Final Exam 2 (20%)

1 like 0 dislike
13k views

A string p is a prefix of a string s if the leading characters of s are identical to p. For example, "abc" is a prefix of "abcde". Develop a function prefix that checks if a C string p is a prefix of another C string s.

p是s的前綴若s開頭的一段字串等於p。例如，"abc"是"abcde"的前綴。寫一個程式 判斷字串p是否字串s的前綴。

Example input 1:

abc
abcde

Example output 1:

abc is a prefix of abcde

 

Example input 2:

bc
abcde

Example output 2:

bc is not a prefix of abcde

 

[Exam] asked in Final Exam
ID: 42299 - Available when: 2018-01-17 14:00 - Due to: Unlimited
retagged by | 13k views

37 Answers

0 like 0 dislike 
Hidden content!
#include *  **  *   * *
#include *   ** ** ** *****
** * ** ** *   **    
 ** * ***    ** *    *

int prefix(char a[], char b[]){
int i, j,n;
int cnt=0;

n= ** *** *****

   * **  * * *    ** *** ** ******  
** **      *  * * **     ***   == b[i]){
 *   **** *  * * *  ** *** **   ***** *** * ***   * *****    *  
** *   *   * ** *** * *  

 * * ** *********  *  
if (cnt == n){
 *** * * *  ***   *     * *** *  *  *   *  *   ***    *  **  1;
**** * *    ******    *   *  ***** ** **  ***    *  *    * 
*** ** ** *   * ** *     * *
* *  **  *  *** **  **** * * ***  * **  **   ** *** ***  ** 0;

}

int main()
{
    *   *     ** ** * ***  s1[100], s2[100];
* *   ** ***** * **  i,j;

* *  *     *  ** **** ** * *  *** *    * *  s1);
***  ****   ***   *** ** **  * * * ** *  **  s2);
** * *** * ** *  ****  * (prefix(s1, s2)){

   *   *****      **** *  * *     * * **     *** * **  *  **  ***  is a prefix of %s", s1,s2);
** *  *  * **  *  * ******   ** **  *    ****  *
**   * * * * *    ** *** * *  ** *** * * * **    * *
   *****   **   **       *   ***   *    * *   * ****** * * *  *    **   **** *  * ** is not a prefix of %s", s1,s2);



}
answered by (323 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <string.h>

int main(){
 **     *  * * * *   *  c;
  ** * **  * * *        ** a[100],b[100];
*******  *** *** *** *    **     **  %s",a,b);
*       * *   * ** ******    *   * * *
 * * ** * * ***  **   *****     ** ** *  **  * **     *  0;
** ***   *  ** *  **** *** *     * * *  * * %d",strlen(a),strlen(b));
  *  **   * * *   *****   **** * * *** **  ** **    
*  *   *   *** ** * * *     *   **** ***     *  **   ** **** * **  ***    * *** *** *** ***  *
  *  *** *   *****  ******  *  *** * **   ***  *     *  ****  *   *** *  * *      * * * **    *** **  **** *       * * * is not a prefix of %s",a,b);
**** ***    *** **     *** * *  * ***** *   ***  ***** ****** ***  *      * * *   ***  **  *    ** * ** 
** ** * *******   **   *** *  **** *   **  ***   *  * *  *****   **  *  ** *   ** ** *     
 * ***  * ****** *   *   * * * * *** *    *** * * *    **  *     *      ** ** *** * *** *    if(c==strlen(a)-1)
* **  * * *  *  * *   * *  *   ** * *** ** * * *    **   **  * * ** **     ****** **  *** **  ***    *** *  *  *  *** is a prefix of %s",a,b);
    }
  **  ***  * ***** *  * **  * 0;
}
answered by (-498 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <string.h>
int main()
{
   *  ** * ****       *  **  ** n,count;
*** *  *  * ** **** *  ***   * * *  * ****  ** *    
** **  ***** * **  *   ** * ** * *   ***** %s",a,b);
  *    *** * * * **** **   *

* *   *  *  *** ** * * * **  * * ***** *** * *** 
   *       **  *** * ********
****      **  * **    ** **** * ** *   * **  **   *** * **** ** ******
**     * ******  *****  **  ***

