1 like 0 dislike
17.5k views

A string p is a prefix of a string s if the leading characters of s are identical to p. For example, "abc" is a prefix of "abcde". Develop a function prefix that checks if a C string p is a prefix of another C string s.

p是s的前綴若s開頭的一段字串等於p。例如,"abc"是"abcde"的前綴。寫一個程式 判斷字串p是否字串s的前綴。

Example input 1:

abc
abcde

Example output 1:

abc is a prefix of abcde

 

Example input 2:

bc
abcde

Example output 2:

bc is not a prefix of abcde

 

[Exam] asked in Final Exam
ID: 42299 - Available when: 2018-01-17 14:00 - Due to: Unlimited

retagged by | 17.5k views

37 Answers

0 like 0 dislike
Hidden content!
#include ****** ******
#include ********** * **
*** *** * ***
* * * * * * ** * **

int prefix(char a[], char b[]){
int i, j,n;
int cnt=0;

n= * * ** ** *

**** * **** ** ** * *** **
*** **** ** ** ** *** * == b[i]){
* ** **** **** *** **** * * * *** * *** * *** ** **
* * **** ***** ** * *** *

* * ** *
if (cnt == n){
* ***** * * * * ***** * * ** * * ** * 1;
** * * **** * * * ** ** * * * * * ** * **
* * * ** * * * * * * *
** *********** ** ** ** *** ** * ** **** * * 0;

}

int main()
{
*** * ** * * ** s1[100], s2[100];
** * * ** **** i,j;

** * ** ******* **** ** * *** *** s1);
** * ** **** ** * * * *** ******** s2);
* * ** ** * ** * (prefix(s1, s2)){

* * ** * ** * *** * * * ** ** **** * * * is a prefix of %s", s1,s2);
***** * * * ***** ** * ** * * * ** * *
* * * *** * ** ** * * * * **** ** *
** ** **** * *** ** ** **** * * * ** **** ** ***** * * * is not a prefix of %s", s1,s2);



}
answered by (323 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <string.h>

int main(){
***** ** * **** ** * ** * c;
** * * ** * * * * a[100],b[100];
***** * * * * * * ** *** * * %s",a,b);
****** *** * * ** * * * **** * * * ***
* *** **** * * ** * *** * *** * ** ** * * 0;
** ** ** * ** ****** ** *** %d",strlen(a),strlen(b));
* *** * * ** ** ***** * * ***
** * * ** *** * **** * ** *** * * * ** * * * * *** * * *******
* * * ** *** * ** * ** * *** ** **** * ** ** * * ** *** * ** *** * ****** * ** * * ** is not a prefix of %s",a,b);
** ****** * ** **** * ** * * * * ** * * * ** * **** * * * *** ** *** **** *** **** **
* *** * * ** *** ** ** ** ***** * ** * * ***** * ** * * ** * **
* ** ** *** * ********* *** ** *** * ** ** * * **** * ** if(c==strlen(a)-1)
* ** ** * * ** ******* * ******* * * * * ** **** * *** * *** * ** * *** **** ***** ** *** * ** * ***** * is a prefix of %s",a,b);
    }
***** * * * * ** * 0;
}
answered by (-498 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <string.h>
int main()
{
* * *** ** *** ** n,count;
*** ** * ** * * ** ** **** * * * * * ****
*** ** ***** ** * * *** *** %s",a,b);
** * ** * * * ** *** ** ** * ** ***

** * *** ****** * *** * * ** ** * * *
** * ** ***** ** * ** *
* * * * ** *** **** * *** ** ** ** *** * * ****** ***
* * ** * ** *** ***** *

* * * **** * ***** ** * (strcmp(a,c)==0)
* ******* * *** **
* * * * ** * * ** ** * * * ** *** * *** * * is a prefix of %s",a,b);
*** ** ** ** *** *
* * *** * * * **** **
** * *** * * **** * *
** ** *** * * * *** * *** * * * * ** ** *** *** * is not a prefix of %s",a,b);
** *** ** * * * *
** ** ** ** * ** * *** * * *** 0;
}
answered by (-284 points)
edited by
0 0
prog.c: In function 'main':
prog.c:8:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s %s",&prefix,&word);
             ^
prog.c:8:16: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
     scanf("%s %s",&prefix,&word);
                ^
prog.c:10:15: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     for(i=0;i<strlen(prefix);++i)
               ^~~~~~
prog.c:10:15: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:10:15: note: include '<string.h>' or provide a declaration of 'strlen'
prog.c:18:6: error: expected '(' before 'printf'
      printf("%s is a prefix of %s",prefix,word);
      ^~~~~~
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
#include<string.h>
int main()
{
*** * ****** ***** * * a[100],b[100];
**** *** * ***** * * * ** *** ***** * * *
    int l1,l2;
* *** * * ** * ****** *
* ******** *** * ********* *
*** * ** * * ** **
** ** ** **** * *** *** * ** * * **** * * ***** is not a prefix of %s",a,b);

