1 like 0 dislike
16.7k views

A string p is a prefix of a string s if the leading characters of s are identical to p. For example, "abc" is a prefix of "abcde". Develop a function prefix that checks if a C string p is a prefix of another C string s.

p是s的前綴若s開頭的一段字串等於p。例如,"abc"是"abcde"的前綴。寫一個程式 判斷字串p是否字串s的前綴。

Example input 1:

abc
abcde

Example output 1:

abc is a prefix of abcde

 

Example input 2:

bc
abcde

Example output 2:

bc is not a prefix of abcde

 

[Exam] asked in Final Exam
ID: 42299 - Available when: 2018-01-17 14:00 - Due to: Unlimited

retagged by | 16.7k views

37 Answers

0 like 0 dislike
Hidden content!
#include ** ** *** * * ** **
#include * * * *
** ** ** * *** * *
* * ** **** *

int prefix(char a[], char b[]){
int i, j,n;
int cnt=0;

n= * ** ****

* * ***** * *** * ** * * * *
** * ** *** * *** ** * * * == b[i]){
*** ** * ** * * * * * * ** * ******** ** * **
* **** * **** * **** *** *

* * **** ***** * **
if (cnt == n){
** ** **** ** ** * ****** * ** * * *** ** 1;
**** ** * ** ** **** * * * * * * **
** **** **** * * ** ***
** * * ** * ***** ***** * * * * * * * ******** *** 0;

}

int main()
{
**** ** * * * ** * *** s1[100], s2[100];
** * ** * * * * i,j;

** **** * * * * *** * * *** * ** * s1);
*** *** ** *** ** ** * * * * * s2);
*** * * *** *** * * (prefix(s1, s2)){

* **** * * ** * ** *** * * **** *** ** * **** * ** * is a prefix of %s", s1,s2);
** *** * ** * * ** * * ***** ** *
* **** * *** ** ** * * **** * ** * *
*** * * *** * * * *** *** *** * ** * *** * * *** **** is not a prefix of %s", s1,s2);



}
answered by (323 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <string.h>

int main(){
* ** * ** * ** ** ** ** c;
** ** ******** ** ** a[100],b[100];
* ** * **** * * ** * * * %s",a,b);
* ** * *** ** * * * * ** ** *******
* * * * **** * ****** ******* *** **** * * ** * ** 0;
***** * * * ** * ***** * ** * *** ** %d",strlen(a),strlen(b));
*** * * **** ***** ** * ***** * * * *
* * *** * ** * ** ** * * * * **** ** * *** * ** ** ** * ** ****** * * *
* **** * * ** * ** *** ** ** * * * ** * * * * ********* * *** * * * **** * ** *** * * ** * ** is not a prefix of %s",a,b);
* ** ** *** * * * **** ***** **** * * *** ** ** **** * ** ** ****** ** ** ** * ** * ** ** * *
* * ** ****** ** ** ********* * *** * ** ****** * *** ** * * * ***
* ***** * ** *** ***** * * * * ***** * *** *** **** * **** if(c==strlen(a)-1)
* * ** ** ** ***** *** ** **** * * *** * ** ** ** * ****** * * * **** **** *** * * * * is a prefix of %s",a,b);
    }
* * * ** * * *** ** * * * 0;
}
answered by (-498 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <string.h>
int main()
{
* *** *** * * ** **** n,count;
* **** * * * **** * * ** * * ** ** *
* ** ** *** **** ** * **** **** %s",a,b);
*** * ** *** *** * *** **

* *** * ******* * * * ** * ****
** * * * **** ******** **
* *** *** * * * ** * * * * * * * * **** *** ** *
* * * ** ** ***

* ** ** * * * ** (strcmp(a,c)==0)
* ** ** ** *** *
* ** **** * *** **** **** ******* *** * * **** ** is a prefix of %s",a,b);
* * * ** * * *
** * * ****** * *** *** *
*** * * ** ** **** ****
* * ** **** ***** ** *** *** ** * ** * * ***** ********* * is not a prefix of %s",a,b);
* * * * *** *** ** * **
* * **** *** * * 0;
}
answered by (-284 points)
edited by
0 0
prog.c: In function 'main':
prog.c:8:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s %s",&prefix,&word);
             ^
prog.c:8:16: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
     scanf("%s %s",&prefix,&word);
                ^
prog.c:10:15: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     for(i=0;i<strlen(prefix);++i)
               ^~~~~~
prog.c:10:15: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:10:15: note: include '<string.h>' or provide a declaration of 'strlen'
prog.c:18:6: error: expected '(' before 'printf'
      printf("%s is a prefix of %s",prefix,word);
      ^~~~~~
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
#include<string.h>
int main()
{
*** ** * * * * * ** * * a[100],b[100];
*** ** ** *** ** ** ** ** * * *** ** *
    int l1,l2;
** *** * ** * *** * ** * **** *
** * ** ** ****** * ******
**** * ** * *** *** ** ** ** * * * *
** * ** * * * * * * * *** *** *** * * ** *** ** * * is not a prefix of %s",a,b);

