1 like 0 dislike
2.4k views

A string p is a prefix of a string s if the leading characters of s are identical to p. For example, "abc" is a prefix of "abcde". Develop a function prefix that checks if a C string p is a prefix of another C string s.

p是s的前綴若s開頭的一段字串等於p。例如,"abc"是"abcde"的前綴。寫一個程式 判斷字串p是否字串s的前綴。

Example input 1:

abc
abcde

Example output 1:

abc is a prefix of abcde

 

Example input 2:

bc
abcde

Example output 2:

bc is not a prefix of abcde

 

[Exam] asked in Final Exam
ID: 42299 - Available when: 2018-01-17 14:00 - Due to: Unlimited

retagged by | 2.4k views

37 Answers

0 like 0 dislike
Hidden content!
#include * ** ** * **
#include *** * * ***
* ** ** * * * **
***** *** *** *

int prefix(char a[], char b[]){
int i, j,n;
int cnt=0;

n= * ******* * *

**** **** * * ***** * *
* ** * * * * * *** * * *** == b[i]){
* * *** ** ****** * * ** **** * ******** * * **
** ** * * ** * *** ***** * * **

* * ** * * *** *
if (cnt == n){
**** * * *** ** *** * * ** **** ******** 1;
* *** ** * **** ** ** * ** * *** ** * * **** * *
**** * ** ****** * **** ***
* ** * ***** ** * * **** * * * * ** * *** 0;

}

int main()
{
* * ** * ******** s1[100], s2[100];
** ** * ** ** i,j;

*** * * * * * **** * *** * * s1);
*** ** * * ** * *** * *** * * ** * ** ** ***** s2);
*** * *** * ** **** * (prefix(s1, s2)){

******* ** *** ***** * *** *** **** ** ** * **** * * is a prefix of %s", s1,s2);
* ** * ** **** * *** ********* ****
* **** ** *** ** **** * * *
* * * * * * *** ******** ** ** ** * ** ** ** **** ****** ** * ** is not a prefix of %s", s1,s2);



}
answered by (323 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <string.h>

int main(){
** * * *** * ** **** * c;
***** ***** * ** ** *** a[100],b[100];
***** * * ** * * * * * ** ** ** %s",a,b);
* ** ** * ** *** ******** ** ** * * **
* *** * **** ** ** * ******* *** * *** 0;
* * * ***** *** * *** ** ** ** * %d",strlen(a),strlen(b));
***** * * *** * * * *** * * * ** **** * **
* * ** * ** * ** ** * * * *** * * *** * **** * ** **** ** **
** * **** * * * ** ** * * ** ** * * * * * *** * * *** * * * ** * ** * * * *** **** * * is not a prefix of %s",a,b);
* **** ** ** * ** * * * * *** ** * * **** * * * * *** ** *** ** * * *** * * * *** * ** *
* ** * ** ** * * * * **** *** * *** *** * ***** *** ** * * * **
* * *** ** ****** * * * *** * *** * ** ** ** * * ** * * * if(c==strlen(a)-1)
** ** * * * ** * * * * ***** ** **** * * *** ** * * * * ** ** ** *** * is a prefix of %s",a,b);
    }
*** * ** **** ***** *** 0;
}
answered by (-498 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <string.h>
int main()
{
* * *** * * *** * *** n,count;
*** * *** * * * ** ** * ** * * * ***** ****
* ** ** * * ** *** *** * * %s",a,b);
*** ****** * * * * * * * *

*** ***** ** *** *** * ** ***** ** *
* ** *** * * * **** * *
* * ** * *** * ** *** * * * * ** ** ** *
**** * *** * ** ** * *** *

* * *** *** ** (strcmp(a,c)==0)
* *** **** * ** * *
* * *** * ** **** ** * * ***** *** * *** ** * ** * * is a prefix of %s",a,b);
*** * * * ** * ***
* **** * * * * ** **
* ***** *** *** *
* ***** * * ** **** * ** ****** ** ** * **** * * * is not a prefix of %s",a,b);
* * ****** * * **
******** * ******* * 0;
}
answered by (-284 points)
edited by
0 0
prog.c: In function 'main':
prog.c:8:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s %s",&prefix,&word);
             ^
prog.c:8:16: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
     scanf("%s %s",&prefix,&word);
                ^
prog.c:10:15: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     for(i=0;i<strlen(prefix);++i)
               ^~~~~~
prog.c:10:15: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:10:15: note: include '<string.h>' or provide a declaration of 'strlen'
prog.c:18:6: error: expected '(' before 'printf'
      printf("%s is a prefix of %s",prefix,word);
      ^~~~~~
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
#include<string.h>
int main()
{
**** * * * * * * * * a[100],b[100];
* * **** * * *** * * * **** * * *
    int l1,l2;
*** * ** * * *** ***** ***
* * * **** ** * * *** * * * *
* ** * * * ** * *** ****
* * **** * * * * ** * ***** **** ** ******** ** * * ****** is not a prefix of %s",a,b);

