1 like 0 dislike
8.3k views

A string p is a prefix of a string s if the leading characters of s are identical to p. For example, "abc" is a prefix of "abcde". Develop a function prefix that checks if a C string p is a prefix of another C string s.

p是s的前綴若s開頭的一段字串等於p。例如,"abc"是"abcde"的前綴。寫一個程式 判斷字串p是否字串s的前綴。

Example input 1:

abc
abcde

Example output 1:

abc is a prefix of abcde

 

Example input 2:

bc
abcde

Example output 2:

bc is not a prefix of abcde

 

[Exam] asked in Final Exam
ID: 42299 - Available when: 2018-01-17 14:00 - Due to: Unlimited

retagged by | 8.3k views

37 Answers

0 like 0 dislike
Hidden content!
#include *** *** ***
#include * * **** **
**** *** * * * ** *
* ** * **** **** ***

int prefix(char a[], char b[]){
int i, j,n;
int cnt=0;

n= ** * ******

*** *** ** **** * * ** * * *
** **** *** * * * * * ** == b[i]){
* ** ** * ** * ** **** ***** * * *** *** **** *** *
* ** *** * ** * * * * *****

* * * * ***** *
if (cnt == n){
* ** ***** ** *** * ** * * ******* *** *** ***** **** 1;
* *** * ** * * * ** * * ** ** **
******* * * * * * * **
* ** * * * * *** * *** * * * ** ******** ** 0;

}

int main()
{
** * * * ** * s1[100], s2[100];
* * ** * * * i,j;

* ** * *** * * ********* * * * *** s1);
**** * ** * ** *** * ** *** * * *** *** ** ** s2);
*** ** *** ** * ** (prefix(s1, s2)){

******* * ** ** * * * ** ** * ** ** * * * * * is a prefix of %s", s1,s2);
* *** **** ** * * * * * * * *
** *** * * ** * * * * **** * *** *
* * * ** ** ** ** *** * * ****** * ** ** * * ****** ** is not a prefix of %s", s1,s2);



}
answered by (323 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <string.h>

int main(){
* * ** * *** *** ** ** c;
** ** *** ***** ** * * * * *** * a[100],b[100];
** ** ** * ** *** ** ***** * ** * %s",a,b);
* **** **** * ** * ****** **** ** * * ** *
** * * * * *** **** *** **** * *** ** 0;
* * ** *** ** *** * **** * * ** * * * %d",strlen(a),strlen(b));
** *** * * ** *** ** * ** * *** *
*** *** ** ****** * * * * ***** * ** * ** * * ***** ** * * * * **
* * * ** *** *** ***** ** * ** * ** * ** * * *** ****** **** **** ** ** * ****** ** * is not a prefix of %s",a,b);
* * ****** * * * * ** ** * * ** * * * ****** ** *** ** ** ** * * * * ** * * ** *
**** ** ** * * * *** * ** * ** **** * ***** ** ** **** * *
* * *** ** ** ** * **** ** **** * * * ****** * * *** * * ** * ** * if(c==strlen(a)-1)
* ***** * ********* ** ******* * ******* * * *** * **** *** * ** ****** *** ** *** * ** ** * is a prefix of %s",a,b);
    }
* *** ** * ****** * * *** 0;
}
answered by (-498 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <string.h>
int main()
{
* * ** ** ** * * * n,count;
* * * ** * ** ** ** ** * ** * *
****** * ******* * ***** %s",a,b);
* * * ***** * ** *

* * * ***** * * ** * * * ** * ***
**** *** ** *** ** *****
**** * ** ** * * ***** * * ** * ***** ** *** *** ** *
** * * **** * *

* *** * *** * * * ** (strcmp(a,c)==0)
* ** * ** * * * *
** * **** *** *** * * ** * ** ** * * *** * *** * * * is a prefix of %s",a,b);
* * * * ** * **
*** * * ***** * * * * * * *
** * *** ** ** ** **
*** ********* *** * *** ***** ** ** * *** **** ** ** is not a prefix of %s",a,b);
**** ** *** * ****
** * *** ** **** ** * * * 0;
}
answered by (-284 points)
edited by
0 0
prog.c: In function 'main':
prog.c:8:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s %s",&prefix,&word);
             ^
prog.c:8:16: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
     scanf("%s %s",&prefix,&word);
                ^
prog.c:10:15: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     for(i=0;i<strlen(prefix);++i)
               ^~~~~~
prog.c:10:15: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:10:15: note: include '<string.h>' or provide a declaration of 'strlen'
prog.c:18:6: error: expected '(' before 'printf'
      printf("%s is a prefix of %s",prefix,word);
      ^~~~~~
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
#include<string.h>
int main()
{
*** ** ******* ** *** * * a[100],b[100];
** *** * * * ***** * ** * *** **** **
    int l1,l2;
* * * ** * ** ****** * ** * ** *
* ** **** * * * * * ** *
* *** ** * ** * ** **** * **
**** * **** ** *** * * **** *** *** ****** * * * *** * ** is not a prefix of %s",a,b);

