Final Exam 2 (20%)

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A string p is a prefix of a string s if the leading characters of s are identical to p. For example, "abc" is a prefix of "abcde". Develop a function prefix that checks if a C string p is a prefix of another C string s.

p是s的前綴若s開頭的一段字串等於p。例如，"abc"是"abcde"的前綴。寫一個程式 判斷字串p是否字串s的前綴。

Example input 1:

abc
abcde

Example output 1:

abc is a prefix of abcde

 

Example input 2:

bc
abcde

Example output 2:

bc is not a prefix of abcde

 

[Exam] asked in Final Exam
ID: 42299 - Available when: 2018-01-17 14:00 - Due to: Unlimited
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Hidden content!
#include   ** * ** * **  
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int prefix(char a[], char b[]){
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}
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Hidden content!
#include <stdio.h>
#include <string.h>

int main(){
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}
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Hidden content!
#include <stdio.h>
#include <string.h>
int main()
{
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}
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prog.c: In function 'main':
prog.c:8:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s %s",&prefix,&word);
             ^
prog.c:8:16: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
     scanf("%s %s",&prefix,&word);
                ^
prog.c:10:15: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     for(i=0;i<strlen(prefix);++i)
               ^~~~~~
prog.c:10:15: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:10:15: note: include '<string.h>' or provide a declaration of 'strlen'
prog.c:18:6: error: expected '(' before 'printf'
      printf("%s is a prefix of %s",prefix,word);
      ^~~~~~
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Hidden content!
#include<stdio.h>
#include<string.h>
int main()
{
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    }


}
answered by (-329 points)
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prog.c: In function 'main':
prog.c:5:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
             ^
prog.c:5:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
               ^
prog.c:7:8: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     l1=strlen(a);
        ^~~~~~
prog.c:7:8: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:7:8: note: include '<string.h>' or provide a declaration of 'strlen'
commented by (4.3k points)
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prog.c: In function 'main':
prog.c:6:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
             ^
prog.c:6:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
               ^
commented by (4.3k points)
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Hidden content!
#include<stdio.h>
     * * *  **    ** **
int main(void)
{

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printf("%s is a prefix of %s",pre,word);
return 0;
}
answered by (-249 points)
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prog.c: In function 'main':
prog.c:8:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&pre);
             ^
prog.c:9:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&word);
             ^
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&pre);
             ^
prog.c:9:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&word);
             ^
commented by (4.3k points)
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Hidden content!
#include <stdio.h>
#include <string.h>
#include <ctype.h>
int main ()
{
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*   *** *     ***** *  ** 0;
}
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Hidden content!
#include <stdio.h>
#include  ** * *   **** *
#include **** *    *** ** 

int main()
{
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** * **    ** ** ** ** **** **
*** * * * **  * *** ***** **  ** 0;
}
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Hidden content!
#include<stdio.h>
  *   ***    *  *** 
int main()
{
 * ***      *** ***  *  i,n;
** *** * **  * * ***     *** p[100],s[100],a[100]={};
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*    ****** *       * *  ** 
*** ******* *  *     * * * ** * * *     ** *  ******  *
*  ****    *   ***  * *    *    0;
}
answered by (54 points)
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Hidden content!
#include<stdio.h>
#include<string.h>

int main()
{
    int i;
    char a[100];
    char b[100];
   **  * * ** * * *** ***   **  * ** * *** * * ***  *  
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    for(i=0;i<strlen(a);i++)
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*****   *   * * ** * * *      *  ***  *** * **    *  *** *** * * ** * * *   * **  **   *** ** * *  **  *   *** 
*   *  * **  ** **    *   ** * **  ** * **   * * *     ***
}
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Hidden content!
#include<stdio.h>
#include<stdlib.h>
#include<string.h>
#define n 100

int aa(char a[],char b[]){
* *  * ** * **  **      *       * ***  ** i;
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  *  * * * *** **** **** ** *  *       *  *    ****** 0;
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 *  *      ** ****  **** *****  ***  **   *** * * ****   * ** **  a[i]==b[i])
* **    * ***  ****** *** **  ***** *   **   *** *  ** *  **  
  * * *** *   * *     **   ***  * **  * * ** ***  * *****       *   *  * * ***   1;
    ** ** *    **     **** * * *   ***** *   *  *** *  **     *    *  *   ** * **** *
 **       *  *  ***  *******  ******       * *  ** 
 ***    **  **  ** * ****    * *   ** 
** *  ** **    * **      * ** *****  0;

}

int main(){
*  **  **    *  * *   ****   *  c[n],d[n],e[n];
 ** *    **    **   ** * i;
 **  *** ** * * * *    * **  *    *** %s",c,d);

*  *****  ** ***** ****  *****
***  * * * *   ****  ********  * * *   *****     *     **    *  is a prefix of %s",c,d);

** *****  ** **    * ** *    **
*    * ** * * ***    *  *  ******  **  * * *  **     *  *  * * ** ** *  is not a prefix of %s",c,d);


}
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