****   *  ** **    *   ** *
  *  **   * * *** ***** * * * *   ***  * ********* ****   * **   is a prefix of %s",p,s);
**  *  ****  * **  ***** *
 *  *  ** * **   **  *****  ***  ** 
  *   * ** **  *  * * ***  *    *  * ** ****** ** *****   *   is not a prefix of %s",p,s);
 **   *      *  *  * *   
*** *  **   * **  *** *   *  *  *** *  *  * **   * *   ** 
* ***  ***  * * *** ***    *  0;
}
answered by (54 points)
edited by
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>

int main()
{
    int i;
    char a[100];
    char b[100];
* *  ** ** *  ******  * *  *  *   ** * ***       
    scanf("%s",b);
    for(i=0;i<strlen(a);i++)
* * **** * *** * *   * **** ***** *    * ** *** 
***      *  *** * *  * ****  * *   *** *  *****     * * ******     ***   *  * *   != b[i])
   *   * *   *  * *****   * ****  *  *      *******  *** * **    *  * ** * * * ** **  ****    * ** *** **    *** ***
* * *******  * * *  ** *  * * **    ****  *  ****   * **  *  * * ****   * *    ** *** ** **  *****    * ** *  *  * *  **  ** ****  ** *  *  *  *      is not a prefix of %s",a,b);
**  *   *  * **    * **  * ***  *  *** *** ***    **** **  * * * ** **   **     *  **   * *  * * *** **  * **  * *   *  **  *****  *** ** *
  *** * * **  ***    * * **** **   * *********  **  * *** ****   ***   **  *  * **   *  *  *     ** ** ***** 
 *  *   * **  * ** *  *******     ** **  *    * * *  *  * ** **   ****  *** * * * *** * **** == b[strlen(a)-1])
 *  ** *****     *        ***   ** * **     * *  **  * ***    **** *   *** * ***** * ** * * *  *  * * * * * *  
 **   *  *     **  *  ****   *     **    ****  ** ****  ***     *  ** *    ***   * **  ** * *  * ** ** *  *    ** **   * *  * * * **** *   ******  * is a prefix of %s",a,b);
 ** ***  ****   *   ** * * ** * **    * ** *  ***  *  *  *   * **  ** *******  ** **** **   ***   *   *    *  **    * *  ***    *** *
    * * ** * **  ** *    **** ****    **    ** *  *  * ****   *   ** **** ** * *  **   ** * ***
*   ** **   **** * ***  * ***  ** ** *   ****  ***   *   **
}
answered by (-301 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<stdlib.h>
#include<string.h>
#define n 100

int aa(char a[],char b[]){
 *  * *   ****  *** ***** ***** ***  i;
**  *  *  * * *  **  ***** * **  ** (a[0]!=b[0]){
 *** **  * *  **  *    * * *****  *** ** * ***** *  **  0;
*** * * ** * ***  ***  *   *   *  
*  ** *   * * * *  **** *  * * *** *  ***  *
 * ***** * * *** ***  *    *    ***   ** *   **** *      **  *   **  * a[i]==b[i])
 **   *   * ** *   * **  *** ***  **    * *      * *  *
 **  * *  ***** **   *** * *  * * * * ** *  **  ***    * *  *   ** **  **  *** * * ***   1;
  *    * * *    *  **  **** ***  * ** ****   * *     *  * ** **** *  ***    ** **********  
* ** *  *      * *******     ***** ** ***** *****  
* * * * * * *    *  * * *   *   *  ** 
 * * ****** * ** **      *  * ***      0;

}

int main(){
*    ** *****  ***     ***   ***  ** c[n],d[n],e[n];
   *   *** *** * ****** ***   * i;
******* ** ***  **    ***      **   %s",c,d);

 **  ** **  ****   * * *** *   * **  *
 ****  *** *     **   ** *  *   **  ***  * ** * ** **       *  *** is a prefix of %s",c,d);

  ** **  **       *  *** *
 * * **      *** ** * **  **  **     **       ** *    * *  is not a prefix of %s",c,d);


}
answered by (-32 points)
edited by
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.127.194
©2016-2025

Related questions

1 like 0 dislike
37 answers
Final Exam 5 (20%)
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42302 - Available when: 2018-01-17 14:00 - Due to: Unlimited | 7.1k views
2 like 0 dislike
31 answers
Final Exam 4 (20%)
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42301 - Available when: 2018-01-17 14:00 - Due to: Unlimited | 6.1k views
1 like 0 dislike
32 answers
Final Exam 3 (20%)
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42300 - Available when: 2018-01-17 14:00 - Due to: Unlimited | 7k views
2 like 0 dislike
30 answers
Final Exam 1 (20%)
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42298 - Available when: 2018-01-17 14:00 - Due to: Unlimited | 5.3k views
0 like 0 dislike
4 answers
[Makeup] Final Exam 2 (20%)
[Exam] asked Jan 19, 2018 in Final Exam
ID: 43460 - Available when: 2018-01-20 09:00 - Due to: Unlimited | 1.3k views
12,783 questions
183,442 answers
172,219 comments
4,824 users