****  *   ** *      * ** * *** (strcmp(a,c)==0)
 ****  *** ***   ** ** * * 
*     ****** *******  **** *        **** * **   * *  ** ** * * *  * *  is a prefix of %s",a,b);
***  *   * **         **
 ***  *      ***   * **   *   *** 
** *****    ** *  *    ** ***   *
* *   *     * ** *  * *   ********  ***  *  **    * *****    *  *  is not a prefix of %s",a,b);
*        *** *  ******** * * 
 *****  * *  *  * *** * *  ** 0;
}
answered by (-284 points)
edited by
0 0
prog.c: In function 'main':
prog.c:8:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s %s",&prefix,&word);
             ^
prog.c:8:16: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
     scanf("%s %s",&prefix,&word);
                ^
prog.c:10:15: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     for(i=0;i<strlen(prefix);++i)
               ^~~~~~
prog.c:10:15: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:10:15: note: include '<string.h>' or provide a declaration of 'strlen'
prog.c:18:6: error: expected '(' before 'printf'
      printf("%s is a prefix of %s",prefix,word);
      ^~~~~~
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>
int main()
{
 * * * *    *     ***** *** a[100],b[100];
*      ***** ** ** **  ****   **     *   ** **  *  ***
    int l1,l2;
  * *** **  *  *       ** *   *
   ** * ***  *  *** * * *** * *
  *    *  ** ***     ** ** *****  *
 ** ** *    ***  **  ** **** * * ***** *     **  ***   * * *   *  is not a prefix of %s",a,b);

    }
 ******    *     ** ****   ** * if(l1<=l2){
*  ** * * ***** *  **** *  * *  * ** *** *    ** *     * prefix=1;
****** ***  *  ****  *** *  **    *     **         * * * i=0;
***  **  **  *  *     * * **    * *  **  *****    ** ** ****    ***  *** 
*** ***   *  * * ** *** **** ** **     *  *   *** ****    *****   *  * * * * ***  (a[i]!=b[i]){
  ***   *     ****   * * * *   *     *  *  ** *****   * * * ** ***** * **   * *   ******  *    * ***** *** *  *****   * 
   **  **  ***  **  **  **       **  *  * * *  ** ***  * * *    * * *   ** **    ** *     * *** *    *** * * ** 
   **             *** *   * **** * *** *   ******      **  * * *  * * * **  ** * *


**  ** * ****    * *  * ** *   ****     **** * * ***
  * **   * ***** ******   ****   *     *  * ****    *  * *****  
* * ** ******  ***  ***    *****   ***     *   **  * ** ****** * ** *  * ** **** *  * *** **  ** * *   * ** is not a prefix of %s",a,b);
**** *  ******** *   ****   *  *** *     *    **  * ** 
**  * **** * *  ** * * **       *   *** * ** * * ** **  *  ***
**** ***  ** **   * **  * ** *    ****   * ** *   * * **  **** * *  *** is a prefix of %s",a,b);


    }


}
answered by (-329 points)
0 0
prog.c: In function 'main':
prog.c:5:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
             ^
prog.c:5:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
               ^
prog.c:7:8: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     l1=strlen(a);
        ^~~~~~
prog.c:7:8: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:7:8: note: include '<string.h>' or provide a declaration of 'strlen'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:6:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
             ^
prog.c:6:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
               ^
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
* ****  *  * ***** * 
int main(void)
{

** *  *     *  ** *** *  *   *  pre[100];
***  * *  **  *  ***  word[100];
*  *   * **** *  * *** *    * ****  *  *   %s",pre,word);
  ***    *    *  *  **** ***  *      **  * * 
 *  ***  *** * ***  *  ***    ***** ** * *

  *   * ** **** **   *** ** i;
*   ******  ***  *  *     * ****  ** *   **   *
   * *   *   **    **  * ****
  *  *  ** *****  ** **  *** **** ****** **   * **** * ** ***  
*** ***  *****  **  * *  *******   **  *   **   
 **       ****** ** *  *   ***   *    ***      ***  *  * ** * ****  * *********  *   is not a prefix of %s",pre,word);
   *  *  ***  * *** * *   *     *     ** * *  *** ****** *****  * *  **** ******   * 0;
  **    *   *  ******* *  ***    *  ** ** *  *    

