1 like 0 dislike
11.7k views

A string p is a prefix of a string s if the leading characters of s are identical to p. For example, "abc" is a prefix of "abcde". Develop a function prefix that checks if a C string p is a prefix of another C string s.

p是s的前綴若s開頭的一段字串等於p。例如,"abc"是"abcde"的前綴。寫一個程式 判斷字串p是否字串s的前綴。

Example input 1:

abc
abcde

Example output 1:

abc is a prefix of abcde

 

Example input 2:

bc
abcde

Example output 2:

bc is not a prefix of abcde

 

[Exam] asked in Final Exam
ID: 42299 - Available when: 2018-01-17 14:00 - Due to: Unlimited

retagged by | 11.7k views

37 Answers

0 like 0 dislike
Hidden content!
#include *** *** * * *
#include * * ***** **
** *** * * **
*** * * ***

int prefix(char a[], char b[]){
int i, j,n;
int cnt=0;

n= * **** **

** ** *** ***** * ******* *
* * * *** *** * * * * * ** == b[i]){
** * **** * *** * * *** * ***** ***** ****
* ** *** ** * ***** * * *

** ** * ********* ***
if (cnt == n){
* * ** * *** * * * ** * ** ** ***** ***** ** 1;
* ** ** * * * ** ** *** *** * * * **** *
* * * * ** ** * * * **
*** ** * * ****** * ** * ** ** * ** * *** * * 0;

}

int main()
{
* * * *** *** s1[100], s2[100];
** * * * * * ***** i,j;

** ** * ** * ***** ****** ***** * s1);
** ** *** ** ** * * ** * * * ** * * * s2);
* * ** *** * (prefix(s1, s2)){

** * ** ** **** *** ** *** * ** * ***** ** * ** *** is a prefix of %s", s1,s2);
** * ****** ** * * ** ****** ****** *
** ** ** * * * **** * * *** *** * * * ****
** * ** * ** ** * ** * * ** * * * ***** ** * *** * * ** ** * is not a prefix of %s", s1,s2);



}
answered by (323 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <string.h>

int main(){
* **** * ** * * * ** c;
* ** * * * ***** ** a[100],b[100];
* * * ** * * ** ** * ** ** %s",a,b);
** * **** * * ** ****** *** ** **** *
** * * * ** * ** *** * * *** *** ** ** *** 0;
* * * * **** * **** * * ** *** * %d",strlen(a),strlen(b));
** * *** **** ** * ** * * * * *
* * *** ****** **** * * ** ** * ** * ** ** ** * * * **** * * **
*** * ******* * ** * ** ** * ** *** ****** ** * ****** * * * ** ** * * * * ** *** * * * * * is not a prefix of %s",a,b);
** ** * *** * * * * **** * * ** * ** ******* * * * ** ** * * ** **** ** * *** ** ** * *
* *** * * ***** ** ** ** ***** * ** * * ** * *** * * *
** ***** ** * ***** * * * * * *** * * *** *** * ******* ** * **** if(c==strlen(a)-1)
* * * ** ** * * * ***** ** ** * **** ** * * * * * *** * * * * * ** * ***** * * ** *** * is a prefix of %s",a,b);
    }
****** ********* *** **** 0;
}
answered by (-498 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <string.h>
int main()
{
* * ** **** ** ****** * n,count;
* ** * ****** ****** * *** * * * * *
*** ** * ******* **** ** ** * *** * %s",a,b);
* ** *** *** * * *** * * * *

* * *** * ***** * ** *** * ** * **
* ** * ********* *** ***
***** * ***** * *** * * * * ** * ** ** *** **** **
** * *** * ** ** ** * **

* ** ** * * ***** (strcmp(a,c)==0)
* * * ***** ** *
**** ** * * * ** * ** * *** **** * *** ** * ** is a prefix of %s",a,b);
** ** * ** ** ******
* ***** ** *** **** ***
**** * * ***** **
** ** ** * * *** * ** * ** ***** *** * * ** * is not a prefix of %s",a,b);
* * *** ** ** ******* * *
** * **** ** * ** ** *** * ** 0;
}
answered by (-284 points)
edited by
0 0
prog.c: In function 'main':
prog.c:8:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s %s",&prefix,&word);
             ^
prog.c:8:16: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
     scanf("%s %s",&prefix,&word);
                ^
prog.c:10:15: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     for(i=0;i<strlen(prefix);++i)
               ^~~~~~
prog.c:10:15: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:10:15: note: include '<string.h>' or provide a declaration of 'strlen'
prog.c:18:6: error: expected '(' before 'printf'
      printf("%s is a prefix of %s",prefix,word);
      ^~~~~~
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
#include<string.h>
int main()
{
* * * ***** ** ****** *** a[100],b[100];
** ** * ** ** ** * *** * * * ** *
    int l1,l2;
* *** * * * ** *** * ** ** * ** * *
** ** *** ** * ***** ** ****
* ** * ** ***** **** ** **
** *** *** *** * ****** **** * ** *** * * * is not a prefix of %s",a,b);