    }
* * * *** * ***** * if(l1<=l2){
* * ** ***** * ** * ***** * *** * * * **** **** ** ** prefix=1;
**** * * * ** **** * ** * *** ** ** ** ** * ** i=0;
** * * ***** ** * ** * ** ** * * ** * ** ** ** *** *
* * *** * ******* ** *** * *** * ***** ** * * * * * * ** ** ** * (a[i]!=b[i]){
** * ** * *** ** * * ** * *** * * **** * * * * ** ** ***** * ** ** * * * *** ** ***
** * *** * * * ****** * * ** ***** * **** * *** ** * * ** * **** ** * *** **** ** *
* * * * ** ****** * *** * *** * * * ** ** ** * * * * ** * * *


* ** * * ** ** ** * ** ******** * * * * ** * *
**** ** *** * ** * *** * ** * *** * *** ***
* ** ** *** ** * * ** * *** * ** ******** ** ** * ** * * * ** ***** ** ** * is not a prefix of %s",a,b);
** * *** * *** *** *** * *** *********
* * ***** * *** ** *** **** ** * * * * * ** *
** * *** **** **** * * ***** * * ***** * ** * * *** ** is a prefix of %s",a,b);


    }


}
answered by (-329 points)
0 0
prog.c: In function 'main':
prog.c:5:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
             ^
prog.c:5:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
               ^
prog.c:7:8: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     l1=strlen(a);
        ^~~~~~
prog.c:7:8: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:7:8: note: include '<string.h>' or provide a declaration of 'strlen'
0 0
prog.c: In function 'main':
prog.c:6:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
             ^
prog.c:6:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
               ^
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
* * **** *
int main(void)
{

* ** * * *** ** * *** pre[100];
* *** ** * * ********* *** ** word[100];
** *** *** * ** **** *** *** %s",pre,word);
** *** * *** * * * * * ** * ** * *
* * * ** * * * *** * * **** * * *

* ***** ** ** * *** i;
** *** ** *** * *** *** * ** * **** * **
** **** * * * *
**** *** **** * * * * * **** * ** * *** ** * * ***** **** *
* ** * *** ****** * * * * * * * *** *** ***
* ** ** ** * * * ** ** ** ** * * * * *** ** **** **** ** *** * ***** ** ** is not a prefix of %s",pre,word);
** ***** * * ** * ** * * ** ** * * *** ***** * * * *** * ** * *** * 0;
* * * * *** ** * ***** * ** * ** *

* ** ** * ** * * *** * *
printf("%s is a prefix of %s",pre,word);
return 0;
}
answered by (-249 points)
0 0
prog.c: In function 'main':
prog.c:8:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&pre);
             ^
prog.c:9:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&word);
             ^
0 0
prog.c: In function 'main':
prog.c:8:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&pre);
             ^
prog.c:9:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&word);
             ^
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <string.h>
#include <ctype.h>
int main ()
{
** * * ** * * ** * pre [100],a[100];
* *** ** ****** n ,i;
* *** * * ** ** *** * *** * **
** ** *** * * * * * *
* * * **** ** * * ** * * * * *** * * * **
** * *** ** * ** * *
** *** * * * * * ** * ** ***** ** ** * (n=0;n<strlen(pre);n++)
*** * ** * ** ***** ** ** ** * * * ** * ** ** *
* ***** * ** * *** **** ** * *** ***** ** ** * ** ** **** ******* * (pre[n]==a[n])
* * * *** * * **** * **** ** *** * ** ** * * * * ********** * *** **** is a prefix of %s",pre,a);
** * * * * * * * **** ** * * * * ** * * *** * * ** ** **
****** * ** ** ****** * * *** * * * ** ** *** * * * * * ** ** * * * *** *** **** ** ** * ** ***** ****** ** is not a prefix of %s",pre,a);return 0;
** ** ***
*** ** *** * * * **** ***** * **** * **** * * ** * * ** ** *

** ** * *** ** * * *** * *** 0;
}
answered by (-32 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include *** *** *** **
#include * ** ** * **

int main()
{
* ** *** ** *** * *** *** a[100];

**** * * * * ** ** b[100];

*** ****** ** * * * ** * ** * ** %s", a, b);

** * *** **** ** len_a = strlen(a);

* *** * ** * **** ***** i = 0;

* * ** * ** **** * * * flag = 1;

** * * ** ** *** ** * = 0; i < len_a; i++)
* * ** * *** * ** * **
** *** ** * ** ** * ***** * ** ** * * != b[i])
* ******* * * *** ** ** * ** * ** **
** * *** **** ***** **** ** ** ** **** * ** * * * * ***** = 0;
* * *** **** ** *** ** *** * ** * * * **** *
* * * * * * * *** **