    }
** * ** * ** * ** * if(l1<=l2){
* * ******* * * **** ** * * * * * ***** ** ** *** prefix=1;
* * ** * ** * * ** *** *** * * * * * ** * i=0;
* *** * * *** * *** * ****** ** *** **** *** ***** *
*** * *** * * ** *** ** * ** * ** * * * * ** * * ** **** * ** ********* * * * (a[i]!=b[i]){
** * * * * * *** * *** *** * * * ***** * * * * ** ** * ** *** * * **** * * ****
* **** ** ** *** * *** * ** ** ** * *********** * * * * ** ******* * * ** *** *** **** ** ** * ***
** * ***** ** *** * * ** * ** * * * * ** *** *** *** *** *** *


* * ** **** ** ***** ** *** * * ** *
* * ** * ** ** *** * * * *** *** * ** * * *** *
*** *** ** * * *** * * * **** ** ****** ** * * ** **** * * ** * ** is not a prefix of %s",a,b);
* ** *** * *** * ****** *** ** ** * * **
* * * * * ** ** *** *********** *** ** ** *** **
* ** * *** * * * * ** * ** * * ** * * * * is a prefix of %s",a,b);


    }


}
answered by (-329 points)
0 0
prog.c: In function 'main':
prog.c:5:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
             ^
prog.c:5:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
               ^
prog.c:7:8: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     l1=strlen(a);
        ^~~~~~
prog.c:7:8: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:7:8: note: include '<string.h>' or provide a declaration of 'strlen'
0 0
prog.c: In function 'main':
prog.c:6:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
             ^
prog.c:6:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
               ^
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
** * * **** *** *
int main(void)
{

* * **** ** * ** ** ** pre[100];
* * ** * ** * ** * *** word[100];
** * ** * ** * * * ** ** ** **** *** %s",pre,word);
** * * **** * ** ***** ** ***** *
* ** ** * * *** * * * *** * * ** * *****

* ** ** * ** *** i;
* * ***** * * ***** ** * ** ** * **** *
* ** *** ** **** ***
** * * * *** **** *** * * * ** * * * * ** ** * *
*** ** * * *** * ** * * ** *** ***** * * *
** * * ** * * * * ** ***** * * ** * **** *** ** * * * *** * * ** is not a prefix of %s",pre,word);
* * * ** * * ** * * * * * * ***** ** ** *** * ** * * ** * 0;
** * * ** * * ** * ** * ** ** * ** ** ****

** * * * * ** * ** ** *
printf("%s is a prefix of %s",pre,word);
return 0;
}
answered by (-249 points)
0 0
prog.c: In function 'main':
prog.c:8:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&pre);
             ^
prog.c:9:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&word);
             ^
0 0
prog.c: In function 'main':
prog.c:8:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&pre);
             ^
prog.c:9:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&word);
             ^
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <string.h>
#include <ctype.h>
int main ()
{
**** ** ** * * ** * * * pre [100],a[100];
* ** ** ** * *** * * n ,i;
****** * * *** * ** *** ** **
* * * * *** ** ** *** * ****
** *** ** *** *** * ** * ***** *
*** ** ** ** *** ******
***** * **** ***** * * * * ***** ** * ** (n=0;n<strlen(pre);n++)
* * * ***** ** ** ** ** * **** ** * * * ***
* * * * * ****** * ** ******* * * ** ****** *** *** * ** * * (pre[n]==a[n])
* ** * **** ** *** ** *** * * * * ** * ** * * *** ** * ** ******** is a prefix of %s",pre,a);
*** ** * * ** ***** * * *** * * * * * ************** *** * ** * ***
* * *** * ** ** * *** * ** * ** ** ** *** * * * * ** ** * *** **** ** ******* ** ****** ** ** * * * is not a prefix of %s",pre,a);return 0;
* * ** * ** ** ****
*** *** **** * * *** * **** *** *** *** * ** * ** * *

* * * ***** * * **** *** **** 0;
}
answered by (-32 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include * ** *
#include *** * * *

int main()
{
*** * * **** * **** ** ** a[100];

** ** * * * * ****** b[100];

* * * * ******* * * * ***** %s", a, b);

* * * **** * ** ** ** len_a = strlen(a);

* * * * *** *** * * * * * ** i = 0;

**** * * *** ** *** ** **** * flag = 1;

* **** *** **** *** * * ** = 0; i < len_a; i++)
** * ***** * ***** **
* * ** *** ** **** * * * * * * ** * * * != b[i])
* * ** * * * *** ** **** ** ***** * **
* ** * ** * ** *** ** ** *** * * ** ** ******* * *** ** * * ** = 0;
* * * ** * **** * **** * * * * ***** *
* * *** * * * *