    }
* * *** ** * *** ** * if(l1<=l2){
** * ** * * ** * ** ** ** ******** *** **** ** prefix=1;
* * * * * ** * * * **** ****** * * * * * **** i=0;
* * ** * * ** ** ** ****** **** ** ***** ** * * **
* * * ** * *** * ** * * * * *** **** ** * * * * * *** * ***** *** * * ** (a[i]!=b[i]){
* * ** ** ** * **** ** *** ** * ***** **** * * * * * *** *** * ** * ** * **** ** ** **
*** * * * ****** ** * *** * * ***** ** * * * * * * * *** * * ****** ** * * * * * *
******* * * * * ** * *** ***** *** ** ** ** *** ** *** * * ** *****


* * * ** * **** ** *** * * ** *** *
* * * ** ** * * ******* ** ********* * ****** *
** ** * *** *** * ** * *** * *** **** *** ****** * * ***** *** * ** ** is not a prefix of %s",a,b);
*** * * * * ****** * *** * ** ** * *** *** **
* ***** * * **** ** ** * *** * * **** * ** * **** **
**** * * * * ** * ****** *** ** * * * ** * * *** is a prefix of %s",a,b);


    }


}
answered by (-329 points)
0 0
prog.c: In function 'main':
prog.c:5:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
             ^
prog.c:5:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
               ^
prog.c:7:8: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     l1=strlen(a);
        ^~~~~~
prog.c:7:8: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:7:8: note: include '<string.h>' or provide a declaration of 'strlen'
0 0
prog.c: In function 'main':
prog.c:6:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
             ^
prog.c:6:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
               ^
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
* * *** ** * * *
int main(void)
{

* *** * * ****** ** pre[100];
* *** ***** ** ** ** * *** word[100];
**** * * ***** * * * * * * %s",pre,word);
**** ** * * **** * * * * * *
* ***** * * ** ** * * * ** * *

* * ** * **** * * * i;
* * * * * ** * ** * ** ****** * **
* *** * * ******** *
** ** * ** **** * * * ** * * * ** ** * * ** *** * * *
***** ** * ** ** * *** * * ****** * * * * * ****
* ** ** * * * ***** * * * * * ***** *** ** ** * * * * ** *** ** **** **** * is not a prefix of %s",pre,word);
**** * * *** ** ** * ** * * * ** * *** * ** ** *** * * * * *** * 0;
* ** ** * ** * *** ** * *** **

** ****** * * *** ** * ***
printf("%s is a prefix of %s",pre,word);
return 0;
}
answered by (-249 points)
0 0
prog.c: In function 'main':
prog.c:8:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&pre);
             ^
prog.c:9:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&word);
             ^
0 0
prog.c: In function 'main':
prog.c:8:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&pre);
             ^
prog.c:9:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&word);
             ^
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <string.h>
#include <ctype.h>
int main ()
{
** * *** *** ******* *** pre [100],a[100];
*** *** *** * * * * * ** n ,i;
** * ** **** ***** * ** * *
** *** * ** * ** ** * *** *
* * * *** ** * ** * ** ** ** * ****
* * * ** ** * ** **
* * * * * * * * ** ** * * * *** * **** (n=0;n<strlen(pre);n++)
* ** * * * **** * ** * * ** * * ** * * * *** **
* * *** *** * * ***** *** * ** * ***** *** ***** (pre[n]==a[n])
* *** *** ********* ** ** * * * * * *** *** ** ** ** * ***** * *** is a prefix of %s",pre,a);
*** *** ** * * *** * * ***** ** ** *** ** * * * * * ** * *****
* ********* * **** ******* *** **** * * * * * ** * * *** *** ** ** *** **** ***** *** ** * * *** ** ******** is not a prefix of %s",pre,a);return 0;
**** *** ** * * * *
** * * ** *** *** * ***** * *** *** * * * * * * **

* * ** * * *** ** 0;
}
answered by (-32 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include *** ** * ***
#include * * * * *** ** *

int main()
{
*** *** ** ** *** ** a[100];

** ** ** * ** **** ** ** * * b[100];

* *** *** * * * *** * %s", a, b);

* * * * * ** ** ** *** ** len_a = strlen(a);

* ** ** * ** * * * i = 0;

* * * * ** ** * * * * flag = 1;

** **** * **** ** **** * * = 0; i < len_a; i++)
*** * ** *** * ** ***
*** **** * * * * * *** * **** *** **** ***** ** ** != b[i])
* * * ** * ** * ** * * * ***** *** ** * * **
* * * ****** ** * * * * ** * ** * * *** * *** ** *** ***** * *** ** = 0;
*** * ** * ** * *** ****** * *** **** ** * * *
* * ** ****** **** ***

