1 like 0 dislike
4.9k views

A string p is a prefix of a string s if the leading characters of s are identical to p. For example, "abc" is a prefix of "abcde". Develop a function prefix that checks if a C string p is a prefix of another C string s.

p是s的前綴若s開頭的一段字串等於p。例如,"abc"是"abcde"的前綴。寫一個程式 判斷字串p是否字串s的前綴。

Example input 1:

abc
abcde

Example output 1:

abc is a prefix of abcde

 

Example input 2:

bc
abcde

Example output 2:

bc is not a prefix of abcde

 

[Exam] asked in Final Exam
ID: 42299 - Available when: 2018-01-17 14:00 - Due to: Unlimited

retagged by | 4.9k views

37 Answers

0 like 0 dislike
Hidden content!
#include *** *** *
#include * * **** *
* *** ** * ****
** * ** * *** **

int prefix(char a[], char b[]){
int i, j,n;
int cnt=0;

n= *** * *** *

* * ** ** * **** * * * ** * *
* *** * *** * * * * == b[i]){
*** * ** * ***** ** * * **** * * ** **** * *
* **** ** * ** * *

* * * ** * ** **
if (cnt == n){
*** * ** * * *** * * ** *** * ** **** ** * * 1;
** **** * * ** * * ** *** *** ** ***
** * **** ** ******* * *
* * * * ** * * * * ** * * ****** * * 0;

}

int main()
{
* * * * ** **** *** * * s1[100], s2[100];
*** ** * ** i,j;

** *** ** ** * * ** * ** ***** * ** s1);
* * * * * * **** * *** * s2);
* * *** *** * *** * * (prefix(s1, s2)){

* * *** *** *** **** * * *** ** * ** * ** ** is a prefix of %s", s1,s2);
* * * ***** ** ** ** * **** ** *** * *
** * * *** * ** * ****** ** ** * ***** *
* * ** * * ***** * * *** * *** * ** **** ** ** ***** ******* ** *** is not a prefix of %s", s1,s2);



}
answered by (323 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <string.h>

int main(){
* ** ** * * * * * * * c;
* ** * * * * * * ** a[100],b[100];
*** * *** ** *** * ****** ****** * * * ** %s",a,b);
* * * * * *** ** ***** *** **** **
* * * * **** * * * ** **** ******** *** 0;
**** * * * ** ** * * **** ** *** %d",strlen(a),strlen(b));
******* * * * * ** *** *** ** ** ** * **
* * *** * * * * *** * *** * * * * * * * * * ** ***** ***
**** ** * * ** * *** * * ** *** ****** * * ** **** **** *** *** * *** *** is not a prefix of %s",a,b);
** * ** * ***** ** * ** * ** ** * ** * ** *** ** *** * * * * * ** ** ** *** * *** ***
*** ** * * * * *** * *** ** * ******* * ** * * * **
* *** ** ** * * * * **** * ** ** **** ****** * * * **** * * * ** ** * if(c==strlen(a)-1)
** ** ** * ** * * * * * * ** ** * *** ** * * * * ** *** * * **** ** ***** * * * * ** * * is a prefix of %s",a,b);
    }
* ** * * * * * * * 0;
}
answered by (-498 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <string.h>
int main()
{
*** * ** ***** *** n,count;
* ** ** * * ** ** * * *
** * ** * * * * ** * %s",a,b);
* ** ******* ** * **** * ** *

** * ** * ** * *** * * * **** ** *
***** ** * ** *
* * *** * * ** ** * * * ** * * ** ** * ***
** * ****** * **** * **

** ** * *** *** * ** * (strcmp(a,c)==0)
** * * *** ** **** ** ****
*** ** ***** ** **** * * * **** * * ** * **** * ** * is a prefix of %s",a,b);
** ** ** * * ** ** **
* ** * * * ** * ** * * **
** ********* ** **** * *
* ****** * ** * * ** * * ******** ** * * *** * ** is not a prefix of %s",a,b);
**** * * * *** * *
* * ** * * ** * ** * 0;
}
answered by (-284 points)
edited by
0 0
prog.c: In function 'main':
prog.c:8:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s %s",&prefix,&word);
             ^
prog.c:8:16: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
     scanf("%s %s",&prefix,&word);
                ^
prog.c:10:15: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     for(i=0;i<strlen(prefix);++i)
               ^~~~~~
prog.c:10:15: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:10:15: note: include '<string.h>' or provide a declaration of 'strlen'
prog.c:18:6: error: expected '(' before 'printf'
      printf("%s is a prefix of %s",prefix,word);
      ^~~~~~
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
#include<string.h>
int main()
{
* *** * ** ** * ** a[100],b[100];
* ********* * * **** ** ** ** ***** ******
    int l1,l2;
** * * ** *** * * *** ** **
* ** * * * * ** **** * *
** * **** **** * * * * *
** * * * * **** **** *** * ** * ** ** * **** ** * **** is not a prefix of %s",a,b);