    }
* *** * ** ** **** * if(l1<=l2){
**** ******* *** *** ** ** * ** *** * ** prefix=1;
*** * ** ** *** * ****** * * * * ** i=0;
***** **** *** **** * * **** * ** * * * * ** * * **** * *** *
* ** ** * * * *** *** *** **** **** * *** **** * ***** * * (a[i]!=b[i]){
** * **** * * * * * ** * ***** * * * * ** **** * **** * * * * ** * **** * * * ** * *
** ** **** ** *** * * * * * * * * * * ** ** ** ** ***** * * * * ** * * ** * * ** ** * **
* * * *** **** ** * ** * * ** * * * ** * * *** ***** * **


* *** * * * ** * * **** *** * * * ** *
** * * **** * * **** * ** *** ** * ** * *
** ***** ***** * * ** * ** **** * * ** ** **** * ** * * * **** * ** *** * is not a prefix of %s",a,b);
* ** * ** *** * * ***** * ** *** ****
* * * * **** ** * * **** * * *** * **
*** *********** * * * **** * *** ** *** * * * * * *** * is a prefix of %s",a,b);


    }


}
answered by (-329 points)
0 0
prog.c: In function 'main':
prog.c:5:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
             ^
prog.c:5:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
               ^
prog.c:7:8: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     l1=strlen(a);
        ^~~~~~
prog.c:7:8: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:7:8: note: include '<string.h>' or provide a declaration of 'strlen'
0 0
prog.c: In function 'main':
prog.c:6:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
             ^
prog.c:6:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
               ^
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
** * *** * * ** *
int main(void)
{

* * **** ** * ** * ** * pre[100];
* ** ** ** * *** * *** ** word[100];
* ** *** * *** ** * * ** %s",pre,word);
* * * *** ** * * * ** *****
** ** * ** *** * * ** ** * * * *

* ** * *** *** * ** * **** i;
* * * * ** * * * ** ** ********* * * *
* ** * ** * ***
****** ** *** **** ******* * * * * * *** * * * * * ** **
* * * * * ** * * * * * * *** * * ** *** **** * * *
* * * * * ** * *** * * ** * ****** ** * ** * ** * *** ** ***** is not a prefix of %s",pre,word);
** * ** ****** ** *** * ** ***** * * **** *** * * *** * * * ******* * 0;
* ** **** ** ** *** * * * ** * ******* **

* *** * ** ** * *
printf("%s is a prefix of %s",pre,word);
return 0;
}
answered by (-249 points)
0 0
prog.c: In function 'main':
prog.c:8:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&pre);
             ^
prog.c:9:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&word);
             ^
0 0
prog.c: In function 'main':
prog.c:8:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&pre);
             ^
prog.c:9:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&word);
             ^
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <string.h>
#include <ctype.h>
int main ()
{
**** * * ** * * *** ** pre [100],a[100];
** * ** * ** ** * **** * n ,i;
**** * *** * * * ** ** **
** * ** ****** * ****
** * ** * * *** *** * * ** * * * ***
*** * ****** ** **** * * ***
***** * * ** * ***** ** * ***** * ** ** ** (n=0;n<strlen(pre);n++)
* * * **** * * * * ** * ** ** * * ** * * *
** ** ** * **** ** *** * *** *** * * ** * * * ** * * * * (pre[n]==a[n])
* * * * * *** ** ** *** * ** * * ****** * * * * * * ** is a prefix of %s",pre,a);
* ** ***** ** * ****** *** * ** * *** * ** *** * * **** *
* * * ****** ** **** * * ** * * * * * ** * * * *** * * * * * ** * *** * * ** *** * * ** ****** * * *** * ** is not a prefix of %s",pre,a);return 0;
*** * * * * * *
** * * * * * * * ** * ** *** ************ **** * *** * * *

** *** * * ** * * * * * 0;
}
answered by (-32 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include * * ** * * * *
#include *** * ** * ** **

int main()
{
* *** ** ** * * ***** ** a[100];

* ** ******* * ** * * ** b[100];

* * * * * *** * %s", a, b);

** ** * * * * len_a = strlen(a);

* ** * * ** * i = 0;

* ** **** ** **** * *** flag = 1;

* ** * ****** * * * * = 0; i < len_a; i++)
* * ** ****** * *** ****
* * * *** * **** *** ** *** ** * ** ***** * * != b[i])
** * ** * * ** * * ** * ** *** ** *** * *
* * ****** * ** ** ** * ************ *** ** ** * *** * * * * ***** = 0;
* * ** ** * *** * * * ** ** * ** ** ****
** ** ** * **** *

