1 like 0 dislike
2.4k views

A string p is a prefix of a string s if the leading characters of s are identical to p. For example, "abc" is a prefix of "abcde". Develop a function prefix that checks if a C string p is a prefix of another C string s.

p是s的前綴若s開頭的一段字串等於p。例如,"abc"是"abcde"的前綴。寫一個程式 判斷字串p是否字串s的前綴。

Example input 1:

abc
abcde

Example output 1:

abc is a prefix of abcde

 

Example input 2:

bc
abcde

Example output 2:

bc is not a prefix of abcde

 

[Exam] asked in Final Exam
ID: 42299 - Available when: 2018-01-17 14:00 - Due to: Unlimited

retagged by | 2.4k views

37 Answers

0 like 0 dislike
Hidden content!
#include * * ***** ** **
#include ** ** ** * ***
* ** ** * *
****** **

int prefix(char a[], char b[]){
int i, j,n;
int cnt=0;

n= * * *** *

* ***** * *** *** *
** * *** * *** * *** ***** *** * == b[i]){
* * * * ** * ** ** * * * ** *** * ** * **
* * * * * * *** * *

*** * *** * **
if (cnt == n){
*** * **** *** * ********* *** * *** * * * 1;
** ****** * **** ** * * * **** * * * ***
* ** **** * ** ** * * *
*** * ******* *** ** * * * ** * * * * * * * 0;

}

int main()
{
*** * *** * *** * s1[100], s2[100];
* * * * * * * ** i,j;

*** * *** * * **** * * * * ** s1);
*** * ***** * *** ** ** * ****** * ** **** s2);
* * * * *** ***** (prefix(s1, s2)){

* ** * * * ** ***** ** * ** * * ** * * * is a prefix of %s", s1,s2);
*** * ** * * ** * * * * *
* * * *** * * * * ** **** * * * * * *
** *** * ** ** * * ***** * * * * * * ** ** * ** ** * * * **** is not a prefix of %s", s1,s2);



}
answered by (323 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <string.h>

int main(){
** ** * *** ** ** * * c;
** ***** **** * ********* a[100],b[100];
* * * * *** * * * ** ****** %s",a,b);
*** * * ** * * * * ** *** * ** * *
* * * *** ** * ** * *** * * * * * * ** 0;
* * *** * ** ******* * ** %d",strlen(a),strlen(b));
** ** *** * * ** *** ** *
****** * * ** ** *** * *** ** * ** * ** ** ** ** * *** *** *
* *** ****** * ** * *** * ***** ** * *** * * * ** *** * * ** * * * * * ** * * * * * is not a prefix of %s",a,b);
* * **** ************ ****** * *** *** * * * * * **** ***** * ** * * *** * ****** * **** * *** *
* **** ** **** * **** *** **** *** * * * ******** *** ** *** * ** *
**** * **** *** ***** * ** * * * * * * * * * * * ****** * * ** * ** if(c==strlen(a)-1)
** ** * * ******* *** * ** **** ** * *** *** ** *** * * * ** * * *** * ***** * ******* * * is a prefix of %s",a,b);
    }
* * * * * * * **** * * ** 0;
}
answered by (-498 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <string.h>
int main()
{
* * * *** * * ** n,count;
** ** ** * * * ** * * ** ** ** * *
* ** ** *** * ** * ** %s",a,b);
* * * * *** * * * ** ** ** * ** *

* * * **** ** * ** ** * ** * * ** ** * * * * ***
*** ** ***
****** * ** ** * * ** * * ******* *** * * *** ** * *
* *** * *** ********

* * * * * ** **** ****** (strcmp(a,c)==0)
* ** * ** * ** ** *
* * * * **** **** *** * *** ** * ****** ***** is a prefix of %s",a,b);
** * * * * * *** * ***
* *** * *** * * * *
** * **** * * * *
* *** * * **** ** *** ** ****** ***** *** **** is not a prefix of %s",a,b);
* * ***** * * **
* * * * * * ** *** *** 0;
}
answered by (-284 points)
edited by
0 0
prog.c: In function 'main':
prog.c:8:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s %s",&prefix,&word);
             ^
prog.c:8:16: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
     scanf("%s %s",&prefix,&word);
                ^
prog.c:10:15: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     for(i=0;i<strlen(prefix);++i)
               ^~~~~~
prog.c:10:15: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:10:15: note: include '<string.h>' or provide a declaration of 'strlen'
prog.c:18:6: error: expected '(' before 'printf'
      printf("%s is a prefix of %s",prefix,word);
      ^~~~~~
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
#include<string.h>
int main()
{
** ** * *** ** *** * * ** * a[100],b[100];
* **** * ** ** ** * ** * *** ** * * *
    int l1,l2;
* * ** * * * * ** * **** *
* ** ** ** * ** ** **
** ******* ** *** * * *** ** ***
** * * * * * ** * * ** * * * * *** ** * ** ** ** is not a prefix of %s",a,b);