**  * *  * ** * ***  *  *  
printf("%s is a prefix of %s",pre,word);
return 0;
}
answered by (-249 points)
0 0
prog.c: In function 'main':
prog.c:8:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&pre);
             ^
prog.c:9:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&word);
             ^
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&pre);
             ^
prog.c:9:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&word);
             ^
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <string.h>
#include <ctype.h>
int main ()
{
* *** *****   *  * ** * **  pre [100],a[100];
 ** **  *  *      **  *  *   n ,i;
*  ** *   *    ***    * **  *  * *   **
  **   *   * **** * * ***  ** *    **** **   * 
     * * ** * ****      **  *     ** *    * **
 ** ***** *****    
* **  *  * * * *   ***  **** * **   *  * *         *  (n=0;n<strlen(pre);n++)
***   *  *  * **** *  **  ******  *   * *     **  **  *  *
*  ** * * * *   ***   *    ** ** *    *   **  **  ***  *   **** **     * *****       *    * (pre[n]==a[n])
* *  ****    * **   *****    *   ******  *   * **  **    * * * *  * **     **** **       *   is a prefix of %s",pre,a);
  * ** * **  *  *******    * ******  *** ** ***** *****  ** ****    * ***
  ***  * *   ** ***** * **    ** * * ***    *     * *   **   *****    * **   ******* ****  *   ** *** * *  ***   *      *   is not a prefix of %s",pre,a);return 0;
  * *  *   * *** **  *  *** *
* ***  ***    **  ** * *  *****  *  *****  ******   * ** **  **  *      ** **** **

* *  * *   **** ** **  *  *   **  *  0;
}
answered by (-32 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include     * *****  *   
#include  *  * *        

int main()
{
*** *******   *****  *** *** a[100];

***           **         **  **      b[100];

 * *     **  *** * * *    ******** ** *   %s", a, b);

******   * * ** *  * *   **  *   len_a = strlen(a);

 ***   *   ** *  *       ********  i = 0;

 **    ***  **  ** **  ** flag = 1;

  ***  ** ******   **** **  *   = 0; i < len_a; i++)
****         * ** * ****
 ****   * * **  * ** ***  * *  **  **** *  * * *  ** * **  * *   * != b[i])
* ** * **    *  ** * *      **  * **   *    ***   **   * *
**** **  * * * *  *  * *** * ** * **** *    *   *** * *   * *** *  *** * *  = 0;
****  **  *      * *  *****  * **  **    **  *  ** *
 **   * *  *****   * **  **

*   * *       *  ** * *     *  == 0)
 * * ***   *  **** **  ** ** 
* **   * ** **   *** **  **  **  **** * ** **  *  *  ********  **      is not a prefix of %s", a, b);
**** *  * *** ** *      ***       
      * ****  * *   **    *  * * 
  ******  **** **   * *  **    *
  ***  *** * **    *****        *****     *  ***  *  *** ***  *  ***  is a prefix of %s", a, b);
* ***** ** *  * *      **
* * * * **  ******  **   * *  * 0;
}
answered by (-285 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
 ** **   * * ***    ** 
int main()
{
*  *   ** ***** ****    * *** *  * * i,n;
**  *******  **** **** *    *  p[100],s[100],a[100]={};
**  *  *    * **** *    * *  **    * * * %s",p,s);
   ** ***   ** *  * * ****   **   ** 
**  * **** **  * ****   **  *  ** ***
  **   *** **** *** *  ***** ***  ***  *   ****  
   * *** **  *       ***      *  * 
** *    ** * *   * * *     *** *  **    * * **   * ***  ** *  is a prefix of %s",p,s);
*  * **** ***  * ***  * *  
**     *     *** *   ***  
 **** ** ** *      **  *** *   *    ***  * * ** ** * * * *  ** is not a prefix of %s",p,s);
   * *   * * ***  ****
 * * * * ***   **** ** * * *  ** * * ***  * * **
  ** * ******* *  * * ** *  ** 0;
}
answered by (54 points)
edited by
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>

