1 like 0 dislike
2.2k views

A string p is a prefix of a string s if the leading characters of s are identical to p. For example, "abc" is a prefix of "abcde". Develop a function prefix that checks if a C string p is a prefix of another C string s.

p是s的前綴若s開頭的一段字串等於p。例如,"abc"是"abcde"的前綴。寫一個程式 判斷字串p是否字串s的前綴。

Example input 1:

abc
abcde

Example output 1:

abc is a prefix of abcde

 

Example input 2:

bc
abcde

Example output 2:

bc is not a prefix of abcde

 

[Exam] asked in Final Exam
ID: 42299 - Available when: 2018-01-17 14:00 - Due to: Unlimited

retagged by | 2.2k views

37 Answers

0 like 0 dislike
Hidden content!
#include *****
#include * * * * * ** **
*** **** *** *** *
** ***** * * **** *

int prefix(char a[], char b[]){
int i, j,n;
int cnt=0;

n= **** * *

*** * * ***** * * ** ***** * * * ***
* * **** ** **** ***** == b[i]){
****** ** * * * ** *** **** * *** *** ** * *** ***
*** * * ** * ** **** ** *** **

* ***** *** *
if (cnt == n){
** * * * ** * * * *** ** * * **** * **** * * ****** 1;
** **** *** * ** ** ** ** ** * * ****
* *** ** * * * *** *** *
* **** ** * ** *** ** **** * * * **** * *** 0;

}

int main()
{
* **** * * ****** s1[100], s2[100];
* * ** * ******** * i,j;

* *** * * ** ***** * * ***** * * s1);
** ** * * ** ** * **** * * * *** ** * s2);
**** **** * ** *** * (prefix(s1, s2)){

* * **** * ** * * * * ******* ** * * * * ** *** * *** is a prefix of %s", s1,s2);
* * * **** ** * *** * * * *** * **
* * ** ****** * * ***** * ** * ** * **
*** * ** * ***** * *** ***** * * * ** * ***** * ** * * **** ** is not a prefix of %s", s1,s2);



}
answered by (323 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <string.h>

int main(){
* * * * * ** * c;
* *** * ** * * a[100],b[100];
** ** *** ********* * * * * %s",a,b);
* * * ** * ** *** ** *** *** **
* ** * **** *** ** * *** ** * ******* * **** ** 0;
*** ** *** * * * * * *** * ** * ** * %d",strlen(a),strlen(b));
****** * * ** * * *** ** * * **** * *** *
*** **** * *** ***** * * ** ** ****** ** * * ****** * *** ******* * * *
** * * ** * ** * * ** * * * *** * ** *** ** ** ** *** *** ** ** * *** * ** ** * * * ** ** ** ** * * * is not a prefix of %s",a,b);
* * ** * * * ** ** * *** ** * ** * * *** **** * * * ***** ** * * ** * * **
** * ***** * *** * * ** * * ** * * ** *** ** ** ** * * *
** *** ** *** * * * * * ** ***** * *** ** * * * * ***** ** ** * if(c==strlen(a)-1)
*** ** * * ** * * *** * * ** * ** * ******* ** ** * **** * *** *** **** * * * *** ** * is a prefix of %s",a,b);
    }
*** ** * ** * * * * 0;
}
answered by (-498 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <string.h>
int main()
{
* * ** *** *** * * * * * n,count;
** *** * * * ** *** * *** ** * ***** * ** * *
*** * * * ** ** *** * ** %s",a,b);
* * * ** *** * * *

* ** * ** * ** ** *** *** * *** *** *** *
** **** ** * * * **** **
*** ** **** ** * ******* * *** * * ***** * * **
** ** * ** * ** ** * * * *

* *** * ** ** ** * (strcmp(a,c)==0)
*** * * ** ** * * * *
** * ** **** * * ** ***** * ** * ** ****** * ** *** is a prefix of %s",a,b);
*** * ** ** ** * * *
***** * ** **** ** * *
** ** * ******* *
* * * *** * * * ** ** * * ** * * * ******** * ** *** * ** ** is not a prefix of %s",a,b);
* ** ** * *** * **** *
*** ** ** * * ** 0;
}
answered by (-284 points)
edited by
0 0
prog.c: In function 'main':
prog.c:8:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s %s",&prefix,&word);
             ^
prog.c:8:16: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
     scanf("%s %s",&prefix,&word);
                ^
prog.c:10:15: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     for(i=0;i<strlen(prefix);++i)
               ^~~~~~
prog.c:10:15: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:10:15: note: include '<string.h>' or provide a declaration of 'strlen'
prog.c:18:6: error: expected '(' before 'printf'
      printf("%s is a prefix of %s",prefix,word);
      ^~~~~~
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
#include<string.h>
int main()
{
** ** **** ** * ** ** * a[100],b[100];
* ** *** * * * * * ** * * ** *
    int l1,l2;
* * *** *** ** * ** * * * *
** * * * * * *** ** ** * * * *
* ** **** * *** *** * *** * *
**** ** * * ****** **** *** ** *** * * ***** * is not a prefix of %s",a,b);

