1 like 0 dislike
8.3k views

A string p is a prefix of a string s if the leading characters of s are identical to p. For example, "abc" is a prefix of "abcde". Develop a function prefix that checks if a C string p is a prefix of another C string s.

p是s的前綴若s開頭的一段字串等於p。例如,"abc"是"abcde"的前綴。寫一個程式 判斷字串p是否字串s的前綴。

Example input 1:

abc
abcde

Example output 1:

abc is a prefix of abcde

 

Example input 2:

bc
abcde

Example output 2:

bc is not a prefix of abcde

 

[Exam] asked in Final Exam
ID: 42299 - Available when: 2018-01-17 14:00 - Due to: Unlimited

retagged by | 8.3k views

37 Answers

0 like 0 dislike
Hidden content!
#include * * ****
#include *** * ***** *
** *** * * **** *
**** * * * ****

int prefix(char a[], char b[]){
int i, j,n;
int cnt=0;

n= ** ******

* ** * * * ***** * **** * * *
*** ***** * ** * * * == b[i]){
*** * * * * * *** * ** ** ** * ***** * ** ** **
*** * * ******* ** *

* * * * ** *
if (cnt == n){
* * **** * ** *** ** * ** * * * * *** 1;
* * *** * ******* * * *** * * *** ** * *
* ** *** * *** *** * *
* *** * *** * *** ** ** * **** *** * * ** *** 0;

}

int main()
{
* ** * *** ****** s1[100], s2[100];
**** * * * ** ****** i,j;

** * * * ** ***** *** *** s1);
* **** * * * ** * *** * ** * * * s2);
** ** ****** ** (prefix(s1, s2)){

* * * ** * ** ** * * * ** ** * **** **** ** * is a prefix of %s", s1,s2);
* ** ****** * * *** **** * ** *** * * * *
* *** *** * *** ** ** * ****
*** * ** * * ** ** **** * * ***** * * ** *** * * * * *** * ***** is not a prefix of %s", s1,s2);



}
answered by (323 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <string.h>

int main(){
* * * ** * **** * ** c;
**** ***** * ***** ** * * a[100],b[100];
**** ** ** * ** * *** ** %s",a,b);
*** * * * ***** *** *** **** * ** *
* * *** *** * *** * * ** * * * *** 0;
* *** *** * ** * * * * *** * * %d",strlen(a),strlen(b));
* * * *** ** * *** ****** *** ****
** * * * **** * * * * *** ** * * * ***** * ** * * * ** *
* * * * * *** ***** *** ** ** ** * ** * * * * * ** * * * *** * * * * * ** ** * ** **** ** * is not a prefix of %s",a,b);
* * * ** * *** * * * *** *** ** * * **** ** * * *** *** **** * ******* * * *** **** ** * ** **
* * * * * ** **** * **** * * * ** **** * ***** * ** * * *** **
* * **** *** **** *** ** * ** ** *** * * *** ** *** *** * if(c==strlen(a)-1)
* **** ** ** * ** * ** * * ** ** *** * * ** * *** * *** * * ** *** * **** ****** **** * * ** is a prefix of %s",a,b);
    }
* * * ** * * * * 0;
}
answered by (-498 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <string.h>
int main()
{
** ** *** ** ** *** n,count;
** * * * *** ** * * ** * *** * * ** ** *
* * * *** * * * ** **** ** %s",a,b);
* ** * **** **** ** * **** *

*** * *** * * * * * ** ** * ******* * *** * *
* *** * *** ** ** * **** *
* **** * ******* ** * ** ** *** * * *** * * ** *
* * * ** ***** *

** *** * ***** ** ** *** (strcmp(a,c)==0)
** ** **** * ********
** *** ** ** ** **** * *** * *** ** ** **** *** * ** * * is a prefix of %s",a,b);
* * * ** * ***** **** *
*** * * * * * *** *
* * ** ***** **
** ** *** ** ********* ******* **** * * **** **** ** * ** ** * ** is not a prefix of %s",a,b);
**** * * * ** ** **
** * * ** ** * * *** * 0;
}
answered by (-284 points)
edited by
0 0
prog.c: In function 'main':
prog.c:8:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s %s",&prefix,&word);
             ^
prog.c:8:16: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
     scanf("%s %s",&prefix,&word);
                ^
prog.c:10:15: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     for(i=0;i<strlen(prefix);++i)
               ^~~~~~
prog.c:10:15: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:10:15: note: include '<string.h>' or provide a declaration of 'strlen'
prog.c:18:6: error: expected '(' before 'printf'
      printf("%s is a prefix of %s",prefix,word);
      ^~~~~~
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
#include<string.h>
int main()
{
*** *** **** * ** * * ** ** a[100],b[100];
** *** ** * * ** * * * * * *** ** * * **
    int l1,l2;
**** * * * ** ** **** ** **
*** * * * * ** *** *******
* ** * * *** ** ** * * ** * *
** *** * ** *** * * ** * **** * * * ** ** * * **** ** ** is not a prefix of %s",a,b);

