Final Exam 2 (20%)

1 like 0 dislike
15.5k views

A string p is a prefix of a string s if the leading characters of s are identical to p. For example, "abc" is a prefix of "abcde". Develop a function prefix that checks if a C string p is a prefix of another C string s.

p是s的前綴若s開頭的一段字串等於p。例如，"abc"是"abcde"的前綴。寫一個程式 判斷字串p是否字串s的前綴。

Example input 1:

abc
abcde

Example output 1:

abc is a prefix of abcde

 

Example input 2:

bc
abcde

Example output 2:

bc is not a prefix of abcde

 

[Exam] asked in Final Exam
ID: 42299 - Available when: 2018-01-17 14:00 - Due to: Unlimited
retagged by | 15.5k views

37 Answers

0 like 0 dislike 
Hidden content!
#include ** * *     *   * 
#include     ***  *     *
 * ***  * *  *        * 
*        **      *   **

int prefix(char a[], char b[]){
int i, j,n;
int cnt=0;

n=     **    * 

* **  ****  ** ***  ** *   ***** *****  * *
 * *  *** * **  **   * *  * * **   * == b[i]){
*    ********* ***  * ***   * ** **  **     **** *    *   
* *   * *  *  * *    **  *

  ****    **  *** **
if (cnt == n){
**    *      *        **  *      *    ***  *  *   *    ** *   * 1;
* ***     *** *** * ***     * **  *     **  *  ***** **  *  *  ** 
 * ****  *    * *** ** * **  *
      ** ****** ** ***    *****   * * ****  * ***  **  0;

}

int main()
{
   *  *  **  * * ***  *** s1[100], s2[100];
* * ***    *  *** **  i,j;

**  *    **** *     * * * * **  ** s1);
   * *      *     ***  ** * * ****    ***    * *  * ***  s2);
  ** * **   **  **  * ** (prefix(s1, s2)){

*     **  * **  *      ***     ** ** ** **  *  ** *   ***  *   is a prefix of %s", s1,s2);
 ** *  * ***   ** **   **** * *  ** **    * *   
*** **** ***   *    *    *    ** * *  ** **** *** **
  * * * *  ***   *****  **  ***  * *   ** * * ********    *  **** **   **    *  is not a prefix of %s", s1,s2);



}
answered by (323 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <string.h>

int main(){
     * ** ** * * **  * *  *    *** c;
* * * *   * *** **** *** *  a[100],b[100];
   *  * *  *   *   ***  ** *  * * %s",a,b);
* **  * *  *   *      * * *  ** * ** ***** *
*  ** * ** **  ** **** **** ***  * *** **    ***  **  ***  *** * 0;
 *  *  ** ** ****  **  **  ** ** *   %d",strlen(a),strlen(b));
* *  **** ** * *   *     *  *   *** * *
 *  ***          *  *   **** * ****    **  ** ****  **** ** ***   **** **    ** **** ****  *** *  *
 * ****  ****    * ** * *     *   *** *** ** * * ** **  * ****  ***  ** *   *    * *  *  *  **** **** **   *  *** ** *****   is not a prefix of %s",a,b);
**  *  *** **    *** ** ** *        * * *  * ***  * * **   ** ***   *   * *    * ****** ** *     *******  **
*   ****** **  *  *   * * * *      *******  *  * *  ***       **      *  *
 * ** * **   * ****   *** ****** *  **** *       *** **  *   * * *    * * * **   * * * * if(c==strlen(a)-1)
** ** * ** *** **  *   * ***** *****   * **** ***** *  *** *  **  * ***  ** **  *  * **  * ***      * * *   ***** *  *    ** *   is a prefix of %s",a,b);
    }
 * * * ***  *   ***   *  * * 0;
}
answered by (-498 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <string.h>
int main()
{
*   ******* *    *   **     * * n,count;
 ***  *** ** *   ** **   *   **  *  ****  ***  *
*  ***** ** **      ***  * * ** *   **  * %s",a,b);
  *    * *  ***** ****     *  ***  *

*  *    ** * * *** ** *   **  ** ***  ** * ***   * *
* ***   * *    *   *** ** ** 
 * ** ****    * ***   ****     * * ***  * ****** *****   **  *  **
 ***  **  *  *   * *   **