    }
** * ** *** *** **** * * if(l1<=l2){
** ***** *** * **** ***** * * * * * **** prefix=1;
** *** * * ** * ** ** * ** * * ** *** * * ** * i=0;
** ** * ** ** * *** ** ** ****** * *** **** ****
** * *** * *** ** * * * * * * ** * **** * ** * * ***** **** * *** ***** (a[i]!=b[i]){
** ** ** ** * ** * ** * ***** *** * * *** *** *** ** * *** ** * * *** ** * * * * *
* *** * ** *** ***** * * ** * ** * * ** * * * *** ***** ** * * *** * * * ** *
* * **** **** * * * ** * *** * ***** *** * ** * ***** * *


* * **** ** **** * ** * ** **** ** * *
*** * ** **** ** ** ** * * ** *** ** *
* * * * *** ** ****** * * * **** * *** *** * ************ ** ** **** ** * *** is not a prefix of %s",a,b);
* ***** * ** * * ** **** ** * ** * **
** * **** * **** * **** * * * * ** *** **
* ** ** * ***** * * * ******* ** * * **** ** is a prefix of %s",a,b);


    }


}
answered by (-329 points)
0 0
prog.c: In function 'main':
prog.c:5:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
             ^
prog.c:5:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
               ^
prog.c:7:8: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     l1=strlen(a);
        ^~~~~~
prog.c:7:8: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:7:8: note: include '<string.h>' or provide a declaration of 'strlen'
0 0
prog.c: In function 'main':
prog.c:6:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
             ^
prog.c:6:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
               ^
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
*** ** *** * * *
int main(void)
{

* ** ** ** * * * **** pre[100];
**** ** *** ** *** * word[100];
** * ** ** * * * ***** **** %s",pre,word);
* * * *** ** **** ** * ** * *
*** *** * * * ** * * * ** ** *******

** ****** ** ** ****** * * * i;
* * * *** ** * ***** ****** *** * ***
* * * ******** *** **
*** ** ** * ** ** * ***** ** *** * **** *** *** *
* **** **** * * * * * ** * ** ** * *
* * * * * **** * ** **** *** ** * * * *** * * * ** ** * ** * * * * * is not a prefix of %s",pre,word);
*** * *** *** * * ** * ***** **** * * ** *** * * * *** * * * * 0;
** *** * * ** * **** ** * ** * *

** * ** *** * * *** ** * * **
printf("%s is a prefix of %s",pre,word);
return 0;
}
answered by (-249 points)
0 0
prog.c: In function 'main':
prog.c:8:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&pre);
             ^
prog.c:9:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&word);
             ^
0 0
prog.c: In function 'main':
prog.c:8:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&pre);
             ^
prog.c:9:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&word);
             ^
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <string.h>
#include <ctype.h>
int main ()
{
* * * *** ** *** *** pre [100],a[100];
* * ** ***** *** *** ** n ,i;
** ** * * * *** ** ***** ********
* ******* * * **** *** **** ***
* ** * * ** ** *** * * * * * * * ***
* * *** * * ** * ** *
** **** * *** ** * ** * ** *** * * * * * * * (n=0;n<strlen(pre);n++)
* * ** * * * ** * *** * * * ** * * ** * * *
* ** *** ***** * *** * * ** ** ** ******* * ** * (pre[n]==a[n])
* * *** * *** * * * ** *** ** * ** * **** ** ** * ** * ** * * is a prefix of %s",pre,a);
*** * ** *** ** * * ** ****** ****** **** * * ** * ** * *
* *** ** ** * * ** ** ** * ** * * ** * *** * ** *** * ***** ** ** ***** ** * ***** * * * ** is not a prefix of %s",pre,a);return 0;
* * * **** * * **** * **** *
***** * *** ** * **** * * ** *** * **** ***** **** * * *** ** ***

*** *** * * ** ** *** * 0;
}
answered by (-32 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include * ** * ** *
#include ** *** * ** * **

int main()
{
*** **** * * * *** ** * ** * a[100];

*** ***** ** * * * b[100];

* * ** ** * *** * **** ** ** * ***** ** %s", a, b);

**** * *** * len_a = strlen(a);

*** * * ** *** * * * * ** i = 0;

**** * ** **** ** ** * * flag = 1;

* * * **** * ** * ** ** = 0; i < len_a; i++)
*** *** *** ** * ** * ***
*** ** * * **** ** * * ********* ** ** *** *** ** * != b[i])
* ** ** ***** ** **** * * ** ** **** **
*** * * * * ** * *** ****** * ****** *** ****** * *** **** * * * *** * ** * = 0;
**** ** ** * *** * ** ** ** **** ** * ** *
* ** * ** ** *