int main()
{
    int i;
    char a[100];
    char b[100];
 *    * *  ** *   *** *    *********  * *** ** *  *  
    scanf("%s",b);
    for(i=0;i<strlen(a);i++)
*  *   * * * **  * ** ** **  *  ** *  ***  *** 
   * *****   ***  ***** *  **  * ***  * ****   *  * ***  *    * *  ** *  ***  ** * ** * != b[i])
* * *     *   *** *    ***   *    ****  **  * **     * * **  ****** * ***  * ****** ***   ****** * **  *****
  * * *  **  ** * * * ***      *   *** *  *  ******  ** * **   **  *** *  ******* *** * *   *  * * ***** ****  ** **   ******** * * * * ***    ********  is not a prefix of %s",a,b);
**    * * * ***** * * *** **  *    ** * *** **  *  ****    *  *  *    * * **  * * * ******* *  *    ** **   **    ** *** **   *   *  
  **   *  ***  * *  ** * * **  *  **  * *     *  ***   * * * * ** *   * *** *** **  *  *  * *  **** * **  
 *   *** *    * * **  *****       *** ** ***  *   * ** * *   **  **        *  **** ******     == b[strlen(a)-1])
   *   ** *     ***** * * *   **  **  *** ***   *** *  *  * * ***  * ** *   * * ****  ** *    *** *  
* *    * *** *  **  * **  * * *** * *   ****  **  * *  **  *** **  ***** *** *** **  ** **  **   ** * *     * * ** ***  *   ** **  * *  **** is a prefix of %s",a,b);
  * *  ** ****  *      ***  ***  * ****     *   ** ********* * *    *** *  **  ****    * ***  *  ***** * ** *   * * * * *** ***  ** 
 *  * ******   *   **** * ***** *   * * *  ***   * *  ** ** ** *    *   ***     *  * ***  *  * ***  * *   
 * * ***  * **   * ** *      **   * ** * ** ***  ** *  **
}
answered by (-301 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<stdlib.h>
#include<string.h>
#define n 100

int aa(char a[],char b[]){
******   **** **** * * **  i;
 *  *   **        * ** *  * * * ***  (a[0]!=b[0]){
 * ******* * **   ***** *   * ******* *** * *    *   * 0;
  * *     ** *****  *  * * * * 
* ***  *     ** *  **  ***    *  * *  *  * ***   * ** ** 
  ** ** * **       **  * **** ** ** **  * **** ** ** * * ***  a[i]==b[i])
  * *****    *    * **  *** ** **  * * **   ** ** *
  ** *** *** *   ** *    *  *** * * ** * ***  *  ** ****    **  ***    ** **    *** **  1;
 **   **  **** ** *** * ** * * ***    * * * ***    * *      *   * **   ** ** ** 
    * ** * **  **** *  ** *   * *   ***   * ** * **    *
 *  ** *    *** *  * **   ***     *   
**  * * * ** * * * *** *  ***  *  *      *  0;

}

int main(){
* **         * *** * *      * * c[n],d[n],e[n];
    *  ***     **   *  * * *   i;
    * ** *** * ***** * *   ***   *  * %s",c,d);

***   * * ** *  * *  ** * *   *
   *      *    * ****    ***  *   **   *    * ** *   *   *  is a prefix of %s",c,d);

 *  ** *** * * * *   **     
 *   ***  ** * * *** *** * * ** *  * ** ********   ******  * *  **  *   is not a prefix of %s",c,d);


}
answered by (-32 points)
edited by
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:108.162.241.185
©2016-2025

Related questions

1 like 0 dislike
37 answers
Final Exam 5 (20%)
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42302 - Available when: 2018-01-17 14:00 - Due to: Unlimited | 12.6k views
2 like 0 dislike
31 answers
Final Exam 4 (20%)
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42301 - Available when: 2018-01-17 14:00 - Due to: Unlimited | 11.6k views
1 like 0 dislike
32 answers
Final Exam 3 (20%)
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42300 - Available when: 2018-01-17 14:00 - Due to: Unlimited | 13.4k views
2 like 0 dislike
30 answers
Final Exam 1 (20%)
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42298 - Available when: 2018-01-17 14:00 - Due to: Unlimited | 10.3k views
0 like 0 dislike
4 answers
[Makeup] Final Exam 2 (20%)
[Exam] asked Jan 19, 2018 in Final Exam
ID: 43460 - Available when: 2018-01-20 09:00 - Due to: Unlimited | 2.6k views
12,783 questions
183,442 answers
172,219 comments
4,824 users