    }
***** * **** * * ** if(l1<=l2){
*** **** * *** *** * * * * * * *** *** ** prefix=1;
* *** * ** * * **** * ** * * * ** ** * ** ** *** i=0;
*** *** ** ** * * * ** * * *** * **** * **
* * *** ** * * * **** *** * * * * **** * * * **** ** ** *** *** (a[i]!=b[i]){
* ******* * ******* * ***** * ** * ** *** * * * ** * *** * * ***** * * * *** * *** *****
*** * *** *** * ** * ****** *** **** * *** * *** ** * * **** ** ***** **** ** ******* * * * *
** *** ** * * *** ** ** * * * * * * * ** ** ** ** *** *** *


******* * ** ** * ***** **** *** * * * * * *** * ***
*** * ** ** * ** ** * ** * ** * *
* * ******* * ** * * ** * ** *** * * *** * **** * * * ***** ** ***** * * is not a prefix of %s",a,b);
*** *** * * * *** * ** * *** *** ** ** *
*** ** ** ** ** * * ** * ** *** * **** ***
* *** * * * * * * * * ** *** ** * * **** ** is a prefix of %s",a,b);


    }


}
answered by (-329 points)
0 0
prog.c: In function 'main':
prog.c:5:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
             ^
prog.c:5:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
               ^
prog.c:7:8: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     l1=strlen(a);
        ^~~~~~
prog.c:7:8: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:7:8: note: include '<string.h>' or provide a declaration of 'strlen'
0 0
prog.c: In function 'main':
prog.c:6:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
             ^
prog.c:6:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
               ^
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
* ***** * * * *
int main(void)
{

* * **** *** * ** ** ** * pre[100];
** * * *** * word[100];
* * * * * ** * ** * * ** * %s",pre,word);
* * ** * *** ******* *** * * * * ***
*** * * **** *** * * * ** * *** *

* * * * * ** ** * * ** * i;
* ** ** ***** * * * ***** * * ** * ** ***
************ *** *** * *
* * ** ** ******* ** ** *** * ** * *** * *** *** * ** *
*** * ***** * ** ** * **** * *** *** *
* ** * *** ***** * ** * ** **** *** ** * ** * * * * *** ** * * ** * * is not a prefix of %s",pre,word);
* ** * * * ***** * *** ** * *** **** ******* ** ****** *** * ** * * * ** 0;
**** ** *** * * * * ** **** *** * ** *** * *

** * *** ** * ** *** *** *
printf("%s is a prefix of %s",pre,word);
return 0;
}
answered by (-249 points)
0 0
prog.c: In function 'main':
prog.c:8:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&pre);
             ^
prog.c:9:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&word);
             ^
0 0
prog.c: In function 'main':
prog.c:8:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&pre);
             ^
prog.c:9:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&word);
             ^
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <string.h>
#include <ctype.h>
int main ()
{
** **** **** *** ** ** pre [100],a[100];
*** ** * ** * * **** ** n ,i;
** * * *** * ** * ** * * * ***
* * * * * *** * * **** * ****
* *** * ** ** * * * ** *** * * *
* ** * *** *
*** ** * * **** * * * *** *** * ** **** * (n=0;n<strlen(pre);n++)
* **** * **** * * *** * * * * ** *** * ** * *
** *** * ****** ** * * **** ** * ******* * * ** *** ** *** (pre[n]==a[n])
*** *** **** * * * * ** *** * * * ** * ** * * * ** * ** * ******** ** is a prefix of %s",pre,a);
***** ***** ** * *** * **** ** *** * * * * * ** * ** * * * * ** ** ** *
* ********* ** * ** ** ******** * *** *** * * * * ** ** * * * *** ** ** * ** * ** * * * * **** is not a prefix of %s",pre,a);return 0;
*** * * *** ******
*** * * * ** * * * ********** * **** ** *** ** **** * * **

** * * ***** ** * ****** * ** 0;
}
answered by (-32 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include * * * *****
#include * * *** *** *

int main()
{
* ** * ** ** * *** *** a[100];

* * * ** ** * **** *** * b[100];

** * * * ** ** **** * ** %s", a, b);

* * *** * ****** *** ** len_a = strlen(a);

** ***** **** * * * ** i = 0;

* *** **** * ** ** * *** flag = 1;

* * ** * ** * * ** * ** ** = 0; i < len_a; i++)
**** * ** * *** * * **
* * *** ** ** * * * **** ** ** * ** * * != b[i])
* ** ** * ******* ****** * * * *
** ** ** *** * * * * * *** * * * ** *** ** ** *** * * * * ***** = 0;
* ** **** ** *** * * ** * * * **** ****** *
*** * * * ***