***** * * ** * * *** ** ** == 0)
** * ** * * * * *
** * **** * * * *** * **** ** ** ** ***** *** * * *** is not a prefix of %s", a, b);
** ** ****** ** ** * * *
*** * *** **** ** * *
*** ** * * * * * * **
** **** *** * ** ** * * * * ****** * * * * * ** * *** is a prefix of %s", a, b);
** * * * * *
* ** * * * * * * *** *** 0;
}
answered by (-285 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
** *** * ** * * * *
int main()
{
* * ***** * ** i,n;
** **** * ** * ** *** * ** p[100],s[100],a[100]={};
** *** * ********** * * ** * ***** %s",p,s);
* * * * * *** ****
** * ** ** *** ** * *** *** * * * *
* ** ***** ***** ** * * *** * * ** ** ** **** ** *
* * * *** *** ** * * * *
* * * *** ** * * * * *** * ***** * * * ** * * ** ** ** is a prefix of %s",p,s);
*** * **** *** * * *
* * * * * * * * **
* *** * * *** ** *** **** ** ** * ** *** * is not a prefix of %s",p,s);
* * * ******** ** ** * *
* * * * * * *** * *** * * **** * ** ****** * *
* * ** ** * * ** 0;
}
answered by (54 points)
edited by
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
#include<string.h>

int main()
{
    int i;
    char a[100];
    char b[100];
* ** * * * **** * *** * ** * *** **
    scanf("%s",b);
    for(i=0;i<strlen(a);i++)
** *** **** * *** ** ** * *** * *** * *
** * * * * * *** * * **** * ** * ******* ** ** **** ** * **** * ** **** != b[i])
*** ***** ** * ****** * * * *** ** * * * ** * * * * * *** ** * **** * *
* * * * **** *** ** * * * * *** * * ** *** *** * *** * * ** * ** * ** * ** * *** * * * * * ***** * * * * is not a prefix of %s",a,b);
** ** * * * ************ ** * ** * * *** ** ** *** *** * * * ** ** ** ** **** **** **** * * * *** *
* * * * * ** **** **** ** * *** *** ** * * ** *** * ** * ***** ****** * * *** ****
** ** * *** ** * * **** *** * * ** * * *** ** * * * *** **** * ** * **** ** ** *** **** == b[strlen(a)-1])
* ** * *** *** ** ****** * * *** *** * * * * * ** * *** * *** * * * *** ** *** * * *
** * **** ** **** ***** * *** **** * *** * * * * ** * * ** * * ** * * **** * ** **** ** * * ** *** * * * * is a prefix of %s",a,b);
* ** ***** * * * *********** ***** *** * **** * ******* ** * *** ** * * * * * * * * ** ** ** ** * * * * * * ** *
** ***** ** ** ****** ** ** * * * * * ***** * ** *** * * * * * * * ***
** *** * * **** *** * * ** *** ** * * *
}
answered by (-301 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
#include<stdlib.h>
#include<string.h>
#define n 100

int aa(char a[],char b[]){
* *** ** * * * * ** i;
** ***** ***** ***** **** (a[0]!=b[0]){
* * * * *** * ** ***** * ** ***** *** ** *** 0;
** ** **** ** ******* * * * *** *
* ************ *** *** * ** *
** * **** * *** **** * ***** * ** ** **** * a[i]==b[i])
*** * ** ** ** * * * ** * * ** **
* ** ** * *** ** ** * ***** ******* * *** * * *** *** * * * ** 1;
** *** * * * ** * * * *** * * ** * **** * * * * ** * **
* * * ******* * ** *** * * ******* ** *** ****
* *** ** *** ** * ** * ****
* ** * * * *** * ** **** *** 0;

}

int main(){
* * * **** ** * * * * ** * c[n],d[n],e[n];
** * ***** * ** i;
** * * * * * * * ** *** ** %s",c,d);

* * * ** * *** * * *
* * ** ** *** * *** **** *** *** ** ** * * * * ** ** ** is a prefix of %s",c,d);

* * ** *** *** *
***** * * *** ** * * *** ** ** *** * *** * is not a prefix of %s",c,d);


}
answered by (-32 points)
edited by
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.130.12
©2016-2025

Related questions

1 like 0 dislike
37 answers
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42302 - Available when: 2018-01-17 14:00 - Due to: Unlimited
| 11.7k views
2 like 0 dislike
31 answers
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42301 - Available when: 2018-01-17 14:00 - Due to: Unlimited
| 10.6k views
1 like 0 dislike
32 answers
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42300 - Available when: 2018-01-17 14:00 - Due to: Unlimited
| 11.9k views
2 like 0 dislike
30 answers
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42298 - Available when: 2018-01-17 14:00 - Due to: Unlimited
| 9.5k views
0 like 0 dislike
4 answers
[Exam] asked Jan 19, 2018 in Final Exam
ID: 43460 - Available when: 2018-01-20 09:00 - Due to: Unlimited
| 2.4k views
12,783 questions
183,442 answers
172,219 comments
4,824 users