    }
*** * *** *** ** ** if(l1<=l2){
* *** ** * *** * *** *** * *** * * * * * prefix=1;
**** ** ** * ******* **** ** ** * i=0;
* * *** * *** * ***** *** **** * * * ******** * * ** *** * *
** **** ** **** * * * ** *** * * * * * **** * *** **** * * * ** (a[i]!=b[i]){
***** * * * * * ** * ** ** *** **** *** ** * ** ** * * ** * ***** ****** ***** ***
** **** * * * ** ***** **** * * ** * *** ** * * *** ** * **** * * **** * * *** ** * *
**** * * * ** * ** *** * * * * * **** ** *** * ***** *** *** *


*** * ***** ** ** ** *** * ** *** *** * *
** * * * *** ***** * * * * *** * *** **** *** *
******* * ** * ***** ** *** * * * *** **** ******** * * * *** * *** * * ** is not a prefix of %s",a,b);
*** * * *** * *** * * * * *** * ** * *****
** * ** * ** * ** * *** ** ** * ***** *
**** *** * ** ** ******** * **** *** * ** * * ** ** * * * is a prefix of %s",a,b);


    }


}
answered by (-329 points)
0 0
prog.c: In function 'main':
prog.c:5:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
             ^
prog.c:5:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
               ^
prog.c:7:8: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     l1=strlen(a);
        ^~~~~~
prog.c:7:8: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:7:8: note: include '<string.h>' or provide a declaration of 'strlen'
0 0
prog.c: In function 'main':
prog.c:6:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
             ^
prog.c:6:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
               ^
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
* *** * ** ***
int main(void)
{

* ** ** ** * * * * pre[100];
* ** ** ** ** ** * * * * word[100];
* *** *** * **** * ** *** * %s",pre,word);
** * ** * ** * *** *** ** *
** * * ** * * * *** * ** ***

* ** * * * * ** * ** i;
** * ** *** * * * ** * ** **
***** * * ** ** * *
*** ** ** * ** * ** * * ** * ** * *** **** *
* *** *** * ** * *** *** *** * ** ***
** ** *** * ** * *** ** **** ** ****** * * * ** * ** * * * ** ** * * * ** * is not a prefix of %s",pre,word);
* * **** * * * * *** ** * * * *** * ** ** ** *** ** ** * * *** *** 0;
** ** * * * * * **** **** ** * * * * * **** **

* ** * *** * * * *
printf("%s is a prefix of %s",pre,word);
return 0;
}
answered by (-249 points)
0 0
prog.c: In function 'main':
prog.c:8:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&pre);
             ^
prog.c:9:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&word);
             ^
0 0
prog.c: In function 'main':
prog.c:8:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&pre);
             ^
prog.c:9:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&word);
             ^
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <string.h>
#include <ctype.h>
int main ()
{
* *** ** * *** * ** pre [100],a[100];
*** ** ** * ** ** * n ,i;
* ** ** * ** ** **** *** **** *
* * * *** * * ***** ** * ** *
* * *** * ** * ** * * * *
* * ** ** * * * ** * *
** **** *** ** * ** *** * * * * * * ** * * (n=0;n<strlen(pre);n++)
*** **** * * * *** ******* *** ** **** *****
** ** ** ** **** * ******* * ** * * ** *** * * ** * ***** * * *** *** * ** (pre[n]==a[n])
* ***** * * ***** *** ** ** *** *** *** *** *** ******** * * is a prefix of %s",pre,a);
** *** * * * *** ** * ****** *** * * ** * ** * * * *** ***
* * *** **** **** ** ****** * * * * * * * ** * * *** *** * ***** * **** * **** * * ** * * is not a prefix of %s",pre,a);return 0;
* ** * * ***
** * * *** ****** * ** * * * * * * * * *** * *****

** *** * * ** * ***** 0;
}
answered by (-32 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include * * * * *
#include * * * **** ** *

int main()
{
** *** ****** *** * ** a[100];

***** * ** * **** * ** b[100];

** ** * * ** ****** ** ** * %s", a, b);

****** * * **** *** len_a = strlen(a);

* *** *** *** *** *** * i = 0;

** * * **** * flag = 1;

* **** * * * * * ** * * * = 0; i < len_a; i++)
** ** ** *** * ** *
** * * * * ** * * * * * * * * != b[i])
* ** *** * * ****** * *** * * *** *
* ** **** **** ***** *** * ** * * * ** * ** *** *** * * ** * = 0;
* **** * *** * * ***** *** ** *** * ****** ****
*** * **** * * * * * ***