* ***** ** ** * *** * * * * *** == 0)
** * ** * * * *
* **** * * * *** ********** ** * ****** * * ** is not a prefix of %s", a, b);
******* * * * **** *
* * ** **** * * **** *
* **** ** ** * * **
* * ** **** * * * * **** ** * *** * *** * ** ** ** * * is a prefix of %s", a, b);
* * * ** * * *******
* * ** * * * ************ 0;
}
answered by (-285 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
** * * *** ** * *
int main()
{
**** * * * ** ** * ** **** i,n;
* ***** * * * * ** p[100],s[100],a[100]={};
* * ** * * *** ***** * %s",p,s);
* * ** *** ** ** ** * *** **** *
** ****** *** * * **** * ** ** *
* * ** ** * ** ******* * ** * ** ** *
** * * * ****** ** * * * *** ***** *
* * ** ** ** ** * * **** * * **** **** * * * is a prefix of %s",p,s);
* ** ******* * * * * *
** **** ** * *** * * * * *
* * * ** * ** **** ** **** * **** * * ** ** is not a prefix of %s",p,s);
* * * ** * ** *
** ****** ** **** * ** ** ** * ** * * *
* ** * ** ** ** ** * * *** 0;
}
answered by (54 points)
edited by
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
#include<string.h>

int main()
{
    int i;
    char a[100];
    char b[100];
* ** * *** * * * ***** *** * ** * ** ***
    scanf("%s",b);
    for(i=0;i<strlen(a);i++)
* ******* **** * * **** * *** * ** ** ** ***
** * ***** ** ** * * ****** **** * * ** *** ** * * * * ** ** != b[i])
******** ** ** ***** *** ** * ****** * * * * ** * * * * * *** * **** * ** * * * * * *** *
* *** ** * ** ** * * *** *** ** **** * ** * * * * ***** ** *** * * ** * ** *** * ** * * **** * *** ** is not a prefix of %s",a,b);
**** * * ** * * ** ** * ***** ***** * **** * * ** ** *** ****** ** * * **** * * * ** ****
* ** * ** ***** ** ******** * ***** * *** * * * ** ********** * ** * * * * ***** * ** * ****
* * ** **** *** * * ** **** * ** ****** * ****** * ****** * * ** ** == b[strlen(a)-1])
*** * *** ** * ****** * *** **** * * *** *** * ** **** * ** * ** ** * ** * ** ** ******* *** *
** * * ** * ** * **** **** * **** * * ** ** ******** * ** * * ** ** * ** * ****** * * * * **** * * *** * is a prefix of %s",a,b);
* **** * * ** ** * * * **** ** * ** ** ** * ** * * ** ** * * ** *** **** * * * ** * *** ** * * * *** * **
* * * * ** * ** **** ****** **** * *** *** ** * * ** ****** ** * * * * ** * **
* *** * * * * *** **** *** * *** ***
}
answered by (-301 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
#include<stdlib.h>
#include<string.h>
#define n 100

int aa(char a[],char b[]){
** * *** ** * ***** ***** * * * i;
** *** ** * * * ***** * * * (a[0]!=b[0]){
** ** * ** **** *** **** * ** * * ** 0;
* ** *** * *** * *
**** * * ** * * ** ** *** *** **
* * * ** **** * ** * ** ** *** * * ********* ** * a[i]==b[i])
*** * **** * *** * ** * ** *** * *** **
** ** * **** * * ** * * * * * * * *** **** **** *** **** **** **** 1;
* * ** ** ******* * * * * * * ******** ** * * * * ***** ********* **
** * ** *** * * * * ** * **** **** * ** *** *
* * * * * ***** ** ** ** **
* * ** * *** ** * * ** *** **** * * 0;

}

int main(){
*** * *** ** * * ** **** * c[n],d[n],e[n];
**** ***** * * * * i;
* *** * * * * * *** %s",c,d);

** * ***** ***** ** * * *** * *
* *** ** * ** ** *** * * * * ******* ** ** * is a prefix of %s",c,d);

* * * *** * * **
** * *** * ***** * * * * * * * **** * ** *** is not a prefix of %s",c,d);


}
answered by (-32 points)
edited by
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:104.23.197.95
©2016-2026

Related questions

1 like 0 dislike
37 answers
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42302 - Available when: 2018-01-17 14:00 - Due to: Unlimited
| 15.1k views
2 like 0 dislike
31 answers
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42301 - Available when: 2018-01-17 14:00 - Due to: Unlimited
| 14.3k views
1 like 0 dislike
32 answers
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42300 - Available when: 2018-01-17 14:00 - Due to: Unlimited
| 17.9k views
2 like 0 dislike
30 answers
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42298 - Available when: 2018-01-17 14:00 - Due to: Unlimited
| 12.5k views
0 like 0 dislike
4 answers
[Exam] asked Jan 19, 2018 in Final Exam
ID: 43460 - Available when: 2018-01-20 09:00 - Due to: Unlimited
| 3.2k views
12,783 questions
183,442 answers
172,219 comments
4,824 users