**** ***   * ** * *   **** (strcmp(a,c)==0)
** * ***  ** *   *** ** *  ****
 * * * ****  *** * ** * *  ***  * * **    *  **** * * *  ** ** ***  is a prefix of %s",a,b);
 *   ** * * *** * * *  ***
  * *    ***    * ****   
 **    **  * ** *   * *  *
**  * ** *** *  ** **  **** **  *********     * *  **  ** *  is not a prefix of %s",a,b);
*** **** * **   ** *  * * 
   *   *        * *  * ** * *  * 0;
}
answered by (-284 points)
edited by
0 0
prog.c: In function 'main':
prog.c:8:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s %s",&prefix,&word);
             ^
prog.c:8:16: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
     scanf("%s %s",&prefix,&word);
                ^
prog.c:10:15: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     for(i=0;i<strlen(prefix);++i)
               ^~~~~~
prog.c:10:15: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:10:15: note: include '<string.h>' or provide a declaration of 'strlen'
prog.c:18:6: error: expected '(' before 'printf'
      printf("%s is a prefix of %s",prefix,word);
      ^~~~~~
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>
int main()
{
*  *  *** *   *  ** * *****   a[100],b[100];
*  *    ******  *  **  **    *  ** ** * *    ** * 
    int l1,l2;
*  * *  ***     *   **   *  **    * ****
 *    * * *  *  **** * ** * *****
 *** *  **     *** * *  ** *  *** ***   *
***   *    ***  * **** * ** *******     *    **  * * **  ** is not a prefix of %s",a,b);

    }
  *  ***  *** *  ***   **  if(l1<=l2){
 *  *** ***   * ****** * **** *  **  ****  ** ***  *   ** * *** prefix=1;
*  *  * *  * ****  * ** **** ** *   *** ***** **** ****  i=0;
  *** *         *  * * * ** **  * * ***     *     *** *    * ** 
  *  **   *   * *   *  * ***  *  *  ** *     * ** ****  *****   ***  * **    **  * * (a[i]!=b[i]){
 ***  *  * * ***  *     *  * ** * ** *   ***   * *** *     *** *  ***  ****** *   *   **  *  * *    **  ** *** ***  
* **    * *     ************  * *  * * **  *  *  **** * * **   **   ****  ** *      * *   * ** ** **** *** * *
 * **   ** **** * *  * * * *** **    ** **   **  ****   *   *  ** * * *** *  * **


  * *        **    *** **  *** * ** **  *  * * * *  * * *** **    
**       ***  **         * *   **** ** *   * *    *  * *     *   **
*  **** ** ** ** ** * ** *** **  *   ** * * ** * *   *  *** * * **   ** * **** *    *** ** is not a prefix of %s",a,b);
 ***  * ***  *   *  **  * **  *   ******   ** * * **** 
 *** *  *** *   *    ***** * ** **  ******** **   * * * **
* * *  * **     *  ** ***  ** * * * *    * *  ** ***  * ** **  ***  *  is a prefix of %s",a,b);


    }


}
answered by (-329 points)
0 0
prog.c: In function 'main':
prog.c:5:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
             ^
prog.c:5:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
               ^
prog.c:7:8: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     l1=strlen(a);
        ^~~~~~
prog.c:7:8: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:7:8: note: include '<string.h>' or provide a declaration of 'strlen'
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:6:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
             ^
prog.c:6:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
               ^
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
 *    *     * *   * * * * *
int main(void)
{

  **  *  **   *   *   * **  pre[100];
**     * *   * ** * * word[100];
* *** * * **** **  **   * *  *  * %s",pre,word);
  **  **** ***** * *    **    * * *  * *   * 
* *  ***   * * ********** ****  * ** ** ***

**  * ** ****  **  ** *****   i;
 * *   * **   * * ********     *****  ** * *    **
 **  *  **** **    * 
*** * * **  **** ***  ***  ** * *    **** *   *** * ** *** ** * *   ** * 
* **** *  *  **  * ***   ** * ***   *   ****   *  * ***  *  
 * *** *********** * ** *****  *  *  *  * * * * * * ***       *    *  **   *  * ** * is not a prefix of %s",pre,word);
** * * **  *   *** *  * *     *  **  **   ******** *   ** **  ****   **** ****** ** ** ** 0;
***** ** ** *    * * * *  ********* ***  * *   ** *  * * 