******** ** * *** * ** * == 0)
* * * ** * * *
** * * * * * * * ****** * * **** ** * ** * ** * * * is not a prefix of %s", a, b);
** * ** * * ** * ** * *
** ***** * * * * * ** *
* ** *** * ** * ***
* ** * * **** ** *** * ** * ** ** *** * ** ****** * *** * * * * is a prefix of %s", a, b);
** * ** * ** * * ** *
** *** * **** * ***** *** *** 0;
}
answered by (-285 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
* ** *** ** ***
int main()
{
* * ******* ** ** i,n;
***** *** *** * * ****** p[100],s[100],a[100]={};
*** *** **** **** * ** ******* %s",p,s);
** * ***** *** * ** ** *
* * * * * * *** ** **** *
* * * **** *** * ** * ***** * ** **
*** ** ** *** ** ** * *** * ***
* ** * **** ********* **** * ** * ***** * ** *** * *** is a prefix of %s",p,s);
**** * * ** **
* ** ** * ** * * * *****
* *** * ** * **** ** *** *** ** ** * * **** * is not a prefix of %s",p,s);
* * * * ********* * * ** **
* * * * ** * * ** ****** * ****** * * ** *
* *** * **** ** ** * * * 0;
}
answered by (54 points)
edited by
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
#include<string.h>

int main()
{
    int i;
    char a[100];
    char b[100];
*** *** * **** *** * * *** * * **** **
    scanf("%s",b);
    for(i=0;i<strlen(a);i++)
* ** **** ** * * ** * ** * * *** * ** *
**** * *** ** * * * ** *** * * ** ** * **** * ** * *** *** * != b[i])
***** * ** **** * * ***** * ** * *** ** *** * * * * *** ** * **** * **** ** * ***
* ** * ** * ** ***** * ** * ** * * * * ** **** **** **** * *** * ** * * * * **** * * * * ** * *** * * * ** * ** is not a prefix of %s",a,b);
** * **** * ** **** ** *** ** *** * *** * ** * **** * ** *** **** *** * **** * *** **** **** * * **
**** ** ** **** * **** ** * *** * * **** * ** * * *** *** * ****** **** * *** * **
* *** * *** ** * ** * * *** * * ** ******* * * ** **** * *** * *** * *** * == b[strlen(a)-1])
*** * ** * *** * **** ** * * * * *** * ** * * ** * ** * ** ** * ** * ** * * * ** **
*** ***** * ** ** ** ** **** *** *** ***** * ** * ** * * ** **** ********** * ** ** * * **** * **** * is a prefix of %s",a,b);
* ** * * ***** * * * * ** * ** **** * * *** * * * * ** ***** *** ** ******** * * *** **** * *** * ** *** ***** *** * **
*** * **** * *** ** ** * * * ** *** **** ** * ***** ***** ***** *** * *** * *
* ** ***** * ** * ** **** *** ***
}
answered by (-301 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
#include<stdlib.h>
#include<string.h>
#define n 100

int aa(char a[],char b[]){
** * * ** * * * ** ** * *** i;
**** ********* *** ******* * (a[0]!=b[0]){
******* ** * ** * ***** ** * * ** * ** * 0;
** * * * ** * ** ** * ****
*** * ******* *** ***** * * *** * * **
* * *** * ** * * * * * * * * ** ****** ** a[i]==b[i])
** ** * * ** * **** **** ** ** ****** **
* * * ** * * * ** * *** **** ** * *** *** **** *** *** * * * 1;
** *** **** * * **** * * * ***** * * * ***** *** ** ** ** ** **
* ** * * ** ** * ** **** *** * ** **** * **
** ** * * ** * * ** * ** *
** * * * **** ** * * * * * *** 0;

}

int main(){
* * * * * *** * *** ** ** * *** c[n],d[n],e[n];
** * * * * ** * *** *** ** i;
*** *** * ** ** * *** * * * *** %s",c,d);

** * * * * * *** * *
* ***** *** *** *** *** **** * * *** ***** * * ** * is a prefix of %s",c,d);

* * * *** ** * **** *
* *** ** **** ** ** * ** * * ** * * * * ** is not a prefix of %s",c,d);


}
answered by (-32 points)
edited by
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.17.119
©2016-2025

Related questions

1 like 0 dislike
37 answers
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42302 - Available when: 2018-01-17 14:00 - Due to: Unlimited
| 8.6k views
2 like 0 dislike
31 answers
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42301 - Available when: 2018-01-17 14:00 - Due to: Unlimited
| 7.5k views
1 like 0 dislike
32 answers
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42300 - Available when: 2018-01-17 14:00 - Due to: Unlimited
| 8.7k views
2 like 0 dislike
30 answers
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42298 - Available when: 2018-01-17 14:00 - Due to: Unlimited
| 6.7k views
0 like 0 dislike
4 answers
[Exam] asked Jan 19, 2018 in Final Exam
ID: 43460 - Available when: 2018-01-20 09:00 - Due to: Unlimited
| 1.6k views
12,783 questions
183,442 answers
172,219 comments
4,824 users