    }
*** ** **** * ** * if(l1<=l2){
*** * ** * * ** * * * **** * * ** *** * * * prefix=1;
* **** * **** * * ** * ** ** *** ** * i=0;
** **** ** ** * * * ** * * * *** * ** * *** ***** *
***** *** * * *** * * * * *** ** **** ** * ** *** * (a[i]!=b[i]){
*** * ** *** * **** * * ** ** * * *** * ** * * ** *** * * * *** * ** * ** **** *
* ** *** **** * * *** * * * * *** ** *** *** * ** * * * * * * * *** ** * ** * ** ** *** *
**** * * ** ***** ** *** * * * **** ****** **** ** ** *** * ** * * *


** * *** ** * * *** ** ** * ** ** * * * ***** * * ***
****** ** *** * *** *** ** * * * * * **** * ** * * ** * ***
****** *** * **** *** * * ** * * ** * *** **** * * *** ** * *** ** ** * * is not a prefix of %s",a,b);
* ***** *** **** * * **** * * **** *
* ***** * ** * ** * * ** ** *** **
* * *** * ** ** **** * * ** ** * * **** ** * * * * is a prefix of %s",a,b);


    }


}
answered by (-329 points)
0 0
prog.c: In function 'main':
prog.c:5:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
             ^
prog.c:5:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
               ^
prog.c:7:8: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     l1=strlen(a);
        ^~~~~~
prog.c:7:8: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:7:8: note: include '<string.h>' or provide a declaration of 'strlen'
0 0
prog.c: In function 'main':
prog.c:6:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
             ^
prog.c:6:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
               ^
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
** ** * ** * **
int main(void)
{

* ** *** * * * * ** * * * pre[100];
** * * *** * *** ** word[100];
***** * ** ** *** * * ***** *** ** %s",pre,word);
** *** *** *** * *** * * * * **
** * ******** **** * ** **

* * * **** ** * ** ** * ** * i;
** * * ****** *** * * *** * ** ****
* * * * ** * **** *
* * * * ** * * ** * **** **** ** *** * ** ** * *
* * *** *** * * ** * * * * * *** * * **
** ** *** ** *** * * *** ** * * * * *** * * ** ****** * ** ***** is not a prefix of %s",pre,word);
* * ** * * *** ** * * * ** *** * * * * ***** * * **** * ** * * 0;
*** ****** ** * * * * * *** * * * * *

**** * ** ** ** **** * * *
printf("%s is a prefix of %s",pre,word);
return 0;
}
answered by (-249 points)
0 0
prog.c: In function 'main':
prog.c:8:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&pre);
             ^
prog.c:9:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&word);
             ^
0 0
prog.c: In function 'main':
prog.c:8:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&pre);
             ^
prog.c:9:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&word);
             ^
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <string.h>
#include <ctype.h>
int main ()
{
*** ** ** * *** ** * **** pre [100],a[100];
**** * * ** * * ** * n ,i;
** * * ****** * * ** ** * *** *** *
******** *** * *** ** * * * *
*** ** * ** * ** * * ** * ***** ** ** * *
* * * ** *** * * *
** * *** * ** * * * ** *** * * ** *** * ****** (n=0;n<strlen(pre);n++)
*** * ** * ** *** **** ** ** ** ** *
** ** * ** * * * ** ** ***** * ******* *** ** *** ** (pre[n]==a[n])
* * *** ** *** ** * **** * * * * ********* * ** * ****** **** * ** *** * * is a prefix of %s",pre,a);
*** *** * *** *** * * * * ** ** *** * ** * *** * *** *** ** **
**** ** * **** ** ****** ** * ** ** ** ** * * * * ** ** **** * ** **** **** ** * ** is not a prefix of %s",pre,a);return 0;
** ** * * ** * * * * *
** * * ** * ** * ** ** * * * * * ** * * * **** * *** *** *

***** * * *** ** * 0;
}
answered by (-32 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include ** ** * * *
#include **** *

int main()
{
* * * * * ** ** * * *** a[100];

* *** * * * * * b[100];

* * * ** * ***** * * * * %s", a, b);

** * * ** * * ** ***** len_a = strlen(a);

***** **** * * *** ** i = 0;

* ** *** * * * ** flag = 1;

* * ** * *** ** = 0; i < len_a; i++)
* * * * ** * *
* ** ** ** * * ** * ** * ****** *** ***** ** * != b[i])
* ** ** ** *** * **** ***** ** ***** * **
** **** ** *** ******* * * * **** * * * * *** ** ** = 0;
* *** * **** * ****** * *** ** ** **
* ** * * * ** ** **** *