*********   ** * *  **
printf("%s is a prefix of %s",pre,word);
return 0;
}
answered by (-249 points)
0 0
prog.c: In function 'main':
prog.c:8:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&pre);
             ^
prog.c:9:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&word);
             ^
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:8:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&pre);
             ^
prog.c:9:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&word);
             ^
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <string.h>
#include <ctype.h>
int main ()
{
 ** *  *     * ****    *****   * *  pre [100],a[100];
 *****  ** **   *** *  * ***   n ,i;
*   ** * **   ** * ** **  *   **  *  * **
 **** *  *** *  *** * * ***   *****
 **  *     ** * **  *   **    ****  *  ***   **  
***   *  *** ** ****  *****
****  **   ****  ***   ** *      *****  **** ** ***      (n=0;n<strlen(pre);n++)
*** *     * * **  *****  *  * **  *** * ** 
  *   *  * **   **  *   *   * ***   *    *    ************* *  * * **        (pre[n]==a[n])
* ** ** **     **  ** * * *     ** * ** **** *  ****** ******* *  *   ** ******   *       is a prefix of %s",pre,a);
*     **   ** * **       * **  **     * *     *** * * ***   ** *  *   *  ***** * * *  * * 
 **** *  **        ** **   **  * *   *  ****   * *  * **    **   ***   **  * *   ***  *   **  *  ** ** * *** is not a prefix of %s",pre,a);return 0;
***  ** ** *     *   ****
   ** *** * * *      **  ******  ** ** ***   *    ****    ********      * * **  **

   **     * * **   ********    0;
}
answered by (-32 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include *  ****  **   *
#include *  *        *

int main()
{
  **   * * *** ***   * **  *   a[100];

 * ****   * * * *  **  *  * * b[100];

   ** ****  **  **   ** **  **  *  **   %s", a, b);

*   * *  ****  * * **  * **** ** len_a = strlen(a);

******  ** * ***  * *  *  * i = 0;

***  * ******* * * * ***  * flag = 1;

**     * * **** *   * * *** *** = 0; i < len_a; i++)
*   *     *** * *   * * ** *         
*     *  * * ***** *   * ** * *  ** ** *** ***  *** ** *** ** != b[i])
 ** * * * *  * *   *  ** *  *    *  *** ****    **  *
*  *  *   ***  * *  *  *** ** * *   *** *    * * * *   ** ******** ** **  *     *  * = 0;
***  * ** ****    *  **  **   *** *   **    ** *
****  * ****** *      * *     *  

   *  **  **  *     **    *    == 0)
   ****** *    *** ** *  
 ** ** *  ***  ** ** ** *  *   ** * *  *   ** ** *  ** is not a prefix of %s", a, b);
* **       *      * **
 * *** * * **     **    * *
***  **  * * **     *** *
* *** * *  *        *  **   *   **  *   * * *  ******      is a prefix of %s", a, b);
 *    *    * *  * **  ** ***
 * ** *** * * *  **    * * **   *    0;
}
answered by (-285 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
 * ***   **** ***   ** **
int main()
{
***  * *  ****  **  * *  * i,n;
 **   ***     * ** *** * *  *** *** p[100],s[100],a[100]={};
**  * * *  *** ** *  **     * **     * ****      %s",p,s);
*   ** **  ***   *  *   *        *
 * ***   * ****  ** * ** * *** * **
 ** ** ***** * *** ** *   * * *  *      **  *******  
 *   *   ********** ***** **  ***  *   *   **
* ***  *   * * *  ************ * *   ********* *** *  *     ****** **  is a prefix of %s",p,s);
* ** ** * ** **    *  **  
***   *     * * **   * * ** ***  **
 ** *****  * ** *    * * * *  **  **  **     ***   * ******      is not a prefix of %s",p,s);
*  *****  *** * * ** * 
 **   *** * * *    * * *   ** *   * ******** ** ***** *** * ** 
 ** ** * *   * *   *    * * 0;
}
answered by (54 points)
edited by
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<string.h>