** ** * * *** * * ** * * * == 0)
* ** * * ** *
** * ** ** * * ****** ***** * * ** * * **** * * ** *** is not a prefix of %s", a, b);
** * * * * * **
* * ** * *** **** *
** ** ** ** * ***** *
* * ** * ***** * ** ** * ****** * * ** * * ** * * is a prefix of %s", a, b);
* * * * *** ** **
* * *** **** ** * ** * 0;
}
answered by (-285 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
** * * ** * * * ** *
int main()
{
* * * * * ** *** *** * i,n;
****** ***** * * ** ***** ** p[100],s[100],a[100]={};
* ** *** ** ***** ** * %s",p,s);
* *** *** ** * * *
** ** * * * * ****** * * *
** *** ** ***** ** * * * ***** * *** * * *
** * *** ******* ** ** * * **
** *** * ***** *** * * * ** *** * * * *** * ** * * is a prefix of %s",p,s);
* * * * ** * **
* * * *** * ***
* * * ** * * * * * *** *** * ****** *** is not a prefix of %s",p,s);
* * *** ** *****
** ** *** * * * **** * ** * * * ***
*** * * *** ** * 0;
}
answered by (54 points)
edited by
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
#include<string.h>

int main()
{
    int i;
    char a[100];
    char b[100];
* ** * * * * * * ** * * * ** **
    scanf("%s",b);
    for(i=0;i<strlen(a);i++)
*** * * * ****** * ** ***** ** *** * * *
* ********* ** *********** * **** *** ** * **** * * *** * * * * *** * * ** != b[i])
* ** **** * ** * * *** ** *** * * ** * ** * *** *** ** *** * * **** ** * * * *
* ** ** ** *** ** **** * ** * ** * * *** * * * * *** ** ** *** **** ** * * *** * * *** ***** * * * *** * * * * * is not a prefix of %s",a,b);
* * * * * ** ****** * ** * * * * ***** *** * * * * *** ** ** * ** ** ** ****** ** * * ******* ***** ***** * *
* * * * * ** **** * * * ** ** ** * * ******* * **** ** * ** ***** * ***** * *** * *
** * * *** **** ** * * * **** * ** * * *** * ***** ****** * ** ** * == b[strlen(a)-1])
** * * * *** **** **** ** * ** ** * *** * * * **** * *** **** * ** * * * ** * ** **
** ** ** * ** ** * ** ** * **** ** * *** * *** * * * * * * ******* * * ** * * * *** * *** **** * * * * ** ** ** ** is a prefix of %s",a,b);
* * ***** ** * **** ** ** *** * * *** ***** ** ** **** * ** * *** * * ***** * * * ** ** ** *** ** **
* * * * * * * ** * * *** * * * *** *** * * ** * * * * * * *
*** *** ***** * **** * * * * * **** *
}
answered by (-301 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
#include<stdlib.h>
#include<string.h>
#define n 100

int aa(char a[],char b[]){
* * * * * * ** * * *** * i;
** * ** * * * ** *** *** ******* (a[0]!=b[0]){
*** ** * * *** ** ** * * * **** * * *** 0;
* ** *** ** * *** ** * *
* ** ** * * ** * * * ** * * ***
** ** * * * ** **** ****** ** ***** ******** * ** a[i]==b[i])
* **** *** *** * * * * * * ** ** * *****
** *** * * * *** * * ***** * ** ** **** * ****** ****** *** * 1;
* ** ** ** * * ** ** ** * ** * * * **** ** ****** * ** ** * * * * **** **
** **** * ** ** * ** ** * * * *
** * **** ** ********* * ** *
* **** ** * * ** ** *** 0;

}

int main(){
** **** * * ** * ** c[n],d[n],e[n];
*** **** ** * *** **** i;
* ** ** * * *** * ****** * ** %s",c,d);

** * * ** * * * *** *
*** * * *** * ***** * * * * ****** * ***** ** * is a prefix of %s",c,d);

** * ** * * * *
* ** * * * * * *** * ** ** * * * * **** * * * ** is not a prefix of %s",c,d);


}
answered by (-32 points)
edited by
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:108.162.216.229
©2016-2024

Related questions

1 like 0 dislike
37 answers
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42302 - Available when: 2018-01-17 14:00 - Due to: Unlimited
| 5k views
2 like 0 dislike
31 answers
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42301 - Available when: 2018-01-17 14:00 - Due to: Unlimited
| 4.5k views
1 like 0 dislike
32 answers
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42300 - Available when: 2018-01-17 14:00 - Due to: Unlimited
| 4.8k views
2 like 0 dislike
30 answers
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42298 - Available when: 2018-01-17 14:00 - Due to: Unlimited
| 3.7k views
0 like 0 dislike
4 answers
[Exam] asked Jan 19, 2018 in Final Exam
ID: 43460 - Available when: 2018-01-20 09:00 - Due to: Unlimited
| 943 views
12,783 questions
183,443 answers
172,219 comments
4,824 users