* ** * * * * ** * * ** * * == 0)
** ** * ** ** *** *
* ** * * * * ** ** ** ** *** ** * **** * * * ****** is not a prefix of %s", a, b);
** * *** * ******** **** *
** * * * * ** **** *
* ** * ***** * * *
* * ***** * ** *** * ******* ** * * **** * * ***** **** * is a prefix of %s", a, b);
**** *** ** * *** ***
*** * * * * * ** *** * * 0;
}
answered by (-285 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
* ** *** *** ** ** *
int main()
{
** * ** * ** * *** * i,n;
** * *** ** * **** * p[100],s[100],a[100]={};
** * ** * * ** ** * * * * ** %s",p,s);
*** * * ** **** **** *** ****
*** * ** * * * **** ** **** *
* ** * * * ** **** * * * ** * **
* * ** * *** * *** ***** ***** ***
* *** ** ** *** ** * ***** ******* ** * ** ***** ** * is a prefix of %s",p,s);
* ** ** * ***** ***
** **** *** * * **** ** *** * *
** * * *** **** * ** * ** *** ***** * ** ***** * *** * is not a prefix of %s",p,s);
* * *** ***** * * **
** * * *** ** *** ** * * * ** * ** ** *
********* ** ** * ** * *** 0;
}
answered by (54 points)
edited by
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
#include<string.h>

int main()
{
    int i;
    char a[100];
    char b[100];
**** ** * ** * ** * * ** * ** * *
    scanf("%s",b);
    for(i=0;i<strlen(a);i++)
** * * ** ** * ** *** ** * * * ** ** ** **
** *** * ** *** ** ** * *** ** ** * ** *** ** ****** * *** * * ** * != b[i])
* * *** **** * * ****** * * **** * ** * * * ***** * * ** **** *** ******** **
** *** *** * *** * * ***** ** * *** ** * * ** * * ** * * * * *** ***** * ** ** ** ****** * ** *** * * * ** * is not a prefix of %s",a,b);
*** * ** ************ * ** ** ** * * *** * ** * * *** * * * ** ** ** ** ** ** *** * ***** ** ** ** * *
* * ** ** **** * * * * * *** * **** ** * ***** * * *** * * ** ** **** *
** ** * * * * *** * ** ** **** ** *** * ** ** **** **** * **** ** == b[strlen(a)-1])
** * *** * * * **** * * * ** * **** * *** **** **** ** ** * **** ** * * * ** * *** *
** ** * * ** * ****** * ***** * * ****** * * ** * **** * * ** * * ** * * ** *** * ** ***** ***** * ** * ** ** is a prefix of %s",a,b);
* ** * *** ** * ** * * * * *** ** ****** *** ** ** * ** * * *** ** **** ** * * * *** ** ** * ** **** ** *
* *** ** * ** *** * * ** *** * ******* ** * * ** * * * * ** *** * ** *
* * * * ** * ** ** **** * * * **
}
answered by (-301 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
#include<stdlib.h>
#include<string.h>
#define n 100

int aa(char a[],char b[]){
*** *** ** ** ****** ** i;
* ****** *** * * *** * * * (a[0]!=b[0]){
* * * ** *** * ** ** *** ******** * * * * * 0;
* *** ******* **** ***** *
* * **** * * **** ** * ** ** ** ** *
* *** * *** ** *** * *** * ****** * * *** ** **** ** a[i]==b[i])
* ***** ** * * * ** * * ** **** * * * * * ** *
* **** *** ** * * * ** *** * * * * ** * ** * * *** ** * * * * ** 1;
* * * * * ******* * * * *** **** * * * * *** * **** ** ** *
* * ******* *** **** ** * *** * * ** *** **
** * * * ** **** ** ** * * **
* ** **** * * * * * *** * 0;

}

int main(){
** * * ** ** ** *** * * c[n],d[n],e[n];
* * * *** * ** i;
**** * * ** ***** * * * ** * ** %s",c,d);

* ** * ******* * * * * **
* ** ** * * * * * * * * * * *** ****** ** **** * ** * is a prefix of %s",c,d);

**** ** *** * ** * *
** ** * * *** ** **** * * * **** * *** ** *** * * is not a prefix of %s",c,d);


}
answered by (-32 points)
edited by
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.126.199
©2016-2024

Related questions

1 like 0 dislike
37 answers
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42302 - Available when: 2018-01-17 14:00 - Due to: Unlimited
| 2k views
2 like 0 dislike
31 answers
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42301 - Available when: 2018-01-17 14:00 - Due to: Unlimited
| 2k views
1 like 0 dislike
32 answers
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42300 - Available when: 2018-01-17 14:00 - Due to: Unlimited
| 2.3k views
2 like 0 dislike
30 answers
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42298 - Available when: 2018-01-17 14:00 - Due to: Unlimited
| 1.7k views
0 like 0 dislike
4 answers
[Exam] asked Jan 19, 2018 in Final Exam
ID: 43460 - Available when: 2018-01-20 09:00 - Due to: Unlimited
| 468 views
12,783 questions
183,443 answers
172,219 comments
4,824 users