int main()
{
    int i;
    char a[100];
    char b[100];
 **  * * ** ** ***   *** * * *   *    * ***  ***
    scanf("%s",b);
    for(i=0;i<strlen(a);i++)
** *** **   **   * *****      ** **** ******   ***   *  
***** * * ****  *     ** *  ***       * *  **  ** * ********* ** *  * *  * **   *   != b[i])
 *  ** *  ** **   **   **** **    *** *    *  *** * *   **    ** * ** *   *  *   ** *    * *  *** **  **   *   *
*    ** *  *   *****  * **     *  *    * * *  *          * *   ***  ***  *   *****  *  **  ***    *    ** *     * ** * *******  * *  * * **         * is not a prefix of %s",a,b);
    **   ** ** *  *****   *** **** *   ***      **     ***  **   **  *   * ** * ** *  ****   ** *   *  **     * **  *****   * **   **   ** * 
  **    *  *  *  * ****   * ** *** *** * ** ** *   *  *****  ** *  ** *   ** *  *   ** **   *     *  *     ***** 
*   ***********  *           ** ** ****      * * **   *    * * **   ** * ** *   ******   * * == b[strlen(a)-1])
 ** ** *    *  *   * **   * **  *    *** ***  **  ***  ** *  ** ** ****    *  *** **  **     **  ** ***  * ** ** 
* *  *   *   *   * *    *  * * *** *      ****   **** **    **   **  ****  * * *** ***  **    *  *   ****   ***    ** ** * **   *   **   is a prefix of %s",a,b);
* * ********    * *      * * **     * * ** *   *    * *   *  **  ** *** * * *** ** ***  * *  * **** *   * **** * *  *  **** *** * * *      **
*** ***  ***  * ** * *** **** * ** * * * **  *    *  * ** ** *    * *** *  ***   **  *** ****  *** *  ******  * 
   **** *  * * * ** *     ** * *  *           *  * **  
}
answered by (-301 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
#include<stdlib.h>
#include<string.h>
#define n 100

int aa(char a[],char b[]){
 *  ***   *   * * ** ** *  * **   * i;
*  ***    *   *****     ********** * (a[0]!=b[0]){
* *   *** **   * **       ****    **  **  ***** ** **   *      0;
** * **** * *** * *  *   *   **  *
* ******* * * *   *  **  *  * **      *  *    *
*** ** **** ** *****    *  *  **** *   ** *  *  **     * *** *    **    ** a[i]==b[i])
 * *    ****     *  ** *** *  **     * ** ** **  **       *
* ** *    ***    *   **** * *  ***** **  * *   * **    **** *    **  **** 1;
** *** *        * * ** *******   ** * ******* ******* *   *  ***      *****  ** ***** * 
**  *   **       * *** ***** ** **** **    **   *  *  
*  ** * *  *   *   **  * **     * 
  **  *   * *     *  **  ****    **  * *** 0;

}

int main(){
*      * ***   * **       c[n],d[n],e[n];
* *  **   *  *** * ** *  i;
* * * * ***** *****   * *   **  * %s",c,d);

  ** *   *   ** ******* *   * * ** * 
  **  ** *** * *     *    *    * ** * **  *        * *  ******* * is a prefix of %s",c,d);

  ******* **   *  ** * * * *
***   ***  **     *     *   ***  **  *  *     ***** *   **  * ****  ** *  is not a prefix of %s",c,d);


}
answered by (-32 points)
edited by
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.68.87.43
©2016-2026

Related questions

1 like 0 dislike
37 answers
Final Exam 5 (20%)
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42302 - Available when: 2018-01-17 14:00 - Due to: Unlimited | 14.1k views
2 like 0 dislike
31 answers
Final Exam 4 (20%)
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42301 - Available when: 2018-01-17 14:00 - Due to: Unlimited | 13.4k views
1 like 0 dislike
32 answers
Final Exam 3 (20%)
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42300 - Available when: 2018-01-17 14:00 - Due to: Unlimited | 16.6k views
2 like 0 dislike
30 answers
Final Exam 1 (20%)
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42298 - Available when: 2018-01-17 14:00 - Due to: Unlimited | 11.5k views
0 like 0 dislike
4 answers
[Makeup] Final Exam 2 (20%)
[Exam] asked Jan 19, 2018 in Final Exam
ID: 43460 - Available when: 2018-01-20 09:00 - Due to: Unlimited | 3k views
12,783 questions
183,442 answers
172,219 comments
4,824 users