** *** ** * * ** ***** ** * * * ** == 0)
*** ****** * * **
* ** * * * ** ** * ** ** * ****** * * * * *** * * * ** is not a prefix of %s", a, b);
** * * ** * **** * **
* ** *** ** *** ** **
*** * ** *** * *
* * * **** * ******* * **** * * **** * * ******** * * ** is a prefix of %s", a, b);
* * ***** *** * * ** * **
** ** ** ** ** * *** 0;
}
answered by (-285 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
*** ***** * * *
int main()
{
** * * ** ** * **** i,n;
*** * *** ** * **** **** p[100],s[100],a[100]={};
***** ** * ** ** ** **** * %s",p,s);
* ** *** ** * ***** *** * ** ****
* ***** *** * * * ** * **********
* * ** * * ** ** * * * * * *** * *
* ** * ** * * * **** ** ** * *
* *** *** ******* ***** *** ***** *** ** * ** * * is a prefix of %s",p,s);
* * * * ** * ** ** *
** * * **** ** ******** *
** * ***** * ** * * * ** * * **** * ** ** ** **** is not a prefix of %s",p,s);
* ** *** *** ***** * * *
* ** * * * ** ***** * * **** ** * * * **
** * ** *** * * ** * ******* 0;
}
answered by (54 points)
edited by
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
#include<string.h>

int main()
{
    int i;
    char a[100];
    char b[100];
* * ** *** * * * * * * ** * *******
    scanf("%s",b);
    for(i=0;i<strlen(a);i++)
** *** * *** **** * ** * * * * *
** ** * * **** * ** *** ** ** ********** ** ** * ** * * ** * ** * != b[i])
* * * * * ** * * * ** ** * ** **** * ** * * * * * * * * *** ** * * * ***** * *
**** * **** * ** ** ** * ** *** * * * * * ****** * ****** * * * ** ** * ** * * ** ** * ** ** ** ** **** *** is not a prefix of %s",a,b);
* ****** ** * ** ** * * * ** *** * * ** * ** * * * *** ** * * * ****** ** ** * * ** **** * * ** * * *****
* ** * ** *** * * ** ** * * ** ** ** * ** * * ** *** *** * **** **** *
** * *** **** * * * ** *** * * **** *** ***** ** ** * ** ** ** ****** * == b[strlen(a)-1])
* * * * * **** ** ** *** ** ** ** ** * ***** * *** *** *** *** ****** ************** * ** * **
****** ** ***** * ** ** **** * ****** * * ** ** **** ** * **** ** * * * * ** ** ** *** * ** ** *** ** ** * * **** is a prefix of %s",a,b);
*** * * * * * ********* ** ** * ** *** * * ** * * * * ** ** * * * * ** ** * **** ** **** * * * * **** * * * *
* ** * ******* ** * **** ** * **** ** ** **** ** *** * ** ** * * * ** * ** *** *
*** ******* **** * ** ** ** ** * *** **** ** * ** *
}
answered by (-301 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
#include<stdlib.h>
#include<string.h>
#define n 100

int aa(char a[],char b[]){
*** ** ** ** *** ** ** ** i;
* ** * ** * *** * **** *** ** (a[0]!=b[0]){
**** * *** *** ****** ***** * *** **** * * * *** ****** 0;
** ** * * *** * ** ** * ** ******
*** ** ** * * * ** * ** ** *** ** *
** ** ** * * * ** ** ** * ** * *** * ** ** * * * ** ** a[i]==b[i])
*** ** * * * * * * *** * **** ** * **
** * * **** ******* ***** * ** ** * * * * ** *** ***** ****** * *** *** * ** 1;
*** * * ** *** * * ** ** * * ** * ** * **** * * ** ** *****
* * ** **** ***** * ** * * ***
** *** * ** **** ** ** ** * * *
** **** * * ** * * *** * 0;

}

int main(){
*** * * *** * ** * * ****** c[n],d[n],e[n];
** * ** * ** * i;
*** * ** *** * * * ** ** * %s",c,d);

* ***** ** * * * *
** ** * ** * ** ** * * ** ** * * ** ** * * is a prefix of %s",c,d);

***** * * * * * *** ***
* ** **** *** * * * * * * * *** * * ** * * is not a prefix of %s",c,d);


}
answered by (-32 points)
edited by
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.100.40
©2016-2025

Related questions

1 like 0 dislike
37 answers
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42302 - Available when: 2018-01-17 14:00 - Due to: Unlimited
| 8.6k views
2 like 0 dislike
31 answers
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42301 - Available when: 2018-01-17 14:00 - Due to: Unlimited
| 7.5k views
1 like 0 dislike
32 answers
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42300 - Available when: 2018-01-17 14:00 - Due to: Unlimited
| 8.7k views
2 like 0 dislike
30 answers
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42298 - Available when: 2018-01-17 14:00 - Due to: Unlimited
| 6.7k views
0 like 0 dislike
4 answers
[Exam] asked Jan 19, 2018 in Final Exam
ID: 43460 - Available when: 2018-01-20 09:00 - Due to: Unlimited
| 1.6k views
12,783 questions
183,442 answers
172,219 comments
4,824 users