    }
** * * **** * * ** * if(l1<=l2){
* * * * ** * * **** ** ** * * ** prefix=1;
* * ** * * * ** * * *** * ***** **** * * ** * ** *** i=0;
** ** **** * ***** * *** * * * ** * * ****** * ** **
* * *** * * ** ** * * * *** **** ***** * * ****** ** ******* (a[i]!=b[i]){
** * * * **** * ** ** * ** *** ***** * ** * ** *** ***** * * * * *** **** * * * ** * * *
** ** * ** **** ********* *** **** ***** * ** * ** * ** ** ** ** * ** *** * ** ******** * **
* ** * ** ** * ** ** ** * ** * * ** ****** *** ** **** ** *


* * * ** * * * *** *** * ****** *** ** **
* ** ** * *** ** * ****** * ** * **** * * * *
*** ** * **** * * *** * * * ** * **** ** ** *** * * * *** * * * ** ** * ** * is not a prefix of %s",a,b);
*** * **** * ** * ** * * * * **
** * * * ** ** **** * ******** * ** * *
** * ****** * ** * * ** ***** **** * ** ***** * *** is a prefix of %s",a,b);


    }


}
answered by (-329 points)
0 0
prog.c: In function 'main':
prog.c:5:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
             ^
prog.c:5:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
               ^
prog.c:7:8: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     l1=strlen(a);
        ^~~~~~
prog.c:7:8: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:7:8: note: include '<string.h>' or provide a declaration of 'strlen'
0 0
prog.c: In function 'main':
prog.c:6:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
             ^
prog.c:6:15: warning: format '%s' expects argument of type 'char *', but argument 3 has type 'char (*)[100]' [-Wformat=]
     scanf("%s%s",&a,&b);
               ^
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
*** * *** * ** * **
int main(void)
{

** ** *** * * * **** * ** pre[100];
*** * * * * *** word[100];
**** ** ** * ** ********* *** * %s",pre,word);
* * * ****** * **** *** ** * **
* ** * ** ** ** * * * * ** * * *

** *** ** * ** ** * * i;
*** *** * ***** ***** * *** * * **** * **
*** * * ** * * ** *
* *** * * ** ** **** * * ** ** * *** **** * ** *** *
* **** * ** * * * * * *********** **
** ***** ** *** ** *** * * *** ** ** * * * * ** * ******* * ** * *** * * is not a prefix of %s",pre,word);
*** * ** *** * *** * * ** * * ** * ** * * *** * * * ** ** **** ** 0;
* *** * * *** ** * * * * ** * ** * ***

* * * **** ** ** ***
printf("%s is a prefix of %s",pre,word);
return 0;
}
answered by (-249 points)
0 0
prog.c: In function 'main':
prog.c:8:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&pre);
             ^
prog.c:9:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&word);
             ^
0 0
prog.c: In function 'main':
prog.c:8:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&pre);
             ^
prog.c:9:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[100]' [-Wformat=]
     scanf("%s",&word);
             ^
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <string.h>
#include <ctype.h>
int main ()
{
* ***** * * *** * * * * pre [100],a[100];
* ** * *** * **** * n ,i;
***** * ****** ***** * **** ***
* * * **** **** *** * ** ** ***** *
*** * ***** * * * * ** * * * ********
* * * * * *** *** ** *
** * * ** **** * ** * * * * * ** ** (n=0;n<strlen(pre);n++)
* * *** * * ** * **** ** ** * ** ** **** * * *** **
* ** * * ** ** * *** ** ***** *** * ****** * * * ** *** *** * *** (pre[n]==a[n])
* **** * * ** * ** * * * * * * *** * *** * ** * **** * ** **** *** ** is a prefix of %s",pre,a);
****** **** * * * * ** * ***** * * ** * ** * ******** * **** **** *** **
* * * * * * * * *** * * **** *** * **** ** * **** * * * ********* * ** * *** ** * is not a prefix of %s",pre,a);return 0;
** * * * * *** * *
* ** * * * *** * ** ** * ** *** * * * **** * * *

** * * * ** * * * * 0;
}
answered by (-32 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include ** ** * * *
#include ****** * ** **

int main()
{
**** ** **** * * * a[100];

* **** ** ** ** b[100];

** ** ** * ** ** * * ** ** ** *** %s", a, b);

*** *** ** * * * *** * ** len_a = strlen(a);

** ** * * **** **** * **** i = 0;

* * * ** * ***** **** flag = 1;

*** * ** * ******* ** = 0; i < len_a; i++)
** * * *** * * ** *
* ** * ** ***** ** *** * * ** * *** ******* * **** != b[i])
** ** *** *** * *** **** *** ** *
* **** ** * * **** * * * *** * * * * ** * * ** * * * * ***** ** * * * = 0;
* * *** ** *** * * * *** ******* ** *** * **
* **** ** ** *