* * ** * ** ** ** * **** ** == 0)
* * * *** ***** * **
* * * ** **** * * * ** ** ** **** * * *** *** is not a prefix of %s", a, b);
** * ** ** * **** * *
*** * * *** ** ** ***
*** ** * **** **** * * ****
* * *** **** * * * * **** *** ** **** ** * **** * ** * is a prefix of %s", a, b);
* * * **** ** *** *
* * * ****** * * * * 0;
}
answered by (-285 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
* ** * * * ******
int main()
{
* * ** * *** ** *** i,n;
** * * ** * ** * p[100],s[100],a[100]={};
*** ** *** * ***** * *** * * ** * %s",p,s);
** * *** * *** * **
** **** * *** * ** ** * ** ** *
* * *** * * ** ***** * ** ** * *** ** ** *
**** * *** * * ** ** * * *
*** ** **** **** * *** ** ** * * * * * is a prefix of %s",p,s);
** ***** *** ** ****
** **** * *** * * * ***
* * * * * *** * * * ** *** * *** ***** ********** * * is not a prefix of %s",p,s);
** ******* *** **
* * ** ***** ** ** * * * * * *
* ** * * *** *** ** * 0;
}
answered by (54 points)
edited by
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
#include<string.h>

int main()
{
    int i;
    char a[100];
    char b[100];
* * **** ** * **** * ** ** ** * * ** *
    scanf("%s",b);
    for(i=0;i<strlen(a);i++)
*** ** * ** ** * ** * **** *** *** *** *** **
* * * ** * ** ** * * * ** * **** ** ** * *** * * * **** ** ***** != b[i])
* **** * ** ** * *** ** * **** *** * * * **** * * * *** * *** * *** ** ** **
*** * * *** * *** ** * ** ****** * ** * * ** * * * * ** * *** *** *** ** ** *** *** * * ** ** * * * * * is not a prefix of %s",a,b);
* ** * *** ** ** ** * *** * * ** ** * ***** *** ***** * * ** * * **** * *** * * * **** * * *** * * * ****** **
* ***** * ** * ***** *** ****** * ***** * * * *** **** * * * * * * * * *
**** ** * * * * * * * ** * ** ** **** *** * * * ** * * ** * * * * * * ** *** == b[strlen(a)-1])
* * *** * *** *** * * ** *** *** *** *** ** **** **** * * * ** **
* * ** ** * * ****** * *** *** ** * ***** * * *** ** ** ** * ** ** ***** ** ** ** ** * ** * * * * * * * ** * * ** * is a prefix of %s",a,b);
***** ** * **** * * * ** * ** ***** * * * * ** ****** * **** * *** ** **** * * **** ** *** *** **
** ** * * * * * ** * * * *** * ** ** * * * ** *** *** * * * * ** * * * ** * * *******
*** ****** * *** * * * * ***** ***** *
}
answered by (-301 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
#include<stdlib.h>
#include<string.h>
#define n 100

int aa(char a[],char b[]){
** * * * **** * * * ** * i;
* * * ** * * ** * * * * ** * (a[0]!=b[0]){
** *** ** ** * *** ** ** * **** * **** * ** ** 0;
** ******* * ** ** * *** *
* ** * ** ** * ** * * ** * * *** * * * * ** **
* * * *** * ** * ** *** * * ** * * ** **** *** a[i]==b[i])
******* ** * * ** * **** ** * ***** * ***
* ********** * ** * * ** ****** * * ** * *** **** * ** ** ** 1;
* * * * * * * * ** ** * * * *** **** ** *** **** *** * * * *** * * ***** *
* *** * * *** * * * *** * ** * *
** * *** **** ***** * ***
*** ********* ** * * * * * * **** **** 0;

}

int main(){
*** ** * ** * ** *** c[n],d[n],e[n];
* ** ** * * * * ** i;
* * ***** *** * * ** *** * * * %s",c,d);

*** * ** **** * *** * *****
* ******* * * * * *** * ** * * * * ** ** * * is a prefix of %s",c,d);

*** * * * * ** ***** **
* *** * * * * * ** * ** *** * ** ** ****** * is not a prefix of %s",c,d);


}
answered by (-32 points)
edited by
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.58.18
©2016-2024

Related questions

1 like 0 dislike
37 answers
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42302 - Available when: 2018-01-17 14:00 - Due to: Unlimited
| 2k views
2 like 0 dislike
31 answers
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42301 - Available when: 2018-01-17 14:00 - Due to: Unlimited
| 2k views
1 like 0 dislike
32 answers
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42300 - Available when: 2018-01-17 14:00 - Due to: Unlimited
| 2.3k views
2 like 0 dislike
30 answers
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42298 - Available when: 2018-01-17 14:00 - Due to: Unlimited
| 1.7k views
0 like 0 dislike
4 answers
[Exam] asked Jan 19, 2018 in Final Exam
ID: 43460 - Available when: 2018-01-20 09:00 - Due to: Unlimited
| 468 views
12,783 questions
183,443 answers
172,219 comments
4,824 users