**** * * * **** * * ** * ** == 0)
* * * * * *** * * * ** *
* * ** ** * * * * * ** **** ** *** *** * *** * * ** is not a prefix of %s", a, b);
* * * * * * *** ** ** *
** *** * * * ** * **
* ** * * ** *** *
** ********** ** *** ******* ** ** ***** ******* * * * * is a prefix of %s", a, b);
* * ** * ** * * * **
* * **** * ** ** ** * **** 0;
}
answered by (-285 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
** * **** ** ***
int main()
{
* ** *********** ** * ** i,n;
* *** * ** * * ** p[100],s[100],a[100]={};
******** ** *** ** * ** *** *** ******* ** %s",p,s);
* * * ** * * * * *** * *
**** * ** * ** ** * * * ** **
*** * * *** **** ***** * *** ** * *** ***
****** * * ** *** ** * ***** * * * *
* ** ** *** * ** * ** * ** * * ** * *** ** **** is a prefix of %s",p,s);
* * *** ** * * **** **
* *** * **** ** * **** *
* * * * ** ***** ** ** *** * ** * **** *** * *** is not a prefix of %s",p,s);
*** * * * *** ***
* ** * *** ***** ** * * * * * **** * ** * ** * **
* * ** * * ** *** 0;
}
answered by (54 points)
edited by
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
#include<string.h>

int main()
{
    int i;
    char a[100];
    char b[100];
** **** ** ** *** ** * ** * * * * ******* * *
    scanf("%s",b);
    for(i=0;i<strlen(a);i++)
* * **** * * * *** * * * ****** * * *** ** ** *
**** * * *** * * ***** *** * ** * *** ** *** **** * != b[i])
*** ** * * ** ** * ** *** ** * ** * * * * * * ** * * * * *** **
** * * *** * * * ** ** ** * *** * * * * * * ** * *** * * *** *** * ****** * *** * ** * * *** is not a prefix of %s",a,b);
** * * * **** * *** * *** * * * * * * ** ***** ** ** ** * * ** ******* * ** *** ** *** ** ***
* * * ** ** * *** * * * * ** ** *** **** ** *** **** * *** *** ** ** * *** *
** * ** *** * **** * ** *** * *** * * * ** * * * * * *** * *** * * ** == b[strlen(a)-1])
* ** *** ** ** * ** ** **** * *** * * ****** * ** *** * * ** *** * ** ****** ** ** ** * * * * *
** ***** *** * ** *** * * * *** ** ** * * * ** *** ***** ******* * ******* ** *** * * * *** * * * ** * * is a prefix of %s",a,b);
** * * * *** * ** * * * * * *** *** ** ** ** * * ******* *** * * **** *** * * **** * ** * **** ** * ** * * * * * **
* * * **** ** * * * * *** ****** ** * ** * **** * **** * * * * *** ** * ** * ** *
* * * * ** **** **** * * * ** * * **
}
answered by (-301 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
#include<stdlib.h>
#include<string.h>
#define n 100

int aa(char a[],char b[]){
* *** * **** * ** * * * i;
** ** ** ** * * ** * ******* (a[0]!=b[0]){
**** * ** * * ** * * * * * * ** *** * ****** 0;
** ** ** * * * * ** **** * * *
** *** * * *** ** * ***** *** * *** *
** * ***** * *** *** *** * * * ** * * * ** ** *** * a[i]==b[i])
* * * *** *** * * * ****** *** ****** * ****
* * ** * *** * ** ** * **** ***** ** *** * * * * ** * **** * ****** ** * * 1;
*** * ** ** ***** **** * * * ** *** ** * * ***** ****** * ** ***
* **** ***** **** ****** **** * * ******* * ***
**** ** ** ** * ** * * ****
* * * *** ****** **** **** * 0;

}

int main(){
* * *** **** *** ** ** * c[n],d[n],e[n];
* * * ****** * * * * ** * i;
** * * * * **** ** ** *** %s",c,d);

** **** * ****** ** **
**** * ** *** ** ** ** ** * **** * ** * *** * * * * ** ** is a prefix of %s",c,d);

***** * ** * ***
* * * ** * **** ****** ** ** * * * ** ** ** * * * * is not a prefix of %s",c,d);


}
answered by (-32 points)
edited by
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:104.23.243.109
©2016-2026

Related questions

1 like 0 dislike
37 answers
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42302 - Available when: 2018-01-17 14:00 - Due to: Unlimited
| 16.1k views
2 like 0 dislike
31 answers
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42301 - Available when: 2018-01-17 14:00 - Due to: Unlimited
| 15.1k views
1 like 0 dislike
32 answers
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42300 - Available when: 2018-01-17 14:00 - Due to: Unlimited
| 18.9k views
2 like 0 dislike
30 answers
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42298 - Available when: 2018-01-17 14:00 - Due to: Unlimited
| 13.1k views
0 like 0 dislike
4 answers
[Exam] asked Jan 19, 2018 in Final Exam
ID: 43460 - Available when: 2018-01-20 09:00 - Due to: Unlimited
| 3.4k views
12,783 questions
183,442 answers
172,219 comments
4,824 users