*** *** ******* ** **** == 0)
** ***** * *** *** *
**** ** * * **** * ****** * * * * * ** * * * is not a prefix of %s", a, b);
*** * * *** ** * ** ** *
* * * ** **** ** * **
* ***** **** * * **** *
* * * ***** ***** *** * * *** * ** *** ** *** * * ** ** * *** is a prefix of %s", a, b);
* * ** *
***** * ******* 0;
}
answered by (-285 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
** *** * ***
int main()
{
** * ** ** ** * * * * * i,n;
* * * * * ** ** * * *** p[100],s[100],a[100]={};
* * *** ** * ** **** * ** * *** * %s",p,s);
* ******** *** * * * *
** ** ** * *** * ** * * ** ***
*** * * *** ****** ****** ** * * ** *******
* * ** ** ** * * *** ** *
** * * *** * * ** * * * *** * ** ** ** *** * is a prefix of %s",p,s);
*** **** *** ** * ** *
** * **** * * * * * *
** ** * * **** * * * ** * *** * * ** * is not a prefix of %s",p,s);
* ***** **** * ** ** *
** * ** * * * ** * ***** * * * * ** *** * * **
* * *** * *** * ** * * *** * ** 0;
}
answered by (54 points)
edited by
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
#include<string.h>

int main()
{
    int i;
    char a[100];
    char b[100];
* *** ** * * * **** * *** * *** ** * * *
    scanf("%s",b);
    for(i=0;i<strlen(a);i++)
* * * * * ** * *** ** ** ***** * * ** ** **** *
* * **** ******** *** * ** *** * * *** * * **** **** * ** ***** *** * * * * != b[i])
** ** * *** * *** * * * * * ******* ** **** * ** * ***** ** *** * **** *** * * * *
* * ****** ** * * ** * ***** * ** ** ** * **** * ** * *** * * ** * *** ** * * ** * * * **** ***** * * * ** is not a prefix of %s",a,b);
**** *** **** *** * * * * *** ***** * **** **** * * * *** *** **** * ** * * *** ** * ** *** * **** *** *** ************** **
* * * * ** ** *** ** * **** * ** * ** ** *** ** **** ** **** ** ** ** ***
*** * * ***** * * * ** ** * * **** *** * * * * * * * == b[strlen(a)-1])
** * * * ** * * ** * * ** * *** *** **** *** * ** *** ** * * ** *** * * * * * *** ******* *
**** * **** *** **** * * * ** * * ** *** * ** * ** * * * * * * ** * ** ******* * * * * * * * * ** * *** * * is a prefix of %s",a,b);
** * **** *** * * **** * **** ** **** ** * * * * * * **** **** * ** * ***** * ** *** * ***** * **
* * *** * ** ** * * ** * * ** ** * * * *** ********** *** ** * **** * **** **** *** ****
* * * ** * ** * *** * * * * * * * ** * * * *
}
answered by (-301 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include<stdio.h>
#include<stdlib.h>
#include<string.h>
#define n 100

int aa(char a[],char b[]){
* ** ** *** *** * ****** * * i;
* ** * **** *** ** ** *** (a[0]!=b[0]){
***** * **** ****** * *** *** * * * *** * ** *** * 0;
* ** * ****** ** * * * * ***
** * ** *** *** * * ** ** * ***** *** * *** * *****
*** ** * ****** *** * * * ***** **** *** * ** * a[i]==b[i])
** ** * ** ** ** * ** *** * * ** * * * * ***
***** ** * * * * * * *** ** *** ****** ** *** **** * ******* ***** 1;
* *** ** ** ** * ** **** * * * * * ****** * ** * * * ****
******* * * ** * ** * ** * * * * * * *
** ** *** ****** * * * *** *
******** * * * ** ***** *** 0;

}

int main(){
**** * ** * ** * *** ** c[n],d[n],e[n];
** ** * * ** * ** * i;
*** ** ** **** ** * **** ** ** * %s",c,d);

***** * ** * * *** *
*** * * * * * * * **** * *** ** ** * * * is a prefix of %s",c,d);

* **** * *** ** * **
* * *** * * *** ***** * ****** * * ** * * * is not a prefix of %s",c,d);


}
answered by (-32 points)
edited by
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.6.142
©2016-2024

Related questions

1 like 0 dislike
37 answers
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42302 - Available when: 2018-01-17 14:00 - Due to: Unlimited
| 1.8k views
2 like 0 dislike
31 answers
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42301 - Available when: 2018-01-17 14:00 - Due to: Unlimited
| 1.8k views
1 like 0 dislike
32 answers
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42300 - Available when: 2018-01-17 14:00 - Due to: Unlimited
| 2.1k views
2 like 0 dislike
30 answers
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42298 - Available when: 2018-01-17 14:00 - Due to: Unlimited
| 1.5k views
0 like 0 dislike
4 answers
[Exam] asked Jan 19, 2018 in Final Exam
ID: 43460 - Available when: 2018-01-20 09:00 - Due to: Unlimited
| 451 views
12,783 questions
183,443 answers
172,219 comments
4,824 users